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A N N A L E S

U N I V E R S I T A T I S M A R I A E C U R I E - S K Ł O D O W S K A L U B L I N – P O L O N I A

VOL. LXV, NO. 2, 2011 SECTIO A 179–190

JÓZEF SICIAK

Some gap power series in multidimensional setting

Professor Jan Krzyż in memoriam

Abstract. We study extensions of classical theorems on gap power series of a complex variable to the multidimensional case.

1. Power series with Ostrowski gaps. Let (1.1) f (z) =

X

0

Q

j

(z), where Q

j

(z) = X

|α|=j

a

α

z

α

, α ∈ Z

N+

, be a power series in C

N

, i.e. a series of homogeneous polynomials Q

j

of N complex variables of degree j.

The set D given by the formula D := {a ∈ C

N

; the sequence (1.1) is convergent in a neighborhood of a} is called a domain of convergence of (1.1).

It is known that

(1.2) D = {z ∈ C

N

; ψ

(z) < 1}, where

(1.3) ψ(z) := lim sup

j→∞

j

q

|Q

j

(z)|,

and ψ

denotes the upper semicontinuous regularization of ψ.

2000 Mathematics Subject Classification. 30B10, 30B30, 30B40, 32A05, 32A07, 32A10, 32D15.

Key words and phrases. Plurisubharmonic functions, negligible sets in CN, power se- ries, lacunary power series, multiple power series.

(2)

If ψ

is finite, then it is plurisubharmonic and absolutely homogeneous (i.e. ψ

(λz) = |λ|ψ

(z), λ ∈ C, z ∈ C

N

). Therefore, the domain of con- vergence D is either empty, or it is a balanced (i.e. λz ∈ D for all λ ∈ C with |λ| ≤ 1 and z ∈ D) domain of holomorphy. Every balanced domain of holomorphy is a domain of convergence of a series (1.1).

For every balanced domain D in C

N

there is a unique nonnegative func- tion h (so-called Minkowski functional of D) such that h(λz) = |λ|h(z) for all λ ∈ C and z ∈ C

N

, and D = {z ∈ C

N

; h(z) < 1}. In particular, if D is a domain of convergence of (1.1), then h(z) ≡ ψ

(z).

It is known that a balanced domain in C

N

is a domain of holomorphy if and only if its Minkowski functional h is an absolutely homogeneous plurisubharmonic function.

The number

(1.4) ρ := 1/ lim sup

j→∞

j

q kQ

j

k

B

,

where B := {z ∈ C

N

; kzk ≤ 1}, is called a radius of convergence of series (1.1) (with respect to a given norm k · k).

If N = 1, then ψ(z) =

|z|ρ

and D = ρB. If N ≥ 2, then ρB ⊂ D but, in general, D 6= ρB.

Series (1.1) is normally geometrically convergent in D, i.e.

(1.5) lim sup

j→∞

j

q

kQ

j

k

K

< 1, lim sup

n→∞

pkf − s

n n

k

K

< 1,

for all compact sets K ⊂ D, where s

n

:= Q

o

+ · · · + Q

n

is the nth partial sum of (1.1).

Definition 1.1. We say that a function f holomorphic in a neighborhood of a point z

o

∈ C

N

possesses at the point z

o

Ostrowski’s gaps (m

k

, n

k

], if

1

o

. m

k

, n

k

are natural numbers such that m

k

< n

k

< m

k+1

(k ≥ 1),

nk

mk

→ ∞ as k → ∞;

2

o

. lim

j→∞, j∈I

pkQ

j j

k

B

= 0, where B is the unit ball in C

N

, Q

j

(z) ≡ Q

(f,zj o)

(z) := X

|α|=j

f

(α)

(z

o

)

α! z

α

= 1 j!

 d dλ



j

f (z

o

+ λz)

|λ=0

, and I := S

k=1

(m

k

, n

k

], (m

k

, n

k

] denoting the set of integers j with m

k

<

j ≤ n

k

.

Observe that f

o

(z) := P

j∈I

Q

j

(z − z

o

) is an entire function such that

the function g := f − f

o

possesses Ostrowski’s gaps (m

k

, n

k

] at z

o

with

Q

(g,zj o)

= 0 for m

k

< j ≤ n

k

, k ≥ 1. Hence, a holomorphic function f

possesses Ostrowski’s gaps (m

k

, n

k

] at a point z

o

if and only if there exists

an entire function f

o

such that Q

(f −fj o,zo)

= 0 for m

k

< j ≤ n

k

, k ≥ 1.

(3)

Moreover, the maximal domain of existence G = G

f

of f is identical with the maximal domain of existence of f − f

o

.

Definition 1.2. We say that a function f holomorphic in a neighborhood of a point z

o

possesses Ostrowski’s gaps relative to a sequence of positive integers {n

k

}, if {n

k

} is increasing and there exists a sequence of positive real numbers {q

k

} such that q

k

→ 0 as k → ∞ and lim

j→∞,j∈I

pkQ

j j

k

B

= 0, where I := S

k=1

(bq

k

n

k

c, n

k

].

A function f possesses Ostrowski’s gaps according to Definition 1.1 if and only if f possesses Ostrowski’s gaps according to Definition 1.2.

Indeed, if the conditions of Definition 1.1 are satisfied, then it is sufficient to put q

k

:= m

k

/n

k

.

If the conditions of Definition 1.2 are satisfied, consider two cases. If m := lim inf

k→∞

q

k

n

k

is finite, then the function f is entire, so that f has Ostrowski’s gaps (m

k

, n

k

] according to Definition 1 for any sequence m

k

, n

k

satisfying 1

o

.

If lim inf

k→∞

q

k

n

k

= ∞, then f possesses Ostrowski’s gaps (bq

kl

n

kl

c, n

kl

] for a suitable chosen increasing subsequence k

l

of positive integers.

We say that a compact subset K of C

N

is polynomially convex if K is identical with its polynomially convex hull K := {a ∈ C ˆ

N

; |P (a)| ≤ kP k

K

for every polynomial P of N complex variables}. We say that an open set Ω in C

N

is polynomially convex, if for every compact subset K of Ω the polynomially convex hull ˆ K of K is contained in Ω.

The following theorem is known (see [7]). It is a multidimensional version of the classical Ostrowski’s Theorem (see Theorem 3.1.1 in [1]).

Theorem 1. If a holomorphic function f possesses Ostrowski’s gaps (m

k

, n

k

] at a point z

o

∈ C

N

, then the maximal domain of existence G = G

f

of f is one-sheeted and polynomially convex. Moreover, for every compact subset K of G we have

(1.6) lim sup

k→∞

kf − s

nk

k

K1/nk

< 1, where

s

n

(z) ≡ s

(f,zn o)

(z) =

n

X

j=0

Q

(f,zj o)

(z − z

o

)

is the nth partial sum of the Taylor series development of f around z

o

. Corollary 1.1. If

f (z

o

+ z) =

X

k=1

Q

(f,zm o)

k

(z),

where m

k

/m

k+1

→ 0 as k → ∞, then Q

(f,zj o)

= 0 for j / ∈ {m

k

} so that f

has Ostrowski’s gaps (m

k

, n

k

] with n

k

:= m

k+1

− 1. Therefore, the maximal

(4)

domain of existence G

f

of f is identical with the domain of convergence D

f

of the Taylor series development of f around z

o

, i.e.

G

f

= D

f

:= z ∈ C

N

: ψ

(z − z

o

) < 1 , where ψ(z) := lim sup

k→∞ mk

q

|Q

(f,zmko)

(z)|.

The following result gives an N -dimensional version of W. Luh’s Theo- rem 1 in [4]. In particular, it says that if a function f holomorphic in a domain G in C

N

possesses Ostrowski’s gaps at some point z

o

∈ G, then f possesses the same property at every other point a of the maximal domain of existence of f .

Theorem 2. Let f possess Ostrowski’s gaps (m

k

, n

k

] at a point z

o

∈ C

N

. Then

1

o

. f possesses Ostrowski’s gaps 

m

kl

, l

n

kl

l

mi

at every point a ∈ G

f

, where the sequence of natural numbers {k

l

} (independent of a) is chosen in such a way that n

kl

≥ m

kl

l

2

and l

n

kl

l

m

< m

kl+1

for l ≥ 1;

2

o

. If Q

(f,zj o)

= 0 for m

k

< j ≤ n

k

, k ≥ 1

1

, then the sequence n

s

(f,zmko)

− s

(f,a)mk

o

converges to zero normally with order n

k

on C

N

, i.e.

lim sup

k→∞

s

(f,zm o)

k

− s

(f,a)m

k

1/nk

K

< 1 for every compact set K ⊂ C

N

.

By 2

o

and Theorem 1 we get the following:

Corollary 1.2. If f possesses ordinary Ostrowski’s gaps (m

k

, n

k

] at a fixed point z

o

∈ G, then

lim sup

k→∞

nk

r

f − s

(f,a)mk

K

< 1 for every point a ∈ G

f

and every compact subset K of G

f

.

Proof of Theorem 2. 1

o

. Without loss of generality we may assume that z

o

= 0 and

Q

(f,zj o)

= 0, m

k

< j ≤ n

k

, k ≥ 1.

Given a fixed point a ∈ G

f

, we have Q

(f,a)j

(z) = 1

2πi Z

|λ|=r

f (a + λz) − s

nk

(a + λz)

λ

j+1

dλ,

1In such a case we say that f possesses ordinary Ostrowski’s gaps at zo

(5)

kzk ≤ 1, j > m

k

, k ≥ 1, where s

nk

= s

(f,znk o)

(Observe that s

nk

is a polyno- mial of degree at most m

k

), and 0 < r < min(dist(a, ∂G

f

), dist(z

o

, ∂G

f

)).

By Theorem 1 there exist M > 1 and 0 < θ < 1 such that (1.7) kf − s

nk

k

B(a,r)

≤ M θ

nk

, k ≥ 1.

Therefore, by Cauchy inequalities, (1.8)

Q

(f,a)j

B

≤ M

r

j

θ

nk

, j > m

k

, k ≥ 1.

Let {k

l

} be an increasing sequence of natural numbers such that m

kl+1

> l n

kl

l m

, n

kl

m

kl

≥ l

2

, l ≥ 1.

By (1.8) we get Q

(f,a)j

1/j B

≤ M

r θ

nkl/j

≤ M

l θ

l

, m

kl

< j ≤ l n

kl

l

m

, l ≥ 1.

The choice of the sequence {k

l

} does not depend on a ∈ G

f

. Therefore, f possesses Ostrowski’s gaps



m

kl

, l

n

kl

l

mi

at every point a of G

f

(according to Definition 1.1). The proof of the case 1

o

is ended.

2

o

. Observe that for kz − ak ≤

12

r we have

f (z) − s

(f,a)mk

(z) =

X

mk+1

Q

(f,a)j

(z − a) ≤

X

mk+1

Q

(f,a)j

B

 r 2



j

, which by (1.8) gives

(1.9)

f (z) − s

(f,a)m

k

(z) ≤

X

pk+1

2

−j

M θ

nk

≤ M θ

nk

, k ≥ 1, kz − ak ≤ r 2 . By (1.7) and (1.9) we get

(1.10)

s

(f,zmko)

− s

(f,a)m

k

B(a,12r)

≤ 2M θ

nk

, k ≥ 1.

Observe that for z ∈ C

N

s

(f,zn o)

(z) ≤

n

X

j=0

Q

(f,zj o)

B

kz − z

o

k

j

n

X

0

kf k

B(zo,r)

r

j

kz − z

o

k

j

≤ (n + 1)kf k

B(zo,r)



1 + kzk + kz

o

k r



n

.

Put M := kf k

B(zo,r)∪B(a,r)

and c := max{kz

o

k, kak}. Then for z ∈ C

N

u

k

(z) := 1

n

k

log

s

(f,zmko)

(z) − s

(f,a)mk

(z)

≤ 1 n

k

log[2M (m

k

+ 1)] + m

k

n

k

log



1 + kzk + kck r



.

(6)

It follows that the sequence of plurisubharmonic functions {u

k

} is locally uniformly upper bounded in C

N

, and

u(z) := lim sup

k→∞

u

k

(z) ≤ 0, z ∈ C

n

. Therefore, the plurisubhamonic function u

= const.

By (1.10) u

k

(z) ≤

n1

k

log 2M + log θ for z ∈ B(a, r), k ≥ 1. Hence u

≤ log θ in C

N

which ends the proof of 2

o

.  2. E. Fabry’s Theorem. Now we shall present a multidimensional version of E. Fabry’s Theorem (Theorem 2.2.1 in [1]). Let f be a function of N complex variables holomorphic in a neighborhood of 0 with a gap Taylor series development

(2.1) f (z) =

X

k=1

Q

mk

(z), m

k

< m

k+1

.

Put ψ(z) := lim sup

k→∞ mk

p|Q

mk

(z)|, h(z) := ψ

(z). It is known that D := {z ∈ C

N

; h(z) < 1} = {a ∈ C

N

; series (2.1) is convergent in a neighborhood of a} is a domain of convergence of (2.1).

Theorem 3. If lim

k→∞mk

k

= 0, then the domain of convergence D of the series (2.1) is identical with the maximal domain of existence G

f

of f .

Proof. Without loss of generality we may assume that D 6= C

N

.

Due to Fabry we know that Theorem 3 is true for N = 1. It is also well known (by Bedford–Taylor Theorem on negligible sets) that the set E := {z ∈ C

N

; ψ(z) < ψ

(z)} is pluripolar. Therefore, in particular, the set E is of 2N -dimensional Lebesgue measure zero.

Suppose Theorem 3 is not true for some N > 1. Then there is a function g holomorphic in a ball B(z

o

, R) with z

o

∈ D, R > r := dist(z

o

, ∂D) such that g(z) = f (z) for z ∈ B(z

o

, r).

Let b

o

be a fixed point of ∂D such that kb

o

− z

o

k = r.

Since the ball B(z

o

, r) is non-thin at the point b

o

,we have lim sup

z→bo,z∈B(zo,r)

ψ

(z) = ψ

(b

o

).

Therefore, there is a sequence {z

k0

} ⊂ B(z

o

, r) such that z

k0

→ b

o

, and ψ

(z

k0

) → ψ

(b

o

) as k → ∞. It follows that ψ

(b

o

) ≤ 1. Since b

o

∈ ∂D, we have ψ

(b

o

) ≥ 1. Therefore, ψ

(b

o

) = 1.

We know that the 2N -dimensional Lebesgue measure v

2N

(E) = 0. There- fore, by the sub-mean-value property, for every k ≥ 1 there is a point z

k

∈ B(z

k0

,

1k

) ∩ B(z

o

, r) \ E such that ψ(z

k

) = ψ

(z

k

), |ψ

(z

k0

) − ψ(z

k

)| <

k1

. It is clear that the sequence {z

k

} satisfies the following properties:

z

k

∈ B(z

o

, r), z

k

→ b

o

, ψ(z

k

) = ψ

(z

k

), ψ(z

k

) → ψ

(b

o

).

(7)

Put b

k

= z

k

/ψ(z

k

) (k ≥ 1). Then ψ(b

k

) = ψ

(b

k

) = 1, in particular, b

k

∈ ∂D for k ≥ 1, and b

k

→ b

o

as k → ∞.

Fix k so large that b := b

k

∈ B(z

o

, R). Put G

r

:= {λ ∈ C; λb ∈ B(z

o

, r)}, G

R

:= {λ ∈ C; λb ∈ B(z

o

, R)}.

One can easily check that the sets G

r

, G

R

are open, convex, nonempty (because λ

o

b ∈ G

r

for λ

o

:= ψ(z

k

), and G

r

⊂ G

R

). Moreover, G

r

⊂ ∆ :=

{|λ| < 1}, and 1 ∈ G

R

.

The function f (λb) (resp., g(λb)) is holomorphic in ∆ (resp., in G

R

), and f (λb) = g(λb) for λ ∈ G

r

. Therefore, f (λb) = g(λb) on ∆ ∩ G

R

. It follows that g(λb) is an analytic continuation of f (λb) across λ = 1, contrary to the Fabry Theorem for N = 1. We have got a contradiction showing that

Theorem 3 is true. 

Remark. The present proof of Theorem 3 – with no assumption on the continuity of the function ψ

– is a joint result of the author and Professor Azimbay Sadullaev.

3. Fatou–Hurwitz–Polya Theorem. First we shall state Fatou–Hurwitz –Polya Theorem for a series of homogeneous polynomials of N complex vari- ables.

Theorem 4. Let f be a function holomorphic in a neighborhood of 0 ∈ C

N

. Let

(3.0) f (z) =

X

0

Q

j

(z), Q

j

(z) = X

|α|=j

f

(α)

(0) α! z

α

,

be its Taylor series development around 0. Then there exists a sequence

 = {

j

} with 

j

∈ {−1, 1} (resp., 

j

∈ {0, 1}) such that the function f



(z) :=

X

j=0



j

Q

j

(z), z ∈ D,

has no analytic continuation across any boundary point of the domain of convergence D := {ψ

(z) < 1} of series (3.0), where

ψ(z) := lim sup

j→∞

j

q

|Q

j

(z)|.

For N = 1 this theorem (with 

j

∈ {−1, 1}) is due to Fatou–Hurwitz–

Polya (Theorem 4.2.8 in [1]).

Now, we shall present an N -dimensional version of the Fatou–Hurwitz–

Polya theorem for N -tuple power series

(3.1) f (z) = X

|α|≥0

c

α

z

α

,

(8)

where c

α

z

α

is a monomial of N complex variables z = (z

1

, . . . , z

N

) of degree

|α| := α

1

+ · · · + α

N

. The set D := {a ∈ C

N

; the series (3.1) is absolutely convergent in a neighborhood of a} is called a domain of convergence of the multiple power series (3.1).

It is known that D = {z ∈ C

N

; h(z) < 1} is a complete N -circular (hence, in particular, D is balanced) domain whose Minkowski’s functional h ≡ h

D

is given by the formula h(z) = M

(z), where

(3.2)

M (z) := lim sup

|α|→∞

|α|

p|c

α

z

α

|

= lim sup

k→∞

max

n

|α|

p|c

α

z

α

|; |α| = k o

, z ∈ C

N

.

Moreover, h(z

1

, . . . , z

N

) = h(|z

1

|, . . . , |z

N

|) for all z ∈ C

N

, and h is contin- uous (see [2], Lemma 1.7.1 (b)).

Theorem 5. If the domain of convergence D of (3.1) is not empty, then there exists a multiple sequence  = {

α

} with 

α

∈ {−1, 1} (resp., with



α

∈ {0, 1}) such that the function f



(z) := X

|α|≥0



α

c

α

z

α

, z ∈ D,

has no analytic continuation across any boundary point of D.

We shall see that Theorems 4 and 5 are direct consequences of the fol- lowing Lemma 3.2.

Let X := {0, 1}

N

(resp. {−1, 1}

N

) be the space of all sequences x = (x

1

, x

2

, . . . ) where x

j

= 0, or x

j

= 1 (resp. x

j

= −1, or x

j

= 1) for j = 1, 2, . . . . Endow X in the topology determined by the metric

ρ(x, y) :=

X

j=1

1 2

j

|x − y|

j

1 + |x − y|

j

, where

|x − y|

j

:= max{|x

k

− y

k

|; k = 1, . . . , j}.

One can easily check that X is a complete metric space, and therefore, it has Baire property.

Moreover, in the topology a sequence {x(n)} of elements of X converges to an element x ∈ X if and only if for every k

o

∈ N there exists n

o

∈ N such that x

k

(n) = x

k

for k = 1, . . . , k

o

, n ≥ n

o

.

Remark 3.1. Let {f

k

} be a sequence of holomorphic functions in an open subset Ω of C

n

. Then the following three conditions are equivalent:

(1) the series P

1

|f

k

(z)| converges at each point z ∈ Ω, and its sum ϕ(z) := P

1

|f

k

(z)| is locally bounded on Ω;

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(2) the series P

1

f

k

converges locally normally in Ω, i.e. for every point a of Ω there exists a neighborhood U of a such that the series P

1

kf

k

k

U

is convergent;

(3) the series P

1

|f

k

| converges locally uniformly in Ω.

Proof. It is clear that (2) ⇒ (3) ⇒ (1).

Suppose now (1) is true, and let E(a, r) := {z ∈ C

n

; |z

j

− a

j

| < r (j = 1, . . . , n)} be a polydisk whose closure is contained in Ω. Then there is a positive constant M such that P

1

|f

k

(z)| ≤ M for all z ∈ E(a, r). By the Cauchy integral formula

|f

k

(z)| ≤ µ

k

:=  1 πr



n

Z

0

. . . Z

0

|f

k

(a

1

+ re

it1

, . . . , a

n

+ re

itn

)|dt

1

. . . dt

n

, for all z ∈ E(a,

r2

) and k ≥ 1.

By Lebesgue monotonous convergence theorem the series P

1

µ

k

is con- vergent, and so is the series P

1

kf

k

k

U

with U := E(a,

r2

).  We shall see that our extensions of the classical Fatou–Hurwitz–Polya Theorem (Theorem 4.2.8 in [1]) are a direct consequence of the following Lemma 3.2 (slight modification of Lemma 5, p. 97 in [5]).

Lemma 3.2. Let X denote any of the two metric spaces {0, 1}

N

or {−1, 1}

N

. Let {f

k

} be a sequence of holomorphic functions in an open neighborhood Ω of the closure of a ball B = B(w, r) such that the series P

1

|f

k

(z)|

converges at every point z ∈ B. Let a be a boundary point of B.

Then, either the series P

1

f

k

is normally convergent on a neighborhood of a, or there exists a subset R of X of the first category such that for every x ∈ X \ R the function f

x

(z) := P

k

x

k

f

k

(z), z ∈ B, has a singular point at a (in other words, f

x

cannot be analytically continued to any neighborhood of a).

Proof. Given a natural number m, let R

m

denote the set of all x ∈ X such that there exists a holomorphic function ˜ f

x

on E

m

(where E

m

is the polydisk E

m

:= E a,

m1

 with center a and radius

m1

) such that | ˜ f

x

(z)| ≤ m on the polydisk, and ˜ f

x

(z) = f

x

(z) for all z ∈ B ∩ E

m

. By definition, we put R

m

= ∅, if m < 1/ dist(a, ∂Ω).

It is clear that the set R := S

1

R

m

≡ {x ∈ X ; f

x

has an analytic continuation across a}.

The lemma will be proved if we show that the following two claims are true.

Claim 1. The set R

m

is closed in the space X .

Claim 2. If the interior of R

m

is not empty, then the series P

1

f

k

is

normally convergent on a neighborhood of a.

(10)

Indeed, if the series f

x

:= P

1

x

k

f

k

converges normally on no neighbor- hood U of a, then for every m ≥ 1 the set R

m

is closed and has empty interior. Hence, the set R := S

1

R

m

≡ {x ∈ X ; f

x

has an analytic con- tinuation ˜ f

x

across a} is of the first category, and for every x ∈ X \ R the function f

x

has a singular point at a, i.e. f

x

has no analytic continuation across a. We say that a function ˜ f

x

holomorphic on a polydisk E with center a is an analytic continuation of f

x

across a, if ˜ f

x

(z) = f

x

(z) on B ∩ E.

Proof of Claim 1. Let {x(j)} be a sequence of elements of R

m

convergent to x ∈ X . Let {h

j

} ≡ { ˜ f

x(j)

} be a sequence of holomorphic functions on E

m

such that |h

j

(z)| ≤ m on E

m

and h

j

(z) = f

x(j)

(z) on the intersection B ∩ E

m

for j ≥ 1 . Observe that for every k

o

there exists j

o

such that

|f

x(j)

(z) − f

x

(z)| ≤ P

k>ko

2|f

k

(z)| for all z ∈ B ∩ E

m

and for all j > j

o

. It follows that the sequence {h

j

} is convergent at each point of B ∩ E

m

. By Vitali’s theorem the sequence {h

j

} is locally uniformly convergent on E

m

to a holomorphic function h bounded by m and identical with f

x

on E

m

∩ B, which shows that x ∈ R

m

.

Proof of Claim 2. If R

m

has a nonempty interior, then there exist x(0) = (x

1

(0), x

2

(0), . . . ) ∈ R

m

and a natural number k

o

such that

(*) x ∈ X , x

j

= x

j

(0) (j = 1, . . . , k

o

) =⇒ x ∈ R

m

. Put

M := sup (

k0

X

k=1

|f

k

(z)|; z ∈ E

m

)

, u

k

:= <f

k

, v

k

:= =f

k

.

By implication (2) ⇒ (3) of Remark 3.1 it is sufficient to show that (**)

X

k=1

|f

k

(z)| ≤ M + 4m, z ∈ E

m

.

Let A be a finite subset of N \ [1, k

0

]. Given a fixed point z of E

m

, put A

1

:= {k ∈ A; u

k

(z) ≥ 0}, A

2

:= {k ∈ A; u

k

(z) < 0}.

It is clear that A = A

1

∪ A

2

, A

1

∩ A

2

= ∅. Consider two cases.

Case 1: X = {0, 1}

N

. Let x(j) = (x

1

(j), x

2

(j), . . . ) (j = 1, 2) be two points of the interior of R

m

defined by the formulas:

x

k

(j) = x

k

(0), k = 1, . . . , k

0

, j = 1, 2;

x

k

(j) = x

k

(0), k > k

0

, k / ∈ A, j = 1, 2;

x

k

(1) = 1, x

k

(2) = 0, k ∈ A

1

;

x

k

(1) = 0, x

k

(2) = 1, k ∈ A

2

.

(11)

Then X

k∈A

|u

k

(z)| ≤

X

k∈A

(x

k

(1) − x

k

(2))f

k

(z)

= | ˜ f

x(1)

(z) − ˜ f

x(2)

(z)| ≤ 2m.

By the arbitrary property of A and z one gets

X

k=k0+1

|u

k

(z)| ≤ 2m, z ∈ E

m

. The same argument gives

X

k=k0+1

|v

k

(z)| ≤ 2m, z ∈ E

m

. Hence

X

k=1

|f

k

(z)| =

k0

X

k=1

+

X

k=k0+1

 |f

k

(z)| ≤ M + 4m, z ∈ E

m

.

Case 2: X = {−1, 1}

N

. Now we define two elements x(1), x(2) of the interior of R

m

by the formulas:

x

k

(j) = x

k

(0), k = 1, . . . , k

0

, j = 1, 2;

x

k

(j) = x

k

(0), k > k

0

, k / ∈ A, j = 1, 2;

x

k

(1) = 1, x

k

(2) = −1, k ∈ A

1

; x

k

(1) = −1, x

k

(2) = 1, k ∈ A

2

. Then

2 X

k∈A

|u

k

(z)| ≤

X

k∈A

(x

k

(1) − x

2

(2)) f

k

(z)

= | ˜ f

x(1)

(z) − ˜ f

xk(2)

(z)| ≤ 2m.

Hence, by the analogous argument as in the proof of the case 1, we get

X

k=1

|f

k

(z)| ≤ M + 4m, z ∈ E

m

,

which ends the proof of the case 2. 

Corollary 3.3. Let {f

k

} be a sequence of holomorphic functions on an open set Ω ⊂ C

N

. Let D denote the set of all points a in Ω such that the series P

1

f

k

is absolutely convergent at every point of a neighborhood of a. Assume that the sum ϕ(z) := P

1

|f

k

(z)| is locally bounded in D, and D ⊂ Ω. Let X be any of the two metric spaces {0, 1} ¯

N

or {−1, 1}

N

.

Then there exists a subset R of X of the first category such that for every point x ∈ X \ R the holomorphic function f

x

(z) := P

k=1

x

k

f

k

(z), z ∈ D,

cannot be continued analytically across any boundary point of D.

(12)

Proof. Let {w

j

} be the sequence of all rational points of D (or any count- able dense subset of D). Let a

j

be a point of ∂D such that kw

j

− a

j

k = dist(w

j

, ∂D). By Lemma 3.2 for every j there exists a subset R

j

of X of the first category such that for every x ∈ X \ R

j

the function f

x

has a singular point at a

j

. The set R := S R

j

is again of the first category such that for every x ∈ X \ R the function f

x

has analytic extension across no boundary

point of D. 

Proof of Theorems 4 and 5. It is sufficient to apply Lemma 3.2 with Ω = C

N

, with f

k

= Q

k

and f

k

= c

α(k)

z

α(k)

(k ∈ Z

+

), respectively, where α : Z

+

3 k 7→ α(k) ∈ Z

N+

is a one-to-one mapping, and with D replaced by the domain of convergence D of the corresponding power series.  Remark 3.4. The author would like to draw reader’s attention to the fact that, unfortunately, the proofs of Theorems 4 and 5 published in [6] contain flaws.

References

[1] Bieberbach, L., Analytische Fortsetzung, Springer-Verlag, Berlin 1955.

[2] Jarnicki, M., Jakóbczak, P., Wstęp do teorii funkcji holomorficznych wielu zmiennych zespolonych, Wydawnictwo Uniwersytetu Jagiellońskiego, Kraków, 2002.

[3] Klimek, M., Pluripotential Theory, Oxford University Press, New York, 1991.

[4] Luh, W., Universal approximation properties of convergent power series on open sets, Analysis 6 (1986), 191–207.

[5] Saint Raymond, J., Transformations s´epar´ement analytiques, Ann. Inst. Fourier (Grenoble) 40 (1990), 79–101.

[6] Siciak, J., Generalizations of a theorem of Fatou, Zeszyty Naukowe UJ 11 (1966), 81–84.

[7] Siciak, J., Sets in CN with vanishing global extremal function and polynomial approx- imation, Ann. Fac. Sci. Toulouse 20 (2011), no. S2, 189–209.

Józef Siciak

Institute of Mathematics Jagiellonian University Łojasiewicza 6

30-348 Kraków Poland

e-mail: Jozef.Siciak@im.uj.edu.pl Received May 16, 2011

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