À r
r..fl-STEVENS INSTITUTE OF TECHNOLOGY
EXPERIMENTAL TOWING TANK
HOBOKEN. NEW JERSEY
THE EFFECT OF SAdflG BñPACT ON A SHIP HULL STRUCTURE
Kazuo Ochi
or 53 Panel SNÄME
E.T.TO Project
2067Lab.
y. Scheepboijwkjrd
Technische Hoschol
Deift
INTRODUCTION
i
EQUATION OF MOTION AND ITS SOLUTION
DISTRIBUTION OF EXTNAL FORCE AMONG VIBRATION MODES
iS
1n'FXT OF EXTERNAL FORCE DURATION 21
CPARISON OF DERIVED SOLUTION WITH FITE DIFFERENCE METHOD
(Polacheck' s Solution)
COMPARISON WITH EXPI1XENTAL RESULT OBTAINED ON A SHIP MODEL
26
CONCLUDING RARKS 30 AC1VLEDGE4ENT 32 NIENCLATURE
33
REFERCES
35
APPENDIX (A) DETAILS OF THEORETICAL ANALYSIS 37
DERIVATION OF EQUATION OF MOTION 37
SOLUTION OF THE TRANSFORMED EQUATION OF MOTION
SOLUTION FOR RECTANGUlAR PULSE
t7
(A-Li) SOLUTION FOR SUSODDAL DISTRIBUTED FORCE
56
PREFACE
20 May 1959
This report was sponsored by the S-3 Panel, HuU
Structure Conriittee, of the Society of Naval Architecte and
Narine Engineers.
It
was prepared by Dr. Kazuo Ochi of the Transportation Technical ResearchInstitute, Tokyo, while
a visiting staff iiraber of
the Davidson Laboratory(formerly
Experimental Towing Tank). (SNAME Purchase
Order No. 113,
D. T. Project Oo 2O67)The S-3 Panel has decided to issue the report in this
rough preliminary fox to a few interested individuals.
It
is hopedthat the
author will publish a paper on the subject in due course.Meanwhile,
attention is
called to the method used for distributingthe external
force amongthe
different modes of vibratIon (pp. 15-18). This procedure is somewhatcontre-versal
and isnot endorsed
by the S-3Panel or the Davidson
TR0DUCT ION
The problem of hull stress in ships produced by a rapidly applied force, such as often occurs in a ship's slamming, is one of the most Ini-portant problems for a siip designer. Yet, few theoretical analyses of
a typical ship's structural response to an impact have been attempted be-cause of the difficulty of the transIent phenomena analysis.
The careful examinatIon of pressure and strain records measured on ships at sea or on model tests in towing tanks at the time cf slamming show that there exist two types of pressure and accompanying stress
dis-tributon0 In one type, the water pressure in the slamming area is
sud-denly applIed and soon removed. The duration of the load
iS
generally of the order ¿f 0.02 sec. or less for a full size ship, and a sudden change of hull stress occurs almost irrinediately and shows the maximum value at the first vibratory cycle after a slam. In the othertypE,
the pressure at slamming is gradually applied and may last for some3.5
sec. for a full size ship. A notable feature of this typeIS
that the critical 5treSs does not occur at the time of impact but some time later, say from the first tothe thIrd vibratory cycle after a slam. The typical examples of the former are seen in the records of the test made on the USCGC UNThAK at sea, (2) and model experiments at the towing tank while the typical example of the latter is seen in the record of the test on destroyer at sea
It is conceivable that the difference depends on ship form, ship speed and sea conditions etc., but this is not clear at present0 However, it is quite - certain that the vibratory stress, whIch seems to include several vibratIon
modes, appears a certain time after a slam in both cases0
In a slamming case, relationship between the applied load and the stress cannot be determined by the rules of statics, and it is necessary to inves-r tigate the elastic inves-response of a ship's hull stinves-ructuinves-re to a slamming impact0
In particular, it is important to evaluate the superpositIon of hull stresses resulting from various modes of vIbration and the resultant time history. A slaming impact excItes ship vibration of all modes and such a superpositIon of several modea defines the transient state0
The existing state of knowledge is briefly summarized in the seakeeping monograph by Progessor Korvin-Kroukovsky.
(6)
The known methods of solving-1-N - 97
the vibration problem, which were given by Timoshenko and others, treat mainly the steady state vibration reached under a continuously acting
per-iodic dstrbThg force, but do not obtain a satisfactory solution for a transient response. Taylor treated the vibration problem applicable to a transient phenomenon, but was primarily interested in the evaluation of the vibration frequencies0 He mentioned that a gradual shortening of the apparent period of vibration with tizne was oneof the characteristics
of the transient response. Frankland
(8)
treated the effect cf duration of force application and showed that the effect of duration becomes evi-dent and the 'namic load factor decreases when the duration of a rectang-ular pulse is short in comparison with the natural frequency of the struc-ture. McGoldrick obtained the solution for the response by the normal mode method and applied it to a steady state vIbration of a ship's hull, while Polacheck presented a finite difference solution for a partialdifferential equation of vibration f ôr use with a high-speed automatic digital calculator. In the paper of Ormandroyd and others
(1,
the de-tailed mathematical analysis of the vibration process, including shear deflection and shear flow, was atteirn,ted, but. it is regretable that the application to ship slamming was not mentioned. The author attempted to treat approximately a transient phenomenon, such as ship slaniming, by the recourse to the Heaviside Operator calculation. In the latter of the author's papers, he discussed the basIc properties of slamming stresses, especially the hull stress which was represented as resulting from summatIon of all modes of vibration.
In spite of these many investigations, the available material is not sufficient to permit discusrn a! the magnitude and time history of slam-ming stresses. The greatest obstacle, which has not been treated before, is the problem of distribution of an applied exciting force among various vibration modes. Inasmuch as the slamming stress is expressed by the
superposItion of various vibration modes, the applIed force should be ra-tionally distributed among these modes. This problem is avoided in a steady state vibration by concentrating on the synchronous conditions and assuming that in all but an insignificant part of the impulse is applied to the mode under consIderation The distribution should be a
-3-function of the position of the applied force, damping coefficient (dif-ferent for each mode) and of the duration of exciting force. The thve
tigation of the damping factor at different frequencies is important in this connection. In the present paper an £ttempt is presented to obtain a theoretical solution of a transient phenomenon in case of ship slamming, taking the foregoing comments into account. The main purpose of the paper is to discuss the time history of slamming stress obtained by superposition of venous vibration modes and proper consideration of damping factors,
In particu.Lar, the exciting force distnibuticn among vibration modes is evaluated in this connection. This is accomplished by an appication of the
least work theem0 The theory and the numerical calculation are mainly
discussed for a rectangular pulse of about 0.02 sec. duration in a full size ships However, a theoretical solution for a slowly applied force (a sinusoidal distributed force) is also given in the appendix.
In solving the problem outlined by the foregoing discussion, certain simplifying assumptions are necessary partly because of insufficient level of the present 1awwledge and partly in oriler to simplify the troublesome calculation0 These assumptions are: (1) Virtual mass is taken to be
con-stant during slam0 (2) Shear and rotary inertia effects are not considered.
(3)
Section of ship is taken as uniform. These effects should be taken into account in future work. The effect of virtual mass is considered to be es-pecially important, as it nay be a function of vibration mode and time.EQUATION OF MOTION AND ITS SOLUTION
Assume a
ships
hull as a simple beam withuniform
section shown in FIg. 1, the equation of the flexural vibration of the beam is given by the following formula0ET
(1)
where f
-Mass
of shIp perunit
volume. A SectIonal areaE
Young's
modulous I -. Moment of inertiaC-fluid damping coefficient
C- internal damping coefficIent
F- external force per unit length, which
is the
arbitrary function of x and t
The purpose of the present paper is to discuss the problem cf a
tran-sient phenomenon when an external force due
to slamming Is applied to the
ship hull, therefore it will be convenient
to introduce the HeavisideOper-ational transformation in
the above equation.Taking into account the
in-Itial condition as the displacemer.t
and velocity are zero when t
O. Theequation (1) iS transformed
as followa2
-dL4 T- E1(li- /1)
(2)
where-
ElCI
I
-P
pJ
where
out with respect to position. We get,
-t-0G
-'(o)t
ELCH-(/)
-
'z.
() -
)dt
q - Reaviside operator with respect
to position
tho,
)(3)
the
trans-ut
(14)into (3), the original equation of motion (1) is transformed
with respect to time and position0 That is,
%4
(o,)
(o,)
eEI(!
Cy)
(S)
N
-
-S-p
- HeviSide operstor with respect to time
f(x)
- Position function of n external force.
øf(P)
- Transformed time function
of an external force.
In the next place, the i-jeaviside operational transformation is carried
5L(q)TransforTned position function of
an external force.
If a
single
force is applied to an arbitrarypoint
Equation
(5) should be solved under the given
boundary conditionsand given
form of an externalforce.
The
boundary condit±on of a beamis considered to be both
ends free, that
is the bending moment and shear-ing force are zero at bothends.
AtfIrst,
the following condition at x - O is taken,namely
-= O
I
(Lt)(
= C
a3d
Equation (6) is transforned and put
into
equation () Itgives,
-4o)
dt
4_À4 EI)
By calculating
the inverse transformation with respect of q is carriedout
in equation (7),
+
t
(o,)
(8)
whereSL Ait-L) - J À(t-1)
C&4À)
(6)
=
(J2
/
)\))
N - LL97The boundary condition at the other end of beam
iS
applied to the equation (8), and two un1own functIons Ø(o p),
(o p) are de-terrnined as follows: where (d,) -
À-2)ì
Y)} g()
E1(i-a
l(C
)__-
P()
z'r
(ÀQ)4(cÀ-()
(4ÀL
1)
A(-.C)J 1(A)
p LAt-}
pRZ)From equation (8) and (9), the function (x p) Is evaluated.
(9) (Í-C)1 'Ck)- À(-:)}gcAL)
(i,
=
À(i-)1
EL(ItC,)A3
J L C-X1(ÀL)
A(-f(A)
-t-&(AQ.)(lo)
The above formula is applicable for l x 10 But 11 the origin
x O Is taken at the other end of beam and substitute
Cl
- l)i' or l
ail
-7-aboveforxiulas are also applicable for O x l ( the range of x is changed to i l x 1 in this case)o
Now a deflection of beam is obtained by carrying out the inverse transformation on equation (10) with respect to time. Prior to
proceed-ing with this transformation, the form of an external force çÇ (p) should be determined0 When a disturbance load is suddenly applied and removed
a short time t, as shown in Fig. 2(a), the function Ø, (p)
iS
expressedf
--p
I (F(-
)EI(l1CyE)À3
tA()} A)
-13(AL)fr-
Tt
The following calculation is for thIs rectangular impulse, the solution for slow2y applied sinusoidal distribution force is given later. The de-flection of beam for a rectangular puise is given by the following formula from ecuation (10) and (il).
r(À)-dA(-]
t)
-t-A)
(u)
(12)
In order to evaluate the deflection, it
iS
sufficiit for us to cal-culate the residues of the equation (12) at singular points. It gives,-N - 1497
-8-F-3)
IlL
(-L)9
(+3)(-!)
fA I 66o
2(6k)f
(z-3)4
2- 3)
(E-)5
(3-4î)
(-L
420 l2P- 60 + 204k
where
-
ì473O,7.853, 10.996,
iL,137 . . . .for each mode4 k
-rEi
L()(S4
(j
-
S4)
-
Cl/A(J/L)4}
E -
[i4
L CDistributed force in j-mode vibration at a specific point i
The ist group of the above f orrcula is a rigid body, rotatatory motion
of a beam which produces no
stress in the beam0 The 2nd group is asta-tical deflection, while the remaIning term
corresponds
to a transiita
s-(2ck).
60 2CL3[(rn)
_(w)
k
-
()
) X -x IF.
(Wi. \4'2Y
(%
)2[(
T +ç y) j j
.rA%C'Y)}
t
Íc
)4_,i
L 2YZ(»_i J
t +
E}
(13)
-9-deflectIon of the
beam.
Attention should becalled to the fact
that
the
equation (13) is a surrfnation of allforces acting at arbitrary points
and also is a summation of all possiblevibration
modes which are caused by anexternal force at the point.
So, the external force F1
at a specific point(distance l from the origin of a beam) should be distrIbuted among
all thepossible vibration modes.
Let force F1 be the force producing the j-mode
vibration (j - 1, 2, 3
..
.
u).
In other words,
the distributedenter-nal force
at a specific point produces the j-mode vibration, and
sunna-tlon of deflections caused by all these vibration modes
and
positions would be the final answer. The method of how to distribute the exciting force will be discussed in the next paragraph.From the deflection f orxnula for a rectangular pulse shown in equation (13),
a transient bending moment is
evaluated asfollows:
H =
c-L3)x..2
(2í.)t3
(A. 16-t-*iL
L X»j
')
+k-&)]
N -
¿497-
lo
-C()4t
[ck)4 C24
L}
fr
A steady state bending moment after the force is rcmoved is obtained
as follows by the same procedure as before.
M'F
where
{CgLie
X z.c4/ ()4;
!2fA ,2A CZ(if
[4
t /2pA r Jt
c"
4L
/2A '7? ,<-()
[(.i)
r(»1) - (1j)
))
'Çì (/ ()4}t
i fA /2[-L
tC
(J}2J
t WI J
(1g)
¿fA 4A'î;
t
C4J
t7()4tJ
'c-
il
-y2As mentioned before, a solution for O x l is obtained y the
saine formulas as (114) and (15) when the origin x - O is taken at the other end of the beam and a substitt.e(l - l)f or l. In this case, the range of x becomes i
- l x 1.
It is of interest to mention here that a bending moment (stress) in higher vibration modes die out in turn. This is easily comprehended from equation (15), in which the damping term
i3
proporti nal to the fourth power of the constant So, the term e- m
' will rap-idly decrease in the higher mode vibration and the bending moment due to the higher modes will die out
in
a very short time.The bending moment for a slowly applied force, namely a sinusoidal distribution load as shown in Fig. 2(b),
iS
obtained r the same method f or a rectangular pulseif
the function (p) is exr)ressed as the f ol-lowing formula instead of equation (11).-lip /'r
(t
(1(16)
N - 1497
12
-whereT2 - Duration of an external force for a sinusoidal d1strbution load0
i656)
't-f
where
\4'
I
4(4/
¡rnk)AtA(
L()-{rA
i2f4I wI 4
t2.
('Y
L24.(Y)4fl
-The first term of (17) gives a forced bending moment during the force
is applied, while the second term gives a transient bending moment.
6 F
(j) i)sǻyj
a
ç--(17)
13
-p(A(!S(À'X) JL
CV )
, 2 \412 J ç(XJ4A
C) À)
ÂC)
ik
{{À()
(A)À(!-!:)
C()4t
x 1-Ï(;V42]
fr
The steady-state bending moment is giv
as follows,
H
fC/-Ci/
[t
'24 y2(W4]
(4 I2e
(]]
IA /f4 CC()4ÌJ
'1A /2where
[ (»)
) () ]
['))
j
()
_C/
+C;()4}t
r./Ci
Ci
()4J
j
+ ¿ L(i)
24
¿rA' !2fcy f
21L
[(Y)-
'2f4 2f4j
-I
+ %A[(r_
%( r!J
i
N - b97
zj
(18),
The external force F applied at a specific point should be rationally distributed into each vIbratIon mode, because a deflectIon or a bending moment caused by an external force is expressed by the superposition of various vibration modes as mentioned before. Suppose these vibration modes are 1, 2, 3 . . ,u mode, an external force at a specific point F1
should be dIstributed in F11, F.2, F13. . .F1 for each mode. This is written as,
t).
(19)
A deflection at an arbitrary point
iS
expressed,z
(20)where is a deflection due to the j-mode, vibration caused by a distri-buted external force F. at a specific point i.
Bding manient at an arbItrary point is
M = EI Z1
(21)Ci the other hand, a deflection is expressed by a product of func-tion of x and t as is easiiy seen in equation (13),
X() T
(t) (22)X (y-),
where C is a constant, D is a function of j-mode andATj (t) are the func-tion of
x and
t respectively0From (21) (22), a bending moment is expressed by
Ei C
Fa (23)Strain enerr of a system is obtained as 2E1
=4'
Z
1.111 (
d L £t
-(it-i) (u-i) LkV
£:
. t=0
F1=
-2Y
---V
o
F2
z ---
o
'FL44)Now the external force F is a summation of F1 as shown in (19) If we consider a force Ff1, F12 . . . . are
independent
varIables and Fj is adepend3t
variable. Then, byapplying
the least work theorum, we get,(25)
16
97Readers may question whether the least work theorem is applicable in this case. A brief explanation should be mentioned here. As is well known, the least work theorem means that the magnitude of moment or stress
is such as to make the strain energy of the system minimunì for a body in equilibrium under a certain force. This theorem would be applicable in the dynaini.c problem if we take the strain energy of a whole system and the whole time during which a force is applied. Also, in a strict
mean-ing,
the right hand side of equation (2g) would not always be zero but equal to a deflection at the point where a force is applied. For exinple,the ist equation of (2g) would be expressed as,
j__
3I
, DF.,where
Y11 Deflection of the ist. mode vibration at point i As is shcwn later (see equation 28), each term is wrItten as,
2KF,
o
K
C' D ( d? 2K=
- CdX
L 2 d. t .1 C (a) (c) - 17-o
(b) -2 K F where=
ci,.
,Then, the equation (a) becomes
(2KL
C) F
-
=0
(d)It is proved numerically that the value of Cil in equation (d) is negligibly small compared with 2K.1. For example, we suppose a single force F 50 ton is applied at the point
0.075
L aft of the forward perpendicular of a ship 500 ft. length, duration of load is 0.02 sec, without damping. This is an example of numerical ciculation stated later in detail. For this case, the value of 2K is 2062 xio2
as is shown in a later paragraph (see table 1). While the value of Cil is T1 (t), wheref T (t) K 1
As is clear in this example, C1 is negligibly small compared
with 2Kilo Then the equation (d) becomes
Kil Fil
-K
F-O
iu iuIn other words, the above mentioned assumption is preferable and equation
(25)
is permitted in our case.Turning now to the proceding problem, V1, V2 . .
. .V1 in equation
(25)
are expressed by the following formulas respectively f rom equation (22) and (2).). Et -2'
I 2 - 2yCDF (T')
(t) dt -J L -r , - t 2;(
()dz
1T(t)
= K
2 (26)vfc
/ r.LV --'
¿
dX; dc o (e)=
where the function K..(x, t) is designated as
(e)
N - !97
18
-z
(
t) =
cL91 ()d
J1 T.(t)
t
From (25) and (19), we get
;
= 2
) V2= o
Fo
VL-
2 k
(27)
(28)
- 19)
Then, from (25) and (28),
K F
- K
F= o
K K F
0
(29)
E
LL
::I
I
F:.
L'
Equation (31) gives the distrituted f ca'ce among each mode vibration.
(31)
N 197 - 20
Fill F e .Fj(u_l) are ritten from (29)
F11 - K1.JK11.
-
K/K
(30)Fj(ul)
Ki(u_l)iu Fj
From(29)and (30) , F11, F12 . . . F are evaluated. They are,
N
21
-_____ EFFECT OF EXTERNAL FORCE DURATION
r It is of interest to discuss the effect of duration of loading on a
transient phenomenon0 The effect would be different according to a dif-ferent type of disturbance profile such as instantaneously applied rec-tangular type or sinusoidal one, so the discussion will be made on both cases0 Also, inasmuch as it is considered that the effect of damping seems to be of
secondary
importance in discussing the effect of duration of loading, the discussion will be made omitting damping terms0(a)
Rectangular Pulse
The factor N which is designated to show the
effect of duration of
loading is derived as follows from equation (ls).N
[i
2.[(-
c:y(y;4
(32)
If dainpings are neglected,
N -
21-cos
(mj1)2
J
-
2sin
(m1/kl)2 T1/2}
(33
While the period of the j-mode vibration without damping is expressed.
T1
2n/(_)
Coefficient C. is designated for convenience as
c
j
-
lj
(SS)
Then, equation
(33)
is simply rearranged
N - 2. sin
(c'ii)
(36)
From the above formula, it is easily conprehended that an effect of
du-ration of loading will be
maximum whena time duratin of rectangular
pulse is one hal.f of a period of the j-mode vibration, But actually,
the value of C1 is about 0.1 or so in case of general ship
I"
(b) Sinusoidal Distribution Load
The factor N ror a sinusoidal distribution load is from equatiofl (18)
If dampings are neglected
_(
C N-
p7)2
2(Ç;)
(::.(Ì)/)4
or
where
tir' ' (2Jc/ '\ S'2(4)
- Circular frequency
4C C64 (c«rc J(38)
(36!)
22
-I 2 AiA
Lc
4Xrfl
N-
[S- 'n42.
(% +
(37)
The absolute value of N versus C is shown in
Fig0 3(a).
Fig. 3(a) shows that a slight difference of duration of loading brings a marked effect on a bending moment (stress) in a transient phenomenon. In order to check this more clearly, n example of effect is numerically eval-uated for a destroyer and the factor N is shown inFig0 3(b).
In thiscal-culation, the values of natural frequency for each mode are taken the ex-perimental values on Destroyer C. R. WADE (length 383 ft.). On the other hand, the duration of loading is about
3°
or36
sec, for a destroyerof nearly the saine length. By the way, inasmuch as the equation (38') is indeterminate for 1/2, a special consideration has to be paid for this particular case0 But the value of is more than 3 even in the ist mode in case of an ordinary ship slanudng, so the equation (38) is enough
to evaluate the effect for ship slamming9
-COMPARISON OF DERIVED SOLUTION WITH FINITE DIFFERENCE METHOD (POLACHECK'S SOLUTION)
AS untioned in the introduction, Polachec1 presented a finite dif-ference solution for a partial differential equation of vibration for use with a high-speed automatic digital caicu1ator(:1. In order to check the propriety of the derived solution, comparisons were made between these two solutions under the sane conditions for two different dampings. The dim-ensions used in the calculation are as follows:
Length
Mass per unit length Sectional area
i -500ft.
fA1.5
ton-sec2/ft2 2A -5 ft.
N - ¿497214
-Young's modulous E - 2 io6 ton/inch2
Moment of inertia
I - 6
X ft.Damping Coefficient C/in- O and 1.
External force
F -5oton
(Rectangular Impact)
Position of applied force
-0.075 1 aft of the F. P0
(single force) Duration of Load
- 0.02 sec,
The eva1uaed distributed forces and bending moment at midship for each mode vibration in case of no damping are shown in Table 1.
The cal-culaticn formulas to evaluate are equations (31) (27) (114) and
(15). The evaluated percentages of distribution force for each mode are plotted in Fig. 14. As is comprehended in the figure,
the effect
of
damping is rec-ognized: for instance, the distribution percentage with dampingshifts to lower modes to a certain degree compared with no damping. It is clear that a tolerable percent of
the external force is distributed in this case, however it depends on the position where the external force
is applied. In order to ascertain this, an example of the effect of an impact
point
isshown in Fig. in case of no damping0
Fig. 5 is the one example, however
it
shows Important suggestions to the slamming problem.Because the con-siderable parts of an external force are applied the position between O.15L and 0.25 L aft of the
forward perpendicular in case of slamming impact for ordinary merchant ships, however a tolerable force would be applied near O.1OL aft of the forward perpendicular for full-form ships0
Now, a superimposed calculated bending moment is shown in Fig. 6 and 7 comparing with Polacheck's solution. It is regretable that we have the claculating sheets by Polacheck's method recorded at every 0.02 sec., so we cannot plot exact curves
including
higher mode vibration; however, so much for the comparison between these curves, it may serveto check the propriety of the present method. There is a considerable degree of correspondence between two curves. The reason for any des-crepancies may be considered in part due to the assumption that the present method does not include the shear and rotatory inertia terms0
!97
-COMP&RISON
wrrH
E)CPETh!ENTAL RESULTS OBTAfl'ED ON A SHTP MODELIn order to apply the present method to a slamming case, the numerical claculation on the deck stress due to the slamming impact is mode for one of the model ships (V-form forward) on which the experiments were made by the author
The principal dimensions of the model are as follows:
(19.68 ft.) (27l ft.) (1.714 ft,) (1.63 inch2)
(1,575
lbs.)(25143
inch14)(15,358
x io3
psi)
(11.8 inch)Model speed and draft under consideration were 2.141 rn/sec.
(F -
v/ /-jI
O322)
and 20.0 cu(787
inch) respectively, and the model.suffered a heavy slamming under this condition. The measured duration of load was 0.005 sec. Virtual mass coefficient is assurued to be equal to each mode and is taken as 1.2,
In the numerical calculation, the applied impact force in ship bottom is obtained by multiplying the measured pressure
by
bottom pressure area, and this impact force is divided into five parts for the convenience of calculation, namely 00/lOL, 1/bL, 1.5/bOL, 2/1CL and2.5/bL
aft of' the forward perpendicular0 The stress on deck is calculated by the super-position of the stress due to each distrIbuted force and up to 7th. mode0 The divided force into five parts are as follows:N - 1497
-
26
-Length L - 600 cm Breadth B -
82.6 cru
Depth D - 53,0 cm Sectional area A -10.5
cineDisplacemit at light draft
W
7)5 kg
Moment of inertia
I - 10,550 cm Young's modulous (brass)
E - 10,7140
kg/xnim2Distance between deck and neutral axis
These will
be
distributed among each mode vibration.The derivation of damping coefficients used in this numerical calculation will be mentioned in aetail in Appendix (B). The main point of the derived method is that
McGoldrick's
formula (h1 is modified using Sezawaspaper(1,
as the model is made of brass. The damping coefficients
C1/2fA + cI/2?A (N/1)
By using these coefficients, the distribution percentage of the external force among
each mode
at each point is obtained as shown in Fig08.
It is evident from this figure that the higher modes
should not
beneglected
in atransmet phenomenon such as slamming case even though these are damped in
a short time0
The
time history of the superposed stress amidship is shown in Fig.9
with the experimentally measured stress0 The superposed stress curve agrees quite weLl with the experimental curve except on the ist cycle, and a great
deal can be learned from the comparison.
(1) The higher mode stress, say
the 7th. mode stress, cannot be neglect at the beginning stage of the calculation of vibratory stress due to slarrmiing however it dies out quickly with large damping.
ed are as follows (see table 2)
Vibration mode
Cf + CI (M/i)
C1 +CT
(M/l)L
2k
2rA.o 1 1.300020l
23.033
0.0171
3.623
0.0168
9.677 0.0168 5 ]J4.1i57 0.0168 6 20.196 0.0168 726.877
0.0168
27
-F,00 L aft of F.?. j,2 Kg(70 Lbs0)
F,0.10 L
1008
(238)
F,00l L
28 2 (62.0) F,0020 L .0(96 8)
F,002
L 30 .1.(66.9)
Even though the
th mode stress is negligibly small from the
beginning, the 3rd mode stress should not be
neglected throughout the
time history, because its effect is still large near
the 14th cycle of
the vibratory stress and the maximum basic wave
sag$ng stress will be
superimposed near here.
Damping coefficients which are derived by the before mentioned
procedure are proved to be proper0
Now, the large discrepancy between the calculated and experimental
stress values is recognized in the ist cycle.
In the experiment, the
deck stresses were picked up by the resistance typo wire strain gauge and
megsured in the osoilograph. The natural frequency of the vibrators of
the oscillograph were about 900 cps or so, and were sufficient to record the
phenomena.
Also, the experimental stress value of the ist cyice are not
thought to be excessively high in this case, in comparison to the other case
in the series tests.
Therefore, the discrepancies of stress value at the
ist cycle may be considered dependent on some other reasonable causes, Lut
they can not be ascertained at the present stage.
The distribution of the slamming stress on Ship deck at each cycle after
the impact force is removed is shown in Fig. 100
The measured one is also
written in the figure. From the consideration of this figure, it is of
in-terest to note that the maxinum stress is recognized somewhat forward of
ainidship, that is about 0.142 L aft of the forward perpendicular at the ist
and the 2nd cycle, and it will be amidship at or after the 14th cycle. The
experimental results show the same tendency as the theoretical results,
how-ever discrepancies are recognized beteen their absolute values at the ist
and 2nd cycle.
The property that the distribution of the slamming stress on deck shows
the maximum somewhat forward of amidship immediately after the siazmuing
im-pact was recognized in the results of the several model experiments.
(II)
This is now proved theoretically by the superposition method of all proper
vibration modes.
The next problem is to discuss at what time the highest stress occurs
after the slamming impact, or to see the instants of time various events
occur when the impact stress is superposed on the basic bending stress.
From
N - 1497
the exçerimental data, the basic hogging and sagging stresses ainidship are 0.12 Kg/mm2, (5 - -0.l Kg/mm2, period is 113 sec., and the
slam-ming occurs 032 sec, after the maximum hogging in this case. The behavior of the midship stress with time which is obtained by the superposition of the basic bending stress and the impact stress is shown in Fig. 11.
From the consideration of Fig. 11, the highest stress which is super-posed on the basic bending stress occurs in the interval between 0.11 and 0.23 sec. after the slamming impact except the ist cycle. This corresponds to bet-ween 0. and 1.1 sec. after the slamming impact in case of the full size ship. In other words, the highest stress occurs about the ¿th cycle, in the vacinity of which the maximum sagging appears.
The magnitude of the superposed high stress in the vacinity of the
xmax-imum sagging is about l.l. times the values of the basic sagging stress. This shows a little higher value than the value described in the experiments on the full size ship (the value for the full size ship is said to be about 1.2 or
1.30.). This discrepancy seems to depend on the fact that the experiment was made in the light draft cOndition and very high speed, namely in the very
se-vere slamming condition.
-CCLUDThG RFLkRXS
0n the basis of the theoretical work on the elastic response of the slamming impact and from the comparison with the other solution and ex-perimental results, several conclusions can be drawn0
These are as follows:
jì
elastic response, namely a vibratory stress which is produced by the impact at the time of ship slamming seems to include several vibra-tion modes, The higher mode vIbration should not be neglected at thebe-ginning stage of slamming however it dies out. quickly with large damping0 The above mentioned high mode vibrations die out in turn. For example, the 7th mode vibration dies out after the 2nd cycle, th mode (though its amount is small at midship compared with the other mode) dies out after the 3rd cycle, and the
3rd
and the ist mode vibration remainip to the time the basic bending stress curve reaches the maximum sagging condition,
A distributIon of an external force due to slam shows that it seems to be a function of the position where the force Is applied, and also a function of duration of loading and damping coefficient.
(ti) The distribution of the slamiiing stress shows the maximum
some-what forward (00b2 L aft of the forward perpendicular) immediately after the impact force is removed, and the maximum shifts toward midship after several cycles0
() The stress superposed on the bas±c bending stress shows the high-est stress in the interval between O5 and l..1 sec, in the full size ship after the slain except the ist cycle0
The magnitude of the superposed high stress in the vicinIty of the maximum sagging is about lli. times the value of the basIc sagging stress by the numerical calculation0
External damping due to the generation of pressure wave seems to be not negligible in the ist mode vibration, it takes about 20 % of the
total damping in the ist mode. It is sufficient to consider only the in-ternal (structurai) damping in the other modes.
N - Lj.97
-N - L97
31
-(8)
The effect of a duration of loading for a sLwy applied force
is remarkable0 Â slight difference
of duration seems to bring a marked
ACOGET
The author wishes to acknowledge the kind advice and instruction of
Professor B. V. KorvinXroukovs1 and the encouragement and help of Professor E. V. Lewis, under whose guidances this work has been carried
out. Also, the author
would like
to extend hIs thanks to Dr. P. Kaplan who read through the mathatical part of the paper and kIndly gave some helpful suggestions0N - t97
-N - L97
33
-N EJCLATURE
1 Length of beam
12 Length of beam between a specific point i and an original point
y Deflection of beam
f
Mass per unit volume A Sectional areaI
Momt of inertia
E Young's modulous
C Internal damping coefficient C. Fluid damping coefficient
F External force applied at a specific point i
Distributed force of F4 among the j-mode vibration V Strain enerr of the whole system
Strain iergr of the j-mode of vibration
p Heaviside operator with respect to time, namely d/dt q Heavisde operator with respect to posìtion, namely d/dx
Notation which means Heaviside operational transformation Notation which means inverse operational transformation (xp)Transfornied function with respect to tIme
(qp)Transformed functIon with respect to time and position
øf(xP)Transformed function of an external force with respect to time
(f(qp)Transfor1ned function of an external force with respect to time and positior
T
Duration of an external force' Phase lag
w
Phase lagT Period of the j-mode vibration of beam
C The ratio of duration of time to the period of j-mode vibration,namely
/T
N Factor which shows an effect of duration of loading mj Constants, suffix j means the j-mode vibration
PAp 2+Cf P
Er + cup
k-"* o( (x)
-
(Cosh x + Cos x )
(xisj(Sinhx+Siflx)
' (x) -
(Cash x
- Cas x )
-
(Sixth x - Sin x )
(x) -
(Cash x Cos x 1)
(x)(CoshxCosx+1)
-
.(Sixth x Gos X
- Cosh x Sin x)
2(x) -
.(Sinh x Sin x )
97
31
-RTFEN CES
Jasper, N. H. and Birmingham, J. T. : Sea Tests of the USCGC
UNIMAK, Part 1. General Outline of Tests arid Test Results, DTMB Report No. 976
(1956)
Greenspon, J. E. : Sea Tests of the USCGC UNIMAK, Part 3,
Pressures, Strains, and Deflections of the Bottom PlatIng
mci-dent to Slamming, DTMB ReportNo0 978 (1956)
Akita, Y. and OchI, K. : Model Experiment on the Strength of Ships Moving in Waves. Trans. SNAME
(1955)
(Li) Ochi, K. : Model Experiments on Ship Strength and Slamming in
Regular Waves, Trans. SNAME
(1958)
(under printing).Warnsick, W. H. and St. DenIs, M. : Destroyer Seakeeping Tra1s,
Proceedings of the Symposium on BehavIor of Ships in a Seaway(1957)
Korvin-Kroukovsky, B0 V0 : Seakeeping MOnograph
(1957)
Taylor, J. L. : Dynamic Longitudinal Strength of Ships, Trans0 INA
(19L6)
Franklarid, J0 M. : Effects of Impact on Simple Elastic Structures, DTMB Report 1L81 (19b2)
McGoldrick, R. T. : Calculation of the Response of a Ship Hull to
a Transient Load by a DigItal Process, DTMB Report 1119
(1957)
(lo)
Polacheck, H0 : Calculation o± Transient Excitation of Ship Hulls by Finite Difference Methods, DTMB Report No. 1120(1957)
Orrnandroyd, J., Hess, R. L., Hess, G. K., Wrench, J. W., Doiph, C. L., arid Schoenberg, C. :
Dynamics
of a Ship's Structure,University ofMichigan,
(1951)
Ochi, K. : On the Stress Distribution of Ships at the Slamming Speed,
Trans, Tech. Res. Inst. Report No.
19 (1956)
Och!, Ke : Some Consideration Concerning the Effect of Slamming
Impact on Hull Structure, ETT Note No. ).79 (1958)
(1L) (cGoldr1ck, R. T. : Comparison Between Theoretically and
Exper-ientally Determined Natural Frequencies and Modes of VIbration of Ships, DTB ReDort No0 936
(195b)
Sezawa, K. : Damping Forces in Vibrations of a Ship, Trans0 of
Soc. Nay. Arch0 of Japan (1936)
Sezawa, K. : Die Wirkung des ddrucks auf die Biegungschuwingung
eines Stabes mit innere Dampfung, ZA1 (1932)
(1?) Suyeh±ro,'K. : c the Damped Transversal Vibration of Prismatic
Bors, 3u11. Earthquake Res0 Inst. Tokyo Univ. (1929)
Whittaker and Watson, : Modern Analysis (1915)
Taylor, J. L. : TJbration of Ships, Trans0 INA (1930)
Kumai, T. : DampIng Factors in the Higher Modes of' Ship Vibration,
Res. Inst. Applied Mechanics Report No. 21, Kyushu Univ. (1958)
N - 1197
-APPDIX (A) DETAILS OF THEORETICAL ANALYSIS
(A-l) DERIVATION OF EQUATI( OF MOTION
Suppose a ship's hull as a simple beam shown in
Fig0
1, the equation of a flexural vibration of the beam including damping terms is derIved by the following procedure. Tangential viscosity and Tensile viscosity are assumed being proportional to the velocity of shear and tensile strainsrespectively, so they are written, Tangential viscosity
TensIle viscosity
where C! C" are coefficients, ' and a are shear and tensIle strains0
i i
A lateral motion of a bar per unit length including tangtial viscosity is given,
2 C'
__
2I5 +(2)
at2 x G
where f) Mass of ship per unit volume including virtual mass A - Sectional area
S - Shearing force
G - Modulous of rigidity
An angular motion of a bar per unit length including tangential and tensIle viscosIties Is given,
rT
-
-
+
where I - Moment of inertIa M - Bending moment
E - Young's modulous
By differentIating wIth x, it gives,
a3 I S -' C M
r I
--
t) =
-'-
5t)
E
From (2) and (3'), the terms including S are eliminated.
II c ti4t c
2t
(1) C" i(3)
(3')
37
-CA.
C:M
-a
t
?LL
-i-
-ì-WhIle a
bending
moment is given,2
MaEI
Then,
equation(b)
is rearranged,pT
(\ Ef
-
cI
r
2 -
-
&If a transverse dimension of a bar i
ll enough
compared with its length, the first term of the right hand side of equation(6)
will be negligiblysmall.
Then,
equatIon(6)
is simply wrItten,(7)
where a coefficient C. is substituted for C for
simplicity, this corresponds
to an internaldamping coeffIcIent Ó±
bar0 Equation (7) was derived byezawa(16)
and Suyehiro many years ago.
In case of
a forced vIbration due to an extsrnal force F (x, t) and If a fluiddamping is considered, equation (7) would be
as follows,
-.44
A-
tEI----F(t)
(8)
where Cf Fluid damping coefficIent.
The purpose of the present paper is to discuss the
problem of
a transient
phenomenon when an
external force due to slamming is applied to ship's hull,therefore it will be convenient to introduce the Heaviside operator in the above equatlon. First of all, the
Heavlside
operational calculation is carriedN - 2j97
-out with respect to time,
arid a tr.nsfonned term of y (x, t) ±s wrItten
as ' (x, p). That. is,(9)
N
--39
-where p - Heavislde operator with
respect to time,
d/dtor it Is wrItten
symbolicallyy (x,t)
' (x, p,)
(10YIn proceeding
the transformation in
equation (8), the following transformation formulasare used.
t)
.(z)
(o)
t)
p(2
o)-
(z,o)(:L t)
d4
D
p7; ((zc)
An
tea1 force F (x, t)
in the right hand sIde of equation (8) istransformed as
follows,F (x,t) - f(x) g(t) £(x) (p) (12)
The initial conditions are taken as velocity and
dIsplacement are both
zero when
t
O, namelyat t - O, y (x,cJ) O
(13)
(20)
N - li97 - 0
-Put (11) (12) into (8) and taking consideration of (13), the
trans-formed
equation of motion with respect to time is obtained._
(]J4)where
I EL
(1g)
In the next place, the Heaviside operational
transformation is
carried out with respect to pos1ton x, andthe
transformed term of Ç' (x, p) ±s written as(/i
(q, p)0
That is,
-(16)
where q is the Heavislde operator.with respect to
position,
d/dt or lt is written symbolically,çi (x,p) :
P (q,p)
(17)In proceeding the ci1cu1ation, the
following
formula is used4()_
(o) )-(18)
The term of the external
force f (x)
Ç (p) In the right hand side ofequatic (iii.) is written by transformation,
f(x)
ciÇ (p)
*f()
f (P)(19)
Put (18) (19)
into equatIon (Th), the transformed equation of motionwIth respect to time and position is obtained as follows,
(
À) ()
+
+
-(ó,,b\
Here, we consider the
function of
(/
(q) for a single force at a
specific point x - 1,as shom in Fig. 12.
If a force,
magnitude of whichis F,
iS
assumed to apply uniformly between x l and x - oo, it isext'ressed by the transformed form
as
F1
e1i
(21)Similarly, a force applied uniformly between x -
l
+ Land x
-00
is written,+ 1 )
Fe
i i (22)Therefore a force F1 between l + and i. is obtained from (21)(22).
:
Fe -
The.
;
- 2i.
(t-2. .21--
(L.)
-n -(23)For unit length Al. -1, the transformed function of Pf (q) is obtained,
Pf (q) - F1 q (2L)
Put
(2L) into(20)
the originalequation
of motion (8) is transformed as follows,(_
4)
(A-2) SOLUTION OF THE TRANSFORME EQUATION OF MOTION
We now solve the given transformed equation of motion (2g) wider the given boundary conditions and given form of an external force0 The boundary condition of beam is considered to be both ends free, that is the bending moment and shearing force are zero at both ends. At first, the condition at x - O is introduced. The condition is,
In the transformed form, (26) becomes
d2
l(O, p) O
(o, p) - o
3.
So, equatIon (25) becomes,
-(À)
(o)+
(28)In the above equation, (O, p) and
3
'(o,
p) are still unknown, but these are obtained by taking consideration of the boundary condition at the other end of beam. For thIs purpose, the inverse operational trans-formation is carried out with respect of q. Equation (28) is rearranged as
-C)
(28')The ist term of equation (28') is inversely transformed by following procedure.
j1
4 (29) N - LL97-
I2 -d3dx3
t0
ci-Zoo
The integral path of
f.
means the path from C-ooalong the straight line parallel to theimaginary axis of the q-complex plane.
hi1e, by
using the Jordan's inrna(18), the integral pathf
would be equa]. to the integral pathf
,
that is the suui of thé integral along the straight lineparallel
to the imaginary axis from C-lao to C+iao and along the infinite closed circle from +iqo to C-ioo including the singular pointsin this domain. Then, the solution of equation (29) is to evaluate the re-sIdues at singular points in the domain (see Fig. 13). Now, returning to
equatton (29), the residue evaluation on the 1st term is carried out as follows,
where - (t'(Q
h\
-____
t-'
-2Ar
-c
i-4--
1+-LJ
c
1-
e1 )
4«o4)
L)(2
J
j.¿Aa
N -
97t3
-c
oÇ(A2..).c)
(30)
ç,( (À)
--
Al
- CAX)
(31)
Similarly, the 2ns term of equation (28') is transformed,
q
(1
I
-1)
(32)
where,
The 3rd0 term is transformed,
()
FA(-)}
45)
-À
ET('/)
A3where
=
Ax -
A(3g)
By using transformed
formulas (30) (32) (3L), equation (28') is transformed as,4(x
) -4- -()
ê 1:)
(36)
The boundary condition at
the
other end of beaii is now applicable tointroduce in equation
(36) The boundary condition Is expressed as follows,,t)(
o
Condition
(37)
is writtt in the transformed form,o
N - L97
-(314)(37)
(38)
From
(36)
and
(38),
two unknown terms
(o, p),
.'(o, p) are obtained0
In the procedure of claculation, the differtials of function
(À.) (Ax),(A))
are simply written as follows,
where
(hl)
-
(C4À-- CÀz)
The function
Ç' (O, p) and
'(O, p) are obtained,
4cc
)
=
c)
A((-)I
(()j
(A)
Ej((-t-C4
t)À3
=
1' ¡)
À(!_L)} (A)
d.
EI(HCr)Àl
where
)(A)
c)
(CJL ('JA D
(39)
(L1o)-
-From (!l) and (36), the function 9((x, ) i evaluated as follows,
=
F E.L (iYE)'
H 1(
_À(-1) À)
()43)The above formula is applicable for l.. x
l, namely for AB range of beam in Fig. 1. For BC range, all above formulas are also applIcable
if the origin x - O Is taken at the other end of beam and substitute
l_li
f or In this case, the range of x
is l-li x l.
Now, a deflection of beam is
obtained by carrying out the inverse operational transformation on equation (L3) with respect
to time, that is,
t)
-
q)(. p)Prior to thx proceeding
integratIon, the form of the external force should be determined.
A
Y()
-
À(-f
O)
±
N - 1497
-(A-3) SOLUTI FOR RECTANGULAR PULSE
When a disturbance load
IS
suddenly applied and removed after a short tIme ?, as shown in Fig. 2(a), the applied force Is expressed in the form of the Heaviside operational transformat,ion as,Then, a deflection of beam for a rectangular pulse is expressed by the fol-lowIng formula f rom (L3)
(144) (t5),
-P1-Li
i .iiL) EI((tC.,')A3
L
À(!-')} 1 i Àc)}
À)
It IS sufficient for us to evaluate the residues of the above formula at singular points.
(1. a) Residue at singular point p - O for O t T1
The 1st. term of equation
(6)
is expanded as a Series of p, considering p is small, -. { (%-EI(H-C1')
3 ErA3 2'V(iY
3!
2i_
2 p 1(A)j-- O
J 147 -'LA )- 1\(k- ) TCÀ) -(146) 7 ZÀ -fr 7! (147)Put (t7) into (L6), the residue of the ist. term of
(It6)
is obtained3
---
(x-i)
E t
Similarly the residue of the 2nd term is obtained by
expanding
a series ofp. That
iS,
4F
(2f-3' i
(It9)
TA ,
Ei (.
J
The residue of the 3rd. term becomes,
/2 F
c-4.
s-r (
Á-!)
-4.;)2
-)z
(2-É)x.
(so)
EI t /o 2.0
60
2O»
JTherefore the deflection of a quasi static motion of beam is the si.munation
of
(it8)
(149) (0),
that is F4@D_3)
1pg)
-
-.----
-t- -
-S-OPAL
-E.- Ç(ì._Í)
+3)(J-)
(2-3i)L4 (I2
42.0 /.2P+
C3-4)Z
('-')
[2.
20
4L
20P
uThe
ist. and the 2nd. terms of the above formula are rigid body and rotary motion of beam respectively, while the remaining terms correspond to a statIcal deflection of beam0N - 1497
148
-(148)
(I. b) Residue at singular point p - O for
The transfoniied function of tim (p) should be taken
(l_et1)
instead of i, as shown in equation (1). It is easily recognized that all residues are zero in this case.(2 a) Residue at singular points which satisfy
(xi)
O for O tEquation (146) has singular points which satisfy
L)=
(-Àt CÀ D o
(2)
If we write roots of the above equation as rnj (where j -2,
3, 14.
.the value of mj are as follows,
=
r 1473O,
± 7853
±:10.996
r ¿14.730,
ilO99ó
(3)
Each value corresponds to the ist, 2nd, 3rd . mode vibration respect-iveiy. Wow the residue is obtaned by carrying out the following calcu-lations,
-;-[3i(í4
&r:) -
/À(-)
(J)
(Sb)
In equation (3), -_(Xl) is evaluated as dp where dAL1t)
I(tt)t(Ej+çI)
4À3(ic'i
CÀL
- C..uA2
LÀi )
149
-(SS)
Then, the denominator of equation
(51) becomes,
-
-
EIt
[An]
4-,
FIt(J
-
pA ')
-
4-while, p is evaluated from equation
(15)
where
4
f-/
f.A'
Ei
Put
(57)
into (SLL), the summation ofresidues, nneiy
the deflection of beam is obtained. That is,u
F.
LkAt
C:/()fJ4]2}
[
y.)
(i.) J(b)
[()
y1)_ () F')] ()
LL(' )
At
cV(y)4/t
{(-
%4tC./()41
t E]
(59)
( /f-
-
tl
EI(Ct f-A')± n4(Er G1)
L
4À
(EL i- (I)2fr
Cs 2fA.i:1' 4
14\be
N - LL97so
(6)
(58)
where
L
¿
f4-y
Attention should be called to the fact that the equation
(59)
is a
summation of all possible vibration modes which are caused by an external
force at all points.
So, the external force P1 at a specific point should
be distributed into the force which causes the j-mode (j - 1, 2, 3 .
.u)
vIbration, and thIs is written as F.
lj
substituted for F in the
i
equations.
In other words, an external force F1
at a specific
duces the j-mode vibration, and sirrnnation of deflections caused
these vibrations concerning vibratIon mode and position of external force
should be the final answer.
The method of how to derive the distributed
force for each mode of vibration was mentioned in the paper,
(2
b)
Residue at singular points which satisfy
(xl) - O for
t
The transformed function of time
should be taken (l-e'
)instead of 1.
Then
ePt
in equation () is replaced by (l-e)e
proceeding the same calculation as before, a simunation of residues Is
ob-tained as follows,
\ /%i/ 4'j%)
- C41.
-
C%4())4
I
'T/
(fi' 4
L' W
'12tA(4
2J)
former
point
gro-by all
N - 197
51
-X[&()
?')
-. ¿[çt
[4t
(62)
Jt
{%Át
4J(tt
}- ¿_
2'
4 Q_
For a simplicity of calculation we use the following temporaly notations.
lì
e
L f
Then the time depìdit term in
equation
(62) can
be rearranged as follows,
'a ('g.
j1 ir
(63)
N -
!L97 -52
--' Ç()Y
---
J-
.) (_ ? ) J
_t
r
-M.e
C
LC'e-nY
jw) t
-e4:M) -
-) t
-t DM-t c c 7,<L (
J' (4):
_t
r
/_
I-L
- 2C
e
t
g -t/k;1
-2.
¡J
--w,
ml-; 2,uT ' f=
j -2C
n-)
e. :i
+(6h)
where
, , - -- tL
¿4Al-- W)
(
tT V1-ne. tC(7i2.z;
u ç-7ii
Therefore the equation (62) can be
written,
4 c
4fl4
2e
J(
4ri
t T;'i L w
;i-()t {) r)
()J
(-)
uj)
t
-(6S)-(66)
where
C%i
Y,:[(-
+(í)]
I ¡r%Ø)4
c[(r)4
+ A(E
From deflection formulas for a rectangular
pulse as shown in equations
(S7) (9)
and (66), bending monients are evaluated as follows,
Vj
()
t
LI
c'
-,+ 72tØ)
4 )(£4
L)
ÍAt
%(r I
(67)
)
jj
(68)
N - tL97
-+
As mentioned before, a solution for O x l is obtained by these f orrnuias when the origin x O is taken at the end of beam and substitutel_li
for In this case, the range of x is i - l x 1, It is of interest to mention here that bending moments (stresses) due to higher mode of vibration die out in turn. This is proved from equatIon (69), in which the damping term is proportIonal to the furth power of constant m . So,
_ímt/T
i
the term '
1. '
would r'apidly decrease in the higher mode Ibration,in other words, the bending moment due to higher rn e will soen die out at the beginning stage0
ft-s
Pv1--. L Li
C; / fi :/ ' r
- ¿2tA/-
"
J s E-1
(
[1y.4./+
t ri. r_[()
(-9
c)t
-)
11!
)'/
(?. tA )(r'!:'
s)]
ä(1--)
] t
-r-(69)
r y 5__5 -rLA(4r
t
{try
--17
'(f
(A-Li) SOLIJTÏON FOR SINUSOIDAL DISTRI3UTIGN FORCE
Vhen an external force is applied i.ii a sinusoidal form with time and
removed after a short time as shown in Fig. 2(b), the applied force is
ex-pressed in the form of the following Heaviside operational transformation.
&v otT
1 1-î-Jii-e.
) (TVLi
EL(c(-A-Then, a deflection of beam for a sinusoidal distribution force applied
at a specIfic point is
cpressed as following formula from
(Li3) (1111)and (70),
(M)
(71)
By the saine method as mentioned before, the integration in equation (73) is
evaluated by calculating the residues.
(1. a) Residue at singular points p
-
i (rr/-..)
forO tT
The residue in this case is obtained by carrying out the following
cal-cilatI on.
M - ¿4.97
-
-(jo)
1(A)
-LiJ
(A.)À-L)
À(/i ?(À)
(Àx)
'Ç
-r
This is the calculation for a forced deflection which is caused when a sinusoidal distribution force is
applied.
Inasmuch as the effect of damping is considered tobe small in a forced deflection, damping
terms may be neglectedin
the procedureof
calculation.Therefore,
is simply written, neglecting
damping coefficients,-
EICJ
El
in which
then,
where,
hile the term containing X in equation (72) shows always the same value
ir-respective of
var±ousvalues of X.
For example,
(7g)
(73)
-
-L-1
4 t \I / 1T-
¿JÀ
À = -'
-f
-(76) J
À(C-L)
JTherefore, the term
ÀL-L)
d-i)
&A) frW)o4(À)1-)\3
L
shows the constant value, incidentally the calculatIon Is sirnple By carrying out the calculation, equation (72) becomes,
-
t (-
¿J
(r
'v'id))})
À(Î-Nk-L) 1(u) Qf-J
¿Tt
-i/-tì
_iA)e
(4iT/q) N b97-k -4 '() À(-I
r(À)
A)
4(TÇ
) (77)fri'
OtT2
(1. b) Residue at singular points p
-V
j(k.
)=uj
In this case, the same calculatIon as shown in equatIon (72)is made
-p
multiplying (1 + e 2)
forN - L97
-
-JÀ(-
(A)-A(-!:)}
)(()
A(-L)
(À)-3
(78)
ÀL) ==ItCTn1'T)It is suffIcient to consider the time
dependent term
instead of
Sin in equation (77). While the time dependent termbecoines
St±/(t-'Tì= 2(t)Ca
=c
(79)Therefore the residue in
this case is
zero, In other words the beam has no deflectionafter a
time an ternal force is removed0(2. a) Residue at singular points which satIsfy
9(Xi)
-
O for o tThe
equation 5'(i) - O has many roots in. as alreadymentioned0
The
residues of
equation (71)about
thesesingular
points are evaluated by thesaine procedure as mentioned in the section (2. a for a rectangular pulse0 Tnat is, pt
A(--I)} (M)
JI
EI(j+ C p)À3(1y7).
d A(- : )T ()
AL)
+ (8o)The equation
(5g) (56) (57)
are also apnllcable in this case, then a
sian-rnaticn of'residues is obtained as f o1lcws,
where
X 4 I' +Ìf)i
Cj// CC«K(}] [t
( )+
fA[1Jïr-
7)_())J
(+)
C:(:
-fA ) LL(Th) 4-C'
rAizf4.
ç,
I "ZJ/(7()4Ì
[
)-L
/2AA(j
E. ).Z1(2
%AA(rJ
-
(N - ¿97
-60-ZJt }
(81)
(82)
(2. b) Residue at singular points which satsTy.(Xl) - O for
CalculatIon procedure mentioned iii (2. b) Thr a rectangular pulse is
also applicable in this case being replaced e in the equation (80) by
(I + e ¿it
The time depndt term in equation (81) is
14t
I, y2L2.
L (- )
(t
)n whichthe definitions of in, n are described in (63). The above formula can be rearranged às follows,