A lattice model for transition zones in ballasted railway tracks
de Oliveira Barbosa, João Manuel; Faragau, Andrei B.; van Dalen, Karel N.
DOI
10.1016/j.jsv.2020.115840
Publication date
2021
Document Version
Final published version
Published in
Journal of Sound and Vibration
Citation (APA)
de Oliveira Barbosa, J. M., Faragau, A. B., & van Dalen, K. N. (2021). A lattice model for transition zones in
ballasted railway tracks. Journal of Sound and Vibration, 494, 1-22. [115840].
https://doi.org/10.1016/j.jsv.2020.115840
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ContentslistsavailableatScienceDirect
Journal
of
Sound
and
Vibration
journalhomepage:www.elsevier.com/locate/jsv
A
lattice
model
for
transition
zones
in
ballasted
railway
tracks
João
Manuel
de
Oliveira
Barbosa
∗,
Andrei
B.
F
˘ar
˘ag
˘au,
Karel
N.
van
Dalen
a TU Delft, Faculty of Civil Engineering and Geosciences (CiTG), Department of Engineering Structures, Section of Dynamics of Solids and Structures. Stevinweg 1, 2628 CN Delft, the Netherlands
a
r
t
i
c
l
e
i
n
f
o
Article history: Received 20 May 2020 Revised 4 November 2020 Accepted 9 November 2020 Available online 16 November 2020
Keywords:
Moving load Infinite lattice
Support stiffness variation
a
b
s
t
r
a
c
t
The procedurepresented inthiswork aimsatprovidingaframework for studying
set-tlementofballastinzoneswithstiffnessvariationoftherailwaytracksupport.The
pro-posed procedureresults fromexpandingan existinginfiniteperiodicmodelofarailway
tracktoaccountforvariationsinthestiffnessofthefoundation.Ballastissimulated via
alinearlattice,whosedynamicresponsediffersfromthatofacontinuum.Theexpanded
model iscomposedofthreeregions:aleftregion,whichissemi-infiniteandperiodic; a
mid-region,offinitelengthandwherethepropertiesofthefoundationcanchange;anda
rightregion,whichisalsosemi-infiniteandperiodicandwhosepropertiescandifferfrom
thoseoftheleftregion.Theequationsofmotionofthemid-regionarewrittendirectlyin
thetimedomain,withtherailbeingdescribedbyfiniteelements.Ontheotherhand,the
leftandrightsemi-infiniteregionsaretreatedsemi-analyticallyinthefrequencydomain,
and afterwards theirresponsesareconverted tothe timedomain,resulting in
convolu-tionintegralsprescribedattheboundariesofthemid-regionthatsimulatenon-reflective
boundaries. Thefinalmodel onlycontainsthedegrees offreedomcorresponding tothe
mid-region(whichcanbeasshortastheregionwherethestiffnessvariationispresent),
and thatleadstofastercalculationsthaniftheboundarieswereplacedfurtherawayto
dissipateundesired reflections.Themethodiscastinthetimedomain,andallelements
areassumedtobehavelinearly.Inthefuture,themodelwillbeexpandedtoincorporate
non-linearbehaviouroftheballast.Thepresentedmethodisvalidatedbymeansofsimple
examples, andafterwardsappliedtoarealscenarioinwhichaculvertcrossesarailway
track. Aspresented,themethodcanbeusedtostudy thelineardynamicsoftransitions
zones, study mitigationmeasures,and infer about indicators likeforce transmitted and
energydissipated,whichmightbeusefultoassessthedevelopmentofsettlementofthe
ballast.
© 2020TheAuthor(s).PublishedbyElsevierLtd.
ThisisanopenaccessarticleundertheCCBYlicense
(http://creativecommons.org/licenses/by/4.0/)
1. Introduction
Previousstudiesandmeasurements indicatethat differentialballastsettlementoccursatafasterpaceinregions where railwaytracksexperiencevariationsintheirsupportstiffnessthaninregionswithhomogeneoussupport[1,2].The acceler-ateddifferentialsettlementdemands formorefrequentmaintenance operations,whichtranslatesintoadditionalcosts and
∗Corresponding author.
E-mail address: j.m.deoliveirabarbosa@tudelft.nl (J.M. de Oliveira Barbosa).
https://doi.org/10.1016/j.jsv.2020.115840
0022-460X/© 2020 The Author(s). Published by Elsevier Ltd. This is an open access article under the CC BY license ( http://creativecommons.org/licenses/by/4.0/ )
disruptionsofthetrainschedules.Theseregions ofstiffnessvariationarethereforeofinteresttorailwayresearchers,since understandingthephenomenabehindtheaccelerateddegradationhelpsdesigningsolutionstomitigatetheissue.
Studiesfocusingonsettlementofballastcanbecategorizedintofield measurementsandconditionmonitoring[3,4],in which thepositionof railsandthe geometryofballast aremeasured andmonitoredinthe periodbetweenmaintenance operations;labtests[5–7],inwhichballast layersarecyclicallyloaded andtheevolutionofitsgeometryisrecorded;and numericalsimulations,inwhichmoreorlesscomplexmathematicalmodelsareformulated topredicttheresponseofthe track. Whilstthe first category is very useful fordetecting main features of the settlement, it isless viable to optimize mitigation measures,since anyalterationwouldrequirenewconstructions, andthat wouldfirstrequirean approvalfrom therelevantsafetyauthorities,whichareusuallyveryconservativeandstrict.Ontheotherhand,labtestsallowforabetter control of the loading process and in thisway are useful to derive constitutive laws for the ballast (which can include mitigationmeasures suchasgeogrids[8] orbindingpolymers[9]),butforstudyingrailwaytracksupportstiffnesschanges thisapproachbecomesunfeasibleduetothespacerequiredtoaccommodatesuchfeatures.Numericalsimulationshavethe disadvantageofbelongingtoafantasyworld,inwhicheverythingiswelldefinedandcontrolled,butareveryversatileand thus usefulforassessing theefficiencyofmitigation measures.The threecategoriesofstudiescomplementeach other.In thiswork,thefocusliesonnumericalsimulations.
Awidevarietyofmodelsfocussingonlongitudinalvariationsofthetracksupporthavebeenpresentedintheliterature. Theyincludesimple 1Dmodels ofrails restingonviscoelastic Winklerfoundationswithlongitudinallyvarying properties [10–13],simple2Dmodelsofhalf-spaceswithstepvariationsintheirproperties[14,15],andverydetailed2Dor3Dmodels of track, foundationandpotential mitigation measures [16–19]. Forthe latter,the mostcommonsolution strategy isthe use ofthe finite element method(FEM) todiscretize the domainand its differentcomponents, whicheventually can be describedwithnon-linearconstitutivelawsthatdefinethesettlementbehaviourofballast[20].However,becauseFEMcan only handlefinitedomains, inorderto avoidboundaryeffects, largevolumesof domainhaveto bemodelled, leadingto hugecomputationaltimesandrenderingtheapproachnotsuitableforlargeparametricstudies.
Inwhatconcernsballastdescription,onecanassumecontinuummodelsordiscretemodels.Thefirstassumptionis read-ilyavailableinanyFEMsoftware,andcanbecombinedwithnon-linearconstitutivelawsthatdefinetheballastbehaviour [21].However, representingballast insuch awayfailstocapturecertainfeatures ofits dynamicresponse,namelythe ex-istenceofathresholdfrequencyabove whichwavescannot propagate,aswell asthespecificdispersivebehaviourathigh frequencies;thismayverywellaffectthelocaldynamicbehaviouroftheballastandthusthedevelopmentofpermanent deformations.Discretemodels, ontheother hand,intendtodescribe each particleofballastindependently, andthuscan provide moreaccuratedescriptions ofits behaviour.Thediscrete elementmethod(DEM) [22–26] is themethodusedthe most, sinceitcandescribethecontactbetweenparticles quitewellandcapturedifferentfailure modesofballast,butdue toitshighcomputationalcost,itcannotbeusedtosimulatethelengthsofthetrackneededtoconsiderchangesinthe stiff-nessofthesupport.AlternativelytoDEM,latticemodels[27,28]alsointendtodescribeeachballastparticleindividually,but theyassumethatallparticlesareequalandregularlydistributedandthatcontactsbetweenparticlesdonotchange,inthis wayavoidingthecontactcalculationsandreducing thecomputational time.Bymakingthelattice connectionsnon-linear, settlementbehaviourcanbesimulated.
The procedurepresentedinthisworkaims atprovidingaframework forstudyingtrain-passage inducedsettlement of ballast inzoneswithstiffnessvariationsof thesupport.The purposeofthe framework isto allowparametric studieson mitigation solutions,andthereforethecalculationsshouldnot betoocomputationallyintensive.Therefore,atime-domain 2D modelisproposed,inwhichballastandfoundationare describedbya linearlattice(infuturework,non-linearlattice connections willbe addedto lookatsettlementbehaviour),andtheinfinitecharacter ofthetrackinthe longitudinal di-rectionisachievedwithnon-reflectiveboundaries. Theproposedapproachconsistsindividingtheballastedtrackinthree regions:onebeforethestiffnessvariationthatissemi-infiniteinthelongitudinaldirection;oneafterthestiffnessvariation thatisalsosemi-infinite;andamiddleregionoffinitelengthwherethestiffnessvariationisdescribed.Becausethedomains beforeandafterthestiffnessvariationarereplacedbytransmittingboundaries,thefinalmodelonlycontainsthedegreesof freedom correspondingtothemiddleregion(whichcanbeasshortastheregionwherethestiffnessvariationispresent), andthatleadstofastercalculationsthaniftheboundarieswereplacedfurtherawaytodissipateundesiredreflections.The resultingapproachisanexpansionofthemodelpresentedinapreviouswork[29],inwhichasemi-analyticalsolutionfor thetrackwithoutstiffnessvariationispresented.
Thismanuscriptisorganizedasfollows.Section2 introducesthemodelintermsofthethreeregionsmentionedinthe previous paragraphandformulatestheequationsofmotionofeachregioninthetimedomain.InSection3,theequations derivedinapreviouswork[29] areworkedoutinordertoobtainthetransmittingboundariesthatreplacethesemi-infinite regions. InSection 4,themethodisverifiedby comparingeachintermediate stepwithequivalentmodels,andthe three-regionmodelwiththeanalyticalexpressionsfrom[29].InSection5,theusageoftheproposedapproachisillustratedbased ona realstretchoftheDutchrailwayline.Inthelast section,Section6,theworkissummarizedandfinalconsiderations areproffered.
2. Threeregionmodel
The procedurepresented inthisarticlebuildson themodelintroduced ina previous work[29],inwhich therailway trackisconsideredtobeperiodicandissolvedsemi-analyticallyformovingandnon-movingloads.There,railsaremodelled
Fig. 1. Schematization of the periodic model (adapted from [29] ).
Fig. 2. Left, middle and right regions.
Fig. 3. Mid-region and interaction forces.
asan Euler-Bernoullibeam,sleepers asrigidmasses,andballastandfoundationasahorizontallylayeredlattice, whichis a regular networkofequallyspaced massesconnectedviaviscoelastic connections,asdefinedinthe workby Suikerand collaborators[27,28].Theweightofthelattice massesandthepropertiesoftheviscoelasticconnections maychangefrom layer tolayer inorder todistinguish thedifferentmaterial propertiesofballast andfoundation. Fortheballast layer, the propertiescan be inferredfromlabcompression tests(seeSection 4), whileforsoil/foundationlayers, thepropertiescan be inferredfromequivalentcontinuousmodels[27] (beawarethatlatticeslimit theapproximationofcontinuumlayersto Poisson’sratiobelow0.25,seeSection5.1).Fig.1 schematizestheperiodicmodel.
The expansiondescribedinthiswork consistsinaddingamid-regioninwhichthepropertiesofthefoundation(orof anyothercomponent, thoughheretheinterest isinthefoundation)canvary.Inthisway,themodelisdividedintothree parts: aleft region,whichisperiodicandsemi-infiniteandformulated semi-analyticallyinthefrequencydomain;a mid-region,withinwhichmaterialpropertiescanchangeandthatisformulatedinthetimedomain;arightregion,whichlike the left region issemi-infiniteand formulated semi-analyticallyin thefrequencydomain. The left andrightregions may havedistinctballastorfoundationproperties.Fig.2 schematizesthedivisionofthesub-regions.
In thefollowingsubsections eachofthe sub-regionsisdescribed, andthe procedureto couplethemisexplained.The mid-regionisdescribedfirst.
2.1. Mid-region
Fig. 3 shows the mid-region isolated from the rest ofthe domain. In the figure, the mid-region is represented by 3 regularcellsofthesametypeasthoseoftheleftandrightregions,butinprinciplethemid-regioncanconsistofanytype ofstructure,providedthatthegeometriesatitsleftandrightboundariesarecompatiblewiththesideregions.Inaddition, thematerial propertiesofthemid-regioncanchangefromlocationtolocation,anditslength canassumewhatevervalue necessary. Thisregionis acteduponby external forces(fext,not representedinFig.3), whichinmostcaseswill bea set
ofloads moving ontopofthe railfromone edgetothe other,andbytheinteraction forcesattheleft (fl) andright(fr)
boundaries.Theseinteractionforcesrepresenttheeffectofthesemi-infiniteregionsonthemiddledomain,andwillensure thatthesimulationisnotaffectedbyunwantedreflectionsattheseedges.Theinteractionforcesoneachsidearecomposed byashearforceandamomentattherail,andacoupleofhorizontalandverticalforcesateachmassofthelattice.
Fig. 4. Left and right regions and interaction forces.
Due to its simplicity, the Finite Elementmethod is used to describe the behaviour of the rail,which in this work is dividedintoelementsthatarehalfthelengthofthelatticecharacteristicdistanced (inprinciple,anydiscretizationlength canbeused,butforconvenienceassociatedwithmeshing,d/2isused).Thus,afterdiscretizingtherailandassemblingall railelementsandviscoelasticconnectionsofthelatticeintothestiffnessanddampingmatrices(KandC),andalltheinertial elementsintothemassmatrixM,theequationsofmotionofthemid-regioncanbewrittenas
M ll Mlm Mml Mmm Mmr Mrm Mrr M u¨ l ¨ um ¨ ur ¨ u + C ll Clm Cml Cmm Cmr Crm Crr C u˙ l ˙ um ˙ ur ˙ u + K ll Klm Kml Kmm Kmr Krm Krr K u l um ur u =fext+ f l 0 fr (1)Forconvenience,thedegreesoffreedomhavebeendividedintothoseattheleftinterface(l),thoseattherightinterface (r),andtheremainingones(m). Thesub-indicesinthematricesK,CandM,andintimedependantvectorsuandf rep-resentthesegroupsofdegreesoffreedom.InEq.(1),thetime dependantvectorucontainstheresponseofeachnode(for nodesoftherailsandsleepers,theresponsesaretheverticaltranslationandtherotation;forthelatticenodes,theyarethe horizontalandtheverticaltranslations).ThemassmatricesMll andMrr arezeroeverywhereexceptatentries
correspond-ing tothedegreesoffreedomassociated withtherail (notethatatthelateralboundariesofthemid-regionthereare no latticeparticles;theseareconsideredintheleftandrightregions;seeFig.4 forthedefinitionoftheleftandrightregions). Also, themassmatricesMlm=MT
ml andMrm=M T
mr arenon-zerobecause theapplicationofthefiniteelement methodto
describetherailleadstoinertialtermscouplingtheleftandrightnodesofeachrailelement.
Eq.(1) issolveddirectlyinthe timedomainusingtheNewmarkmethod[30].Applicationofthismethodleadsto the followingtime-steppingscheme
⎧
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎩
¯ Kuj=fj ext+⎡
⎣
f j l 0 frj⎤
⎦
+Ma0uj−1+a2u˙j−1+a3u¨j−1 +Ca1uj−1+a4u˙j−1+a5u¨j−1 ˙ uj=a 1 uj− uj−1− a 4u˙j−1− a5u¨j−1 ¨ uj=a 0 uj− uj−1− a 2u˙j−1− a3u¨j−1 (2)wheretheupperindex j referstothetimeinstantt=j
t (
t istheconstanttime step;thepresenceoftheupperindex meansthevariableistimedependant),K¯ istheequivalentdynamicstiffnessmatrixgivenby
¯
K=a0M+a1C+K (3)
andtheconstantsa0 toa5aregivenbythefollowingexpressions[31]:
a0= 1
β
t2, a1=
γ
β
t, a2= 1
β
t a3= 1 2
β
− 1, a4=γ
β
− 1, a5=t
γ
2β
− 1 (4) The constantsβ
andγ
aretheNewmarkparameters,andaresetatβ
=0.25andγ
=0.5,whichleadstounconditionally stablesolvers,atleastinthecaseoflinearandfinitesystems.Inthecurrentcase,theexistenceoftheboundaryforcesflandfr,whichsimulatesemi-infinitedomains, violatesthefinitesystemcriteria, meaningthatthemethoddoesnot necessarily
havetobe unconditionallystable. ThechoiceoftheseNewmarkparametersassumesthatwithin thetimeinterval
t the
accelerationsremainconstantandequaltotheaveragebetweenthepreviousandthenexttime-step. Tosolvethetime-steppingalgorithminEq.(2) foruj,u˙jandu¨j,theinteractionforcesf
landfrmustfirstbedetermined.
Iftheseforceswereresultingfromsomeknownexcitation,ofwhichoneknewtheirtimeevolution,thenthesystemcould be solvedasitis.However,theseforcesaredependanton theresponseoftheboundaryinsucha waythat the displace-ments ofthethreeregions mustbecompatibleattheinterfaces,andthus thesetermsmust befurtherexpanded.Thatis addressedinthefollowingsubsections.
2.2. Leftandrightregions
Fig. 4 showsthe left andrightregions isolated fromthe mid-region.Theyare actedupon by the interactionforces fl
andfronthecorrespondingsides(now actingintheoppositedirection:action-reactionpair),andby otherexternalforces
fext,landfext,r(notrepresentedinFig.4),withforcesmovingalongtherailbeingthemostcommonexternalexcitation.The
responseoftheboundariesofthesedomainscanbewrittenas
uα
(
t)
=− t−∞Hα
(
t−τ
)
fα(
τ
)
dτ
+uα,ext(
t)
(
α
=l,r)
(5)where Hα
(
t)
is the impulse response matrix ofthe left (α
=l) and right (α
=r) boundaries(vertical displacement and rotationoftherailandhorizontalandverticaltranslationsoflatticemassesattheboundariesduetosuddenunit-impulse forcesappliedatt=0andatthesameboundaries),anduα,ext(
t)
istheresponseoftheseboundariesduetotheexternallyappliedforcesfext,landfext,r.Theminussigninfrontoftheintegralisduetotheaction-reactionpairattheinterface.Also,
uα
(
t)
correspondstoulandurinEq.(1),sincetheremustbecompatibilityofdisplacementsattheinterface.Duetothediscretenatureofthetimesolverusedforthemid-region,theforcesfα
(
t)
canonlybeknownattheintervalst=j
t:fαj =fα
(
jt
)
.Thus,inordertoevaluatetheintegralinEq.(5),atimeevolutionhastobeassumedfortheseforces betweenthediscretetimeinstants.Here,theapproachproposedbyBodeetal.[32] isfollowed.Thatapproachassumesthat withinatimeintervaltheforceremainsconstantandequaltothemeanoftheforceatthebeginningandattheendofthe timeinterval,i.e.,fα
(
t)
≈fj−1 α +fαj
2 ,
(
j− 1)
t<t<j
t (6)
Whencomparedtootherassumptionsfortheforceevolution,suchaslinearvariation,constantandequaltoforceat be-ginning,orconstantandequaltoforceatend,theapproximationproposedin[32] istheonethatshowedmorerobustness intermsofstabilityofthesolver,andthusistheoneadoptedinthiswork.Nonetheless,thisapproximation(oranyother) isnot consistentwiththeassumptions madewiththeNewmarkmethodusedtosolvethemid-region(inthemid-region, assumptionsaremadeabouttheaccelerationevolution,whileatthesideregions,assumptionsaremadeabouttheevolution oftheinteractionforces),andthatcanleadtounwantedreflectionsattheboundaries.Thesereflectionscanbeminimized byreducingthetimestep,asdiscussedlaterinSection4.
BasedontheapproximationinEq.(6) andtheexpressionsinEq.(5),theboundaryresponsesatthetimeinstantt=j
t
aregivenby uαj =uα
(
jt
)
=− j i=−∞ it (i−1)tHα(
jt−
τ
)
dτ
fi−1 α +fiα 2 +uα,ext(
jt
)
=−1 2 t 0 Hα(
τ
)
dτ
fαj − j−1 i=−∞ 1 2 t −tHα(
(
j− i)
t+
τ
)
dτ
f i α+uα,jext (7)whichcanberewrittenas
uαj =−F0 αfαj− j−1 i=−∞ Fαj−ifi α+uα,jext (8)
wherematricesFαj arecalculatedwith
Fαj =1 2
t −t
Hα
(
jt+
τ
)
dτ
(9)Eq.(8) splits theinterface displacements inthree components:thedisplacements induced by theforcesactingonthe sametimeinterval;theaccumulateddisplacementsduetoforcesactingontheprevioustime intervals(historyterm);and thedisplacementsinducedbytheexternallyactingforces.Thatequationprovidestheframeworktostudytheleftandright regions, butexpressions forthedisplacementsuα,jext andfortheimpulse responsematricesHα
(
t)
andFαj still needtobe defined. Duetothesemi-infinitenatureofthesidedomains,thesequantitiescanbe easiercalculatedsemi-analytically in thefrequencydomainandlateronconvertedtothetimedomain.SuchisexplainedinSection3,butfirstthecouplingof thesideregionstothemid-regionisexplained,sothatthewholeproblemcanbesolved.2.3. Couplingthesideregionstomid-region
Eq.(8) canberearrangedtoisolatefαj ontheleft-handside,leadingto
fαj =−
F0 α−1 uαj+ j−1 i=−∞ Fαj−ifi α− uα,jext (10)If Eq. (10) is now inserted into the time-stepping algorithm (2), after some rearrangement, namely moving the factor
(
F0α
)
−1uαj totheleft-handside,oneobtainsanexpandedtime-steppingalgorithmoftheform⎧
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎩
ˆ¯ Kuj=fj ext+⎡
⎣
¯f j l 0 ¯fj r⎤
⎦
+Ma0uj−1+a2u˙j−1+a3u¨j−1 +Ca1uj−1+a4u˙j−1+a5u¨j−1 ˙ uj=a 1 uj− uj−1− a 4u˙j−1− a5u¨j−1 ¨ uj=a 0 uj− uj−1− a 2u˙j−1− a3u¨j−1 fαj =−F0 α−1uαj +¯fαj,α
=l,r (11) wherevectors¯fj l and¯f j r aredefinedby ¯fj α=−F0α−1 j −1 i=−∞ Fαj−ifiα− uj α,ext (12)andwherethenewequivalentstiffnessmatrixKˆ¯ isgivenby
ˆ¯ K=a0M+a1C+
⎡
⎣
Kll+ F0 l −1 Klm Kml Kmm Kmr Krm Krr+ F0 r −1⎤
⎦
(13)In short,time-steppingalgorithms (2)and(11) arevery similar, withthedifference that some oftheterms haveslightly differentexpressions, namelytheequivalentstiffnessmatrix,whichinEq.(11) containsstiffnessterms
(
F0l
)
−1 and(
F0r)
−1associated withthe leftandrightregions,andtheinterface force vectors,whichforthealgorithm inEq.(11) contain the history ofwhat happenedat theboundary beforet=j
t, andare givenby Eq.(12). The extraexpression in Eq.(11) is neededtocalculatetheinteractionforcesfljandfrj,whichcanonlybeevaluatedaftertheinterfacedisplacementsuljandu
j r
havebeencomputed.
Note that, as presented,the mid-region is acted upon by external forces fextj and incident displacements uα,jextat the left and rightinterfaces; both thesequantities are prescribed by the user. Whereasuα,j ext can be calculated taking into consideration the possible interaction withan oscillator moving on the rail of the side regions, the external forces fextj cannotconsidersuchinteractionwithoutfirstaugmentingthesystemofEqs.(11) withtheequationsgoverningthemotion oftheoscillator.Thisinteractionwithanoscillatorwillbeconsideredinafuturework;inthiswork,fextj anduα,j extrepresent theactionofamovingconstantload.
3. Semi-analyticalevaluationofinterfacematricesandvectors
Section 2 explainsthemainframeworkofthemodelproposed inthiswork. Itreliesontheknowledgeoftheimpulse responsematricesHα
(
t)
anddisplacementsuα,ext(
t)
,bothreferringtotheinterfacesbetweensideregionsandmid-region.Duetothesemi-infinitecharacteristicoftheformer,thecalculationofthementionedquantitiesisnotstraightforward,and itiseasierdonefirstsemi-analyticallyinthefrequencydomain,andthenconvertedtothetimedomain.Thepresentsection explainshowthisisachieved,startingwiththematricesHα
(
t)
.3.1. Calculationofimpulseresponsematrices
The impulseresponsematricesHα
(
t)
give theresponseofall degreesoffreedom atthe interfaceoftheleft (α
=l) or right(α
=r)region,duetounit-impulseforcesappliedatanydegreeoffreedomofthesameinterface(forthecalculationof thesematrices,theleft/rightregionstandsalone;apartfromtheappliedimpulseforces,thatinterfaceisforce/stress-free). Theirfrequency-domaincounterparts,H˜α(ω
)
,aretermeddynamicflexibilitymatricesandcontaintheharmonicresponseof alldegreesoffreedomduetounitharmonicforcesappliedatanydegreeoffreedom.Therowsofthematricesrefertothe degreeoffreedomatwhichtheresponseisobserved,whilethecolumnsrefertothedegreeoffreedomwheretheforceis applied.MatricesHα(
t)
canbeobtainedfromH˜α(ω)
throughaninverseFouriertransformHα
(
t)
= 1 2π
+∞ −∞ ˜ Hα(
ω
)
eiωtdω
(14)andmatricesFαj,asdefinedinEq.(9),canbecalculatedvia
Fαj = 1 2
π
+∞ −∞ ˜ Hα(
ω
)
sin(
ω
t
)
ω
eiωjtdω
(15)The dynamicflexibility matrices H˜α can be calculated semi-analytically based on the expressions derived in [29].In that referencework,thedisplacements,internal shearandinternal momentoftherail,displacementsofthesleepers,and displacementsofthelatticearegivenforarbitraryforcesactingontherailoronthelattice,assuminginfiniteperiodicity.To gofromtheseinfinite-domainsolutionsandobtainthoseofasemi-infinitedomainofthesametype(towhichthedynamic flexibility matricesH˜α refer), one must impose that there is no transmission offorces betweenthe left and right semi-infinitedomains that composethe infinitedomain.Thisconditionisequivalenttocreatinga semi-infinitedomainwitha freeboundary(asdesired),andcanbeachievedbyaddingfictitiousforcesofappropriateamplitudeatthepartoftheinfinite domainthatistoberemoved(i.e.,forthecalculationofH˜lthefictitiousforcesareappliedtotherightofthefreeboundary;
forthecalculationofH˜r,totheleft).ThisprocedureisexplainednextforH˜l(forH˜r,theprocedureisverysimilaranddoes
notrequirefurtherexplanation).
Consider a periodically infinite domain asrepresented in Fig. 1. At each vertical alignment going through the lattice masses, it ispossible to apply unit forces Frail andmoments Mrail at the rail, andhorizontal Flatj
x and verticalFzlatj unit forces at the lattice masses, and for each of these loads, the expressions fromwork [29] can be used to calculate the displacements v rail,rotations
θ
rail,internalshearsrailandmomentmrail oftherailatanyposition,andalsothehorizontalxlatjandverticalzlatjdisplacementsofthelatticemassesatanyverticalalignment(jstandsforthedepthindexofthelattice mass). Applythementioned setofforcesatalignmenti indicatedinFig.1 (the forcesattherailshould beappliedatan infinitesimaldistancetotheleftofthealignment),andcollectthedisplacementsofthesamealignmentinmatrixUi,iand the displacementsofalignment ii(alsorepresentedinFig. 1)inmatrixUii,i (firstsubscript refers tothealignment where theresponseiscalculated;secondsubscriptreferstowheretheloadisapplied).Forexample,matrixUi,iisoftheform(the partofthesuperscriptafterthecommaineachofthematrixentriesrepresentstheloadlocationanddirection)
Ui,i=
⎡
⎢
⎢
⎢
⎢
⎢
⎢
⎢
⎢
⎢
⎢
⎢
⎢
⎢
⎣
v
rail,Frail i,iv
rail,M rail i,iv
rail,Flat1 x i,iv
rail,Flat1 z i,i · · ·v
rail,FlatN x i,iv
rail,FlatN z i,iθ
rail,Frail i,iθ
rail,M rail i,iθ
rail,Flat1 x i,iθ
rail,Flat1 z i,i · · ·θ
rail,FlatN x i,iθ
rail,FlatN z i,i xlat1,Frail i,i xlat1,M rail i,i x lat1,Flat1 x i,i x lat1,Flat1 z i,i · · · x lat1,FlatN x i,i x lat1,FlatN z i,izilat,i1,Frail zilat,i1,Mrail zlat1,Fxlat1
i,i z lat1,Flat1 z i,i · · · z lat1,FlatN x i,i z lat1,FlatN z i,i . . . ... ... ... ... ... ... xlatN,Frail i,i xlatN,M rail i,i x latN,Flat1 x i,i x latN,Flat1 z i,i · · · x latN,FlatN x i,i x latN,FlatN z i,i
zi,ilatN,Frail zi,ilatN,Mrail zlatN,Fxlat1
i,i z latN,Flat1 z i,i · · · z latN,FlatN x i,i z latN,FlatN z i,i
⎤
⎥
⎥
⎥
⎥
⎥
⎥
⎥
⎥
⎥
⎥
⎥
⎥
⎥
⎦
(16)Matrix Ui,i doesnot correspond to the dynamicflexibility matrix H˜l because the expressions from work [29] do not
satisfy the free boundary conditionneeded to simulate a semi-infinite domain,i.e., atalignment i there is transmission offorcesfromthe leftto therightside.Theseforces,heretermedconnecting forces,correspond totheinternal shearand moment of the rail at alignment i, and to the resultant forces at the lattice masses dueto the viscoelastic connections betweenalignmentsiandii(seeFig.1).CollectalltheseconnectingforcesinamatrixSi,ioftheform
Si,i=
⎡
⎢
⎣
srail,Frail i,i srail,M rail i,i s rail,Flat1 x i,i s rail,Flat1 y i,i · · · s rail,FlatN x i,i s rail,FlatN y i,imirail,i ,Frail mirail,i ,Mrail mrail,Fxlat1
i,i m rail,Flat1 y i,i · · · m rail,FlatN x i,i m rail,FlatN y i,i Fi,i
⎤
⎥
⎦
(17)(the firstsubscript referstothealignment wherethe connectingforcesare calculated,whilethesecondsubscript refersto the alignment where the forces are applied) wheresubmatrix Fi,i, which containsthe connecting forces at the lattice, is calculatedwith
Fi,i Fii,i =K˜i,ii Ulat i,i Ulat ii,i (18) InEq.(18),matrixK˜i,iiisthedynamicstiffnessmatrixwhereallthehorizontalanddiagonalconnectionsbetweenalignmentsiandiiareassembled,andmatricesUlat
i,i andUlatii,iarethesubmatricesofUi,iandUii,i,respectively,thatcollectonlythelattice displacements,i.e.,afterremovingthefirsttworows.
In orderto compensatefor thenon-zero connectingforces Si,i, asecond set offorces(termedfictitious forces) mustbe applied at alignment iisuch that the combinationof the connecting forces causedby the loads atalignment i andthose causedbythefictitiousforcesiszero,i.e.,(Oisamatrixofzeros)
Si,i+Si,iiAfic=O (19)
MatrixAfic,whichcontainstheamplitudesofthefictitiousforcesneededtosatisfythefree-boundaryconditionofthe
semi-infinitedomain,isasquarematrixofwhicheachcolumncorrespondstothefictitiousforceamplitudesforeachloadscenario atalignmenti.ItisobtainedbyrearrangingEq.(19),anditreads:
Afic=−
(
SThe dynamic flexibility matrix H˜l of the left domain relatingforces anddisplacements atthe free surface ofthe left
semi-infinitedomainisnowobtainedbyaddingtheinfinite-domaindisplacementsinduced bythefictitiousforcestothose inducedbytheloadsappliedatalignmenti,i.e.,
˜
Hl=Ui,i+Ui,iiAfic
=Ui,i− Ui,ii
(
Si,ii)
−1Si,i(21) ThecalculationofmatrixH˜rfollowsthesamestepsasformatrixH˜l,withthealignmentsiandiiswapped,anditsfinal
expressionis
˜
Hr=Uii,ii− Uii,i
(
Sii,i)
−1Sii,ii (22) Notethattocalculatetheleft andrightflexibilitymatrices,itmaybenecessarytoconsiderdifferentmaterialpropertiesif the leftandrightsemi-infinitedomainsaredifferent.Theexpressions fortheircalculation arestillEqs.(21) and(22),but foreach,thequantitiesmustbecalculatedwiththecorrespondingmaterialproperties.3.2. AlternativeapproachforcalculatingH˜α
Thoughthemethodexplainedintheprevioussubsectionworkswell andissolelybasedonthesemi-analytical expres-sionsfromwork[29],thefactthattheseexpressionsrequirethenumericalevaluationofintegralsoverwavenumbersleads to timeconsumingcalculations. Alternatively,afastermethod,which takesadvantageoftheperiodiccharacteristicofthe structure,canbeapplied.Itreliesonthediscretizationoftherailandrecursivecloningofcells,leadingtosomenumerical approximation(andpropagationoferrors).Nevertheless,sincethediscretizationappliedisquitefinecomparedtothe char-acteristicwavelengthintherail(thefocusisonlowfrequencies,below5kHz),theintroducederrorsareminimaland,thus, this alternative approach leadsto virtually the same resultsas themethod presented inthe previous subsection (which introducesnodiscretizationerrors).
ConsidertheportionoftheperiodicallyinfinitedomainrepresentedinFig.1 thatislimitedbythealignmentsiiandiii. After discretizingtherailintosmallbeamelements(say,withlengthl=d/2,whered isthecharacteristicdistanceofthe lattice – see Fig.1), thefrequency-domainequations ofmotionofthe resultingsystem(latticemasses, sleeper massand discretizednodesofthebeam)arewrittenas
⎡
⎣
K˜K˜mlll K˜K˜mmlm K˜mr ˜ Krm K˜rr⎤
⎦
u˜ l ˜ um ˜ ur =⎡
⎣
˜f˜fextext,,ml ˜ fext,r⎤
⎦
(23)wherematricesK˜αβ(
α
,β
=l,m,r)arethedynamicstiffnessmatrices(K˜αβ=−ω
2Mαβ+i
ω
Cαβ+Kαβ)andwhere˜fext,α are theexternal forcesappliedateachnode. Forconvenience, thedegreesoffreedomhavebeendividedintothosebelonging totheleftedge(alignmentii,denotedwithl),thosebelongingtoalignmentrightedge(alignmentiii,denotedwithr),and thosebelongingtothemiddle(denotedwithm).Takingintoconsiderationthatthemiddlenodesarefreeofexternalforces, i.e.,˜fext,m=0,thenthemiddledegreesoffreedomcanberemovedfromthesystemofequations,obtaininganewrelationofthetype
˜ K0 ll K˜ 0 lr ˜ K0 rl K˜0rr ˜ u1 l ˜ u1 r = ˜ f1 ext,l ˜f1 ext,r (24) wherethesubmatricesK˜0αβ (
α
,β
=l,r)areobtainedthroughtheexpression˜
K0αβ=
δ
αβK˜αβ− ˜KαmK˜mm−1K˜mβ (25)InEq.(25),
δ
αβistheKroneckerdelta(δ
αβ=1ifα
=β
;δ
αβ=0ifα
=β
),thesuperscript0inmatrixK˜ referstostepzero (at stepn, 2n cellsare considered;therecursive procedureis explainednext),andthesuperscript 1atvariables u˜ and˜f referstothecellnumber(20=1).MatrixK˜0relatestheforcesanddisplacementsoftheedgesofonecell;twoofsuchcellscan beplacednextto eachotherandcoupledwiththeportionofthedomainlimitedbyalignments iandii,obtaining in thiswayanewdomaincomprisingtwocells.Themotionofthistwo-cellsdomainisdescribedbythefollowingsystemof equations
⎡
⎢
⎢
⎢
⎣
˜ K0 ll K˜0lr ˜ K0 rl K˜ 0 rr+K˜couplell K˜ couple lr ˜ Kcouplerl K˜0 ll+K˜ couple rr K˜0lr ˜ K0 rl K˜ 0 rr⎤
⎥
⎥
⎥
⎦
⎡
⎢
⎢
⎣
˜ u1 l ˜ u1 r ˜ u2 l ˜ u2 r⎤
⎥
⎥
⎦
=⎡
⎢
⎢
⎢
⎣
˜f1 ext,l ˜ f1 ext,r ˜f2 ext,l ˜ f2 ext,r⎤
⎥
⎥
⎥
⎦
(26)whichrelatesforcesanddisplacementsattheextremitiesofthetwocells. MatrixK˜couplerepresentsthedynamicstiffness
(Eq.(18)), augmentedwiththedegreesoffreedom (andassociatedvalues)corresponding tothenodesofthe rail(oneon each side).Assumingagainthattherearenoforcesappliedinthemiddlealignments, i.e.,˜f1
ext,r=0and˜f2ext,l=0,thenthe
variablesu˜1
r andu˜2l canberemovedfromthesystemofequations,obtaininginthiswayanewsystemofthetype
K˜1 ll K˜1lr ˜ K1 rl K˜ 1 rr u˜1 l ˜ u2 r = ˜f1 ext,l ˜f2 ext,r (27) Ifthisprocedureisappliedrecursivelywiththenewlyobtainedmatrixntimes,oneobtainsasystemofequationsofthe type K˜n ll K˜nlr ˜ Kn rl K˜ n rr u˜1 l ˜ u2n r = ˜f1 ext,l ˜ f2n ext,r (28) relatingthedisplacementsoftheleftalignmentofthefirstcellanddisplacementsoftherightalignmentofthecell2nwith the forcesapplied at thesame alignments. Thus, by applyingthisrecursive procedure ntimes, one isable todescribe a domaincontaining2n cellswithasystemofequationscontainingonlythedegreesoffreedomattheedges ofthedomain. TheexpressionstorecursivelycalculateK˜nαβ (
α
,β
=l,r)are ˜ Kn ll=K˜ n−1 ll − ˜ Kn−1 lr O⎡
⎣
K˜n−1 rr +K˜couplell K˜ couple lr ˜ Kcouplerl K˜n−1 ll +K˜ couple rr⎤
⎦
−1˜ Kn−1 rl O ˜ Kn lr=− ˜ Kn−1 lr O K˜n−1 rr +K˜couplell K˜ couple lr ˜ Kcouplerl K˜n−1 ll +K˜ couple rr −1 O ˜ Kn−1 lr ˜ Kn rl=− O K˜n−1 rl K˜n−1 rr +K˜ couple ll K˜ couple lr ˜ Kcouplerl K˜n−1 ll +K˜ couple rr −1 ˜ Kn−1 rl O ˜ Kn rr=K˜nrr−1− O K˜n−1 rl K˜n−1 rr +K˜ couple ll K˜ couple lr ˜ Kcouplerl K˜n−1 ll +K˜ couple rr −1 O ˜ Kn−1 lr (29)
Since each alignment contains few degreesof freedom (for mostcases not reaching the hundred figure), each evalu-ation of (29)isvery fast,and within afraction ofsecondsthousands ofcellscan be simulated.Also, aslong asthere is some damping(inpractice,thatisalways thecase),matricesK˜n
lr andK˜ n
rl willgoto zero,andmatricesK˜ n ll andK˜
n rr will no
longerchange,meaningthattheleftandrightedgesofthemodelleddomainbecomeuncoupled.Inotherwords,assensed fromeachedge,oneiseffectivelymodellingasemi-infinitedomain.Inthisway,afterconvergenceoftherecursivescheme describedinEq.(29),thedynamicflexibilitymatricesH˜land/orH˜rarecalculatedwith
˜ Hl=
˜ Kn rr −1 ˜ Hr= ˜ Kn ll −1 (30)Thisrecursiveprocedurerevealedtobequitefast,andfortheexampleshowninSection5,ittakeslessthanonesecond to calculate the dynamicflexibility matricesforeach frequency, withn ranging between11(2048 cells) and15 (32,768 cells)forconvergencetobereached;theotherapproachtakesmorethanoneminute.Therelativeerrorbetweenthetwo approacheswasintheorderof10−4,meaningthatthetwoprocedureswillgivethesamevaluesuptothethirdsignificant digit.
Now that the dynamicflexibility matriceshave been derived, the only unknown components left in Eq.(12) are the displacementsuα,jextattheedgesofthesemi-infiniteregionscausedbyexternalloads.Thesearereferredtoastheincident displacementsandarederivedinthefollowingsubsection.
3.3. Calculationofincidentdisplacements(movingload)
The incident displacements at the edges of the semi-infinite domains are needed to account for the external forces applied at thesedomains. Forthe problemtackled inthis article,theseforces correspondto loads travelling atconstant speed,firstalongtheleftregionandafteralongtherightregion.Iftheincidentdisplacementswerenotaccountedfor,then atthemomentthattheloadenteredthemid-region,atransientresponsewouldbegenerated,withwavespropagatingboth towards theleft andrightsidesofthe interface andpollutingtheresults (the samewouldhappen whentheloadexited to the rightdomain). Of course,it can be argued that it ispossible to get ridofthe transientresponses by making the mid-regionlongenough,butthatwoulddefeatthepurposeoftheapproachpresentedhere,whichistoreducethenumber ofdegreesoffreedomandthereforethesimulationtime.
Similarly totheprocedureemployed fortheimpulse responsematrices,the incidentdisplacementsuα,jextare obtained fromtheirfrequencycounterpart,u˜α,ext
(ω)
,throughtheexpressionuα,jext= 1 2
π
+∞
−∞ u˜α,ext
(
ω
)
eInturn,thefrequency-domainincidentdisplacementsu˜α,ext
(ω)
canbecalculatedbycombiningtheresponsesinducedbyaloadmovingonaninfinitelyperiodicdomainwiththoseofpointloads,insuchawaythatthefreeboundaryisrespected. While theresponseofthe infinitedomainduetoamoving loadcanbe evaluated easily,the responseduetopoint loads still requiresthe evaluationof integralsover wavenumbers, rendering that method lessattractive. However, the stiffness matricesK˜n
ll andK˜ n
rr derivedintheprevioussubsectioncanbeusedtoobtaintheresponseoftheinfinitedomaintopoint
loadswhileavoidingtheintegralevaluation.Thewholeprocessisexplainednextforu˜l,ext
(ω)
.ConsideraverticalforcemovingwithconstantspeedV alongtherailofthe(infinite)domaindepictedinFig.1.Consider thatthisloadcrossesthealignmenti(fortheleftdomainthatiswherethefreeboundaryhastobeimposed)attimet=tl. This load induces displacements u˜ML
i at alignment i and displacements u˜MLii at alignment ii (these vectors contain both responsesoftherailandofthelatticemassesatthecorrespondingalignments,asexplainedinSection3.1;expressionsfor theseresponses canbe foundinreference[29]).Alongsidewiththedisplacements, themoving loadalsoinduces internal forcesatalignmenti(connectingforcesbetweentheleftandrightsidesofthealignment),whichcanbecalculatedvia
˜ fML i =
˜ Kcouplell K˜couplelr u˜ ML i ˜ uML ii (32) MatricesK˜coupleαβ arethesameasexplainedinSection3.2,andvector˜fMLi containsbothshearforcesandmomentsattherail, andconnectingforcesatthelatticebetweenalignmentsiandii,asexplainedinSection3.1.BecausematricesK˜coupleαβ contain stiffnesscomponentsofadiscretized Eulerbeamrepresentingtherail,some approximationerrorswillbe introduced,but theseareverysmallduetothelongwavelengthoftherailbendingcomparedtothediscretizationlength.
Now,inordertoimposethefreeboundaryconditionatalignmenti,(fictitious)forcesofamplitudesaficmustbeapplied
atalignmentiisuchthatthecombinedeffectresultsintherequiredboundarycondition.Thisstepisthesameasexplained inSection 3.1,withthedifference thatnowafic representsavector ofunknown amplitudesandnota matrix,dueto the
factthatonlyoneloadingscenarioisconsidered(themovingload).Thesefictitiousforcesinducedisplacementsu˜fic i andu˜ficii atalignmentsiandii,andconnectingforces˜ffic
i givenby ˜ ffic i =
˜ Kcouplell K˜couplelr u˜ fic i ˜ ufic ii (33) As mentioned already,duetoits computational cost,it isnot desiredto makeuseofexpressions in reference[29] to calculatethedisplacementsinducedbypoint forces.Instead,thematricesK˜nllandK˜nrr describedintheprevious subsection
are addedtothestiffnessmatricesK˜coupleαβ inordertoobtainthedynamicstiffnessmatrixofthefulldomainassensedby alignmentsiandii,andinthisway,thedisplacementsu˜fic
i andu˜ficii arecalculatedvia(Iistheidentitymatrix,Oisamatrix ofzeros)
˜ ufic i ˜ ufic ii = ˜ Kcouplell +K˜n rr K˜ couple lr ˜ Kcouplerl K˜couplerr +K˜nll −1 O I afic (34)After substitutingEq.(34) inEq.(33),theconnecting forces˜ffic
i induced bythefictitiousforces(ofyetunknown amplitudes
afic)aregivenby ˜ ffic i =
˜ Kcouplell K˜couplelr K˜ couple ll +K˜ n rr K˜ couple lr ˜ Kcouplerl K˜couplerr +K˜nll −1 O I afic (35)Thefreeboundaryconditionrequiresthatthereisnotransmissionofforcesbetweenleftandrightsidesofthedomain atalignmenti,whichisachievedbytheidentity˜fML
i +˜f fic
i =0.TakingintoconsiderationEqs.(32) and(35),thatidentityis satisfiedif afic=−
⎛
⎝
K˜couplell K˜couplelr ˜ Kcouplell +K˜n rr K˜couplelr ˜ Kcouplerl K˜couplerr +K˜nll −1 O I⎞
⎠
−1 ˜ Kcouplell K˜couplelr u˜ ML i ˜ uML ii (36)The incident displacementsu˜l,ext attheleft boundaryare nowcalculated bycombiningthe displacementsinduced by themovingloadandthoseinducedbythefictitiousforces,resultingin
˜ ul,ext=u˜MLi −
I O ˜ Kcouplell +K˜n rr K˜ couple lr ˜ Kcouplerl K˜couplerr +K˜nll −1 O I⎛
⎝
K˜couplell K˜couplelr ˜ Kcouplell +K˜n rr K˜couplelr ˜ Kcouplerl K˜couplerr +K˜nll −1 O I⎞
⎠
−1 ˜ Kcouplell K˜couplelr u˜ ML i ˜ uML ii (37)Fortheincidentdisplacementsattherightboundary,u˜r,ext,theprocedureisverysimilar,withthedifferencethat
align-menti isswitchedwithalignmentii,andthatthedisplacementsu˜ML
i andu˜MLii arecalculatedforthemovingloadcrossing the alignmentii atthetime instant t=tr=tl+Lm/V,whereLm isthelength ofthe mid-region.The finalexpression for
˜ ur,extis ˜ ur,ext=u˜MLii −
O I ˜ Kcouplell +K˜n rr K˜couplelr ˜ Kcouplerl K˜couplerr +K˜nll −1 I O⎛
⎝
K˜couplerl K˜couplerr K˜couplell +K˜n rr K˜ couple lr ˜ Kcouplerl K˜couplerr +K˜nll −1 I O⎞
⎠
−1 ˜ Kcouplerl K˜couplerr u˜ML i ˜ uML ii (38) 4. Example1-ValidationThe purposeofthe firstexample showninthiswork isto verifyall stepsof theprocedure.Forthat reason, a simple railwaystructure,consistingofrails,sleepersandballastrestingonarigidfoundationisconsidered.Also,inorderto com-pare theresultsobtainedusingthismethodwiththoseofreference[29],nostiffnessvariationisconsidered.The bending stiffnessandunit mass oftherail areEIrail=12.08× 106N.m2 andm
rail=120kg (correspondingtotwo UIC60 rails),the
width,massandrotationalinertiaofthesleepersareWs=0.3m,Ms=315kgandJs=4.73kg.m2,thesleeperspacing (cen-tre tocentre) isL=0.6m,andthethicknessoftheballastlayeris Hballast=0.3m.Railpadsare appliedbetweentherail
andthe sleepers,withverticalandrotationalstiffnesses Kv=108N/mandKθ=2.14× 105N.m (thesevaluescorresponds
tothepadsunderbothrails,andarebasedonthevaluesreportedin[33];therotationalstiffnesswasobtainedassuming that thepad isequallydistributed alongthecontactwiththesleeper,of lengthWp=0.16m, resultinginKθ=KvWp2/12),
andcorrespondingviscousdampingCv=105N.s/mandCθ=4.25× 102N.m.s.Inaddition,under-sleeperpadsareused
be-tweensleepersandballast,totallingaverticalstiffnessofKusp=1.72× 108N/mpersleeper[34] andcorrespondingviscous
dampingCusp=1.72× 105N.s/m(the trackwidthisassumedtobe 2.6m,sameassleeperlength).Thedampingvaluesof
thepadsassume aviscous dampingratioofC/K=0.001s−1.Inthefrequencydomain,theviscousdampingisconsidered viacomplexstiffnessesofthetypeK˜
(ω)
=K+iCω
.The propertiesofthe ballastare inferredfromthe boxtestresultsreportedby McDowelletal.[5].There,the authors subjected aballastsamplewhoseparticles sizesranged between25 and50mm (themedianwasapproximately30mm) tosuccessivecompressiveloads,andobserveda ballaststiffnessofabout300kPa/mm.Fromthereportedgranulometry,a particle sizeofd=0.03mwaschosen;thisresultsin11lattice massesper column(the bottomone beingfixed),N=11 lattice massesincontactwitheachsleeper (thestiffnessofthe under-sleeperpadsmustbe distributedby thesemasses) and M=9 free masses in between sleepers. On the other hand, the properties of the particle connections were deter-mined via an inverse problem, in which the springs of a lattice layer with the same thickness as the sample used in the box test (300 mm)were tuned to provide the reported vertical stiffness; together with assuming a Poisson ratio of
ν
=0.2 [27] and aviscous damping ratioofC/K=0.001s−1,the followingvalues were obtained:normallattice stiffness anddampingKnaxi=9.68× 107N/mandCaxin =9.68× 104N.s/m; shearlatticestiffnessanddampingKaxis =1.21× 107N/m
andCs
axi=1.21× 10
4N.s/m;diagonallatticestiffnessanddampingKn
diag=4.23× 10
7N/mandCn
diag=4.23× 10
4N.s/m.
Re-gardingthemasspropertiesoftheballast,anhomogenizeddensityof1800kg/m3 hasbeenassumed,whichtranslatesinto
a particle massofmb=4.21kg (this mayseema largenumber, butthisvalue accountsforall theparticles atthe same levelalongthewidthofthetrack,whichis2.6m).Forthedefinitionofthelatticeparametersandrailstructureparameters, thereaderisreferredtothepreviouswork[29].
4.1. VerificationofimpulseresponsematricesFαj
Before looking atthe response induced by a moving load, the intermediate steps are first verified, starting withthe calculation of the impulse response matrices Fαj. With that intention, the procedure explained in Section 3.2 is applied tocalculatethedynamicflexibilitiesH˜α andthentheir inverseFouriertransformasinEq.(15).Thetimeresponseisthen comparedwiththatsameresponseobtainedwithatimedomainsolver.Forthetimesolver,100cellsoftheperiodicdomain representedinFig.1 aremodelledbasedonafiniteelementdiscretizationoftherail.The100cellsresultin60moftrack modelledoneach sideofthefreeboundaries, whichislongenoughtoabsorb thepossiblereflectionsattheedges ofthe modelleddomain.Atimestepof
t=0.001sisusedforbothapproaches.Thecomparisonsoftheresponses(components ofFαj)aredisplayedinFig.5a-b(fortheverticaldeflectionoftherailduetoaverticalloadatthesamepoint)andFig.6 a-b (forthehorizontaldeflectionofthemiddlelattice massduetoa horizontalforceatthe sameposition).The subfigures c-d show thecorresponding componentsof thedynamicflexibilities H˜α (which cannot be compared since they areonly calculatedinthefrequencydomain).
AscanbeseenfromFigs.5–6,thecorrespondencebetweenblueandredlinesinsubfiguresa-bistothepointthat no differences canbe detected between theresponses obtained withEq.(15) andwiththetime domainmethod.There are neverthelesssomesmalldifferencesbetweenthetwo,whichcanbefurtherminimizedbyfurtherdecreasingthetimestep.
Fig. 5. Vertical response of the rail due to vertical load on the rail. a) impulse response of left boundary; b) impulse response of right boundary; c) dynamic flexibility of left boundary; d) dynamic flexibility of right boundary.
Thegoodcorrespondencebetweentheresultsobtainedwiththedifferentmethodsverifiesthevalidityofthisintermediate step.
By comparing Figs. 5a,c with Figs. 5b,d,it is observed that the response is larger for the left boundary than for the right boundary. This is because thespan between the free edge of the rail andthe closest sleeper is larger forthe left boundarythanfortherightboundary(seeFig.4),resultinginamoreflexibleinterface.Therearealsodifferencesregarding thehorizontalresponseofthelatticemassinFig.6 (easiertoseewhencomparingredlinesinsubfigurescandd),which arejustifiedbytheasymmetriccutdecidedfortheboundaries.
4.2. Verificationofincidentdisplacementsuα,j ext
Toverifyiftheproceduretocalculatetheincidentdisplacementsattheboundariesiscorrect,theresultsobtainedwith theprocessexplainedinSection3.3 arecomparedwiththoseobtainedwiththesametimedomainmethodasinSection4.1. The externalloadisassumedvertical,ofunitmagnitudeandtravellingalongtherailatconstantspeedV=60m/s.Fig.7 shows the comparisonfor thevertical deflection of therail at the boundaries, andFig. 8 shows the comparisonfor the horizontalresponseofthemiddlelatticemass.
Once again, the match between blue lines and red lines in Figs. 7a-b and 8a-b reveals a very good correspondence betweenthemethoddescribedinSection3.3 andthetimedomainmethod,thusverifyingthecorrectnessoftheformer.In addition,bycomparingtheresponsesoftheleftboundaryandthoseoftherightboundary,verydistinctbehaviourscanbe discernedthatarenotjustifiedsolelybytheasymmetryoftheleftandrightdomains.Thereasonforthesebigdifferences isinthemovingnatureoftheload;whileintheleftdomaintheloadismovingtowardsthefreeedgeandthenleavesit,in therightdomaintheloadsuddenlyentersitandthenmovesawayfromthefreeedge.Thatiswhytheresponseoftheleft boundaryincreasesgradually andthenshowsafreedecaybehaviour(startingthemomenttheloadcrossesthefreeedge), andwhytheresponseoftherightboundaryiszerountil theloadreachestheedge,thenpresentsasuddenincrease,and decaysafterwards.
Fig. 6. Horizontal response of the middle mass of the lattice due to horizontal load at the same mass. a) impulse response of left boundary; b) impulse response of right boundary; c) dynamic flexibility of left boundary; d) dynamic flexibility of right boundary.
4.3. Verificationofthewholeprocedure
The wholeprocess asexplainedinSection2 isverifiednext.Withthat intention,theresponses ofaninfiniteperiodic trackduetoa loadmoving attheconstantspeed ofV=60m/s andunit magnitudeobtainedusingtheproposed method andusingtheequationspresentedinwork[29] arecompared.Fortheproposedmethod,themid-regionconsistsoften iden-ticalcells,andforthetime step,two casesareconsidered:
t=0.001s(asinthepreviousexamples)and
t=0.0001s. Theresultstobecomparedaretheverticaldeflectionsoftherailatthecontactpointswiththesleepers.Becausethe mag-nitudeofthemovingloadisconstantintime,theresponseofanygivenpointattwodistinctcellsmustbethesame(apart fromatimeshift),andthus,theexpressionsin[29] areusedtocalculatetheresponseoftherailonlyatoneposition.
Fig.9 showstheresultsobtainedwiththe twomethods;Figs. 9aand9cshowtheresponses atthe differentpositions over time, asobtained with the proposed method, for the time steps
t=0.001s and
t=0.0001s, respectively, and Figs. 9b and9d show thesame responses forthe sametime steps, butwith time shiftssuch that the periodicityof the response can be assessed.Figs. 9band9d alsodepict indashed blackline thetheoretical responseasobtained withthe expressions from[29].TheverticaldashedlinesinFigs.9aand9crepresenttheinstantsatwhichthemoving loadenters andleavesthemid-region.
FromFig.9aitisobservedthatatthemomentsthattheloadentersandleavesthemid-region,somedisturbancesoccur that affecttheresults.Thisisalsoobservable inFig.9b,whereitcanbe seenthat theresponseofthe railatthesleeper positions is not perfectlyperiodic,i.e., there aresome disturbances around theexpected response(in dashed black line). The reasonforthesedisturbancesistheincompatibilitybetweentheassumptionsmadefortheleftandrightregions and those madeforthemid-region;while fortheformeritis assumedconstantforce duringonetime interval, forthelatter itisassumedconstantacceleration.Byreducingthetimestep,itisexpectedthattheinconsistenciesbecomelessrelevant, and such is proven inFigs. 9c-d, whereit is seen that no disturbances can be seen whenthe load enters orleaves the mid-region,andalsothat thereisavirtuallyperfectoverlapoftheresponses oftherailatdifferentpositions.Despitethe differencesbetweenexpectedandobtainedresponsesfor
t=0.001s,themaximumdeflectionis wellcaptured(only at
Fig. 7. Vertical response of the rail due to vertical load moving along the rail. a) incident displacement at left boundary; b) incident displacement at right boundary; c) frequency response of left boundary; d) frequency response of right boundary.
thefirst sleeperthemaximumdeflectionisslightlysmaller)andtheoverallshapeaswell.Thus, thistime stepisusedin theexamplesolvedinthenextsection,sothatthecalculationsdonotbecometootimeconsuming.
5. Example2– culvertpassage
To demonstrate the capabilitiesof the model,the case ofa railway line passing over a culvert is considered next. It representsatransitionfromasoftfoundationtoaverystiff foundationandagaintoasoftfoundation,andisbasedonan existing stretch ofthe Dutchrailwayline nearthecity of Gouda, whichis thoroughlydescribedin previous publications by otherauthors[35–37].Here,onlytheparametersthatare essentialforthesimulationaredescribed,andthemodelling assumptionsareexplained.
Fig.10 schematizes theconditionsatthesite:a culvert,withlongitudinaldimensioncorrespondingto foursleepers, is placed atthe depth of60cm belowtheballast layer; theculvert rests onpiles, makingit practically immovable(rigid); twoconcreteslabswiththicknessof30cmandlengthcorrespondingto7sleeperslieoneachsideoftheculvertwiththe intentionofmitigatingtheabruptstiffnessvariation;thefoundationconsistsofasandembankmentontopofclayandsand layers.
Forthesuperstructure(rails/sleepers/ballast),theparametersandmodellingstrategies(latticewithcharacteristic diame-ter d=3cm)arethesameasexplainedinSection4.Regardingtheunderlyingfoundation,itismodelledasalatticewith thesamecharacteristicdiameterd astheballastandwhosepropertiesarediscussedinthenextsubsection.Fortheculvert, since itispractically immovable,itismodelledbyconstrainingthemotionofalllatticemassesthatareatthelocationof theculvert(thussimulatingarigidandimmovablebody).Inturn,theapproachslabsaresimulatedbyassigningthe proper-tiesofconcretetothelatticemassesandlatticeconnectionsatcorrespondinglocations.Thepropertiesassumedforconcrete are Young’smodulus E=20GPa,Poisson’sratio