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POLONICI MATHEMATICI LIX.2 (1994)

On local motion of a general compressible

viscous heat conducting fluid bounded by a free surface by Ewa Zadrzy´ nska ( L´ od´ z)

and Wojciech M. Zaja ¸czkowski (Warszawa)

Abstract. The motion of a viscous compressible heat conducting fluid in a domain in R3bounded by a free surface is considered. We prove local existence and uniqueness of solutions in Sobolev–Slobodetski˘ı spaces in two cases: with surface tension and without it.

1. Introduction. In this paper we consider the motion of a viscous heat conducting fluid in a bounded domain Ω

t

⊂ R

3

with a free boundary S

t

. Let v = v(x, t) be the velocity of the fluid (i.e. v = (v

1

, v

2

, v

3

)), % = %(x, t) the density, ϑ = ϑ(x, t) the temperature, f = f (x, t) the external force field per unit mass, r = r(x, t) the efficiency of heat sources per unit mass, p = p(%, ϑ) the pressure, µ and ν the constant viscosity coefficients, σ the constant coefficient of surface tension, κ the constant coefficient of heat conductivity, c

v

= c

v

(%, ϑ) the specific heat at constant volume, p

0

the external (constant) pressure. Then the problem is described by the following system (see [4], Chs.

2 and 5):

(1.1)

%(v

t

+ v · ∇v) + ∇p − µ∆v − ν∇ div v = %f in e Ω

T

,

%

t

+ div(%v) = 0 in e Ω

T

,

%c

v

t

+ v · ∇ϑ) + ϑp

ϑ

div v − κ∆ϑ

− µ 2

3

X

i,j=1

(v

i,xj

+ v

j,xi

)

2

− (ν − µ)(div v)

2

= %r in e Ω

T

,

T · n − σHn = −p

0

n on e S

T

,

1991 Mathematics Subject Classification: 35A05, 35R35, 76N10.

Key words and phrases: free boundary, compressible viscuous heat conducting fluid, local existence, anisotropic Sobolev spaces.

Research supported by KBN grant no. 211419101.

(2)

(1.1)

[cont.]

v · n = − φ

t

|∇φ| on e S

T

,

∂ϑ

∂n = e ϑ on e S

T

, v|

t=0

= v

0

in Ω ,

%|

t=0

= %

0

in Ω , ϑ|

t=0

= ϑ

0

in Ω ,

where φ(x, t) = 0 describes S

t

, n is the unit outward vector normal to the boundary (i.e. n = ∇φ/|∇φ|), e Ω

T

= S

t∈(0,T )

t

× {t}, Ω

t

is the domain of the drop at time t and Ω

0

= Ω is its initial domain, e S

T

= S

t∈(0,T )

S

t

× {t}.

Finally, T = T(v, p) denotes the stress tensor of the form

T = {T

ij

} = {−pδ

ij

+ µ(v

i,xj

+ v

j,xi

) + (ν − µ)δ

ij

div v}

(1.2)

≡ {−pδ

ij

+ D

ij

(v)} ,

where i, j = 1, 2, 3, D = D(v) = {D

ij

} is the deformation tensor. Moreover, thermodynamic considerations imply that c

v

> 0, κ > 0, ν ≥

13

µ > 0. By H we denote the double mean curvature of S

t

which is negative for convex domains and can be expressed in the form

(1.3) Hn = ∆

St

(t)x, x = (x

1

, x

2

, x

3

) ,

where ∆

St

(t) is the Laplace–Beltrami operator on S

t

. Let S

t

be given by x = x(s

1

, s

2

, t), (s

1

, s

2

) ∈ U ⊂ R

2

, where U is an open set. Then

St

(t) = g

−1/2

∂s

α

g

−1/2

b g

αβ

∂s

β

(1.4)

= g

−1/2

∂s

α

g

1/2

g

αβ

∂s

β

(α, β = 1, 2) ,

where the summation convention over repeated indices is assumed, g = det{g

αβ

}

α,β=1,2

, g

αβ

= x

α

· x

β

(x

α

= ∂x/∂s

α

), {g

αβ

} is the inverse matrix to {g

αβ

} and { b g

αβ

} is the matrix of algebraic complements of {g

αβ

}.

Let the domain Ω be given. Then by (1.1)

5

, Ω

t

= {x ∈ R

3

: x = x(ξ, t), ξ ∈ Ω}, where x = x(ξ, t) is the solution of the Cauchy problem

(1.5) ∂x

∂t = v(x, t), x|

t=0

= ξ ∈ Ω, ξ = (ξ

1

, ξ

2

, ξ

3

) .

Therefore the transformation x = x(ξ, t) connects Eulerian x and Lagran- gian ξ coordinates of the same fluid particle. Hence

(1.6) x = ξ +

t

R

0

u(ξ, s) ds ≡ X

u

(ξ, t) ,

(3)

where u(ξ, t) = v(X

u

(ξ, t), t). Moreover, the kinematic boundary condition (1.1)

5

implies that the boundary S

t

is a material surface. Thus, if ξ ∈ S = S

0

then X

u

(ξ, t) ∈ S

t

and S

t

= {x : x = X

u

(ξ, t), ξ ∈ S}.

By the equation of continuity (1.1)

2

and (1.1)

5

the total mass M of the drop is conserved and the following relation between % and Ω

t

holds:

(1.7) R

t

%(x, t) dx = M .

The aim of this paper is to prove the local-in-time existence and unique- ness of solutions to problem (1.1) in Sobolev–Slobodetski˘ı spaces (see def- inition in Sect. 2). In the case of compressible barotropic fluid the corre- sponding drop problem has been considered by W. M. Zaj¸ aczkowski in [13]

and [16], while papers [14] and [15] refer to the global existence of solution to the same drop problem. Local existence of solutions in the compressible barotropic case was also considered in [5], [6], [12], while in the incompress- ible barotropic case local existence is proved in [2] and [10].

This paper consists of four sections. In Section 2 notation and auxiliary results are presented. In Section 3 we prove the local existence and unique- ness of solution to problem (1.1) in the case σ = 0. In this case there is no surface tension. Finally, Section 4 concerns the local existence and unique- ness of solution to problem (1.1) in the case σ 6= 0, i.e. when the shape of the free boundary S

t

of Ω

t

is governed by surface tension.

2. Notations and auxiliary results. In Sections 3 and 4 of this paper we use the anisotropic Sobolev–Slobodetski˘ı spaces W

2l,l/2

(Q

T

), l ∈ R

1+

(see [3]), of functions defined in Q

T

where Q

T

= Ω

T

≡ Ω × (0, T ) (Ω ⊂ R

3

is a domain, T ≤ ∞) or Q

T

= S

T

≡ S × (0, T ), S = ∂Ω.

We define W

2l,l/2

(Ω

T

) as the space of functions u such that kuk

W2l,l/2(ΩT)

=

 X

|α|+2i≤[l]

kD

ξα

ti

uk

2L2(ΩT)

(2.1)

+ X

|α|+2i=[l]



T

R

0

R

R

|D

ξα

it

u(ξ, t) − D

αξ0

ti

u(ξ

0

, t)|

2

|ξ − ξ

0

|

3+2(l−[l])

dξ dξ

0

dt

+ R

T

R

0 T

R

0

|D

ξα

ti

u(ξ, t) − D

αξ

ti0

u(ξ, t

0

)|

2

|t − t

0

|

1+2(l/2−[l/2])

dt dt

0



1/2

≡ h X

|α|+2i≤[l]

|D

ξα

ti

u|

22,ΩT

+ X

|α|+2i=[l]

([D

ξα

ti

u]

2l−[l],2,ΩT

+ [D

αξ

ti

u]

2l/2−[l/2],2,ΩT,t

) i

1/2

< ∞ ,

(4)

where we use generalized (Sobolev) derivatives, D

αξ

= ∂

ξα1

1

ξα2

2

ξα3

3

, ∂

ξαj

j

=

αj

/∂ξ

jαj

(j = 1, 2, 3), α = (α

1

, α

2

, α

3

) is a multiindex, |α| = α

1

+ α

2

+ α

3

,

ti

= ∂

i

/∂t

i

and [l] is the integer part of l. In the case when l is an integer the second terms in the above formulae must be omitted, while in the case of l/2 being integer the last terms in the above formulae must be omitted as well.

Similarly to W

2l,l/2

(Ω

T

), using local mappings and a partition of unity we introduce the normed space W

2l,l/2

(S

T

) of functions defined on S

T

= S × (0, T ), where S = ∂Ω.

We also use the usual Sobolev spaces W

2l

(Q), where l ∈ R

+

, Q = Ω (Ω ⊂ R

3

is a bounded domain) or Q = S. In the case Q = Ω the norm in W

2l

(Ω) is defined as follows:

kuk

Wl

2(Ω)

=

 X

|α|≤[l]

kD

αξ

uk

2L2(Ω)

+ X

|α|=[l]

R

R

|D

αξ

u(ξ) − D

ξα0

u(ξ

0

)|

2

|ξ − ξ

0

|

3+2(l−[l])

dξ dξ

0



1/2

≡  X

|α|≤[l]

|D

αξ

u|

22,Ω

+ [D

ξα

u]

2l−[l],2,Ω



1/2

,

where the last term is omitted when l is an integer. Similarly, by using local mappings and a partition of unity we define W

2l

(S).

To simplify notation we write kuk

l,Q

= kuk

Wl,l/2

2 (Q)

if Q = Ω

T

or Q = S

T

, l ≥ 0 ; kuk

l,Q

= kuk

Wl

2(Q)

if Q = Ω or Q = S, l ≥ 0 , and W

20,0

(Q) = W

20

(Q) = L

2

(Q). Moreover,

kuk

Lp(Q)

= |u|

p,Q

, 1 ≤ p ≤ ∞ . Next introduce the space Γ

0l,l/2

(Ω) with the norm

kuk

Γ0l,l/2(Ω)

= X

|α|+2i≤l

kD

ξα

ti

uk

0,Ω

≡ |u|

l,0,Ω

and the space L

p

(0, T ; Γ

0l,l/2

(Ω)) with the norm

kuk

Lp(0,T ;Γ0l,l/2(Ω))

≡ u

l,0,p,ΩT

, where 1 ≤ p ≤ ∞ .

Moreover, let C

α

(Ω

T

) (α ∈ (0, 1)) denote the H¨ older space with the norm

kuk

Cα(ΩT)

= sup

T

|u(ξ, t) − u(ξ

0

, t

0

)|

(p|ξ − ξ

0

|

2

+ |t − t

0

|

2

)

α

;

(5)

let C

B0

(Ω

T

) be the space of continuous bounded functions on Ω

T

with the norm

kuk

C0

B(ΩT)

= sup

T

|u(ξ, t)|

and let C

2,1

(Q) (Q ⊂ R

3

× (0, T )) denote the space of functions u such that D

αξ

ti

u ∈ C

0

(Q) for |α| + 2i ≤ 2.

Finally, the following seminorms are used:

u

κ,QT

=



T

R

0

|u|

22,Q

t

dt



1/2

,

where Q = Ω (Ω ⊂ R

3

is a bounded domain) or Q = S, and κ ∈ (0, 1);

[u]

l,2,Q

= [u]

l,2,Q,ξ

+ [u]

l,2,Q,t

, where

[u]

l,2,Q,ξ

= X

|α|+2i=[l]

[D

ξα

ti

u]

l−[l],2,Q,ξ

, [u]

l,2,Q,t

= X

|α|+2i=[l]

[D

ξα

ti

u]

l/2−[l/2],2,Q,t

,

Q = Ω × J (Ω ⊂ R

3

is a domain, J = (0, T ) or J = (−∞, T )) or Q = S × J . In the case when J = (0, T ) the seminorms [D

αξ

ti

u]

l−[l],2,Q,ξ

and [D

ξα

ti

u]

l/2−[l/2],2,Q,t

are defined in (2.1). In the case when J = (−∞, T ) we define the above seminorms in the same way.

Let X be whichever of the function spaces mentioned above. We say that a vector-valued function u = (u

1

, . . . , u

ν

) belongs to X if u

i

∈ X for any 1 ≤ i ≤ ν.

In the sequel we shall use various notations for derivatives of u (where u is a scalar- or vector-valued function u = (u

1

, u

2

, u

3

)). If u is a scalar-valued function we denote by D

ξk

u (where ξ ∈ Ω ⊂ R

3

) the vector of all derivatives of u of order k, i.e. D

kξ

u = (D

αξ

u)

|α|=k

. Similarly, if u = (u

1

, u

2

, u

3

) we denote by D

ξk

u the vector (D

ξα

u

j

)

|α|=k, j=1,2,3

. By D

kξ,t

u we denote the vector (D

ξα

ti

u

j

)

|α|+2i=k,j=1,2,3

in the case when u = (u

1

, u

2

, u

3

) and the vector (D

ξα

ti

u)

|α|+2i=k

in the scalar case. Hence

|D

kξ

u| = X

|α|=k

|D

ξα

u| and |D

kξ,t

u| = X

|α|+2i=k

|D

ξα

ti

u| .

We also use the notation ∇

ξ

u ≡ D

1ξ

u or u

ξ

≡ D

ξ1

u.

Next, we denote by u · v either the scalar product of vectors u and v, or

the product of matrices u and v.

(6)

Finally, we denote by D

kξ,t

uD

lξ,t

v the following number:

(2.2) D

ξ,tk

uD

ξ,tl

v = X

|α|+2i=k

|β|+2j=l p

X

m=1 s

X

n=1

D

αξ

ti

u

m

D

ξβ

tj

v

n

,

where u = (u

1

, . . . , u

p

), v = (v

1

, . . . , v

s

) (k ≥ 0, l ≥ 0, p > 1, s > 1). The product of more than two such factors is defined similarly.

We use the following lemmas.

Lemma 2.1. The following imbedding holds:

(2.3) W

rl

(Ω) ⊂ L

αp

(Ω) (Ω ⊂ R

3

) ,

where |α| + 3/r − 3 ≤ l, l ∈ Z, 1 ≤ p, r ≤ ∞; L

αp

(Ω) is the space of functions u such that |D

ξα

u|

p,Ω

< ∞; W

rl

(Ω) is the Sobolev space.

Moreover , the following interpolation inequalities hold : (2.4) |D

αξ

u|

p,Ω

≤ cε

1−κ

|D

lξ

u|

r,Ω

+ cε

−κ

|u|

r,Ω

,

where κ = |α|/l + 3/(lr) − 3/(lp) < 1, ε is a parameter and c > 0 is a constant independent of u and ε;

(2.5) |D

ξα

u|

q,S

≤ cε

1−κ

|D

ξl

u|

r,Ω

+ cε

−κ

|u|

r,Ω

,

where κ = |α|/l + 3/(lr) − 2/(lq) < 1, ε is a parameter and c > 0 is a constant independent of u and ε.

Lemma 2.1 follows from Theorem 10.2 of [3].

Lemma 2.2 (see [7]). For sufficiently regular u we have k∂

ti

u(t)k

2l−1−2i,Ω

≤ c(kuk

2l,ΩT

+ k∂

ti

u(0)k

2l−1−2i,Ω

) , where 0 ≤ 2i ≤ 2l − 1, l ∈ N and c > 0 is a constant independent of T .

Lemma 2.3. Let u(ξ, t) = 0 for t ≤ 0. Then

T

R

−∞

dt

T

R

−∞

dt

0

|u(ξ, t) − u(ξ, t

0

)|

22,Q

|t − t

0

|

1+2α

T

R

0

dt

T

R

0

dt

0

|u(ξ, t) − u(ξ, t

0

)|

22,Q

|t − t

0

|

1+2α

+ 1

α

T

R

0

|u(t)|

22,Q

t

dt , where Q = Ω (Ω ⊂ R

3

is a domain) or Q = S = ∂Ω, and α ∈ R.

Lemma 2.4. Let τ ∈ (0, 1). Then for all u ∈ W

20,τ /2

(Ω

T

), (2.6)

T

R

0

|u|

22,Ω

dt t

τ

≤ c

1

T

R

0

dt

T

R

0

dt

0

|u(·, t) − u(·, t

0

)|

22,Ω

|t − t

0

|

1+τ

+ c

2

T

−τ

T

R

0

|u|

22,Ω

dt ,

(7)

where c

1

, c

2

do not depend on T and u. For T = ∞ the last term in (2.6) vanishes.

This was shown in [11], Lemma 6.3.

3. Local existence in the case σ = 0. In order to prove local existence of solutions of (1.1) we rewrite it in the Lagrangian coordinates introduced by (1.5) and (1.6):

(3.1)

ηu

t

− µ∇

2u

u − ν∇

u

u

· u + ∇

u

p(η, γ) = ηg in Ω

T

,

η

t

+ η∇

u

· u = 0 in Ω

T

,

ηc

v

(η, γ)γ

t

− κ∇

2u

γ = −γp

γ

(η, γ)∇

u

· u + µ

2

3

X

i,j=1

xi

· ∇

ξ

u

j

+ ξ

xj

· ∇

ξ

u

i

)

2

+ (ν − µ)(∇

u

· u)

2

+ ηk in Ω

T

,

T

u

(u, p) · n = −p

0

n on S

T

,

n · ∇

u

γ = e γ on S

T

,

u|

t=0

= v

0

in Ω ,

η|

t=0

= ρ

0

in Ω ,

γ|

t=0

= ϑ

0

in Ω ,

where u(ξ, t) = v(X

u

(ξ, t), t), γ(ξ, t) = ϑ(X

u

(ξ, t), t), η(ξ, t) = ρ(X

u

(ξ, t), t), g(ξ, t) = f (X

u

(ξ, t), t), k(ξ, t) = r(X

u

(ξ, t), t), ∇

u

= ξ

x

ξ

≡ {ξ

ix

ξi

},

T

u

(u, p) = −p1 + D

u

(u) ,

D

u

(u) = {µ(ξ

kxi

ξk

u

j

+ ξ

kxj

ξk

u

i

) + (ν − µ)δ

ij

u

· u}

(here the summation convention over repeated indices is assumed and 1 is the unit matrix) and γ(ξ, t) = e e ϑ(X

u

(ξ, t), t).

Let A = {a

ij

} be the Jacobi matrix of the transformation x = X

u

(ξ, t), where a

ij

= δ

ij

+ R

t

0

ξj

u

i

(ξ, τ ) dτ . Assuming that |∇

ξ

u|

∞,ΩT

≤ M we obtain (3.2) 0 < c

1

(1 − M t)

3

≤ det{x

ξ

} ≤ c

2

(1 + M t)

3

, t ≤ T ,

where c

1

, c

2

> 0 are constants and T > 0 is sufficiently small. Moreover, det A = exp



t

R

0

u

· u dτ



= ρ

0

/η .

(8)

Let S

t

be determined (at least locally) by the equation φ(x, t) = 0. Then S is described by φ(x(ξ, t), t)|

t=0

≡ e φ(ξ) = 0. Thus, we have

n(x(ξ, t), t) = − ∇

x

φ(x, t)

|∇

x

φ(x, t)|

x=x(ξ,t)

and n

0

(ξ) = − ∇

ξ

φ(ξ) e

|∇

ξ

φ(ξ)| e . First we consider the linear problems

(3.3)

Lu ≡ u

t

− µ∇

2ξ

u − ν∇

ξ

ξ

· u = F in Ω

T

,

D

ξ

(u) · n

0

= G on S

T

,

u|

t=0

= u

0

in Ω

(where D

ξ

(u) = {µ(∂

ξi

u

j

+ ∂

ξj

u

i

) + (ν − µ)δ

ij

ξk

u

k

}) and

(3.4)

γ

t

− κ∇

2ξ

γ = K in Ω

T

, n

0

· ∇

ξ

γ = e γ on S

T

, γ|

t=0

= γ

0

in Ω . We assume

(3.5) F ∈ W

22,1

(Ω

T

), G ∈ W

3−1/2,3/2−1/4

2

(S

T

),

D

ξ,t2

G

1/4,ST

< ∞, u

0

∈ W

23

(Ω) and

(3.6) K ∈ W

22,1

(Ω

T

), e γ ∈ W

3−1/2,3/2−1/4

2

(S

T

),

D

2ξ,t

e γ

1/4,ST

< ∞, γ

0

∈ W

23

(Ω) . Moreover, we assume the following compatibility conditions:

(3.7) D

ξα

(D

ξ

(u(0)) · n

0

− G(0)) = 0, |α| ≤ 1, on S , and

(3.8) D

αξ

(n

0

· ∇

ξ

γ(0) − e γ(0)) = 0, |α| ≤ 1, on S .

First we consider problem (3.3). Define functions ψ

i

for i = 0, 1 by (3.9) ψ

i

= ∂

ti

u|

t=0

in Ω .

Hence

(3.10) ψ

0

= u

0

, ψ

1

= µ∆u

0

+ ν∇ div u

0

+ F (0) .

Lemma 3.1. Let Ω ⊂ R

3

be either a halfspace or a bounded domain with smooth boundary ∂Ω and let T ≤ ∞. Assume that

(3.11) ψ

0

∈ W

23

(Ω), ψ

1

∈ W

21

(Ω) . Then there exists v ∈ W

24,2

(Ω

T

) such that

(3.12) ∂

it

v|

t=0

= ψ

i

in Ω (i = 0, 1)

(9)

and

(3.13) kvk

4,ΩT

≤ c(kψ

0

k

3,Ω

+ kψ

1

k

1,Ω

) , where c > 0 is a constant independent of T .

P r o o f. Using the Hestenes–Whitney method (see [1]) we can extend ψ

0

and ψ

1

to functions e ψ

0

∈ W

23

(R

3

) and e ψ

1

∈ W

21

(R

3

) such that k e ψ

0

k

3,R3

≤ ckψ

0

k

3,Ω

, k e ψ

1

k

1,R3

≤ ckψ

1

k

1,Ω

,

where c = c(Ω). Then from [16] (Lemma 6.5) we deduce that there exists e v ∈ W

24,2

(R

3

× R

1+

) such that

(3.14) ∂

ti

e v|

t=0

= e ψ

i

, i = 0, 1 , and

(3.15) k e vk

4,R3×R1

+

≤ c(k e ψ

0

k

3,R3

+ k e ψ

1

k

1,R3

) ≤ c(kψ

0

k

3,Ω

+ kψ

1

k

1,Ω

) . Therefore v = e v|

T

satisfies conditions (3.12) and (3.13).

Now we prove the following theorem.

Theorem 3.1. Let S ∈ W

24−1/2

and let assumptions (3.5) and (3.7) be satisfied (T < ∞). Then there exists a solution of (3.3) such that u ∈ W

24,2

(Ω

T

) and

(3.16) kuk

4,ΩT

≤ c(T )(kF k

2,ΩT

+ kGk

3−1/2,ST

+ D

ξ,t2

G

1/4,ST

+ |u(0)|

3,0,Ω

) , where c is an increasing continuous function of T and

(3.17) |u(0)|

3,0,Ω

= ku

0

k

3,Ω

+ k∂

t

u|

t=0

k

1,Ω

. P r o o f. Introduce the function

(3.18) w = u − v ,

where v is the function from Lemma 3.1. Then instead of (3.3) we obtain the problem

(3.19)

w

t

− µ∆w − ν∇ div w = F − Lv ≡ f in Ω

T

, D

ξ

(w) · n

0

= G − D

ξ

(v) · n

0

≡ g on S

T

,

w|

t=0

= 0 in Ω ,

where in view of the compatibility condition (3.7) we have

(3.20) f (0) = g(0) = 0 .

It is sufficient to consider problem (3.19) in Ω

T

≡ R

T

≡ R

3+

× [0, T ] because using a partition of unity and appropriate norms (see [8], Sects.

20, 21) we obtain the existence and the appropriate estimate of solutions of

(3.19) in a bounded domain Ω.

(10)

Thus, consider problem (3.19) in R

T

and extend functions f , g, w by zero for t < 0 to functions f

1

, g

1

, w

1

. Then instead of (3.19) we get the following boundary value problem:

(3.21) Lw

1

= f

1

in e D

4

(T ) = R

3+

× (−∞, T ] , D

ξ

(w

1

) · n

0

= g

1

in e E

3

(T ) = R

2

× (−∞, T ] .

Next using the Hestenes–Whitney method extend f

1

and g

1

to functions f

2

and g

2

defined on R

3+

× (−∞, ∞) and R

2

× (−∞, ∞), respectively. Then instead of (3.21) we have the problem

(3.22)

Lw

2

= f

2

in e D

4

= R

3+

× (−∞, ∞) , D

ξ

(w

2

) · n

0

= g

2

in e E

3

= R

2

× (−∞, ∞) , and the estimate

(3.23) kf

2

k

2,D

e

4

≤ ckf

1

k

2,D

e

4(T )

.

Next we extend f

2

by the Hestenes–Whitney method to a function f

3

∈ W

24,2

(R

4

) such that

(3.24) kf

3

k

2,R4

≤ ckf

2

k

2,D

e

4

. Consider now the system

(3.25) Lw

3

= f

3

in R

4

.

By potential techniques (see [8], Sections 12 and 21) and (3.23), (3.24) there exists a solution w

3

∈ W

24,2

(R

4

) of (3.25) and

(3.26) kw

3

k

4,R4

≤ c(T )kf k

2,RT

, where c(T ) is an increasing function of T .

Introduce the function

(3.27) w

4

= w

2

− w

3

.

By (3.22) and (3.25) we have (3.28)

Lw

4

= 0 in e D

4

,

D

ξ

(w

4

) · n

0

= g

2

− D

ξ

(w

3

) · n

0

≡ g

3

in e E

3

.

Again by potential techniques there exists a solution w

4

∈ W

24,2

( e D

4

) of (3.28) and

kw

4

k

4,D

e

4

≤ c[g

3

]

3−1/2,2,

E

e

3

≤ c([g

2

]

3−1/2,2,

E

e

3

+ kw

3

k

4,D

e

4

)

≤ c(T )([g

1

]

3−1/2,2,

E e

3

(T ) + kf k

2,RT

) ,

where we used (3.26) and the Hestenes–Whitney method for g

1

. Hence

(11)

(3.29) kw

4

k

4,RT

≤ c(T )([g

1

]

3−1/2,2,E

e

3(T )

+ kf k

2,RT

) . Further, using Lemma 2.3 we have

[g

1

]

3−1/2,2,

E

e

3(T )

= X

|α|=2

[D

αξ

g

1

]

1/2,2,

E

e

3(T ),ξ

+ [∂

t

g

1

]

1/2,2,

E

e

3(T ),ξ

(3.30)

+ X

|α|=2

[D

αξ

g

1

]

1/4,2,

E

e

3(T ),t

+ [∂

t

g

1

]

1/4,2,

E

e

3(T ),t

≤ c

 X

|α|=2

[D

αξ

g]

1/2,2,R2×[0,T ],ξ

+ [∂

t

g]

1/2,2,R2×[0,T ],ξ

+ X

|α|=2

[D

αξ

g]

1/4,2,R2×[0,T ],t

+ [∂

t

g]

1/4,2,R2×[0,T ],t

+



T

R

0

|D

ξ,t2

g|

22,R2

t

1/2

dt



1/2



≤ c(kgk

3−1/2,ST

+ D

ξ,t2

g

1/4,ST

) , where S

T

= R

2

× [0, T ].

Taking into account the right-hand side of (3.19) and (3.18), (3.21), (3.22), (3.25)–(3.30) we conclude that there exists a solution u ∈ W

24,2

(Ω

T

) of (3.3) satisfying

(3.31) kuk

4,RT

≤ c(T )(kF k

2,RT

+ kvk

4,RT

+ kGk

3−1/2,ST

+ D

2ξ,t

G

1/4,ST

+ kv

ξ

n

0

k

3−1/2,ST

+ D

2ξ,t

(v

ξ

n

0

)

1/4,ST

) , where

v

ξ

n

0

=

3

X

i,j,k=1

v

j

n

0k

. By Lemma 3.1 we have

(3.32) kvk

4,RT

≤ c(kφ

0

k

3,R3

+

+ kφ

1

k

1,R3

+

) and

kv

ξ

n

0

k

3−1/2,ST

≤ k e v

ξ

n

0

k

3−1/2,S×(0,∞)

≤ ck v e

ξ

k

3,R3 +×(0,∞)

(3.33)

≤ ckvk

4,RT

≤ c(kφ

0

k

3,R3

+

+ kφ

1

k

1,R3 +

) , where we have used the fact that S ∈ W

24−1/2

.

It remains to estimate D

ξ,t2

(v

ξ

n

0

)

1/4,ST

. We have

(12)

(3.34) D

2ξ,t

(v

ξ

n

0

)

1/4,ST

=



T

R

0

|D

2ξ

n

0

D

1ξ

v + D

1ξ

n

0

D

ξ2

v + n

0

D

ξ3

v + n

0

t

D

1ξ

v|

22,S

t

1/2

dt



1/2

≤ c



T

R

0

|D

2ξ

n

0

|

24,S

|D

ξ1

v|

24,S

+ |D

2ξ

v|

22,S

+ |D

3ξ

v|

22,S

+ |∂

t

D

ξ1

v|

22,S

t

1/2

dt



1/2

, where we have used the fact that S ∈ W

24−1/2

and Lemma 2.1, and where the products are understood in the sense of (2.2).

Next, by Lemma 2.1 we get

T

R

0

|D

2ξ

n

0

|

24,S

|D

ξ1

v|

24,S

t

1/2

dt ≤ c

T

R

0

kD

1ξ

vk

21,S

t

1/2

dt . Hence in view of Lemma 2.4, (3.34) yields

D

ξ,t2

(v

ξ

n

0

)

1/4,ST

≤ c



R

0

|D

ξ1

e v|

22,S

+ |D

2ξ

e v|

22,S

+ |D

3ξ

e v|

22,S

+ |D

1ξ

t

e v|

22,S

t

1/2

dt



1/2

≤ c

1



R

0

dt

R

0

dt

0

 |D

ξ1

e v(ξ, t) − D

1ξ

e v(ξ, t

0

)|

22,S

|t − t

0

|

1+1/2

+ |D

2ξ

e v(ξ, t) − D

ξ2

e v(ξ, t

0

)|

22,S

|t − t

0

|

1+1/2

+ |∂

t

D

ξ1

e v(ξ, t) − ∂

t0

D

1ξ

v(ξ, t e

0

)|

22,S

|t − t

0

|

1+1/2

+ |D

3ξ

e v(ξ, t) − D

ξ3

e v(ξ, t

0

)|

22,S

|t − t

0

|

1+1/2



1/2

. Therefore

(3.35) D

ξ,t2

(v

ξ

n

0

)

1/4,ST

≤ ckvk

4,RT

, where we have used Theorem 5.1 from [8].

Taking into account (3.31)–(3.33) and (3.35) we get (3.16). This com- pletes the proof of the theorem.

In the same way we can prove

Theorem 3.2. Let S ∈ W

24−1/2

and let assumptions (3.6) and (3.8) be satisfied (T < ∞). Then there exists a solution of (3.4) such that γ ∈ W

24,2

(Ω

T

) and

(3.36) kγk

4,ΩT

≤ c(T )(kKk

2,ΩT

+ k e γk

3−1/2,ST

+ D

2ξ,t

e γ

1/4,ST

+ |γ(0)|

3,0,Ω

) ,

(13)

where c is an increasing function of T and

(3.37) |γ(0)|

3,0,Ω

= kγ

0

k

3,Ω

+ k∂

t1

γ|

t=0

k

1,Ω

. Now we have to consider the following problems:

(3.38)

ηu

t

− µ∇

2ξ

u − ν∇

ξ

ξ

· u = F in Ω

T

, D

ξ

(u) · n

0

= G on S

T

,

u|

t=0

= u

0

in Ω

and

(3.39)

ηc

v

(η, β)γ

t

− κ∇

2ξ

γ = K in Ω

T

, n

0

· ∇

ξ

γ = e γ on S

T

,

γ|

t=0

= γ

0

in Ω .

First we consider (3.38). The following theorem is proved in [15].

Theorem 3.3. Assume that

S ∈ W

24−1/2

, F ∈ W

22,1

(Ω

T

), G ∈ W

3−1/2,3/2−1/4

2

(S

T

),

D

2ξ,t

G

1/4,ST

< ∞, u

0

∈ W

23

(Ω),

η ∈ L

(0, T ; Γ

02,1

(Ω)) ∩ C

α

(Ω

T

) (α ∈ (0, 1)), 1/η ∈ L

(Ω

T

).

Moreover , let the compatibility condition (3.7) be satisfied. Then there exists a unique solution u ∈ W

24,2

(Ω

T

) to problem (3.38) satisfying the estimate

kuk

4,ΩT

≤ φ

1

(|1/η|

∞,ΩT

, |η|

∞,ΩT

, T )[kF k

2,ΩT

+ kGk

3−1/2,ST

(3.40)

+ D

ξ,t2

G

1/4,ST

+ φ

2

( η

2,0,∞,ΩT

, kηk

Cα(ΩT)

)kuk

2,ΩT

] + φ

3

(|1/η|

∞,ΩT

, T )|u(0)|

3,0,Ω

,

where φ

i

(i = 1, 2, 3) are nonnegative increasing continuous functions of their arguments.

Now we consider problem (3.39). Assume that η ∈ L

(0, T ; Γ

02,1

(Ω)) and β ∈ W

24,2

(Ω

T

). Applying Theorems 10.2 and 10.4 of [3] we find that η ∈ C

B0

(Ω

T

) and β ∈ C

B0

(Ω

T

). Therefore, there exists a bounded domain V ⊂ R

2

such that (η(ξ, t), β(ξ, t)) ∈ V for any (ξ, t) ∈ Ω

T

.

Lemma 3.2. Assume that η ∈ L

(0, T ; Γ

02,1

(Ω)) ∩ C

α

(Ω

T

) (where α ∈ (0, 1/2)), 1/η ∈ L

(Ω

T

), η > 0, β ∈ W

24,2

(Ω

T

), 1/β ∈ L

(Ω

T

), β > 0, c

v

∈ C

2

(R

2+

), c

v

> 0. Then ηc

v

(η, β) ∈ L

(0, T ; Γ

02,1

(Ω)), ηc

v

∈ C

α

(Ω

T

), 1/(ηc

v

(η, β)) ∈ L

(Ω

T

) and

(3.41) ηc

v

(η, β)

2,0,∞,ΩT

≤ ψ

1

(kc

v

k

C2(V )

, k1/c

v

k

C0(V )

, η

2,0,∞,ΩT

, kβk

4,ΩT

, |β(0)|

3,0,Ω

) ,

(3.42) |ηc

v

(η, β)|

∞,ΩT

≤ kc

v

k

C0(V )

|η|

∞,ΩT

,

(14)

(3.43) |1/(ηc

v

(η, β))|

∞,ΩT

≤ k1/c

v

k

C0(V )

|1/η|

∞,ΩT

, (3.44) kηc

v

(η, β)k

Cα(ΩT)

≤ ψ

2

(kc

v

k

C2(V )

, kηk

Cα(ΩT)

, kβk

4,ΩT

, |β(0)|

3,0,Ω

, T ) , where ψ

i

(i = 1, 2) are nonnegative increasing continuous functions of their arguments.

P r o o f. By the assumptions we can choose V such that V ⊂ R

2+

. Thus (3.42) and (3.43) are obviously satisfied. In order to obtain (3.41) we cal- culate the derivatives D

αξ

ti

(ηc

v

) (where |α| + 2i ≤ 2) and next we apply Lemmas 2.1 and 2.2. To prove (3.44) we also use Lemmas 2.1 and 2.2 and the Sobolev imbedding theorem.

Theorem 3.4. Assume that

S ∈ W

24−1/2

, K ∈ W

22,1

(Ω

T

), e γ ∈ W

3−1/2,3/2−1/4

2

(S

T

), γ

0

∈ W

23

(Ω), η ∈ L

(0, T ; Γ

02,1

(Ω)), 1/η ∈ L

(Ω

T

), η ∈ C

α

(Ω

T

) (0 < α < 1/2), η > 0, β ∈ W

24,2

(Ω

T

), 1/β ∈ L

(Ω

T

), β > 0, c

v

∈ C

2

(R

2+

), c

v

> 0.

Moreover , let the compatibility condition (3.8) be satisfied. Then there exists a unique solution γ ∈ W

24,2

(Ω

T

) to problem (3.39) satisfying the estimate

kγk

4,ΩT

≤ φ

4

(kc

v

k

C0(V )

, k1/c

v

k

C0(V )

, |η|

∞,ΩT

, |1/η|

∞,ΩT

, T ) (3.45)

× [kKk

2,ΩT

+ k e γk

3−1/2,ST

+ D

ξ,t2

e γ

1/4,ST

+ φ

5

(kc

v

k

C2(V )

, k1/c

v

k

C0(V )

, η

2,0,∞,ΩT

, kηk

Cα(ΩT)

, kβk

4,ΩT

, |β(0)|

3,0,Ω

, T )kγk

2,ΩT

] + φ

6

(k1/c

v

k

C0(V )

, |1/η|

∞,ΩT

, T )|γ(0)|

3,0,Ω

,

where φ

i

(i = 4, 5, 6) are nonnegative increasing continuous functions of their arguments.

P r o o f. Since by Lemma 3.2, ηc

v

(η, β) ∈ L

(0, T ; Γ

02,1

(Ω)), ηc

v

(η, β) ∈ C

α

(Ω

T

) (α ∈ (0, 1/2)) and 1/(ηc

v

(η, β)) ∈ L

(Ω

T

), using the same argu- ment as in Theorem 3.3 and inequalities (3.41)–(3.44) we prove the existence of a unique solution γ ∈ W

24,2

(Ω

T

) of problem (3.39) satisfying the estimate (3.45).

Now consider the problems

(3.46)

ηu

t

− µ∇

2w

u − ν∇

w

w

· u = F in Ω

T

,

D

w

(u) · n = G on S

T

,

u|

t=0

= u

0

in Ω ,

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