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Hydrodynamics and Elasticity Class 1

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Hydrodynamics and Elasticity Class 1

1. Given a scalar field φ(r), a vector field u(r), and a tensor field Σ(r), establish the identities:1

∇ × ∇φ = 0 (1)

∇ · (∇ × u) = 0 (2)

∇ · (φu) = φ∇ · u + u · ∇φ (3)

∇ × (φu) = φ∇ × u + (∇φ) × u (4)

(u · ∇)u = (∇ × u) × u + ∇ 1 2u2



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2u = ∇(∇ · u) − ∇ × (∇ × u) (6)

Σ = ∇ · (Σr) − (∇ · Σ)r, (7)

where Σr ≡ Σ ⊗ r is a third-rank tensor and (∇ · Σ)r ≡ (∇ · Σ) ⊗ r is a second-rank tensor.

u · (∇ · Σ) = ∇ · (Σ · u) − Σ : ∇u, (8)

where A : B = AijBij is the inner product of two second-rank tensors A and B.

2. A second-rank tensor W is antisymmetric if,

WT= −W, (9)

where WTis the transpose of W.

(a) Check that an antisymmetric second-order tensor is traceless and has only three independent ele- ments.

(b) The vector cross W of a vector w is defined by

W · a = w × a, (10)

for all vectors a. Show that W is antisymmetric and has components

Wij= −ijkwk, (11)

where ijk is the Levi-Civita permutation symbol, defined by

ijk=

1, if {i, j, k} = {1, 2, 3}, {2, 3, 1}, or {3, 1, 2},

−1, if {i, j, k} = {2, 1, 3}, {1, 3, 2}, or {3, 2, 1}, 0, if any index is repeated.

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In the expression (11) above, the vector w is written in an embedded form as a reducible second-rank tensor.

(c) The axial vector w of an antisymmetric tensor W is defined through Eq. (10). Show that w has components

wi= −1

2ijkWjk. (13)

Use the  − δ identity:

ijkilm= δjlδkm− δjmδkl, (14)

where δij is the Kronecker delta, defined by

δij =

 1, if i = j,

0, if i 6= j. (15)

1Throughout this text, lightface Latin and Greek letters denote scalars. Boldface lowercase Latin and Greek letters denote vectors. Boldface uppercase Latin and Greek letters denote tensors.

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(d) The vorticity ω of a vector field u is defined by

ω = ∇ × u. (16)

Show that 12ω is the axial vector of the antisymmetric part

−1

2(∇u − ∇uT) (17)

of velocity gradient2 tensor ∇u.

3. Every (reducible) second-rank tensor A may be decomposed into a sum of irreducible parts:

A = A(0)+ A(1)+ A(2), (18)

with

A(0)ij = 1

3Akkδij, A(1)ij = 1

2(Aij− Aji), A(2)ij =1

2(Aij+ Aji) −1

3Akkδij. (19)

Note that A(0)is a scalar in an embedded form as a second-rank isotropic tensor, A(1)is the antisymmetric part of A, being equivalent to an axial vector, and A(2)is the irreducible (symmetric and traceless) second- rank tensor part of A. 3

Show that

A : B = A(0) : B(0)+ A(1) : B(1)+ A(2) : B(2). (20)

4. Recall the divergence theorem for a second-rank tensor field T Z

∂V

T · nda = Z

V

∇ · (TT)dr, (21)

where V is a bounded region with boundary ∂V , and n denotes the outward unit normal to the boundary

∂V of V . Show that

Z

∂V

(r × ΣT· n)da = Z

V

(r × ∇ · Σ − 2σ)dr, (22)

where σ is the axial vector of the antisymmetric part of Σ. This identity will be used in the derivation of the local balance equation for the angular momentum.

2We define the gradient ∇u of the vector field u in terms of the Taylor expansion of the field (assuming such an expansion exists), viz.

u(r + δr) = u(r) + δr · ∇u + o(|δr|) as δr → 0, with components

ei· ∇u = ∂u

∂ri

= lim

h→0

u(r + hei) − u(r)

h ,

and

(∇u)ij= (ei· ∇u) · ej=∂uj

∂ri

.

3The quantities Akk, the axial vector of A(1), and A(2)form spherical tensors of rank 0, 1, and 2, respectively. They transform like the spherical harmonics Ylm for l = 0, 1, and 2. For details see e.g. Jerphagnon J., Chemla D. and Bonneville R., Adv. Phys.

27 609 (1978).

2

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