DELFT UNIVERSITY OF TECHNOLOGY MECHANICAL ENGINEERING DEPARTMENT
OEMO SECTION
TRANSIENT RESPONSE ANALYSIS
OF
MARINE PROPULSION SHAFTING SYSTEMS
BY COMPUTER SIMULATION
By: G.A. Schouten March 1996
SUMMARY
The dynamic behaviour of marine propulsion shafting systems is transient in nature and can be described under either steady state or transient operating conditions; the
former being a special case of the latter. The differential equations describing the
dynamic behaviour of systems take into account the non-linearities associated with engine and propeller operation over the speed range. However, it is normal practice
to linearise such non-linearities about the steady operating conditions in the
frequency domain calculation to enable the formulation of the problem. This meansthat a frequency domain calculation is unable to predict the response time of the
system in traversing the speed range of the system in response to changes in the
engine governor setting or variations in the propeller pitch settings.
Therefore, a time domain computer simulation program for the analysis of the
torsional dynamic behaviour of marine propulsion shafting systcms under transient
operating conditions has been developed. A modular approach is used for the
simulation, where the shafting system is considered to comprise a collection of
component models, each with its own set of dynamic characteristics. A fixed step,
fourth-order Runge-Kutta integration technique is used for time marching. The
correctness of the program has been demonstrated by comparing preliminary
torsional vibration results obtained from frequency domain vibration analysis andtime domain simulation of the system under steady operating conditions. Under
such conditions the frequency domain analysis and time domain simulation produce the same results. The initial conditions of shaft speeds and torques specified in the time domain simulation define the starting operating condition of a system and the simulation automatically converges to the steady operating condition, whereas the
frequency domain analysis implicitly assumes steady state operation at the given
conditions. The time domain simulation therefore presents a more realistic
representation of the system's dynamic energy balance by taking into account the
mean speed of the system and its velocity perturbations due to torsional
vibrationinstead of "assuming" a steady system speed as in the frequency domain analysis
thus
eliminating erroneous matching of
the operation ofshafting system
components and the associated non-linearities. The full capabilities of the time
domain program are then demonstrated by the simulation of a marine propulsion
shafting system example under transient operating conditions.
The time domain simulation is a comprehensive method for analysing the torsional
vibration dynamic characteristics of marine propulsion shafting systems under
transient operating conditions. However, frequency domain analysis is
computationally much more efficient in determining the torsional vibration response under steady operating conditions.
Delft University of Technology 1996 acknowledgements
ACKNOWLEDGEMENTS
The author wishes to acknowledge Dr. Kian Banisoleiman for his invaluable help,
guidance and supervision throughout the duration of this project. Thanks are
extended to Prof. J. Klein Woud for his help and constructive criticism during his
visits to London. Special thanks to Mr J. Carlton for the opportunity to work in the
Technical Investigation,
Propulsion and Environmental Engineering (TIPEE)
Department of Lloyd's Register of Shipping. The author is also very grateful to the staff of the TIPEE and the Machinery Design and Dynamics (MDD) Department for their help and suggestions.GENERAL NOMENCLATURE Ca; Ce kQ kr fill In (00
Q
No R, To old 1(4,, Vs (mm) (Nms/ rad) (Nms/ rad) (mm) (N)(/)
(kg.m2), (NM/ rad)(/)
(/)
(mm) (kg) (rpm) (rad/ s) (rad/ s) (Nm) (mm) (m)(/)
(mm) (N) (Nm) (rad) (rad/ s) (rad/ s2)(m/s)
(m)(m/s)
(m/ s2), boreabsolute damping coefficient relative damping coefficient propeller diameter
force
advance coefficient mass moment of inertia torsional stiffness coefficient propeller torque coefficient propeller thrust coefficient conrod length
mass
rotational speed
fundamental frequency natural frequency
propeller torque (in open water) crankthrow radius
gear radius gear ratio stroke
propeller thrust (in open water) torque angular displacement angular speed angular acceleration ship speed displacement. velocity acceleration
LIST OF CONTENTS
Page
INTRODUCTION 1
MODERN MARINE PROPULSION SHAFTING SYSTEMS 3
7.1 Straight Shafting System 5
-).') Branched Shafting System 7
FREQUENCY DOMAIN ANALYSIS OF PROPULSION SHAFTING SYSTEMS
TIME DOMAIN SIMULATION OF PROPULSION SHAFTING SYSTEMS 13
4.1 Modelling Technique 14
4.2 Sign Convention 14
4.3 Engine Crankshaft Model 17
4.4 Propeller Model 29
4.5 Shaft Model 33
4.6 Gearbox Model 35
4.7 Clutch Model 37
4.8 Epicyclic Gear Model 39
4.9 Ship Model.. 43
4.10 Program Structure 44
RESULTS OF TIME DOMAIN SIMULATIONS 46
5.1 Steady State Simulation and Correctness Testing 46
5.1.1 Simple Test System 46
5.1.2 Straight Marine Propulsion Shafting System 59
5.2 Transient Simulation of a Marine Propulsion Shafting System 69
CONCLUSIONS AND RECOMMENDATIONS 78
REFERENCES 80 APPENDIX 1 APPENDIX 2 APPENDIX 3 APPENDIX 4 APPENDIX 5
Lloyd's Register of Shipping Cylinder-line Model
Epicyclic Gear Simulation
LR 278 Vibration Analysis Results FORTRAN 77 Program Codes
1.
3.
1. INTRODUCTION
The dynamic behaviour of marine propulsion shafting systems can be considered
qualitatively as the temporal displacement, velocity, acceleration and jerk signatures ofthe system along its geometry and relative to a fixed frame of reference. This
behaviour is primarily due to the elasticity of the shafting system, by twisting,
elongation and bending in response to external forces exerted on the system from the prime mover, the propeller and out of balance forces. The dynamic behaviour of the
shafting system is also a characteristic of the shafting system's geometry, the materials used and the supporting arrangement in the installation.
As such, the shafting system transmits power mechanically from the prime mover to
the propeller and exhibits vibration characteristics due to intermittent and cyclic
nature of the external forces acting on the system. These forces predominantly
comprise firing in multi-cylinder Diesel engines and propeller blade passing frequencyin a non-uniform wakefield distribution, which exists around the propeller. Such
vibration characteristics are predominantly exhibited in the torsional, axial and lateraldegrees of freedom. The torsional and the axial dynamic behaviour of propulsion
shafting systems are coupled through both the geometry of engine crankshaft and the
propeller hydrodynamics. The lateral
dynamic behaviour is due to whirling of
eccentric misaligned mass centres and is minimised by careful positioning of bearings and alignment of the shafting arrangement.The dynamic behaviour of marine propulsion shafting systems is transient in nature and can be described under either steady state or transient modes of operation; the former being a special case of the latter. The steady state is typified when the engine
is running at a fixed operating point and a constant power is transmitted to the
propeller at a steady speed. The transient condition is when the operating point of theengine and the propeller are changing, due to changes in demand and power
imbalance, engaging or disengaging of a clutch, impact loading of the propeller or acombination of these.
The differential equations describing the dynamic behaviour of a shafting system and the associated non-linearities in the external forcing functions can be linearised about
the steady speed, for steady state operation. However, a description of the system
behaviour over a wide range of operating conditions requires the inherent
non-linearities in the total system over the entire speed and the torque range to be taken
into account.
Conventional techniques used for the analysis of shafting system dynamic behaviour
commonly adopt a frequency domain approach to
determine the
vibrationcharacteristics of the shafting system under steady operating conditions. This
approach is justified in the minimum energy state of the system at a steady speed
because the forcing functions required for operating conditions about a steady speed are cyclic in nature. Under transient operation however, when the speed is changing
significantly the non-linearities associated with speed and non cyclic forcing functions mean that the system dynamics can no longer be described in the frequency domain.
Delft University of Technology 1996
The objective of this thesis project is to develop a modular, interconnecting shafting system simulation program, which is suitable for the transient response analysis of
modern marine propulsion shafting systems directly in the time domain. Time domain
simulation of shafting system's dynamic behaviour allows a continuous transient
response analysis and forms a powerful tool in the range of marine
propulsionshafting system analysis capabilities. It can be used specifically for; Analysis of transient response in propulsion shafting systems.
Assessment of stresses in the shafting system during ship emergency manoeuvring.
Analysis of shafting vibration peaks due to engine misfiring or propeller blade
impact loading.Integration with time domain detailed engine and propeller simulation. Engine, shafting system and propeller matching.
A simulation environment for integrated ship propulsion system control for
traversing over the barred speed range.The development of such la time domain computer simulation program is presented in this report.
The report is presented in 6 chapters. Chapter 1 is the introduction. Chapter 2 presents
examples of modern marine propulsion shafting systems from which two typical
examples are chosen for further detail analysis. Chapter 3 presents the conventional theory of the frequency domain vibration analysis, for comparison purposes. Chapter 4 presents the developed time domain simulation program and discusses the models
of shafting system components. Chapter 5 presents a correctness testing for the
developed time domain program by comparing the results of the time domain
simulation with the frequency domain analysis under steady operating conditions. The capabilities of the simulation program are then demonstrated using a selected example of the marine propulsion shafting systems from chapter 2. The conclusions2. MODERN MARINE PROPULSION SHAFTING SYSTEMS
Lloyd's Register of Shipping (LR) is the world's premier ship classification society. The function of a ship classification society is to ensure that the construction of a ship is in
accordance with the standard of construction for safety of life at sea. A ship is
classified according to the standard of construction and equipment as stated in the
Rules of the classification society. The costs of the insurance of both ship and its cargo depend to a great extent upon this classification and it is therefore to the advantage of
the shipowner to have an internationally approved Classed ship. A brief overview of
LR's history, main activities, and organisation structure is presented in appendix 1. The ships which are built in accordance with the Rules of LR are assigned a class in the
Register book. For example, a ship is classed +100A1 when it is fully built to the
highest standard assigned by LR and surveyed during all stages of construction. The
additional +LMC notation is assigned when the propelling and essential auxiliary
machinery has been constructed, installed, and tested under the society's special
survey and in accordance with the society's Rules indicating that the ship has Lloyd's
Machinery Certificate.
Five typical examples of modern marine propulsion shafting systems are selected from actual ships. These ships are assigned the class +100A1 +LMC with LR. The schematic
representation of the five typical shafting system examples are presented in figure
[2.11. (Al BI IC)
>.<
2-STROKE ENGINE oKE ENGINE GEARBOX BEARING FLP-XIBLE coUPLING FLEXIBLE CLU1VH GENERATURMED PI 101PHI *FILER CONIBt)LIABLEBTTCH
PIP )PELLER
Figure 2.1: The schematic representation of _five typical marine propulsion shafting systems.
Delft University of Technology 1996 chapter?
The particulars of the systems shown are;
A two-stroke, low speed Diesel engine with a high number of cylinders coupled
directly to a fixed-pitch propeller through a straight shafting system.
A two-stroke, low speed Diesel engine with a low number of cylinders coupled
directly to a controllable-pitch propeller through a straight shafting system.
A two-stroke, low speed Diesel engine coupled directly to a controllable-pitch
propeller through a straight shafting system. A Power Take Off (PTO) branch is
coupled to the free end of the engine through a gearbox.
One of a pair of four-stroke medium speed Diesel engines distributing power by a
single reduction gearbox to a controllable-pitch propeller and a PTO-branch.
A four-stroke, medium speed Diesel engine distributing power by a single
reduction gearbox to a controllable-pitch propeller and to a PTO-branch which
comprises a shaft alternator and a flexible coupling. The PTO-branch is engaged or disengaged from the system by a flexible clutch.The shafting systems examples shown in figure [2.1] are used to propel a container
ship, oil
tanker, bulkcarrier, passenger/freight
ferry,and a chemical
tanker,respectively.
Two modern marine propulsion shafting systems examples were selected from these for further detailed analysis. The first one is example (a), a straight shafting system,
and the second one is example (d), a branched shafting system. These examples were chosen because they included the most commonly used shafting system components.
2.1 STRAIGHT SHAFTING SYSTEM
The straight marine propulsion shafting system selected is a typical configuration used for the propulsion of single screw container ships and comprises a two-stroke, in-line,
nine cylinder Diesel engine driving a six-bladed, fixed-pitch propeller. The general
arrangement plan of a typical single screw container ship is presented in figure [2.2].
The particulars of the selected straight shafting system are as follows (N.B. the
operating condition of the engine is presented at the Maximum Continuous Rating
(MCR) speed of the engine);
MAIN ENGINE PARTICULARS
Engine type: 2-stroke, in-line, turbocharged, single acting piston with crosshead, low speed, reversible type Diesel engine. power output (MCR)
engine speed (MCR) mean effective pressure number of cylinders cylinder bore
stroke firing order
SHAFTING SYSTEM PARTICULARS
intermediate shaft 1 intermediate shaft 2 screw shaft PROPELLER PARTICULARS propeller diameter number of blades blade area ratio pitch at 0.7 radius propeller inertia (kW) 11415 (rpm) 120.7 (bar) 16.46
(/)
9 (mm) 500 (mm) 1950(/)
1-9-2-7-3-6-54-8 (rrunxmm) 0 440 x 6540 L (mmxmm) 0 440 x 4000 L (mmxmm) 0 612 x 8317 L (mm) 5850(/)
6(/)
0.723 (m) 4.690 (kg.m2) 31700/"7'1' r.. GO 01 7,---*7.-..-.."-.`... Er; -1,:r...71-41E111 a__ -,-..-f..1,-1.1-r---.41_,: _ _11.-__722,.7._.-7 I., --lilt 00 00700 , DO 00 I, ilL L..q. IF ! ' I ," 00 II' I1 8 II 1:L11 -11 $717 11
7I
I 1 ,I ; I I 10 01 nI I s 1 'r "Jal I I oI /i 1 .;1 ' .1. ''L zt,rii., : 1 .-. .41.. .14,.=.,1-,-,. .01:11313111, L.':". '''' ' L9 -0 ^02 WO oro3.1tr..-
-F . rv t--- -r-I )""?':---V-. -., _F 4, I.:.._,f ..._:L!
( NM MG 0000 ..,... 1-?;...k. 11-=4. ...-!_1 j...i.,....Z.5... 1," If(' . 1 I .. -.11 -. $ ".n.... .0 ... I ''. c. -I .. . - -.,_- ,G -.,_.,_- ---...- .!: ,h.F:7 i; ,2-__' Fra_ro - 7 .. 'A 1177° ,1-7 7. -1-71*-- ''' I I A .. -I -r. V r .. V.-0... 1-- ... 444-, . t -..1 i____.:'. , .r.a.- ,.-41.1-_-. L'IVl..1-,,lv_i ,I. It ...._2,...,1 1_6.1_1-../ L 1. 4--.1. * ..--,1- ,...-.--',3 rse-mILIN11.113.1.:1411.7,.1 . -.. Co, W....e.1.-.4201N...0 V 100=1 0 14.5 r1:11111/,_,, 19-.01*.--!-I --; , `11 r ":, I
II II-II I I 11 1 11 1 1 I , ..1 NI,/ 0, ....0 .0 3 y .0l r ..-= , -_._ 1. 0. .r F---ar---I, -..., .3; ill, '',---3 i..k 3s '1 r,--'.;4-,-1, 5---:-.-r --71,:l 1.,---0-1-. 7. r 1 . 7 t S.' . . 142-4.1,-.-I I-tn., II' s !tn. na. -NI1101 W./ L._ ---4._ . .7: 7: r---F-- r---F-- _ _ _ -_.. IC -& f -42!:1. J1_la...132. p.m r4 _ .004 ,P,10 OM 01., IQ Fr I/ I -; 1- - I: ;,/Prr #4;;Vj A CORMASTLE MC. F. )01 Slt1.4-111 °N-41111.1.. 114_3111L,31. .:.-:1 ...:. :iv: : : ,.'1.' -2 ----, 0.---1 ....--.... ....,..e.:--1 - ---us :, 1":31.1 :L.:. 0.4104 ..0 e 10 P 77-0 .0.1 rOGO .70.0 1 . 1.0 .7 NMI, NO .00 NO 3 '00 .0.4 K. 3 1 .0.0 NI ;14.1odr...Nit....1 ...I ,.... f. ....1..;613,.4.(oj 1 ...L-....14 r"...t..-... 4....-...4... .I. ...-. --1 :a ... I. -. :-. - - ^1. 4,41 ....-t---i. 00 f M ".F...',.
-...t. MO z.-= IS ILL --:-.:-,_-__- : ...-vb-.." ---:.,..c:: : .a._: ..;.::: 00 ".: 7. _. z....,----L .."..t.. e . --Laj-1-11 -1 II II I Tr- -t-L\
-2.2 BRANCHED SHAFTING SYSTEM
The branched marine propulsion shafting system selected is used for the propulsion system of a twin screw, Roll On/ Roll Off (RO/ RO) passenger/ freight ferry. This
vessels is powered by four four-stroke, in-line, six cylinder Diesel engines operating at a constant engine speed. The two controllable-pitch propellers are each driven by one pair of engines through a single reduction gearbox. The electrical power is supplied by a shaft alternator driven from the gearbox.
As can be seen from example (d) in figure [2.1], the two engines and the generator on
the PTO-branch are separated from the gearbox by flexible clutches to prevent the torsional vibration being transmitted from the engines to the gearbox and from the
gearbox to the generator. Under normal operating conditions a constant engine
speed is maintained whilst the ship speed is governed by changing the pitch of the
controllable-pitch propeller..,
The particulars of the selected branched shafting system are as follows;
'ENGINE PARTICULARS
Engine type: 4-stroke, in-line, turbocharged, trunk piston, medium speed Diesel engine.
power output (MCR) engine speed (MCR) mean effective pressure number of cylinders cylinder bore,
stroke firing order
GEARBOX PARTICULARS
reduction ratio (engine-shaft) step-up ratio (engine-PTO),
3.2885 :1.0 0.2833 : 1.0
Not that the dimensions of the shaft are presented as the outer diameter, the inner
diameter, and the length of the shaft(mmxmmxmrn) 0 350 x 0 150 x 72133 L (mmxmmxmm) 0 350 x 0 150 x 7134 L (minx mmx mm) 0 350 x0 150 x 4876 L (minx mrrixmm) 0 397 x 0 150 x 137783 L (kW) 4320 (rpm) 510 (bar) 24.07 (/)' 6 (mm) 400 (mm) 560 14-5-6-3-2
SHAFTING SYSTEM PARTICULARS
intermediate shaft 1 intermediate shaft 2 intermediate shaft 3 4 screw shaft
Delft University of Technology
996--
- - _ chapter!.PROPELLER PARTICULARS propeller diameter
number of blades
(/)
4blade area ratio propeller inertia
The general arrangement plan of a typical twin screw, RO/ RD passenger/ freight ferry Is presented in figure [2.3]. woriir
laM
-
ilUiroPPArJnas-1,411110efilleiguscuom.drl=rta
"r=t11,1=c7=7
mai 0:L9AP 119011119 c te. OC19.0.1101111ML.Imit! Pill
mirii
11/11/M2
Figure 2.3: General arrangement plan of a typical RO/RO passenger/freight ferry. (mm)
(/)
(kg.m2)3. FREQUENCY DOMAIN ANALYSIS OF PROPULSION SHAFTING SYSTEMS
The dynamic behaviour of marine propulsion shafting systems under steady state operating conditions is normally analysed using frequency domain vibration analysis. The system's vibration behaviour at these conditions is described by the natural frequencies and forced damped response analysis of the shafting system. A standard matrix approach is presented
in this chapter to analyse the torsional vibration behaviour of a straight shafting system in
the frequency domain.
The equivalent mass-elastic torsional vibration model of this system is shown in figure [3.1].
This system comprises equivalent mass moments of inertia, flexibilities and damping,
representing the material properties and geometry of the engine, shafting arrangement, andthe propeller. 'where: (141 [C] 1[K] { x(kg.m2)
(Nms/rad)
(Nm/ rad) (Nm) (rad) (rad/ 0, (rad/ s2)Figure 3.7: Torsional mass-elastic model of a straight marine propulsion shafting system.
The dynamic behaviour of this system under steady operating conditions can be described by a series of differential equations linearised about a predetermined steady speed. These
linearised differential equations may be expressed by the following equation in matrix form;
Pin {61 ± {C1 {OF} +[K]. {c4)
matrix of equivalent mass moments of inertia matrix of equivalent damping coefficients. matrix of equivalent stiffness coefficients vector of excitation moments
vector of displacement response vector of velocity response
vector of acceleration response
The dimensions of the matrices and vectors presented in this equation are (nxn) and (nxl), respectively, where n = number of inertia stations in the system. It should be noted that the
equivalent system for the axial vibration analysis cart also be described by the same form of matrix equation (3.1). However, the material properties of the system, the system geometry, and the excitations are then described in terms of mass, axial flexibility, axial damping, and forces.
10 II
Delft University of Technology 1996 _ chapter 3 A complex number description of the displacement, velocity and acceleration response IS
used to satisfy equation (3.1) using the standard solution of the second order
linear-differential equations. The displacement, velocity and acceleration response are described bythe following equations;
edmi = 0 ofele"" 041(cogp1 + j.siny
= 601 es'
...(3.3),
where:
=
(rad/ s)
angular speed(rad) comp1,2x amplitude
00 j (rad) harmonic amplitude
(rad) phase angle
The complementary function on the Right Hand Side KRHS) of the equation is expressed as;
T, Tof To pp fio,
where: To., (Nm) complex amplitude
Tom (Nm) harmonic amplitude
Substituting for equations (3.2) through to (3.5) in equation (3.1), the matrix equation (3.1)
may be expressed by the following equation;
ci-(02.Em11,= Vol
w. (3.6)
The vibration behaviour of the equivalent mass-elastic system is described by both the
homogeneous and the particular solution of matrix equation (3.6). The homogeneous
solution of the equation, that is when the RHS of equation (3.6) is zero; i.e. a system withoutexcitation or external torques, gives the natural frequencies of the equivalent system. The
particular solution of equation (3.6)
that is the system with excitation, gives the forced
damped vibration response of the equivalent system.
(3.0
(3.5) 0,
The homogeneous solution of equation (16) may be expressed by the following Matrix
equation;1{6,01[[K]-01.21A41.10,
It can be seen from equation (3.7) that the natural frequencies are determined without
considering damping in the system. Damping in the system will cause a slight shift in the natural frequencies, but analysis of an undamped system is considered sufficient to predict problem frequencies. Note that the natural frequencies depend on the system's geometry
and material properties only, i.e. the [KJ and [M] matrices..
The only non-trivial solution of equation (3.7) is obtained by setting the determinant of the
system matrix to zero, which gives the following equation [Newland, 1989];
detN
co 2 M =0; (3.3)
There will be n values of corresponding to the eigenvalues 0)2 which satisfy equation (3.8),
for a n station system. These values are the natural frequencies of the system and can be expressed by the diagonal (nxn) matrix [ail. Letting [il] be the system matrix then, if and only if [Al is diagonal (N.B. a diagonal system matrix can be achieved by the Hessenberg
eduction technique [Newland, 1989]);
ifro2HAF[mr tic]
(3.9)
The homogeneous solution is normally expressed as two i(mm) matrices [w2] and [p]. The
former is the diagonal matrix containing all of the eigenvectors, while the latter contains the
corresponding mode shapes, arranged in columns known as
the eigenvectors. A
characteristic mode shape expressed generally by the vector {ca} exists for each natural
frequency and is found for the system by substituting cut into equation (3.7).
The obtained natural frequencies of the system indicate at what frequencies and their orders the system will freely vibrate or resonate. Resonance occurs when a natural frequency of the system coincides with an order of the fundamental forcing function frequency. This can be a dangerous condition that may cause very large response amplitudes and high stresses in the
structure. The shafting systems are designed to avoid possible resonance conditions within
the speed range by both active (e.g. damper) and passive (e.g. a barred speed range)
compensation.11
Delft University of Technology 1996 chapter 3 The forced damped vibration response of the system under steady state operating condition
is given by the particular solution of matrix equation (3)6), and may be expressed by; {60 } 41-1.1to
(3.10)i
with
18] =E[K] + Jo).
(17141
Under steady state operating conditions the engine and propeller excitations are periodic
time functions and can therefore be represented by Fourier analysed series [Thomson, 1983].
These series give the magnitude and the phase angle of the forcing function for the
individual harmonic orders of the fundamental frequency with respect to the engine MeanIndicated Pressure (MIP) at a steady speed. The Fourier analysed data provided by the
engine manufacturer is presented in the harmonic tables. For example, the magnitudes and
the phase angles of the first sixteen whole and the first thirty-two whole and halve orders of
the fundamental frequency are presented in such tables, for a two- and. four-stroke engine
respectively.
The torsional vibration response of the system due to excitation is determined by solving
matrix equation (3.10) for {00} . A particular solution is found for each order in the Fourier
analysis of the 'excitation. The magnitudes and the phase angles of the displacement
response for each order are calculated from the following equations;dRe20-of +Im260j
true0, pc, arctan
Ree
(3.11)
The signs of the real and imaginary part of the response define the quadrant In which the
phase angle is placed.
The results of the frequency domain vibration analysis include, besides the amplitudes and phase angles of the displacement response of all the stations in the system, the additional stresses and torques in the shaft sections, and, as appropriate, the stresses in the flexible
couplings and dampers. The torsional vibration analysis must be carried out for all the
relevant, different shafting system configurations, for normal and cylinder misfiring
operating conditions.00,1 =
4. TIME DOMAIN SIMULATION OF PROPULSION SHAFTING SYSTEMS A computer simulation program for the analysis of the transient dynamic behaviour of
marine propulsion shafting systems in the time domain has been developed. The
program is based on reformulation and solution of a number of simultaneous first and second order differential equations, representing the torsional dynamic behaviour ofthe shafting system in the time domain. A fixed-step, fourth order Runge-Kutta
integration technique was used for time marching [Thomson, 1983]. This program alsocaters for typical non-linearities in the operating conditions of the shafting system
during transient conditions, such as; Engine operation.
Propeller operation.
Changes in the shafting system configuration due to clutching operations. Torque transmission whilst slipping clutch plate.
A modular approach was used for the simulation of shafting systems. A system is considered to comprise a collection of component models, each with its own set of
dynamic characteristics. The component models are selected from a library. The
advantages gained from this modular approach are that;The library of component models can be reused to simulate a variety of marine
propulsion shafting systems.
It easier to understand and test the functionality and limitations of the individual
components, than the complete system.
More sophisticated component models can be developed as may be required at a
latter stage.
Energy balance for individual components cater for the transmitted power and
automatically converge to steady operating conditions.The development of the shafting system component library is presented in this
chapter. This library comprises tested transient response models of the following;Engine crankshaft Propeller Shaft Layshaft gearbox Clutch Epicyclic gear Ship
Delft University of Technology
4.1 MODELLING TECHNIQUE
The shafting system components are represented in the simulation program by their
equivalent torsional mass-elastic models. These component models can then be linked together to represent an integral system.
The models are developed by considering a rigid body approach, using equivalent
mass moments of inertia, massless torsional springs, and viscous dampers to represent
the material properties (mass) and geometry (flexibility) of the component. A
mass-elastic free body diagram is presented to indicate the simplifications and the modelling
assumptions used, for each component. The torsional degrees of freedom, external torque boundary conditions and internal reaction torques are also presented for each
component.
4.2 SIGN CONVENTION
The sign convention adopted in the developed component models is illustrated by the
simple system of figure [4.2.1]. This shows a single cylinder engine coupled to a
propeller (load), by a shaft, along with its equivalent torsional mass-elastic model. In it the engine is represented by an equivalent mass moment of inertia, and an equivalent stiffness and a relative damping coefficient are used to represent the torsional elasticity of the shaft geometry and the vibration attenuation characteristics of the shaft material respectively. The inertia of the shaft is lumped with the engine and the load inertias ateach end of the shaft. An absolute damping coefficient is used to represent a speed
dependent load.
SHAFT
y Cal
Figure 4.2.1: A simple shafting system along with its torsional mass-elastic model.
.11 12
kl
ENGINE LOAD
The generalised free body diagram of the simple mass-elastic system is presented in
figure [4.22]. The external torque
act4
on the engine inertia, station (i), due to firingforce "Tex(i)" is assumed to be tir. in the same 'direction as 0. The internal reaction
torque acting on the RHS of
station (i), "Tr(i)", exerted by the shaft on the engineinertia is considered to be -ye since it opposes the direction of motion. The torque,
exerted on the Left Hand Side (LHS) of the station (1+1), "T1(i+1)", due to the twist in
the shaft is considered to be +ve. Thus the following torque conservation equations
can be specified for a twist in the shaft, acted by displacement of 0, and 02+1 at stations (1) and (i+1), at either end of the shaft.
'Tx
-
-k1.(9-
i+1) Cip(15/i -64+1) ...(4.21) and Tr(i) 71,.0k1.0; 94J+ci.(ei
-(4.2.2) where: Ta,t (Nm) torque at the RHS of inertia station (i)71,a+1 (Nm) torque at the LHS of inertia station (i+1) ki I(Nm/ rad) torsional stiffness coefficient between inertia
stations (i) and (i+/).
(Nms/rad), equivalent relative damping coefficient between
inertia stations (i) and (i+1). (rad) displacement of inertia station (i)
O (rad/ s); velocity of inertia station (i)i
NB. Thartd Tn4i, are zero in figure (4.2.2).
CO)
r3rn
Ca(i+L)
Figure 4.2.2: Generalised free body diagram. of the simple mass-elastic system.
DelajLiv
fl_i_Q_±c-si_s_Qgin ,} 1996-
chapter 4,Tex(i)
J(i)
K(i)
J(i+1) 0,
The viscous torque acting on the inertia station (HI) is determined from the absolute
damping coefficient with a negative sign indicating that it opposes the direction of motion;
Cai+, i±,
.. (4.2.3)
where: (Mm) absolute damping torque
(Nms/rad) equivalent absolute damping coefficient
The acceleration of the equivalent mass moments of inertia are then determined from the torques acting on each inertia, using the following equation:
6 (TLJ + TR., + TExi TA,i
J,
.. (4.2.4)
where. 6, (rad/ s2) torsional acceleration of inertia station (1)
TEX: (Nm) external torque acting on inertia station (i)
TA.! (Mm) absolute damping torque acting on station (i) (kg.m2) equivalent mass moment of inertia station (i) Equation (4.2.4) is presented in its generic form for torsional acceleration of the inertia
station (i) in terms of the external torque, the absolute damping torque, and the shaft
torques acting on each side of the inertia station. Depending on the connectivity one or
more of the torques above may be zero. Moreover,
it should be noted that
computation of the torques used in equation (4.2.4) are correctly signed as was shown in equations (4.2.1) through to (4.2.3).
Ca,+7,
4.3 ENGINE CRANKSHAFT MODEL
The engine crankshaft forms an integral part of the propulsion shafting system. Figure [4.3.1] shows a schematic representation of an in-line, nine cylinder engine crankshaft
along with its equivalent torsional mass-elastic model. The complex geometry of the
crankshaft structure
is modelled simply by a series of characteristic torsional
stiffnesses separated by representative mass moment of inertia at each crankthrow. The vibration attenuation characteristics of the crankshaft structure and the material
used are represented in the model by the relative and the absolute damping
coefficients.
Figure 4.3.1: A crankshaft along with its torsional mass-elastic model.
Each inertia station is assumed to comprise; the rotating inertia of the two crankwebs,
crankpin, and the two halves of the adjacent crank journals, referred to the axis of
rotation shown in figure [4.3.1]. The parallel axis theorem is used to refer the inertia of the crankpin to the axis of rotation. The inertia of the equivalent rotating mass part of the connecting rod (conrod) is also referred to the rotation axis of the crankthrow and
added to the total inertia. This lumped inertia at the crankthrow s then considered to
be constant throughout the engine cycle.
A procedure for calculating the torsional stiffness characteristics of a crankshaft in is
given by Homori [1991].
Analytical techniques for determining the relative and the absolute damping
coefficients are based on correlations to experimentally measured data [Jenzer, 1991]. One correlation suggested by Geislinger [LR, 1995] is as follows;
For an in-line engine: the absolute damping coefficient is given by;
chapter 4
and the relative damping coefficient is given by;
C1 =8000.
=12000.
( (b2
380
For a Vee type engine: the absolute damping coefficient is given by;
Ca, = 7.8 x 10-1°.(b x
and the relative damping coefficient is given by;
(0.5+.0625 x z)
(033+.0417 x
where: b (mm) bore
(mm) stroke
z
(/)
number of cylinders.The absolute damping coefficient can also be used to simulate the speed dependent component of the engine friction if the firing forces acting on the crankpin are not
corrected for engine friction.
Values of the crankshaft absolute and relative damping coefficients used in this report
were obtained from measurements performed by the engine manufacturer. The
method proposed by Geislinger was used to obtain these damping coefficients when
no data from the manufacturer was available.
The crankshaft excitation at the crankpin was determined by correcting the cylinder
gas-pressure excitation force for the cylinder-line
inertiaforces. Note that the
calculation of the crankshaft excitation was performed for an in-line, two-stroke,
crosshead Diesel engine. The in-line, four-stroke, trunk-piston engine configurations
can be treated in the same way as two-stroke, crosshead engines. However, a different
approach should be used for Vee type engine configurations because the angle
subtended between vertical and the cylinder banks [Hafner,1984].4
(b 2
4.3.1 GAS PRESSURE EXCITATION FORCE
The cylinder gas-pressure excitation force was derived from knowledge of the cylinder pressure diagram versus crankangle throughout the engine cycle. A typical example of a pressure crankangle diagram of a two-stroke, slow speed Diesel engine is presented in figure [4.3.2]. The MERLIN engine simulation capability [Banisoleiman, 1993] was
used to determine this diagram. In it the gas-pressure crankangle diagram obtained
with retarded fuel injection timing.
where: 120 100 80 60 40 20 0
pressure crankangle diagram
---F' (NI) conrod force
Fp (N) piston gas-pressure force
p (N/ m2) cylinder gas-pressure
A (m2) piston area
4) (deg.) angle subtended between the conrod and vertical
0 50 100 150 200 250 300 350
crankangle [deg]
Figure 4.3.2: The indicator diagram oft? two-stroke, slow speed Diesel engine.
The gas-pressure force is transmitted through the cylinder-line geometry, comprising the piston, piston rod, crosshead and conrod, to the crankpin of the crankthrow. The
gas-pressure forces acting on the different parts of cylinder-line geometry of a
crosshead engine are presented in figure [4.3.3]. The gas-pressure force along the line of the conrod is determined using the following equation;,=
p. AF
cos
cos
1996
Xp Munn thsplaccmcnt L Comm] length Ro Crankihrow mhos
9.0)
Figure 4.3.3: Gas-pressure forces acting on the cylinder-lineofa crosshead engine.
The force transmitted through the conrod can be resolved into component in the
tangential and radial directions relative to the orbit of the crankpin, using the
following equations;
= F'. sin(0 +
.. (4.3.2)
= F'. cos(0 +
.. (4.3.3)
where: F"T (N) tangential force
F"R (N) radial force
0 (deg.) crankangle from Top Dead Centre (TDC)
The cylinder gas-pressure torque is obtained, from equations (4.3.1) & (4.3.2). The
radial component of the force is not used because it has a zero moment about the axis
of rotation. This force component is responsible for bending of the crank throw and
coupling with axial excitation. The gas-pressure torque may then be expressed as;
sin(0 +4))
7'pressure = Ro.F;' = R. p. A.
cosd)
)
.. (4.3.4)
where: Tpressurc (Nm) cylinder gas-pressure torque
Rearranging equation (4.3.4) and using the sine rules, the cylinder gas-pressure torque was expressed bythe following equation;
= R. p. A.(tan(0 cos() + sine)
.. (4.3.5)
The relationship between the angle between the conrod and the vertical, and the
cranIcangle may be expressed by the following equations using the cylinder-line
geometry; Rostilt]) = .sine
or coscl) = T pressureR.
A. sine + )2 .-L
.sin- 0 .. (4.3.6) where : L (m) conrod length between bearing centresSubstituting for tan 0 in equation (4.3.5) using equation (4.3.6), the gas-pressure torque is expressed as;
(
.. (4.3.7)
The gas-pressure torque acting on the crankshaft is determined from equation (4.3.7) using the cylinder-pressure diagram at the operating condition of the engine. In this
calculation, the components in the cylinder-line are considered to be rigid. Appendix 2 shows a model of a cylinder-line where the flexibility of the cylinder line components is taken into account.
An example of the calculated gas-pressure torque, for a typical, two-stroke Diesel
engine, is presented in figure [4.3.4].
It has been calculated from the pressure
crankangle diagram presented in figure [4.3.2]. The torque is plotted over one enginecycle with TDC at U and Bottom Dead Centre (BDC) at 180 degrees crankangle 0, for each cylinder. The conrod length used is L = 1.638 (m) and the crankthrow radius is Ro = 0.680 (m). This torque was then corrected for the inertia forces and used to represent the external torque acting on a crankshaft inertia station.
-L.sin20
Delft University of Technology 1996 where: 500000 400000 300000 200000 (6' 100000 200000 0 50 100 150 200 250 300 350 crankangle [deg]
Figure 4.3.4: The gas-pressure torque acting on a crankshaft inertia station ofa two-stroke engine.
4.3.2 INERTIA FORCES
The cylinder gas-pressure force was corrected for the motion of the cylinder-line
inertias. The inertia forces can be thought as the forces required to accelerate and
decelerate the reciprocating and rotating mass components of the cylinder-line as a result of the rotation of the crankshaft. The rotating mass, for a crosshead engine, is
defined as the rotating mass part of the conrod whereas the reciprocating mass is
defined as the mass of the piston, piston rod, crosshead with guide shoes, and the
reciprocating mass part of the conrod.The components of the inertia force acting on the cylinder-line of a crosshead engine and the sign convention used are presented in figure [4.3.5]. The inertia forces due to
the rotating and reciprocating mass parts are determined by using the following
equations;= .R0.6
.. (4.3.8)
FI = -Mrecrp '17
.. (4.3.9)
F1 rotat (N) inertia force due to rotating mass
Fi,recip (N) inertia force due to reciprocating mass
in rota! (kg) rotating mass
m prop (kg) reciprocating mass
6 (rad/s2) crankshaft acceleration
3,, (m/ s2) piston acceleration pressure torque L. 0 100000
-F"T merrier
h.recip
= F1,recip
FRumerna = FI"Tip '
The radial component of the inertia force is not used in the torsional vibration
treatment because it has no moment about the axis of rotation of the crankthrow. This
force component however is responsible for bending of the crankthrow and coupling
with axial excitation.
4))
Figure 4.3.5: The cylinder-line inertia forces of a crosshead engine.
The inertia force due to the rotating mass part is not used in the correction. Instead, the
equivalent inertia of the rotating mass part of the conrod is referred to the axis of
rotation of the crankthrow using the parallel axis theorem and is taken into account
through the dynamics of the shafting system.
The inertia force acting on the crankpin is resolved into components in the tangential
and radial directions relative to the orbit of the crankpin using the following
equations; sin(8 +4) COSS cos(0 +4)1 coscO ) .. (4.3.10) .. (4.3.11)
where: inertia (N) tangential inertia force
1996 chapter 4 The inertia torque is obtained by combining equations (4.3.9) & (4.3.10). It is given by;
where: T inertia
sin + 40)
= - Ro.Mre(11, XP '
(N) inertia torque
Rearranging and substituting for equation (4.3.6) in equation (4.3.12), the inertia torque may be expressed as;
R° .sin10
1
R2
0) .sir-0\L}
.. (4.3.12) .. (4.3.11)The piston displacement from TDC is obtained from the cylinder-line geometry and is expressed as;
xp = Ro.( I - cos° ) + L.( I -
cos)
.. (4.3.14)
where: (in) piston displacement from TDC
The piston displacement as a function of crankangle is obtained by substituting
equation (4.3.6) into equation (4.3.14), and it may be expressed by the following
equation;.. (4.3.15)
Equation (4.3.15)
is then differentiated twice with respect to time to find the
acceleration of the piston from TDC, which is expressed as;xp = Ro.( I
- cos()) + L.( I-I - sin20
Ttnertio = R(, p sin() +
cos0
= Ro 62Xp 250 2001 150 100 50 -50 -100 -150 cos() + l cos 20 L r (RU)
.29
25 Kl.sin 70, 2L (RO) "_20 r ''" piston acceleration ...(4.3.16)Equation (4.3.16) yields the plston acceleration at any cranlcangle position throughout the cycle of a typical two-stroke Diesel engine, as illustrated in figure [4.3.6]. On this
diagram a crankangle of 0 represents the position of the piston at TDC. The conrod length used is L = 1.638 (m), the crankthrow radius is Ro = 0.680 (m),, and the mean
engine speed n = 140.0 (rpm).
Figure 4.3.6: The piston acceleration against crank utgle position throughout one cycle of a typical two-stroke Diesel engine from TDC.
ote
a), 1~(1 where:
(rad/s)
angular speed of crankshaft50r 100 150, 200 250 300, 350 crankangle Ide0
r
r 0
4
opt
1,44
1 1a
V44--R, fl sThO + 0 0 . ( R 1 3 sin2 20 LDel ft University of Technolouy chapter 4
The inertia torque is obtained by substituting equation (4.3.16) into equation (4.3.13).
Figure [4.3.7] shows the inertia torque, for the same two-stroke engine, plotted over
one engine cycle, with TDC at 0 and BDC at 180 degrees crankangle (L = 1.638 (m), Ro = 0.680 (m), mrp = 1872 (kg) and n = 140 (rpm)).
It should be noted that the acceleration, and both the gas-pressure and inertia torque
presented in the figures [4.3.6] & [4.3.7], respectively, were obtained using the
instantaneous engine speed, that is the engine speed with its velocity perturbations
due to torsional vibration. 500000 400000 300000 A
-
200000 100000 0 0 -100000 -200000 0\
7 inertia torque pressure-torque 50 100 150 200 250 300 350 crankangle [deg]Figure 4.3.7: The inertia torque of a typical two-stroke Diesel engine over one engine cycle from
TDC.
An approximate method of computing the inertia force correction has been proposed
by Fujii [1984], which disregards the terms proportional to the second or higher
powers of Ro/ L. The inertia torque according to Fujii is given by the following
equation;3 R
Tinertia reciP .R(2, .6 2 R .sin 0 + sin 20 + sin 30
s L 2 L
R2 6
(
1 R0 cos() + cos20 + R0 .cos302
.. (4.3.17)
a)
Mrecip
The inertia torque calculated by the exact method of equations (4.3.16) & (4.3.13) is
compared to Fujii's approximation, for the same engine in figure [4.3.8]. It can be seen that there is a good agreement between the two methods.
200000 150000 100000 50000 0 -50000 100000 -150000 200000 200000 150000 100000 50000 a) 0 -50000 100000 150000 200000 FUJII approximation inertia torque _--50 100 150 200 250 300 350 crankangle [deg)
Figure 4.3.8: The Fujii 119841 approximation and the inertia torque.
The method proposed by the BICERA [Nestorides, 1958] only takes into account the
first term on the RHS of equation (4.3.17). This method is used to show the influence of
the crankthrow acceleration on the calculation of the inertia torque. The BICERA approximation of the inertia torque is shown in figure [4.3.9]. Superimposed on this
plot is the inertia torque presented in figure [4.3.7] It can be seen from the plot that the influence of the crankthrow acceleration of the two-stroke engine at these conditions is not significant.
BICERA --Inertia torque
0 50 100 150 200 250 300 350
crankangle [deg)
Delft University of Technology 1996
4.3.3 CRANKSHAFT EXCITATION
The crankshaft excitation of the typical, two-stroke, crosshead Diesel engine obtained from the gas-pressure torque and corrected for the inertia forces is presented in figure
[4.3.14 This plot also shows both the gas-pressure and inertia torque components for comparison purposes. 500000 400000 300000 200000 100000 4_) 19 10 0 10 29 crankshaft ecitatibn pressur t-orque inertia torque 50 100 150 200 250 300 350 crankangle [deg]
Figure 4.3.10: Crankshaft excitation including the inertia force correction.
As a measure of confirming the above computation, a plot of the tangential
gas-pressure, inertia, and crankshaft excitation force presented by Veritec [1985] is shown in figure [4.3.11]. As can be seen, similar trends to that predicted above were obtainedconfirming the correctness of the sign convention and the algorithm used. Note that the gas-pressure, inertia, and crankshaft excitation torque can be derived multiplying
the tangential force by the crankthrow radius.
GAs FORCES + MASS FORCES (T)
Figure 4.3.11: Crankshaft excitation including the inertia force correction according to Veritec
11985]. GAS FOR
/
1
/
/\
la. i / / ///
N \ \ \ \\
/ 90 / //
/ ---...' CRANK ANGLE i I MASS FORCES -0 0 -100000 -2000004.4 PROPELLER MODEL
The model of a fixed-pitch propeller has been developed using the equivalent mass
moment of inertia and the equivalent massless torsional spring stiffness. The latter was used to represent the flexibility of the propeller shaft. A schematic representation of a
typical 4-bladed fixed-pitch propeller is presented in figure [4.4.1], along with its
torsional mass-elastic model.Figure 4.4.1: A _fixed-pitch propeller and its torsional mass-elastic model.
The equivalent inertia of the propeller comprises the dry propeller mass moment of inertia and half the mass moment of inertia of the propeller shaft. The other half is
added to the equivalent mass moment of inertia of the intermediate shaft connected to
the propeller shaft. The equivalent propeller inertia is corrected for the effects of
entrained water by adding 25 to 40 % of the dry propeller's mass moment of inertia. Methods were proposed by Parsons [1981] and Schwanecke [1963] to determine the
propeller added mass moment of inertia due to these effects.
The equivalent torsional stiffness coefficient of the propeller shaft was determined
using the method described by Nestorides [1958].
4.4.1 PROPELLER EXCITATION
The propeller excitation is obtained from the kT, kg
- J diagram of an equivalent
Wageningen B-screw series propeller, with the same power requirements as the
original propeller [Oosterveld, 1975]. This kT, kg- J presents the non-dimensionalisedpropeller open water performance for the thrust coefficient kT and the torque
coefficient kg. These parameters are plotted against the advance coefficient J, which represents the non-dimensional form of the axial displacement per revolution of thepropeller.
A typical example of a kT, kg - J diagram from a Wageningen B-screw series propeller is presented in figure [4.4.2].
Jpropeller
410
1996
0.8
,(1.) oil0
0.3
0.6
0.2 0.1 4 --4 01.10.2
0.3 0.40.5
0.60.7
Advance coefficient J
Figure 4.4.:A typical kr, kQ - J diagram of a Wageningen B-screw series propeller
The advance coefficient may be expressed as;
Vs w) n. D
where I (I) advance coefficient
Vs
(m/s)
ship speed(/)
wake fractionD (m), propeller diameter
ri (rps) propeller rotational speed
The wake fraction is defined by Kuiper [199411 as the relation between the entrance.
velocity of the v. ater at the propeller tip, in the axial direction Viz ,and the speed of the
ship V9. where;
= Vs.(1 w)
The propeller efficiency rio is also presented on figure (4.4.21 and is defined by Kuiper 11994] as the ratio between the delivered and the effective power of the propeller. The propeller torque and thrust coefficient are obtained from the kr, k(2 - J diagram at the instantaneous value of the advance coefficient. The torque coefficient IQ is used to determined propeller torque from the following non-dimensionalised form;
Q = P
Ds le().. (4.4.2)
where: Q (Nm) propeller torque (in open water)
Pw (kg/ m3) sea water density
kg
(/)
torque coefficient Ii -K4eta
, L II ... )1 III 7...: T -' -0.8 0.9 chapter 4 0 [I] -(4.4.1) 0.4 0 0.5 0 . 3where: Cap (1) 11R (Nms/ rad) (Nm) (rad/ s)
(/)
Q (Nm) (rps)absolute damping coefficient propeller torque
propeller angular speed relative rotative efficiency propeller torque (in open water) propeller rotational speed
The propeller thrust is calculated from the thrust coefficient using the following
equation;= p
.n2 7'.. (4.4.3)
where: T (N) propeller thrust (in open water)
kT
(/)
thrust coefficientThe acceleration of the propeller is then determined from the torques by using the
following equation, as was presented earlier in section 4.2; x Tps
0\
p
J,,
where: 0 (rad/ s2) acceleration of propeller
Tps (Nm) propeller shaft torque
Jp (kg.m2) equivalent mass moment of propeller
4.4.2 PROPELLER DAMPING COEFFICIENT
The absolute equivalent propeller damping coefficient is used to represent the
7ropeller loading in the frequency domain vibration analysis programs. Methods wereproposed by Parsons [1981] and by Schwanecke [1963] to determine this damping
coefficient.
The propeller equivalent damping coefficient can be also obtained from the propeller
KT, KQ - diagram. This damping coefficient is determined at the operating point of the
propeller using the following equation [Klein Woud, 1993];
am
52
car
= = 1 ao) 21t an .. (4.4.4) T)
Delft University of Technology 1996
Substituting for equations (4.4.1) & (4.4.2), and rearranging equation (4.4.4), the
absolute propeller damping coefficient may be expressed as;ak
Ca = w). + 2 n k n
27c1
-.. (4.4.5)
where: partial derivative of thek(2curve
4.5 SHAFT MODEL
The schematic representation of a typical straight shafting arrangement is shown in
figure [4.5.1], along with the torsional mass-elastic model of this arrangement. It can be
seen that this system comprises two intermediate shafts, a screw shaft, and a fixed-pitch propeller supported by three shaft bearings and a stern tube bearing (not shown in the figure). As can be seen from figure [4.5.1], the straight shaft arrangement is
modelled by representative inertias coupled by a series of equivalent torsional
massless spring stiffnesses.where:
INTERMEDIATE I INTERMEDIATE 2
?.1
Figure 4.5.1: A typical straight shafting arrangement along with its torsional mass-elastic
model.
The inertias of the shafts are lumped at the connecting flanges. For example, half of the
inertia of shaft 1 is considered at the engine flywheel, and the other half at the
connecting flange to intermediate shaft 2 and so on. Thus, the following inertia stations are identified;Psi (kg.m2) Inertia of the intermediate shaft 1
1152 (kg.m2) Inertia of the intermediate shaft 2
jps (kg.m2) Inertia of the propeller shaft
Jr (kg.m2) Inertia of the propeller
It should be noted that the inertia of the flanges are also included at each end of the
shaft. PROPELLER SHAFT Station Inertia 1 0.5 1N1 2 0.5. am + Its?) 0.5 .am + Ps) 4 0.5 p + f p 3 .
Delft University of Technology 1996
The torsional stiffnesses of intermediate shaft 1, intermediate shaft 2 and the propeller
shaft are modelled by stiffnesses 1051 , KIs2 and Kin , respectively. These equivalent
stiffness coefficients are determined using the method described by Nestorides [1958]j..
The accelerations of the 'equivalent inertias are determined using the equations from section 4.2. For example the acceleration of station 2 ( intermediate shaft 2) may be
expressed by;
° 1S2
TIM S2
IS2
where: 0 .0 (rad/s2) torsional acceleration of station 2
T1.5/ (Nm) intermediate shaft 1 torque at LHS of station 2'
TIS2 (Nm) intermediate shaft 2 torque at RHS of station 2 1152 (kg.M2) inertia of station 2
Delft University of Technology 1996 chapter 4
4.6 GEARBOX MODEL
A layshaft gearbox model comprising two, three or four series meshing gears has been
developed for the simulation of branched marine propulsion shafting systems. These
models excluded any losses at the rolling surfaces of the gears. In reality there are
speed dependent losses due to oil churning and bearing housings, and torque
dependent losses due to friction at the rolling surfaces of involute cut gears. The gearteeth were considered rigid in the gearbox model.
Figure 4.6.1: The torsional mass-elastic model and the free body diagram of a three gear layshaft
gearbox.
The modelling approach is presented in terms of a three gear layshaft gearbox. The
same technique was used for the two and the four gear gearboxes. The torsional mass-elastic model of the three gear geartrain is shown in figure [4.6.1]. As can be seen from
this diagram, the model comprises one speed and three torque degrees of freedom.
The sign convention on the free body diagram of this geartrain, shown on figure
[4.6.1], was used to formulate the equations of motion for individual gears. These
equations may be expressed as;
11.0i =
-
Ft .2 RI2 F, .1.R,
.J I3. =
-where: J, (kg.m2) mass moment of inertia
(rad/ s2) acceleration of gear
.(Nm) external torque F,, 1+1 (N) internal force .. (4.6.1) .. (1.6.2) .. (4.6.3) F2, I F3,2
10
= /4The following two equations were derived from the geartrain geometry; where: On (rad) Rn (m) °2 = Je R = .a
-angular displacement of gear gear radius
The acceleration of gear numbers 2 and a is determined by diffe:entiating equations,
(4.6.4) & (4.6.5) twice with respect to time. The acceleration of gear number 1 is then found by substituting for these equations, and rearranging equations (4.6.1) through to
(4.6.5). It should be noted that no losses were taken into account and therefore the, forces in between the gears were the same, that is F72 =F21 and F23=F32. Thus the
acceleration of gear numbers 1 through to 3 may then be expressed as:.
R, ..T R,,_T) R2 2 R3 3 =
J +J
111112+.1 2 R23 3 14 ) .44.6.6) (4.6.5) .. (4.6:7) ... (4.6,8) Note that due to the single di.gree of speed freedom, the ratio of the,gear accelerations and speeds are in the same ratio as their displacement.0 =
R,
4.7 CLUTCH MODEL
The operation of the clutch was modelled in each of its three working conditions:
engaged, slipping or disengaged. Figure [4.7.1] presents two typical dry friction clutchexamples used in marine propulsion shafting systems. They are the torsionally-stiff
Pneumastar and the torsionally-elastic Pneumaflex clutch, both manufactured by
Lohmann and Stolterfoht.Ke I le2 INPUT AIR-PRESSURE RUBBER MEMBRAME OUTPUT
Figure 4.7.1: The Pneurnastar and Pneunzaflex dry friction clutches.
The mass-elastic model for an engaged, and a disengaged or a slipping clutch
areshown in figure [4.7.2]. These models comprise two inertia stations connected by a
torsional spring, which represents the torsional stiffness characteristics of the rubber
membrane in the clutch. In a stiff friction clutch, the value of this stiffness is very high indicating almost a rigid connection.
1c12
Figure 4.7.2: The mass-elastic models of an engaged, disengaged or slipping clutch.
It should be noted that the equivalent mass moments of inertia of the disengaged
clutch halves are different from those specified for the engaged clutch. These inertias can be obtained from the clutch manufacturer.When the clutch is disengaged, the input member rotates whilst the output member
is at rest. When the clutch is slipping, the torque in between the two halves is
afunction of the clearance between the friction plates between the input and output
member, irrespective of the relative speed between the two members. This clearance is
controlled by compressed air pressure. The slip time of the clutch is set by the
manufacturer for automatic sequencing of the clutch compressed air supply.le I 1c1
CLUTCH ENGAGED CLUTCH DISENGAGED
Delft University of Technology 1996 chapter 4
The characteristics of the clutch in slipping conditions are accounted for in the
simulation model by specifying both the slip time and the slip torque against the
clearance between the friction plates in between the two clutch members. Therefore, many different types of clutches can be simulated by specifying the characteristics of
the slipping clutch in the simulation model.
The torque generated during the slipping operation will accelerate the stationary half and decelerate the rotating half of the clutch. The acceleration of the clutch, either in engaged, slipping or disengaged position is determined from equation (4.2.4). The acceleration of the input clutch in a Slipping condition is expressed by the following
equation;
(14C ="SHAFT ±
Ttitli
CL in
where:
art
Jos (rad/ s2> acceleration of clutch input halveTSHAFT (Nm) input shaft torque
TSLIP (Nm) clutch slipping torque
4.8 EPICYCLIC GEAR MODEL
A fully floating, transient model of an epicyclic gear was developed using Huckvale's [1978] model. Figure [4.8.1] shows a schematic diagram of an epicyclic gear with one
torque and two speed degrees of freedom. As can be seen from this diagram, the
epicyclic gear comprises a planet carrier, three planet gears, a ring and a sun gear. The planet gears are mounted on the planet carrier and mesh with the sun gear at one end, and with the ring member at the other end.1=1 Ring Plana Sun Caner Fs I
Figure 4.8.1: A schematic representation of an epicyclic gear and its free body diagram.
The epicyclic gear used in a marine type application is illustrated by the constant
speed gear drive system of figure [4.8.2]. This drive consists of a three wheel geartrain,epicyclic gear, hydrostatic speed control unit, and a constant frequency shaft
alternator. Both an elastic and a tooth coupling mounted on the free end of the
crankshaft isolate the generator and its drive from torsional and axial engine
vibrations.,
Figure 4.8.2: A schematic drawing of a constant speed gear drive system.
t iver it of chn lo 1
Such constant speed gear drive systems are used typically for electrical power
generation at sea from a low speed main Diesel engine directly coupled to a fixed-pitch propeller. The hydrostatic control unit continuously compensates the variable input speed of the main engine to keep the output speed of the epicylcic gear exactly
matched with the required constant electrical supply frequency. For example, a
variable input speed of 50 through to 70 rpm will be converted to a constant 1800 rpm for the 60 Hz shaft alternator.The gear-ratio of the epicyclic gear presented in figure [4.8.1] may be expressed as;
where: (rad/ s) angular speed of sun 0R
(rad/s)
angular speed of ringO.
(rad/s)
angular speed of carrier rip =.. (4.8.1)
where: 11E.
(/)
epicyclic gear ratioRR (m) ring radius
Rs (m) sun radius
The relationship of the carrier, ring, and sun gear speed was used to define the speed
ratio of the epicyclic. This relationship is expressed as;
.. (4.8.2)
The speed relationships of the epicyclic gear members are given by the following two equations; 1 0 = (ri,. +1) .. (4.8.3) where: 2rir 0 = +1).(rir
0,,
(rad/s)
velocity of a planet.. (4.8.4)
The free body diagram of the epicyclic gear, presented in figure [4.8.1], is used to
calculate the resultant acceleration of the individual gears As can be seen, only 1
planet is shown, because the other planets are described by the same free body
diagram. The equations of motion for this system are;-FRI .. (4.85) =Tr RE.FEI ..1(4.8.6) Rs. FR ... (4.8.7) Jo. R. FR, R. FR2 ..(4.8.8) where: Ocg.m2) (rad/ s2), T, (Nm) Fa, 12 (Nm) Rc (m) Rp (in)
mass moment of inertia acceleration of gear external torque
internal force in between gears carrier radius
planet radius
An extra equation is then derived to take into account the motion of the planet about
the rotation axis of the carrier, and it is given by the following equation;,
t
JE.1+2.(rlis '1 le
FR2+R .F +R F
riE 1
1'' -
".C C2' S
(4.8.9)
The acceleration of the carrier, planet, ring, and sun gear are obtained by rearranging
equations (4.8.3) through to (4.8.9) into the following form;
jy2
ix. z)
...(4.8.10)J T
Ty Op Y(lc
(4:8.11) R = -,4996 chapter 4_
Jz = J
Tr = 2ri ( -ft, -1
+6,
2 rih. ri 11)2+4
..0.8.16) (4.8.17)The acceleration of the epicyclic gear members is determined assuming no losses, that
is Fo=Fo, FR7=FR2 and Fi57=F52 . The epicyclic gear model, excluded any losses at the
rolling surfaces. In reality there are speed dependent losses due to the bearing
housings, and torque dependent losses due to friction at the rolling surfaces of gears.
A time domain simulation program has been developed for the simulation of an
epicyclic gear under transient operating conditions. This program was used for a
simple transient simulation of an epicyclic gear, and the results of this simulation are
presented in appendix 3.
with
J
X - R+J
CJr =
+J +J
Si (rig I) 2) _0.8.12) .. (4.8.13) ...(4.8.14) ,..(4.8.15) 2 .) ' 1+ 2Li' +1
[
P ri,,. - I)
-( 2 2ri riJ
T1 = T 2 (4.8.18)4.9 SHIP MODEL
The propeller excitation the propeller torque and thrust is obtained from the KT, KQ
-J. diagram of an equivalent Wageningen B-screw series propeller. Both the propeller torque and thrust are obtained from this diagram for the advance coefficient J at the
propeller operating point. The advance coefficient at this point is also a function of the
ship speed. Therefore, a simple model of a ship has been developed to determine the
ship speed at the propeller operating point.
The mass of the ship can be determined from its dimensions using the following
equation;ms/rio =pCLBT
.. (4.9.1) where: where: (kg) Ch(/)
Lp (m) 13, (m) (rn) as (m/s) Vs (m/s) T (N) td(/)
R (N) Ica(/)
ship mass block coefficientlength between perpendiculars breadth moulded
design draught moulded
The acceleration of the ship is computed from the propeller thrust and the ship
resistance. A ship resistance curve is used based on a quadratic ship velocity, i.e. R a. V52. The acceleration of the ship is determined from the following equation;dV,
T.(I - td) - R
a.,
-dt tn.( + ) .. (4.9.2) acceleration of ship ship speed propeller thrustthrust deduction factor resistance of ship entrained mass factor
Mship
=