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151 (1996)

Bing maps and finite-dimensional maps

by

Michael L e v i n (Haifa)

Abstract. Let X and Y be compacta and let f : X → Y be a k-dimensional map. In [5] Pasynkov stated that if Y is finite-dimensional then there exists a map g : X → I

k

such that dim(f × g) = 0. The problem that we deal with in this note is whether or not the restriction on the dimension of Y in the Pasynkov theorem can be omitted. This problem is still open.

Without assuming that Y is finite-dimensional Sternfeld [6] proved that there exists a map g : X → I

k

such that dim(f ×g) = 1. We improve this result of Sternfeld showing that there exists a map g : X → I

k+1

such that dim(f × g) = 0. The last result is generalized to maps f with weakly infinite-dimensional fibers.

Our proofs are based on so-called Bing maps. A compactum is said to be a Bing com- pactum if its compact connected subsets are all hereditarily indecomposable, and a map is said to be a Bing map if all its fibers are Bing compacta. Bing maps on finite-dimensional compacta were constructed by Brown [2]. We construct Bing maps for arbitrary compacta.

Namely, we prove that for a compactum X the set of all Bing maps from X to I is a dense G

δ

-subset of C(X, I).

1. Introduction. All spaces are assumed to be separable metrizable.

I = [0, 1]. By a map we mean a continuous function. In [5] Pasynkov stated:

Theorem 1.1. Let f : X → Y be a k-dimensional map of compacta.

Then there exists a map g : X → I k such that f × g : X → Y × I k is 0-dimensional.

This theorem is equivalent to

Theorem 1.2 (Toruńczyk [7]). Let f , X and Y be as in Theorem 1.1.

Then there exists a σ-compact subset A of X such that dim A ≤ k − 1 and dim f | X\A ≤ 0.

Now we will prove the equivalence of these theorems. Let f : X → Y be a map of compacta. The following statements are equivalent:

1991 Mathematics Subject Classification: 54F45, 54F15.

Key words and phrases: finite-dimensional maps, hereditarily indecomposable con- tinua.

[47]

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(i) There exists a σ-compact (k − 1)-dimensional subset A of X such that dim f | X\A ≤ 0;

(ii) For almost all maps g in C(X, I k ), dim(f × g) ≤ 0 (where almost all

= all but a set of first category);

(iii) There exists a map g : X → I k such that dim(f × g) ≤ 0.

Note that in (i)–(iii) we do not assume that Y is finite-dimensional.

(i)⇒(ii) (cf. [7]). Let A = S

A i , where the A i are compact and A i ⊂ A i+1 . By Hurewicz’s theorem [3] almost all maps in C(X, I k ) are k-to-1 on every A i . Let g be such a map. Since A i ⊂ A i+1 , g is also k-to-1 on A. Let y ∈ Y and a ∈ I k . Clearly (f × g) −1 (y, a) ⊂ (f −1 (y) \ A) ∪ g −1 (a) and as g −1 (a) is finite,

dim(f × g) −1 (y, a) = dim(f −1 (y) \ A) ≤ 0.

(ii)⇒(iii) is obvious and for a proof of (iii)⇒(i) see [6].

In this note we study the following problem which is still open.

Problem 1.3. Do Theorems 1.1 and 1.2 hold without the finite-dimen- sionality assumption on Y ?

Sternfeld [6] made a significant progress in solving Problem 1.3.

Theorem 1.4 ([6]). Let f : X → Y be a k-dimensional map of compacta.

Then for almost all maps g : X → I k , dim(f × g) ≤ 1.

Theorem 1.5 ([6]). Let f : X → Y be a k-dimensional map of compacta.

Then there exists a σ-compact (k − 1)-dimensional subset A of X such that dim f | X\A ≤ 1.

Note that from the proof of the implication (i)⇒(ii) it follows that The- orem 1.4 can be derived from Theorem 1.5.

The approach of [6] does not allow one to reduce the dimension of f to 0 in Theorems 1.4 and 1.5 by removing a σ-compact finite-dimensional subset A. This case is left open in [6]. In this note we prove:

Theorem 1.6. Let f : X → Y be a k-dimensional map of compacta.

Then there exists a map g : X → I k+1 such that dim(f × g) ≤ 0. Equiv- alently, there exists a σ-compact k-dimensional subset A of X such that dim f | X\A ≤ 0.

Theorem 1.7. Let f : X → Y be a weakly infinite-dimensional map of compacta. Then there exists a σ-compact weakly infinite-dimensional subset A of X such that f | X\A is 0-dimensional.

The last theorem generalizes the analogous result of [6]. There the di- mension of f | X\A is reduced to 1.

Our approach is based on some auxiliary maps which we will call Bing

maps. A compactum is said to be a Bing space if each of its subcontinua

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is hereditarily indecomposable. We will say that a map is a Bing map if its fibers are Bing spaces. Bing maps on finite-dimensional compacta were constructed by Brown [2]. We construct Bing maps on arbitrary compacta.

Namely, we prove:

Theorem 1.8. Let X be a compactum. Almost all maps in C(X, I) are Bing maps.

See [4] for another application of Bing maps.

In the next section we will also use:

Theorem 1.9 (Bing [1]). Any two disjoint closed subsets of a compactum can be separated by a Bing compactum.

Theorem 1.10 (Bing [1]). In an n-dimensional (strongly infinite-dimen- sional) Bing compactum X there exists a point x∈X such that every non- trivial continuum containing x is n-dimensional (strongly infinite-dimen- sional).

2. Proofs

P r o o f o f T h e o r e m 1.8. Let Q = {(x 1 , x 2 , . . .) : x i ∈ I} be the Hilbert cube and let

D = {(F 0 , F 1 , V 0 , V 1 ) : F i , V i ⊂ Q, F i are closed and disjoint, V i are disjoint neighborhoods of F i }.

Following [1] we say that A ⊂ Q is D-crooked for D = (F 0 , F 1 , V 0 , V 1 ) ∈ D if there is a neighborhood G of A in Q such that for every ψ : I → G with ψ(0) ∈ F 0 and ψ(1) ∈ F 1 there exist 0 < t 0 < t 1 < 1 such that ψ(t 0 ) ∈ V 1 and ψ(t 1 ) ∈ V 0 . Clearly

(i) if A is D-crooked then there exists a neighborhood A ⊂ G which is also D-crooked.

Actually, in [1] it is proved that:

(ii) a compactum A ⊂ Q is a Bing space if and only if A is D-crooked for every D ∈ D, and

(iii) there exists a sequence D 1 , D 2 , . . . ∈ D such that for every com- pactum A ⊂ Q, A is a Bing space if and only if A is D i -crooked for every D i . We say that a map g : X ⊂ Q → I is D-crooked if its fibers are D- crooked.

Let X ⊂ Q be compact and let D ∈ D.

(iv) The set of all D-crooked maps from X to I is open in C(X, I).

Let g : X → I be D-crooked. By (i) for every y ∈ I there is a neighbor-

hood U y such that g −1 (U y ) is also D-crooked. Let ε > 0 be so small that

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every subset of I of diameter ≤ ε is contained in some U y . One can show that every map ε-close to g is D-crooked and (iv) follows.

(v) The set of all D-crooked maps from X to I is dense in C(X, I).

Let g : X → I. We will approximate g by a D-crooked map. By an arbitrary small change of g we may avoid the ends of I and hence it may be assumed that g(X) does not contain 0 and 1.

Let ε > 0. Take y 1 = 0 < y 2 < . . . < y n = 1 such that y j+1 − y j < ε. Let δ > 0 be so small that y j + δ < y j+1 − δ for every j. By Theorem 1.9 take Bing compacta S j which separate between g −1 ([0, y j −δ]) and g −1 ([y j +δ, 1]), j = 2, . . . , n −1 (note that we regard the empty set as a Bing space). Modify g on every M j = g −1 ([y j − δ, y j + δ]), j = 2, . . . , n − 1, so that the image of M j is contained in [y j − δ, y j + δ] and the fibers of y j − δ, y j and y j + δ are g −1 (y j − δ), S j and g −1 (y j + δ) respectively.

So without loss of generality we may assume that A j = g −1 (y j ) are Bing spaces for all j = 1, . . . , n. Let A = S

A j . Then A is a Bing space. Let D = (F 0 , F 1 , V 0 , V 1 ). Take disjoint closed neighborhoods F i 0 of F i such that F i 0 ⊂ V i and define D 0 = (F 0 0 , F 1 0 , V 0 , V 1 ) and V i 0 = int F i 0 . By (ii), A is D 0 -crooked and by (i) we can take a D 0 -crooked neighborhood B of A in Q.

We claim that G = B ∪ V 0 0 ∪ V 1 0 is D-crooked. Let ψ : I → G satisfy ψ(0) ∈ F 0 and ψ(1) ∈ F 1 . Clearly there exist 0 ≤ b 0 < b 1 ≤ 1 such that ψ(b i ) ∈ ∂V i 0 ⊂ F i 0 and ψ([b 0 , b 1 ]) ⊂ B \(V 1 0 ∪V 2 0 ) ⊂ B. Since B is D 0 -crooked, there exist b 0 < t 0 < t 1 < b 1 such that ψ(t 0 ) ∈ V 1 and ψ(t 1 ) ∈ V 0 and therefore G is D-crooked.

Clearly T = X \ G is D-crooked and since T does not meet A, A ∪ T is also D-crooked. Set X j = g −1 ([y j , y j+1 ]) and T j = X j ∩ T . Then T j does not meet A j and A j+1 . So we can take maps g j 0 : X j → [y j , y j+1 ] such that g j 0 −1 (y j ) = A j ∪ T j and g 0 j −1 (y j+1 ) = A j+1 . Define g 0 : X → I by g 0 (x) = g 0 j (x) for x ∈ X j . Then g 0 is well-defined and ε-close to g. Every fiber of g 0 is contained in either A ∪ T or G. So g 0 is D-crooked and (v) follows.

To complete the proof of the theorem we apply the Baire theorem to (iii)–(v).

P r o o f o f T h e o r e m 1.6. By Theorem 1.8 take a Bing map ψ : X → I.

Define p = f × ψ and

D n = {D : D is a continuum contained in a fiber of p, diam D ≥ 1/n}.

Set B n = S

D∈D

n

D and B = S

B n . Then B n is compact. Since f is k- dimensional, dim D ≤ k for every D ∈ D n .

Let us show that dim ψ| B

n

≤ k. Indeed, for every a ∈ I, A = ψ −1 (a) is a Bing compactum. Clearly B n ∩ A = S

{D : D ∈ D n and D ⊂ A}. Hence

by Theorem 1.10, dim(B n ∩ A) ≤ k. So dim ψ| B

n

≤ k.

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By Theorem 1.2 and (ii) in the introduction, for every B n almost all maps ϕ in C(X, I k ) satisfy dim(ψ × ϕ)| B

n

= 0 and hence almost all maps ϕ satisfy dim(ψ × ϕ)| B = 0. Let ϕ be such a map. It is easy to see that for g = ψ × ϕ : X → I k+1 , f × g is 0-dimensional and we are done.

P r o o f o f T h e o r e m 1.7. We need the following

Lemma 2.1. Let f : X → Y be a perfect (= closed with compact fibers) map with dim Y = 0 and let T be the union of trivial components of X.

Then dim T = 0.

P r o o f. Let x ∈ T and let G be a neighborhood of x in X. Take disjoint open sets V 1 and V 2 such that x ∈ V 1 ⊂ G and f −1 (y) ⊂ V where y = f (x) and V = V 1 ∪ V 2 . Set U = Y \ f (X \ V ). Then V is open and y ∈ U . Let H be clopen in Y such that y ∈ H ⊂ U . Then V 0 = f −1 (H) is also clopen in X and V 0 ⊂ V . Thus V 0 = V 1 0 ∪ V 2 0 is a disjoint decomposition of V 0 with V i 0 = V 0 ∩ V i and therefore the V i 0 are clopen in X. Clearly x ∈ V 1 0 ⊂ G and we are done.

Returning to the proof of Theorem 1.7, let ψ, p and B n be as in the proof of Theorem 1.6. By the same reasoning we see that the B n are weakly infinite-dimensional. Clearly p is also weakly infinite-dimensional. By [6], Lemma 1, there exists a σ-compact zero-dimensional subset Z of Y × I such that for every y ∈ Y , U y = ({y} × I) \ Z is zero-dimensional. Define A 1 = p −1 (Z) and A 2 = S

n≥1 B n . Set A = A 1 ∪ A 2 and let us show that A is the desired set.

Obviously A is σ-compact and weakly infinite-dimensional. Let y ∈ Y . Define V y = p −1 (U y ) and let T y = the union of trivial components of V y . By Lemma 2.1, dim T y = 0. Clearly T y = V y \ A 2 . Also clearly

T y = V y \ A 2 = p −1 (U y ) \ A 2 = p −1 (({y} × I) \ Z) \ A 2

= (p −1 ({y} × I) \ p −1 (Z)) \ A 2 = (f −1 (y) \ A 1 ) \ A 2

= f −1 (y) \ (A 1 ∪ A 2 ) = f −1 (y) \ A.

So f −1 (y) \ A is zero-dimensional and we are done.

References

[1] R. H. B i n g, Higher dimensional hereditarily indecomposable continua, Trans. Amer.

Math. Soc. 71 (1951), 653–663.

[2] N. B r o w n, Continuous collections of higher dimensional indecomposable continua, Ph.D. thesis, University of Wisconsin, 1958.

[3] K. K u r a t o w s k i, Topology II , PWN, Warszawa, 1968.

[4] M. L e v i n and Y. S t e r n f e l d, Atomic maps and the Chogoshvili–Pontrjagin claim,

preprint.

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[5] B. A. P a s y n k o v, On dimension and geometry of mappings, Dokl. Akad. Nauk SSSR 221 (1975), 543–546 (in Russian).

[6] Y. S t e r n f e l d, On finite-dimensional maps and other maps with “small” fibers, Fund.

Math. 147 (1995), 127–133.

[7] H. T o r u ń c z y k, Finite to one restrictions of continuous functions, ibid. 75 (1985), 237–249.

Department of Mathematics Haifa University

Mount Carmel, Haifa 31905, Israel E-mail: levin@mathcs2.haifa.ac.il

Received 4 January 1996;

in revised form 19 May 1996

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