• Nie Znaleziono Wyników

On the Becker Univalence Criterion

N/A
N/A
Protected

Academic year: 2021

Share "On the Becker Univalence Criterion"

Copied!
2
0
0

Pełen tekst

(1)

ANNALES U N I V E R S I T AT I S MARIAE C U R I E - S K L 0 D 0 WSK A

LUBLIN- POLONIA

VOL. XXXVI/XXXVH, 14________________ SECT1O A______________________________ 1982/1983

Technische Universität West Berlin

Ch. POMMERENKE

Onthe Becker Univalence Criterion

O Beckera kryterium jednolistnoici

Об условии однолистности Бекера

1.

Let the function

g

(z) =

bz + b0

+ h,

z '■

1 + ... be analytic in £l < | z 1 <«“] .

J.

Becker [2] [3, p. 173] has proved that if

jr’fz)

(lz|’-l)lz —1<1 for |z |> 1 (1)

<(«)

then

g

is univalent. We want to show by a simple example that the constant 1 is best possible.

Theorem.

Let a >

1.

Then the function

• 3 Jt ♦ 1

«(2)-z+s (fl/2.+ *~1) -y- <2)

- a« i * 2k 1

it not univalent in

£ | z 1 > 1J

but tatitfiet

g*(z)

(HI1-1)1*

for

12|>1. (3)

Proof. It follows from (2) that

( |x I» — l)|x

|x I3 -1

|x3 — 1 I

< a.

Substituting f =

i/

sin

t

in (2) we obtain that

(2)

124 Ch. Pommerenke

»/3 .. „ . CO»

t

g(l) = l-f [(cos f ) û-l] —— dt.

o surf

Since a > 1 it follows that

j

(1)<1-/’^ [(coif )'* — 1] -^-dt = l-tan^O.

o sin f 4

Now g(x~) G R for x € [1, + “) and g(x) -* + <*>asx-+ + <». Hence there exists x0 > 1 such that g(x0) = 0. Since g is odd it follows that also g( — x0) = 0 so that g is not univalent.

2. Let now / be analytic in £|z | < 1J . Becker has also proved [1] [3, p. 173] that if /"(z)

(l-kl’ )l* ~l<l for |z |< 1 (4) /(2)

then/is univalent.

As an example, let b = 4.2 • 10' *,r - 1.20613 and

/(z) = /exp [rf + bru f“ ] di ( | z | < 1). (5)

o

Numerical calculation shows that Im /(/) < 0. Since / has non-negative coefficients it follows that/is not univalent. The bound in (4) is found to be < 1.121. Hence we see that the constant 1 in Becker’s criterion cannot be replaced by 1.121. This slightly improves the estimate 1.210 obtained from the exponential function [1]. The problem whether 1 is best possible remains open.

REFERENCES

[ 11 U eck er, J.,

Löwncnche Differentialgleichung und quaiikonform fortiettbare ichllchle Funktio­

nen,

J. Reine Angew. Math. 255 (1972), 23-43.

(2) Becker, 3.,

Löwnertche Differentialgleichung und Schllchtheltikriterien,

Math. Ann. 202 (1973), 321-335.

(3) Pommerenke, Ch.,

Univalent Function»,

Vandenhoeck & Ruprecht, Gottingen 1975.

STRESZCZENIE Autor konstruuje dwa przykłady funkcji, aby dowiełć, ie

(1) 1 - jest najlepszą stałą w kryterium Beckera dla funkql holomorficznych w obszarze 1 <|r| <~

(2) dla funkcji holomorficznych w kole |s| < 1 stała Beckera nie przekracza 1,121.

РЕЗЮМЕ

Автор конструируя два примера функций доказывает, «го

(1) 1 - самая лучшая константа в условии Бэкзра для функций голоморфных в облает 1 < 1« I <

(2) эта константа не больше, чем 1,121 .в случае функций голоморфных в круге | s | < 1.

Cytaty

Powiązane dokumenty

A new approach is presented for constructing recurrence rela- tions for the modified moments of a function with respect to the Gegenbauer polynomials...

The columns of problem sol. characterize the termination of the residual problem E to determine an optimal integer solution. lb counts the number of terminations because of Lemma 3

In general, even when there is a critical point of multiplicity d, a sharper upper bound than (1.16) is available by applying our result for pure exponential sums, Theorem 2.1,

4.5.. Denote this difference by R.. In a typical problem of combinatorial num- ber theory, the extremal sets are either very regular, or random sets. Our case is different. If A is

We note that, at first glance, the results Carlitz achieves in [1] do not appear to be the same as Theorem 1 with α = 1.. It can be checked, however, that they are

The levels of such parameters characterizing dynamic loads and overloads of examined movement structures as: maximal and average values of vertical ground reaction forces, total

The term &#34;the same problem&#34; means that all mechanical and physical parameters are the same (ex- cept for cohesion), as well as the shape of the medium - boundary surfaces,

One can check that due to Lefschetz Principle our formulation of the Jacobian Conjecture for C covers the case of the Jacobian Conjecture formulated for any field k of