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On Sidon sequences of even orders

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LXIV.4 (1993)

On Sidon sequences of even orders

by

Sheng Chen (San Marcos, TX)

Let h ≥ 2 be an integer. A set A of positive integers is called a B h - sequence if all sums a 1 + . . . + a h , where a i ∈ A (i = 1, . . . , h), are distinct up to rearrangements of the summands. A B h -sequence is also called a Sidon sequence of order h [7]. Sidon was led to consider such sequences in connection with the theory of Fourier series. In [7] he raised the question of how many terms not exceeding n a B h -sequence may have. Some earlier important results on B h -sequences may be found in [2, Ch. 2].

Let A be a B h -sequence. Denote by A(n) the cardinality of A ∩ [0, n].

For any positive integer r, denote by rA the set of integers P r

i=1 a i where a i ∈ A (i = 1, . . . , r). It follows from the definition of B h -sequences that

hn ≥ (hA)(hn) ≥ A(n) h

 , which implies

A(n) = O( √ h n) .

Erd˝ os [2, 8] and Kr¨ uckeberg [5] showed that there exists a B 2 -sequence A such that

lim sup

n→∞

A(n) √ n ≥ 1

√ 2 .

On the other hand, Erd˝ os [2] also proved that, for any B 2 -sequence A, lim inf

n→∞ A(n)

r log n n < ∞ .

Nash extended the result to B 4 -sequences. He showed [6] that, for any B 4 -sequence A,

lim inf

n→∞ A(n) 4 r log n

n < ∞ .

1991 Mathematics Subject Classification: Primary 11B83; Secondary 11B50, 05B10.

Key words and phrases: additive number theory, difference sets, B h -sequence, Sidon

sequences.

(2)

A natural conjecture [4] is as follows.

Conjecture. If A is a B h -sequence, then lim inf

n→∞ A(n) h r log n

n < ∞ .

For h odd, no results of this kind have been proved as far as the author knows.

For h even (h = 2k > 4), Jia [4] showed that, if A(n 2 ) ≤ A(n) 2 , then lim inf

n→∞ A(n) 2k r log n

n < ∞ .

As mentioned in [4], the condition A(n 2 ) ≤ A(n) 2 does not hold for all B 2k -sequences.

The author [1] proved that a weaker result of a similar nature does hold, namely

lim inf

n→∞

A(n)

2k √ n

4k−4 p

log n < ∞ , which has been improved by Helm [3] to

lim inf

n→∞

A(n)

2k √ n

3k−1 p

log n < ∞ .

In this paper, we give an affirmative partial answer to the Conjecture.

Theorem. For any B 2k -sequence A, lim inf

n→∞ A(n) 2k r log n

n < ∞ .

Corollary. Let A = {a 1 < a 2 < . . . < a n < . . .} be an infinite B 2k -sequence. Then

lim sup

n→∞

a n

n 2k log n > 0 . First some notations and lemmas.

Let A be a B 2k -sequence and r be a positive integer, 1 ≤ r ≤ 2k. For any x = x 1 + . . . + x r where x s ∈ A (s = 1, . . . , r), denote by x the set {x 1 , . . . , x r } (counting the multiplicities of the appearance of x i ’s) and

r ∗ A = {x = x 1 + . . . + x r : x s ∈ A, x s 6= x t , 1 ≤ s, t ≤ r} . Note that, since A is a B 2k -sequence, x = y ∈ rA if and only if x = y.

Let A be a B 2k -sequence. Let n be a large integer fixed hereafter and

u = bn 1/(2k) c. For any sequence B, denote by B i (n), or simply B i , the set

B ∩ ((i − 1)kn, ikn], i = 1, 2, . . .

(3)

Set D = A ∩ (0, ukn], C = k ∗ D, c i = |C i |, and τ (n) = min

n≤m≤un

A(m)

2k √ m . Lemma 1.

τ (n) 2k n log n = O

 X u

i=1

c 2 i

 . P r o o f. Note that

 u X

i=1

c i

√ i

 2

 u X

i=1

1 i

  X u

i=1

c 2 i 

≤ 2 log u

u

X

i=1

c 2 i . On the other hand, for any positive integer i (1 ≤ i ≤ u),

C(ikn) ≥ A(in) k



≥ cA(in) k ,

where c > 0 is an absolute constant depending only on k, and A(in) k =  A(in)

2k √ in

 k √

in ≥ τ (n) k √ in . Hence,

u

X

i=1

c i

√ i =

u

X

i=1

 1

i − 1

√ i + 1

 i

X

j=1

c j + 1

√ u + 1

u

X

j=1

c j

≥ 1 8

u

X

i=1

1

i 3/2 C(ikn) ≥ c 8

u

X

i=1

A(in) k i 3/2

≥ c

8 τ (n) k √ n

u

X

i=1

1

i ≥ cτ (n) k

n log u . So,

τ (n) 2k n log u ≤ O  X u

i=1

c 2 i  . As u = bn 1/(2k) c, Lemma 1 follows.

Lemma 2.

u

X

i=1

c 2 i = O(n) .

P r o o f. Set W = {(x, y) ∈ (k ∗ A) × (k ∗ A) : x ∩ y = ∅}. Define

a map f : W → (−∞, ∞) by (x, y) 7→ x − y. If f (x 0 , y 0 ) = f (x, y), i.e.,

x 0 − y 0 = x − y, then x 0 + y = x + y 0 . As A is a B 2k -sequence, x 0 ∪ y = x ∪ y 0 .

Since x ∩ y = x 0 ∩ y 0 = ∅, we have x = x 0 and y = y 0 . Thus f is one-to-one.

(4)

For any integer r, 1 ≤ r ≤ k, let

V (r, D) = {(x, y) ∈ (r ∗ D) × (r ∗ D) : −kn < x − y < kn} . Then

(1)

u

X

i=1

c 2 i ≤ |V (k, D)| . Write V (k, D) = S k

j=0 V j (k, D) (disjoint union) where

V j (k, D) = { (x, y) ∈ V (k, D) : |x ∩ y| = j}, 0 ≤ j ≤ k . Then

(2) |V (k, D)| =

k

X

j=0

|V j (k, D)| .

For any B 2k -sequence B and any integers j, r (0 ≤ j, r ≤ k), let W (r, D, j, B) be the set of 4-tuples (x, b, b, y) such that

(a) x, y ∈ r ∗ D with −kn < x − y < kn, (b) b ∈ j ∗ B, and

(c) b ∩ x = b ∩ y = x ∩ y = ∅.

If j = 0, we simply write W (r, D) instead.

Note that |V j (k, D)| = O(|W (k − j, D, j, D)|). Combining this with (1) and (2), we have

(3)

u

X

i=1

c 2 i = O  X k

j=0

|W (k − j, D, j, D)|  . Hence it suffices to show that, for all j (0 ≤ j ≤ k),

|W (k − j, D, j, D)| = O(n) .

C a s e j = 0. Then W (k, D, 0, D) = W (k, D) ⊆ W and f (W (k, D)) ⊆ (−kn, kn). Hence,

(4) |W (k, D, 0, D)| ≤ 2kn .

C a s e j = k. Then V (0, D, k, D) = {(b, b) : b ∈ k ∗ D}. Hence, (5) |W (0, D, k, D)| = |k ∗ D| ≤ |D| k = A(ukn) k = O(( 2k

ukn) k ) = O(n) . C a s e 1 ≤ j ≤ k − 1. Let I = {i : 1 ≤ i ≤ u and |D i | ≥ 2k}. Set B = S

i∈I D i , and B 0 = D \ B. We divide our proof into two subcases.

S u b c a s e I: |B| ≤ |B 0 |. Note B 0 = P

1≤i≤u;i6∈I D i . So |B 0 | ≤ u(2k −1).

Hence,

|D| = |B 0 | + |B| ≤ 2|B 0 | ≤ 4ku .

(5)

Therefore,

(6) |W (k − j, D, j, D)| ≤ |(2k − j) ∗ D| ≤ |D| 2k−j ≤ (4ku) 2k−j = O(n) . S u b c a s e II: |B 0 | ≤ |B|. Note B is also an B 2k -sequence. We claim (7) |W (k − j, D, j, B)| = O(n) .

To show (7), define a map v : W (k − j, D, j, B) → W as follows. Let (x, b, b, y) ∈ W (k − j, D, j, B). As b ∈ j ∗ B, b = P j

s=1 b s where b s ∈ D i

s

and i s ∈ I (s = 1, . . . j). Since |D i

s

| ≥ 2k, we can choose b 0 s ∈ D i

s

(s = 1, . . . , j) so that

(i) all b 0 s ’s are distinct and (ii) b 0 s 6∈ x ∪ y ∪ b, s = 1, . . . , j.

Let b 0 = P j

s=1 b 0 s . Then (x, b, b 0 , y) ∈ W . Define v : W (k − j, D, j, D) → W by (x, b, b, y) 7→ (x, b, b 0 , y). Clearly, v is well defined and one-to-one.

Furthermore, by the choice of b 0 s , −kn ≤ b s − b 0 s ≤ kn for all 1 ≤ s ≤ j. So,

−jkn ≤ b − b 0 ≤ jkn. Hence,

−(j + 1)kn < (x + b) − (b 0 + y) < jkn + kn . Thus,

|W (k − j, D, j, B)| = |f (v(W (k − j, D, j, B)))| ≤ 2(j + 1)kn ≤ 2k 2 n , which is (7).

Note

W (k − j,D, j, D) (8)

= [

(x,y)∈W (k−j,D)

{(x, b, b, y) : b ∈ j ∗ D, b ∩ (x ∪ y) = ∅}

= [

(x,y)∈W (k−j,D)

{(x, b, b, y) : b ∈ j ∗ (D \ (x ∪ y))} , and similarly,

(9) W (k − j, D, j, B) = [

(x,y)∈W (k−j,D)

{(x, b, b, y) : b ∈ j ∗ (B \ (x ∪ y))} . On the other hand, for any z = (x, y) ∈ W (k − j, D), it follows from the assumption that |B 0 | ≤ |B|, and

|D \ z| = |(B \ z)| + |B 0 \ z| ≤ 2|B \ z| + |z| ≤ 2|B \ z| + 2k . Therefore,

(10) |j ∗ (D \ z)| = |D \ z|

j



≤ 2|B \ z| + 2k j



≤ c(|j ∗ (B \ z)| + 1) ,

where c is an absolute constant depending only on j, hence only on k.

(6)

Combining (7)–(10), we have

|W (k − j, D, j, D)| = X

z∈W (k−j,D)

|j ∗ (D \ z)|

(11)

≤ X

z∈W (k−j,D)

c(|j ∗ (B \ z)| + 1)

≤ c  X

z∈W (k−j,D)

|j ∗ (B \ z)| + X

z∈W (k−j,D)

1 

= c(|W (k − j, D, j, B)| + |W (k − j, D)|) = O(n) . Now Lemma 2 follows from (3)–(5) and (11).

P r o o f o f t h e T h e o r e m. It follows from Lemmas 1 and 2 that τ (n) 2k log n = O(1). Hence,

lim inf

n→∞ A(n) 2k r log n

n = lim inf

n→∞ inf

n≤m≤un



A(m) 2k r log m

m



≤ lim inf

n→∞ inf

n≤m≤un

 A(m)

2k √ m

2k p

log(un)



≤ 2 lim inf

n→∞ τ (n) 2k p

log n < ∞ .

Acknowledgments. The author would like to thank Weizhen Gu for a helpful discussion.

References [1] S. C h e n, A note on B 2k -sequences, preprint.

[2] H. H a l b e r s t a m and K. F. R o t h, Sequences, Springer, New York 1983.

[3] M. H e l m, A remark on B 2k -sequences, preprint.

[4] X.-D. J i a, On B 2k -sequences, J. Number Theory, to appear.

[5] F. K r ¨ u c k e b e r g, B 2 -Folgen und verwandte Zahlenfolgen, J. Reine Angew. Math.

206 (1961), 53–60.

[6] J. C. M. N a s h, On B 4 -sequences, Canad. Math. Bull. 32 (1989), 446–449.

[7] S. S i d o n, Ein Satz ¨ uber trigonometrische Polynome und seine Anwendungen in der Theorie der Fourier-Reihen, Math. Ann. 106 (1932), 536–539.

[8] A. S t ¨ o h r, Gel¨ oste und ungel¨ oste Fragen ¨ uber Basen der nat¨ urlichen Zahlenreihe. II , J. Reine Angew. Math. 194 (1955), 111–140.

DEPARTMENT OF MATHEMATICS SOUTHWEST TEXAS STATE UNIVERSITY SAN MARCOS, TEXAS 78666

U.S.A.

E-mail: SC03@SWTEXAS.BITNET

Received on 16.11.1992 (2332)

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