DECOMPOSABLE HULLS OF MULTIFUNCTIONS Andrzej Nowak
Silesian University Institute of Mathematics Bankowa 14, 40–007 Katowice, Poland
e-mail: anowak@ux2.math.us.edu.pl and
Celina Rom University of Bielsko–BiaÃla Department of Mathematics Willowa 2, 43–309 Bielsko–BiaÃla, Poland
Abstract
Let F be a multifunction with values in L
p(Ω, X). In this note, we study which regularity properties of F are preserved when we consider the decomposable hull of F .
Keywords: decomposable set, multifunction, decomposable hull.
2000 Mathematics Subject Classification: 26E25, 49J53, 54C60.
1. Definitions and some elementary properties
In this section, we give the notation and definitions used in the whole paper.
Let (Ω, Σ, m) be a measure space and (X, k·k) a separable Banach space. By L
p(Ω, X) we mean the Banach space of equivalence classes of Σ-measurable functions v : Ω −→ X with the norm kvk
Lp= ( R
Ω
kvk
pdm)
p1< +∞ for
1 ≤ p < +∞, and kvk
Lp= ess sup
ω∈Ωkv(ω)k < +∞ for p = +∞. An open
ball in L
p(Ω, X) with the center v and radius r is denoted by B(v, r). For
A ∈ Σ we denote by χ
Athe characteristic function of A. We call a set K ⊂
L
p(Ω, X) decomposable if for all u, v ∈ K and each A ∈ Σ, χ
Au+χ
Ω\Av ∈ K
(cf. Hiai and Umegaki [1], Olech [3]). Let A ⊂ L
p(Ω, X). By a decomposable
hull of A, dec A, we mean the smallest decomposable subset of L
p(Ω, X) which contains A, i.e.
dec A := \
{K : A ⊂ K and K ⊂ L
p(Ω, X) decomposable}.
A closed decomposable hull of A, cl dec A, is the smallest closed and decom- posable subset of L
p(Ω, X) containing A. It is not difficult to see that
dec A = n X
ni=1
χ
Aiv
i: A
i∈ Σ, v
i∈ A, i = 1, . . . , n, [
n i=1A
i= Ω, A
i∩ A
j= ∅
for i 6= j, n ∈ N o
and cl dec A = cl (dec A), where cl denotes the closure operation. Such a representation of elements from dec A will be used in the whole paper.
Let T, Y be nonempty sets. By P(Y ) we denote the family of all nonempty subsets of Y . A mapping F : T −→ P(Y ) is called a multi- function from T to Y . For Z ⊂ Y we define
F
−1(Z) = {t ∈ T : F (t) ∩ Z 6= ∅}, F
−1(Z) = {t ∈ T : F (t) ⊂ Z}.
In this paper, we study multifunctions from a topological or measurable space T into L
p(Ω, X). We associate with F : T −→ P(L
p(Ω, X)) two new multifunctions G(t) := dec F (t) and G
1(t) := cl dec F (t), and examine which regularity properties of F (e.g., measurability, continuity) are preserved for G and G
1. The results obtained are analogous to classical theorems on the convex hull of a multifunction.
2. Weakly measurable multifunctions
Throughout this section (T, Γ) is a measurable space, Y is a metric space,
and L
p(Ω, X), 1 ≤ p < +∞, is defined for (Ω, Σ, m) with a finite measure
m. A multifunction F : T −→ P(Y ) is called weakly measurable if F satisfies
the condition F
−1(U ) ∈ Γ for each open set U ⊂ Y (cf. [2]). A countable
family V of measurable selections of F such that F (t) =cl{f (t) : f ∈ V } for
all t ∈ T is called a Castaing representation of F .
The following theorem characterizes weakly measurable multifunctions:
Theorem A ([2], Theorem 5.6). Let Y be a separable complete metric space, and F : T −→ P(Y ) a closed-valued multifunction. Then F is weakly measurable iff it has a Castaing representation.
Using this characterization we prove the following result:
Theorem 1. Suppose 1 ≤ p < +∞, L
p(Ω, X) is separable, and F : T −→
P(L
p(Ω, X) is a weakly measurable multifunction with closed values. Then the multifunctions G, G
1: T −→ P(L
p(Ω, X)) defined by G(t) := dec F (t), G
1(t) := cl dec F (t), t ∈ T , are also weakly measurable.
In the proof of Theorem 1 we use two lemmas. For A, B ∈ Σ we denote by A ÷ B the symmetric difference of A and B.
Lemma 1. Suppose L
p(Ω, X) is separable. Then there exists a countable family Π ⊂ Σ such that for each ² > 0 and each A ∈ Σ there is B ∈ Π satisfying m(A ÷ B) < ².
P roof. Fix z ∈ X with kzk = 1 and consider the set Z = {χ
Az : A ∈ Σ}.
Since L
p(Ω, X) is separable, Z has a countable dense subset E. Let Π be a countable family of B ∈ Σ such that χ
Bz ∈ E, where we identify A
1, A
2with m(A
1÷ A
2) = 0. Hence, for each ² > 0 and A ∈ Σ there exists B ∈ Π such that m(A ÷ B) = kχ
Az − χ
Bzk
pLP< ².
Lemma 2. Suppose L
p(Ω, X) is separable. Let A be a subset of L
p(Ω, X), B a dense subset of A, and Π such as in Lemma 1. Then
V = {χ
B1y
1+ χ
B2\B1y
2+ . . . + χ
Bk−1\Sk−2
i=1 Bi
y
k−1+ χ
Ω\Sk−1i=1Bi
y
k: B
1, . . . , B
k−1∈ Π, y
1, . . . , y
k∈ B, k ∈ N}
is a dense subset of cl dec A.
P roof. We shall show that for each z ∈ dec A and each ² > 0 there exists v ∈ V such that kz − vk
Lp< ². Fix z ∈ dec A and ² > 0. The function z has a representation z = P
ki=1
χ
Aiz
iwhere k ∈ N, z
i∈ A, A
i∈ Σ, i = 1, . . . , k, S
ki=1
A
i= Ω, A
i∩ A
j= ∅ for i 6= j. Since B is dense in A, for each
δ > 0 there exist y
1, . . . , y
k∈ B such that kz
i− y
ik
Lp< δ, i = 1, . . . , k. Let
Π ⊂ Σ be such as in Lemma 1. For each η > 0 and each i = 1, . . . , k − 1 there is B
i∈ Π satisfying m(A
i÷ B
i) < η. Denote
C
1= B
1, C
2= B
2\ B
1, . . . , C
k−1= B
k−1\
k−2
[
i=1
B
i, C
k= Ω \
k−1
[
i=1
B
iand v = P
ki=1
χ
Ciy
i. By our construction, v ∈ V. We shall prove that for δ and η sufficiently small, kz − vk
Lp< ². We have
kz − vk
Lp= k X
k i=1(χ
Aiz
i− χ
Ciy
ik
Lp≤ X
ki=1
kχ
Aiz
i− χ
Ciy
ik
Lp.
For a fixed i ∈ {1, 2, . . . , k}, kχ
Aiz
i− χ
Ciy
ik
pLp=
Z
Ω
kχ
Aiz
i− χ
Ciy
ik
pdm = Z
Ai∩Ci
kz
i− y
ik
pdm
+ Z
Ai\Ci
kz
ik
pdm + Z
Ci\Ai
ky
ik
pdm.
Observe that R
Ai∩Ci
kz
i− y
ik
p< δ
p. For i < k we have C
i\ A
i⊂ B
i\ A
iand A
i\C
i= (A
i∩B
1)∪. . .∪(A
i∩B
i−1)∪(A
i\B
i). Consequently, m(C
i\A
i) < η and m(A
i\ C
i) < iη. Since A
k= Ω \ S
k−1i=1
A
i, we have C
k\ A
k⊂
k−1
[
i=1
A
i\ B
i, A
k\ C
k⊂
k−1
[
i=1
B
i\ A
i.
Hence, m(C
k\ A
k) ≤ (k − 1)η and m(A
k\ C
k) ≤ (k − 1)η. By the ab- solute continuity of integral, for each γ > 0 there is η > 0 such that R
Ai\Ci
kz
ik
pdm < γ, R
Ci\Ai
ky
ik
pdm < γ, i = 1, 2, . . . , k. Thus we obtain the estimation kz − vk
Lp≤ k(δ
p+ 2γ)
1p. If δ, γ and η are sufficiently small, then kz−vk
Lp< ². From here it follows that dec A ⊂ cl V and, consequently, cl dec A ⊂ cl V. A converse inclusion is obvious.
P roof of T heorem 1. By Theorem A the multifunction F has a Cas-
taing representation V
F. We shall construct a Castaing representation for
the multifunction G
1. Let Π ⊂ Σ be such as in Lemma 1. Denote
V := ©
g : T −→ L
p(Ω, X) | g(t) = χ
B1f
1(t) + χ
B2\B1f
2(t) + . . . + χ
Bk−1\Sk−2
i=1Bi
f
k−1(t) + χ
Ω\Sk−1i=1Bi
f
k(t), B
1, . . . , B
k−1∈ Π f
1, . . . , f
k∈ V
F, k ∈ N} .
Let us note that the set V is countable and by Lemma 2, G
1(t) = cl {g(t) : g ∈ V} for each t ∈ T . Next we shall show that each g ∈ V is measur- able. To this end, fix C ∈ Σ and consider the function S
C: v −→ χ
Cv, v ∈ L
p(Ω, X). Since S
Cis continuous, all functions S
C◦ f, f ∈ V
F, are measurable. For fixed sets C
1, . . . , C
k∈ Σ and functions f
1, . . . , f
k∈ V
Fthe function g defined by g(t) := χ
C1f
1(t) + . . . + χ
Ckf
k(t) is measurable too, as the sum of measurable functions S
Ci◦ f
i, i = 1, . . . , k. Thus V is a Castaing representation of G
1and, by Theorem A, we conclude that G
1is weakly measurable. The multifunction G is weakly measurable too, because G
−1(U) = G
−11(U) for every open set U in L
p(Ω, X).
3. Lower and upper semicontinuous multifunctions In this section, (T, τ
1), (Y, τ
2) denote topological spaces. Recall that a multifunction F : T −→ P(Y ) is called lower semicontinuous if for every U ∈ τ
2, F
−1(U ) ∈ τ
1, and F is called upper semicontinuous if for every U ∈ τ
2, F
−1(U ) ∈ τ
1.
For lower semicontinuous multifunctions F : T −→ P(L
p(Ω, X)) we have the following theorem:
Theorem 2. Let 1 ≤ p < +∞ and F : T −→ P(L
p(Ω, X)) be a lower semicontinuous multifunction. Then the multifunctions G, G
1: T −→
P(L
p(Ω, X)) defined by G(t) := dec F (t), G
1(t) := cl dec F (t), t ∈ T , are also lower semicontinuous.
P roof. At first we shall show that for each open ball B(z, ²) in L
p(Ω, X), the set G
−1(B(z, ²)) is open in T . Let us observe that t ∈ G
−1(B(z, ²)) iff there exists y ∈ G(t) satisfying ky − zk
Lp< ². Each y ∈ G(t) can be represented as y = P
ni=1
χ
Aiy
iwhere n ∈ N, y
i∈ F (t), A
i∈ Σ, for
i = 1, . . . , n, S
ni=1
A
i= Ω, A
i∩ A
j= ∅ for i 6= j. For such a function y we have
ky − zk
pLp= Z
Ω
k X
n i=1χ
Aiy
i− zk
pdm = X
n i=1Z
Ai
ky
i− zk
pdm.
The inequality ky − zk
Lp< ² is satisfied iff there exist positive numbers
²
1, . . . , ²
nsuch that P
ni=1
²
pi< ²
pand R
Ai
ky
i− zk
pdm < ²
pifor i = 1, . . . , n.
For a fixed n ∈ N and ² > 0 we introduce the family D
n:=
n
(A
1, . . . , A
n, ²
1, . . . , ²
n) : A
i∈ Σ, ²
i> 0, i = 1, . . . , n, [
n i=1A
i= Ω,
A
i∩ A
j= ∅ for i 6= j, ²
p1+ . . . + ²
pn< ²
po
. Let V
A,²:= {t ∈ T : there exists y ∈ F (t) such that R
A
ky − zk
pdm < ²
p}.
For α = (A
1, . . . , A
n, ²
1, . . . , ²
n) ∈ D
ndenote X
α= T
ni=1
V
Ai, ²i. Now it is not difficult to see that G
−1(B(z, ²)) = S
n∈N
S
α∈Dn
X
α. For fixed A ∈ Σ, z ∈ L
p(Ω, X) and ² > 0 we denote
U
A, ²= n
x ∈ L
p(Ω, X) : Z
A
kx − zk
pdm < ²
po
.
Let us observe that V
A, ²= F
−1(U
A, ²). Since the function x −→ R
A
kx − zk
pdm is continuous, U
A, ²is open in L
p(Ω, X). Thus the sets V
A, ²and G
−1(B(z, ²)) are open in T . If U is an open set in L
p(Ω, X), then
G
−1(U) = G
−1³ [
{B(z, ²) : z ∈ U, B(z, ²) ⊂ U}
´
= [ {G
−1(B(z, ²)) : z ∈ U, B(z, ²) ⊂ U}
is open in T . Consequently, the multifunctions G and G
1are lower semi- continuous.
Remarks.
1. Our Theorem 2 also holds for L
∞(Ω, X); the above proof needs only
some obvious changes.
2. Theorem 2 is a generalization of Proposition 6.3 from [4], where the authors assumed that T is a σ-compact metric space. (We are grateful to the Referee for this information).
In the case of the upper semicontinuity there is no result similar to Theo- rem 2. Let us consider the following example, where T = X = R with the natural topology, Ω = [−1, 1], Σ is the σ-field of Lebesgue measurable sets and m is the Lebesgue measure.
Let F : R −→ P(L
1([−1, 1], R)) be given as F (t) = {f
1,t, f
2,t}, where f
1,t(u) = t, f
2,t(u) = 0, u ∈ [−1, 1], t ∈ R. It is easy to show that F is upper semicontinuous.
We shall prove that G(t) = dec F (t), t ∈ R, is not upper semicontinuous.
Let (A
k) be the sequence of subsets of [0, 1] defined by
A
1= [0, 1], A
2=
· 0, 1
2
¸
, . . . , A
k=
"
0 ∗ µ 1
2
¶
k−1, 1 ∗
µ 1 2
¶
k−1#
∪
"
2 ∗ µ 1
2
¶
k−1, 3 ∗
µ 1 2
¶
k−1#
∪ . . . ∪
"
³
2
k−1− 2
´
∗ µ 1
2
¶
k−1,
³
2
k−1− 1
´
∗ µ 1
2
¶
k−1# ,
k = 3, 4, . . . and consider the functions h
n= (1 +
8n1)χ
An∈ L
1([−1, 1], R), n ∈ N. Let us note that kh
k− h
lk
L1>
14for k 6= l. Thus the set {h
1, h
2, . . .}
has no accumulation point. Consequently, it is closed in L
1. The set U = L
1([−1, 1], R) \ {h
1, h
2, . . .} is open and G(1) = {χ
A: A ∈ Σ} ⊂ U, since h
n6∈ G(1) for every n ∈ N. Thus t = 1 ∈ G
−1(U) but (1−², 1+²) 6⊂ G
−1(U) for every ² > 0. Indeed, for each n ∈ N, h
n= (1 +
8n1)χ
An∈ G(1 +
8n1).
4. H-continuous multifunctions
Let (T, τ ) be a topological space and (Y, d) a metric space. For A ⊂ Y we
denote B(A, ²) = {y ∈ A : d(y, A) < ²}. A multifunction F : T −→ P(Y )
is called H-upper (H-lower) semicontinuous at t
0∈ T iff for every ² > 0
there exists a neighbourhood U of t
0such that for every t ∈ U, F (t) ⊂
B(F (t
0), ²) (respectively, F (t
0) ⊂ B(F (t), ²)). A multifunction F : T −→
P(Y ) is H-continuous iff F is H-upper and H-lower semicontinuous at every t ∈ T .
The following example shows that also in the case of the H-continuity there is no result similar to Theorem 2. Let T = X = R with the natural topology, Ω = [−1, 1], Σ be the σ-field of Lebesgue measurable sets and m the Lebesgue measure. We define F : R −→ P(L
1([−1, 1], R)) as
F (t) =
( clB(θ, |t|), t 6= 0 {θ}, t = 0 where θ denotes zero in L
1([−1, 1], R). Then
dec F (t) = cl dec F (t) =
( L
1([−1, 1], R), t 6= 0
{θ}, t = 0
It is easy to show that F is H-continuous but G(t) = dec F (t) and G
1(t) = cl dec F (t) are not H-upper semicontinuous at t
0= 0. Note that unlike the previous example, the multifunction F is not upper semicontinuous, except t = 0.
In this case we have only the following theorem.
Theorem 3. Let T be a topological space and let f
i: T −→ L
p(Ω, X), i = 1, 2, . . . , k, be continuous functions. Then the multifunction F : T −→
P(L
p(Ω, X)) defined by F (t) = dec {f
1(t), . . . , f
k(t)} is H-continuous.
P roof. Fix t
0∈ T and ² > 0. Since f
1, . . . , f
kare continuous, there is a neighbourhood U of t
0such that for each t ∈ U, kf
i(t) − f
i(t
0)k ≤
1k², i = 1, 2, . . . , k. We shall prove that for t ∈ U we have F (t) ⊂ B(F (t
0), ²) and F (t
0) ⊂ B(F (t), ²).
In order to show the first inclusion, we fix t ∈ U and y ∈ F (t). Then
y = X
ki=1
χ
Aif
i(t),
where A
1, . . . , A
k∈ Σ, i = 1, . . . , k, S
ki=1
A
i= Ω, A
i∩ A
j= ∅ for i 6= j.
Observe that
z = X
ki=1
χ
Aif
i(t
0) ∈ F (t
0),
and
ky − zk
Lp≤ X
ki=1