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doi:10.7151/dmps.1145

DISCRETE APPROXIMATIONS OF GENERALIZED RBSDE WITH RANDOM TERMINAL TIME

Katarzyna Ja´nczak-Borkowska Institute of Mathematics And Physics University of Technology and Life Sciences

Kaliskiego 7, 85–796 Bydgoszcz, Poland e-mail: kaja@utp.edu.pl

Abstract

The convergence of discrete approximations of generalized reflected back- ward stochastic differential equations with random terminal time in a gen- eral convex domain is studied. Applications to investigation obstacle elliptic problem with Neumann boundary condition for partial differential equations are given.

Keywords: generalized reflected BSDE, discrete approximation methods, viscosity solution.

2010 Mathematics Subject Classification: Primary: 60H10, 60Gxx;

Secondary: 35J20.

1. Introduction

Pardoux and Peng in [13] have introduced nonlinear backward stochastic differen- tial equations (BSDEs for short). Since then many papers have been devoted to the study of BSDEs, mainly due to their applications. The main aim of studying BSDEs was to give a probabilistic interpretation for solutions of partial differen- tial equations (PDEs for short).

In [5] the authors put some constrains on the solution of BSDE. They assumed that the first component of the solution takes its values in a given convex set D ⊂ Rd and the problem was called the reflected BSDE (RBSDE for short). Later, Pardoux and R˘a¸scanu in [14] considered RBSDE with random terminal time and pointed out the connection between RBSDEs and variational inequalities.

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The notion of generalized BSDEs was introduced in [15]. By generalized it is meant that to the stochastic equation an additional component – an integral with respect to one dimensional increasing process – is added. Recently papers about the generalized RBSDEs on a finite time interval have appeared. The paper [16] treats one dimensional case and [7] treats d-dimensional case. The existence and uniqueness of the generalized RBSDE (GRBSDE for short) with random terminal time and its connection with PDEs with an obstacle problem and Neumann boundary condition was shown in [8].

In the literature we can find many papers related to discrete approximations of backward stochastic equations. We should list here [1, 3, 4, 10] that treat the case of BSDEs with deterministic terminal time and [18] that treats the case of BSDEs with random terminal time. Discrete approximations of RBSDEs firstly were proposed in one-dimensional case (e.g. [1, 11]) and later also in d- dimensional case (see [6]). In [7] an approximation scheme for the solution of generalized RBSDE with deterministic terminal time was given.

In the present paper we propose the discrete approximation of the solution of the following GRBSDE with random terminal time τ :

Yt∧τ = ξ + Z τ

t∧τ

f (s, Ys, Zs)ds + Z τ

t∧τ

ϕ(s, Ys)dΛs (1)

− Z τ

t∧τ

ZsdWs+ Kτ − Kt∧τ, t ∈ R+,

where W = (Wt)t∈R+ is m-dimensional Wiener process and Λ = (Λt)t∈R+ is one dimensional continuous and increasing process, Λ0 = 0. Moreover, we show the convergence of the proposed scheme to the solution of (1).

The paper is organized as follows. In Section 2 we give a definition of a solution of GRBSDE with random terminal time. We formulate here a theorem about existence and uniqueness of the solution of (1). In the next section we construct a discrete approximation scheme for solving (1) and give its properties.

Moreover, this section is devoted to proving the main theorem - theorem about convergence of the proposed scheme. Finally, in the last section we show the application of the constructed scheme to numerical solving of the obstacle problem for PDE with Neumann boundary condition.

Throughout the paper we will use the following notations. By |x| we mean an Euclidean norm in Rd, x ∈ Rd, kxk stands for (trace(xx))1/2, where x is a transposition of a matrix x ∈ Rd×m. For a process K = (K1, ..., Kd) by

|K|t=Pd

i=1|Ki|twe denote its variation on [0, t], where |Ki|tis a total variation of Ki on [0, t].

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2. Definition

Let (Ω, G, P) be a complete probability space carrying a standard m-dimensional Wiener process W = (Wt)t∈R+. Let F = (Ft)t∈R+ be the usual augmentation of the filtration generated by W and assume that Λ = (Λt)t∈R+ is an adapted, one dimensional continuous and increasing process, Λ0 = 0.

Let τ be an almost surely finite F stopping time and let ξ be an Fτ measur- able, square integrable random variable with values in ¯D, where D is a convex subset of Rd. Suppose that functions f : R+ × Ω × Rd× Rd×m → Rd and ϕ : R+× Ω × Rd→ Rd are measurable.

Definition. A solution of the generalized reflected backward stochastic differ- ential equation (GRBSDE) with random terminal time associated with data (τ, ξ, f, ϕ, Λ) is a triple (Y, Z, K) = (Yt, Zt, Kt)t∈R+ of F progressively measurable processes in ¯D × Rd×m× Rd satisfying

Yt = ξ + Z τ

t∧τ

f (s, Ys, Zs)ds + Z τ

t∧τ

ϕ(s, Ys)dΛs (2)

− Z τ

t∧τ

ZsdWs+ Kτ − Kt∧τ, t ∈ R+ and such that for some λ ∈ R

E

 sup

t≤τ

eλt|Yt|2+ Z τ

0

eλtkZtk2dt + Z τ

0

eλt|Yt|2t



< ∞, where K is a continuous process with locally finite variation, K0 = 0 and

Z τ 0

(Yt− St)dKt≤ 0, (3)

for every F progressively measurable process S = (St)t∈R+ with values in ¯D.

Moreover, on the set {t ≥ τ } we have Yt= ξ, Zt= 0, Kt= Kτ.

Assume that there exist constants L, κ > 0, β < 0, µ ∈ R such that for any t ∈ R+, y, y0 ∈ Rd, z, z0 ∈ Rd×m

(A1) • |f (t, y, z) − f (t, y0, z0)| ≤ L(|y − y0| + kz − z0k),

• hy − y0, f (t, y, z) − f (t, y0, z)i ≤ µ|y − y0|2, (A2) • |ϕ(t, y) − ϕ(t, y0)| ≤ L|y − y0|,

• hy − y0, ϕ(t, y) − ϕ(t, y0)i ≤ β|y − y0|2,

• |ϕ(·, ·, ·)| ≤ κ,

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(A3) for some real numbers λ and ν such that λ > 2µ + L2, ν > β E

 Z τ 0

eλt+νΛt|f (t, 0, 0)|2dt + Z τ

0

eλt+νΛt|ϕ(t, 0)|2t



< ∞,

(A4) ξ is Fτ measurable random variable with values in D,¯ Eeλτ +νΛτ(|ξ|2+ 1) < ∞ and

E

 Z τ 0

eλt+νΛt|f (t, ξt, ζt)|2dt + Z τ

0

eλt+νΛt|ϕ(t, ξt)|2t



< ∞,

where ξt = E(ξ|Ft), ζ is F progressively measurable d × m-dimensional process such that ER

0tk2dt < ∞ and ξ = Eξ +R 0 ζtdWt, (A5) there exists q ≥ 2 such that for every M > 0

E Z M

0

|f (t, 0, 0)|2qdt < ∞.

Theorem 1 [8, Theorem 2.2 and Proposition 4.1]. Let τ be an almost surely finite F stopping time and let assumptions (A1)–(A5) hold. Then there exists a unique solution of (2).

Moreover, for any a ∈ D there exists C > 0 such that for λ > 2µ + L2 E

 sup

t≤τ

eλt|Yt− a|2+ Z τ

0

eλt|Yt− a|2t+ Z τ

0

eλtkZtk2dt + Z τ

0

eλtd|K|t



≤ CE



eλτ|ξ − a|2+ Z τ

0

eλt|f (t, a, 0)|2dt + Z τ

0

eλt|ϕ(t, a)|2t

 .

3. Convergence of the approximation scheme

We will give an approximation scheme for (2) based on an approximation of a Wiener process by a random walk. In a construction of this scheme and in the proof of its convergence we will use results from [7], where a scheme for (2) when τ is a deterministic terminal time was given.

Set Wtn = (√

n)−1P[nt]

j=1εnj, t ∈ R+, where for each n ∈ N, {εnj}j∈N is a sequence of independent symmetric Bernoulli random variables, and by Fn = {Ftn}t∈R+ denote the natural filtration of Wn.

By Λn,L we will denote a process with bounded jumps such that Λn,Lt = P[nt]

j=1∆Λn,L(j−1)/n, where ∆Λn,Lj/n = min((2L)−1, ∆Λnj/n) and ∆Λnj/n = Λnj/n

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Λn(j−1)/n. Note that since Λ has continuous trajectories, maxj≤[nTn]|∆Λnj/n| → 0 and supt≤Tnn,Lt − Λt| ≤P[nT ]

j=1 |1/(2L) − ∆Λnj/n|1{∆Λn

j/n>1/2L} → 0, a.s.

Now we need to approximate the stopping time τ by a sequence of bounded stopping times {τn}n. Since for every n ∈ N, τn is bounded, we can find Tn∈ N such that τn≤ Tn. Denote τjn= j/n ∧ [nτn]/n, j ∈ N.

In order to define the discrete GRBSDE with random terminal time we take j = nTn, . . . , 0 and on the set {τn ≤ j/n} put yτnn

j = ynτn = ξn = E(ξ|Fτnn) and znτn

j = zτnn = 0, ∆kτnn

j+1 = 0. Next, on the set {[nτn] > j} we solve yj/nn = yτnn

j+1+ 1

nf (j/n, ynj/n, zj/nn )1{[nτn]>j}

(4)

+ ϕ(j/n, ynj/n)1{[nτn]>j}∆Λn,Lj/n− 1

√nzj/nn εnj+1+ ∆kτnn

j+1.

By a solution of (4) we mean a triple (Yn, Zn, Kn) = (Ytn, Ztn, Ktn)t∈[0,Tn] of Fn adapted processes in ¯D×Rd×m×Rdsuch that K0n= 0 andRτn

0 (Yt−n−St−n )dKtn≤ 0 for every Fn adapted process Snwith values in ¯D, where Ytn= ynτn

[nt], Ztn= zτnn

[nt], Ktn = P[nt]

j=1∆kτnn

j. Moreover, on the set {t ≥ τn}, Ytn = Yτnn, Ztn = 0 and Ktn= Kτnn.

Theorem 2. Assume (A1)–(A5). Let {τn} be a sequence of Fn stopping times such that supnEeλτn(|ξn|2+ 1) < ∞ and τn−→ τ . Then for every T ∈ RP +

n→∞lim E

 sup

t≤T

|Yt∧τn n − Yt∧τ|2+ Z T

0

kZt−n,τn− Ztτk2dt + Z T

0

|Yt−n,τn− Ytτ|dΛt + sup

t≤T

|Kt∧τn n− Kt∧τ|2



= 0.

Before proving the above theorem we will give some properties of the discrete scheme. First note, that the triple (Yn, Zn, Kn) is a unique solution of (4), that is equivalent to

Yt∧τn n = ξn+ Z τn

t∧τn

f (%ns−, Ys−n, Zs−n )d%ns + Z τn

t∧τn

ϕ(%ns−, Ys−n)dΛn,Ls (5)

− Z τn

t∧τn

Zs−n dWsn+ Kτnn− Kt∧τn n, t ∈ R+,

where %nt = [nt]/n. Now, note that solving (4) relies on finding on the set {[nτn] > j}

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zj/nn = zj/nn 1{[nτn]>j}=√

nE(ynτn

j+1εnj+1|Fj/nn )1{[nτn]>j}, hnj/n = E(yτnn

j+1|Fj/nn ) + 1

nf (j/n, π(hnj/n), znj/n)1{[nτn]>j}

+ ϕ(j/n, π(hnj/n))1{[nτn]>j}∆Λn,Lj/n, yj/nn = π(hnj/n),

∆knτn

j+1 = yj/nn − hnj/n.

Since f and ϕ are Lipschitz, hnj/nis well defined for n > 2L . Moreover processes defined above satisfy

Z T 0

(Yt−n − St−n )dKtn≤ 0.

(6)

Indeed, since D is a convex set hπ(h)−x0, π(h)−hi ≤ 0, h ∈ Rd, x0 ∈ ¯D (see ex.

[12]). In particular, hy(j−1)/nn − x0, ∆knj/ni ≤ 0 for any x0 ∈ ¯D and j = 1, . . . , [nTn] and as a consequence, for any Fn adapted process Sn with values in ¯D

Z T 0

(Yt−n − St−n )dKtn=

[nT ]

X

j=1

hy(j−1)/nn − S(j−1)/nn , ∆kj/nn i ≤ 0.

It can be shown that E supt≤τneλt|Ytn|2 < ∞ and for t ∈ R+, E(kZtnk2+ |Kn|2t)

< ∞.

Proposition 3. Assume that (A1)–(A4) are satisfied and τn is a sequence of Fn stopping times such that supnEeλτn(1 + |ξn|2) < ∞.

(a) There exists a constant C > 0 such that for any n ∈ N and a ∈ D

E

 sup

t≤τn

eλt|Ytn− a|2+ Z τn

0

eλ%ntkZt−n k2d%nt + Z τn

0

eλ%nt|Yt−n − a|2n,Lt



≤ CE



eλτnn− a|2+ Z τn

0

eλ%nt|f (%nt−, a, 0)|2d%nt + Z τn

0

eλ%nt|ϕ(%nt−, a)|2n,Lt



(7)

and

E

 sup

t≤τn

eλt|Ktn|2+ eλτn|Kn|2τn



≤ CE



1 + eλτnn− a|2 Z τn

0

eλ%nt|f (%nt−, a, 0)|2d%nt + Z τn

0

eλ%nt|ϕ(%nt−, a)|2n,Lt

 .

(b) The solution of (5) is unique.

Proof. (a) By the Itˆo formula

eλ(t∧τn) |Yt∧τn n− a|2+ λ Z τn

t∧τn

eλs|Ys−n − a|2d%ns + Z τn

t∧τn

eλ%nsd[Yn]s

= eλτnn− a|2+ 2 Z τn

t∧τn

eλ%ns(Ys−n − a)f (%ns−, Ys−n, Zs−n )d%ns

+2 Z τn

t∧τn

eλ%ns(Ys−n − a)ϕ(%ns−, Ys−n)dΛn,Ls + 2 Z τn

t∧τn

eλ%ns(Ys−n − a)dKsn

−2 Z τn

t∧τn

eλ%ns(Ys−n − a)Zs−n dWsn.

Since exponent function is nonnegative and by (6), Rτn

t∧τneλ%ns(Ys−n − a)dKsn≤ 0.

Using assumptions on f and ϕ and by the equality [Yn]t=Rt

0kZs−n k2d%ns eλ(t∧τn) |Yt∧τn n− a|2+ λ

Z τn t∧τn

eλ%ns|Ys−n − a|2d%ns + Z τn

t∧τn

eλ%nskZs−n k2d%ns

≤ eλτnn− a|2+ (2µ + L2/ε + η) Z τn

t∧τn

eλ%ns|Ys−n − a|2d%ns

+ ε Z τn

t∧τn

eλ%nskZs−n k2d%ns + 1/η Z τn

t∧τn

eλ%ns|f (%ns−, a, 0)|2d%ns

+β Z τn

t∧τn

eλ%ns|Ys−n − a|2n,Ls + 1/|β|

Z τn t∧τn

eλ%ns|ϕ(%ns−, a)|2n,Ls

−2 Z τn

t∧τn

eλ%ns(Ys−n − a)Zs−n dWsn.

(8)

Let ε, η > 0 be such that ˜ε = 1 − ε > 0 and ˜λ = λ − (2µ + L2/ε + η) > 0. Since β < 0,

eλ(t∧τn) |Yt∧τn n− a|2+ ˜λ Z τn

t∧τn

eλ%ns|Ys−n − a|2d%ns (7)

+ |β|

Z τn t∧τn

eλ%ns|Ys−n − a|2n,Ls + ˜ε Z τn

t∧τn

eλ%nskZs−n k2d%ns

≤ eλτnn− a|2+ C Z τn

t∧τn

eλ%ns|f (%ns−, a, 0)|2d%ns

+ C Z τn

t∧τn

eλ%ns|ϕ(%ns−, a)|2n,Ls − 2 Z τn

t∧τn

eλ%ns(Ys−n − a)Zs−n dWsn, where by C we denoted a constant which values may vary from line to line. Since {R·

0eλs(Ys − a)ZsdWs} is a martingale, after integrating the above inequality we get

E



eλ(t∧τn)|Yt∧τn n− a|2 + Z τn

t∧τn

eλ%ns|Ys−n − a|2n,Ls + Z τn

t∧τn

eλ%nskZs−n k2d%ns

 (8)

≤ CE



eλτnn− a|2+ Z τn

t∧τn

eλ%ns|f (%ns−, a, 0)|2d%ns

+ Z τn

t∧τn

eλ%ns|ϕ(%ns−, a)|2n,Ls

 . Note that

E sup

t≤τn

Z τn t∧τn

eλ%ns(Ys−n − a)Zs−n dWsn

≤ CE

Z T 0

e2λ%ns|Ys−n − a|2kZs−n k2d%ns

1/2

≤ 1 2E sup

t≤τn

eλt|Ytn− a|2+ CE Z T

0

eλ%ntkZt−n k2d%nt. Therefore taking supremum in (7) and using (8) we get estimate on E supt≤τneλt|Yt∧τn n − a|2.

Now, note that from

Kt∧τn n = Y0n− Yt∧τn n− Z t∧τn

0

f (%ns−, Ys−n, Zs−n )d%ns

− Z t∧τn

0

ϕ(%ns−, Ys−n)dΛn,Ls + Z t∧τn

0

Zs−n dWsn

(9)

and the previous estimates it follows that E supt≤τneλt|Ktn|2 + Eeλτn|Kn|τn ≤ CE



eλτnn− a|2+ (Λn,Lτn )2

+ Z τn

0

eλ%ns|f (%ns−, a, 0)|2d%ns + Z τn

0

eλ%ns|ϕ(%ns−, a)|2n,Ls

 ,

which shows the part (a).

(b) Let (Yn, Zn, Kn), ( ˜Yn, ˜Zn, ˜Kn) be two solutions of (5). By the Itˆo formula,

eλ(t∧τn)|Yt∧τn n− ˜Yt∧τn n|2+ λ Z τn

t∧τn

eλ%ns|Ys−n − ˜Ys−n|2d%ns + Z τn

t∧τn

eλ%nskZs−n − ˜Zs−n k2d%ns

≤ (2µ + L2/ε) Z τn

t∧τn

eλ%ns|Ys−n − ˜Ys−n|2d%ns + ε Z τn

t∧τn

eλ%nskZs−n − ˜Zs−n k2d%ns

+ 2β Z τn

t∧τn

eλ%ns|Ys−n− ˜Ys−n|2n,Ls − 2 Z τn

t∧τn

eλ%ns(Ys−n − ˜Ys−n)(Zs−n − ˜Zs−n )dWsn.

Integrating and choosing ε < 1 such that 2µ + L2/ε < λ we complete the proof.

Proof of Theorem 2. The proof of the theorem we divide into three steps.

Step 1. For every natural M we construct a solution (YM, ZM, KM) of GRBSDE

YtM = ξ + Z M ∧τ

t∧τ

f (s, YsM, ZsM)ds + Z M ∧τ

t∧τ

ϕ(s, YsM)dΛs

(9)

− Z τ

t∧τ

ZsMdWs+ KM ∧τM − Kt∧τM , t ∈ R+

in the following way. Let ξM = E(ξ|FM) and Λτ be a process stopped in the stopping time τ , i.e., Λτt = Λt∧τ.

For t ∈ [0, M ] consider

YtM = ξM + Z M

t

1[0,τ ](s)f (s, YsM, ZsM)ds + Z M

t

ϕ(s, YsM)dΛτs (10)

− Z M

t

ZsMdWs+ KMM − KtM.

(10)

Since ξM is FM measurable, from [7] it follows that there exists a unique solution of (10) on a deterministic interval [0, M ]. Note that, on the set {t ≥ τ }, ξM = ξ and

YtM = ξ + 0 − Z M

t

ZsMdWs+ KMM − KtM.

By the uniqueness of the solution of BSDE, increments of the process KM are constant, i.e., KMM = KtM = KτM. Therefore YtM = ξ − RM

t ZsMdWs and in particular YτM = E(ξ|Fτ) = ξ. On the other hand, by the Itˆo formula

E



|YτM|2+ Z M

τ

kZsMk2ds



= E|ξ|2.

As a consequence, on the set {t ≥ τ } YtM = ξ, and ZtM = 0.

For t > M put YtM = ξt, ZtM = ζt and KtM = KMM. These processes satisfy YtM = ξ −

Z τ t

ZsMdWs,

and on the set {t ≥ τ }, YtM = ξt= ξ and ZtM = 0.

It can be shown that (compare [8]) E

 sup

t≤τ

eλt|YtM − a|2+ Z τ

0

eλt(|YtM − a|2t+ kZtMk2dt) + Z τ

0

eλtd|KM|t



≤ CE



eλτ|ξ − a|2+ Z τ

0

eλt|f (t, a, 0)|2dt + Z τ

0

eλt|ϕ(t, a)|2t

 , (11)

where Γt= Λt+ t. It is clear that the solution of (9) converges to the solution of (2) when M → ∞.

Step 2. For every M ∈ N we construct a sequence (Yn,M, Zn,M, Kn,M) of solutions of GRBSDE on [0, M ] which approximate the solution of (10) (compare [7]). We will show that this sequence converges to the solution of (5), when M → ∞. Let ξMn = E(ξn|FMn). For j = nM we put yτn,Mn

j = ξMn , zτn,Mn j = 0,

∆kτn,Mn

j+1 = 0. Next, for j = nM − 1, . . . , 0 we solve yτn,Mn

j = yτn,Mn j+1+ 1

nf

j/n, yτn,Mn j , zτn,Mn

j



1{[nτn]>j}

+ ϕ

j/n, yτn,Mn j



∆Λn,Lτn

j 1{[nτn]>j}− zn,Mτn j ∆Wτnn

j+1 + ∆kτn,Mn j+1.

(11)

If we put Ytn,M = yτn,Mn

[nt], Ztn,M = zτn,Mn

[nt] and Ktn,M = P

j≤[nt]∆kτn,Mn

j , then the triple (Yn,M, Zn,M, Kn,M) is a unique (compare Proposition (3)) solution of

Ytn,M = ξnM+

Z M ∧τn

t∧τn

f (%ns−, Ys−n,M, Zs−n,M)d%ns +

Z M ∧τn

t∧τn

ϕ(%ns−, Ys−n,M)dΛn,Ls

− Z M

t∧τn

Zs−n,MdWsn+ KM ∧τn,Mn− Kt∧τn,Mn, t ∈ [0, M ].

(12)

Let (Yn, Zn, Kn) be a solution of (5). For t ∈ [0, M ] we have

Yt∧τn n = YM ∧τn n+

Z M ∧τn t∧τn

f (%ns−, Ys−n, Zs−n )d%ns +

Z M ∧τn t∧τn

ϕ(%ns−, Ys−n)dΛn,Ls

Z M ∧τn t∧τn

Zs−n dWsn+ KM ∧τn n− Kt∧τn n.

By the Itˆo formula and assumptions,

eλ(t∧τn)|Ytn− Ytn,M|2+

Z M ∧τn t∧τn

eλ%ns(λ|Ys−n − Ys−n,M|2+ kZs−n − Zs−n,Mk2)d%ns

≤ eλ(M ∧τn)|YM ∧τn n− ξMn|2+ (2µ + L2/ε)

Z M ∧τn t∧τn

eλ%ns|Ys−n − Ys−n,M|2d%ns

+ ε

Z M ∧τn t∧τn

eλ%nskZs−n − Zs−n,Mk2d%ns + 2β

Z M ∧τn t∧τn

eλ%ns|Ys−n − Ys−n,M|2n,Ls (13)

− 2

Z M ∧τn t∧τn

eλ%ns(Ys−n − Ys−n,M)(Zs−n − Zs−n,M)dWsn.

Choosing ε < 1 such that 2µ + L2/ε < λ and after integrating we get

E



eλ(t∧τn)|Ytn− Ytn,M|2+

Z M ∧τn t∧τn

eλ%ns|Ys−n − Ys−n,M|2n,Ls

+

Z M ∧τn t∧τn

eλ%ns(|Ys−n − Ys−n,M|2+ kZs−n − Zs−n,Mk2)d%ns



≤ CEeλ(M ∧τn)|YM ∧τn n− ξMn|2.

(12)

Moreover, taking supremum in (13) we get E sup

t≤M

eλ(t∧τn)|Ytn− Ytn,M|2≤ CEeλ(M ∧τn)|YM ∧τn n− ξMn|2.

Similarly we can compute for λ0 such 2µ + L2/ε = λ0< λ. Since sup

n

Eeλ(M ∧τn)|YM ∧τn n− ξMn|2 ≤ 2 sup

n

E sup

t≤τn

eλt|Ytn|2+ 2 sup

n

Eeλτnn|2 < ∞

and Eeλ0(M ∧τn)|YM ∧τn n− ξnM|2 ≤ Ce0−λ)MEeλ(M ∧τn)|YM ∧τn n− ξnM|2, we have

M →∞lim sup

n

E

 sup

t≤τn

eλ0t|Ytn− Ytn,M|2+

Z M ∧τn

0

eλ0%nskZs−n − Zs−n,Mk2d%ns

+

Z M ∧τn 0

eλ0%ns|Ys−n − Ys−n,M|2n,Ls + sup

t≤τn

|Ktn− Ktn,M|2



= 0.

Step 3. Using the proof of Theorem 4.1 in [7] we get

n→∞lim E

 sup

t≤M

|Yt∧τn,Mn− Yt∧τM |2+ Z M

0

kZt−n,M,τn− ZtM,τk2dt

+ Z M

0

|Yt−n,M,τn− YtM,τ|2t+ sup

t≤M

|Kt∧τn,Mn− Kt∧τM |2



= 0.

Combining arguments from steps 1–3 we complete the proof.

4. Partial differential equations

In [7] and [16] it was shown that GRBSDE with deterministic terminal time gives a probabilistic formula for the viscosity solution to an obstacle problem for parabolic PDE with Neumann boundary condition. Moreover, in [7] the appli- cation of the discrete approximation in solving appropriate PDE was given. In [8] the connection between GRBSDE with random terminal time and an obstacle problem for elliptic PDE with Neumann boundary condition was shown. Here we will give an application of the numerical scheme in solving PDE.

Let O, G be open connected bounded and smooth subsets of Rm such that G ∩ O 6= ∅ and ∂O ∩ G 6= ∅, ∂G ∩ O 6= ∅.

Assume that b : Rm→ Rm and σ : Rm→ Rm×m are Lipschitz functions, i.e.

for some L0 > 0, all x, x0 ∈ Rm

(B1) |b(x) − b(x0)| + kσ(x) − σ(x0)k ≤ L0|x − x0|

(13)

and let (Xx, Ax) be a solution of SDE with reflection, i.e., Xtx= x +

Z t 0

b(Xsx)ds + Z t

0

σ(Xsx)dWs+ Axt, t ∈ R+, (14)

where P (Xx ∈ ¯O) = 1, Ax is a process with locally finite variation |Ax|, that increases only if Xtx ∈ ∂O; Ax0 = 0, X0 = x ∈ O ∩ G (for a unique existence see [9]).

In particular, if O = {x; φ(x) > 0}, ∂O = {x; φ(x) = 0} for some φ ∈ Cb2(Rm) such that |∇φ(x)| = 1 for x ∈ ∂O, then

Axt = Z t

0

∇φ(Xsx)d|Ax|s = Z t

0

∇φ(Xsx)1{Xx

s∈∂O}d|Ax|s. Define τx= inf{t ≥ 0; Xtx∈ G} and assume that/

(B2) Eτx< ∞.

Suppose that D = (a1, b1) × (a2, b2) × . . . × (ad, bd) and g : ∂G ∩ ¯O → ¯D. Let (Yx, Zx, Kx) be a solution of GRBSDE with data (τx, g(Xτxx), F, Φ, |Ax|), where F (t, ω, y, z) = f (Xtx(ω), y, z), Φ(t, ω, y) = ϕ(Xtx(ω), y), t ∈ R+, ω ∈ Ω, y ∈ Rd, z ∈ Rd×m, i.e.

Yt∧τx x = g(Xτxx) + Z τx

t∧τx

f (Xθx, Yθx, Zθx)dθ + Z τx

t∧τx

ϕ(Xθx, Yθx)d|Ax|θ

− Z τx

t∧τx

ZθxdWθ+ Kτxx − Kt∧τx x, t ∈ R+. (15)

Assume that functions g, f and ϕ are continuous and there exist constants κ, p ≥ 0, L > 0, µ ∈ R and β < 0 such that µ + L2< 0 and for any x ∈ Rm, y, y0 ∈ Rd, z, z0 ∈ Rd×m,

|g(x)| ≤ κ(1 + |x|p), hy − y0, f (x, y, z) − f (x, y0, z)i ≤ µ|y − y0|2,

|f (x, y, z) − f (x, y0, z0)| ≤ L |y − y0| + kz − z0k , (B3) |f (x, y, 0)| ≤ κ(1 + |y|), |ϕ(x, y)| ≤ κ,

|ϕ(x, y) − ϕ(x, y0)|i ≤ L|y − y0|, hy − y0, ϕ(x, y) − ϕ(x, y0)i ≤ β|y − y0|2,

E Z τx

0

|f (Xtx, ξt, ζt)|2dt < ∞,

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