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A median-unbiased estimator of the AR(1) coefficient Preprint 575. IMPAN June 1997

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A MEDIAN–UNBIASED ESTIMATOR

OF THE AR(1) COEFFICIENT

Ryszard Zieli´nski

Inst. Math. Polish Acad. Sc., Poland P.O.Box 137 Warszawa, Poland

Key words: autoregressive model, median-unbiasedness

ABSTRACT

A proof is given that the median of the ratios of the consecutive observa-tions of a stationary first–order autoregressive process Xt = αXt−1+ Yt is

a median–unbiased estimator of α.

1. INTRODUCTION

The paper is concerned with the median–unbiased estimation of the station-ary first order autoregressive process

(1) Xt = αXt−1+ Yt, t = . . . , −1, 0, 1, . . .

with independent innovations Yt. To the best of my knowledge there

ex-ist only two papers in the subject which contain some constructive results, namely Hurwicz (1950) and Andrews (1993). Both are concerned with the case that Yt are i.i.d. normal N (0, 1) random variables.

Hurwicz (1950) observed that every ratio Xt/Xt−1, t = 2, 3, . . . , n, is a

median-unbiased estimator of α. In the basic version of the process (1), where

Yt are normally distributed, the ratio Xt/Xt−1 has a Cauchy distribution,

so that neither any ratio Xt/Xt−1 nor the mean (n − 1)−1Pnt=2Xt/Xt−1

can be efficient. However ”one might conjecture that the median of the ratios

Xt/Xt−1, t = 2, 3, . . . , n, would be a more efficient estimate of α and perhaps

an unbiased one” (Hurwicz(1950), p. 368).

Andrews (1993) constructed an exactly median–unbiased estimator of α however his proposal suffers from two disadvantages: 1) it heavy depends on the assumption of normality of innovations and 2) to apply, it needs numerical

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tables, separately for each number of observations used, or an appropriate computer procedure. An advantage of his approach was that the models he discussed were more general than our model (1).

The aim of this note is to prove that the Hurwicz conjecture concerning median-unbiasedness is really true. What is more, it appears that the median of the ratios is a median-unbiased estimator of α not only in the Gaussian case but whenever the medians of independent (not necessary identically distributed) innovations Y1, Y2, . . . , Yn are equal to zero. It follows that the

Hurwicz estimator is median-bias robust against heavy tails of innovations as well as against ε-contamination with contaminants symmetric around zero. The problem of efficiency is more difficult first of all due to the fact that it is not as clearly stated as that of unbiasedness, and will be considered elsewhere.

2. THE HURWICZ ESTIMATOR

Our basic assumptions concerning the distributions of the innovations are that the innovations are independent, their medians are equal to zero, and they are continuous in the sense that P {Yt ≤ 0} = P {Yt ≥ 0} = 1/2 and

P {Xt = 0} = 0 for all t = 1, 2, . . . , n − 1; otherwise the Hurwicz estimator

might not be defined. For a given segment

(2) X1, X2, . . . , Xn, n fixed,

of the process (1) consider the ratios X2/X1, X3/X2, . . . , Xn/Xn−1. To avoid

too many technicalities we assume that n is even so that the median of the ratios is uniquely determined. As an estimator of α we take

(3) αˆHUR = Med š X2 X1 ,X3 X2 , . . . , Xn Xn−1 ›

where Med(ξ1, ξ2, . . . , ξN) denotes the sample median of the observations, i.e.

if ξ1:N ≤ ξ2:N ≤ . . . ≤ ξN :N and N = 2k − 1 then Med(ξ1, ξ2, . . . , ξN) = ξk:N.

3. RESULTS

In the proof of the main result the following Lemma plays the central role. Lemma. Let ξ1, ξ2, . . . , ξN, N odd, be random variables and let c be a

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(C1) P {ξj ≤ c} =

1

2 for all j = 1, 2, . . . , N ;

(C2) for every m = 1, 2, . . . , N , for every choice i1, i2, . . . , im (1 ≤ i1 < i2 < . . . < im ≤ N) of integers, and for every x1, . . . , xm−1

P {ξim ≤ c|ξi1 = x1, . . . , ξim−1 = xm−1} = 1 2 Then P {Med(ξ1, ξ2, . . . , ξN) ≤ c} = 1 2.

Proof. First of all observe that for every m = 1, 2, . . . , N and for every choice i1, i2, . . . , im of different integers 1, 2, . . . , N

(3) P {ξi1 ≤ c, ξi2 ≤ c, . . . , ξim ≤ c} =

’ 1 2

“m

That is a simple consequence of the following calculations

P{ξi1 ≤ c, ξi2 ≤ c, . . . , ξim ≤ c} = = c Z −∞ . . . c Z −∞ P {ξim≤c|ξi1=x1,. . . ,ξim−1=xm−1}Pξi1...ξim−1(dx1. . .dxm−1) = 1 2 c Z −∞ . . . c Z −∞ i1...ξim−1(dx1. . . dxm−1) = 1 2P {ξi1 ≤ c, ξi2 ≤ c, . . . , ξim−1 ≤ c}

where Pξi1...ξim−1 is the joint distribution of ξi1. . . ξim−1.

Now we shall make use of the following formula for the distribution function of the sample median of dependent observations (David (1981), Sec. 5.6)

P {Med(ξ1, ξ2, . . . , ξN)≤ c} = N X m=N +12 (−1)m−N +12 ’ m − 1 N +1 2 − 1 “ Sm

where Sm is the sum of €mn probabilities P {ξi1 ≤ c, ξi2 ≤ c, . . . , ξim ≤ c}.

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P {Med(ξ1,ξ2, . . . , ξN)≤ c} = = N X m=N +12 (−1)m−N +12 ’ m − 1 N +1 2 − 1 “’ N m “ ’ 1 2 “m = ‚ N ! (N +12 − 1)!ƒ2 N +1 2 −1 X k=0 (−1)k ’N +1 2 − 1 k “ 1 k + N +12 ’ 1 2 “k+N +12 = ‚ N ! (N +12 − 1)!ƒ2 N +1 2 −1 X k=0 (−1)k ’N +1 2 − 1 k “Z1/2 0 tk+N +12 −1dt = ‚ N ! (N +12 − 1)!ƒ2 1/2 Z 0 tN +12 −1 N +1 2 −1 X k=0 ’N +1 2 − 1 k “ (−t)kdt = ‚ N ! (N +12 − 1)!ƒ2 1/2 Z 0 tN +12 −1(1− t) N +1 2 −1dt = 1 2

which ends the proof of the Lemma.

Theorem. If the innovations Y1, Y2, . . . , Yn are independent random

vari-ables such that P {Yt ≤ 0} = P {Yt ≥ 0} =

1

2 for all t = 1, 2, . . . , n, and

P {Xt = 0} = 0 for all t = 1, 2, . . . , n − 1, then the Hurwicz estimator ˆαHUR

is median–unbiased:

Pα{ˆαHUR ≤ α} =

1

2 for all α∈ (−1, 1)

Proof. For the sequence of observations X1, X2, . . . , Xn, n even, denote

N = n− 1 and apply the Lemma with ξ1 = X2 X1, ξ2 = X3 X2, . . . , ξN = Xn Xn−1 For ξj we have ξj = α + Yj+1 Xj

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Pα{ξj ≤ α} = Pα{ Yj+1 Xj ≤ 0} = Pα{Yj+1 ≤ 0, Xj > 0} + Pα{Yj+1 ≥ 0, Xj < 0} = 1 2 · Pα{Xj > 0} + 1 2 · Pα{Xj < 0} = 1 2 and the hypothesis (C1) of the Lemma holds.

Similarly, for every m = 2, 3, . . . , N , for every choice of integers i1, i2, . . . , im

(1 ≤ i1 < i2 < . . . < im ≤ N), and for every x1, x2, . . . , xm−1, taking into

account that Yim+1 is independent of Xi1, . . . , Xim, obtains

Pα{ξim ≤α|ξi1 = x1, . . . , ξim−1 = xm−1} = = Pα{ Yim+1 Xim ≤ 0|ξi1 = x1, . . . , ξim−1 = xm−1} = Pα{Yim+1 ≤ 0, Xim > 0|ξi1 = x1, . . . , ξim−1 = xm−1}+ + Pα{Yim+1 ≥ 0, Xim < 0|ξi1 = x1, . . . , ξim−1 = xm−1} = 1 2 · Pα{Xim > 0|ξi1 = x1, . . . , ξim−1 = xm−1}+ + 1 2 · Pα{Xim < 0|ξi1 = x1, . . . , ξim−1 = xm−1} = 1 2 so that the second hypothesis (C2) of the Lemma is satisfied and the Theorem follows.

ACKNOWLEDGEMENTS

The research has been partially supported by the grant KBN 2 PO3D 021 11. The author is deeply indebted to Hocine Fellag (Tizi-Ouzu, Algeria) for in-spiring discussions.

REFERENCES

Andrews, D.W.K. (1993), ”Exactly Median–Unbiased Estimation of First Order Auto–Regressive/Unit Root Models”. Econometrica, 61, 139–165 David, H.A. (1981), Order Statistics, 2nd ed., Wiley

Hurwicz, L. (1950), ”Least–Squares Bias in Time Series”. In Statistical

In-ference in Dynamic Economic Models, ed. by T.C.Koopmans. Wiley, New

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