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and to two half-circles at the ends, radius r = BD = 1m. The beam is loaded by tensile mining actions on the hori

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GEOENGlNEER|NG-FOUNDAT|ONS (M.Sc. Study in CE) Final Evajuation Test #1

Y) =O

Calculation Task #2: a 14m long symmetrical foundation beam can be split to a rectangular part BxL1=2mxl2m

and to two half-circles at the ends, radius r = BD = 1m. The beam is loaded by tensile mining actions on the hori

zontal contact level which act along the beań. Ultimate shearing stress t equals @ = 30kPa with the pre-ultimate interval xo :3.0m. Two veńical beam sides are free offrictional forces, Zt= 0. Draw shapes of t(.x) and Z(x).

C#1 (15 min, max 7pts.)

C#2 (l0 min, max 4pts.) DATE of the TEST:

Q#1 (5 min, max 3pts.) Student's name: ł,tr BPZAVAĘ

Q#2 (5 min, max 3pts.) Student's lD number: 3' +O(

Q#3 (5 min, max 3pts.)

Today's Student's CODE in the format AB12: MBEtr'

TOTAL (40 min, max 20pts.) FlNAL SCORE:

Attention: note that completely wrong answer may by evaluated with negative points !

Cąlculation Task #I: simple modelling of a long vertical pile uses a horizontal (rotated) half_infinite beam ot Winkler subsoil. The beam is loaded only by a force Po applied to the end Ę:0, no concentrated momęnt Mo

ź

at this end. The general solution to be used fo. Ę : xlLw > 0, L* _ d4 .BI(B .6) is as follows:

1) Formulate all boundary conditions, (2pts.)

2) Find all the constants Ci, (2pts.)

3) Present graphically the following three solutions:

y(Ę): settlements [m], (]pt.)

M(Ę): bending moments [kNm], (Lpt.)

Q@: shearing forces [kN], (Ipt.) along the entire beam, 0 < Ę. *.

Hint: app|y the Euler-Bernoulli condition.

Ouestion #l: a very rigid foundation beam is loaded eccentrically by a vertical force P [kN/m]

applied on the left side from the center. Contact of the beam with the subsoil is smooth.

Draw in one figure probable shapes of vertical contact stresses under foundation for 3 different cases of the beam-subsoil interaction:

a) the Winkler subsoil model with a concave mining subsidence (R < 0).

b) the Winkler subsoil model with no mining deformations,

c) the Winkler subsoil model with a convex mining subsidence (R> 0).

The eccentriciĘ e is "small" and the mining radius |R| is "very large".

Mark a)b)c) for each curve.

Ouestion #2: answer 6 questions with only one of the letters T=TRUE or F=FALSE, respectively:

(]pt. for 4 correct answers, 2pls. for 5 correct answers, 3pts. for 6 correct answers; ,

_

nó written justification is Óxiected here - just mark T oiF; no negative points wili&gned here)

. the Pastemak model ofthe elastic subsoil uses 3 parameters ... F

. when a long mining fiont (in 2D) approaches a building, compressive strains appear first (e<0) ...F

. 4 virtual forces ł ,Tz,T,Tł of Blęichare necessary to solve any infinite beam ...,. ,.,..,...F

. in ZEM-SIN algońt}rm for prismatic beams with 13 identical segments ńere is always }\1> yn andwl'= r, , . . . . . T

. in ZEM-SIN algorińm for prismatic beams witłr

1

7 identical segments there is alwa}s 1t = }1 . . . , . . . . . .

,

F

. in ZEM-SIN algorithm for beams which undergo mining subsidences Ą+4 where d: const, numerical solutions ri do not depend on the value ofd

Ouestion #3: infinite beam on the Winkler subsoil has a perfectly fixed support (no spring element) at a distance s from the point Ę :0 being loaded by P.

Draw probable solutions for the vertical displacement curve Jp, moments M and shearing forces Qfor -oo < Ę < +*.

Yrs):o

Pay special attention to the supported cross-section and the loadęd place.

Calculate values of tensile forces Z [kN]

acting at three distinguished cross-sections:

,,: tT,,lh,3o Zc:ZB * Z,Xr, 30

Zr:Zc + 3,ł, 3o 7v

'!t 1,1

= p=-ń"p,,ń=o

,, JrĆ;Z: *c,,, F n. 17 *7\

'-roĄ-rP

h,, 'N =

l3 -t_

t-P

rył=-P, Ą:o

:O T

Q: *-El 'Y,,,,

ła,(Cr,ę: bś\r, ,LŃ= ł|"

.?'.W --T

= P" L,j

-3 óv dy-

-)9

f(Ę) e-Ę,sin

,

e-Ę.cosł ę*Ę,cńtł ę*Ł.sin{,/

df/dŁ -e-Ę,sinĘ + e-Ę.cosĘ -e-Ę,sinĘ - e-Ę.cosĘ e,\.cox/ę

LY ę,/ -/Lu

s.stnĘ e*Ę,sinĘ/#cost

dzfldŁ2 -2ę-Ę.cosĘ l/ 2ę-Ę.sinŁ L' ft*Ę.siną ŹX*;ą

d3fldąs 2e-Ę,sin,+2ę-Ę.cos, -Zę-Ę,sĘ a 29-ĘĘ6Ę1| -de* .sin|- Ze* .cośŁ 2ę*,ósĘ- 2e*Ę.sinŁ

'V^

l::t;

O1 l\ i i,=/ [_ >

L}ą % ,l l

t r--o +El .C3,(-l,

lOs Z-El

!-, =po ,l- T=o

L-U lb_l8-19-Winter

l;,,*rł

ó"

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