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156 (1998)

Endomorphism algebras over large domains

by

udiger G ¨ o b e l (Essen) and Simone P a b s t (Dublin)

Abstract. The paper deals with realizations of R-algebras A as endomorphism al- gebras End G ∼ = A of suitable R-modules G over a commutative ring R. We are mainly interested in the case of R having “many prime ideals”, such as R = R[x], the ring of real polynomials, or R a non-discrete valuation domain.

0. Introduction. This work is based on a previous paper [3] on realiza- tion theorems. In [3] an R-module G over a commutative ring R with 1 6= 0 is constructed such that the endomorphism algebra of G coincides with a given R-algebra A (in general modulo an ideal). There is a given countable multi- plicatively closed subset S of R such that A and therefore G is S-torsion-free and S-reduced; recall that an R-module G is S-torsion-free if gs = 0 implies g = 0 for any s ∈ S, g ∈ G, and it is S-reduced if T

s∈S Gs = 0. Such con- structions are by now standard, they are discussed in [3] and in some of the references given there. The desired module G can be constructed between a free A-module B and its S-adic completion b B.

However, it is clear that in many cases S must be uncountable in order to have T

s∈S As = 0; for example, if R is a valuation domain with a lattice of ideals not coinitial to ω and A = R, then T

s∈S As 6= 0 for all countable S ⊆ R \ {0} (see [6]). In this case a different technique is needed to realize a given algebra A as endomorphism algebra of some module G. The topological methods may not work any longer for |S| > ℵ 0 since the natural S-topology (generated by Gs (s ∈ S)) may not be metrizable; see Example 3.8 in [7].

However, if S is uncountable, which may be necessary as we have seen, a construction of the desired module G is given in [8]. This construction [8] is difficult and awaits simplification. A first simplification is given in [9]; but here R is restricted to be a Pr¨ ufer ring.

1991 Mathematics Subject Classification: 08A35, 13Cxx, 13L05, 20K20, 20K30.

This work is supported by GIF project No. G-0294-081.06/93 of the German–Israeli Foundation for Scientific Research & Development.

[211]

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Our present purpose is to link the construction for |S| > ℵ 0 with the much easier topological methods in the countable case as given for example in [3]; by doing so, we do not achieve realization theorems for the same general class of R-algebras A as in [8]. It is our intention to present an easier proof. Note that the “local approach” used in this paper might be of interest for considering other problems; it seems likely that results related to a countable multiplicatively closed subset could be generalized to the uncountable case by using this technique.

The following easy observation (Lemma 2.1 of [1]) is the key to replacing the uncountability of S by a family of pleasant topologies, one for each s ∈ S;

in this case s-reduced and s-torsion-free refer to the new set {s n | n < ω}.

Observation 0.1. Let S ⊆ R, s ∈ S and let G be S-torsion-free. More- over , let s ω G = T

n<ω Gs n and G s = G/s ω G. Then G s is s-torsion-free and s-reduced, and every endomorphism σ of G induces a canonical endomor- phism σ s of G s continuous in the s-topology on G s .

In [3] and [8] unwanted endomorphisms are killed by considering their action on a fixed free module B = L

A (and adding new elements to B);

in this paper we investigate their induced action on B s . We are able to control the endomorphisms on B, getting rid of their induced counterparts for all possible (uncountably many) s ∈ S. This way we obtain realization theorems for R-algebras A as discussed at the end of this section.

First we want to describe the required tools which may be interesting in their own right. In order to find the desired elements needed to enlarge the base module B and to kill unwanted homomorphisms, we must be able to embed such a B into a suitable (larger) algebraically compact module e B.

This, of course, is closely related to the work of R. Warfield [11]. However, we are interested in an explicit construction in order to say more about e B (see 1.3). An approach using reduced powers is given in §1. The link to the aforementioned s-topologies is given by:

Theorem 1.6. Let e B be an algebraically compact R-module, G an S-RD- submodule of e B, s ∈ S and let c G s denote the s-adic completion of G s . Then there exists a monomorphism φ : c G s → e B s where φ¹G s is the canonical embedding of G s into e B s .

In order to apply Shelah’s combinatorial machinery, the Black Box Lem-

ma 3.2, the source of elements waiting for the construction of the final

module has to be selected carefully. Such potential elements are provided

in §2. In §3 we adopt Shelah’s combinatorial idea and present it in a form

suitable for application in §4 and §5; as a result we obtain a module G

depending on a given R-algebra A and G will be S-reduced and S-torsion-

free. In the classical case [3] we also find constructions for G to be (S-)

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torsion or (S-) mixed. It is not clear at present how to construct an S-torsion module G for |S| > ℵ 0 . However, it is easy to show that it is impossible to construct an S-mixed module G in the usual way for S not coinitial to ω, as stated in the following observation (see [9], p. 69).

Observation 0.2. Let S , A, R be as above with S not coinitial to ω, G an A-module and T a subset of G consisting of S-torsion elements. Moreover , assume that a support function [ ] is defined for G with |[g]| ≤ ℵ 0 for all g ∈ G, [g] = ∅ iff g = 0, and τ a = 0 implies τ 6∈ [ga] for all τ ∈ T, g ∈ G, a ∈ A. Then G is an S-torsion module.

However, the module G constructed here is an S-torsion-free A-module;

therefore we can identify A ⊆ End R G with scalar multiplication. Tradition- ally we want to find a two-sided ideal Ines G / End G such that End R G = A ⊕ Ines G (the general realization theorem). If the algebra is more special we are able to determine Ines G directly.

Let us summarize some of our main results. Since it is convenient to present first a realization in a simple case, we consider in §5 the cotorsion- free case separately, before we have a look at the general case (§6) and at an application (§7). Note that the notion of cotorsion-freeness used here differs slightly from the classical definitions in [3] and [8]. As mentioned before, we will get our realization theorems using local arguments, i.e. we get “local realizations” given by the following theorems.

Theorem 5.7. If A is a cotorsion-free R-algebra, then there exists an R-module G with End G s = A s for each s ∈ S.

Theorem 6.4. If A is an S-reduced and S-torsion-free R-algebra, then there exists an R-module G with End G s = A s ⊕ Ines G s for each s ∈ S.

Note that Ines G s consists of all endomorphisms of G s mapping c G s into G s . To lift these local realizations to a global realization End G = A(⊕ Ines G) we need additional assumptions. In the cotorsion-free case (§5) we shall assume that A is F -complete with respect to the filtration F = {s ω A | s ∈ S} (see [6]). Moreover, Ines G must be “well related” (see Defini- tion 6.5) in the general case. Note that an endomorphism φ of G is inessential if all induced endomorphisms φ s of G s (s ∈ S) are inessential.

Also, we shall introduce the notion of an ℵ 0 -cotorsion-free module; in a

sense the definition given in this paper (§7) generalizes the one used in [3]. If

A is ℵ 0 -cotorsion-free then Ines G contains exactly the locally “sub-finitely

generated” endomorphisms φ, i.e. Im φ s is contained in a finitely generated

submodule of G s for each s ∈ S (see Definition 7.1). It is easy to show that

under this assumption Ines G is well related. The main results are now given

as follows:

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Theorem 5.9. If A is F-complete and cotorsion-free, then there exists an R-module G with End G = A.

Theorem 7.9. If A is F-complete and ℵ 0 -cotorsion-free, then there exists an R-module G with End G = A ⊕ Fin l G.

Here Fin l G denotes the ideal of all locally sub-finitely generated endo- morphisms.

We finish the introduction with an example of an algebra A satisfying the hypothesis of 7.9. A non-trivial example of an F -complete, cotorsion-free algebra A is given in §5 (see Example 5.8).

Let R be a maximal valuation ring, S = R \ {0} and A = R. It is easy to see that R is ℵ 0 -cotorsion-free; moreover, R is linearly compact in the discrete topology (see [6], p. 20) and hence F -complete. Note that for a non-discrete R this really is an example with an uncountable S not coinitial to ω.

1. Algebraically compact modules. Let R be a non-zero commuta- tive ring with 1 6= 0. Modules will be considered as right R-modules.

First recall that an R-module M is algebraically compact if every finitely solvable system of linear equations over M has a global solution in M . It is well known that every R-module is pure embeddable in an algebraically compact module. Note that we call a submodule G of M a pure submodule if for every finite system of linear equations over G having a solution in M , there also exists a solution in G (notation: G ⊆ M ). A related concept is that of relative divisibility; recall that a submodule G of the R-module M is relatively divisible or an RD-submodule of M if G ∩ M r = Gr for all r ∈ R (notation: G ⊆ rd M ). It is well known that purity implies relative divisibility and that the concepts coincide for modules over Pr¨ ufer rings (see [11]).

Algebraically compact modules can be characterized in different ways, e.g. a module is algebraically compact if and only if it is pure injective (see [11], [12]). Moreover, it is sufficient to consider systems of |R| · ℵ 0 equations, i.e. it is enough to show that an R-module M is (|R| · ℵ 0 ) + -algebraically compact, to prove algebraic compactness (see [5], Ch. V). We will use the last mentioned fact to construct an algebraically compact module.

Note that there are many different ways to embed a given module in an

algebraically compact module (e.g. see [11], [10], [5]). For the convenience of

the reader unfamiliar with the concept we construct an algebraically com-

pact extension e B of a given module B using an approach via reduced powers

which will make the needed properties easy to prove; recall that the reduced

power B I /F of a module B with respect to a filter F is given by identifying

two elements (m i ) i∈I , (n i ) i∈I of B I whenever the set {i ∈ I | m i = n i } is

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an element of F . Using the definitions of a filter and the reduced power it is easy to verify that S-torsion-freeness and decompositions of B are inherited by reduced powers.

Proposition 1.1. Let B be an R-module.

(a) If B is S-torsion-free for some subset S of R, then B I /F is S-torsion- free.

(b) If B = C ⊕ D, then B I /F = C I /F ⊕ D I /F .

The first lemma (see Ex. 8 in [5], Ch. V) gives a useful relation between an R-module B and the reduced power B I /F with respect to a certain filter.

It will be our main tool for constructing an algebraically compact extension.

Lemma 1.2. Let B be an R-module, κ an infinite cardinal, I the set of all finite subsets of κ and F the filter generated by the collection X α = {m ∈ I | α ∈ m} (α < κ). Then the diagonal map δ : B → B I /F (m 7→

(m) i∈I /F ) is a pure embedding and every finitely solvable system of κ equa- tions over Bδ with coefficients in R has a solution in B I /F .

P r o o f. It easy to check that δ is a pure embedding; the proof is left to the reader. Thus we may identify B and Bδ.

We consider a finitely solvable system of κ equations P

x∈X xr x,α = m α (m α ∈ B, r x,α ∈ R, α < κ). For every i ∈ I there exists a solution m x,i

(x ∈ X) in B of the corresponding subsystem P

x∈X xr x,α = m α (α ∈ i).

We define m x = (m x,i ) i∈I /F for each x ∈ X. Since X α = {i ∈ I | α ∈ i} ∈ F is a subset of Y α = {i ∈ I | P

x∈X m x,i r x,α = m α } we get Y α ∈ F for each α < κ. Therefore (m x ) x∈X is a global solution in B I /F of the considered system.

We thank the referee for pointing out that we can achieve the same result using any κ-regular ultrafilter F (see [2], Cor. 4.3.14).

We are now ready to construct an algebraically compact extension.

Lemma 1.3. Let R be of cardinality κ ≥ ℵ 0 and let B be a non-zero R-module. Then there exists an R-module e B of cardinality less than or equal to |B| κ such that e B is an algebraically compact R-module containing B as a pure submodule.

P r o o f. e B is constructed in such a way that it is κ + -algebraically com- pact, which coincides with being algebraically compact. To get solutions for all finitely solvable systems of κ equations we apply Lemma 1.2 κ + times.

Therefore let I, F be as in Lemma 1.2. We get e B as the union of a smooth ascending chain {B α | α < κ + } satisfying the following conditions:

(1) B α is an R-module of cardinality at most |B| κ ,

(2) B α is a pure R-submodule of B α+1 , and

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(3) every finitely solvable system of κ equations over B α with coefficients in R has a solution in B α+1 .

For α = 0 let B 0 = B and if α is a limit then take B α = S

β<α B β . Now let α + 1 be a successor. Assume that B α has been constructed satisfying the conditions above. Defining B α+1 = B α I /F we immediately see that B α+1 satisfies (2) and (3) by Lemma 1.2 and (1) is given by |B α+1 | ≤

|B α I | = |B α | |I| ≤ (|B| κ ) κ = |B| κ . Define e B = S

α<κ

+

B α ; obviously, e B is an R-module of cardinality at most κ + · |B| κ = |B| κ containing B as a pure R-submodule. Moreover, every finitely solvable system of κ equations over e B turns out to be a system over B α for some α < κ + since κ + is a regular cardinal. Hence, there is a solution in B α+1 ⊆ e B. So, e B is κ + -algebraically compact and thus it is algebraically compact.

We would like to point out an interesting fact: the above construction is also suitable for extending the ring structure of R to an algebraically compact module e R such that e B becomes an e R-module (see e.g. [9]). Note that e B need not be algebraically compact as an e R-module.

We reserve the notation “e” for an algebraically compact module con- structed as in Lemma 1.3.

The next corollary is an immediate consequence of Proposition 1.1 and the previous lemma; since S-torsion-freeness and decompositions are inher- ited by reduced powers, the above construction guarantees that they are also inherited by algebraically compact extensions.

Corollary 1.4. (a) If B is S-torsion-free for some subset S ⊆ R, then B is also S-torsion-free. e

(b) If B = C ⊕ D is any decompostion of an R-module B, then e B = C ⊕ e e D.

In the main part of this section we investigate the relation between an algebraically compact module and canonical topological completions of its S-RD-submodules, where S ⊆ R is a given multiplicatively closed subset.

Note that we call a submodule G of M an S-RD-submodule if M s ∩ G = Gs for all s ∈ S.

For an R-module M and s ∈ S we define s ω M = T

n<ω M s n and M s = M/s ω M . Obviously, M s is always s-reduced, i.e. reduced with respect to {s n | n < ω}, and if M is S-torsion-free then M s is s-torsion-free for each s ∈ S (see Observation 0.1). Moreover, for each s ∈ S, the following holds:

Proposition 1.5. If M is algebraically compact, then so is M s .

P r o o f. Suppose M is an algebraically compact R-module and let P

x∈X xr x,α = m α , m α = m α +s ω M (α < κ) be a finitely solvable system of

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equations over M s . We define a corresponding system of equations over M by P

x∈X xr x,α + y α = m α , y α = y α,n s n (α < κ, n < ω) where y α , y α,n are also unknowns. It is easy to check that this system is also finitely solvable.

Since M is algebraically compact by assumption, there is a global solution h x ∈ M (x ∈ X), h α ∈ s ω M (α < κ). Hence (h x + s ω M ) x∈X is a solu- tion of the considered system of equations. Therefore M s is algebraically compact.

The final theorem gives the basic idea for the “local” approach used to realize certain R-algebras.

Theorem 1.6. Let M be an algebraically compact R-module, G an S- RD-submodule of M , s ∈ S and let c G s denote the s-adic completion of G s . Then there exists a monomorphism φ : c G s ,→ M s where φ¹G s is the canonical embedding π : G s ,→ M s (g + s ω G 7→ g + s ω M ).

P r o o f. Proposition 1.5 allows us to define φ : c G s → M s in the following manner: let g ∈ c G s . We may express g as g = P

n<ω a n s n where a n ∈ G s and a n s n 6∈ G s s n+1 whenever a n s n is non-zero. Since x n − x n+1 s = a n (n < ω) is a system of equations over G s ⊆ M s which is finitely solvable, there is a solution x n = h n (n < ω) in M s . Now let φ be defined by gφ = h 0 . To verify that φ is well defined we consider an element g ∈ c G s with g = P

n<ω a n s n and g = P

n<ω b n s n and let (h n ) n<ω , (k n ) n<ω be the solutions of the corresponding systems of equations. Therefore, for each n < ω, we have h n − h n+1 s = a n and k n − k n+1 s = b n . Hence h 0 − k 0 = P n−1

i=0 (a i − b i )s i + (h n − k n )s n for each n < ω. By our assumption we have P n−1

i=0 (a i − b i )s i ∈ c G s s n ∩ G s = G s s n ⊆ M s s n and therefore h 0 − k 0 is an element of M s s n for every n < ω. Since M s is s-reduced, h 0 and k 0 coincide and thus φ is well defined.

As an immediate consequence we find that φ¹G s is the canonical embed- ding π.

It is easy to check that φ is an R-homomorphism, considering the corre- sponding systems of equations in the definition and using the fact that M s is s-reduced.

Finally, we show that φ is injective. Let g = P

n<ω a n s n ∈ c G s with a n s n 6∈ G s s n+1 for a n s n 6= 0. Suppose gφ = 0. Let (h n ) n<ω be a solution of the corresponding system of equations. Therefore we get 0 = gφ = h 0 = a 0 + h 1 s. Hence a 0 ∈ G s s, which implies a 0 = 0. So it follows that 0 = h 1 s = a 1 s + h 2 s 2 and by the same argument as before a 1 s = 0. Continuing this procedure implies a n s n = 0 for each n < ω, i.e. g = 0. Therefore φ is injective and this completes the proof.

Note that the previous result is also true with respect to an arbitrary

countable multiplicatively closed subset C of S. In particular, it follows that

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for an algebraically module M the quotient M C is complete in its C-adic topology, as is well known.

We now proceed to define a suitable “hull” within which we construct the desired module G.

2. Potential elements. In this section we specify the elements which will be suitable for the construction of the desired module G.

Let S ⊆ R be a fixed multiplicatively closed subset without zero divisors and let A be an S-torsion-free and S-reduced R-algebra. Moreover, we choose cardinals κ, λ such that λ = λ κ and κ ≥ |A| · |S|.

As in [3] and [8] we first define a free module B generated by a basis T which is equipped with a certain partial order. Let T be the tree given by T = ω> λ = {τ : n → λ | n < ω}. For each element τ of T the length of τ is the finite set l(τ ) = dom τ = n = {0, . . . , n − 1}. The elements of T are ordered by τ ≤ σ if l(τ ) ≤ l(σ) and σ¹l(τ ) = τ . An (infinite) branch of T is a map v : ω → λ; we can identify v with a linearly ordered subset of T by v = {v n = v¹n | n < ω} ⊆ T . Let Br T denote the set of all branches of T . Now we define B to be the free A-module generated by the tree T : B = L

τ ∈T τ A.

Let e B denote the algebraically compact R-module as obtained by Lem- ma 1.3, i.e. B ⊆ B and | e e B| ≤ |B| |R| . Also, by Corollary 1.4, e B is S- torsion-free and the decompositions of B are inherited by e B. In particular, for each τ ∈ T , we have e B = τ e A ⊕ ( L

σ6=τ σA) ; thus there is a unique τ -component b¹τ ∈ τ e A for any element b of e B. Therefore we may define a support function in the usual way (see also [3], [8]): for g ∈ e B, X ⊆ e B let [g] = {τ ∈ T | g¹τ 6= 0} and [X] = S

g∈X [g] be the support of g and of X, respectively. Since we shall argue mostly “modulo s” we also define the s-support of g and of X by [g] s = {τ ∈ T | g¹τ 6∈ τ s ω A} and e [X] s = S

g∈X [g] s , for each s ∈ S. Obviously, for any s ∈ S and for all g, h ∈ e B with g ≡ h mod s ω B, the s-supports [g] e s , [h] s coincide. Hence we may define the support of an element g = g +s ω B ∈ e e B s (s ∈ S) by [g] = [g] s . Moreover, g¹τ = g¹τ + τ s ω A defines a (unique) τ -component of g for any e τ ∈ T ; we get as an immediate consequence [g] = {τ ∈ T | g¹τ 6= 0} for any g ∈ e B s (s ∈ S).

Next we define a norm k k for the elements and subsets of T which canon- ically extends to the elements and subsets of e B and e B s = e B/s ω B (s ∈ S) e using the supports (see also [3], [8]). We fix a continuous strictly increasing function % : cf(λ) + 1 → λ + 1 such that 0% = 0 and cf(λ)% = λ. The norm kτ k of an element τ ∈ T is defined by kτ k = min{ν < cf(λ) | τ ∈ ω> (ν%)}

and the norm of a subset T 0 of T is given by kT 0 k = sup τ ∈T

0

kτ k. Note that

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kτ k = α means that α% is the smallest ordinal in Im % satisfying τ (i) < α%

for all i < l(τ ). Hence kτ k is always a successor ordinal. Also note that λ ⊆ T as elements of length 1, hence k k is also defined for each subset of λ.

Using the norm, for a subset T 0 of T and for any ordinal ν < λ, we define the part of T 0 to the right of ν by ν T 0 = {τ ∈ T 0 | kτ k > ν}.

In [3] elements for constructing the desired module are found within the S-adic completion of a free module B. As mentioned in §0 this is no longer possible for uncountable S. The required elements will be chosen from the algebraically compact module e B but not all are suitable. Following an idea in [8] we define potential elements needed in the construction; they are taken from e B

0

, the set of all elements of e B with countable support. For certain submodules U of e B we shall need “preimages” of elements of the s-adic completion of (U + s ω B)/s e ω B (“s” refers to the set {s e n | n < ω}). To be more precise we define a series (g k ) k<ω of elements of e B to be an (s, U )-chain (s ∈ S, U ⊆ e B) if g k − g k+1 s ∈ U and, for some ν < kg 0 k, ν [g k ] ⊆ [g 0 ] for each k < ω. We are now ready for

Definition 2.1. We define the set POT = POT(B) of potential elements in e B

0

inductively as follows:

(i) B ⊆ POT;

(ii) if (g k ) k<ω is an (s, U )-chain of elements of e B

0

and s ∈ S, U ⊆ POT, then g k is potential for all k < ω;

(iii) if bs ∈ POT and s ∈ S then b is potential;

(iv) elements of an A-module generated by potential elements are potential.

An A-module U ⊆ POT is called a potential module.

If a module U is an S-RD-submodule of e B we may consider c U s , the s-adic completion of U s = U/s ω U (s ∈ S), as a submodule of e B s (see Theorem 1.6).

Note that in this case we may identify U/s ω U with (U + s ω B)/s e ω B. Since e this is not possible in general, let us agree on using U s for (U + s ω B)/s e ω B e whenever U is not an S-RD-submodule of e B.

The notion of a canonical module has been proven useful (see e.g. [3], [8]); an S-RD-submodule of e B generated by at most κ potential elements containing its support [P ] is called a canonical module. Let C denote the set of all canonical modules; as an immediate consequence of the definition we get

Lemma 2.2. For P ∈ C, X ⊆ POT with |X| ≤ κ there exists P 0 ∈ C

with P ∪ X ⊆ P 0 . Moreover , C is non-empty and closed under unions of

countable ascending chains.

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In [3] and [8] the branches of T have been used to define elements play- ing a crucial role in the construction of the desired module. Instead of go- ing into the rather unusual notion of branches with leaves (see [8]) we use the idea from [3] replacing the S-adic limits by a family of corresponding (s, B)-chains.

Definition 2.3. For any branch v of T and s ∈ S, we define potential elements v k,s (k < ω) as a solution in ( L

τ ∈v τ A) of the following, finitely solvable system of equations over B: x k − x k+1 s = v k (= v¹k) (k < ω).

The above-defined elements have some nice properties:

Lemma 2.4. Let v ∈ Br T , s, q ∈ S, a ∈ A, a = a + q ω A ∈ A q , and v k,s = v k,s + q ω B. Then: e

(i) v k,s ¹v n = v n s n−k for any k ≤ n < ω, (ii) [v k,s ] = {v n | n ≥ k} for each k < ω, (iii) the sequence (v k,s ) k<ω is an (s, B)-chain, (iv) [v k,s a] ⊆ [v k,s a] ⊆ [v k,s ] ⊆ v,

(v) a = 0 ⇔ v k,s a = 0 ⇔ [v k,s a] is finite ⇔ v \ [v k,s a] is infinite, (vi) (as n = 0 for some n < ω) ⇔ v k,s a ∈ B q ⇔ [v k,s a] is finite ⇔ v \ [v k,s a] is infinite.

P r o o f. By 2.3 we immediately get [v k,s ] ⊆ {v n | n ≥ k} and v 0,s = P n

i=0 v i s i +v k+1,s s k+1 for each n, k < ω. Therefore v 0,s ¹v n = ( P n

i=0 v i s i )¹v n + v k+1,s s n+1 ¹v n = v n s n , which implies [v 0,s ] = {v n | n < ω}. Moreover, v k,s ¹v n = (v 0,s P k−1

i=0 v i s i )s −k ¹v n = v n s n−k for all k ≤ n < ω. Now parts (i) and (ii) are obvious and (iii) follows by the definition of an (s, B)-chain, 2.3 and part (ii). Moreover, (iv) is immediate from (ii) and the definition of the support.

Next we show (v). Clearly, a = 0 ⇒ v k,s a = 0 ⇒ [v k,s a] is finite ⇒ v \ [v k,s a] is infinite.

Conversely, assume v \ [v k,s a] is infinite. Therefore there are infinitely many n ≥ k such that v k,s a¹v n = 0. On the other hand, we have v k,s a¹v n = v n as n−k for each n ≥ k by (i). Hence as n−k = 0 for infinitely many n ≥ k.

Since A is S-torsion-free that implies a = 0.

Finally, we consider (vi). Assuming that there is an n < ω with as n = 0 (in A q ) we get either v k,s a = 0 ∈ B q for n = 0 or, for n > 0,

v k,s a ≡

n+k−1 X

i=k

v i as i−k + v k+n,s as n

n+k−1 X

i=k

v i as i−k + v k+n,s as n

n+k−1 X

i=0

v i as i−k mod q ω B, e

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which induces v k,s a ∈ B q . Hence [v k,s a] is finite and v \ [v k,s a] is infinite.

Now, if v \ [v k,s a] is infinite, we get 0 = v k,s a¹v i = v k,s a¹v i + q ω v i A for e infinitely many i < ω. Therefore v k,s a¹v i = v i as i−k ∈ q ω v i A for infinitely e many k ≤ i < ω. Hence as n ∈ q ω A ∩ A = q e ω A for some n < ω and this completes the proof.

3. Construction. Now we are going to construct the required R-module G. As in [3] and [8] we shall use Black Box arguments to prove realization theorems. Different versions of the Black Box are known; the one presented here is very similar to that given in [3].

First we need to say what we mean by a “trap”; since we are concerned only with discrete realizations we can omit one of the parameters used in the definition of “trap” in [3], but we shall need to use the elements s of S as an additional parameter. As we want to catch and “kill” homomorphisms via their induced actions on the corresponding quotients, it seems natural to consider endomorphisms on quotients from the outset. Our definition of a trap then becomes:

Definition 3.1. A quadruple (f, P, s, φ) is called a trap if f : ω> κ → T is a tree embedding, P is a canonical module, s ∈ S, and φ ∈ End P s satisfying the following conditions:

(a) Im f ⊆ P ,

(b) [P ] is a subtree of T ,

(c) kP k is a limit ordinal of cofinality ω, and (d) kvk = kP k for each v ∈ Br(Im f ).

We are now ready to present the Black Box in a suitable form.

The Black Box Lemma 3.2. For an ordinal λ ≥ λ there exists a transfinite sequence (f α , P α , s α , φ α ) α<λ

of traps such that, for α, β < λ ,

(i) β < α ⇒ kP β k ≤ kP α k,

(ii) β 6= α ⇒ Br(Im f β ) ∩ Br(Imf α ) = ∅, (iii) β + κ

0

≤ α ⇒ Br(Im f α ) ∩ Br([P β ]) = ∅,

(iv) if K is a potential module, X a subset of K with |X| ≤ κ, s ∈ S and φ ∈ End K s , then there exists an α < λ such that

X ≤ P α , kXk < kP α k, s = s α , and φ¹P α s = φ α .

A detailed proof of the existence of a slightly different Black Box is given in [3]. Besides the aforementioned differences it is necessary to replace the

“fixed” S-adic completion, as used in the version of the prediction prin-

ciple (iv) in [3], by arbitrary potential modules (see also [8]); this is due to

the fact that in general there is no “universal” module to which suitable

homomorphisms can be (uniquely) extended.

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Note that the Black Box is very robust under changes of its setting; the only real concern is the cardinality of the objects in question. Lemma 1.3 and the choice of κ and λ guarantee that all cardinalities of interest are bounded by λ.

Construction 3.3. Choose a transfinite sequence (f α , P α , s α , φ α ) α<λ

as in Lemma 3.2. Moreover, let ∞ be a fixed element which does not belong to e B.

We will construct inductively a sequence (b β ) β<λ

in POT ∪ {∞} and an ascending smooth chain (G µ ) µ≤λ

of potential modules such that, for all µ ≤ λ ,

(I µ ) b β + s ω β B 6∈ G e s µ

β

for each β < µ.

If µ = 0 we put G 0 = B = L

τ ∈T τ A. Therefore G 0 is a potential module by definition.

If µ is a limit we assume that the potential modules G α and the elements b β are given for all α, β < µ such that (I α ) is satisfied for each α < µ. We take G µ = S

α<µ G α , which is obviously also potential and it satisfies (I µ ) since b β + s ω β B 6∈ G e s α

β

for all β < α < µ.

Now let µ = α + 1 be a successor, G α a potential module and let the elements b β (β < α) be given satisfying (I α ). Suppose it is possible to choose a branch v α ∈ Br(Im f α ), an (s α , G α )-chain (g α k ) k<ω , b α ∈ POT ∪ {∞}, and G α+1 in such a way that (I α+1 ) and the following conditions are satisfied:

(II α+1 ) G α+1 = G α + P

k<ω g k α A,

(III α ) sup k<ω kg k α − v k,s α

α

k < kv α k (= kP α k), (IV α ) g k α + s ω α B ∈ d e P α s

α

for each k < ω, and (V α+1 ) either

b α + s ω α B = (g e α 0 + s ω α B)φ e α (1) or

b α = ∞. (2)

We then make such a choice and depending on the outcome of (V α ), we call α a strong ordinal in case (1) and a weak ordinal in case (2). Note that whenever it is possible to get α to be strong we do so. If such a choice is not possible, then we call α useless and we put G α+1 = G α , g α k = 0 (k < ω), and b α = ∞. (We shall show that in fact this case never arises.) However, in every case G α+1 consists of potential elements.

Finally, let G be given by

G = G λ

= B + X

α<λ

X

k<ω

g α k A

with b β + s ω β B 6∈ G e s

β

for each β < λ .

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Note that the above construction is also very similar to the one given in [3]; the obvious changes are due to the “local” approach used in this paper.

4. Properties of the constructed module. In this section we are going to assemble some properties of G, e.g. we shall describe the essential part of the support of the elements of G and G s (s ∈ S). Again, the re- sults and methods used are very similar to those in [3]; indeed, we get the same results with respect to the quotients G s for each s ∈ S. Moreover, we also need to include corresponding results for the elements of G. However, detailed proofs are given for the convenience of the reader.

First we summarize a few properties satisfied by the elements which we use to extend the submodules G α in the strong or weak case.

Lemma 4.1. Let α < λ be any weak or strong ordinal and s = s α . Then there exists ν < kv α k such that, for all a ∈ A, q ∈ S and k < ω,

(i) g k α a¹τ = v α k,s a¹τ for each τ with kτ k > ν, (ii) ν [g α k a] ⊆ ν [g α k a] = ν [v α k,s a] ⊆ v α ,

(iii) a = 0 ⇔ g k α a = 0 ⇔ ν [g k α a] is finite, and

(iv) (as n = 0 for some n < ω) ⇔ g α k a ∈ G q α ν [g α k a] is finite, where g α k = g α k + q ω B, a = a + q e ω A.

P r o o f. By (III α ) in Construction 3.3 we have sup k<ω kg k α −v α k,s k < kv α k.

Since kv α k is a limit ordinal by Definition 3.1 we may choose ν < kv α k such that ν > sup k<ω kg α k − v k,s α k. Therefore we get (g α k − v α k,s )¹τ = 0 for each τ with kτ k > ν. Hence, for any a ∈ A, we have g α k a¹τ = v k,s α a¹τ whenever kτ k > ν. So ν [g k α a] ⊆ ν [g k α a] = ν [v k,s α a] ⊆ v α according to Lemma 2.4, which proves (i) and (ii).

Clearly a = 0 ⇒ g α k a = 0 ⇒ ν [g α k a] is finite.

To complete (iii) assume that ν [g α k a] = ν [v α k,s a] is finite. By Lemma 2.4 we have [v k,s α a] ⊆ [v k,s α ] = {v α,i = v α ¹i | i ≥ k} = M . It follows that

ν [v k,s α a] is a finite subset of M and therefore there is n ≥ k such that

ν [v k,s α a] ⊆ {v α,i | k ≤ i ≤ n}. Now, since kv α,i k ≤ kv α,j k for all i ≤ j < ω, it follows that [v k,s α a] is finite. Hence a = 0 by Lemma 2.4 and therefore (iii) is proved.

For (iv) we assume as n = 0 (in A q ) for some n < ω. Using g α k+n as n 0 mod q ω B we get g e α k a ≡ g α k a − g k+n α as n mod q ω B. Since g e 0 = g k α − g α k+n s n is an element of G α by the definition of a chain, g α k a = g 0 a is an element of G q α .

Therefore ν [g α k a] ⊆ [g k α a] ⊆ v α ∩ [g 0 ] is finite because v α does not appear

before the (α + 1)th step by 3.3 and Lemma 3.2.

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Finally, assume that ν [g α k a] is finite. Therefore ν [v k,s α a] is finite according to (ii). Now, in the same way as before, we find that [v k,s α a] is finite. Hence as n = 0 (in A q ) for some n < ω by Lemma 2.4, which completes the proof.

In the next lemma we describe the supports of the elements of G and G s (s ∈ S). As also in [3] and [8], this will be the main tool for testing if a given potential element belongs to G or not.

The Recognition Lemma 4.2. Let g ∈ G \ B, s ∈ S, and g = g + s ω B ∈ G e s .

(a) (i) There exists a unique α < λ such that g ∈ G α+1 \ G α .

(ii) Moreover , either g ∈ B s or there is a unique β ≤ α such that g ∈ G s β+1 \ G s β .

(b) (i) With α as in (a)(i) there is a strictly decreasing sequence of ordinals α = α(0) > . . . > α(r) in λ (r < ω) with kP α(i) k = kP α k for i ≤ r and an ordinal ν < kP α k such that

ν [g] = F ∪ [

i≤r

ν [v α(i) ] (disjoint union)

where F is a finite set of elements of T each of norm greater than kP α k.

(ii) With β as in (a)(ii) there is a strictly decreasing sequence of ordinals β = β(0) > . . . > β(k) in λ (k < ω) with kP β(i) k = kP β k for i ≤ k and an ordinal µ < kP β k such that

µ [g] = F 0 [

i≤k

µ [v β(i) ] (disjoint union)

where F 0 is a finite set of elements of T each of norm greater than kP β k.

(c) (i) For any γ < λ with kP γ k = kP α k there exist a ∈ A and l < ω such that, for almost all τ ∈ v γ , we have g¹τ = τ as l(τ )−l γ .

(ii) For any δ < λ with kP δ k = kP β k there exist a 0 ∈ A s and l 0 < ω such that, for almost all τ ∈ v δ , we have g¹τ = τ a 0 s l(τ )−l δ

0

.

P r o o f. Since the modules G α (α ≤ λ ) and therefore the modules G s α (α ≤ λ ) form an ascending smooth chain, (a) is obviously satisfied.

Now g ∈ G α+1 = B + P

γ≤α

P

k<ω g α k A. By 3.3 we see that (g γ k ) k<ω is an (s γ , G γ )-chain for each γ ≤ α. Moreover, every strictly decreasing chain of ordinals is finite. Therefore we can split the sums in finitely many steps in such a way that we may consider g as an element of B + P

i≤n g m α(i) A for ordinals α = α(0) > . . . > α(n) and for some n, m < ω, i.e. g = b + P

i≤n g m α(i) a i (b ∈ B, a i ∈ A).

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Now, for every weak or strong ordinal γ we have kg m γ k = kP γ k (m < ω) by Lemmas 2.4 and 4.1. Moreover, the Black Box induces kP γ k ≤ kP γ

0

k ≤ kP α k whenever γ ≤ γ 0 ≤ α. Therefore there is r ≤ n such that kP α(i) k = kP α k for i ≤ r and kP α(i) k < kP α k otherwise. Hence g = b+x+ P

i≤r g α(i) m a i

where kxk ≤ max r<i≤n kg α(i) k < kP α k.

Since kP α k is a limit, [b] does not contain any element of norm kP α k. The branches v α(i) (i ≤ r) are different and therefore the pairwise intersections are finite. Thus we may choose ν < kP α k (large enough) such that

ν [g m α(i) a] = ν [v α(i) a] for i ≤ r,

ν [v α(i) ] ∩ ν [v α(j) ] = ∅ for i 6= j ≤ r,

• kxk < ν, and

• either kτ k ≤ ν or kτ k > kP α k for any τ ∈ [b].

Defining F = {τ ∈ [b] | kτ k > kP α k} we get ν [g] = F ∪ S

i≤r ν [v α(i) ], which is a disjoint union by our choice of ν. This proves part (i) of (b).

To get the second part of (b) we can use similar arguments.

Note that kg γ m k = kP γ k whenever s j γ 6∈ s ω A for all j < ω. Since g β(i) j a 0 i G s β(i) whenever a 0 i s j β(i) = 0 (in A s ) by Lemma 4.1, we may assume that s j β(i) 6∈ s ω A for all i ≤ k, i.e. we get g = b + P

i≤n g β(i) m a 0 i (b ∈ B s , a 0 i ∈ A s ).

Finally, we get (c) choosing a = a i (a 0 = a 0 i ) for γ = α(i) (δ = β(i)) for some i ≤ r (i ≤ k) and a = 0 (a 0 = 0) for γ 6∈ {α(0), . . . , α(r)}

(δ 6∈ {β(0), . . . , β(k)}).

As an immediate consequence of the above Recognition Lemma we have:

Corollary 4.3. An element g ∈ G is contained in B iff [g] is finite, and an element g ∈ G s (s ∈ S) is contained in B s iff [g] is finite.

Now we are ready to prove further properties of G.

Lemma 4.4. G is an RD-submodule of e B and G is S-reduced and S- torsion-free.

P r o o f. We immediately see that G ⊆ e B is S-torsion-free since e B is S-torsion-free by Corollary 1.4. We prove inductively that G is an RD- submodule of e B.

For ν = 0 we have G 0 = B ⊆ B and therefore G e 0 rd B. If ν is a limit e and if G µ rd B for all µ < ν, then G e ν = S

µ<ν G µ rd B, since RD-purity e is of finite character.

Now we investigate ν = α + 1 assuming G α rd B. If α is a useless e ordinal, then there is nothing to show since G α = G α+1 . Otherwise we consider ebr ∈ G α+1 \ G α with r ∈ R and eb ∈ e B. There are k < ω, 0 6= a ∈ A, and g ∈ G α such that

(1) ebr = g + g k α a.

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By Lemma 4.2 we see that [g] ∩ v α is finite. On the other hand, since a 6= 0, there is ν < kv α k such that

(2) ν [g k α a] = ν [v k,s α

α

] ⊆ v α is infinite by Lemma 4.1. Therefore, for all τ ∈ ν [g α k a] \ [g],

(3) ebr¹τ = (g α k a)¹τ.

By (2), (3) and Lemma 2.4 it follows that ebr¹τ = (g α k a)¹τ = (v k,s α

α

)¹τ = τ as l(τ )−k α for each τ ∈ ν [g α k a] \ [g]. Hence as l(τ )−k α is an element of Ar, i.e.

as l(τ )−k α = a 0 r for some a 0 ∈ A. According to the definition of an (s α , G α )- chain, g 0 = g α k a − g l(τ ) α as l(τ )−k α is an element of G α . Thus, using (1), we have g + g 0 = ebr − g l(τ ) α as l(τ )−k α = (eb − g α l(τ ) a 0 )r ∈ G α . Since G α rd B by e assumption, there exists h ∈ G α such that g +g 0 = hr = (eb−g α l(τ ) a 0 )r, which implies ebr = (h+g α l(τ ) a 0 )r where h+g α l(τ ) a 0 ∈ G α+1 . Therefore, G α+1 rd B. e Finally, G = S

α≤λ

G α rd B. e

Similarly, using the fact that A is S-reduced, it is easy to show by trans- finite induction that G = S

α≤λ

G α is an S-reduced R-module as well.

Note that we now may identify (G+s ω B)/s e ω B with G/s e ω G since G is an RD- and hence an S-RD-submodule of e B. Moreover, we may consider c G s , the s-adic completion of G s = G/s ω G, as a submodule of e B s by Theorem 1.6.

The key lemma for the non-existence of useless ordinals and for “killing”

unwanted endomorphisms is given next.

Lemma 4.5. Let α < λ , ν < kP α k, and for each v ∈ Br(Im f α ) let (g v k ) k<ω be an (s α , G α )-chain such that, for all k < ω, ν [g v k − v k,s

α

] = ∅.

Then there exists v ∈ Br(Im f α ) such that

(1) b β + s ω β B 6∈ (G e α+1 (v)) s

β

for all β < α where G α+1 (v) = G α + P

k<ω g v k A.

P r o o f. Let s = s α and suppose that the conclusion is false. Then there exists, for each v ∈ Br(Im f α ), an ordinal β = β(v) such that b β + q ω B ∈ e (G α+1 (v)) q where q = s β . By our Construction 3.3 that means b β 6= ∞ and b β + q ω B = (g e 0 β + q ω B)φ e β ∈ c P β q . Moreover, there are a = a(v) ∈ A q and k = k(v) < ω such that

(2) (b β + q ω B) − g e v k a ∈ G q α .

Since (g v k ) k<ω is an (s, G α )-chain and b β + q ω B 6∈ G e q α by assumption, we have as n 6= 0 (in A q ) for each n < ω. Clearly we also have ν [g k v a] = ν [v k,s a].

Now, using Lemma 2.4, we find that ν [g v k a] is infinite. For all γ < α it

is certainly true that kv γ k ≤ kP α k = kvk and v 6= v γ . Therefore there is an

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infinite subset X of v such that X ⊆ [b β + q ω B] ⊆ [P e β ] by our Recognition Lemma. Since [P β ] is a subtree of T this implies v ⊆ [P β ]. Hence v is an element of Br(Im f α ) ∩ Br([P β ]). The Black Box tells us that this is only possible for β < α < β + κ

0

.

We have shown by now that for each v ∈ Br(Im f α ), there exist β(v) <

α, k(v) < ω, and a(v) ∈ A s

β(v)

such that

(3) β(v) < α < β(v) + κ

0

and (b β(v) + q ω B) − g e v k(v) a(v) ∈ G s α

β(v)

. Now let β 0 be the smallest ordinal satisfying β 0 < α < β 0

0

. This implies

β 0 ≤ β(v) < α < β 0 + κ

0

for all v ∈ Br(Im f α ).

Therefore |{β(v) | v ∈ Br(Im f α )}| < κ

0

= |Br(Im f α )|. Hence there are different branches v, u ∈ Br(Im f α ) with β(v) = β(u) = β. Subtracting the corresponding equations in (3) gives g k(v) v a(v)−g u k(u) a(u) ∈ G s α

β

. Arguing as before we show that an infinite subset of v is contained in ν [g k(u) u a(u)] ⊆ u, which contradicts the assumption that v, u are different branches.

Corollary 4.6. There are no useless ordinals. An ordinal α < λ is strong or weak according as (g 0 α + s ω α B)φ e α lies outside or in G s

α

.

P r o o f. Take g v k = v k,s

α

for each v ∈ Br(Im f α ) and apply Lemma 4.5.

After we have considered the R-module G from a more general point of view, we are now going to investigate special cases.

5. The cotorsion-free case. Considering the classical definition of a cotorsion-free module in the countable case (see e.g. [3], [4]) there seem to be different ways to generalize it to the uncountable case. In [8] an (ω-) cotorsion-free module is defined by having 0 as the only (ω-) complete sub- module where (ω-) completeness is an obvious replacement for completeness in the S-adic completion for countable S. Our notion of cotorsion-freeness is adapted to the modules under consideration.

Definition 5.1. An R-module M is defined to be cotorsion-free if it is S-torsion-free, S-reduced, and Hom(c R s , M s ) = 0 for each s ∈ S.

Note that it is easy to check that a module which is cotorsion-free in the above sense is also (ω-) cotorsion-free with respect to the definition given in [8] and both definitions coincide if S is countable.

The above version of cotorsion-freeness allows us to follow “locally” the arguments in [3], which are sketched below for the convenience of the reader.

Using the special form of G we are able to show that G is cotorsion-free if A is. We assume that A is cotorsion-free throughout this section.

Lemma 5.2. If A is cotorsion-free then G, constructed as in 3.3, is also

cotorsion-free.

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