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Theaimof thispaperis tostudy H-harmoni fun tions, where H is a naturally de ned G-invariant real system of se ond order di erentialoperatorsonDwhi hannihilatespluriharmoni fun tions

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(1)

ALINE BONAMI 1

, DARIUSZ BURACZEWSKI 1;2

, EWA DAMEK 1;2

, ANDRZEJ

HULANICKI 1;2

, RICHARD PENNEY, AND BARTOSZ TROJAN 1;2

Abstra t. We onsiderhereageneralizationoftheHuasystemwhi hwasproved

byJohnsonandKoranyito hara terizePoisson-SzegointegralsforSiegeldomains

oftubetype. Weshowthatthesituationis ompletelydi erentwhendealingwith

nontubetypesymmetri irredu iblesymmetri domains: thenallfun tionswhi h

are annihilatedbythis se ond ordersystemand satisfyanH 2

typeintegrability

onditionarepluriharmoni fun tions.

1. Introdu tion

Let D be a bounded symmetri domain in C m

, and let G be the group of all

biholomorphi transformationsof D. Theaimof thispaperis tostudy H-harmoni

fun tions, where H is a naturally de ned G-invariant real system of se ond order

di erentialoperatorsonDwhi hannihilatespluriharmoni fun tions. ThesystemH

isde ned intermsofthe Kahlerstru tureof Dand makessenseoneveryKahlerian

manifold.

To de ne the system H, we re all some basi fa ts about D. Let T 1;0

(D) be the

holomorphi tangent bundle of D. The Riemannian onne tion r indu ed by the

Bergman metri onDpreservesT 1;0

(D)andsodoesthe urvaturetensor. ForZ;W

two omplex ve tor elds we denote by R (Z;W) = r

Z r

W r

W r

Z r

[Z ;W℄

the

urvature tensor restri ted toT 1;0

(D). Letf be asmooth fun tion onD and let

(Z;W)f =(ZW r

Z

W)f =(WZ r

W Z)f: (1)

Then (Z;W) may be seen as a se ond order operator whi h annihilates both

holomorphi and antiholomorphi fun tions, and onsequently, the pluriharmoni

fun tions. Conversely, ifall(Z;W)annihilatef, thenf ispluriharmoni . Indeed,

wehave (

z

j

;

z

k )=

z

j



z

k .

Let(; )bethe anoni alHermitianprodu tinT 1;0

(D). Fixingasmoothfun tion

f, we use ( ; ) to de ne a smooth se tion 

f

of the bundle of endomorphisms of

1

Thisworkwaspartlydonewithin theproje tTMR Network\Harmoni Analysis", ontra t

no. ERBFMRX-CT97-0159. Wethank the European Commissionand the mentionedNetwork

forthesupportprovided.

2

TheauthorswerepartlysupportedbyKBN grant2P03A04316,FoundationforPolishS ien es,

Subsidy 3/99.

(2)

T (D):

(f Z;W)=(W;Z)f; (2)

where Z;W are holomorphi ve tor elds. Then we de ne Hf as another smooth

se tion of the bundle of endomorphisms of T 1;0

(D) by

(Hf Z;W)=Tr (R (Z;W)





f

)=Tr(R (W;Z)

f ): (3)

To omputeexpli itlyHf,wemaytakeanorthonormalframeofse tionsofT 1;0

(D),

whi h we denoteE

1

;E

2

; ;E

m

. Then

Hf = X

j;k ((E

j

;E

k

)f)R (E

j

;E

k ): (4)

The system His,of ourse,a ontra tionofthe tensor eld 

f

. It isinvariantwith

respe t tobiholomorphisms, whi h means that

H(f Æ )= 1



[(Hf)Æ ℄

 (5)

for every biholomorphi transformation of D,



being itsdi erential.

By de nition, H-harmoni fun tions are fun tions whi h are annihilated by H.

We will onsider here symmetri Siegel domains, for whi h these notions are well

de ned sin e they are holomorphi ally equivalent to bounded domains. When D is

asymmetri Siegeldomainoftube type,(3)isequivalenttothe lassi alHuasystem.

Thissystemisknownto hara terizethePoisson-Szegointegrals(see[FK℄and[JK℄).

This means that a fun tion on D is H-harmoni if, and only if, it is the Poisson-

Szego integral of ahyperfun tiononthe Shilov boundary. Originally,the urvature

tensor was not expli it in the Hua system. For lassi al domains, the system has

been de ned by L. K. Hua as a \quantization"of the equation de ning the Shilov

boundary(see[Hu℄and[BV ℄). L.K.HuaprovedthatthesystemannihilatesPoisson-

Szego integrals. Thenthe system wasextended by K.Johnsonand A.Koranyi [JK℄

toallsymmetri tubetypedomainsandwaswrittendownintermsoftheenveloping

algebra of the semi-simple Liegroup of automorphisms of the domain. K. Johnson

and A. Koranyi proved not only that for all tube domains the system annihilates

the Poisson-Szego kernel, butalsothattheH-harmoni fun tionsare Poisson-Szego

integrals. Rewriting Johnson{Koranyi formula C(;



) in terms of the urvature

tensor, assuggested byNolanWalla h,one obtainsthe same system asabove. Itis

why we all Hthe Hua-Walla hsystem.

Noti e that (4) and (5) have a perfe t sense on any Kahlerian manifold, and,

for general Siegel domains, the system (4) has been already studied in [DHP℄. In

parti ular, for non tube symmetri Siegel both (4) and Johnson{Koranyi formula

C(;



) take the same form. In the work of N. Berline and M. Vergne [BV ℄ it is

observed thatC(;



)doesnotannihilatePoisson-Szegointegrals,andtheproblem

of des ribingC(;



){harmoni fun tionsisrisen. Hereweare goingtoanswertheir

(3)

Main Theorem. Let D be a symmetri irredu ible Siegel domain of type II, and

let F be an H-harmoni fun tion on D whi h satis es the growth ondition

sup

z2D Z

N()

jF(uz)j 2

du<1;

(H 2

)

whereN() isa nilpotentsubgroupof S whosea tionisparalleltothe Shilovbound-

ary. Then F ispluriharmoni .

This is in astriking ontrast to the ase when D isa symmetri tube domain. It

requires some omments.

The Poisson-Szego integrals on type II domains have been hara terized by N.

Berlineand M.Vergne[BV℄ aszerosof aG-invariantsystemwhi h,ingeneral,isof

the thirdorder. It is obtained by \quantization"of the Shilov boundary equations.

Theyalsoprovethatfordomainsoverthe oneofhermitianpositivede nitematri es

one anusease ondordersystem,

Z

,to hara terizePoisson-Szegointegrals. This

system appears already in the book by Hua [Hu℄. It is obtained from C(;



) by a

proje tion that eliminatesa part of the equations.

All this shows that the system H does not seem to be anoni al in any sense,

although it is de ned with the aid of the urvature tensor, ertainly an important

invariant, the geometri meaning of the system being still un lear. Our present

work suggests that it would be interesting to understand se ond order systems of

operatorson symmetri Siegel domains whi h are invariant under the full group of

biholomorphisms.

Inthe proofofthe maintheorem,weuseheavilythetheoryofharmoni fun tions

with respe t to subellipti operators on solvable Lie groups [R℄, [D℄, [DH℄, [DHP℄.

To do this, we identify the domain D with a solvable Lie group S  G that a ts

simply transitively on D. We then use a spe ial orthonormal frame of S-invariant

ve tor elds, E

1

;E

2

;;E

m

, to ompute the operator H by the formula (4). In

fa t, we only onsider the left-invariantse ond order ellipti operators built out of

the diagonalof H,

H

j

f =(HfE

j

;E

j ):

(6)

Ellipti operatorswhi hare linear ombinationsofoperators H

j

playthe main role

in our argument, and in parti ular the Lapla e-Beltrami operator , whi h is the

tra e of H. We represent H-harmoni fun tions as various Poisson integrals, and

weuse properties of these representations.

Linear ombinationsoftheoperators(E

j

;E

k

)havealreadybeenusedto hara -

terizepluriharmoni fun tions(see[DHMP℄). Weshouldemphasizethatthesystems

under study here are di erent from those of [DHMP ℄, and the proofs require new

ideas. Sin e a part of the onstru tion is the same in the two papers, we try to

simplify the presentation for the reader's onvenien e.

Our growth assumption (H 2

) is made mainly for te hni al reasons, L 2

harmoni

analysis being the easiest. We hope to be able to obtain similar on lusions for

(4)

however, a somewhat more deli ate te hni . In fa t, it is not lear that the on-

lusion requires any growth ondition at the boundary, and one may onje ture

that onlygrowth onditions atin nity are ne essary to insure pluriharmoni ityfor

H{harmoni fun tions on symmetri irredu ible Siegel domains of type II. On the

other hand, for tube type domains, one may onje ture that growth onditions on

derivatives atthe boundaryinsure pluriharmoni ity for H-harmoni fun tions as it

is the ase inthe unit ball([BBG℄) for -harmoni fun tions.

Finally,letusremark that,if wedonot insist oninvarian epropertiesof thesys-

tems onsidered, then itis always possible to hara terize pluriharmoni fun tions,

amongthefun tionswhi hareharmoni withrespe ttotheLapla e-Beltramioper-

ator , asthosewhi hareannihilatedbyasinglese ondorder operatorL(without

any growth ondition). Indeed,a lassi altheoremofForelli(seeRudin'sbook[Ru ℄)

asserts that every smooth fun tion in the unit ball whi h is annihilated by the op-

erator P

z

j z

k

 2

zjz

k

ispluriharmoni inthe ball. SoL an be taken as thisoperator

suitably translated,sothat afun tionwhi hisannihilatedby Lispluriharmoni in

the neihborhoodof apoint. Thenthe real-analyti ityof thefun tion, whi h follows

from the fa t that itis {harmoni ,insures its pluriharmoni ityeverywhere.

In view of Forelli's Theorem, it is not so mu h the small number of operators in

the system used to hara terizepluriharmoni fun tionsthan the stronginvarian e

properties ofthe systemitselfwhi hare relevant. Inthis ontext, thepresent paper

an be viewed as a omplementto [DHP℄ and[DHMP ℄.

2. Hua-Walla h systems

2.1. General Hua-Walla h systems. In this subse tion, D is a general domain

inC m

whi hisholomorphi allyequivalenttoabounded domain. Were allherethe

propertiesof theKahlerianstru turerelatedtotheBergmanmatri aswellassome

elementaryfa tsabouttheHua-Walla hsystem whi hwewilluse later. Thereader

may referto [He ℄ and [KN℄ formore details onthe prerequisites.

Let T be the tangent bundle for the omplex domain D, and let T C

be the

omplexi ed tangent bundle. The omplex stru ture J and the Bergman metri g

areextendedfromT toT C

by omplexlinearity. LetT 1;0

andT 0;1

betheeigenspa es

of J su hthat Jj

T

1;0 =iId ,Jj

T

0;1 = iId . Wehave

T C

=T 1;0

T 0;1

:

The onjugation operatorex hangesT 1;0

and T 0;1

.

Thespa esofsmoothse tionsofT,T C

,T 1;0

willbedenoted (T), (T C

), (T 1;0

),

respe tively. Smooth se tions of T 1;0

are alled holomorphi ve tor elds.

The Riemannian onne tion r isalso extended from (T) to (T C

) by omplex

linearity and, sin e r is de ned by a Kahlerian stru ture, it ommutes with J.

An immediate onsequen e is that r

Z

W belongs to (T 1;0

) (respe tively (T 0;1

))

1;0 0;1

(5)

(T ), we have that r

U

V =r

U V and

[U;V℄=r

U

V r

V U;: (7)

Therefore, for Z;W holomorphi ve tor elds,

r

W Z =

(1;0)

([W;Z℄);

(8)

where 

(1;0)

denotes the proje tion from T C

onto T 1;0

. The urvature tensor

R (U;V)=r

U r

V r

V r

U r

[U;V℄

preserves also T 1;0

and R (U;V)Z = R (U;V)Z. The restri tion of R (U;V) to T 1;0

is also denoted by R (U;V). On T 1;0

the Hermitian s alar produ t arising from the

Bergman metri is denoted by

(Z;W)= 1

2

g(Z;W):

ForU,V,Z,W holomorphi ve tor elds, we have

(R (V;U)Z;W)=(R (W;Z)U;V)=(U;R (Z;W)V): (9)

In parti ular,

R (W;Z)=R (Z;W)



: (10)

Letusnowgoba k tothe de nitions given intheintrodu tion. The identityZW

r

Z

W = WZ r

W

Z is a dire t onsequen e of (7). The fa t that all (Z;W)

annihilate pluriharmoni fun tions follows from (8) as well as from the identity

(

z

j

;

z

k )=

z

j



z

k

. Moreover,

(Z; W)f = (Z;W)f:

whi h means that 

f

is a tensor eld. The equality in (3) omes from (7), while

one proves (4)using (9) for (R (W;Z)E

k

;E

j ).

Let us now show invarian e of H

D

with respe t to biholomorphisms. Let be

a biholomorphismfrom D ontoD 0

, and



the holomorphi di erentialof whi h

maps T 1;0

D

ontoT 1;0

D 0

. Alltensor elds aretransportedby ,in luding, of ourse,the

Riemannian stru ture and the urvature tensor. Thus

R

D

(W;Z)= 1

 R

D 0

(

 W;

 Z)

 :

Moreover, for a smooth fun tion f on D 0

and g =f Æ , we have 

g

= 1





f

 .

So

(H

D

gZ;W)=Tr R

D 0

(

 W;

 Z)

f



whi h implies

H

D

g = 1

 (H

D 0

f)

 :

Finally, letus remark that, fromformulas (1), (3)and (10), it follows that 

f

=

(

f )



, and Hf = (Hf)



. So, to study H-harmoni fun tions, it is suÆ ient to

(6)

Wewantnowto omputeexpli itlythe Hua-Walla hoperatorforsymmetri irre-

du ibleSiegeldomains. Todoit,wewilluseFormula(4)foraparti ularorthonormal

basis E

1

;:::;E

m .

2.2. Preliminaries on irredu ible symmetri ones. Let be an irredu ible

symmetri one inanEu lideanspa e. Ouraimistodes ribepre isely thesolvable

groupthata ts simplytransitivelyon. Thegroupwillbeusedinthe onstru tion

of the orthonormal basis. We doit allin terms of Jordan algebras, and we refer to

the book of Faraut and Koranyi [FK℄ for these prerequisites, introdu inghere only

the notations and prin ipalresults that willbeneeded later.

A nitedimensional algebraV witha s alarprodu th;i isanEu lideanJordan

algebra if for allelementsx;y and z inV

xy=yx x(x

2

y)=x 2

(xy) hxy;zi=hy;xzi:

We denoteby L(x) the self-adjointendomorphismof V given by the multipli ation

by x, i.e. L(x)y =xy:

For an irredu ible symmetri one ontained in a linear spa e V of same di-

mension,the spa eV anbemadeasimplerealEu lideanJordanalgebrawithunit

elemente, so that

= intfx 2

: x2Vg:

Let G be the onne ted omponent of the group of all transformations in GL(V)

whi h leave invariant, and let G be its Lie algebra. Then G is a subspa e of the

spa e of endomorphisms of V whi h ontains all L(x) for all x 2 V, as well as all

x2y forx;y 2V,where x2y=L(xy)+[L(x);L(y)℄(see [FK℄ for these properties).

We x aJordan framef

1

;:::;

r

ginV,that is,a omplete system oforthogonal

primitive idempotents:

2

i

=

i

;

i

j

=0 ifi6=j;

1

+:::+

r

=e

and none of the

1

;:::;

r

is a sum of two non-zero idempotents. Let us re all that

the length r is independent of the hoi e of the Jordanframe. It is alled the rank

of V. To have anexample inmind, one may thinkof the spa e V of the symmetri

rr matri esendowed withthe symmetrizedprodu tofmatri es 1

2

(xy+yx). Then

the orresponding one is the set of symmetri positive de niterr matri es, the

set ofdiagonalmatri eswith allentries equalto0ex ept forone equalto1 being a

Jordan frame.

The Peir e de omposition of V related to the Jordan frame f

1

;:::;

r

g ([FK℄,

Theorem IV.2.1)may be writtenas

V = M

1ijr V

ij : (11)

It is given by the ommon diagonalization of the self-adjoint endomorphims L(

j )

with respe t to their only eigenvalues 0, 1

2

, 1. In parti ular V

jj

= R

j

is the

eigenspa e of L( ) related to 1, and, for i < j, V is the interse tion of the

(7)

eigenspa es of L(

i

) and L(

j

) related to

2

. All V

ij

, for i < j, have the same

dimension d.

For ea h i < j, we x on e for all an orthonormal basis of V

ij

, whi h we note

fe

ij

g,with1 d. To simplifythe notation,wewrite e

ii

=

i

( takingonlythe

value 1). Then the system fe

ij

g, for i j and 1  dimV

ij

, is an orthonormal

basis of V.

Let usdenoteby A the abelian subalgebraof G onsisting of elementsH =L(a),

where

a = r

X

j=1 a

j

j 2

M

i V

ii :

We set 

j

the linear form on A given by 

j

(H) = a

j

. It is lear that the Peir e

de ompositiongivesalsoa simultaneous diagonalizationof all H2A, namely

Hx=L(a)x=



i

(H)+

j (H)

2

x x2V

ij : (12)

Let A = expA. Then A is an abelian group, and this is the Abelian group in the

Iwasawade ompositionofG. Wenowdes ribethenilpotentpartN

0

. ItsLiealgebra

N

0

is the spa e of elements X 2G su h that, for allij,

XV

ij



M

kl;(k;l )>(i;j) V

kl

;

where the pairs ordered lexi ographi ally. On e N

0

is de ned, we de ne S

0 as

the dire t sum N

0

A. The groups S

0

and N

0

are then obtained by taking the

exponentials. It follows from the de nition of N

0

that the matri es of elements of

S

0

and S

0

, in the orthonormalbasis fe

ij

g, are upper-triangular.

The solvable group S

0

a ts simply transitively on . This may be found in[FK℄

Chapter VI, aswellasthe pre isedes riptionofN

0

whi hwillbeneeded later. One

has

N

0

= M

i<jr N

ij

;

where

N

ij

=fz2

i

:z 2V

ij g:

This de omposition orresponds toadiagonalizationoftheadjointa tionofAsin e

[H;X℄=



j

(H) 

i (H)

2

X; X2 N

ij : (13)

Finally, letV C

=V +iV be the omplexi ationof V. We extend the a tion of G

C

(8)

2.3. Preliminaries on irredu ible symmetri Siegel domains of type II.

We onsider the Siegel domain de ned by anirredu ible symmetri one and an

additional omplex ve tor spa e Z together with a Hermitian symmetri bilinear

mapping

: ZZ !V C

;

su h that

(;)2 ;  2Z;

(;)=0 implies =0:

The Siegeldomain asso iatedwith these data is de ned as

D=f(;z)2ZV C

: =z (;)2g:

(14)

It is alled of tube type if Z is redu ed to f0g. Otherwise, it is alled of type II.

There is arepresentation  :S

0

3s 7!(s)2GL(Z) su h that

s(;w)=((s);(s)w); (15)

and su h that all automorphisms (s), for s 2 A, admit a joint diagonalization

(see [KW℄). To redu e notations, we shall as well denote by  the orresponding

representation of the algebraS

0

. ForX 2S

0

, (15) impliesthat

X(;w)=((X);w)+(;(X)w): (16)

As an easy onsequen e, one an prove that the onlypossible eigenvalues for(H),

with H 2A, are 

j

(H)=2, for j =1;:::;r. So wemay write

Z = r

M

j=1 Z

j

with the property that

(H)=



j (H)

2

;  2Z

j : (17)

Moreover, all the spa es Z

j

have the same dimension 1

. A proof of these two fa ts

may be found in [DHMP℄. We all  the dimension of Z

j

for j = 1;:::;r. Let us

remark, using (16) and (17), that for ;w 2 Z

j

, we have L(

j

)(;w) = (;w).

Therefore, (;w) = Q

j

(;w)

j

, for ;w 2 Z

j

. Moreover, h

j

;(;)i > 0 for

 2Z

j

and so the Hermitianform Q

j

is positive de niteonZ

j .

The representation  allows to onsider S

0

as a group of holomorphi automor-

phisms of D. More generally, the elements  2 Z, x 2 V and s 2 S

0

a t on D in

1

Infa t,thepresentstudygeneralizestoallhomogeneousSiegel domainsrelatedtoirredu ible

(9)

the following way:

(w;z)=(+w;z+2i(w;)+i(;));

x(w;z)=(w;z+x); (18)

s(w;z)=((s)w;sz):

We allN()thegroup orrespondingtothe rsttwoa tions,thatisN() =ZV

with the produ t

(;x)(

0

;x 0

)=(+ 0

;x+x 0

+2=(; 0

)):

(19)

All three a tions generate a solvable Liegroup

S=N()S

0

=N()N

0

A =NA;

whi h identi es with a group of holomorphi automorphisms a ting simply transi-

tively on D. The group N(), that is two-step nilpotent, is a normal subgroup of

S. The Lie algebraS of S admitsthe de omposition

S =N()S

0

=



r

M

j=1 Z

j







M

ij V

ij







M

i<j N

ij



A:

(20)

Moreover, by (12), (13) and (17), one knows the adjoint a tionof elementsH 2A:

[H;X℄=



j (H)

2

X for X 2Z

j

;

[H;X℄=



i

(H)+

j (H)

2

X for X2V

ij

; (21)

[H;X℄=



j

(H) 

i (H)

2

X for X 2N

ij :

Sin eS a tssimplytransitivelyonthedomainD,wemayidentifySandD. More

pre isely, we de ne

 :S 3s7!(s)=se2D;

(22)

where e is the point (0;ie) in D. The Lie algebra S is then identi ed with the

tangent spa e of D at e using the di erential d

e

. We identify e with the unit

element of S. We then transport both the Bergman metri g and the omplex

stru ture J from D to S, where they be ome left-invariant tensor elds on S. We

still write J for the omplex stru ture on S. Moreover, the omplexi ed tangent

spa e T C

e

is identi edwith the omplexi ationof S, whi h we denoteby S C

. The

de ompositionT C

e

=T (1;0)

e

T (0;1)

e

istransported into

S C

=QP: (23)

Elements of S C

are identi ed with left invariant ve tor elds on S, and are alled

left invariant holomorphi ve tor elds when they belong to Q. The onjugation

operator ex hanges Q and P, while the transported operator J oin ides with iId

(10)

seen as a Hermitian form on Q, and orthonormality for left invariant holomorphi

ve tor elds means orthonormality for the orresponding elements inQ.

Now, let us onstru t an orthonormal basis of left invariant holomorphi ve tor

elds. We rst build a basis in S. To do this, we use the de omposition given in

(20) and give a basis forea h blo k.

Wehavealready xedanorthonormalbasisfe

jk

ginV orrespondingtothePeir e

de omposition hosen. Forj <k and 1 d, wede neX

jk 2V

jk andY

jk 2N

jk

astheleft-invariantve tor eldsonS orrespondingtoe

jk

and2e

jk 2

j

,respe tively.

Forea hj wede neX

j

andH

j

astheleft-invariantve tor eldsonS orresponding

to

j 2V

jj

andL(

j

)2A, respe tively. It remainsto hoose a basisof ea hZ

j . We

hoose fore

j

anorthonormalbasis of Z

j

relatedto4Q

j

, whereQ

j

is the quadrati

form de ned above. Forz

j

= x

j +iy

j

the orresponding oordinates, we de ne

X

j

;Y

j

as the left-invariant ve tor elds onS whi h oin idewith 

xj

and 

yj at

e.

Finally, wede ne

Z

j

=X

j iH

j

; Z

jk

=X

jk iY

jk

; Z

j

=X

j iY

j :

We an nowstate the following lemma.

Lemma 2.1. The left invariant ve tor elds Z

j

, for j = 1;;r, Z

jk

, for j <

k  r and = 1; ;d, and Z

j

for j = 1; ;r and = 1; ;, onstitute an

orthonormal basis of holomorphi left invariantve tor elds.

Proof. This lemma is already ontained in [DHMP ℄, to whi h we refer for details.

Toprove thatZ

j ,Z

jk

,and Z

j

are holomorphi ve tor elds,itissuÆ ient toprove

that

J(X

j )=H

j

; J(X

jk )=Y

jk

; J(X

j )=Y

j :

To do this, we ompute the image of the ve tor elds X

j

;H

j

;X

jk

;Y

ij

;X

j

, and Y

j

by the di erential d

e

. We nd the following tangent ve tors at e: 

x

jj , 

y

jj , 

x

jk ,



y

jk ,

x

j

, and

y

j

. Here the oordinates thatwehaveused inZV C

aregiven by

(;z)=



X

j;

(x

j +iy

j )e

j

; X

ij;

(x

ij +iy

ij )e

ij



:

The assertionfollows aton e, using the omplex stru ture in ZV C

.

To show orthonormality, it is possible to use Koszul's formula whi h allows to

get the Bergman metri from the adjointa tion. This is done in [DHMP℄, Lemma

(1.18). 2

2.4. Hua-Walla h systems for irredu ible symmetri Siegel domains. We

now ompute the operator H in the orthonormal basis that we have built in the

previous subse tion. Infa t,it isenoughto ompute thefollowingoperators, alled

strongly diagonal HW operators,and de ned by

H f =(Hf Z ;Z ) ; j =1;;r:

(11)

We have the following proposition.

Proposition 2.2. Thestrongly diagonal HW operators H

j are

H

j

= X

L

j +2

j +

X

k<j X



kj +

X

l >j X



jl

; (24)

where



j

=X 2

j +H

2

j H

j

L

j

=(X

j )

2

+(Y

j )

2

H

j (25)



ij

=(X

ij )

2

+(Y

ij )

2

H

j :

Proof. We rst ompute the urvature tensor R (Z;Z), with Z =Z

1

;;Z

r

. From

(8), weknowthat, for Z;W in Q,

r

Z

W =

Q

([Z;W℄)=

Q

([Z;(W +W)℄);

(26)

where 

Q

denotes the proje tion from S C

onto Q. We laim that

Lemma 2.3. The followingidentities hold:

r

Z

j Z

k

=iÆ

jk Z

j

r

Z

j Z

kl

= i

2 (Æ

l j Z

kj +Æ

kj Z

jl

) if k<l

r

Z

j Z

k

= i

2 Æ

jk Z

j :

Proof. In the omputation, we have seen that we may repla e the three left hand

sides of the formulas above by 2

Q ([Z

j

;X

k

℄), 2

Q ([Z

j

;X

kl

℄) and 2

Q ([Z

j

;X

k

℄), re-

spe tively. Moreover, if we repla e Z

j

by iH

j

inthese three expressions, we obtain

the righthand sides, by virtue of(21). Thus thelemma follows, on e weprovethat

all bra kets [Z

j

;X

k

℄, [Z

j

;X

kl

℄, and [Z

j

;X

k

℄ vanish. This last fa t follows from a

standard argument. One proves that ea h of these ve tor elds is annihilated by

all endomorphisms adH (H)Id, with H 2 A, for a value (H) that is not an

eigenvalue of adH forsome H. Soit vanishes. 2

Let usgo onwith the proof of the proposition. It is easyto dedu e the a tion of

r

Z

onQfromtheone ofr

Z

. Indeed,sin e the a tionofS preservesthe Hermitian

s alar produ t, and sin e Z is left-invariant,

0=Z (U;V)=(r

Z

U;V)+(U;r

Z V)

forany oupleU,V ofleft-invariantholomorphi ve tor elds. Sotheendomorphism

of Q de ned by r

Z

is the opposite of the adjointendomorphismde ned by r

Z . It

follows fromthe matrix representation given inthe lemma that they are equal, and

they ommute. So, forU 2Q,

R (Z

j

;Z

j

)U = r

[Z ;Z ℄

U = 2ir

Z U

(12)

sin e [Z

j

;Z

j

℄ = 2iX

j

= i(Z

j +Z

j

). Using again Lemma 2.3 and the expression of

Hf given in(4), we see that

H

j

= X

(Z

j

;Z

j

)+2(Z

j

;Z

j )+

X

k<j X

(Z

kj

;Z

kj )+

X

l >j X

(Z

jl

;Z

jl ):

Wereferto[DHMP℄ forthe omputationof(Z

j

;Z

j

),(Z

j

;Z

j

),and(Z

kj

;Z

kj ).

2

We also refer to [DHMP ℄ for the omputation of the Lapla e-Beltrami operator

,

= X

j



j +

X

k<j X



kj +

X

j;

L

j : (27)

Itisprovedin[DHP℄thattheLapla e-Beltramioperatoristhetra eoftheoperator

H.

All results, up to now, are also valid for the tube domain T

= V +i, whi h

identi es with the subgroup VS

0

of the group S and appears as a parti ular ase.

Left invariant di erential operators a t from the right. Therefore, we an identify

left invariantdi erential operators onthe tube domain with left invariantdi eren-

tial operators on the domain D itself. We add a subs ript or supers ript for su h

operators omingfromthetubedomain,and de neH T

j

,j =1;;r,and

T

asthe

operators omingfromthestronglydiagonalHW operatorsforthetubedomainand

the Lapla e-Beltrami operator,respe tively. Then, we have the following orollary,

the proof of whi h isimmediate:

Corollary 2.4. Thefollowing identities hold:

H T

j

=2

j +

X

k<j X



kj +

X

l >j X



jl

; (28)



T

= r

X

j=1 H

j

: (29)

2.5. Indu tion pro edure. We olle t in this subse tion some information and

some notations whi hwillbeused inallproofswhi h arebased onindu tiononthe

rank of the one. So, here, we assume that r>1. We rst de ne

A =linfL(

1

);:::;L(

r 1

)g and A +

=linfL(

r )g;

and, inananalogous way,

N

0

= M

i<jr 1 N

ij

and N +

0

= r 1

M

j=1 N

jr :

N +

0

is an ideal of N

0

, while N

0

is a subalgebra. Clearly A = A A +

and

N

0

=N N +

.

(13)

Next, we de ne A ;A ;N

0

;N

0

as the exponentials of the orresponding Lie

subalgebras. ThenS

0

=N

0

A isthe solvablegroup orrespondingtothe one ,

determined by the frame

1

; ;

r 1

, whi h is of rank r 1 as we wanted. The

underlying spa e V for is the subspa e

V =

M

1ij<r V

ij :

We willmake anextensive use of the fa t that

A =A A +

and N

0

=N

0 N

+

0

in the sense that the mappings

A A +

3(a ;a +

)7!a a +

2A;

and

N

0

N +

0

3(y ;y +

)7!y y +

2A

are di eomorphisms.

Now, let usde ne

Z =

r 1

M

j=1 Z

j :

Then it is easily seen that Z Z is mapped by  into the subspa e (V ) C

.

Moreover, (;)belongsto when 2Z . So, wemayde netheSiegeldomain

D as

D =f(;z)2Z (V ) C

: =z (;)2 g:

Let usde ne N() =Z V and

N() +

=Z

r

 M

jr V

jr :

Then, again, N() is a subalgebra and N() +

is an ideal of N(). We de ne

N() and N() +

as their exponentials. ThenN() isa semi-dire t produ t

N()=N() N() +

:

Clearly N() is the nilpotentstep two\boundary"group orresponding toD .

Finally, wewant to de ompose the group N. Let N =N() (N

0

) , and N +

=

N() +

(N

0 )

+

. Then N is a semi-dire t produ t N = N N +

. Moreover, the whole

group S may be writtenas

S =N N +

A A +

=N A N +

A +

:

(14)

3. Poisson integrals

The aimofthis se tionistoprove thefollowingpartialresultinviewof themain

theorem.

Theorem 3.1. Let F be a bounded fun tion on S annihilated by  and by H

j , for

j =1;:::;r. Then

H T

j

F =0 for j =1;:::;r;

and

L

j F =

X

L

j

F =0 for j =1;:::;r:

>From the formulas of the previous se tion, it is lear that a bounded fun tion

on the domain D whi h is H{harmoni satis es the assumptions. Moreover, the

rst statement implies the se ond one. To prove the rst one, we shall use the

hara terization of H{harmoni fun tions in terms of Poisson-Szego integrals on

tube domains. More pre isely,followingHua [Hu℄and [FK℄, itis suÆ ient toprove

that F, onsidered as a fun tion on the tube domain T

=V +i, is the Poisson-

Szego integral of some bounded fun tion on V. To do this, our main tool will be

the possibility to write F, in di erent ways, as a Poisson integral related to some

ellipti operators whi h annihilateF.

Letus rst givesomenotations. From the lastse tion,we knowthat every g 2S

may be written in a unique way as a produ t (;x)na, with (;x) 2 N() and

n 2 N

0

. We write  for the proje tion on N(), given by (g)= (;x), and ~ for

the proje tion on N, given by (g)~ =(;x)n.

We rst re allpreviousresultsof twoof theauthors. Even if they arevalidinthe

more general ontextof asemi-dire t produ t,we givethem inthe present ontext.

We onsider ellipti operatorswhi h may bewritten as

L = r

X

j=1

j L

j +

r

X

j=1

j H

T

j (30)

with

j

and

j

positive onstants. Then L is a sum of square of ve tor elds plus

a rst order term Z = Z(L), whi h is alled the drift, and may be written as

Z = P

j H

j

, with

j

=

j

+(2+(j 1)d)

j +d

P

k<j

k

. It follows from[DH℄

and [R℄that themaximalboundaryofL anbeeasily omputed (itdepends onthe

signs of 

j

(Z) 

i

(Z)for i <j). In parti ular, it is equal toN() if the sequen e

j

is a non{in reasing sequen e, and to N if it is an in reasing sequen e. Let us

summarize the results that weshall use inthe next proposition.

Proposition 3.2. Let L be givenby (30), and

j

as above.

(i) If L is su h that

j

is a non{in reasing sequen e, there is a unique positive,

bounded, smooth fun tion P

L

on N() with R

P

L

(y)dy = 1 su h that bounded

(15)

L-harmoni fun tions on S are in one-one orresponden e with L (N()) via the

Poisson integral

F(s)=P

L

f(s)= Z

N()

f((sw))P

L

(w) dw:

(31)

(ii)IfLissu hthat

j

isanin reasingsequen e, thereisauniquepositive,bounded,

smooth fun tion

~

P

L

onN with R

N

~

P

L

(y)dy=1su h thatboundedL-harmoni fun -

tions on S are in one-one orresponden e with L 1

(N) via the Poissonintegral

F(s)=

~

P

L

f(s)= Z

N

f(~(sy))

~

P

L

(y) dy:

(32)

Moreover, forea h given>0, wemay hoose the oeÆ ients

j

and

j

sothat (i)

holds, and that

Z

N()

(w)



P

L

(w) dw<1 (33)

where (w) is thedistan e of w from the unit elemente2N() with respe t to any

left{invariant Riemannian metri .

Aswesaid, (i)and(ii)maybefoundin[DH℄ and[R℄. Theintegrability ondition

may befound in[D℄, Theorem (3.10): asuÆ ient ondition for (33) is that

 X

2

j

(H

j )

2

+(Z)<0;

for all linear forms on A of the form  =



k +

p

2

;



k

2

. The fa t that this ondition

may besatis ed is elementary.

Wehave hosen toaddatilde every timethat weare on ernedwith anoperator

whose maximal boundary is the whole groupN. Wethen de ne P

L

asan integral,

P

L (w)=

Z

N0

~

P

L

(wy) dy:

(34)

Let usremark that, in this ase, the fun tions F whi h may be writtenas

F(s)=P

L

f(s)= Z

N()

f((sw))P

L

(w)dw;

(35)

with f a bounded fun tion on N(), onstitute a proper subspa e of the spa e of

bounded fun tions whi h are annihilated by L. It is in parti ular the ase for the

Lapla e-Beltrami operator, whi h is obtained for the values = 2 = 1, and has

maximal boundaryN.

The mainstep inthisse tionisthe nextproposition. Ithasbeen proved in[DHP℄

for general homogeneousSiegel domains(non ne essarilysymmetri ), and formore

general operators. However, in the ase of symmetri Siegel domains, whi h is the

ase under onsideration, the proof may be simpli ed onsiderably. We in lude it

(16)

Proposition 3.3. Let F be a bounded fun tion on S annihilated by  and by H

j ,

for j =1;:::;r. Then, there exists a bounded fun tion f on N() su h that F may

be written as

F(s)=P



f(s)= Z

N()

f((sw))P



(w) dw:

Proof. Wealready knowthat there exists somebounded fun tion

~

f onN su h that

F maybewrittenas

~

P



~

f. Moreover, wemayassumethat

~

f isa ontinuousfun tion

and provethat, inthis ase,f istherestri tionof

~

f onN(). Indeed, inthe general

ase, we onsider the sequen e of fun tionsF

m

de ned by

F

m (s)=

Z

N



m

(n)F(n 1

s) dn=

~

P

 (

m



~

f)(s):

with 

m

an approximate identity whi h is ompa tly supported and of lass C 1

.

Clearly F

m

tends to F pointwise. Let us assume that we have already proved the

propositionfor ontinuousfun tions. ThenF

m

=P

 (f

m

). Allthefun tions(f

m )are

boundedbykfk

L

1,sowe anextra ta



{weak onvergentsequen e whi h onverges

to f. Then P

 (f

m

) onverges to P



(f) pointwise. Hen e F =P

 f.

So, let

~

f be a bounded ontinuous fun tion on N, and let F =

~

P



~

f. To prove

the proposition, we want to prove that, for ea h xed w 2 N(), the fun tion

y 7!

~

f(wy) is onstant on N

0

. Indeed, assume that it is the ase and denote by f

the restri tion of

~

f toN(). Then,fors=wya withw2N(), n2N

0

anda2A,

we an write

F(wya)=

~

P



~

f(wya)= Z

N()N0

~

f(wyavua 1

)

~

P



(vu)dvdu;

= Z

N()N

0

f(wyava 1

y 1

)

~

P



(vu) dvdu;

=P



f(wya):

Let us nallyremark that it issuÆ ient to prove that y 7!

~

f(y) is onstant onN

0 .

Indeed, on e we have proved this, for ea h w 2N() we have the same on lusion

with F repla ed by

w

F, with

w

F(g) =F(wg)=

~

P

 (

w

~

f)(g). Again

w

~

f(y) =

~

f(wy)

is onstant, whi h we wanted to prove.

So, letus showthat y7!

~

f(y) is onstant onN

0

. Let usde ne

F

H

(wya)= Z

N0

~

f(yaua 1

)

Z

N()

~

P



(vu) dv



du:

(36)

We laim that

F

H

(g)= lim F((exptH)g);

(37)

(17)

where H is the ve tor eld H=

j=1 H

j

. Indeed, writing

F(g)= Z

N()N

0

~

f(~(gvu))

~

P



(vu) dvdu;

wehave

F((exptH)wya)=F(w

t y

t

aexptH)= Z

N()N

0

~

f(w

t y

t av

t u

t a

1

)

~

P



(vu)dvdu:

Foranelement g of N we have used the notation

g

t

=(exptH)g(exp( tH)):

It follows from (21) that u

t

= u for every u 2 N

0

, and that w

t

tends to the unit

element. This implies (37). We now laimthat

F

H

(wya)=F

H (ya) (38)

H

j F

H

=0 for j =1;:::;r and F

H

=0 (39)

HF

H

=0:

(40)

We have already proved (38). Then (39) follows from the fa t that left and right

translations ommute. So, for every t, F((exptH)g) is annihilated by the HW

operators and the Lapla ian. To see (40), we use again the fa t that u

t

= u for

every u2N

0

and the formula(36) toobtain that

F

H

(ya(exptH))=F

H (ya):

Then (40) follows aton e.

Finally, uniqueness in Proposition 33implies that y 7!

~

f(y) if and only if F

H is

onstant. Toprovethat F

H

is onstant,we onsider thefun tion Gde ned onN

0 A

by G(ya)=F

H

(ya). Then learly Gis annihilated by alloperators

D

j

= H

j

+2(H 2

j H

j )+

X

i<j X

((Y

ij )

2

H

j )+

X

j<kr X

((Y

jk )

2

H

k ) (41)

and by H. So, to omplete the proof,it is suÆ ientto prove the following lemma.

Lemma 3.4. Let G be a bounded fun tion on N

0

A whi h annihilated bythe opera-

tors H;D

1

;:::;D

r

. Then G is onstant.

Proof. There is nothing to prove when r = 1. For r = 2, let us remark that G,

whi h isannihilated by H

1 +H

2

, is alsoannihilated by H

1 H

2 sin e

(D

1 D

2

)G= (+2)(H

1 H

2

)G=0:

Therefore, H

1

G=0 and H

2

G=0 and so, G is a bounded fun tion onthe Abelian

group N

0

=R d

annihilated by the Lapla eoperator. Hen e G is onstant.

Let us now onsider r >2. We assume that the lemma has been proved with r

repla ed by r 1. We write G asa Poisson integralwith respe t to the operator

D= X

D ;

(18)

for whi hthedriftZ(D)isequaltoZ =

j H

j

,with

j

=(+2+(j 1)d)

j +

d P

k<j

k

. We rst remark that we may hoose the oeÆ ients

j

so that the

j

de rease for j  2 (when +2 > d, one an even nd a sequen e

j

su h that

j

isde reasing,and on lude dire tly sin eeveryD{harmoni bounded fun tionis

onstant). Withthis hoi e,the maximal boundaryof D isthe groupN

1

=expN

1 ,

with

N 1

=

j>1 N

1j :

Wealsode neN 1

=expN 1

, withN 1

=

1<i<jr N

ij

. Every yinN

0

an bewritten

in a unique way as y

1 y

0

, with y

1 2 N

1

and y 0

2 N 1

. We de ne 

1 by 

1

(ya) = y

1 .

Then, (see [DH℄),there exists fun tions

D

and  su hthat

G(ya)= Z

N1

(

1

(yau))

D

(u) du:

The fun tion  is bounded, and we an assume as before that it is ontinuous.

Usingnotationsofthe subse tion2.5. onthe indu tionpro edure, we analsowrite

y 2 N

0 as y

+

y . When y is in N

1

, then y +

belongs to N

1r

= expN

1r

. We shall

prove that (y) depends only on y +

. Again, to prove this, it is suÆ ient to prove

that (y ) is onstant. Indeed, on e we have proved this, we may apply it to

y +

(with

y

+(n)=(y +

n)), using the fun tion

y

+Gin pla e of G.

In order to prove that (y ) is onstant, let usde ne, asbefore,

G

#

(ya)= lim

t! 1

G((exptH

r )ya)

= lim

t! 1 Z

N1

(

1 (y (y

+

)

t au (u

+

)

t a

1

))

D (u

+

u ) du +

du

= Z

N

1

(

1

(y au a 1

))

D (u

+

u ) du +

du :

Here u

t

= (exptH

r

)u(exp( tH

r

)). We have used the fa t that (y )

t

= y , and

(y +

)

t

tends to the unit element. We have

G

#

(y y +

a a +

)=G

#

(y a )=G

#

(y +

y a a +

)

D

#

j G

#

=0; for j =1;:::;r 1;

H

#

G

#

=0;

where H

#

=H

1 +H

2

++H

r 1

, and, forj =1;:::;r 1,

D

#

j

=2H 2

j

(+2)H

j +

X

i<j ((Y

ij )

2

H

j )+

X

j<kr 1 X

((Y

jk )

2

H

k ):

From the indu tion hypothesis, we on lude that G

#

is onstant. So (y ) is also

onstant. Hen e (y) = (y +

), and, using obvious notations, we on lude that G

may infa t be writtenas

G(ya)= Z

N1r

(

1r

(yau))

D

(u)du:

(19)

Sin e exptH

j

ommutes with elementsof N

1r

for j =2;r 1, we on lude that

H

j

G=0. So(H

1 +H

r

)G=0. Moreover,

D

1 G=



2H 2

1

(+2)H

1 +

X

((Y

1r )

2

H

r )



G=0

D

r G=



2H 2

r

(+2+(r 2)d)H

r +

X

((Y

1r )

2

H

r )



G=0;

whi h, asin the ase r=2, impliesthat G is onstant. 2

On e we have on luded forthe lemma,we on lude for the proposition 3.3. 2

Our next step is the followingtheorem.

Theorem 3.5. Let f be a bounded fun tion on N() and let F = P



f. Assume

that



T

F =0:

Then

F((;x)ya)= Z

V f



(xyava 1

y 1

)p(v) dv;

(42)

wheref



(x)=f(;x)andpisthePoisson-SzegokernelforthetubedomainV+i.

Proof. Usingthe same kindof proofasin the lastproposition,wemay assumethat

f is ontinuous. The maximal boundary for 

T

onsidered as anoperator onVS

0

is VN

0

. Letp~be the orresponding kernel on VN

0

. Thenthe fun tionF



,whi h is

de ned for  2Z xed by F((;x)s)=F



(xs), may be writtenas

F



(xya)= Z

VN

0 g



(xyavua 1

))p(vu)~ dvdu;

(43)

where v 2V, u2N

0 .

We have also

F



(xya)=P



f((;x)ya)= Z

N()

f((;x)ya(;v)a 1

y 1

)P



(;v)ddv:

Let a

t

=expt(

P

r

j=1 jH

j

). Then, onone hand,

lim

t! 1 F

 (xya

t )=g

 (xy)

in *-weaktopology onL 1

(VN

0

)and on the other,

lim

t! 1 F

 (xya

t

)=f(;x);

pointwise. Hen e g



(xy)=f(;x)=f



(x). Therefore,

F



(xya)= Z

VN0 f



(xyava 1

aua 1

)~p(vu) dvdu;

= Z

V f



(xyava 1

y 1

)(

Z

N0

~

p(vu)du) dv:

(20)

It remains to prove that it is also equal to the right hand side of (42). But this

last expression is a

T

{harmoni fun tion (sin e the Poisson{Szgego kernel is 

T {

harmoni ), with the sameboundary values onVN

0

. This proves (42). 2

Proof of Theorem 3.1. Again, using Proposition 3.3, we may assume that F =

P



f. Moreover, we may assume that f is ontinuous, using the same tri k as in

the proof of Proposition 3.3. So, it follows from Theorem 3.5 that F



is a Poisson-

Szegointegralonthetubedomain. Weknowfrom[Hu ℄and[JK℄thatPoisson-Szego

integrals on symmetri tube domains are annihilated by Hua operators, i.e. in our

situation F



is annihilatedby H T

j

. This nishes the proof. 2

4. The proof of pluriharmoni ity

In thisse tionweprovethefollowingstatement, whi himpliesthemaintheorem:

Theorem 4.1. Assume that

sup

s2S

0 Z

N()

jF (;x)s



j 2

ddx<1 (44)

and

F =H

1

F =:::=H

r

F =0:

(45)

Then F is pluriharmoni .

We rst laim that the results of the lastse tion on bounded fun tions apply to

(H 2

) growth onditions. Indeed, wehave thefollowinglemma. Here Lis anellipti

operatoras in(30),

L= r

X

j=1

j L

j +

r

X

j=1

j H

T

j

;

with oeÆ ients hosen so that it has maximal boundary N() and satis es the

integrability ondition (33) forsome  tobe hosen later.

Lemma 4.2. A fun tion F whi h satis es(44) and (45) maybe written as a Pois-

son integral

F(g)= Z

N()

f((gw))P

L

(w) dw; f 2L 2

(N()); g 2S:

(46)

Proof. We redu e to bounded fun tions by onvolving F from the left. More pre-

isely,let 

n 2C

1

(N()) be anapproximate identity, and let

F

n (g)=

Z

N()



n

(w)F(w 1

g) dw:

Then F

n

is bounded, and satis es (45). Soit follows fromthe lastse tion that

F

n (g)=

Z

f

n

((gw))P

L

(w)dw;

(21)

for anf

n

2 L (N()). Moreover, f

n

, whi h may be obtained as a {weak limit in

L 1

,whent! 1,ofF

n

(exptH)aswellasaweaklimitinL 2

(N()),isuniformly

in L 2

. Hen e,

kf

n k

L 2

(N())

sup

s Z

N()

jF(ws)j 2

dw

Wemay take forf 2L 2

(N()) the weak limitof asubsequen e, andget (46). This

on ludes the proof of the lemma. 2

To prove Theorem 4.1, we may assume that F = P

L

f as above. Moreover,

eventually onvolvingf inthegroupN()withaC 1

ompa tlysupportedfun tion

as in the lastse tion,wemay assume that

Assumption on f: itmay be writtenas

~

f where  isa C 1

ompa tly supported

fun tion.

Atthispoint,ourmaintoolwillbeharmoni analysisofthenilpotentgroupN().

On e we haveproved that the Fourier transformof f vanishesoutside [ , one

on ludes easilylikein [DHMP ℄.

Letus rstre allsomebasi fa tsaboutFourieranalysisonN(),following[OV℄.

Let ( ; ) be the Hermitians alar produ t on Z for whi h the basis e

j

, whi h was

introdu edinsubse tion 2.3, isorthonormal. It oin ides with4Q

j

onea hZ

j ,and

thesesubspa esarepairwiseorthogonal. Forea h2V,letusde netheHermitian

transformation M



:Z !Z by

4h;(;!)i=(M



;!); ;! 2Z:

and onsider the set

=f2V :detM

 6=0g

forwhi htheaboveHermitianformisnondegenerate. Remarkthatitisinparti ular

the ase for  2 sin e we assumed that (;) belongs to nf0g for all  6= 0.

The same is valid for  2 . So detM



, whi h is a polynomial of , does not

vanish identi ally, and  is an open set of full measure. It arries the Plan herel

measure (see [OV℄), given by

()d =jdetM

 jd:

Let us des ribe the Fo k representation asso iated to  2 . For every  2  we

de ne a omplex stru ture J



, whi h determines the representation spa e H

 . Let

jM



jbethe positive Hermitiantransformation su h that jM

 j

2

=M 2



. Then

J



=ijM

 j

1

M

 :

If 2thenJ



=iI =J oin ides withthe ordinary omplexstru ture inZ. For

general , the omplex stru ture J



has a ni e des ription in anappropriate basis.

Namely, there is a -measurable hoi e of an ( ; ) orthogonal basis e



1

;:::;e



m su h

that

H

 (e



;e



)=

j Æ

jk

(22)

with 

j

=1(dependingonand lo ally onstant). Inthe basise

1

;:::;e

m

;Je

1

;:::,

Je



m

of Z over R we have

J

 (e



j )=

j (Je



j

) and J

 (Je



j

)= 

j e



j :

Let

B



==H

 :

A dire t al ulation shows that

B

 (J

 e



j

;e



k )=Æ

jk

and so

B

 (J



;)>0 if  6=0:

We de ne H



as the set of all C 1

fun tions F on Z whi h are holomorphi with

respe t tothe omplex stru ture J



and su h that

F()() 1

2

e



2 B

 (J



;)

2L 2

(Z;dz):

Here dz is the Lebesgue measure related tothe s alar produ t (;)on Z.

The spa e H



isa Hilbert spa e for the s alar produ t

(F

1

;F

2 )



= Z

Z F

1 ()



F

2 ()e

B

 (J



;)

()d:

The Fo k representation U



, whi h is a unitary and irredu ible representation on

H



,is given by

U



(;x)F(!)=e

2ih;xi



2 jj

2

+!





F(! ); (47)

with !



 = B

 (J



!;)+iB



(!;) and jj 2

= 



. Then the Fourier transform of

f 2L 1

(N()), whi h we note U



f

, isde ned asthe operatoronH



given by

(U



f F;G)



= Z

N()

f(;x)(U



(;x) F;G)

 dx:

If f 2L 1

(N())\L 2

(N()), then the Plan herel theorem says that

Z

V kU



f k

2

HS

()d=kfk 2

L 2

(N()) :

It followsthat, for f 2L 2

(N()),U



f

isde ned for almostevery  andisa Hilbert-

S hmidt operator.

NowwewriteanorthonormalbasisofH



,whi h hangesmeasurably with. For

 2Z, wenote 

j;

its oordinates inthe basis e



j

,so that, inparti ular,

B

 (J



;)= X

j j

j;

j 2

:

Given a multi-index =(

1

;:::;

m ), let





=

 j j

2

p

! Y



j (1+

j )

2

j;





j (1 

j )

2

j;

;

(23)

Then every 

is holomorphi with respe t to the omplex stru ture J



and the

family f



g formsa (; )



- orthonormalbasis. Indeed, one may verify that

(



;



)



=

 j j+j j

2

p

! ! Y

j Z

C u

j (1+

j )

2

 u

j (1 

j )

2

 u j

(1+

j )

2

u j

(1 

j )

2

e

juj 2

du:

We nallyde ne, for f 2L 2

(N() and almost every ,

^

f(; ; )=(U



f





;



): (48)

We may nowgivethe main step of the proof.

Lemma 4.3. Let F = P

L

f a fun tion whi h satis es the assumptions of Theorem

4.1, with L and f 2 L 2

(N()) hosen as above. Then, for almost every  and for

all , , we have

^

f(; ; )=0 for 2=



[



: (49)

ProofofTheorem 4.1. Forthe moment,wetakethelemmaforgranted and nish

the proof of Theorem 4.1. Let us rst give some notations. For s 2S

0

, we note F

s

the fun tionde ned onN() by

F

s

(;x)=F((;x)s) (50)

and

^

F(; ; ;s)its Fourier transform. We laim that

^

F(; ; ;s)=e

2h;sei

(U



f



;

); for a.e 2



;

=e 2h;sei

(U



f



;

); fora.e 2



; (51)

=0; for a.e 2=



[



:

Indeed, we know from Theorem 3.5 that F may be written as a Poisson-Szego

integral,i.e.

F((;x)s)= Z

V f

 (xsvs

1

)p(v) dv= Z

V

f(;x u)p

s

(u)du;

with p

s

de ned by

p

s

(u)=det(s 1

)p(s 1

u):

Here the element s 1

is onsidered as a ting on V. If f 2 L 1

(N())\L 2

(N()),

then

(U



Fs



;

)=

Z

N() Z

V

f(;x u)p

s (u)(U



(;x)



;

)duddx

= Z

V (U



f U



(0;u)



;

)p

s (u)du

=(U



f



;

)

Z

e

2ih;ui

p

s

(u) du:

(24)

These formulas are still valid for a general fun tion f 2 L (N()): only use an

approximation of f and the Plan herel theorem.

It remains to al ulate the Fourier transform of p

s

for  2



[



. We shall

do this for  2



. For  2



the proof is analogous. If  2



we onsider the

bounded holomorphi fun tionon V +igiven by

G(z)=e 2ih;zi

=e

2ih;x+isei

=e

2ih;xi 2h;sei

:

Then G is the Poisson integral of its boundary value, i.e.

G(z)= Z

V e

2ih;x ui

p

s

(u)du:

Therefore,

G(ise)=e

2h;sei

= Z

V e

2ih;ui

p

s

(u) du:

Finally, for 2



, we have

(U



Fs



;

)=e

2h;sei

(U



f



;

):

From (51), a dire t omputation (see [DHMP ℄ for the details) shows that 

j F =0

for j = 1;:::;r. Moreover, we already know that L

j

F = 0. Then it follows from

Theorem 3.1 in[DHMP℄ thatF isthe real part of anH 2

holomorphi fun tion. 2

Proofof Lemma 4.3. It remainsto prove the lemma. Letus remark that thereis

nothing to prove for r =1. So the theorem is ompletely proved in this ase. For

r >1, we an make the assumption that the theorem is valid for r 1, and prove

the lemmawith this additionalindu tionhypothesis.

Weuseagainthenotationsofthesubse tion2.5. fortheindu tionpro edure. An

elementa 2A will be writtenas a=a 0

a +

, a 0

2A , a 0

2 A +

. We allS 0

0

the group

N

0

A , and S 0

the group NA . Fors2S

0

, we may write s=ya=ya 0

a +

=s 0

a +

.

Wede neanewfun tionF 0

onS 0

byalimitpro ess. Morepre isely,for(;x)s 0

2

S 0

, we de ne

F 0

((;x)s 0

)=F 0

s 0

(;x)= lim

t! 1

F((;x)s 0

exptH

r ):

(52)

Using the same arguments as before, as well as our assumptions on the boundary

value f of F, one an see that this limitexists and is given by

F 0

s 0

(;x)= Z

N()

f((;x)s 0

w (s 0

) 1

)P 0

L

(w )dw ;

where

P 0

L

(w )= Z

N() +

P

L (w w

+

) dw +

:

We are now able to give a sket h of the proof. The fun tion f may be seen as the

boundary value of F 0

. So, we will onsider the Fourier transform of F 0

s 0

. Using the

indu tion hypothesis forallfun tions

w +F

0

,de ned onS by

w +F

0

(s )=F(w +

s ),

wewillshowthat +F 0

arepluriharmoni . This impliesfortheir Fouriertransforms

(25)

to satisfy a di erential equation with initial data f(; ; ). Then smoothness of

the Fourier transformwillfor e this fun tion tobe zero for 2=



[



.

Our main work will be to show the smoothness of Fourier transforms, and will

ask for many te hni alities.

Step 1: F 0

isa smooth fun tion of arbitrary orderon S 0

.

Proof. First, let W be a right-invariant di erential operator on N(). We know

from the assumptions on f that Wf is well de ned, and bounded. Therefore, we

have

WF 0

s 0

(;x)= Z

N()

Wf((;x)s 0

w (s 0

) 1

)P 0

L

(w )dw :

Moreover, partial derivatives of f grow at most polynomially. The a tion of s 0

is

linear, hen e there are onstants C( ;K) and M( ) su h that

j

s

0f((;x)s 0

w (s 0

) 1

)jC( ;K)(1+(w )) M( )

for (;x)s 0

belonging to a ompa t set K  S 0

, with  any left{invariant distan e

as in (33). Now we sele t  su h that P

L

integrates the right hand side above, to

obtain

Z

N() j

s 0

f((;x)s 0

w (s 0

) 1

)jP 0

L

(w ) dw <1

whi h allows todi erentiate F 0

with respe t tos 0

. 2

Step 2: the fun tion

w +F

0

satis es the indu tion hypothesis onS .

Proof. We laim rst that the assumption (44), with S in pla e of S, is satis ed

for almost every w +

. Indeed, itis suÆ ient toprove that

sup

s 0

2S 0

0 kF

0

s 0

k

L 2

(N())

<1:

(53)

This follows from the fa t that, for every s 0

2S 0

0

, the fun tion F(s 0

exptH

r

) has a

weaklimitin L 2

(N()) when t tends to 1. Indeed, for 2L 2

(N()),

I = Z

N() (F(ws

0

exp (t

1 H

r

)) F(ws 0

exp (t

2 H

r

)))(w) dw

= Z

N() Z

N() (f(wv

1

) f(wv

2 )P

L

(v)(w) dv dw

with v

j

= s 0

exp (t

j H

r )v(s

0

exp (t

j H

r ))

1

for j = 1;2. Integrating with respe t to v

over a ompa t set K and over its omplement weget

I sup

v2K kf(v

1

) f(v

2 )k

L 2

(N()) kk

L 2

(N())

+2kfk

L 2

(N()) kk

L 2

(N()) Z

K

P

L

(v)dv;

whi h tends tozero when t

1

;t

2

! 1.

We now prove that the fun tions

w +F

0

satisfy the ondition (45), again with

+

(26)

element. Noti e that the operators L

j

;

j

and 

kj

have a perfe t sense as left-

invariantoperators onS asfar asindi es are smaller than r . Let

(H 0

j )

T

=2

j +

X

k<j X



kj +

X

j<k<r X



jk :

Again(H 0

j )

T

may be onsidered asoperatorsboth onS and S . In the se ond ase

(H 0

1 )

T

;:::;(H 0

r 1 )

T

are HW operators for the tube V +i . We want to prove

that, for j =1; ;r 1,we have

L

j F

0

=(H 0

j )

T

F 0

=0:

Sin e for i<j <r, L

j , 

ij

, and 

j

ommute withA +

, we have,for g 0

2S 0

,

lim

t! 1 L

j F(g

0

exptH

r )=L

j F

0

(g 0

)

lim

t! 1



j F(g

0

exptH

r )=

j F

0

(g 0

)

lim

t! 1



ij F(g

0

exptH

r )=

ij F

0

(g 0

);

By hypothesis, F satis es(45). Sowe on lude dire tly for L

j F

0

, j =1;;r 1.

For(H 0

j )

T

F 0

, we on lude alsoon e we knowthat

lim

t! 1



jr F(g

0

exptH

r )=0 (54)

Before doing it, we give a last de nition. We note

~

X

jk ,

~

Y

jk , and

~

X

j ,

~

Y

j

the left-

invariant ve tor elds on N whi h oin ide, at the unit element of N, with the

orrespondingelementsofthe basis ofN thatwe onstru ted insubse tion2.3. We

de ne as well

~

L

r

= P

(

~

X

r )

2

+(

~

Y

r )

2

.

In the next omputation, we identify an element a with a n-uple (a

1

;a

2

;a

r ),

with a

j

>0,insu h away that a is the exponentialof P

j (loga

j )H

j

. Inparti ular,

an element a +

2 A +

identi es with a s alar, whi h we note a

r

for omprehension.

With these notations, the previous limitsare obtained for a

r

tendingto 0.

Then, it follows from the fa t that L

r

F =0 and a dire t omputationthat



a

r F(g

0

a

r )=

~

L

r F(g

0

a

r ):

Moreover,



jr F(g

0

a

r )=a

r



X

j<r X

a

j (

~

X

jr )

2

+a 1

j (

~

Y

jr )

2 1



~

L

r



F(g 0

a

r )!0

when a

r

! 0. This nishes the proof of (54), as well as the laim of this step.

Indeed, for almost w +

, the fun tion

w +F

0

is pluriharmoni as a fun tion on S 0

. It

follows that 

1 F

0

vanishes identi ally. This is the main point whi h will be used

later. 2

^

0 0 0

Cytaty

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