E. Z A D R Z Y ´ N S K A and W. M. Z A J A ¸ C Z K O W S K I (Warszawa)
LOCAL EXISTENCE OF SOLUTIONS OF A FREE BOUNDARY PROBLEM FOR EQUATIONS OF
COMPRESSIBLE VISCOUS HEAT-CONDUCTING FLUIDS
Abstract. The local existence and the uniqueness of solutions for equa- tions describing the motion of viscous compressible heat-conducting fluids in a domain bounded by a free surface is proved. First, we prove the existence of solutions of some auxiliary problems by the Galerkin method and by regu- larization techniques. Next, we use the method of successive approximations to prove the local existence for the main problem.
1. Introduction. This paper is concerned with the local motion of a drop of a viscous compressible heat-conducting fluid. Let Ω
t⊂ R
3be a bounded domain of the drop at time t. Let v = v(x, t) (v = (v
1, v
2, v
3)) be the velocity of the fluid, ̺ = ̺(x, t) the density, θ = θ(x, t) the temperature, f = f (x, t) the external force field per unit mass, r = r(x, t) the heat sources per unit mass, θ = θ(x, t) the heat flow per unit surface, p = p(̺, θ) the pressure, c
v= c
v(̺, θ) the specific heat at constant volume, µ and ν the constant viscosity coefficients, κ the constant coefficient of heat conductivity, and p
0the external (constant) pressure. Then the motion of the drop is described by the following system of equations (see [3], Chs. 2 and 5):
̺[v
t+ (v · ∇)v] − div T(v, p) = ̺f in e Ω
T,
̺
t+ div(̺v) = 0 in e Ω
T,
̺c
v(θ
t+ v · ∇θ) − κ∆θ + θp
θdiv v
− µ 2
X
3 i,j=1(v
ixj+ v
jxi)
2− (ν − µ)(div v)
2= ̺r in e Ω
T, (1.1)
1991 Mathematics Subject Classification: 35A05, 35R35, 76N10.
Key words and phrases: free boundary, compressible viscous heat-conducting fluids, local existence.
[179]
T · n = −p
0n on e S
T, v · n = −φ
t/ |∇φ| on e S
T,
∂θ
∂n = θ on e S
T,
̺ |
t=0= ̺
0, v |
t=0= v
0, θ |
t=0= θ
0in Ω, (1.1)
[cont.]
where e Ω
T= S
t∈(0,T )
Ω
t× {t}, e S
T= S
t∈(0,T )
S
t× {t}, S
t= ∂Ω
t, φ(x, t) = 0 describes S
t, n is the unit outward vector normal to the boundary, i.e.
n = ∇φ/|∇φ|, Ω = Ω
t|
t=0= Ω
0. By T = T(v, p) we denote the stress tensor of the form
T(v, p) = {T
ij}
i,j=1,2,3= {−pδ
ij+ D
ij(v) }
i,j=1,2,3, where
(1.2) D (v) = {D
ij(v) }
i,j=1,2,3= {µ(v
ixj+ v
jxi) + (ν − µ)δ
ijdiv v }
i,j=1,2,3is the deformation tensor. Moreover, in view of the thermodynamic consi- derations we assume that c
v> 0, κ > 0, ν >
13µ > 0.
Let the domain Ω be given. Then by (1.1)
5,
Ω
t= {x ∈ R
3: x = x(ξ, t), ξ ∈ Ω}, where x = x(ξ, t) is the solution of the Cauchy problem
(1.3) ∂x
∂t = v(x, t), x |
t=0= ξ ∈ Ω, ξ = (ξ
1, ξ
2, ξ
3).
Integrating (1.3) we obtain the following relation between the Eulerian x and Lagrangian ξ coordinates of the same fluid particle:
x = ξ +
t
\
0
u(ξ, t
′) dt
′≡ X
u(ξ, t),
where u(ξ, t) = v(X
u(ξ, t), t). Moreover, by (1.1)
5, S
t= {x : x = x(ξ, t), ξ ∈ S = ∂Ω}.
By the continuity equation (1.1)
2and the kinematic condition (1.1)
5the total mass is conserved, i.e.
\
Ωt
̺(x, t) dx =
\
Ω
̺
0(ξ) dξ = M, where M is a given constant.
The aim of the paper is to show the local existence theorem for problem
(1.1). In order to prove the local-in-time existence of solutions of (1.1) we
rewrite it in Lagrangian coordinates as follows:
(1.4)
ηu
t− div
uT
u(u, p) = ηg in Ω
T= Ω × (0, T ),
η
t+ η div
uu = 0 in Ω
T,
ηc
v(η, γ)γ
t− κ∇
2uγ + γp
γ(η, γ) div
uu
− µ 2
X
3 i,j=1(ξ
xi· ∇
ξu
j+ ξ
xj· ∇
ξu
i)
2− (ν − µ)(div
uu)
2= ηk in Ω
T,
T
u(u, p) · n
u= −p
0n
uon S
T= S × (0, T ),
n
u· ∇
uγ = γ on S
T,
η |
t=0= ̺
0, u |
t=0= v
0, γ |
t=0= θ
0in Ω,
where η(ξ, t) = ̺(X
u(ξ, t), t), γ(ξ, t) = θ(X
u(ξ, t), t), p = p(η, γ), g(ξ, t) = f (X
u(ξ, t), t), k(ξ, t) = r(X
u(ξ, t), t), γ(ξ, t) = θ(X
u(ξ, t), t), ∇
u= ξ
ix∂
ξi, T
u(u, p) = −pI + D
u(u), I = {δ
ij}
i,j=1,2,3is the unit matrix, D
u(u) = {D
uij(u) }
i,j=1,2,3= {µ(∂
xiξ
k∂
ξku
j+ ∂
xjξ
k∂
ξku
i) + (ν − µ)δ
ijdiv
uu }, div
uu
= ∇
u· u = ∂
xiξ
k∂
ξku
i, div
uT(u, p) = {∂
xjξ
k∂
ξkT
uij(u, p) }
i=1,2,3(∂
xiξ
kare the elements of the matrix ξ
xwhich is inverse to x
ξ= I +
Tt
0
u
ξ(ξ, t
′) dt
′) and summation over repeated indices is assumed.
Let S
tbe determined (at least locally) by the equation φ(x, t) = 0. Then S is described by φ(x(ξ, t), t) |
t=0≡ e φ(ξ) = 0. Thus, we have
n
u= n(X
u(ξ, t), t) = ∇
xφ(x, t)
|∇
xφ(x, t) |
x=Xu(ξ,t)
and n
0= n
0(ξ) = ∇
ξφ(ξ) e
|∇
ξφ(ξ) e | . The proof of the existence of solutions of problem (1.4) is divided into a few steps. First, we examine the auxiliary problem (3.1) and the problem
(1.5)
ηc
v(η, β)γ
t− κ∇
2ξγ
= K + µ 2
X
3 i,j=1(ξ
xi· ∇
ξw
j+ ξ
xj· ∇
ξw
i)
2in Ω
T,
n · ∇
ξγ = γ on S
T,
γ |
t=0= θ
0in Ω,
where η > 0, β > 0 and w are given functions, ξ
xi= ξ
xi(w). We prove the existence of solutions of problems (3.1) and (1.5) by the Galerkin method and by some regularization techniques.
Next, by using the Schauder–Tikhonov fixed point theorem we obtain
the local existence of solutions of problems (3.40) and (3.76) (see Lemmas
3.5 and 3.6).
Finally, applying the method of successive approximations we prove the local existence and the uniqueness of a solution (u, γ, η) of problem (1.4) such that u, γ ∈ A
T, η ∈ B
T, where T ≤ T
∗, T
∗> 0 is a certain constant;
A
Tand B
Tare given by (2.1) and (2.2) (see Theorem 4.2).
We have already considered problem (1.1) in papers [7]–[11]. In [7] we proved by using potential techniques from [5] the local existence of solu- tions of (1.4) in Sobolev–Slobodetski˘ı spaces, i.e. we obtained (u, γ, η) ∈ W
24,2(Ω
T) × W
24,2(Ω
T) × C(0, T ; Γ
3,3/2(Ω)) for T ≤ T
∗, where T
∗> 0 is a certain constant. We cannot apply potential theory in the present paper because this theory is singular in the case of H
3(Ω) regularity (with respect to the space variable ξ) considered in the paper.
Papers [8] and [9] are concerned with conservation laws and a differential inequality, respectively, used in [10]–[11] to prove the global existence the- orem for problem (1.1) in the case of a special form of the internal energy per unit mass ε = ε(̺, θ). The main result of the present paper, i.e. The- orem 4.2, will be used in [12] to examine the global motion of the viscous compressible barotropic fluid in the general case, i.e. without assuming any conditions on the form of the pressure p.
In this paper we use some results of paper [6], which is concerned with the local existence of solutions of a free boundary problem for the equations of compressible barotropic viscous self-gravitating fluids.
Moreover, local existence theorems for free boundary problems for equa- tions of compressible viscous heat-conducting and self-gravitating fluids are proved in [2] and [4].
2. Notation and auxiliary results. We use the following notation:
• kuk
s,Q= kuk
Hs(Q), s ≥ 0, s rational, Q = Ω, S, S = ∂Ω;
• |u|
p,Q= kuk
Lp(Ω), p ∈ [1, ∞];
• kuk
s,p,q,ΩT= kuk
Lq(0,T ;Wps(Ω)), p, q ∈ [1, ∞], 0 ≤ s ∈ Z, Ω
T= Ω × (0, T );
• kuk
s,p,q,ST= kuk
Lq(0,T ;Wps(S)), p, q ∈ [1, ∞], s ≥ 0, s rational, S
T= S × (0, T ).
Moreover, we introduce the spaces:
(2.1) A
T= {u ∈ C(0, T ; H
2(Ω)) ∩ L
2(0, T ; H
3(Ω)) :
u
t∈ C(0, T ; H
1(Ω)) ∩ L
2(0, T ; H
2(Ω)), u
tt∈ C(0, T ; L
2(Ω)) ∩ L
2(0, T ; H
1(Ω)) } and
(2.2) B
T= {u ∈ C(0, T ; H
2(Ω)) : u
t∈ C(0, T ; H
1(Ω)) ∩L
2(0, T ; H
2(Ω)),
u
tt∈ C(0, T ; L
2(Ω)) ∩ L
2(0, T ; H
1(Ω)) }
with the norms
kuk
AT= ( sup
0≤t≤T
kuk
22,Ω+ kuk
23,2,2,ΩT+ sup
0≤t≤T
ku
tk
21,Ω(2.3)
+ ku
tk
22,2,2,ΩT+ sup
0≤t≤T
ku
ttk
20,Ω+ ku
ttk
21,2,2,ΩT)
1/2and
kuk
BT= ( sup
0≤t≤T
kuk
22,Ω+ sup
0≤t≤T
ku
tk
21,Ω+ ku
tk
22,2,2,ΩT(2.4)
+ sup
0≤t≤T
ku
ttk
20,Ω+ ku
ttk
21,2,2,ΩT)
1/2. Finally, define
|u|
l,k,Q= X
0≤i≤l−k
k∂
tiu k
l−i,2,2,Q, where l ≥ k, k ∈ Z
+∪ {0}, Q = Ω
t, S
tand
u
l,k,Ω= X
0≤i≤l−k
k∂
tiu k
l−i,Ω, where l ≥ k, k ∈ Z
+∪ {0}.
We denote all positive constants in estimates by the same letter c. We also use the following lemmas.
Lemma 2.1. The following imbedding holds:
W
rl(Ω) ⊂ L
αp(Ω) (Ω ⊂ R
3, Ω satisfies the cone condition), where either
κ = |α|
l + 3 lr − 3
lp < 1 and 1 ≤ r ≤ p ≤ ∞ or κ = 1 and 1 < r ≤ p < ∞,
and L
αp(Ω) is the space of functions u such that |D
αξu |
p,Ω< ∞;
W
rl(Ω) ⊂ L
αq(S) (S = ∂Ω, Ω ⊂ R
3), where either
κ = |α|
l + 3 lr − 2
lq < 1 and 1 ≤ r ≤ q ≤ ∞ or κ = 1 and 1 < r ≤ q < ∞,
and L
αq(S) is the space of functions u such that |D
ξαu |
q,S< ∞. Moreover, the following inequalities hold :
|D
αξu |
p,Ω≤ cε
1−κ|D
lξu |
r,Ω+ cε
−κ|u|
r,Ω, where
κ = |α|
l + 3 lr − 3
lp < 1, 1 ≤ r ≤ p ≤ ∞,
ε is a parameter and c > 0 is a constant independent of u and ε;
|D
ξαu |
q,S≤ cε
1−κ|D
ξlu |
r,Ω+ cε
−κ|u|
r,Ω, where
κ = |α|
l + 3 lr − 2
lq < 1, 1 ≤ r ≤ q ≤ ∞, ε is a parameter and c > 0 is a constant independent of u and ε.
Lemma 2.1 follows from Theorem 10.2 of [1].
Lemma 2.2. Assume that η ∈ C(0, T ; H
2(Ω)), η
t∈ C(0, T ; H
1(Ω)), η
tt∈ L
2(Ω
T), η > 0, β ∈ A
T, β > 0, c
v∈ C
2(R
2+), c
v> 0. Then ηc
v(η, β) ∈ C(0, T ; H
2(Ω)), ∂
t[ηc
v(η, β)] ∈ C(0, T ; H
1(Ω)), ∂
t2[ηc
v(η, β)] ∈ C(0, T ; L
2(Ω)), 1/(ηc
v(η, β)) ∈ C(Ω × [0, T ]) and
(2.5) sup
t
kηc
v(η, β) k
22,Ω≤ ckc
vk
2C2( ¯V )sup
t
kηk
22,Ωf
1(sup
t
kηk
22,Ω, sup
t
kβk
22,Ω), where f
1(x
1, x
2) = 1 + x
1+ x
2+ x
21+ x
22+ x
1x
2and c > 0 is a constant;
(2.6) sup
t
k∂
t[ηc
v(η, β)] k
21,Ω≤ ckc
vk
2C2( ¯V )f
2(sup
t
kηk
22,Ω, sup
t
kβk
22,Ω, sup
t
kη
tk
21,Ω, sup
t
kβ
tk
21,Ω), where f
2(x
1, x
2, x
3, x
4) = x
1(x
3+x
1x
3+x
2x
3+x
1x
4+x
2x
4)+x
3(1+x
2+x
4) and c > 0 is a constant;
(2.7) sup
t
k∂
t2[ηc
v(η, β)] k
20,Ω≤ ckc
vk
2C2( ¯V )f
3(sup
t
kηk
22,Ω, sup
t
kη
tk
21,Ω, sup
t
kβ
tk
21,Ω, sup
t
kη
ttk
20,Ω, sup
t
kβ
ttk
20,Ω), where f
3(x
1, x
2, x
3, x
4, x
5) = x
1(x
22+ x
2x
3+ x
4+ x
23+ x
5) + x
2x
3+ x
4and c > 0 is a constant;
sup
ΩT
[ηc
v(η, β)] ≤ kc
vk
C( ¯V )sup
ΩT
η;
(2.8)
sup
ΩT
1 ηc
v(η, β) ≤
1 c
vC( ¯V )
sup
ΩT
1 η . (2.9)
In (2.5)–(2.9), V ⊂ R
2is a bounded domain such that (η(ξ, t), β(ξ, t)) ∈ V for any (ξ, t) ∈ Ω
T.
The proof of the above lemma is obtained using Lemma 2.1.
Now, consider the continuity equation (1.4)
2. Integrating it we have (2.10) η(ξ, t) = ̺
0(ξ) exp h
−
t
\
0
div
uu dt
′i
.
By direct calculations we obtain the following lemma.
Lemma 2.3. Let ̺
0∈ H
2(Ω), ̺
0> 0, u ∈ L
∞(0, T ; H
2(Ω)) ∩ L
2(0, T ; H
3(Ω)), u
t∈ L
∞(0, T ; H
1(Ω)) ∩ L
2(0, T ; H
2(Ω)). Then η given by (2.10) belongs to B
Tand the following estimates hold :
sup
Ωt
η ≤ k̺
0k
2,Ωφ
1(a(u, t)), sup
t
kηk
22,Ω≤ k̺
0k
22,Ωφ
2(a(u, t)), sup
t
kη
tk
21,Ω≤ k̺
0k
22,Ωφ
3(a(u, t), a
0(u
t, t), ku(0)k
22,Ω), sup
t
kη
ttk
20,Ω≤ k̺
0k
22,Ωφ
4(a(u, t), a
0(u
t, t), ku(0)k
22,Ω, ku
t(0) k
21,Ω), kη
tk
21,2,2,Ωt≤ tk̺
0k
22,Ωφ
3(a(u, t), a
0(u
t, t), ku(0)k
22,Ω),
kη
ttk
20,Ωt≤ tk̺
0k
22,Ωφ
4(a(u, t), a
0(u
t, t), ku(0)k
22,Ω, ku
t(0) k
21,Ω), kη
tk
22,2,2,Ωt≤ k̺
0k
22,Ωkuk
23,2,2,Ωtφ
5(t, t
a1kuk
23,2,2,Ωt),
kη
ttk
21,2,2,Ωt≤ k̺
0k
22,Ωφ
6(a(u, t))[φ
7(a(u, t), b(t, u, ε
3)) + ku
tk
22,2,2,Ωt], where t ≤ T , φ
i(i = 1, . . . , 7) are positive increasing continuous functions of their arguments, a(u, t) = t
Tt
0
kuk
23,Ωdt
′, a
0(u
t, t) = t
Tt
0
ku
tk
22,Ωdt
′, b is given by (3.46) and a
1> 0 is a constant. Moreover , 1/η ∈ B
Tand
sup
Ωt
1 η +
1
η
2
Bt
≤ φ
8( kuk
23,2,2,Ωt, sup
t
kuk
22,Ω, ku
tk
22,2,2,Ωt, sup
t
ku
tk
22,Ω), where t ≤ T and φ
8is a positive increasing continuous function of its argu- ments.
3. Existence of solutions of auxiliary problems. In order to prove the local-in-time solvability of problem (1.4) we have to consider a few aux- iliary problems. First, we consider the problem
(3.1)
ηu
t− div D(u) = F in Ω
T, D (u) · n
0= G on S
T, u |
t=0= v
0in Ω,
where D(u) is defined by (1.2) and η is a given function. Moreover, (3.2) 0 < ̺
∗≤ η ≤ ̺
∗< ∞,
where ̺
∗and ̺
∗are constants.
Definition 3.1. By a weak solution of problem (3.1) we mean a function u ∈ C(0, T ; L
2(Ω)) ∩ L
2(0, T ; H
1(Ω)) with u
t∈ L
2(Ω
T) which satisfies the integral identity
(3.3)
\
Ω
ηu
tφ + µ
2 S (u)S(φ) + (ν − µ) div u div φ − F φ
dξ −
\
S
Gφ dξ
s= 0
for all φ ∈ H
1(Ω) and the initial condition u |
t=0= v
0; here f φ = P
3i=1
f
iφ
i, f = u
t, F , G, S(u) = {u
iξj+ u
jξi}
i,j=1,2,3and S (u)S(φ) =
X
3 i,j=1(u
iξj+ u
jξi)(φ
iξj+ φ
jξi).
In order to prove the existence of a weak solution to problem (3.1) we shall apply a Galerkin procedure. Choose a sequence of functions φ
1, φ
2, . . . such that: φ
i∈ H
1(Ω) for all i; φ
1, . . . , φ
nare linearly independent for each n; the set of all linear combinations of the functions φ
iis dense in H
1(Ω).
For any n we define an approximate solution of problem (3.1) by
(3.4)
u
n= X
n i=1c
in(t)φ
i(ξ),
\
Ω
ηu
ntφ
i+ µ
2 S (u
n)S(φ
i) + (ν − µ) div u
ndiv φ
i− F φ
idξ
−
\
S
Gφ
idξ
s= 0, u
n(0) = u
n0,
where u
n0→ v
0in H
1(Ω), u
nt(0) → u
t(0) in H
1(Ω), u
ntt(0) → u
tt(0) in L
2(Ω) and ku
n0k
1,Ω≤ ckv
0k
1,Ω, ku
nt(0) k
1,Ω≤ cku
t(0) k
1,Ω, |u
ntt(0) |
2,Ω≤ c |u
tt(0) |
2,Ω; u
t(0) and u
tt(0) are calculated from (3.1); c > 0 is a constant.
Lemma 3.2. Let assumption (3.2) be satisfied. Let η ∈ C(Ω×[0, T ]), η
t∈ L
2(0, T ; H
1(Ω)), η
tt∈ L
2(Ω
T), F ∈ H
2(0, T ; L
2(Ω)), G ∈ H
2(0, T ; L
2(S)), v
0∈ H
1(Ω), u
t(0) ∈ H
1(Ω), u
tt(0) ∈ L
2(Ω). Then there exists a unique weak solution of problem (3.1) such that u ∈ L
∞(0, T ; H
1(Ω)), u
t∈L
∞(0, T ; H
1(Ω)), u
tt∈ L
∞(0, T ; L
2(Ω)) ∩L
2(0, T ; H
1(Ω)) and the following estimate is satisfied:
(3.5) kuk
21,Ω+ ku
tk
21,Ω+ ku
ttk
20,Ω+ kuk
21,2,2,Ωt+ ku
tk
21,2,2,Ωt+ ku
ttk
21,2,2,Ωt≤ Ψ
1(1/̺
∗, ̺
∗, t, kη
tk
21,2,2,Ωt, kη
ttk
20,Ωt)[ kF k
20,Ωt+ kF
tk
20,Ωt+ ε
1kF
ttk
20,Ωt+ kGk
20,St+ kG
tk
20,St+ ε
1kG
ttk
20,St+ kv
0k
21,Ω+ ku
t(0) k
21,Ω+ ku
tt(0) k
20,Ω],
where t ≤ T , Ψ
1is a positive increasing continuous function of its arguments
and ε
1∈ (0, 1) is a sufficiently small constant.
P r o o f. First, multiply (3.4) by c
inand sum up over i from 1 to n.
Using the Korn inequality and Lemma 2.1 we get d
dt
\
Ω
ηu
2ndξ + c ku
nk
21,Ω≤ c
̺
∗(1 + kη
tk
21,Ω)
\
Ω
ηu
2ndξ
+ c( kF k
20,Ω+ kGk
20,S) + ε ku
nk
21,Ω, where we have also used the fact that
µ 2
\
Ω
|S(u
n) |
2dξ + (ν − µ)kdiv u
nk
20,Ω≥ c
\
Ω
|S(u
n) |
2dξ.
Hence, integrating with respect to time, taking ε > 0 sufficiently small and using the Gronwall inequality we have
\
Ω
ηu
2ndξ + ku
nk
21,2,2,Ωt≤ Ψ
2(1/̺
∗, ̺
∗, t, kη
tk
21,2,2,Ωt) (3.6)
×
\Ω
η(0)v
02dξ + kF k
20,Ωt+ kGk
20,St, where Ψ
2is a positive increasing continuous function.
Next, multiplying (3.4) by ˙c
inand summing up over i we obtain (3.7)
\
Ω
ηu
2nt+ 1 2
d dt
µ
2 |S(u
n) |
2+ (ν − µ)(div u
n)
2− F u
ntdξ
−
\
S
Gu
ntdξ
s= 0.
Integrating (3.7) with respect to t and using the Korn inequality yields
\
Ωt
ηu
2ntdξ dt
′+ ku
nk
21,Ω≤ εku
ntk
21,2,2,Ωt+ c ku
nk
20,Ω(3.8)
+ c( kF k
20,Ωt+ kGk
20,St+ kv
0k
21,Ω).
Differentiating (3.4) with respect to t, multiplying by ˙c
inand summing up over i from 1 to n we get
d dt
\
Ω
ηu
2ntdξ + c ku
ntk
21,Ω≤ εku
ntk
21,Ω+ c
̺
∗(1 + kη
tk
21,Ω)
\
Ω
ηu
2ntdξ (3.9)
+ c( kF
tk
20,Ω+ kG
tk
20,S).
Integrating (3.9) with respect to time gives (3.10)
\
Ω
ηu
2ntdξ + ku
ntk
21,2,2,Ωt≤ Ψ
2(1/̺
∗, ̺
∗, t, kη
tk
21,2,2,Ωt)
\Ω
η(0)u
2t(0) dξ + kF
tk
20,Ωt+ kG
tk
20,St.
Next, differentiate (3.4) with respect to t, multiply the result by ¨ c
inand sum up over i from 1 to n. We obtain
\
Ω
ηu
2nttdξ + 1 2
d dt
\
Ω
µ
2 |S(u
nt) |
2+ (ν − µ)(div u
nt)
2dξ
≤ εku
nttk
21,Ω+ c( kη
tk
21,Ωku
ntk
20,Ω+ kF
tk
20,Ω+ kG
tk
20,S).
Hence (3.11)
\
Ωt
ηu
2nttdξ dt
′+ ku
ntk
21,Ω≤ εku
nttk
21,2,2,Ωt+ c( kη
tk
21,2,2,Ωtsup
t
ku
ntk
20,Ω+ kF
tk
20,Ωt+ kG
tk
20,St+ ku
ntk
20,Ωt+ ku
ntξ(0) k
20,Ω).
Finally, differentiating twice (3.4) with respect to t, multiplying by ¨ c
inand summing up over i we have d
dt
\
Ω
ηu
2nttdξ + c ku
nttk
21,Ω≤ c
̺
∗( kη
tk
21,Ω+ 1)
\
Ω
ηu
2nttdξ (3.12)
+ c( kη
ttk
20,Ωku
ntk
21,Ω+ ε
1kF
ttk
20,Ω+ ε
1kG
ttk
20,S).
Therefore, integrating (3.12) with respect to time yields (3.13)
\
Ω
ηu
2nttdξ + ku
nttk
21,2,2,Ωt≤ Ψ
2(1/̺
∗, ̺
∗, t, kη
tk
21,2,2,Ωt)
\Ω
η(0)u
2tt(0) dξ + ε
1kF
ttk
20,Ωt+ ε
1kG
ttk
20,St+ sup
t
ku
ntk
21,Ωkη
ttk
20,Ωt.
Using inequality (3.11) in (3.13) and assuming that εΨ
2kη
ttk
20,Ωtis suffi- ciently small we obtain
(3.14)
\
Ω
ηu
2nttdξ + ku
nttk
21,2,2,Ωt≤ Ψ
3(1/̺
∗, ̺
∗, t, kη
tk
21,2,2,Ωt, kη
ttk
20,Ωt)
\Ω
η(0)u
2tt(0) dξ + ku
tξ(0) k
20,Ω+ ε
1kF
ttk
20,Ωt+ ε
1kG
ttk
20,St+ kF
tk
20,Ωt+ kG
tk
20,St+ ku
ntk
20,Ωt+ sup
t
ku
ntk
20,Ω,
where Ψ
3is a positive increasing continuous function of its arguments.
Now, taking into account inequalities (3.6), (3.8), (3.10), (3.11) and (3.14) we get the estimate
ku
nk
21,Ω+ ku
ntk
21,Ω+ ku
nttk
20,Ω+ ku
nk
21,2,2,Ωt+ ku
ntk
21,2,2,Ωt+ ku
nttk
21,2,2,Ωt≤ Ψ
1(1/̺
∗, ̺
∗, t, kη
tk
21,2,2,Ωt, kη
ttk
20,Ωt) h
kF k
20,Ωt+ kF
tk
20,Ωt+ ε
1kF
ttk
20,Ωt+ kGk
20,St+ kG
tk
20,St+ ε
1kG
ttk
20,St+
\
Ω
η(0)v
20dξ +
\
Ω
η(0)u
2t(0) dξ +
\
Ω
η(0)u
2tt(0) dξ + kv
0k
21,Ω+ ku
tξ(0) k
20,Ωi .
Choosing a subsequence and letting n → ∞ we obtain the existence of a solution of (3.1) and estimate (3.5). Uniqueness follows from (3.5). This concludes the proof.
Lemma 3.3. Let assumption (3.2) be satisfied. Let η ∈ C(0, T ; H
2(Ω)), η
t∈ C(0, T ; H
1(Ω)), 1/η ∈ C(0, T ; H
2(Ω)), (1/η)
t∈ C(0, T ; H
1(Ω)), η
tt∈ L
2(Ω
T), F ∈ H
2(0, T ; L
2(Ω)) ∩ L
2(0, T ; H
1(Ω)), G ∈ L
2(0, T ; H
3/2(S)), G
t∈ L
2(0, T ; H
1/2(S)), G
tt∈ L
2(S
T)), S ∈ H
5/2, v
0∈ H
2(Ω), u
t(0) ∈ H
1(Ω), u
tt(0) ∈ L
2(Ω) (where u
t(0) and u
tt(0) are calculated from (3.1)).
Moreover , let the compatibility condition be satisfied:
D (v
0) · n
0= G(0) on S.
Then the solution u of problem (3.1) belongs to A
Tand for t ≤ T the following estimate holds :
kuk
2At≤ Ψ
4(1/̺
∗, ̺
∗, t, h(t, η, ε
2))[ kF k
21,2,2,Ωt+ kF
tk
20,Ωt(3.15)
+ ε
1kF
ttk
20,Ωt+ sup
t
kF k
20,Ω+ kGk
23/2,2,2,St+ kG
tk
21/2,2,2,St+ ε
1kG
ttk
20,St+ u(0)
22,0,Ω],
where ε
i∈ (0, 1) (i = 1, 2) are sufficiently small constants, Ψ
4is a positive increasing continuous function of its arguments depending also on kΦk
23,Ω(where Φ is a transformation which straightens locally the boundary of Ω) and
h(t, η, ε
2) = kη
tk
21,2,2,Ωt+ kη
ttk
20,Ωt+ ε
2sup
t
kηk
22,Ω(3.16)
+ c(ε
2) sup
t
kηk
20,Ω+ ε
2sup
t
kη
tk
21,Ω+ c(ε
2) sup
t
kη
tk
20,Ω.
P r o o f. In [6] it is proved that the solution u of problem (3.1) be-
longs to L
2(0, T ; H
3(Ω)), so in view of Lemma 3.2 it suffices to prove that
u ∈ C(0, T ; H
2(Ω)) with u
t∈ C(0, T ; H
1(Ω)) ∩ L
2(0, T ; H
2(Ω)), u
tt∈
C(0, T ; L
2(Ω)) and that the estimate (3.15) holds. In order to do it con-
sider as in [6] a covering {Ω
j}
nj=1of Ω and associate with this covering a partition of unity {ζ
j}
nj=1, i.e. P
nj=1
ζ
j= 1, supp ζ
j⊂ Ω
j, ζ
j∈ C
0∞(R
3).
Denote by e Ω an arbitrary set of the covering {Ω
j} such that e Ω ∩ S = ∅.
Denote by ζ a function of the partition of unity {ζ
j} such that supp ζ ⊂ e Ω.
Since the identity (3.3) is satisfied for any test function φ it is also fulfilled for ζφ. Then we have
(3.17)
\
Ωe
ηu
tζφ + µ
2 S (u)S(ζφ) + (ν − µ) div u div(ζφ) − F ζφ
dξ
−
\
S∩ eΩ= eS
Gζφ dξ
s= 0.
Now, apply the transformation Φ : e Ω → b Ω which straightens locally the boundary of Ω. Then (3.17) takes the form
(3.18)
\
Ωb
b
η u e
tφ + b µ
2 [b S ( u)b e S (b φ) + b S ( e u)b D
1(b ζ, b φ) − b D
1( u, b b ζ)b S (b φ)]
J dz +
\
Ωb
{(ν − µ)[ c div e u c div b φ + c div b ub φ · b ∇b ζ − b u · b ∇b ζ c div b φ] − b F b ζ b φ }J dz
−
\
Sb
Gb b ζ b φ √ g dz
s= 0,
where e Ω ∋ ξ → Φ(ξ) = z ∈ b Ω, b u = u ◦ Φ
−1, e u = b ub ζ, J is the Jacobian of the transformation ξ = Φ
−1(z) = (z
1, z
2, z
3+ e ψ(z)), e ψ is an extension to b Ω of a function ψ such that e S is described by ξ
3= ψ(ξ
1, ξ
2), g = 1 + ψ
2z1+ ψ
z22,
∇
ξin S, b D
1, etc. is replaced by b ∇ = ∇
ξΦ(ξ) |
ξ=Φ−1(z)· ∇
z, and b D
1(b ζ, w) = b { b w
i∇ b
jζ + b w b
j∇ b
iζ b }
i,j=1,2,3(w = φ, u; b ∇ = ( b ∇)
i=1,2,3).
Moreover, we need that b Ω = {z ∈ R
3: |z
i| < d, i = 1, 2, 0 < z
3< d }, S = Φ( e b S) = {z ∈ R
3: |z
i| < d, i = 1, 2, z
3= 0 }. Since the first integral in (3.18) vanishes on ∂ b Ω \ b S it can be extended by zero onto R
3+= {z ∈ R
3: z
3> 0 }.
Assume in (3.18) (as in [6]) b φ = δ
−1nδ
nu, where e δ
hu(z) = 1
h [u(z
′+ h, z
3) − u(z)], δ
h−1u(z) = 1
h [u(z
′− h, z
3) − u(z)], z
′= (z
1, z
2).
Then the first term in (3.18) can be rewritten as (see (A.7) in [6])
\
Ωb
b
η e u
tφJ dz = b −
\
Ωb
δ
hη b u e
tδ
huJ dz e −
\
Ωb
b
η u e
tδ
huδ e
hJ dz (3.19)
− 1 2
d dt
\
Ωb
b
η |δ
hu e |
2J dz + 1 2
\
Ωb
b
η
t|δ
hu e |
2J dz
and by Lemma 2.1 the first two terms in (3.19) are bounded by ε kδ
he u k
20, bΩ+ c(ε)(ε
2kb η k
22, bΩ+ c(ε
2) kb η k
20, bΩ) ke u
tk
21, bΩ,
where ε ∈ (0, 1) and ε
2∈ (0, 1). Hence in the same way as in [6] we obtain (cf. inequality (A.8) of [6]) the estimate
(3.20) 1 2
d dt
\
Ωb
b
η |δ
hu e |
2J dz + µ
2 kδ
hu e k
21, bΩ≤ c(ε
2kb η k
22, bΩ+ c(ε
2) kb η k
20, bΩ) ke u
tk
21, bΩ+ c kb η
tk
21, bΩkδ
hu e k
20, bΩ+ ε kδ
hb u k
21, bΩ+ c kb u k
21, bΩ+ c( k e F k
20, bΩ+ k e G k
21/2, bS).
Integrating (3.20) with respect to time, going back to the old variables, summing over all neighborhoods of the partition of unity, using the fact that ε is sufficiently small and letting h tend to 0 we get
(3.21)
\
Ω
ηu
2τdξ + µ ku
τk
21,2,2,Ωt≤
\
Ω
η(0)v
20τdξ + (ε
2sup
t
kηk
22,Ω+ c(ε
2) sup
t
kηk
20,Ω) ku
tk
21,2,2,Ωt+ c kη
tk
21,2,2,Ωtsup
t
kuk
21,Ω+ c( kuk
21,2,2,Ωt+ kF k
20,Ωt+ kGk
1/2,2,2,St), where u
τdenotes the tangent derivatives to the boundary and the constant c depends on kΦk
23,Ω.
To calculate the normal derivatives we use the equation
− div D(u) = F − ηu
t. Hence we have
(3.22) ku
nk
21,Ω≤ c(kF k
20,Ω+ ku
τk
21,Ω) + c(ε
2kηk
21,Ωc(ε
2) kηk
20,Ω) ku
tk
21,Ω. Now, inequalities (3.21) and (3.22) imply
(3.23)
\
Ω
ηu
2τdξ + kuk
22,2,2,Ωt≤
\
Ω
η(0)v
20τdξ + (ε
2sup
t
kηk
22,Ω+ c(ε
2) sup
t
kηk
20,Ω) ku
tk
21,2,2,Ωt+ c kη
tk
21,2,2,Ωtsup
t
kuk
21,Ω+ c( kuk
21,2,2,Ωt+ kF k
20,Ωt+ kGk
21/2,2,2,St), where t ≤ T and the r.h.s. of (3.23) is bounded in terms of the estimates for the weak solution (see Lemma 3.2).
Now, we obtain estimates for sup
tkuk
22,Ωand ku
tk
22,2,2,Ωt. To do this we
put b φ = δ
−1hδ
he u
tin (3.18).
Using the H¨older and Young inequalities and Lemma 2.1 we obtain (3.24)
\
Ωb
b
η |δ
hu e
t|
2J dz + 1 2
d dt
\
Ωb
µ
2 |bS(δ
ne u) |
2+ (ν − µ)( c divδ
nu) e
2J dz
≤ εkδ
hu e
tk
21, bΩ+ c[ ke u
tk
21, bΩ(ε
2kδ
hb η k
21, bΩ+ c(ε
2) kδ
hη b k
20, bΩ) + ke u
tk
21, bΩ(ε
2kb η k
22, bΩ+ c(ε
2) kb η k
20, bΩ) kδ
hJ k
21, bΩ+ kb u k
21, bΩ+ ke u k
22, bΩkδ
hJ k
21, bΩ+ k e F k
20, bΩ+ k e G k
21/2, bS].
Integrating (3.24) with respect to time and using the Korn inequality yields (3.25)
\
Ωbt
b
η |δ
hu e
t|
2J dz dt
′+ kδ
he u k
21, bΩ≤ εkδ
hu e
tk
21,2,2, bΩt+ c[ ke u
tk
21,2,2, bΩt(ε
2sup
t
kδ
hη b k
21, bΩ+ c(ε
2) sup
t
kδ
hb η k
20, bΩ+ c(ε
2) sup
t
kb η k
20, bΩ) + ke u
tk
21,2,2, bΩtkΦk
23, bΩ(ε
2sup
t
kb η k
22, bΩ+ c(ε
2) sup
t
kηk
20,Ω) + kb u k
21,2,2, bΩt+ kΦk
23, bΩke u k
22,2,2, bΩt+ k e F k
20, bΩt+ k e G k
21/2,2,2, bSt+ kv
0k
22, bΩ].
Now, since by Lemma 3.2, (ηu
t)
,t= η
tu
t+ ηu
tt∈ L
2(Ω
t) and F
t∈ L
2(Ω
t) we have [div D(u)]
,t= div D(u
t) ∈ L
2(Ω
t). Therefore, differentiating (3.1)
1and (3.1)
2with respect to t we obtain the problem
(3.26)
ηu
tt− div D(u
t) = F
t− η
tu
tin Ω
T, D (u
t) · n
0= G
ton S
T, u
t|
t=0= u
t(0) in Ω.
Problem (3.26) is, with respect to v = u
t, of analogous form to problem (3.1), so to get an estimate for kvk
22,2,2,Ωt= ku
tk
22,2,2,Ωtwe use the same argument as in the case of the estimate for kuk
22,2,2,Ωt. Thus, (3.20) is now replaced by
(3.27) 1 2
d dt
\
Ωb
b
η |δ
hu e
t|
2J dz + µ
2 kδ
he u
tk
21, bΩ≤ c(ε
2kb η k
22, bΩ+ c(ε
2) kb η k
20, bΩ) ke u
ttk
21, bΩ+ c kb η
tk
21, bΩkδ
hu e
tk
20, bΩ+ ε kδ
he u
tk
21,Ω+ c kb u
tk
21, bΩ+ c( k e F
tk
20, bΩ+ k e G
tk
21/2, bS+ kb η
tk
21, bΩke u
tk
21, bΩ).
Integrating (3.27) with respect to time gives
(3.28)
\
Ωb
b
η |δ
hu e
t|
2J dz +
t
\
0
kδ
he u
tk
21, bΩdt
′≤ c(ε
2sup
t
kb η k
22, bΩ+ c(ε
2) sup
t
kb η k
20, bΩ) ke u
ttk
21,2,2, bΩt+ c kb η
tk
21,2,2, bΩt(sup
t
kδ
he u
tk
20, bΩ+ sup
t
ke u
tk
21, bΩ) + c kb u
tk
21,2,2, bΩt+ c
k e F
tk
20, bΩt+ k e G
tk
21/2,2,2, bSt+
\
Ωb
η(0) |δ
hu
t(0) |
2dξ . Adding inequalities (3.25) and (3.28), next going back to the old variables, summing over all neighbourhoods of the partition of unity, using the fact that ε is sufficiently small and letting h tend to 0 we get
(3.29)
\
Ωt
η |u
tτ|
2dξ dt
′+
\
Ω
η |u
tτ|
2dξ + ku
τk
21,Ω+ ku
tτk
1,2,2,Ωt≤ c(kΦk
23,Ω) h
ku
tk
21,2,2,Ωt(ε
1sup
t
kηk
22,Ω+ c(ε
1) sup
t
kηk
20,Ω) + ku
ttk
21,2,2,Ωt(ε
2sup
t
kηk
22,Ω+ c(ε
2) sup
t
kηk
20,Ω) + kuk
22,2,2,Ωt+ ku
tk
21,2,2,Ωt+ kη
tk
21,2,2,Ωtsup
t
ku
tk
21,Ω+ kF k
20,Ωt+ kF
tk
20,Ωt+ kGk
21/2,2,2,St+ kG
tk
21/2,2,2,St+ kv
0k
22,Ω+
\
Ω
η(0) |u
tτ(0) |
2dξ i . In order to calculate the normal derivatives of u
twe use the equation
− div D(u
t) = F
t− ηu
tt− η
tu
t. Hence, we have
ku
tnk
21,2,2,Ωt≤ c[kF
tk
20,Ωt+ ku
tτk
21,2,2,Ωt+ kη
tk
21,2,2,Ωtsup
t
ku
tk
21,Ω(3.30)
+ (ε
2sup
t
kηk
22,Ω+ c(ε
2) sup
t
kηk
20,Ω) ku
ttk
20,Ωt].
Taking into account inequalities (3.29), (3.30) and the inequality sup
t
ku
nk
21,Ω≤ c(sup
t
kF k
20,Ω+ sup
t
ku
τk
21,Ω) + c(ε
1sup
t
kηk
21,Ω+ c(ε
1) sup
t
kηk
20,Ω) sup
t
ku
tk
21,Ω, which follows from (3.22), and using estimate (3.5) we find that u ∈ L
∞(0, T ; H
2(Ω)), u
t∈ L
2(0, T ; H
2(Ω)) and
(3.31) kuk
22,Ω+ ku
tk
22,2,2,Ωt≤ Ψ
5(1/̺
∗, ̺
∗, t, kη
tk
21,2,2,Ωt, kη
ttk
20,Ωt, ε
2sup
t
kηk
22,Ω+ c(ε
2) sup
t
kηk
20,Ω)
× [kF k
20,Ωt+ kF
tk
20,Ωt+ ε
1kF
ttk
20,Ωt+ sup
t
kF k
20,Ω+ kGk
21/2,2,2,St+ kG
tk
21/2,2,2,St+ ε
1kG
ttk
20,St+ u(0)
22,0,Ω],
where Ψ
5is a positive increasing continuous function.
It remains to find an estimate for kuk
23,2,2,Ωt. Using the same argument as in [6] and after similar calculations to those for (A.16) of [6] we get (3.32) 1
2 d dt
\
Ωb
b
η |∂
τ2j
δu |
2J dz + µ
2 k∂
τ2j
δu e k
21, bΩ≤ c[kb η k
22, bΩkj
δu e
tk
21, bΩ+ (ε
2kb η
tk
21, bΩ+ c(ε
2) kb η
tk
20, bΩ) k∂
τ2j
δu e k
20, bΩ+ kb η k
22, bΩke u
tk
21, bΩ+ kb u k
22, bΩ+ k e F k
21, bΩ+ k e G k
23/2, bS+ ε k∂
n2∂
τj
δu e k
20, bΩ], where j
δis the Friedrichs mollifier operator. Integrating (3.32) with respect to time yields
(3.33)
\
Ωb
b
η |∂
τ2j
δe u |
2J dz + µ k∂
τ2j
δe u k
21,2,2, bΩt≤ c h
kb η k
22,2,2, bΩtsup
t
ke u
tk
21, bΩ+ (ε
2sup
t
kb η
tk
21, bΩ+ c(ε
2) sup
t
kb η
tk
20, bΩ) kb u k
22,2,2, bΩt+ kb u k
22,2,2, bΩt+ k e F k
21,2,2, bΩt+ k e G k
23/2,2,2, bSt+ ε k∂
n2∂
τj
δe u k
20, bΩt+
\
Ωb
b
η(0) |∂
τ2u(0) e |
2J dz i . Next, (A.18) of [6] is now replaced by
(3.34) ∂
τ∂
n2\
ω
δ(x − y)
1 − 1
Φ
23,x(Φ
23,x− Φ
23,y)
e u(y) dy
2
0, bΩt
≤ ckb η k
22,2,2, bΩtsup
t
ke u
tk
21, bΩ+ c
1k∂
τ2j
δe u k
21,2,2, bΩt+ c kb u k
22,2,2, bΩt+ c k e F k
21,2,2, bΩt, where ω
δis the smooth kernel of the mollifier operator j
δ. Estimates (3.33) and (3.34) imply
(3.35) 2c
1µ
\
Ωb
b
η |∂
τ2j
δu e |
2J dz + c
1k∂
τ2j
δu e k
21,2,2, bΩt+ ∂
τ∂
n2\
ω
δ(x − y)
1 − 1
Φ
23,x(Φ
23,x− Φ
23,y) − 2εc
1µ
e u(y) dy
2
0, bΩt
≤ c h
kb η k
22,2,2, bΩtsup
t
ke u
tk
21, bΩ+ (ε
2sup
t
kb η
tk
21, bΩ+ c(ε
2) sup
t
kb η
tk
20, bΩ) kb u k
22,2,2, bΩt+ kb u k
22,2,2, bΩt+ k e F k
21,2,2, bΩt+ k e G k
23/2,2,2, bSt+ ε k∂
n2∂
τj
δe u k
20, bΩt+
\
Ωb
b
η(0) |∂
τ2u(0) e |
2J dz i .
Using the fact that Φ
23,xis close to one and Φ
23,x− Φ
23,yis close to zero for
x, y ∈ b Ω and for b Ω sufficiently small, we obtain from (3.35), after taking the
limit as δ → 0, (3.36)
\
Ωb
b
η |∂
τ2e u |
2J dz + k∂
τ2u e k
21,2,2, bΩt+ k∂
2n∂
τu e k
20, bΩt≤ c h
kb η k
22,2,2, bΩtsup
t
ke u
tk
21, bΩ+ (ε
2sup
t
kb η
tk
21, bΩ+ c(ε
2) sup
t
kb η
tk
20, bΩ) kb u k
22,2,2, bΩt+ kb u k
22,2,2, bΩt+ k e F k
21,2,2, bΩt+ k e G k
23/2,2,2, bSt+
\
Ωb
b
η(0) |∂
τ2u(0) e |
2J dz i . Next, from equation (A.13) of [6] we have
k∂
n3e u k
20, bΩt≤ c(k∂
n2∂
τu e k
20, bΩt+ k∂
n∂
τ2u e k
20, bΩt(3.37)
+ kb u k
22,2,2, bΩt+ kb η k
22,2,2, bΩtsup
t
ke u
tk
21, bΩt+ k e F k
21,2,2, bΩt).
Taking into account (3.36) and (3.37) we see that u ∈ L
2(0, T ; H
3(Ω)) and
kuk
23,2,2,Ωt≤ c h
kηk
22,2,2,Ωtsup
t
ku
tk
21,Ω(3.38)
+ (ε
2sup
t
kη
tk
21,Ω+ c(ε
2) sup
t
kη
tk
20,Ω) kuk
22,2,2,Ωt+ kuk
22,2,2,Ωt+ kF k
21,2,2,Ωt+ kGk
23/2,2,2,St+
\
Ω
η(0) |∂
τ2u(0) |
2dz i .
Adding inequalities (3.31), (3.38) and (3.5) we obtain estimate (3.15).
To complete the proof notice that from u ∈ L
∞(0, T ; H
2(Ω)) ∩ L
2(0, T ; H
3(Ω)) and u
t∈ L
∞(0, T ; H
1(Ω)) ∩ L
2(0, T ; H
2(Ω)) it follows that u ∈ C(0, T ; H
2(Ω)). Next, since u
t∈ L
∞(0, T ; H
1(Ω)) ∩ L
2(0, T ; H
2(Ω)) and u
tt∈ L
∞(0, T ; L
2(Ω)) ∩ L
2(0, T ; H
1(Ω)) we have u
t∈ C(0, T ; H
1(Ω)).
In order to prove that u
tt∈ C(0, T ; L
2(Ω)) differentiate (3.1)
1with re- spect to t, multiply by φ ∈ H
1(Ω) and integrate over Ω, using the boundary condition (3.1)
2, to get
\
Ω
u
ttφ dξ =
\
Ω
− η
tu
tη + F
tη − ∇( 1 η )D(u
t)
φ dξ
−
\
Ω
D (u
t)
η ∇φ dξ +
\
S
G
tη φ dξ
s∀φ ∈ H
1(Ω), where D(u
t) ∇φ = P
3i,j=1
D
ij(u
t)φ
ixj. Hence,
d dt
\
Ω
u
ttφ dξ =
\
Ω
− ∇
1 η
,t
D (u
t) − ∇
1 η
D (u
tt) (3.39)
− η
ttu
tη − η
tu
ttη −
1 η
,t
η
tu
t+ F
ttη + F
t1 η
,t
φ dξ
−
\
Ω
D (u
tt)
η − D(u
t)
1 η
,t
∇φ dξ +
\
S
G
ttη + G
t1 η
,t
φ dξ
s≡ hg
1, φ i
Ω+ hg
2, φ i
S∀φ ∈ H
1(Ω).
Identity (3.39) implies ku
tttk
2L2(0,T ;(H1(Ω))∗)≤ c
T\
0
sup
kφk1,Ω≤1
|hg
1, φ i
Ω|
2dt + c
T\
0
sup
kφk1,Ω≤1
|hg
2, φ i
S|
2dt
≤ Ψ
6( kηk
2BT, k1/ηk
2BT, ku
tk
22,2,2,ΩT, ku
ttk
21,2,2,ΩT, kG
ttk
20,ST,
kG
tk
1/2,2,2,ST, kF
ttk
20,ΩT, kF
tk
20,ΩT), where Ψ
6is a positive increasing continuous function of its arguments. Hence u
tt∈ C(0, T ; L
2(Ω)). This completes the proof of the lemma.
Now, consider the problem (3.40)
ηu
t− div
wD
w(u) = F in Ω
T, D
w(u) · n
w= G on S
T, u |
t=0= v
0in Ω,
where η and w are given functions, n
w= n(X
w(ξ, t), t), D
w(u) = µS
w(u) + (ν −µ)I div
wu, S
w(u) = {∂
xiξ
k∂
ξku
j+∂
xjξ
k∂
ξku
i}
i,j=1,2,3, I = {δ
ij}
i,j=1,2,3. We assume that η satisfies (3.2) and w = w(ξ, t) is such that
x = ξ +
t
\
0