THETANGENCYOF SETS AND MONOTONICITY FUNCTION
Jerzy Grochulski
Institute of Mathematics and Computer Science, Czestochowa University of Technology
Abstract. The present paper deals with the connections between tangency relations of sets Tl(ai,bi,k,p) (l = 1,2) in the metric space (E,ρ) and monotonicity function l.
Let (E,ρ) be a metric space. Let the set
(
p t) {
x E(
p x)
t}
S , = ∈ :ρ , = (1)
denote the sphere with centre of the point p and the radius t, and
(
p t) {
x E(
p x)
t}
K , = ∈ :ρ , < (2)
denote the ball with centre of the point p and the radius t.The a set
( )
( )K
( )
q t rp S
r p S
t q ,
,
∈ ,
= U for t > 0 (3)
and
(
p r)
S(
p t)
S , t = , for t = 0 (4)
will be called the t - neighbourhood of the sphere. The E0 be the family of all non- -empty subset of set E.
Let a and b are non-negative real functions defined in a right-hand neighbour- hood of the point 0 such that
( )
r r→0+→0a and a
( )
r r→0+→0 (5) The pair (A,B) is (a,b) - concentrated at the point p if 0 is a concentration point of the set all real numbers r > 0 such that the sets A∩S(
p,r)
a( )r and B∩S(
p,r)
b( )rare non-empty.
Let l be a real non-negative function defined on the Cartesian product E0xE0 satisfying the condition
{ } { }
(
x y) (
x y)
l , =ρ , for x, y∈E (6)
The set A is (a,b) - tangent order k at the point p ∈ E to the set B if the pair (A,B) is (a,b) - concentrated at the point p and
(
( , ) , ( , ))
01
) 0 ( )
( ∩ →
∩
→ + r r b r
kl A S p r a B S p r
r (7)
where k is an arbitrary positive real number. The relation
( )
( ) ( )
∈ ∧ ∩ ∩ →
=
=
→ + 0
) , ( , ) , 1 (
, : ,
, , ,
) 0 ( )
(
0 k a r br r
l
r p S B r p S A r l E B A B A
p k b a T
(8)
will be called the relations of tangency of the set in the metric space (E,ρ). THEOREM 9. If 0 ≤ t1 ≤ t2, t1,t2 ∈ R (the R is set of real numbers), then
( ) ( )
2
1 ,
,r t S p r t p
S ⊂
Proof. Let t1 > 0 then and
( )
, 1
r t
p
x ∈S from (3) exists a point q∈S
(
p,r)
such that(
q,t1)
,K
x ∈ thereρ
(
q,x)
<t1≤t2 and so x ∈K(
p,t2)
to say(
,)
.t2
t q
x ∈S Let t1 = 0 then
(
,) (
,)
.1 S p r
r p
S t = Let x∈S
(
p,r)
to say ρ(
p,x)
=r and x ∈K(
p,t2)
, there- fore(
,)
.t2
t q
x ∈S This ends the proof.
THEOREM 10. If
(
A,B)
l(
C,B)
l ≤ for A⊂ C
(
A,B,C∈E0)
(11) and a1( )
r ≤a2( )
r for r > 0, then
(
A,B)
∈T1(
a2,b,k,p)
⇒(
A,B)
∈T1(
a1,b,k,p)
Proof. Let
(
A,B)
∈T1(
a2,b,k,p)
and a1( )
r ≤a2( )
r for r > 0. Then ( ) 01 0 →
→ + r
r
a
from here and from theorem (9)S
(
p r)
a( )r S(
p r)
a ( )r2
1 ,
, ⊂ for say
(
( ) ( ))
1(
( , ) ( ), ( , ) ( ))
) , ( , ) , 1 (
2 2
1r a r k a r br
k a l A S p r B S p r
r r p S B r p S A
r l ∩ ∩ ≤ ∩ ∩
from here
(
A,B)
∈T1(
a1,b,k,p)
. This ends the proof.Example 12. The function
(
A B) {
diam(
x B)
x A}
l5 , =sup { }∪ ; ∈
by diamA we shall denote the diameter of the set A, the A,B∈E0,satisfying the condition (6) and (11), therefore for
(
A,B)
∈T1(
a1,b,k,p)
⇒(
A,B)
∈T1(
a2,b,k,p)
THEOREM 13. If
(
A,B) (
l A,D)
l ≤ for B⊂D
(
A,B,D∈E0)
(14) and b1( )
r ≤b2( )
r for r > 0, then(
A,B)
∈T1(
a,b1,k,p)
⇐(
A,B)
∈T1(
a,b2,k,p)
Proof. Let
(
A,B)
∈T1(
a,b2,k,p)
and b1( )
r ≤b2( )
r for r > 0. Then ( ) 01 0 →
→ + r
r
b
from here and from theorem (9) S
(
p r)
b( )r S(
p r)
b ( )r2
1 ,
, ⊂ for say
(
( ) 1( ))
1(
( , ) ( ), ( , )2( ))
) , ( , ) , 1 (
r b r
k a r b r
k a l A S p r B S p r
r r p S B r p S A
r l ∩ ∩ ≤ ∩ ∩
from here
(
A,B)
∈T1(
a,b2,k,p)
. This ends the proof.Example 15. The function l7 by the formula
(
A B)
diam(
A B)
l7 , = ∪
satisfying the condition (6) and (14), therefore fora1
( )
r ≤a2( )
r as r > 0(
A,B)
∈T1(
a,b1,k,p)
⇐(
A,B)
∈T1(
a,b2,k,p)
THEOREM 16. If
(
A B)
l(
C B)
l , ≥ , for A⊂C
(
A,B,C∈E0)
(17) and a1( )
r ≤a2( )
r for r > 0 and( )
0,2 0 →
→ + r
r
a then
(
A,B)
∈T1(
a2,b,k,p)
⇒(
A,B)
∈T1(
a1,b,k,p)
Proof. Let
(
A,B)
∈T1(
a2,b,k,p)
and a1( )
r ≤a2( )
r for r > 0. Then( )
01 0 →
→ + r
r a from here and from theorem (9) S
(
p r)
a ( )r S(
p r)
a ( )r2
1 ,
, ⊂ for say
(
( ) ( ))
1(
( , ) ( ), ( , )( ))
) , ( , ) , 1 (
1 2
1r a r k a r b r
k a l A S p r B S p r
r r p S B r p S A
r l ∩ ∩ ≤ ∩ ∩
from here
(
A,B)
∈T1(
a2,b,k,p)
.This ends the proof.Example 18. The function l6 by the formula
(
A B) {
diam( { }
x B)
x A}
l6 , =inf ∪ ; ∈
satisfying the condition (6) and (14), therefore for a1(r)≤a2(r) as r > 0
(
A,B)
∈T1(
a,b1,k,p)
⇒(
A,B)
∈T1(
a,b2,k,p)
THEOREM 19. If
(
A B) (
l A D)
l , ≥ , for B⊂D
(
A,B,D∈E0)
(20) and b1( )
r ≤b2( )
r for r > 0 and( )
0,2 0 →
→ + r
r
b then
(
A,B)
∈T1(
a,b1,k,p)
⇒(
A,B)
∈T1(
a,b2,k,p)
Proof. Let
(
A,B)
∈T1(
a,b1,k,p)
and a1( )
r ≤a2( )
r for r > 0. Then from here and from theorem (9)S(
p r)
a( )r S(
p r)
a ( )r2
1 ,
, ⊂ for say
(
( ) 2( ))
1(
( , ) ( ), ( , )1( ))
) , ( , ) , 1 (
r b r
k a r b r
k a l A S p r B S p r
r r p S B r p S A
r l ∩ ∩ ≤ ∩ ∩
from here
(
A,B)
∈T1(
a2,b,k,p)
.This ends the proof.The metric ρ induces some li(x) defined by formulas:
} };
);
, ( inf{inf{
) ,
1(A B x y y B x A
l = ρ ∈ ∈
} };
);
, ( sup{inf{
) ,
2(A B x y y B x A
l = ρ ∈ ∈
} };
);
, ( inf{sup{
) ,
3(A B x y y B x A
l = ρ ∈ ∈
} };
);
, ( sup{sup{
) ,
4(A B x y y B x A
l = ρ ∈ ∈
}
; } { sup{
) ,
5(A B diam x B x A
l = ∪ ∈
} );
} ({
inf{
) ,
6(A B diam x B x A
l = ∪ ∈
(
A B)
diam B
A
l7( , )= ∪
The function l1 satisfying conditions (17) and (19). The function l2 satisfying con- dition (11) and (14). The function l3 satisfying condition (17) and (14). The func- tion l4 satisfying condition (11) and (14).
THEOREM 21. For A,B∈E0
(
A B) {
diamA diamBl(
A B) }
l8 , =max , , 4 ,
Proof. Let diam
(
A∪B)
=s<∞. Let theε >0, exist point x,y∈A∪B such as this(
x,y)
s.s−ε <ρ ≤ Then at least one inequality:
(
x y)
ss−ε<ρ , ≤ for x,y∈A
(
x y)
ss−ε<ρ , ≤ for x,y∈B s−ε<ρ
(
x,y)
≤s for x∈ ,A y∈B is true.From here diam
(
A∪B)
=diamA and diamB ≤diamA and l4(
A,B)
≤diamA or diam(
A∪B)
=diamB and diamA ≤diamB and l4(
A,B)
≤diamB else diam(
A∪B)
=l4(
A,B)
and diamA≤l4(
A,B)
and diamB≤l4(
A,B)
therefore
(
A B) {
diamA diamBl(
A B) }
diam ∪ = <
, 4
, max
Let diam
(
A∪ B)
=∞, then exist point x,y∈A∪B that such ρ(
x,y)
>N, where N is arbitrary positive real number, then at least one inequality: ρ(
x,y)
>N for, ,y A
x ∈ ρ
(
x,y)
>N for x,y∈B, ρ(
x,y)
>N for x∈A,y∈B. From here∞
diamA= or diamB=∞ else l4
(
A,B)
=∞. This ends the proof.THEOREM 22. For A,B∈E0 l9
(
A,B)
=max{
diam(
A,l3(
A,B) ) }
.Proof. Let the A =
{ }
x for a x ∈ to sayE diamA=0.Then from Theorem (21){ }
(
x B) {
diamB{ (
x y)
y B} }
diam ∪ =max ,sup ρ , ; ∈
Therefore
(
A B) { {
diamB{ (
x y)
y B} }
x A}
l7 , =inf max ,sup ρ , ; ∈ ; ∈ Let
( )
{ }
{ }
{
diamB,inf sup x,y;y∈B;x∈A}
=diamBmax ρ
that is
( )
{ }
{
sup x,y;y∈B;x∈}
≤diamBinf ρ
to say exist a point x ∈0 A such that sup
{
ρ(
x0,y)
;y∈B}
≤diamB. For an arbitrary point x ∈ A( )
{ }
{ }
{ }
( )
{ }
{
diamB x y y B}
diamB A x B y y x diamBdiamB
=
∈
≤
≤
∈
∉
≤
; , sup , max
;
; , sup , max
inf
ρ 0
ρ
Let
( )
{ }
{ }
{
diamB,inf sup x,y ;y∈B;x∈A}
=inf{
sup{ (
x,y)
;y∈B}
;x∈A}
max ρ ρ
then
( )
{ }
{
x y y∈B x∈A}
≥diamB≥ sup , ; ;
inf ρ
that is
( )
{
x,y;y∈B}
≥diamBsup ρ for x ∈ A
For arbitrary point x ∈ A
( )
{
x,y ;y∈B}
≤max{
diamB,sup{ (
x,y)
;y∈B} }
sup ρ ρ
from here
( )
{ }
{ } { { { ( ) } } }
( )
{ }
{
diamB x y y B} { (
x y)
y B}
A x B y y x diamB
A x B y y x
∈
≤
∈
≤
≤
∈
∈
=
∈
∈
; , sup
; , sup , max
;
; , sup , max
inf
;
; , sup inf
ρ ρ
ρ ρ
Therefore
( )
{ }
{
sup x,y;y∈B;∈A}
=inf{
max{
diamB,sup{ (
x,y)
;y∈B} }
;x∈A}
inf ρ ρ
This ends the proof.
References
[1] Gołąb S., Moszner Z., Sur le contact des courbes dans les espaces metrriques generaux, Colloq.
Math. 1963, 10, 305-311.
[2] Grochulski J., Konik T., Tkacz M., On the equivalence of certain relations of arcs in metric spaces, Demonstratio Math. 1978, 11, 261-271.
[3] Grochulski J., Some properties of tangency relations, Demonstratio Math. 1995, 28, 361-367.
[4] Grochulski J., Some connections between tangency relations, SIMI 2000, Wydawnictwo Politech- niki Częstochowskiej, Częstochowa 2000, 27-32.
[5] Waliszewski W., On the tangency of sets in generalized metric spaces, Ann. Polon. Math. 1973, 28, 275-284.