A NOTE ON DOMINATION PARAMETERS OF THE CONJUNCTION OF TWO SPECIAL GRAPHS
Maciej Zwierzchowski Institute of Mathematics University of Technology of Szczecin al. Piast´ow 48/49, 70–310 Szczecin, Poland
e-mail: mzwierz@arcadia.tuniv.szczecin.pl
Abstract
A dominating set D of G is called a split dominating set of G if the subgraph induced by the subset V (G) − D is disconnected. The cardinality of a minimum split dominating set is called the minimum split domination number of G. Such subset and such number was intro- duced in [4]. In [2], [3] the authors estimated the domination number of products of graphs. More precisely, they were study products of paths.
Inspired by those results we give another estimation of the domination number of the conjunction (the cross product) P
n∧ G. The split dom- ination number of P
n∧ G also is determined. To estimate this number we use the minimum connected domination number γ
c(G).
Keywords: domination parameters, conjunction of graphs.
2000 Mathematics Subject Classification: 05C69.
1. Definitions and Notations
In this paper we discuss finite connected, undirected simple graphs. For any graph G we denote V (G) and E(G), the vertex set of G and the edge set of G, respectively. We say that G is of order n if n is a cardinality of V (G). By hXi
Gwe denote a subgraph of G which is induced by a subset X ⊂ V (G).
A hanging vertex is a vertex of G adjacent to exactly one vertex in G. The
complement of G is denoted by G. A subset D ⊆ V (G) is a dominating set
of G if for every x ∈ V (G) − D there is a vertex y ∈ D such that xy ∈ E(G).
We will also write that x is dominated by D or by y in G.
In [4] it was introduced the notion of split dominating set of a graph.
We say that a dominating set D ⊆ V (G) is a split dominating set of G if the induced subgraph hV (G) − Di
Gis disconnected. A dominating set D ⊆ V (G) is a connected dominating set of G, (see [5]) if the induced subgraph hDi
Gis connected. The domination number [the split domination number, the connected domination number] of a graph G, denoted by γ(G), [γ
s(G), γ
c(G)] is the cardinality of a minimum dominating [a minimum split dominating, a minimum connected dominating] set of G. It is easy to see that γ(G) ≤ γ
s(G) and also γ(G) ≤ γ
c(G). A dominating set D is called a γ(G)- set [γ
s(G)-set, γ
c(G)-set] if D realizes the domination [split domination, connected domination] number, respectively. Note that there exists a γ
c(G)- set if and only if G is connected. The conjunction of two graphs G and H is a graph G∧H, with V (G∧H) = V (G)×V (H) and (g
1, h
1)(g
2, h
2) ∈ E(G∧H) if and only if g
1g
2∈ E(G) and h
1h
2∈ E(H). By P
nwe denote an induced path on n ≥ 2 vertices meant as a graph with V (P
n) = {x
1, x
2, . . . , x
n} and E(P
n) = {x
ix
i+1: i = 1, 2, . . . , n − 1}. If V (G) = {y
1, y
2, . . . , y
m}, then the copy G
∗of G is the graph with the vertex set V (G
∗) = {y
1∗, y
2∗, . . . , y
n∗} and y
∗iy
j∗∈ E(G
∗) if and only if y
iy
j∈ E(G), where y
∗icorresponds to y
i. Further, let D = {y
1, y
2, . . . , y
r} ⊂ V (G), then the subset D
∗= {y
1∗, y
2∗, . . . , y
∗m} ⊂ V (G
∗) is called a duplication of D into the vertex set V (G
∗) of the copy G
∗or shorter into G
∗.
We consider the conjunction P
n∧ G, for n ≥ 2 with a special graph G.
Before proceeding we introduce some notation with respect to P
n∧ G. If y
j∈ V (G), then the vertex (x
i, y
j) of the conjunction of P
n∧ G is simply written as x
ij. For a fixed integer i we put X
i= {x
ij: 1 ≤ j ≤ |V (G)|}. A set B of all vertices belonging to k consecutive sets X
i+1, . . . , X
i+kis called a block of a graph P
n∧ G of size k × |V (G)| . For a convenience, the set X
iwe will call the i-th column of a graph P
n∧ G. Any other terms not defined in this paper can be found in [1].
2. Introduction
In this section we introduce some basic facts which will be useful in further investigations. It was proved in [4], that
Theorem 1 [4]. γ
s(P
n) = §
n3
¨ , for n ≥ 3.
Theorem 2 [4]. For any noncomplete graph G with at least one hanging vertex
γ
s(G) = γ(G).
Next, it is easy to check that
Proposition 3. There is no a split dominating set of P
n, for i = 1, 2, 3.
Proposition 4. γ
s(P
4) = 2, since P
4∼ = P
4.
Now, we calculate a split domination number of P
nif n ≥ 5.
Theorem 5. γ
s(P
n) = n − 3, for n ≥ 5.
P roof. Let V (P
n) = {x
1, x
2, . . . , x
n}, such that d
Pn(x
1) = d
Pn(x
n) = 1 and d
Pn(x
i) = 2, for i = 2, 3, . . . , n − 1. At the beginning we can observe that d
Pn(x
1) = d
Pn(x
n) = n − 2 and d
Pn(x
i) = n − 3, for i = 2, 3, . . . , n − 1.
Now, we show that the induced subgraph H = h{x
n1, x
n2, . . . , x
nk}i
Pnis connected, when n
1< n
2< . . . < n
k, for k ≥ 4. Since n
3− n
1≥ 2, n
4− n
1≥ 2, . . . , n
k−n
1≥ 2, then x
n1is adjacent to x
nsin P
n, for s = 3, 4, . . . , k. Hence H
1= h{x
n1, x
n3, x
n4, . . . , x
nk}i
Pnis a connected subgraph. Arguing as above we prove that H
2= h{x
n2, x
n4, x
n5, . . . , x
nk}i
Pnalso is connected. Since k ≥ 4, then V (H
1) ∩ V (H
2) 6= ∅ and H = hV (H
1) ∪ V (H
2)i
Pnis connected.
This means that there is no a disconnected subgraph of P
nof order at least n − 4. To complete the proof we construct a split dominating set D of P
n, such that |D| = n − 3. Let D consists of vertices x
i, for i = 4, 5, . . . , n.
Since n ≥ 5, thus D 6= ∅ and V (P
n) − D = {x
1, x
2, x
3}. Moreover, vertices x
1, x
2are adjacent to x
4∈ D in P
nand x
3is adjacent to x
5∈ D in P
n. Furthermore, x
2is an isolated vertex in
V (P
n) − D ®
Pn
. All this together gives that D is the minimum split dominating set of P
nof order n − 3, as required.
From the structure of P
n, P
nand from the definition of the connected domination number it follows immediately
Proposition 6.
γ
c(P
n) = n − 2, for n ≥ 3 and
γ
c(P
n) = 2, for n ≥ 4.
From Theorem 1, Theorem 5 and Proposition 6 it follows the Nordhaus- Gaddum type result
Theorem 7.
γ
s(P
n) + γ
s(P
n) = §
n3
¨ + n − 3, for n ≥ 5, γ
c(P
n) + γ
c(P
n) = n, for n ≥ 4.
3. Main Results
Proposition 8. For any graph G, γ(P
2∧ G) ≤ 2γ(G).
P roof. Let D = {x
1, x
2, . . . , x
s} be a minimum dominating set of G. Du- plicating D into two columns P
2∧G we obtain a subset A
2= {x
11, x
12, . . . , x
1s, x
21, x
22, . . . , x
2s} ⊂ V (P
2∧ G). We show that A
2is a dominating set of P
2∧ G.
Let x
1j∈ (V (P
2∧ G) − A
2) . Since D is a dominating set of G, then there exists a vertex x
kof D in G, such that x
kx
j∈ E(G). Further, by the definition of P
2∧ G and by a construction of the subset A
2we have that x
1jx
2k∈ E(P
2∧ G) and x
2k∈ A
2, respectively. Hence x
1jis dominated by A
2in P
2∧ G. Similarly, we can show that the vertex x
2j∈ (V (P
2∧ G) − A
2) is dominated by A
2in P
2∧ G. All this together gives that A
2is a dominating set of P
2∧ G and γ(P
2∧ G) ≤ |A
2| = 2γ(G), as required.
It follows immediately from the obvious inequality γ(G) ≤ γ
c(G) and from the above proposition that
Corollary 9. For any connected graph G, γ(P
2∧ G) ≤ 2γ
c(G).
Proposition 10. For any graph G with γ
c(G) ≥ 2, γ(P
3∧ G) ≤ 2γ
c(G).
P roof. Let D be a γ
c(G)-set. Put A
3= {x
2j, x
3j: for all x
j∈ D}. Now
we show that A
3is a dominating set of P
3∧ G. Arguing as in a proof of
Proposition 8, we see that A
3dominates vertices x
2j, x
3j∈ (V (P
3∧ G) − A
3)
in P
3∧ G. To complete the proof we must show that any vertex from X
1is
dominated by A
3in P
3∧G. We recall that X
1is the first column of the graph
P
3∧ G as it was mentioned earlier. Let x
1j∈ X
1. If x
j∈ V (G) − D, then it
is dominated by a vertex x
k∈ D and in a consequence x
1jis dominated by x
2k∈ A
3. Assume that x
j∈ D. Since hDi
Gis connected and |D| = γ
c(G) ≥ 2, thus there exists a vertex x
k∈ D different from x
j, such that x
jx
k∈ E(G).
Moreover, x
1jx
2k∈ E(P
3∧ G). This means that x
1jis dominated by A
3in P
3∧ G because of x
2k∈ A
3. Hence A
3is a dominating set of P
3∧ G. Since γ(P
3∧ G) ≤ |A
3| = 2γ
c(G), thus the theorem is true.
Remark 1. It is easy to see that A
3also is a dominating set of P
4∧ G, where G is a graph with γ
c(G) ≥ 2. Hence γ(P
4∧ G) ≤ 2γ
c(G) with γ
c(G) ≥ 2.
Proposition 11. For any graph G with γ
c(G) ≥ 2 γ(P
5∧ G) ≤ 3γ
c(G).
P roof. Let D = {x
1, . . . , x
m} be a minimum connected dominating set of G. Duplicating D into 2-nd, 3-rd, 4-th column of P
5∧ G we obtain a subset
A
5= {x
ij: i = 2, 3, 4 and j = 1, 2, . . . m} ⊂ V (P
5∧ G).
Simple observation shows that A
5is a dominating set of P
5∧G. Thus γ(P
5∧ G) ≤ |A
5| = 3γ
c(G) and proof is complete.
In [2] it was presented the following result
Proposition 12 [2]. For n > 1 and every graph G we have γ(P
n∧ G) ≤ 2γ(G) ³j n
4 k
+ 1
´ .
Counterexample. Let P
n= P
3and G = P
5, then P
n∧ G = P
3∧ P
5has two connected components, say Y
1and Y
2. Further, this must be that γ(P
3∧P
5) = γ(Y
1)+γ(Y
2). It is easy to observe that γ(Y
1) = 2 and γ(Y
2) = 3, thus γ(P
3∧P
5) = 5. Now, using the estimation from Proposition 12 we obtain γ(P
3∧ P
5) ≤ 4( ¥
34
¦ + 1) = 4, since γ(G) = γ(P
5) = 2. It is not true, since as we noticed γ(P
3∧ P
5) = 5.
Using above facts we give another estimation for γ(P
n∧ G).
Theorem 13. Let G be a graph with γ
c(G) ≥ 2. Then, for n ≥ 2 we have
γ(P
n∧ G) ≤
( γ
c(G)(2 ¥
n−14
¦ + 1), if n ≡ 1(mod 4), γ
c(G)(2 ¥
n−14
¦ + 2), otherwise.
P roof. Let n = 4q + r, q ≥ 1, 0 ≤ r < 4, r 6= 1. Partition the set V (P
n∧ G) into q blocks B
1, . . . , B
qof size 4 × |V (G)| and one block B
q+1of size r × |V (G)| (it can be that B
q+1= ∅). Put A
ijbe a duplication of A
jinto the block B
i, for i = 1, 2, . . . , q and j = 2, 3, 5, where A
jis the subset defined in the proofs of above propositions.
If n = 4q, then D = S
qi=1
A
i3is a dominating set of P
n∧ G and
|D| = 2qγ
c(G) = 2
µ¹ 4q − 1 4
º + 1
¶
γ
c(G) = γ
c(G) µ
2
¹ n − 1 4
º + 2
¶ .
If n = 4q + 2, then D = S
qi=1
A
i3∪ A
q+12is a dominating set of P
n∧ G and
|D| = 2qγ
c(G) + 2γ
c(G) = µ
2
¹ 4q + 1 4
º + 2
¶
γ
c(G) = γ
c(G) µ
2
¹ n − 1 4
º + 2
¶ .
If n = 4q + 3, then D = S
q+1i=1
A
i3is a dominating set of P
n∧ G and
|D| = 2(q + 1)γ
c(G) = 2
µ¹ 4q + 2 4
º + 1
¶
γ
c(G) = γ
c(G) µ
2
¹ n − 1 4
º + 2
¶ .
Assume that n = 4q + 1. Thus we create q − 1 blocks of size 4 × |V (G)| , say B
1, . . . , B
q−1and one block B
qof size 5 × |V (G)| . Let D = S
q−1i=1
A
i3∪ A
q5, then D is a dominating set of P
n∧ G with
|D| = 2(q − 1)γ
c(G) + 3γ
c(G) = (2q + 1)γ
c(G)
= µ
2
¹ 4q 4
º + 1
¶
γ
c(G) = µ
2
¹ n − 1 4
º + 1
¶ γ
c(G).
Therefore, since γ(P
n∧ G) ≤ |D| , the result holds, for n ≥ 4 as it was assumed at the beginning of the proof.
Since 2γ
c(G) = (2 ¥
n−14
¦ + 2)γ
c(G), for n = 2, 3, 4 and 3γ
c(G) = (2 ¥
5−14
¦ + 1)γ
c(G), then Theorem 13 was proved for any n ≥ 2.
Moreover, since γ
c(P
k) = 2, for k ≥ 4, then the last result and a simple
calculation lead to the following conclusion.
Corollary 14 [2]. For n ≥ 2 and k ≥ 4,
γ(P
n∧ P
k) ≤
n, if n ≡ 0(mod 4),
n + 1, if n ≡ 1(mod 4) and n ≡ 3(mod 4), n + 2, if n ≡ 2(mod 4).
Mention that for the graph P
3∧ P
5, considered after Proposition 12, using the estimation from Theorem 13 we have 5 = γ(P
3∧ P
5) ≤ γ
c(P
5)(2 ¥
3−14
¦ + 2) = 6.
At the end, we consider the minimum split domination number of the conjunction of P
nand a graph G with a special property. First, we assume that G has at least two hanging vertices, then we have
Proposition 15. Let G be a graph with at least one hanging vertex. Then γ
s(P
n∧ G) = γ(P
n∧ G), for n ≥ 2.
P roof. Let G be a graph as in the statement of the corollary. Since G has at least one hanging vertex, thus by the definition of P
n∧ G, we obtain that P
n∧ G has at least one hanging vertex (note that it has at least two hanging vertices, since n ≥ 2). Then according to Theorem 2 we have that γ
s(P
n∧ G) = γ(P
n∧ G), as desired.
Further, we assume that G is a connected graph with the minimum domi- nation number equal to half its order.
The following result was given in [3].
Theorem 16 [3]. A connected graph G of order 2n ≥ 4 has γ(G) = n if and only if either G ∼ = C
4or G satisfies: the vertex set of a graph G can be partitioned into two sets V
1and V
2, such that |V
1| = |V
2| = n with only matching between V
1and V
2and satisfying hV
1i
G∼ = K
nand hV
2i
Gis connected.
From the above theorem it follows that the graph G different from C
4has
at least two hanging vertices. Moreover, according to Proposition 15, we
observe that γ
s(P
n∧ G) = γ(P
n∧ G), for G mentioned in Theorem 16. Now,
we give the estimation for the split domination number with respect to the
conjunction of P
nand a graph G with the minimum domination number
equal to half its order. But first we find a relationship between domination
parameters in G.
Theorem 17. Let G be a connected graph of order 2n ≥ 4 with γ(G) = n.
Then γ
s(G) = γ
c(G) = γ(G).
P roof. Assume that G ∼ = C
4. The subset containing exactly two adjacent [not adjacent] vertices realizes γ(G) = 2 and it is a minimum connected [a minimum split dominating] set of C
4. Thus the result holds, for C
4. Now, assume that G is different from C
4. By Theorem 16 we have that V (G) can be partitioned into two sets V
1and V
2of order n, such that hV
2i
Gis connected and hV
1i
G∼ = K
n. This means that the subset V
1is a set of all hanging vertices of G. Let D = V
2, since there is a matching between V
1= V (G) − D and D in G. It means that D is a minimum dominating set of G. To complete this theorem, we show that D is a γ
c(G)-set and also a γ
s(G)-set. Because of hDi
Gis connected, as it was stated in Theorem 13, then D is a γ
c(G)-set. Moreover, since hV (G) − Di
G∼ = K
n, n ≥ 2 is disconnected, thus we D is a γ
s(G)-set, proving the theorem.
Finally, using this theorem, Theorem 13 and Proposition 15 we obtain the following estimation for a split dominating number of P
n∧ G.
Corollary 18. Let G be a connected graph of order 2m ≥ 4 with γ(G) = m.
Then
γ
s(P
n∧ G) = γ(P
n∧ G) ≤
( γ(G)(2 ¥
n−14
¦ + 1), if n ≡ 1(mod 4), γ(G)(2 ¥
n−14