C O L L O Q U I U M M A T H E M A T I C U M
VOL. 79 1999 NO. 1
CHARGE TRANSFER SCATTERING IN A CONSTANT ELECTRIC FIELD
BY
LECH Z I E L I ´ N S K I (PARIS)
We prove the asymptotic completeness of the quantum scattering for a Stark Hamiltonian with a time dependent interaction potential, created by N classical particles moving in a constant electric field.
1. Introduction. We consider a model describing the quantum dy- namics of a light particle (such as an electron) in collisions with some heavy particles (such as some ions) obeying the laws of classical dynamics. Thus only the light particle is considered a quantum particle, while the heavy par- ticles follow some classical trajectories R ∋ t 7→ χ k (t) ∈ R d . If V k denotes the quantum interaction potential between the quantum particle and the kth classical particle, the total quantum time-dependent interaction V (t) is the operator of multiplication by
(1.1) V (t, x) = X
1≤k≤N
V k (x − χ k (t)),
and the total time-dependent Hamiltonian H(t) is a self-adjoint operator in L 2 (R d ),
(1.2) H(t) = H 0 + V (t, x),
where H 0 denotes the free motion Hamiltonian. The subject of scattering theory is to describe the large time behaviour of the evolution propagator {U (t, t 0 )} t≥t 0 of H(t), that is, the family of unitary operators in L 2 (R d ) satisfying
(1.3) i d
dt U (t, t 0 )ϕ = H(t)U (t, t 0 )ϕ, U (t 0 , t 0 )ϕ = ϕ, for ϕ from the domain of H 0 .
The first papers describing such a model considered the case of linear classical trajectories and H 0 the Laplace operator [10, 25, 26]. The papers
1991 Mathematics Subject Classification: 81U10, 47A40, 47N50.
[37]
[7, 29] deal with classical trajectories which are only asymptotically lin- ear and the papers [30, 31, 32] deal with the dispersive case when H 0 is a more general elliptic operator. We note that all these papers consider the hypothesis that different classical trajectories have different asymp- totic velocities lim t→∞ χ ′ k (t), which implies the separation of trajectories:
|χ k (t) − χ k ′ (t)| ≥ ct with c > 0 if k 6= k ′ .
The aim of this paper is to consider the situation arising in the presence of a constant electric field E ∈ R d \ {0}, when the free motion Hamiltonian for a particle of mass m > 0 and charge q 6= 0 has the form
h 0 (x, p) = p 2
2m − qE · x
and the Hamilton equations ˙p(t) = qE, ˙x(t) = p(t)/m have the solutions of the form
p(t) = qEt + mυ, x(t) = qE
2m t 2 + υt + ω,
where υ = p(0)/m ∈ R d and ω = x(0) ∈ R d . Thus the above solutions of the Hamilton equations describe the motion that is free in the directions orthogonal to the constant field E and uniformly accelerated in the direction parallel to E.
We shall consider only the simplest situation when different classical trajectories have different asymptotic accelerations lim t→∞ χ ′′ k (t). More pre- cisely we begin by assuming the following separation condition: there exist constants T 0 , c > 0, such that for t ≥ T 0 ,
(1.4) |χ k (t) − χ k ′ (t)| ≥ ct 2 if 1 ≤ k < k ′ ≤ N.
Let m k , q k be the mass and the charge of the kth classical particle and assume that χ(t) = (χ 1 (t), . . . , χ N (t)) is a solution of the Newton equations (1.5) m k χ ′′ k (t) = q k E − X
k ′ ∈{1,...,N }\{k}
∇V k,k ′ (χ k (t) − χ k ′ (t)),
where the classical interaction potentials V k,k ′ satisfy the decay condition (1.6) |∇V k,k ′ (x)| ≤ C 0 |x| −1−µ 0 for |x| ≥ C 0
with C 0 , µ 0 > 0.
It is clear that (1.4)–(1.6) imply
(1.7) χ ′′ k (t) = z k + O(t −2(1+µ 0 ) ) with z k = q k
m k
E
as t → ∞, i.e. z k = (q k /m k )E = lim t→∞ χ ′′ k (t) is the asymptotic acceleration of the trajectory χ k . Since (1.7) means that dt d (χ ′ k (t) − z k t) = O(t −2−2µ 0 ), the limit
υ k = lim
t→∞ (χ ′ k (t) − z k t)
exists and introducing e χ k by the relation
(1.8) χ k (t) = 1 2 z k t 2 + υ k t + e χ k (t), we have
(1.9) χ e ′′ k (t) = O(t −2−2µ 0 ), χ e ′ k (t) = O(t −1−2µ 0 ) as t → ∞.
The Hamiltonian of the free motion for a quantum particle of mass m 0 >
0 and charge q 0 6= 0 has the form
(1.10) H 0 = p 2
2m 0
− q 0 E · x, where p = (p 1 , . . . , p d ) = (−i∂ x 1 , . . . , −i∂ x d ).
For quantum interactions V k we assume that for some constants C, b C, ε 0
> 0,
V k (x)(1 + p 2 ) −1+ε 0 is a compact operator in L 2 (R d ), (1.11a)
|∂ x α V k (x)| ≤ C for |x · E| ≥ b C and |α| ≤ 2, (1.11b)
and V k = V k l + V k s with real valued functions V k l , V k s , such that for some µ > 0 we have
|∂ x α V k l (x)| ≤ C(1 + |x|) −µ−|α| for x ∈ R d and |α| ≤ 1, (1.11c)
|∂ x α V k s (x)| ≤ C(1 + |x|) −µ+(|α|−1)/2 for |x · E| ≥ b C (1.11d)
and |α| ≤ 1.
Theorem 1. Let U (t, t 0 ) be defined by (1.3) with H(t) given by (1.1), (1.2), (1.10). For k = 0, 1, . . . , N , let z k = q k E/m k be such that z k 6= z k ′ if 0 ≤ k < k ′ ≤ N . Assume that the trajectories χ k (t) have the form (1.8) with e
χ k (t) satisfying (1.9) for some µ 0 > 0. If V k = V k l + V k s satisfy (1.11a–d) for some µ > 0, ε 0 > 0, then the limit
(1.12)
Ω(t 0 )ψ = lim
t→∞ U (t, t 0 ) ∗ e −itH 0 −iS(t) ψ with S(t) =
t
\
1
dτ X
1≤k≤N
V k l 1 2 z 0 τ 2 − χ k (τ ) ,
exists in the norm of L 2 (R d ) for every ψ ∈ L 2 (R d ). Moreover , the asymp- totic completeness holds, i.e. the wave operator Ω(t 0 ) defined by (1.12) is unitary.
We recall the result of I. M. Sigal [20] (cf. also [3, 4, 5]) which guarantees the absence of eigenvalues for 2-body Stark Hamiltonians H k = H 0 + V k (x).
This allows us to neglect bound states and the asymptotic completeness
formulated in Theorem 1 implies that for every ϕ ∈ L 2 (R d ) there exists ψ ∈
L 2 (R d ) such that ϕ = Ω(t 0 )ψ. Thus U (t, t 0 )ϕ−e −itH 0 −iS(t) ψ → 0 as t → ∞,
which means that the asymptotic behaviour of U (t, t 0 )ϕ is asymptotically the same as for the free evolution (modulo a phase factor e −iS(t) ).
We note that the approach used in the proof below comes from recent developments of scattering theory of N -body systems ([6, 8, 21]). We also mention the references [9, 12, 15–17, 19, 23, 24, 27, 28, 33] concerning Stark scattering in the 2-body case and [1, 2, 13, 14, 18, 22] in the N -body case.
In Section 2 we begin by describing in Lemma 2.1 asymptotic concentra- tion of the free evolution trajectories e −itH 0 ϕ on classical Stark trajectories.
Then it is easy to prove the existence of the wave operator Ω(t 0 ) given by (1.12). Clearly Ω(t 0 ) is an isometric injection and in order to prove the asymptotic completeness it suffices to prove the existence of the limit (1.12 ′ ) Ω(t 0 ) ∗ ϕ = lim
t→∞ e itH 0 +iS(t) U (t, t 0 )ϕ
for every ϕ ∈ L 2 (R d ). Indeed, if Ω(t 0 ) ∗ given by (1.12 ′ ) exists, then applying the chain rule we get Ω(t 0 )Ω(t 0 ) ∗ ϕ = ϕ, that is, Ω(t 0 ) is surjective and hence unitary.
To begin the proof of the existence of (1.12 ′ ) we assume for simplicity V k s = 0 and introduce the auxiliary observable η t . This observable is used in Proposition 3.2 to introduce an energy cut-off, similarly to the “boosted Hamiltonian” of Graf [7]. However, instead of Enss approach used in Graf [7], our next step is based on the existence of the wave operators Ω k (t) of Proposition 3.7 (similar to the Deift–Simon operators of the N -body theory developed in Graf [8]). Then Proposition 3.7 allows us to localize and “distinguish” interactions of different classical charges, reducing the problem to the 2-body problem when the number of classical charges is N = 1.
The situation N = 1 is studied in Section 4 using the ideas of the Mourre estimate. More precisely, knowing that z 0 ·p is the conjugate operator for H 0
(i.e. we have the positive commutator [iH 0 , z 0 · p] = z 0 2 I), we find the propa- gation estimate of Proposition 4.3 using a suitable cut-off g 1 (z 0 ·p/t) instead of z 0 · p. Finally, in Section 5 we sketch the idea allowing one to modify the observable η t in order to recover all the previous results in the case of inter- action potentials with singularities, V k s 6= 0.
2. Preliminary estimates. For U ⊂ R d , C 0 ∞ (U ) is the set of smooth
functions with compact support in U . We write a t = O(f (t)) if there is a
constant C > 0 such that ka t k ≤ Cf (t), where k · k is the norm of L 2 (R d )
or the norm of bounded operators B(L 2 (R d )). The analogous notation will
be used when a t = (a 1 t , . . . , a d t ) assuming ka t k = (ka 1 t k 2 + . . . + ka d t k 2 ) 1/2 .
Moreover, a t = b t +O(f (t)) means a t −b t = O(f (t)). For Z ⊂ R, 1 Z denotes
the characteristic function of Z on R.
Assume that V 0 is a real function satisfying
(2.1) |∂ t n ∂ x α V 0 (t, x)| ≤ Ct −2µ−2|α|−n for |α| + n ≤ 1, and denote by U 0 (t, t 0 ) the evolution propagator of the Hamiltonian (2.2) H 0 (t) = H 0 + V 0 (t, x),
where H 0 is given by (1.10). By rescaling we may assume further on that m 0 = 1.
Let y t = (y 1 t , . . . , y t d ), w t = (w 1 t , . . . , w d t ) be systems of d commuting self-adjoint operators,
(2.3) y t = 2x
t 2 − z 0 , w t = p t − z 0 .
Lemma 2.1. Let U 0 (t, t 0 ), y t , w t be as above and ϕ ∈ C 0 ∞ (R d ). Then (2.4) w t U 0 (t, t 0 )ϕ = O(t −1 ), y t U 0 (t, t 0 )ϕ = O(t −1 )
and for every κ > 0 and j = 1, . . . , d one has 1 [κ;∞[ (|y j t |)U 0 (t, t 0 )ϕ = O(t −1 ).
P r o o f. Define U 0 (t, t 0 ) = U t 0 , f (t) = U t 0∗ pU t 0 ϕ and g(t) = U t 0∗ xU t 0 ϕ.
Then
f ′ (t) = U t 0∗ [iH 0 (t), p]U t 0 ϕ = z 0 ϕ + O(t −2(1+µ) ), g ′ (t) = U t 0∗ [iH 0 (t), x]U t 0 ϕ = f (t)
= f (t 0 ) +
t
\
t 0
f ′ (τ ) dτ = tz 0 ϕ + O(1), hence w t U t 0 ϕ = t −1 U t 0 (f (t) − z 0 tϕ) = O(t −1 ). Moreover,
g(t) = g(t 0 ) +
t
\
t 0
g ′ (τ ) dτ = 1 2 z 0 t 2 ϕ + O(t), and x− 1 2 z 0 t 2
U t 0 ϕ = U t 0 g(t)− 1 2 z 0 t 2 ϕ
= O(t) implies the second estimate (2.4). Finally, using κ 2 1 [κ;∞[ (|λ|) ≤ λ 2 and the second estimate (2.4) we obtain
(κ 2 1 [κ;∞[ (|y j t |)U t 0 ϕ, U t 0 ϕ) ≤ ((y t j ) 2 U t 0 ϕ, U t 0 ϕ) = ky t j U t 0 ϕk 2 = O(t −2 ).
Note that (1.9) implies the existence of
(2.5) lim
t→∞ χ e k (t) = ω k with χ e k (t) = ω k + O(t −2µ 0 ), hence
(2.5 ′ ) χ ′ k (t) = z k t + υ k + O(t −1−2µ 0 ), χ k (t) = 1 2 z k t 2 + υ k t + O(1).
By rotation of the coordinate system we may assume further on that E =
(E 1 , 0, . . . , 0) with E 1 ∈ R \ {0}, hence z k = (z 1 k , 0, . . . , 0) with z k 1 =
E 1 q k /m k . Further, we set
(2.6) τ = 16 1 min{|z k 1 − z k 1 ′ | : 0 ≤ k < k ′ ≤ N }.
Fix J 0 ∈ C 0 ∞ (] − 4τ ; 4τ [) such that 0 ≤ J 0 ≤ 1, J 0 = 1 on [−2τ ; 2τ ], define J 0 = 1 − J 0 and let
V 0k (t, x) = J 0 (4x 1 /t 2 − 2z 1 k )V k l (x − χ k (t)) (2.7)
= J 0 (2y 1 t − 2e z k )V k l (x − χ k (t)) where we have set e z k = z 1 k − z 0 1 . Then we have
Proposition 2.2. Let V 0 = P
1≤k≤N V 0k , where V 0k is given by (2.7).
Then (2.1) holds and for every ϕ ∈ L 2 (R d ) the following limits exist:
(2.8)
Ω(t e 0 ) ∗ ϕ = lim
t→∞ e itH 0 +iS(t) U 0 (t, t 0 )ϕ, Ω(t e 0 )ϕ = lim
t→∞ U 0 (t, t 0 ) ∗ e −itH 0 −iS(t) ϕ.
P r o o f. Since χ k (t) = 1 2 z k t 2 + O(t) there is T 0 such that for t ≥ T 0 we have
J 0 (4x 1 /t 2 − 2z k 1 ) 6= 0 ⇒ |4x 1 /t 2 − 2z 1 k | ≥ 2τ
⇒ |x − χ k (t)| ≥
x 1 − 1 2 z k 1 t 2
− 1 2 z k t 2 − χ k (t)
≥ 1 2 τ t 2 − C ′ t ≥ 1 4 τ t 2 and applying (1.11) we find
(2.9) |x − χ k (t)| ≥ 1 4 τ t 2 ⇒ |(∂ α V k l )(x − χ k (t))| ≤ Ct −2(µ+|α|) if |α| ≤ 1.
We conclude that V 0 satisfies (2.1) noting that
∂
∂x 1
(J 0 (4x 1 /t 2 − 2z k 1 )) = O(t −2 ), ∂
∂t (J 0 (4x 1 /t 2 − 2z k 1 )) = O(t −1 ).
Since C 0 ∞ (R d ) is dense in L 2 (R d ), to obtain the existence of e Ω(t 0 ) ∗ ϕ it suffices to consider ϕ ∈ C 0 ∞ (R d ) and to check that
(2.10) d
dt (e itH 0 +iS(t) U 0 (t, t 0 )ϕ)
= e itH 0 +iS(t) i(S ′ (t) − V 0 (t, x))U 0 (t, t 0 )ϕ = O(t −1−2µ ).
However, for 1 ≤ k ≤ N we have |z k 1 − z 0 1 | ≥ 16τ , hence J 0 (2z 0 1 − 2z 1 k ) = 1 and
(2.11) V 0 t, 1 2 z 0 t 2
= X
1≤k≤N
J 0 (2z 0 1 − 2z k 1 )V k l 1 2 z 0 t 2 − χ k (t)
= S ′ (t).
Thus we may write
V 0 (t, x) − S ′ (t) = V 0 (t, x) − V 0 t, 1 2 z 0 t 2
= γ t · x − 1 2 z 0 t 2
= 1 2 γ t · t 2 y t
with
γ t =
1
\
0
dθ ∇ x V 0 t, (1 − θ)x + 1 2 θz 0 t 2 and (2.1) implies t 2 γ t = O(t −2µ ). Therefore
k(S ′ (t) − V 0 (t, x))U 0 (t, t 0 )ϕk = 1 2 t 2 γ t · y t U 0 (t, t 0 )ϕ (2.12)
≤ Ct −2µ ky t U 0 (t, t 0 )ϕk
and by (2.4) the right hand side of (2.12) is O(t −1−2µ ), i.e. (2.10) follows.
We may use V 0 (t, x) = 0 in Lemma 2.1, hence it is clear that e −itH 0 satisfies the same estimates as U 0 (t, t 0 ), and we obtain the existence of the second limit (2.8) as above with e −itH 0 and U 0 (t, t 0 ) interchanged.
Proof of the existence of Ω(t 0 ). Using the chain rule and the existence of (2.8), we note that it suffices to prove the existence of lim t→∞ U (t, t 0 ) ∗
× U 0 (t, t 0 )ϕ, where as before we may assume ϕ ∈ C 0 ∞ (R d ). Let J ∈ C 0 ∞ (R d ) be such that J(x) = 1 for |x| ≤ τ , J(x) = 0 for |x| ≥ 2τ , 0 ≤ J ≤ 1. Then Lemma 2.1 implies
k(1 − J)(y t )U 0 (t, t 0 )ϕk ≤ k1 [τ ;∞[ (|y t |)U 0 (t, t 0 )ϕk = O(t −1 ), i.e.
t→∞ lim U (t, t 0 ) ∗ J(y t )U 0 (t, t 0 )ϕ = lim
t→∞ U (t, t 0 ) ∗ U 0 (t, t 0 )ϕ and it suffices to show that
(2.13) d
dt (U (t, t 0 ) ∗ J(y t )U 0 (t, t 0 )ϕ)
= U (t, t 0 ) ∗ (D H 0 J(y t ) + iJ(y t )(V (t, x) − V 0 (t, x)))U 0 (t, t 0 )ϕ
= O(t −1−2µ ) + O(t −2 ),
where D a t b t = [ia t , b t ] + dt d b t denotes the Heisenberg derivative.
However, a simple calculation gives
(2.14) D H
0 J(y t ) = 2 t
X
1≤j≤d
∂ j J(y t )(w j t − y t j ) + O(t −3 ) and using (2.4) we obtain (D H 0 J(y t ))U 0 (t, t 0 )ϕ = O(t −2 ).
Next for 1 ≤ k ≤ N we have J 0 (2y 1 t − 2e z k ) 6= 0 ⇒ |y t 1 − e z k | < 2τ
⇒ |y t 1 | ≥ |e z k | − 2τ = |z k 1 − z 0 1 | − 2τ ≥ 14τ ⇒ J(y t ) = 0, hence J(y t )J 0 (2y t 1 − 2e z k ) = J(y t ) and
J(y t )(V − V 0 )(t, x) = X
1≤k≤N
J(y t )J 0 (2y t 1 − 2e z k )V k s (x − χ k (t)).
If T 0 is as at the beginning of the proof of Proposition 2.2, then for t ≥ T 0
we have
J 0 (2y t 1 − 2e z k ) 6= 0 ⇒ |x − χ k (t)| ≥ 1 4 τ t 2 ⇒ |V k s (x − χ k (t))| ≤ Ct −1−2µ . Until the end of Section 4 we assume that V k s = 0, that is, V k = V k l . We now introduce
η 0 t = 1 2
p 1 t − 2x 1
t 2
2
+ 1 4
2x 1 t 2 − z 0 1
2
+ 1 2
X
2≤j≤d
p 2 j t 2 + I, (2.15)
η t = η 0 t + V (t, x) t 2 . (2.16)
Lemma 2.3. If η t 0 , η t are given by (2.15)–(2.16) and D is defined as below (2.13), then D H(t) η t = D H 0 η 0 t + r t with
(2.17) r t = d dt
V (t, x) t 2
−
iV (t, x), x 1 p 1 + p 1 x 1
t 3
. P r o o f. A simple transformation of the expression (2.15) gives
η t 0 = 1 2
p 2 1
t 2 − 2 x 1 p 1 + p 1 x 1
t 3 + 4x 2 1 t 4
+ 1 4
4 x 2 1
t 4 − 4 z 1 0 x 1
t 2 + (z 0 1 ) 2
+ 1
2 X
2≤j≤d
p 2 j t 2 + I
= 1 2
p 2 1
t 2 − x 1 p 1 + p 1 x 1
t 3 +
1
2 · 4 + 1 4 · 4
x 2 1 t 4
− z 0 1 x 1
t 2 + (z 0 1 ) 2 4 + 1
2 X
2≤j≤d
p 2 j t 2 + I
= 1 t 2
1
2 p 2 − z 0 1 x 1
− x 1 p 1 + p 1 x 1
t 3 + 3x 2 1
t 4 + (z 0 1 ) 2 4 + I.
Therefore we may express η 0 t in the following way:
(2.15 ′ ) η 0 t = H 0
t 2 − x 1 p 1 + p 1 x 1 t 3 + 3x 2 1
t 4 + (z 0 1 ) 2 4 + I and compute
D H(t) η t = D H(t)
η t 0 + V (t, x) t 2
= D H(t)
H(t)
t 2 − x 1 p 1 + p 1 x 1
t 3 + 3x 2 1 t 4
= D H(t)
H(t) t 2
−
iV (t, x), x 1 p 1 + p 1 x 1 t 3
+ D H 0
− x 1 p 1 + p 1 x 1
t 3 + 3x 2 1 t 4
= d dt
H 0
t 2 + V (t, x) t 2
−
iV (t, x), x 1 p 1 + p 1 x 1 t 3
+ D H 0
− x 1 p 1 + p 1 x 1
t 3 + 3x 2 1 t 4
= D H 0
H 0
t 2
+ D H 0
− x 1 p 1 + p 1 x 1
t 3 + 3x 2 1 t 4
+ r t = D H 0 η t 0 + r t . Lemma 2.4. If r t is given by (2.17) then r t = O(t −2 ).
P r o o f. First note that d
dt (t −2 V (t, x)) = t −2 ∂ t V (t, x) − 2t −3 V (t, x) = t −2 ∂ t V (t, x) + O(t −3 ).
Thus setting χ ′ k (t) = ( ˙ χ 1 k (t), ˙ χ ⊥ k (t)) ∈ R × R d−1 and using ˙ χ ⊥ k (t) = O(1), we have
t 2 r t = ∂ t V (t, x) −
iV (t, x), x 1 p 1 + p 1 x 1 t
+ O(t −1 )
= X
1≤k≤N
∂ x 1 V k (x − χ k (t))
2x 1
t − ˙χ 1 k (t)
+ O(1).
But 2x 1 /t − ˙ χ 1 k (t) = (2/t)(x 1 − χ 1 k (t)) + O(1) by (2.5 ′ ) and we complete the proof noting that ∂ x 1 V k (x − χ k (t))(x 1 − χ 1 k (t)) = O(1).
Proposition 2.5. If η t is given by (2.16) and D as below (2.13), then (2.18) D H(t) η t = − 3
t
p 1 t − 2x 1
t 2
2
− X
2≤j≤d
p 2 j
t 3 + O(t −2 ).
P r o o f. By Lemmas 2.3 and 2.4 it suffices to check that
(2.19) D H
0 η t 0 = − 3 t
p 1
t − 2x 1
t 2
2
− X
2≤j≤d
p 2 j t 3 . Now we note that formally
(2.20) D a
t (b t eb t ) = (D a t b t )eb t + (b t D a
t eb t ).
If a t and b t are self-adjoint, then (2.20 ′ ) D a
t (b t ) 2 = b t (D a t b t ) + (D a t b t )b t = 2b t (D a t b t ) + hc,
where m t + hc = 1 2 (m t + m ∗ t ) denotes the Hermitian symmetrization of the operator m t . In particular, using
(2.21) D H
0 w t = − w t
t , D H
0 y 1 t = 2
t (w 1 t − y t 1 )
[where w t , y t are given by (2.3)], we obtain 1
4 D H
0 (y t 1 ) 2 = 1 2 y 1 t D H
0 y t 1 + hc = 1
t y 1 t (w 1 t − y 1 t ) + hc, 1
2 D H
0 (w t 1 − y t 1 ) 2 = (w 1 t − y 1 t )D H 0 (w t 1 − y t 1 ) + hc
= 1
t (w 1 t − y 1 t )(2y t 1 − 3w 1 t ) + hc.
Introducing w t ⊥ = (w t 2 , . . . , w d t ) = (p 2 /t, . . . , p d /t) we may express (2.15) in the form
η t 0 = 1 2 (w t 1 − y t 1 ) 2 + 1 4 (y 1 t ) 2 + 1 2 |w ⊥ t | 2 + I and it is clear that 1 2 D H
0 |w ⊥ t | 2 = − 1 t |w ⊥ t | 2 . To complete the proof we com- pute
1 2 D H
0 (w 1 t − y 1 t ) 2 + 1 4 D H
0 (y t 1 ) 2
= 1
t (w 1 t − y t 1 )(2y 1 t − 3w 1 t ) + 1
t (w 1 t − y 1 t )y t 1 + hc
= 1
t (w 1 t − y t 1 )(3y 1 t − 3w 1 t ) + hc = − 3
t (w 1 t − y t 1 ) 2 . 3. Propagation estimates. We denote by G(H) the set of operator- valued functions t 7→ M (t) ∈ B(L 2 (R d )) satisfying
(3.1)
T
\1
dt Re(M (t)U (t, t 0 )ϕ, U (t, t 0 )ϕ) ≤ Ckϕk 2 for all ϕ ∈ L 2 (R d ), all T ≥ 1 and for some constant C > 0.
Sometimes we write M (t) ∈ G(H(t)) instead of M ∈ G(H). We note that if M (t) = O(t −1−ε ) with ε > 0, then M ∈ G(H),
(3.2)
if ( f M ∈ G(H) and M (t) ≤ f M (t) for all t ≥ 1), then M ∈ G(H).
(3.3)
If D H(t) M (t) is well defined, then writing U (t, t 0 )ϕ = ϕ t we have
(3.4)
T
\
1
dt ((D H(t) M (t))ϕ t , ϕ t ) =
T
\
1
dt d
dt (M (t)ϕ t , ϕ t ) = [(M (t)ϕ t , ϕ t )] T 1 and if M (t) = O(1), then D H(t) M (t) ∈ G(H(t)).
Note that η t 0 ≥ I and η t = η 0 t + O(t −2 ), hence for n ≥ 1, t ≥ T 0 , e η n,t = (1 + η t /n) −1 is well defined and satisfies 0 ≤ e η n,t ≤ I. Introducing
(3.5) M 0 (t) = 1
t η e n,t (3(w 1 t − y 1 t ) 2 + |w t ⊥ | 2 )e η n,t ,
we find that Proposition 2.5 gives
(3.6) nD H(t) e η n,t = −e η n,t (D H(t) η t )e η n,t = M 0 (t) + O(t −2 ).
It is clear that (3.4), (3.2) and (3.6) give
Corollary 3.1. If M 0 is given by (3.5), then M 0 ∈ G(H).
Proposition 3.2. For every ϕ ∈ L 2 (R d ) we have
n→∞ lim sup
t≥T 0
k(I − e η 2 n,t )U (t, t 0 )ϕk = 0.
P r o o f. First we set U (t, t 0 )ϕ = ϕ t and note that 0 ≤ λ ≤ 1 ⇒ (1 − λ 2 ) 2 ≤ 4(1 − λ), hence
k(I − e η n,t 2 )ϕ t k 2 = ((I − e η 2 n,t ) 2 ϕ t , ϕ t ) ≤ 4((I − e η n,t )ϕ t , ϕ t ).
It remains to note that e η n,T 0 ϕ T 0 → ϕ T 0 as n → ∞, and −nD H(t) η e n,t ≤
−M 0 (t) + Ct −2 ≤ Ct −2 allows us to estimate [((I − e η n,t )ϕ t , ϕ t )] T T 0 = −
T
\
T 0
dt ((D H(t) η e n,t )ϕ t , ϕ t ) ≤
T
\
T 0
dt Ct −2 /n ≤ C/n.
Further on in this section we assume n ≥ 1 fixed and write simply e
η t = e η n,t . As below (2.20 ′ ), M (t)+hc denotes the symmetrization 1 2 (M (t)+
M (t) ∗ ).
Lemma 3.3. Let J 0 ∈ C 0 ∞ (R). Then M 1 ∈ G(H) if
(3.7) M 1 (t) = 1
t η e t (y 1 t − w t 1 )J 0 (y t 1 )e η t + hc.
P r o o f. Let J ∈ C ∞ (R) be such that the derivative J ′ = −J 0 , and set M 1,0 (t) = e η t J(y 1 t )e η t .
Then D H(t) M 1,0 = M 1,1 + M 1,2 with
M 1,1 (t) = e η t (D H(t) J(y 1 t ))e η t = 2M 1 (t) + O(t −3 ), M 1,2 (t) = 2e η t J(y t 1 )D H(t) η e t + hc.
From (3.4) we have D H(t) M 1,0 ∈ G(H) and it is clear that in order to show M 1 ∈ G(H) it suffices to check that −M 1,2 ∈ G(H).
Noting that
w ⊥ t η e t = O(1), y t 1 η e t = O(1), (w 1 t − y 1 t )e η t = O(1), it is easy to estimate the commutators
n[e η t , w ⊥ t ] = −e η t [η 0 t + O(t −2 ), w ⊥ t ]e η t = O(t −2 ), n[e η t , w t 1 − y t 1 ] = e η t [η t 0 + O(t −2 ), y 1 t − w t 1 ]e η t
= e η t 1
4 (y t 1 ) 2 , y t 1 − w 1 t e
η t + O(t −2 ) = O(t −2 ),
n[e η t , J(y 1 t )] = −e η t [η 0 t , J(y 1 t )]e η t = O(t −2 ).
Using (2.18) to express D H(t) η e t in M 1,2 (t) it is easy to see that the above commutator estimates allow us to write
−M 1,2 (t) = 2
t η e t (3(w 1 t − y 1 t )a t (w t 1 − y t 1 ) + w t ⊥ a t w ⊥ t )e η t + O(t −2 ) with a t = −n −1 J(y t 1 )e η t + hc, and it is clear that the inequality a t ≤ CI implies
(3.8) −M 1,2 (t) ≤ 2CM 0 (t) + Ct −2
where M 0 is given by (3.5). By Lemma 3.3 the right hand side of (3.8) belongs to G(H) and consequently −M 1,2 ∈ G(H).
Proposition 3.4. Let J 0 ∈ C 0 ∞ (R \ {e z 1 , . . . , e z N }) where e z k = z k 1 − z 0 1 . Then M 2 ∈ G(H) if
(3.9) M 2 (t) = 1
t η e t J 0 (y 1 t )y 1 t η e t .
P r o o f. If M 1 is given by (3.7), then M 1 ∈ G(H) and M 2 = 3M 1 + M 3
with
M 3 (t) = 1
t η e t (3w t 1 − 2y t 1 )J 0 (y 1 t )e η t + hc.
Thus it remains to show that M 3 ∈ G(H). But for 1 ≤ k ≤ N , e z k 6∈ supp J 0
and
J 0 (y t 1 ) 6= 0 ⇒ |y 1 t − e z k | = |2x 1 /t 2 − z k 1 | ≥ c > 0
⇒ |x − χ k (t)| ≥
x 1 − 1 2 z k 1 t 2
− C ′ t ≥ 1 2 ct 2 − C ′ t implies
[iV (t, x), w 1 t ]J 0 (y t ) = −∂ x V (t, x)J 0 (y t )t −1 = O(t −3 ).
Therefore introducing
M 3,0 (t) = e η t (y t 1 − w 1 t )J 0 (y t )e η t + hc, we find that D H(t) M 3,0 = M 3,1 + M 3,2 + M 3,3 with
M 3,1 (t) = e η t (D H(t) (y t 1 − w t 1 ))J 0 (y t 1 )e η t = M 3 (t) + O(t −3 ), M 3,2 (t) = e η t (y 1 t − w t 1 )(D H(t) J 0 (y t 1 ))e η t + hc,
M 3,3 (t) = 2e η t (y 1 t − w 1 t )J 0 (y 1 t )D H(t) η e t + hc.
As before, (3.4) gives D H(t) M 3,0 ∈ G(H) and M 3 ∈ G(H) follows if we know that −M 3,2 , −M 3,3 ∈ G(H). To show −M 3,3 ∈ G(H) we note that we may replace M 1,2 by M 3,3 in (3.8) using a t = n −1 J 0 (y 1 t )(w 1 t − y 1 t )e η t + hc ≤ CI to express −M 3,3 similarly to −M 1,2 . Also
−M 3,2 (t) = − 2
t η e t (y t 1 − w 1 t )J 0 ′ (y 1 t )(y t 1 − w 1 t )e η t + O(t −3 )
≤ CM 0 (t) + Ct −3 ∈ G(H(t)).
We keep the notations J 0 , e z k , V 0k , V 0 , H 0 (t), U 0 (t, t 0 ) introduced in Sec- tion 2. Moreover, for 1 ≤ k ≤ N we denote by U k (t, t 0 ) the evolution propagator of the Hamiltonian
(3.10)
H k (t) = H 0 + V k (t, x) with V k (t, x) = V k (x − χ k (t)) + X
k ′ ∈{1,...,N }\{k}
V 0k ′ (t, x).
Corollary 3.5. If M 0 , M 2 , H k are as above, then M 0 , M 2 ∈ G(H k ).
P r o o f. Define η t k by using V k (t, x) instead of V (t, x) in (2.16). As before we obtain
M 0 k (t) = 1
t η e t k (3(w t 1 − y t 1 ) 2 + |w ⊥ t | 2 )e η k t ∈ G(H k (t))
with e η t k = (1 + η k t /n) −1 . We recall that |∂ t n ∂ x α V 0k ′ (t, x)| ≤ Ct −2µ−2|α|−n for
|α| + n ≤ 1, and reasoning as in the proof of Proposition 3.4 we find M 2 k (t) = 1
t e η k t J 0 (y t 1 )y 1 t η e k t ∈ G(H k (t))
for J 0 ∈ C 0 ∞ (R \ {e z 1 , . . . , e z N }). However, η t = η t k + O(t −2 ) implies
((w t 1 −y t 1 ) 2 +|w ⊥ t | 2 )(e η t − e η k t ) = ((w 1 t −y 1 t ) 2 +|w t ⊥ | 2 )e η t k (η t −η k t )e η t /n = O(t −2 ), hence
M j (t) = M j k (t) + O(t −2 ) ∈ G(H k (t)), j = 0, 2.
The following well known lemma is the basic tool allowing us to obtain the existence of wave operators (we give its proof in the Appendix):
Lemma 3.6. Let U (t, t 0 ) and e U (t, t 0 ) be the evolution propagators of H(t) = H 0 + V (t) and e H(t) = H 0 + e V (t) respectively. Assume that for M (t) ∈ B(L 2 (R d )) we may define D H 0 M (t) as bounded operators with (3.11) ( e V (t) − V (t))M (t) = O(t −1−ε ) and
D H
0 M (t) = f M (t) + O(t −1−ε )
where ε > 0, and that there exists f M 0 ∈ G(H)∩G( e H) satisfying the estimates (3.11 ′ ) − f M 0 (t) ≤ f M (t) ≤ f M 0 (t) and M f 0 (t) ≥ 0 for all t ≥ 1.
If ϕ ∈ L 2 (R d ) and Ω t = e U (t, t 0 ) ∗ M (t)U (t, t 0 ), then the limit lim t→∞ Ω t ϕ exists.
Proposition 3.7. Set J(y t 1 ) = 1 − P
1≤k≤N J 0 (y 1 t − e z k ) 2 and define (3.12) Ω 0 (t, t 0 ) = U 0 (t, t 0 ) ∗ J(y t 1 )U (t, t 0 ),
Ω k (t, t 0 ) = U k (t, t 0 ) ∗ J 0 (y t 1 − e z k )U (t, t 0 ) for k = 1, . . . , N.
Then for every ϕ ∈ L 2 (R d ), k = 0, 1, . . . , N , the following limits exist:
(3.12 ′ ) Ω k (t 0 )ϕ = lim
t→∞ Ω k (t, t 0 )ϕ.
P r o o f. Consider first the case k = 0. By Proposition 3.2 it suffices to show that
t→∞ lim U 0 (t, t 0 ) ∗ J(y t 1 )e η 2 n,t U (t, t 0 )ϕ
exists for every n ≥ 1. Further on n is fixed, we write e η t = e η n,t and we apply Lemma 3.6 with e H(t) = H 0 (t) and M (t) = J(y 1 t )e η 2 t .
We begin by noting that the first condition of (3.11) follows from (3.13) (H(t) − H 0 (t))J(y 1 t ) = X
1≤k≤N
J 0 (2y t 1 − 2e z k )V k l (x − χ k (t))J(y t 1 ) = 0.
To check (3.13) we note that J 0 (y t 1 − e z k ) 6= 0 ⇒ |y t 1 − e z k | < 4τ and for k ′ 6= k we have |e z k −e z k ′ | = |z k 1 −z 1 k ′ | ≥ 16τ , hence J 0 (y t 1 −e z k ) 6= 0 ⇒ J 0 (y 1 t −e z k ′ ) = 0 for k ′ 6= k. Thus it is clear that J 0 (2y 1 t − 2e z k ) 6= 0 ⇒ |y 1 t − e z k | < 2τ ⇒ J 0 (y t 1 − e z k ) = 1 ⇒ J(y 1 t ) = 1 − J 0 (y 1 t − e z k ) 2 = 0.
Next we find that D H 0 M = f M 1 + f M 2 with M f 1 (t) = (D H 0 J(y 1 t ))e η t 2 = 2
t η e t (w 1 t − y t 1 )J ′ (y t 1 )e η t + hc + O(t −2 ), (3.14)
M f 2 (t) = 2e η t J(y 1 t )D H(t) η e t + hc + O(t −2 ).
(3.15)
Next for k = 1, . . . , N , we have |y t 1 | ≤ 2τ ⇒ |y 1 t − e z k | ≥ 14τ ⇒ J 0 (2y t 1 − 2e z k ) = 0. Therefore J = 1 on [−2τ ; 2τ ] and 0 6∈ supp J ′ allows us to define J 0 ∈ C 0 ∞ (R \ {e z 1 , . . . , e z N }) satisfying J 0 (λ)λ = J ′ (λ) 2 and to estimate (3.16) ± (w t 1 − y t 1 )J ′ (y t 1 ) + hc ≤ 2(w 1 t − y 1 t ) 2 + 2J 0 (y t 1 )y 1 t
⇒ ± f M 1 ≤ 4M 0 + 4M 2
with M 0 , M 2 given by (3.5), (3.9). Then similarly to the proof of Lemma 3.3 we find ± f M 2 (t) ≤ CM 0 (t) + Ct −2 , hence it is clear that the hypotheses of Lemma 3.6 hold with f M 0 = C 0 M 0 + 4M 2 ∈ G(H) ∩ G(H k ) by Corollary 3.1, 3.5 and Proposition 3.4.
In the case k = 1, . . . , N , we apply Lemma 3.6 with e H(t) = H k (t) and M (t) = e J(y t 1 )e η t 2 , where e J(λ) = J 0 (λ − e z k ). As before we have
(3.17) (H(t) − H k (t)) e J (y t 1 )
= X
k ′ ∈{1,...,N }\{k}
J 0 (2y t 1 − 2e z k ′ )V k l ′ (x − χ k ′ (t)) e J (y 1 t ) = 0.
Indeed, e J(y t 1 ) 6= 0 ⇒ |y t 1 − e z k | < 4τ ⇒ |y 1 t − e z k ′ | ≥ 2τ for k ′ 6= k ⇒
J 0 (2y t 1 − 2e z k ′ ) = 0 for k ′ 6= k. We complete the proof noting that e J = 0 on
[−2τ ; 2τ ] and (3.14)–(3.16) still hold if J is replaced by e J.
4. Asymptotic completeness. In order to obtain the asymptotic completeness it remains to prove
Proposition 4.1. If k = 1, . . . , N and ϕ ∈ L 2 (R d ), then
t→∞ lim J 0 (y t 1 − e z k )U k (t, t 0 )ϕ = 0.
Indeed, using Propositions 2.2, 3.7 and 4.1, we can see that via the chain rule,
e itH 0 +iS(t) U (t, t 0 )ϕ = e itH 0 +iS(t)
J(y 1 t ) + X
1≤k≤N
J 0 (y 1 t − e z k ) 2
U (t, t 0 )ϕ
= e itH 0 +iS(t) U 0 (t, t 0 )Ω 0 (t, t 0 )ϕ
+ X
1≤k≤N
e itH 0 +iS(t) J 0 (y 1 t − e z k )U k (t, t 0 )Ω k (t, t 0 )ϕ converges to e Ω 0 (t 0 ) ∗ Ω 0 (t 0 )ϕ, i.e. the limit (1.12 ′ ) exists.
Before starting the proof of Proposition 4.1 we introduce more notation.
We set
(4.1) H 0k = 1 2 p 2 + e z k x 1 , H e k = H 0k + V k (x − ω k ), where k = 1, . . . , N and ω k is as in (2.5). We define
χ 0 k (t) = 1 2 z k t 2 + υ k t, χ ˙ 0 k (t) = z k t + υ k , (4.2)
H e k (t) = H 0k + e V k (t, x) (4.3)
with
V e k (t, x) = V k (t, x + χ 0 k (t))
= V k (x − e χ k (t)) + X
k ′ ∈{1,...,N }\{k}
V 0k ′ t, x + 1 2 z k t 2 + υ k t . It is easy to see that V 0k ′ t, x+ 1 2 z k t 2 +υ k t
satisfies estimates (2.1) similarly to V 0k ′ . The following lemma allows us to compare e H k and e H k (t).
Lemma 4.2. (a) We have V k (x − e χ k (t)) = V k (x − ω k ) + O(t −2µ 0 ) and d
dt V k (x − e χ k (t)) = −e χ ′ k (t) · ∇V k (x − e χ k (t)) = O(t −1−2µ 0 ).
(b) If h ∈ C 0 ∞ (R) then h( e H k (t)) = h( e H k ) + O(t −2µ 0 ) + O(t −2µ ) and D e H k (t) h( e H k (t)) = d
dt h( e H k (t)) = O(t −1−2µ 0 ) + O(t −1−2µ ).
(c) If g, e h ∈ C 0 ∞ (R) then [e h( e H k ), g( e w t )] = O(t −1 ).
We note that our assumptions ∇V k = ∇V k l = O(1) and (1.9) give imme-
diately the indicated estimate of dt d V k (x − e χ k (t)), while the first estimate of
Lemma 4.2(a) follows by integration. The proof of estimates in (b) and (c) is given in the Appendix.
Proposition 4.3. Let g ∈ C 0 ∞
− 3 4 |e z k |; 3 4 |e z k |
and h ∈ C 0 ∞ (R). Then (4.4) M f h (t) = 1
t h( e H k (t))g( e w t ) 2 h( e H k (t)) ∈ G( e H k (t)), where we have set e w t = p 1 /t.
P r o o f. Let n ∈ N be such that h ∈ C 0 ∞ (]−n; n[). Since ( f M h (t)ϕ, ϕ) = t −1 kg( e w t )h( e H k (t))ϕk 2 , it is clear that f M h 1 +h 2 (t) ≤ 2 f M h 1 (t) + 2 f M h 2 (t).
Thus it suffices to show that for every λ ∈ [−n; n] there is δ > 0 such that M f h (t) ∈ G( e H k (t)) with h ∈ C 0 ∞ (]λ − δ; λ + δ[), |h| ≤ 1.
Let g 1 ∈ C ∞ (R) satisfy g 1 ′ = −g 2 and set
M 0 (t) = e z k h( e H k (t))g 1 ( e w t )h( e H k (t)).
Let ε = min{1, 2µ 0 , 2µ}. Then Lemma 4.2 allows us to write
D e H k (t) M 0 (t) = e z k h( e H k (t))(D e H k (t) g 1 ( e w t ))h( e H k (t)) + O(t −1−ε )
= e z k h( e H k )(D e H k g 1 ( e w t ))h( e H k ) + O(t −1−ε ).
We now show that choosing δ > 0 small enough we have (4.5) e z k h( e H k )[iV k (x−ω k ), g 1 ( e w t )]h( e H k ) ≥ − z e 2 k
8t h( e H k )g( e w t ) 2 h( e H k )−Ct −2 . Using (1.11b) and the standard pseudo-differential expansion [(A.1) of Ap- pendix with n = 2 and then with n = 1] we find the following expression of the commutator:
[iV k (x − ω k ), g 1 ( e w t )] = − 1
t ∂ x 1 V k (x − ω k )g 1 ′ ( e w t ) + O(t −2 ) (4.6)
= 1
t g( e w t )∂ x 1 V k (x − ω k )g( e w t ) + O(t −2 ),
and since e H k has no eigenvalues (cf. [20]), 1 [λ−2δ;λ+2δ] ( e H k ) → 0 strongly as δ → 0. As ∂ x 1 V k (x − ω k )1 [−n;n] ( e H k ) is compact, for δ > 0 small enough we have
(4.7) z e k eh( e H k )∂ x 1 V k (x − ω k )e h( e H k ) ≥ − 1 8 e z k 2
if e h ∈ C 0 ∞ (]λ−2δ; λ+2δ[), 0 ≤ e h ≤ 1. Using e h such that h = he h and Lemma 4.2(c) we obtain (4.5) from (4.6)–(4.7). Next we note that D H 0k g 1 ( e w t ) =
−t −1 (e z k + e w t )g 1 ′ ( e w t ) = t −1 (e z k + e w t )g( e w t ) 2 and since λ ∈ supp g ⇒ |λ| ≤
3
4 |e z k | ⇒ e z k (e z k + λ) ≥ 1 4 z e k 2 , it is clear that (4.8) z e k h( e H k )(D H 0k g 1 ( e w t ))h( e H k ) ≥ 1
4t z e k 2 h( e H k )g( e w t ) 2 h( e H k ).
Let M 1 , M 2 denote the left hand sides of (4.5) and (4.8). Then (4.4) follows from
1
8 e z k 2 M f h (t) ≤ (M 1 + M 2 )(t) + Ct −1−ε
= D e H k (t) M 0 (t) + O(t −1−ε ) ∈ G( e H k (t)).
Proof of Proposition 4.1 . Step 1. Introduce
(4.9)
G k (t) = e −iΦ k (t) e −ix· ˙ χ 0 k (t) e ip·χ 0 k (t) where Φ k (t) =
t
\
1
dτ z 0 · χ 0 k (τ ) + 1 2 χ ˙ 0 k (τ ) 2 .
Since e −ix· ˙ χ 0 k (t) p = (p + ˙ χ 0 k (t))e −ix·χ 0 k (t) and e ip·χ 0 k (t) x = (x + χ 0 k (t))e ip·χ 0 k (t) , we compute
G ′ k (t) = − z 0 · χ 0 k (t) − 1 2 χ ˙ 0 k (t) 2 − x · z k + (p + ˙ χ 0 k (t)) · ˙ χ 0 k (t) iG k (t), iG k (t)H k (t) = 1 2 (p + ˙ χ 0 k (t)) 2 − z 0 · (x + χ 0 k (t)) + V k (t, x + χ 0 k (t))
iG k (t)
= e H k (t) + p · ˙ χ 0 k (t) + 1 2 χ ˙ 0 k (t) 2 − z k · x − z 0 · χ 0 k (t) iG k (t)
= i e H k (t)G k (t) + G ′ k (t).
Thus we have d
dt ( e U k (t, t 0 ) ∗ G k (t)U k (t, t 0 )ϕ)
= e U k (t, t 0 ) ∗ (G ′ k (t) + i e H k (t)G k (t) − iG k (t)H k (t))U k (t, t 0 )ϕ = 0, which implies
(4.10) U e k (t, t 0 ) = G k (t)U k (t, t 0 )G k (t 0 ) −1 . We write e y t = 2x 1 /t 2 . Then
G k (t)J 0 (y 1 t − e z k ) = J 0 (e y t + 2υ k 1 /t)G k (t) = J 0 (e y t )G k (t) + O(t −1 ) and using (4.10) we obtain
(4.11) lim
t→∞ kJ 0 (y 1 t − e z k )U k (t, t 0 )ϕk = lim
t→∞ kJ 0 (e y t ) e U k (t, t 0 )G k (t 0 )ϕk.
Step 2 . It suffices to show that for every h ∈ C 0 ∞ (R) we have
(4.12) lim inf
t→∞ kJ 0 (e y t )h( e H k (t)) e ϕ t k = 0 where we have set e ϕ t = e U k (t, t 0 )G k (t 0 )ϕ.
Indeed, note first that (4.11) is the limit of the norms of ϕ(t) = U k (t, t 0 ) ∗
× J 0 (y t 1 − e z k )U k (t, t 0 )ϕ and that ϕ(t) converges in L 2 (R d ), by a reasoning
analogous to the proof of Proposition 3.7. Thus the limits (4.11) exist and
we may replace them by lim inf.
However, taking h 0 ∈ C 0 ∞ (R) such that h 0 = 1 in a neighbourhood of 0, 0 ≤ h 0 ≤ 1, we have h 0 ( e H k (T 0 )/n)ψ → ψ as n → ∞ and by Lemma 4.2(b),
[((I − h 0 ( e H k (t)/n)) 2 ϕ e t , e ϕ t )] T T 0 =
T
\
T 0
dt (D e H k (t) (I − h 0 ( e H k (t)/n)) 2 ϕ e t , e ϕ t )
≤
T
\