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Local Regularity of the Monge-Amp`ere Equation

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Local Regularity

of the Monge-Amp` ere Equation

Zbigniew Błocki

(Jagiellonian University, Kraków, Poland)

http://gamma.im.uj.edu.pl/eblocki

NORDAN 2010 oteborg, May 8, 2010

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We are interested in local regularity of (RMA) det(uxixj) = f > 0 (for convex solutions in domains in Rn) and (CMA) det(uziz¯j) = f > 0

(for continuous psh solutions in domains in Cn).

Remark. 1. In a way (RMA) is a special case of (CMA).

2. Makes no sense to allow f ≥ 0.

Natural question: f ∈ C ⇒ u ∈ C?

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Real Monge-Amp`ere Equation

Example (Pogorelov, 1971). u(x) = (x21+ 1)|x0|, β ≥ 0, where x0= (x2, . . . , xn). Then

det(uxixj) = c(1+x21)n−2(2β−1)−(2β+1)x21|x0|2(βn+1−n).

• u is convex near the origin iff β > 1/2

• det(uxixj) is smooth and > 0 iff β = 1 − 1/n.

Example only works for n ≥ 3!!!!

Theorem. n = 2, f ∈ C ⇒ u ∈ C Theorem (Aleksandrov, 1942).

n = 2, det(uxixj) ≥ c > 0 ⇒ u is strictly convex Theorem (Pogorelov, 1971).

Ω ⊂⊂ Rn, u = 0 on ∂Ω, f ∈ C(Ω) ⇒ u ∈ C(Ω)

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Coming back to Pogorelov’s example (n ≥ 3):

u = (x21+ 1)|x0|2(1−1/n), so that f = c(1 + x21)n−2. Then

u ∈ Wloc2,p ⇔ p < 1

2n(n − 1) and

u ∈ C1,α ⇔ α ≤ 1 − 2 n. Theorem (Urbas, 1988). If n ≥ 3 and

• either u ∈ Wloc2,p for some p > n(n − 1)/2

• or u ∈ C1,α for some α > 1 − 2/n then

f ∈ C ⇒ u ∈ C.

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Complex Monge-Amp`ere Equation Example. u(z) = (1 + |z1|2)|z0|2(1−1/n) is psh in Cn,

det(uziz¯j) = c(1 + |z1|2)n−2 In particular, u(z1, z2) = 2(1 + |z1|2)|z2| satisfies det(uziz¯j) = 1.

No two-dimensional phenomenon in the complex case!

u ∈ Wloc2,p ⇔ p < n(n − 1), u ∈ C1,α ⇔ α ≤ 1 − 2 n. Theorem (B.-S. Dinew). If u ∈ Wloc2,p for some

p > n(n − 1) then

f ∈ C ⇒ u ∈ C.

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More precisely we have

Theorem. Assume Ω ⊂ Cn, n ≥ 2,

u ∈ P SH ∩ W2,p(Ω) for some p > n(n − 1) solves det(uziz¯j) = f > 0,

where f ∈ C1,1(Ω).

Then ∆u ∈ Lloc(Ω) and for Ω0 ⊂⊂ Ω sup

0

∆u ≤ C,

where C depends only on n, p, ||f ||C1,1(Ω), inff ,

||∆u||Lp(Ω) and dist(Ω0, ∂Ω).

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Sketch of proof. Assume u ∈ C4. Then uj(∆u)j ≥ ∆(log f ) ≥ −C1. Set w := (1 − |z|2)α(∆u)β, α, β ≥ 2. After some computations we will get

ujwj ≥ −C2(∆u)α−1− C3w1−2/β(∆u)2α/βX

i,j

|uj|.

Fix 1 < q < p/(n(n − 1)). Since ||∆u||p is under control, it follows that ||uj||p and ||uj||p/(n−1) are as well. Set

α = 1 + p

qn, β = 2 1 + qn p .

Then

||(ujwj)||qn ≤ C4(1 + (sup

B

w)1−2/β), where f:= − min(f, 0).

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Solve det(vj) = ((ujwj))n, v = 0 on ∂B. Then sup

B

w ≤ C5sup

B

(−v)

≤ C6|| det(vj)||1/nq

= C6||(ujwj)||qn

≤ C7(1 + (sup

B

w)1−2/β) by Kołodziej’s estimate. Therefore

w = (1 − |z|2)α(∆u)β ≤ C8.

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For u which is just in W2,p we consider T = Tεu = n + 1

ε2 (uε− u), where

uε(z) = 1 λ(B(z, ε))

Z

B(z,ε)

u dλ.

Then Tεu → ∆u weakly. One can show that ujTj ≥ nf−1/nTε(f1/n) ≥ −C9

and now we can work as before with T instead of ∆u.

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Theorem (S. Dinew-X. Zhang-X.W. Zhang). 0 < α < 1.

For u ∈ C1,1 we have

f ∈ Cα ⇒ u ∈ C2,α.

It would useful to weaken the assumption to ∆u ∈ Lloc. For this the following version of Bedford-Taylor’s interior regularity would be sufficient:

Assume v is psh and has bounded Laplacian near ¯B. Let u be the psh solution of det(uj) = 1, u = v on ∂B.

Then ∆u ∈ Lloc(B).

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