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LXXXVIII.3 (1999)

Concordant sequences and integral-valued entire functions

by

Jonathan Pila (Melbourne) and

Fernando Rodriguez Villegas (Austin, Tex.)

A classic theorem of P´olya shows that the function 2

z

is the “smallest”

integral-valued entire transcendental function. A variant due to Gel’fond applies to entire functions taking integral values on a geometric progression of integers, and B´ezivin has given a generalization of both results. We give a sharp formulation of B´ezivin’s result together with a further generalization.

1. Introduction. In a classic paper [15], P´olya showed that the growth of an entire transcendental function places restrictions on its integral values.

Let f be an entire function and denote by M (f, r) the maximum of |f (z)|

for |z| ≤ r. Suppose that f (n) is an integer for each non-negative integer n.

P´olya showed in [15] that if

r→∞

lim

M (f, r) r 2

r

= 0 then f is a polynomial.

The obtrusive factor

r was removed by Hardy [11]. The result was then further sharpened by P´olya [16] to the following. Let f be an entire function such that f (n) is an integer for each non-negative integer n. Suppose that

lim sup

r→∞

M (f, r) 2

r

< 1.

Then f is a polynomial.

Thus the function 2

z

is the “smallest” transcendental entire function taking integral values on the set N = {0, 1, . . .}.

The commentary [3] by Boas in P´olya’s collected works indicates some of the many lines of research stimulated by P´olya’s result.

A variation on P´olya’s result for geometric progressions was obtained by Gel’fond [8] (see also [9, §2.3.4]). The result, slightly reformulated (Gel’fond

1991 Mathematics Subject Classification: Primary 11J99.

[239]

(2)

considered geometric progressions a, a

2

, a

3

, . . . but it is more convenient for us to begin the sequence with a

0

), is as follows. Let a ∈ Z, |a| ≥ 2. Let f be an entire function taking integral values on the set X

a

= {1, a, a

2

, . . .} and suppose that

r→∞

lim

M (f, r)

exp((log r)

2

/(4 log a)) = 0.

Then f is a polynomial.

Gel’fond exhibited a function T

a

that plays the role of the “smallest”

X

a

-integral transcendental entire function and showed that M (T

a

, r) = O

 exp

 (log r)

2

4 log a



.

Thus Gel’fond’s result is not quite as sharp at the boundary as that of P´olya–Hardy above. We describe the construction of T

a

below.

A result of B´ezivin [1] generalizes both of these theorems. It is convenient to deal with sequences rather than sets, and indeed with sequences X = {x

0

, x

1

, . . .} that do not contain any repetitions: x

i

= x

j

if and only if i = j.

We will call such a sequence (finite or infinite) proper . B´ezivin considers sequences X = {x

0

, x

1

, . . .} ⊂ Z that are the (infinite) orbits obtained by the iteration of a univariate polynomial P with integral coefficients:

X

P,x0

= {x

0

, x

1

, . . . | x

0

∈ Z, x

i+1

= P (x

i

), i = 0, 1, . . .}.

The case considered by P´olya arises from the choice P (x) = x+1, x

0

= 0, and the case considered by Gel’fond from P (x) = ax, |a| ≥ 2, x

0

= 1. As a further instance, the choice P (x) = x

b

, b ≥ 2, x

0

= a ≥ 2 yields a result of P´olya–Gel’fond type for the set

X

a,b

= {a

bn

| n = 0, 1, . . .}.

Let P be of degree d ≥ 2 and x

0

∈ Z with X = X

P,x0

proper. B´ezivin exhibits a constant λ

0

= λ

0

(P, x

0

) and proves the following result. Let f (z) be an entire function that is integral-valued on X. Suppose that λ > λ

0

and that, for all sufficiently large r,

M (f, r) ≤ exp

 log r log log r − log r log log log r

log d − λ log r

 . Then f is a polynomial.

B´ezivin exhibits a transcendental entire function T

X

that is integral- valued on X and satisfies

M (T

X

, r) ≤ exp

 log r log log r − log r log log log r

log d + O(log r)



for all sufficiently large r. Thus the result is best possible in respect of the

main terms of the order of growth. The construction of T

X

is described

below.

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We prove a sharp version of B´ezivin’s result in which the growth of the X-integral function f is compared directly with the growth of T

X

. Our result shows that T

X

is the “smallest” transcendental entire function that is integral-valued on X in the sense of the above mentioned result of P´olya [16].

Our result also applies to a somewhat more general class of sequences X;

namely, to sequences that enjoy two properties that we now proceed to describe.

The first property is of an arithmetic nature. A sequence X = {x

0

, x

1

, . . .}

of integers will be called concordant if, for all non-negative integers i, j, d, we have

x

i

≡ x

j

mod d ⇒ x

i+1

≡ x

j+1

mod d.

Sequences of the form X

P,x0

are evidently concordant. More generally, a concordant sequence results from the iteration (where possible) of any pseudopolynomial as defined by Hall [10]; that is, a function T : N → Z sat- isfying T (n + k) ≡ T (n) mod k for all non-negative integers n, k. (To enable iteration one would want T : N → N or T defined on all Z.) There exist pseudopolynomials that are not polynomials; there also exist pseudopoly- nomials that are polynomials but that do not have integral coefficients. For further information on pseudopolynomials see [10], [13].

Concordant sequences may be composed preserving the concordant prop- erty. If X = {x

0

, x

1

, . . .} and Y = {y

0

, y

1

, . . .} are sequences with y

n

≥ 0 for all n we define

X

Y

= Z = {z

0

, z

1

, . . .}, z

n

= x

yn

, n = 0, 1, . . . The following proposition is proved in Section 5.

Proposition 1.1. Let X = {x

0

, x

1

, . . .} and Y = {y

0

, y

1

, . . .} be concor- dant sequences of integers and suppose that 0 ≤ y

0

< y

1

< . . . Then X

Y

is concordant.

If X, Y are of the form X

P,x0

with P a polynomial then X

Y

will not in general be of this form; for example, if X = X

a

and Y = X

b,c

then X

Y

consists of the points

a

bcn

, n = 0, 1, 2, . . .

The second property that we require is of an analytic nature and entails that the sequence be very sparse. A sequence X = {x

0

, x

1

, . . .} of complex numbers will be called diffuse if

n→∞

lim |x

n

| = ∞, lim

n→∞

|x

n+1

|

n+1

|x

n

|

2n

= ∞.

We prove in Section 3 that, if P has degree 2 or greater, then the sequence

X

P,x0

, if proper, is diffuse. In Section 5 we prove that any subsequence of a

diffuse sequence is diffuse.

(4)

Given a diffuse concordant sequence X of integers we define below an entire function T

X

, following the constructions of Gel’fond and B´ezivin, that plays the role of the “smallest” transcendental entire function that is integral-valued on X. The following theorem is proved in Section 4.

Theorem 1.2. Let X be a diffuse concordant sequence of integers. Let f be an entire function that takes integral values on X and satisfies

lim sup

r→∞

M (f, r) M (T

X

, r) < 1.

Then f is a polynomial.

The proof of Theorem 1.2 follows the same line of proof as P´olya [15], Gel’fond [8] and B´ezivin [1]. A certain sequence of polynomials associated with X plays a fundamental role. For P´olya, these are the polynomials

φ

0

(x) = 1, φ

j

(x) = x(x − 1) . . . (x − j + 1)

j! , j = 1, 2, . . .

These polynomials have the following properties: φ

n

has degree n, vanishes at the points 0, 1, . . . , n − 1 and takes the value 1 at n. They have the addi- tional property of taking integral values on N (indeed on Z). An analogous sequence φ

X,n

of polynomials may be associated with any proper (infinite) sequence X = {x

0

, x

1

, . . .} of complex numbers. They are uniquely deter- mined by the properties that φ

X,n

has degree n, vanishes at x

0

, x

1

, . . . , x

n−1

and satisfies φ

X,n

(x

n

) = 1.

A sequence X of integers will be called a parade if each of the polynomials φ

X,n

has the additional property of being integral-valued on X. We will refer to the polynomials φ

X,n

as the attendant polynomials of the parade X. B´ezivin [1] proves that the sequences X

P,x0

are parades. We prove the following generalization in Section 2.

Proposition 1.3. Let X be a proper concordant sequence. Then X is a parade.

Let us mention also that while concordant sequences provide many ex- amples of parades, the sequence x

n

= n

2

, n = 0, 1, 2, . . . , is a parade but is not concordant. This sequence is also not diffuse.

For a parade X that is sufficiently sparse the “smallest” X-integral tran- scendental entire function is constructed by simply adding up the sequence of attendant polynomials. One easily proves (see Section 3) the following.

Proposition 1.4. Let X be a diffuse sequence of complex numbers. Then the series

T

X

(z) = X

n=0

φ

X,n

(z)

(5)

converges absolutely for all complex z and determines an entire func- tion T

X

.

We will call T

X

the envelope function of X. When X = N, i.e. P´olya’s situation, the series converges to 2

z

only at non-negative integers. So we will define the envelope function of N to be the function 2

z

. For P = x + k, X = X

P,x0

we can similarly define T

X

(z) = 2

(z−x0)/k

. Since a very sharp result nevertheless obtains in the case X = N, it might be hoped that sparsity hypotheses such as our notion of diffusity could be dispensed with in the formulation of results of the type of Theorem 1.2. However if the sum of attendant polynomials does not converge to an entire function it is not clear in general how to interpolate the values on X by an entire function in an appropriate way to define T

X

.

Various authors have investigated the structure of entire functions that are integral-valued but grow faster than 2

z

. A result of P´olya [16] in this direction is as follows. Let k be a positive number. Suppose that f is an integral-valued entire function and that M (f, r)r

−k

/2

r

is bounded as r →

∞. Then there are polynomials P, Q such that f (z) = P (z)2

z

+Q(z). Selberg [18] obtains the same conclusion under the weaker assumption

lim sup

r→∞

log M (f, r)

r ≤ log 2 + 1 1500 . Pisot [14] shows that if

lim sup

r→∞

log M (f, r)

r < 0.843 . . . then f is of the form

α

z1

P

1

(z) + α

z2

P

2

(z) + . . . + α

zh

P

h

(z)

where α

1

, . . . , α

h

are algebraic integers. See also related results of Buck [5]

and Robinson [17].

As remarked by Buck [5], any structure results of these kinds must be limited to functions growing slower than the function sin(πz): if g is any entire function then g(z) sin(πz) is integral-valued.

It would be interesting to pursue analogous results for other parades.

As far as we are aware, none are known even for the case of geometric progressions.

For a diffuse parade X the canonical product H

X

(z) =

Y

n=0

 1 − z

x

n



is entire, and any investigation of the structure of X-integral entire functions would be confined to functions whose growth rate is between those of T

X

and H

X

.

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B´ezivin [2] considers integral-valued entire functions f on very general subsequences X of geometric progressions X

a

. The sequences considered are not in general parades. He proves under quite general hypotheses that if f is X-integral and

lim sup

r→∞

log M (f, r) log M (H

X

, r) < 1 then f is a polynomial.

Thus any interesting integral-valued entire functions and structure of such functions along the lines of the above mentioned results for such se- quences X would need to occur among functions f that do not satisfy the above condition relative to H

X

but that nevertheless grow slower than H

X

. In view of Proposition 1.1 and the properties of diffuse sequences de- scribed above, Theorem 1.2 applies to any concordant subsequence of proper sequences of the form X

P,x0

where the degree of P is at least 2. Hence in particular it applies to the sequences

X

a,b,c

= {a

bcn

| n = 0, 1, 2, . . .}, X

a,b,c,d

= {a

bcd

n

| n = 0, 1, 2, . . .}, etc.

The results of B´ezivin [2] also apply to these sequences. Thus in these cases one has at least the function T

X

in the growth-rate range of interest.

The remainder of the paper, Section 6, is devoted to establishing some properties of envelope functions. For the functions T

a

of Gel’fond we get a combinatorial expression for the Taylor coefficients by establishing a recur- rence relation satisfied by T

a

. We also show that the envelope function of any diffuse increasing parade shares with the function 2

z

the property that all but finitely many Taylor coefficients are positive.

Acknowledgements. We are grateful to J. FitzGerald, K. Ford, B.

Poonen, I. Rivin and J. Tate for discussions and assistance at various junc- tures. The first author thanks P. Sarnak and the Mathematics Department of Princeton University for their hospitality during the visit that occasioned the present collaboration. We are also most grateful to the referee for sug- gesting several substantial improvements to this paper.

2. Concordant sequences and parades. In this section we prove Proposition 1.3 in a general setting.

Let R be a commutative ring with 1. A sequence X = {x

n

} ⊂ R, n ∈ Z

≥0

, will be called proper if the x

n

’s are all distinct, and concordant if it is proper and for every i, j ∈ Z

≥0

and every ideal I ⊂ R we have

x

i

≡ x

j

mod I ⇒ x

i+1

≡ x

j+1

mod I.

The sequences X

P,x0

are easily seen to be concordant sequences in Z: if

x

i

≡ x

j

mod d then P (x

i

) ≡ P (x

j

) mod d. In Section 5 we construct some

further natural examples of concordant sequences in Z.

(7)

Given a concordant sequence X ⊂ R and an ideal I ⊂ R consider the sequence x

n

= x

n

mod I. Let i ∈ Z

≥0

be the smallest index (if any such indices exist) so that there exists a j

0

∈ Z

≥0

such that i < j

0

and x

j0

= x

i

. Let j be the smallest such j

0

and set δ = j − i ∈ N. It is not hard to see that x

n

is then of the form

x

0

, x

1

, . . . , x

i−1

, x

i

, . . . , x

i+δ−1

, x

i

, . . . , x

i+δ−1

, . . .

with no repetitions other than those explicitly indicated. More precisely, x

j

= x

j0

if and only if i ≤ j, j

0

and j ≡ j

0

mod δ.

From now on we assume that R is a domain and let K be its field of fractions. Given a proper sequence X in R and two positive integers m, n ∈ N with m > n we define

 m n



X

= (x

m

− x

0

)(x

m

− x

1

) . . . (x

m

− x

n−1

) (x

n

− x

0

)(x

n

− x

1

) . . . (x

n

− x

n−1

) ∈ K.

If R = Z and x

n

= n for all n ∈ Z

≥0

then, of course, this is just the usual binomial coefficient

mn



, which explains our choice of notation. Our goal is to prove the following.

Proposition 2.1. Let R be an integrally closed domain and let X be a proper concordant sequence in R. Suppose that m, n ∈ Z with m > n. Then

 m n



X

∈ R.

P r o o f. Let A be a valuation ring in K containing R. That is, A is a subring of K containing R and equipped with a valuation v : A \ {0} → V , where V is a totally ordered group. Fix m, n ∈ N with m > n. For any k ∈ V we define

N (k) = #{j | 0 ≤ j < n, v(x

m

− x

j

) ≥ k}, D(k) = #{j | 0 ≤ j < n, v(x

n

− x

j

) ≥ k}.

It is clear that N, D : V → N are decreasing step functions. More precisely, let k

1

< . . . < k

s

∈ V be an ordered enumeration of the set {v(x

m

− x

i

)} ∪ {v(x

n

− x

i

)}, where i = 0, . . . , n − 1. Then N and D are constant on each of the sets {k ∈ V | k ≤ k

1

}, {k ∈ V | k

j−1

< k ≤ k

j

} for j = 2, . . . , s, and {k ∈ V | k

s

< k}. To simplify the notation we will let N

j

= N (k

j

) and D

j

= D(k

j

) for j = 1, . . . , s − 1. We have

N = v((x

m

− x

0

)(x

m

− x

1

) . . . (x

m

− x

n−1

)) = X

s−1 j=1

k

j

(N

j

− N

j+1

) + k

s

N

s

and

D = v((x

n

− x

0

)(x

n

− x

1

) . . . (x

n

− x

n−1

)) =

s−1

X

j=1

k

j

(D

j

− D

j+1

) + k

s

D

s

.

(8)

By summation by parts, N = k

1

N

1

+

X

s j=2

(k

j

− k

j−1

)N

j

, D = k

1

N

1

+ X

s j=2

(k

j

− k

j−1

)D

j

. Fix k ∈ V and let I ⊂ A be the ideal {a ∈ A | v(a) ≥ k}. Also let, as before, x

n

= x

n

mod I. Since x

n

is concordant our above description of x

n

guarantees the following. Assume first that i ≤ n and let j, j

0

be the unique indices i ≤ j, j

0

≤ i + δ − 1 such that x

n

= x

j

and x

m

= x

j0

. Then

N (k) =

 D(k) if j ≤ j

0

, D(k) + 1 otherwise.

If i > n then N (k) = D(k) = 0.

Therefore v

 m n



X



= N − D = k

1

(N

1

− D

1

) + X

s j=2

(k

j

− k

j−1

)(N

j

− D

j

) and

0 ≤ v

 m n



X



≤ k

s

. We have proved that

mn



X

is in A. Since the valuation ring A was arbi- trary,

mn



X

is also in the intersection of all such A’s. Since R is an integrally closed domain, the intersection of all valuation rings containing R is R [4, VI, §3, Theorem 3]. This completes the proof.

Proof of Proposition 1.3. The conclusion follows from Proposition 2.1 since

φ

X,n

(m) =

 m n



X

.

Remark 2.2. B´ezivin [1] proves a version of Proposition 2.1 for se- quences formed by iteration of a univariate polynomial. One may extract somewhat more information in that case. Let d be a positive integer. Let a

0

, a

1

, . . . , a

d

be independent indeterminates and set R = Z[a

0

, a

1

, . . . , a

d

].

Let K be the quotient field of R. For a univariate polynomial P and a non-negative integer k we will denote by P

[k]

the kth iteration of P , with the convention that P

[0]

is the identity polynomial P

[0]

(x) = x. We now let P ∈ R[x] be the polynomial

P (x) = X

d j=0

a

j

x

j

.

The sequence {P

[0]

, P

[1]

, P

[2]

, . . .} in R[x] is concordant. Proposition 2.1

(9)

implies that, for non-negative integers n, m with m ≥ n, the quotient Q

n,m

=

n−1

Y

k=0

(P

[m]

− P

[k]

)

(P

[n]

− P

[k]

) ∈ K(x)

is in fact in R[x]. Thus for X = X

P,x0

we have φ

X,n

(m) = Q

m,n

(x

0

).

3. Diffuse sequences and granularity. We will call a sequence X of complex numbers semidiffuse if

n→∞

lim |x

n

| = ∞, lim inf

n→∞

|x

n+1

|

|x

n

| > 1, lim inf

n→∞

|x

n+1

|

n+1

|x

n−1

|

n−1

|x

n

|

2n

> 1.

Suppose that U : Z → Z. If x

0

∈ Z then we can form the sequence of iterates of x

0

under U :

X

U,x0

= {x

0

, x

1

, . . . | x

0

∈ Z, x

i+1

= U (x

i

), i = 0, 1, . . .}.

Proposition 3.1. Suppose that U : Z → Z satisfies lim inf

|n|→∞

|U (n)|

n

2

> 0.

Suppose that X

U,x0

is proper. Then X

U,x0

is diffuse.

P r o o f. Write X = X

U,x0

= {x

0

, x

1

, . . .}. Under our hypotheses there exist positive constants C, c such that

|U (n)|/|n| ≥ c|n|

for all |n| > C. We may assume c < 1. Now |x

n

| → ∞ as n → ∞ because X is proper, hence

|x

n+1

|/|x

n

| = |U (x

n

)|/|x

n

| ≥ c|x

n

| ≥ 3/c

for all sufficiently large n, so that |x

n

| ≥ (2/c)

n

for all sufficiently large n.

Therefore, for sufficiently large n,

|x

n+1

|

n+1

|x

n

|

2n

= |U (x

n

)|

n+1

|x

n

|

2n

≥ c

n+1

|x

n

|

2

≥ 2

2n

→ ∞ as n → ∞. This completes the proof.

Corollary 3.2. Let P be a polynomial of degree 2 or greater and x

0

∈ Z.

Suppose that X

P,x0

is proper. Then X

P,x0

is diffuse.

Our interest in the application of Proposition 3.1 is confined to the case

where U is a pseudopolynomial. Hall [10] gives a description of the ring

of pseudopolynomials and proves that any pseudopolynomial U satisfying

U (n) = O(θ

n

) for some θ < e − 1 is a polynomial. This result, also found

by Ruzsa and Perelli–Zannier, has been variously improved (see [13]). This

suggests the following question. Suppose U is a pseudopolynomial that is

not a polynomial, and that X

U,x0

is proper. Is X

U,x0

diffuse?

(10)

Ford [7] has given a neat argument to show that if X is a proper concor- dant sequence that is not an arithmetic progression then lim

n→∞

|x

n+1

|/|x

n

| is an integer ≥ 2, or ∞. This raises the question of whether such a sequence is always semidiffuse.

For sequences generated by linear polynomials with non-unit slope we get the following.

Proposition 3.3. Let P ∈ Z[x] be of the form P (x) = ax+h with |a| ≥ 2 and x

0

∈ Z. Suppose that X

P,x0

is proper. Then X

P,x0

is semidiffuse.

P r o o f. Write X = X

P,x0

= {x

0

, x

1

, . . .}. For a 6= 1 one has x

n

= h

1 − a +



x

0

h 1 − a

 a

n

.

Thus, with |a| ≥ 2, we see that X is proper if and only if x

0

1−ah

 6= 0.

The semidiffusity follows from

n→∞

lim

|x

n+1

|

n+1

|x

n−1

|

n−1

|x

n

|

2n

= lim

n→∞

|a

n+1

|

n+1

|a

n−1

|

n−1

|a

n

|

2n

= a

2

> 1.

Lemma 3.4. Let X be a diffuse sequence of complex numbers. Then

n→∞

lim

n−1

Y

k=0



1 + |x

k

|

|x

n

|



= 1, lim

n→∞

n−1

Y

k=0



1 − |x

k

|

|x

n

|



= 1.

P r o o f. Let ε > 0. We will show that there is a non-negative integer N = N

ε

such that

n−1

Y

k=0



1 + |x

k

|

|x

n

|



≤ 1 + ε for all n ≥ N . Choose Q > 1 such that

exp

 1

Q − 1



1 + ε.

Since X is diffuse we have lim

n→∞

|x

n+1

|/|x

n

| = ∞ and we may choose a non-negative integer M such that |x

n+1

| ≥ Q|x

n

| for n ≥ M . Next choose a positive integer N such that, for all n ≥ N , we have

M −1

Y

k=0



1 + |x

k

|

|x

n

|



1 + ε.

Let now n ≥ N . For positive x we have log(1 + x) < x. Hence

n−1

Y

k=0



1 + |x

k

|

|x

n

|





M −1

Y

k=0



1 + |x

k

|

|x

n

|



exp



n−1

X

k=M

|x

k

|

|x

n

|



.

(11)

The first factor on the right is less than

1 + ε since n ≥ N . For the second factor we get

exp



n−1

X

k=M

|x

k

|

|x

n

|



≤ exp

 X

j=1

1 Q

j



= exp

 1

Q − 1



1 + ε, giving the required estimate.

A similar computation establishes that

n−1

Y

k=0



1 − |x

k

|

|x

n

|



≥ 1 − ε

for all sufficiently large n since, for sufficiently small positive x, we have log(1 − x) ≥ −2x.

Lemma 3.5. Let X = {x

0

, x

1

, . . .} be a semidiffuse sequence of complex numbers. Then

lim sup

n→∞

n−1

Y

k=0



1 + |x

k

|

|x

n

|



< ∞, lim inf

n→∞

n−1

Y

k=0



1 − |x

k

|

|x

n

|



> 0.

P r o o f. Since X is semidiffuse we may choose an integer M and a con- stant λ > 1 such that |x

n+1

|/|x

n

| ≥ λ for all n ≥ M . Choose N such that

Y

M k=0



1 + |x

k

|

|x

n

|



≤ 2 for all n ≥ N . For such n we have

n−1

Y

k=0



1 + |x

k

|

|x

n

|



Y

M k=0



1 + |x

k

|

|x

n

|



n−1

Y

k=M



1 + |x

k

|

|x

n

|



≤ 2 exp

 X

j=1

λ

−j



≤ 2 exp

 1

λ − 1

 .

A similar computation establishes the non-zero lower bound for the lim inf and completes the proof.

Let X be a sequence of complex numbers. For each non-negative integer n we set

r

n

= r

n

(X) = max{|x

0

|, |x

1

|, . . . , |x

n

|}.

If X is semidiffuse then, for all sufficiently large n, we have r

n

= |x

n

| and

|x

n

| < |x

n+1

|.

Proof of Proposition 1.4. We prove that T

X

is entire under the weaker

assumption that X is semidiffuse. Let U be a positive number. Suppose

(12)

z ∈ C with |z| ≤ U . Choose an integer M , a positive constant C and a constant λ > 1 such that for all n ≥ M the following inequalities hold:

r

n

= |x

n

|, |x

n+1

|

|x

n

| + U ≥ λ, Y

n k=0



1 − |x

k

|

|x

n

|



1 C . For n ≥ M we then have

X,n

(z)| ≤ C|z − x

0

| · |z − x

1

| . . . |z − x

n−1

|

|x

n

|

n

C

λ

n

.

So the series converges uniformly for |z| ≤ U , and hence determines an entire function in the disc of radius U (see for example [19, §2.8]). Since U was taken arbitrarily, this proves the proposition.

Let X be a parade and suppose that the envelope function T

X

is an entire function. Informally, the notion of granularity for X, defined below, registers the property that for large n there is a radius r > x

n

at which φ

X,n

represents essentially all the mass of T

X

. The precise formulation is tailored to the employment of this notion in the proofs of our main theorems in the next section. For an entire function f we let m(f, r) denote the minimum of |f (z)| for |z| = r. We will say that X is granular if

n→∞

lim inf

r≥rn

r r − r

n

· M (T

X

, r) m(φ

X,n

, r) = 1.

We will say that X is semigranular if

r≥r

inf

n

r r − r

n

· M (T

X

, r) m(φ

X,n

, r) has an upper bound independent of n.

Proposition 3.6. Let X be a diffuse parade. Then T

X

is granular.

P r o o f. Write X = {x

0

, x

1

, . . .}. Since X is diffuse we may, by Lemma 3.4, choose a non-negative integer M such that, for k ≥ M , we have r

k

= |x

k

| and

k−1

Y

j=0



1 + |x

j

|

|x

k

|



≤ 2,

k−1

Y

j=0



1 − |x

j

|

|x

k

|



1 2 .

For each integer n we set S = S

n

= r

nn

and choose N = N

n

such that r

N

≤ S ≤ r

N +1

. We also set

q = q

n

= max

k≥n

|x

k

|

2k

|x

k+1

|

k+1

, h = h

n

= max

k≥n

|x

k

|

|x

k+1

| .

It follows from the diffusity that lim

n→∞

q

n

= lim

n→∞

h

n

= 0.

(13)

We will show that

n→∞

lim S

S − r

n

· M (T

X

, S) m(φ

X,n

, S) = 1.

That S/(S − r

n

) → 1 as n → ∞ is clear; we prove the same for the second factor.

We have

1 ≤ M (φ

X,n

, S) m(φ

X,n

, S)

Q

n−1

k=0

(1 + |x

k

|/|x

n

|) Q

n−1

k=0

(1 − |x

k

|/|x

n

|) . It follows by Lemma 3.3 that

n→∞

lim

M (φ

X,n

, S) m(φ

X,n

, S) = 1.

We set

T

n

= T

X,n

= T

X

− φ

X,n

. To establish the proposition it suffices to prove that

n→∞

lim

M (T

n

, S

n

) m(φ

X,n

, S

n

) = 0.

We have

M (T

n

, S) ≤

n−1

X

k=0

M (φ

X,k

, S) + X

k=n+1

M (φ

X,k

, S).

We split the sums on the right hand side into six sums Σ

1

, Σ

2

, . . . , Σ

6

with the following ranges:

k ≤ M − 1, M ≤ k ≤ n − 2, k = n − 1, n + 1 ≤ k ≤ N,

k = N + 1 and k ≥ N + 2.

For any positive r and non-negative integer n we have, since the differ- ences |x

i

− x

j

| are all integers,

M (φ

X,k

, r) ≤ (r + |x

0

|)(r + |x

1

|) . . . (r + |x

k−1

|)

|x

k

− x

0

| · |x

k

− x

1

| . . . |x

k

− x

k−1

| ≤ (2 max{r, r

k−1

})

k

. However, this estimate may be improved in various circumstances. If k ≥ M then, by our assumption on M , we can improve this estimate by observing that

|x

k

− x

0

| · |x

k

− x

1

| . . . |x

k

− x

k−1

| ≥

12

|x

k

|

k

, while if k ≥ M and r ≥ |x

k

| then

(r + |x

0

|)(r + |x

1

|) . . . (r + |x

k−1

|) ≤ 2r

k

.

(14)

The first range is estimated crudely by Σ

1

=

M −1

X

k=0

M (φ

X,k

, S) ≤ M (2S)

M −1

. In the second range, where M ≤ k ≤ n − 2, we have

Σ

2

=

n−2

X

k=M

M (φ

X,k

, S) ≤

n−2

X

k=M

2S

k

≤ 2nS

n−2

. In the third range k = n − 1 so that

Σ

3

= M (φ

X,n−1

, S) ≤ 4S

n−1

/r

n−1n−1

.

To estimate the sum over the fourth range n + 1 ≤ k ≤ N , we observe that, for j non-negative,

S

r

n+j+1n+j+1

= (r

n+jn+j

)

2

r

n+j+1n+j+1

 S r

n+jn+j



2

1 S ≤ q

 S r

n+jn+j



2

. Since S/r

n+1n+1

≤ q it follows that S/r

n+jn+j

≤ q

2j−1

. Thus

S

n+j+1

r

n+j+1n+j+1

· r

n+jn+j

S

n+j

= (r

n+jn+j

)

2

r

n+j+1n+j+1

· S

r

n+jn+j

≤ qq

2j−1

≤ q

2j

. Hence

Σ

4

= X

N k=n+1

M (φ

X,k

, S) ≤ 4 X

j=0

S

n+j+1

r

n+j+1n+j+1

≤ 4 S

n

r

nn

X

j=0

q

2j+1−1

4q 1 − q · S

n

r

nn

. The fifth range is estimated by observing that

(S + |x

0

|)(S + |x

1

|) . . . (S + |x

N −1

|)(S + |x

N

|) ≤ 2S

N

2S while

|x

N +1

− x

0

| . . . |x

N +1

− x

N

| ≥

12

r

N +1N +1

12

S

N +1

. Therefore

Σ

5

= M (φ

X,N +1

, S) ≤ 8.

In the last range we have k ≥ N + 2 so that S ≤ r

k−1

. We have Y

k=N +2

 1 + S

|x

k

|



≤ exp

 X

j=1

h

j



≤ exp

 h

1 − h

 . Therefore

(S + |x

0

|) . . . (S + |x

N

|)(S + |x

N +1

|)(S + |x

N +2

|) . . . (S + |x

k−1

|)

≤ 2 exp

 h

1 − h



S

N +1

(2|x

N +1

|)|x

N +2

| · |x

N +3

| . . . |x

k−1

|,

(15)

and so

M (φ

X,k

, S) ≤ 8 exp

 h

1 − h

 S

N +1

|x

N +1

|r

N +2

. . . r

k−1

r

kk

≤ 8h

k

exp

 h

1 − h

 . Thus

Σ

6

= X

k=N +2

M (φ

X,k

, S) ≤ 8 exp

 h

1 − h

 X

k=n+2

h

k

8h 1 − h exp

 h

1 − h

 . Now

m(φ

X,n

, S) ≥ (r

n+1

− |x

0

|)(r

n+1

− |x

1

|) . . . (r

n+1

− |x

n−1

|)

|x

n

− x

0

| · |x

n

− x

1

| . . . |x

n

− x

n−1

|

S

n

4r

nn

= S

n−1

4 .

Since X is diffuse we have q

n

, h

n

→ 0 as n → ∞. We have also S = r

nn

≥ 2

n

for all sufficiently large n. Therefore the sums Σ

1

, Σ

2

, Σ

3

, Σ

4

, Σ

5

, Σ

6

are all o(S

n−1

) as n → ∞.

Remark 3.7. Under the conditions of Proposition 3.6 we have M (T

X

, r

nn

)/r

nn2−n

→ 1 as n → ∞.

For a sequence X of complex numbers we define R

n

(X) =

s

r

n+1n+1

(X) r

n−1n−1

(X) .

Proposition 3.8. Let X be a semidiffuse parade. Then T

X

is semigran- ular.

P r o o f. We set R

n

= R

n

(X) and establish an upper bound independent of n for

R

n

R

n

− r

n

· M (T

X

, R

n

) m(φ

X,n

, R

n

) .

Such a bound obtains for the first factor by the semidiffusity of X. Indeed as n → ∞ we have

r

n

R

n

= r

n

r

n−1n−1

q

r

n+1n+1

r

n−1n−1

=

 r

n−1

r

n



n−1

r

nn

q

r

n+1n+1

r

n−1n−1

→ 0.

By Lemma 3.5 there is a non-negative integer M and a positive constant C such that, for all n ≥ M , we have

n−1

Y

k=0



1 + |x

k

|

|x

n

|



< C,

n−1

Y

k=0



1 − |x

k

|

|x

n

|



> 1

C .

(16)

By the semidiffusity we can assume that there are constants λ > 1 and δ > 1 such that (increasing M if necessary)

|x

n+1

|

|x

n

| ≥ λ, |x

n+1

|

n+1

|x

n−1

|

n−1

|x

n

|

2n

≥ δ

also hold for all n ≥ M , and further that r

n

= |x

n

| for all n ≥ M . Thus for n ≥ M we have

m(φ

X,n

, R

n

) ≥ C

2

R

nn

/r

nn

. Now suppose that n is so large that

δ

(n−M −1)(n−M −2)/2

≥ M (2r

M

)

M

. We begin with the estimate

M (T

X

, R

n

) ≤ X

k=0

M (φ

X,k

, R

n

)

and split the sum on the right into three sums over the ranges k ≤ M − 1, M ≤ k ≤ n, k > n.

To estimate the sum over the range k > n we note that, for j non- negative,

R

n

r

n+jn+j

r

n+j+1n+j+1

= r

2(n+j)n+j

r

n+j+1n+j+1

r

n+j−1n+j−1

· R

n

r

n+j−1n+j−1

r

n+jn+j

≤ δ

−1

R

n

r

n+j−1n+j−1

r

n+jn+j

≤ . . . ≤ δ

−j

R

n

r

nn

r

n+1n+1

≤ δ

−j

. Therefore

R

n+j+1n

r

n+j+1n+j+1

· r

nn

R

nn

≤ δ

−j(j−1)/2

, so that

X

k=n+1

M (φ

X,k

, R

n

) ≤ R

nn

r

nn

X

j=1

δ

−j(j−1)/2

R

nn

r

nn

· δ

δ − 1 .

For the sum over the second range we proceed similarly, noting that for non-negative j with n − j ≥ M we have

r

n−jn−j

R

n

r

n−j−1n−j−1

= r

2(n−j)n−j

r

n−j−1n−j−1

r

n−j+1n−j+1

· r

n−j+1n−j+1

R

n

r

n−jn−j

≤ δ

−1

r

n−j+1n−j+1

R

n

r

n−jn−j

≤ . . . ≤ δ

−j

R

n

r

nn

r

n−1n−1

≤ δ

−j

,

(17)

so that

R

n−j−1n

r

n−j−1n−j−1

· r

nn

R

nn

≤ δ

−j(j−1)/2

, yielding

n−1

X

k=M

M (φ

X,k

, R

n

) ≤ R

nn

r

nn

X

j=1

δ

−j(j−1)/2

R

nn

r

nn

· δ

δ − 1 . For the range k ≤ M − 1 we have

M −1

X

k=0

M (φ

X,k

, R

n

) ≤ M (2R

n

)

M

. From the discussion of the second range it follows that

R

Mn

r

MM

· r

nn

R

nn

≤ δ

−(n−M −1)(n−M −2)/2

. Hence P

M −1

k=0

M (φ

X,k

, R

n

)

m(φ

X,n

, R

n

) ≤ C

2

M (2r

M

)

M

δ

(n−M −1)(n−M −2)/2

≤ C

2

. Thus

M (T

X

, R

n

) m(φ

X,n

, R

n

) ≤ C

2



1 + δ − 1



and this completes the proof.

Corollary 3.9. Let X be a semidiffuse parade. Then M (T

X

, R

n

)r

nn

/R

nn

is bounded independently of n.

P r o o f. This follows from the proof of Proposition 3.8.

4. Proof of Theorem 1.2. In this section we prove Theorem 1.2. In fact we prove the following.

Theorem 4.1. Let X be a parade with T

X

entire. Suppose that T

X

is granular. Let f be an entire function that takes integral values on X and satisfies

lim sup

r→∞

M (f, r) M (T

X

, r) < 1.

Then f is a polynomial.

We also prove the following version that, in view of Proposition 3.3,

applies to semidiffuse parades. However, we do not know of any examples

of parades that are semidiffuse but not diffuse that are essentially different

from the case treated by Gel’fond; that is, sequences generated by iteration

of a linear polynomial with non-unit slope.

(18)

Theorem 4.2. Let X be a parade with T

X

entire. Suppose that T

X

is semigranular. Let f be an entire function that takes integral values on X and satisfies

lim sup

r→∞

M (f, r) M (T

X

, r) = 0.

Then f is a polynomial.

Suppose that f is an entire X-integral function in the hypothesis of Theorem 4.1 or 4.2. The strategy of the proof of Theorems 4.1 and 4.2, following the strategies of P´olya [15, 16], is as follows. First, construct a polynomial Q that takes the same values as f on X. Second, prove that f and Q are identically equal. The approach used by Gel’fond [8, 9] and B´ezivin [1, 2] is slightly different. They show that f can be represented by an interpolation series with respect to X, and then show that this series terminates after finitely many terms so that it is a polynomial.

We begin with four propositions. The first three evaluate the coefficients that will be used to construct Q out of the polynomials φ

X,n

. The fourth gives the requisite uniqueness of interpolation and is analogous to a Hilfssatz [15, §4] of P´olya.

We denote by V (x

0

, . . . , x

n

) the Vandermonde determinant on x

0

, . . . . . . , x

n

. If X = {x

0

, x

1

, . . .} is a sequence of complex numbers containing at least n + 1 elements we set V

n

(X) = V (x

0

, x

1

, . . . , x

n

).

Proposition 4.3. Let {x

0

, x

1

, . . . , x

n

} ⊂ C be a set of distinct points and let ψ

j

, j = 0, 1, . . . , n, and f be functions defined on {x

0

, x

1

, . . . , x

n

}.

Suppose that ψ

j

(x

j

) = 1, j = 0, 1, . . . , n, and ψ

j

(x

i

) = 0 whenever i < j.

For m = 0, 1, . . . , n set

c

m

= det

 

ψ

0

(x

0

) ψ

1

(x

0

) . . . ψ

m−1

(x

0

) f (x

0

)

.. . .. . .. . .. .

ψ

0

(x

m

) ψ

1

(x

m

) . . . ψ

m−1

(x

m

) f (x

m

)

 .

Then

f (x

k

) = X

n j=0

c

j

ψ

j

(x

k

), k = 0, 1, . . . , n.

P r o o f. The proof is by induction: for n = 0, the conclusion holds be- cause c

0

= f (x

0

) and ψ

0

(x

0

) = 1.

Assuming that the conclusion holds for n points, we prove it for n + 1.

Since ψ

n

(x

k

) = 0 for k = 0, . . . , n − 1, the induction hypothesis shows that f (x

k

) =

X

n j=0

c

j

ψ

j

(x

k

), k = 0, 1, . . . , n − 1.

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