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XCIII.1 (2000)

Algebraic independence of the values of Mahler functions satisfying implicit functional equations

by

Bernd Greuel (K¨oln)

1. Introduction and results. In a sequence of three papers Mahler ([4]–[6]) discussed the transcendence and algebraic independence of values of functions in several variables satisfying a certain type of functional equation.

In his survey article [7], 37 years later, he stated three new problems. The third problem (for the first and second problem cf. Loxton and van der Poorten [3]) dealt with implicit functional equations of the type

(1) P (z, f (z), f (T z)) = 0

with T z = z

d

, d ∈ Z, d ≥ 2 and a polynomial P (z, y, u) with coefficients in Q, the algebraic closure of Q. Nishioka [8] (cf. Chapter 1.5 in [11]) solved this problem for polynomial transformations T . In [9] she extended her method to functions in several variables and suitable generalizations of the transfor- mation T z = z

d

.

Becker [1] generalized the result of Nishioka to algebraic transforma- tions T. T¨opfer gave in [15] a quantitative version of Becker’s result. In that article T¨opfer asked for a proof of the algebraic independence of the val- ues of several functions satisfying implicit functional equations at algebraic points.

In this paper we follow the proof of T¨opfer [15] and derive a lower bound for the transcendence degree of the values of functions f

1

, . . . , f

m

satisfy- ing a special system of implicit functional equations for the transformation T z = z

d

with an integer d ≥ 2. It should be easy to generalize the follow- ing result to polynomial or even rational or algebraic transformations T (cf.

Becker [1] and T¨opfer [14, 15]).

For the development of Mahler’s method in the last 15 years see the monograph of Nishioka [11] and the overview article of Waldschmidt [16] for further references.

2000 Mathematics Subject Classification: 11J82, 11J91.

[1]

(2)

Throughout the paper let K denote an algebraic number field and O

K

the ring of integers in K. As usual we denote by α the house of an algebraic number α, which is the maximum of the absolute values of the conjugates of α. A denominator of an algebraic number α is a positive integer D such that Dα ∈ O

K

. If P (z, y

1

, . . . , y

m

) =: P (z, y ) is a polynomial with complex coefficients, deg

z

P =: d

z

P denotes the partial degree of P with respect to z, deg

y

P =: d

y

P denotes the total degree in y := (y

1

, . . . , y

m

) and analogous notations in other cases. If the coefficients of P are algebraic, the height H(P ) of P is defined as the maximum of the houses of the coefficients of P , and the length L(P ) is the sum of the houses of the coefficients. In what follows let c, c

0

, c

1

, . . . and γ

0

, γ

1

, . . . denote positive constants which are independent of the parameters M, N, k, k

0

, k

1

used. For a vector µ ∈ C

m

we define |µ| := |µ

1

| + . . . + |µ

m

| and by N and N

0

we denote the positive and nonnegative integers.

Theorem 1. Let f

1

, . . . , f

m

be analytic in a neighborhood U of the ori- gin, algebraically independent over C(z) and suppose that the coefficients of their power series

f

i

(z) = X

j=0

f

i,j

z

j

(i = 1, . . . , m) belong to a fixed algebraic number field K and satisfy

f

i,j

≤ exp(c

0

(1 + j

L

)) and D

[c0(1+jL)]

f

i,j

∈ O

K

for j ∈ N

0

and i = 1, . . . , m with suitable constants D ∈ N and L ≥ 1. Let n ∈ N

m

and β := n

1

· . . . · n

m

. Suppose that the functions f

1

, . . . , f

m

satisfy the functional equations

(2) a(z)f

j

(z

d

)

nj

=

n

X

j−1 ν=0

P

ν,j

(z, f (z))f

j

(z

d

)

ν

with polynomials a ∈ Q[z]\{0} and P

0,1

, . . . , P

nm−1,m

∈ Q[z, y ] and an integer d satisfying d > max{β

L

, d

y

(P )}, where d

y

(P ) is defined by

d

y

(P ) := max{deg

y

(P

0,1

), . . . , deg

y

(P

nm−1,m

)}.

Assume α ∈ Q

∩ U and a(α

dk

) 6= 0 for all k ∈ N

0

. Let m

0

be the smallest integer satisfying

m

0

m log d − L(m + 1) log β 1 +

log βlog d

 log β + log d + L(m + 1) 1 +

log βlog d



+ m 

(2 log β + log d

y

(P )) . Then

trdeg

Q

Q(f

1

(α), . . . , f

m

(α)) ≥ m

0

.

(3)

As an application of this theorem we obtain easily the following

Corollary 2. Under the assumptions of Theorem 1, if α, f and the parameters d, β and d

y

(P ) satisfy for m > 1 the inequality

log d

y

(P )

log d < 1 −

log βlog d

2m

2

− m − 1 + L(m + 1) 1 +

log βlog d



(2m − 1)  (m − 1) L(m + 1) 1 +

log βlog d



+ m  ,

then f

1

(α), . . . , f

m

(α) are algebraically independent.

Remarks. (i) Nishioka [8] proved the transcendence of f (α) under the condition d

2

> n

2

max{d, deg

y

(P )}, where f satisfies the functional equation (1) and n = deg

u

(P ).

Under the hypotheses of Theorem 1 we get the transcendence of f (α) only under the stronger condition d > max{n

3+1

, deg

y

(P )}. The reason for this is that we have to construct a sequence of polynomials (Q

k

)

k0≤k≤k1

, where the difference k

1

− k

0

has to be relatively large (cf. Lemma 8). In the simpler case m = 1 it suffices to find just one integer k to obtain a contradic- tion. By an improvement of the method of proof we get the transcendence of f (α) under the condition d > max{n

2

, deg

y

(P )}, which coincides with the condition of Nishioka in the case d > deg

y

(P ). Note that we have to assume d > d

y

(P ) only for technical reasons (cf. formula (24)).

(ii) T¨opfer proved in [15] a transcendence measure for f (α) under the condition d > n max{n, deg

y

(P )}.

(iii) For m ≥ 1 and β = 1 we get the result of Nishioka [10]. In [10]

one can also find a lot of applications. For other examples in this case, but d

y

(P ) = 1, see Chirski˘ı [2] and T¨opfer [14].

Our next example deals with infinite products of the form f

n

(z) :=

Y

j=0

(1 − z

dj

)

nj

, where d and n are positive integers with d ≥ 2.

Let 1 ≤ n

1

< . . . < n

m

(m ≥ 2). Then the functions f

ni

are analytic for

|z| < 1 and satisfy the functional equations

f

ni

(z) = (1 − z)f

ni

(z

d

)

ni

(i = 1, . . . , m).

Hence we have the following:

Corollary 3. Let 1 ≤ n

1

< . . . < n

m

be integers and β := n

1

· . . . · n

m

. If α is algebraic with 0 < |α| < 1 and d is an integer with

log d > (2m

2

− 1 + p

4m

4

− 2m

2

+ m) log β,

(4)

then the values

Y

j=0

(1 − α

dj

)

nj1

, . . . , Y

j=0

(1 − α

dj

)

njm

are algebraically independent over Q. Under the corresponding conditions on α, d and n we get the algebraic independence of

Y

j=0

(1 − α

dj

), Y

j=0

(1 − α

dj

)

2j

, . . . , Y

j=0

(1 − α

dj

)

nj

.

Remark. Nishioka proved (Theorem 3.4.13 in [11]) the algebraic inde- pendence of

Y

j=0

(1 − α

dj

) (d = 2, 3, . . .) for any algebraic number α with 0 < |α| < 1.

P r o o f (of Corollary 3). The algebraic independence of the functions f

n1

, . . . , f

nm

over C(z) will be shown in the last section.

By the remark after Lemma 4, f

n1

, . . . , f

nm

satisfy the conditions for the houses and denominators of the coefficients in Theorem 1 for any L > 1.

Then the assumption of Corollary 3 follows immediately from Theorem 1 and Corollary 2.

2. Preliminaries and auxiliary results. For µ ∈ N

0

, µ ∈ N

m0

and f

i

(z) := P

j=0

f

i,j

z

j

(i = 1, . . . , m) we define f

i

(z)

µ

:=

X

j=0

f

i,j(µ)

z

j

, f

i,j(µ)

:= X

ν1,...,νµ∈N0

ν1+...+νµ=j

f

i,ν1

· . . . · f

i,νµ

, (3)

f (z)

µ

:= f

1

(z)

µ1

· . . . · f

m

(z)

µm

= X

j=0

f

j(µ)

z

j

,

f

j(µ)

:= X

ν1,...,νm∈N0 ν1+...+νm=j

f

1,ν11)

· . . . · f

m,νmm)

. (4)

Lemma 4. If f

i,j

≤ exp(c

0

(1 + j

L

)) and D

[c0(1+jL)]

f

i,j

∈ O

K

for i = 1, . . . , m and all j ∈ N

0

with L ≥ 1 and D ∈ N, then for all µ ∈ N

0

and µ ∈ N

m0

the following assertions hold:

(i) f

i,j(µ)

≤ exp(c

1

(µ + j

L

)), D

[c1(µ+jL)]

f

i,j(µ)

∈ O

K

,

(ii) f

j(µ)

≤ exp(c

2

(|µ| + j

L

)), D

[c2(|µ|+jL)]

f

j(µ)

∈ O

K

.

(5)

P r o o f. Assertions (i) and (ii) are consequences of the identities (3) and (4) using the fact that the number of ν ∈ N

µ0

with ν

1

+ . . . + ν

µ

= j is bounded by

j+µ−1µ−1



≤ 2

j+µ

.

Remark. If the functions f

1

, . . . , f

m

satisfy functional equations of type P

i

(z, f

i

(z), f

i

(z

d

)) = 0 (i = 1, . . . , m)

with polynomials P

i

∈ Q[z, y, u]\{0} and deg

u

(P

i

) ≥ 1, we see that there exist an algebraic number field K, an explicit computable constant c > 0 and a positive integer D ∈ N such that for j ∈ N

0

and all ε > 0:

(i) f

i,j

∈ K,

(ii) f

i,j

≤ exp(c(1 + j

1+ε

)), (iii) D

1+j

f

i,j

∈ O

K

hold, i.e. the conditions of Lemma 4 are fulfilled for all L > 1. For a proof of this remark see Lemma 1.5.3 of Nishioka [11] and Proposition 1 of Becker [1] for a more general result.

Lemma 5. For N ∈ N there exists a polynomial R ∈ O

K

[z, y ]\{0} with the following properties:

(i) deg

z

R ≤ N , deg

y

R ≤ N , (ii) log H(R) ≤ c

3

N

(m+1)L

, (iii) ν := ord

0

R(z, f (z)) ≥ c

4

N

m+1

for suitable constants c

3

, c

4

∈ R

+

.

P r o o f. Put

R(z, y ) :=

X

N λ=0

X

|µ|≤N

r

λ,µ

z

λ

y

µ

with (N + 1)

N +mm



unknown coefficients r

λ,µ

. Then R(z, f (z)) :=

X

N λ=0

X

|µ|≤N

r

λ,µ

z

λ

f (z)

µ

= X

h=0

β

h

z

h

(say) with (cf. the identity (4))

(5) β

h

=

min{h,N }

X

λ=0

X

|µ|≤N

r

λ,µ

f

h−λ(µ)

.

Assertion (iii) is equivalent to the condition β

h

= 0 for 0 ≤ h < c

4

N

m+1

, and this yields at most [c

4

N

m+1

] + 1 equations in the

(N + 1)

 N + m m



1

m! N

1+m

> 2c

4

N

m+1

+ 1

(6)

unknowns r

λ,µ

for a suitable constant c

4

. After multiplication with a suit- able denominator D

[c2N(1+m)L]

according to Lemma 4 the coefficients f

h−λ(µ)

are algebraic integers and their houses are bounded by exp(c

5

(N

(1+m)L

)).

Siegel’s lemma (cf. Hilfssatz 31 in Schneider [12]) yields the assertion.

Lemma 6. Let ν be as in Lemma 5 and β

h

denote the Taylor coefficients of R(z, f (z)) as in the proof. Then

(i) |β

h

| ≤ exp(c

6

(h + N

(1+m)L

)) ≤ exp(c

7

(h + ν

L

)).

(ii) |β

ν

| ≥ exp(−c

8

ν

L

).

(iii) Suppose that k ∈ N satisfies d

k

≥ c

9

ν

L

with ν, N, L as above and a suitable constant c

9

∈ R

+

depending only on f and α. Then there exist constants c

10

, c

11

∈ R

+

depending only on f and α such that

−c

10

νd

k

≤ log |R(T

k

(α), f (T

k

(α)))| ≤ −c

11

νd

k

, where T

k

(α) denotes the kth iterate of T at the point α.

P r o o f. From (5) we get β

h

=

min{h,N }

X

λ=0

X

|µ|≤N

r

λ,µ

f

h−λ(µ)

.

This representation together with Lemma 5 and the inequality |f

i,j

| ≤ exp(γ

0

(j + 1)) (notice that the functions f

1

, . . . , f

m

are analytic in a neigh- borhood of 0), hence |f

h(µ)

| ≤ exp(γ

1

(|µ| + h)) with γ

0

, γ

1

∈ R

+

, implies the first estimate of Lemma 6.

For D, L, c

4

as above and ν as in Lemma 5 we get (recall ν ≥ c

4

N

1+m

) D

2(N +νL)]

β

ν

∈ O

K

and

β

ν

≤ exp(γ

3

(N

(1+m)L

+ ν

L

+ N )) ≤ exp(γ

4

ν

L

).

By a Liouville estimate we obtain the second part.

We now come to the last part of Lemma 6. By Lemma 5 we write R(T

k

(α), f (T

k

(α))) = β

ν

(T

k

(α))

ν

 1 +

X

h=1

β

h+ν

β

ν

(T

k

(α))

h



and by the assumption on k and the first two parts of Lemma 6 we get

X

h=1

β

h+ν

β

ν

(T

k

(α))

h

X

h=1

exp(c

7

L

+ h) + c

8

ν

L

− γ

5

hd

k

)

X

h=1

exp(γ

6

ν

L

− γ

7

hd

k

) < 1

2 .

(7)

Now the assertion follows from |T

k

(α)|

ν

= exp(−γ

8

νd

k

) and exp(−c

8

ν

L

) ≤

ν

| ≤ exp(2c

7

ν

L

).

Lemma 7. Let S, U

1

, . . . , U

d

∈ C satisfy S

d

+ U

1

S

d−1

+ . . . + U

d

= 0 and

−X

1

≤ log |S| ≤ −X

2

, log |U

i

| ≤ Y (1 ≤ i ≤ d) for X

1

, X

2

, Y ∈ R

+

. Then there exists j ∈ {1, . . . , d} such that

−dX

1

− Y − log d ≤ log |U

j

| ≤ −X

2

+ Y + log d.

P r o o f. This is Lemma 4.2.3 of Wass [17].

Remark. The examples S

d

+ U

d

= 0 and S

d

+ U

1

S

d−1

= 0 show that the bounds for |U

j

| cannot be improved.

The proof of Theorem 1 depends on the following result from elimination theory, which can be found in T¨opfer [13, Theorem 1] with slight modifica- tions.

Lemma 8. Suppose ω ∈ C

m

and K is an algebraic number field. Then there exists a constant c

12

= c

12

(ω, K) ∈ R

+

with the following prop- erty: If there exist increasing functions ψ

1

, ψ

2

, Λ : N → R

+

, real numbers Φ

2

≥ Φ

1

≥ c

12

, positive integers k

0

< k

1

, m

0

∈ {0, . . . , m} and polynomials (Q

k

)

k0≤k≤k1

∈ O

K

[ y ] such that the following assumptions are satisfied:

(i) 1 ≤ ψ

1

(k + 1)/ψ

2

(k) ≤ Λ(k) and ψ

2

(k) ≥ c

12

(log H(Q

k

) + deg

y

Q

k

) for k ∈ {k

0

, . . . , k

1

},

(ii) the polynomials (Q

k

)

k0≤k≤k1

satisfy, for k ∈ {k

0

, . . . , k

1

}, (a) deg

y

Q

k

≤ Φ

1

,

(b) log H(Q

k

) ≤ Φ

2

,

(c) −ψ

1

(k) ≤ log |Q

k

(ω)| ≤ −ψ

2

(k),

(iii) ψ

2

(k

1

) ≥ c

12

Λ(k

1

)

m0−1

Φ

m10−1

max{ψ

1

(k

0

), Φ

2

}, then trdeg

Q

Q(ω) ≥ m

0

.

3. Construction of an auxiliary function. Since the case β = 1 (i.e.

n

1

= . . . = n

m

= 1) was treated by Nishioka [10] we can assume β > 1.

The proof is rather long, so we give a short sketch of the main steps.

In the first step we show how the powers of f (α) can be reduced by using

the functional equations. In the second step we consider R(T

k

(α), f (T

k

(α)))

for a polynomial R and construct by induction a polynomial R

k

, with de-

grees and height depending only on the degrees and height of R and on

d, β, d

y

(P ) and k, such that |R

k

(α, f (α))| has almost the same analytic

bounds as |R(T

k

(α), f (T

k

(α)))|. In the last step we use this polynomial R

k

to construct a suitable sequence of polynomials Q

k

∈ O

K

[ y ] satisfying the

assumptions of Lemma 8 and prove Theorem 1 by Lemma 8.

(8)

For a real number a we define a

+

:= max{a, 0} =

12

(a + |a|).

Let K be an algebraic number field containing α, the coefficients of f

1

, . . . , f

m

(cf. the assumption of Theorem 1 and Lemma 4) and the co- efficients of the polynomials a, P

0,1

, . . . , P

nm−1,m

. Without loss of generality we can assume a ∈ O

K

[z] and P

0,1

, . . . , P

nm−1,m

∈ O

K

[z, y ].

In what follows let k ∈ N be fixed. Under the conditions of Theorem 1 on α, d and f we put for abbreviation

τ

κ

:= α

dκ

, ϕ

i,κ

:= f

i

dκ

) and ϕ

κ

:= (f

1

dκ

), . . . , f

m

dκ

)).

For j = 1, . . . , m let P

nj,j

:= a and we define the following notations:

d

z

(P ) := max{deg

z

(P

0,1

), . . . , deg

z

(P

nm,m

)}, d

y

(P ) := max{deg

y

(P

0,1

), . . . , deg

y

(P

nm,m

)},

L(P ) := max{L(P

0,1

), . . . , L(P

nm,m

)}.

Lemma 9. Suppose that k ∈ N and λ ∈ N

0

. Then for all j = 1, . . . , m we have

(a(τ

k−1

)f

j

k

))

λ

=

n

X

j−1 i=0

P

i,λ,j(k)

k−1

, ϕ

k−1

)(a(τ

k−1

)f

j

k

))

i

with polynomials P

i,λ,j(k)

∈ O

K

[z, y ] satisfying

d

z

(P

i,λ,j(k)

) ≤ (λ − i)

+

d

z

(P ), d

y

(P

i,λ,j(k)

) ≤ (λ − i)

+

d

y

(P ),

L(P

i,λ,j(k)

) ≤ 2

(λ−nj)+

L(P )

(λ−i)+

.

P r o o f. For λ ∈ {0, . . . , n

j

− 1} we choose P

i,λ,j(k)

= δ

i,λ

, where δ

i,k

is the Kronecker symbol, and the assertions are obvious.

Let now λ = n

j

+ l for l ∈ N

0

. We show the assertion by induction on l.

This is obvious for l = 0 because of (2) and (a(τ

k−1

)f

j

k

))

nj

=

n

X

j−1 i=0

P

i,j

k−1

, ϕ

k−1

)a(τ

k−1

)

nj−1−i

(a(τ

k−1

)f

j

k

))

i

, with P

i,n(k)

j,j

(z, y ) := P

i,j

(z, y )a(z)

nj−1−i

.

In the induction step the assertion follows from

(a(τ

k−1

)f

j

k

))

nj+l+1

= (a(τ

k−1

)f

j

k

))

nj+l

(a(τ

k−1

)f

j

k

))

=

n

X

j−1 i=0

P

i,n(k)

j+l,j

k−1

, ϕ

k−1

)(a(τ

k−1

)f

j

k

))

i+1

(9)

=

n

X

j−2 i=0

P

i,n(k)j+l,j

k−1

, ϕ

k−1

)(a(τ

k−1

)f

j

k

))

i+1

+ P

n(k)

j−1,nj+l,j

k−1

, ϕ

k−1

)(a(τ

k−1

)f

j

k

))

nj

=

n

X

j−2 i=0

P

i,n(k)j+l,j

k−1

, ϕ

k−1

)(a(τ

k−1

)f

j

k

))

i+1

+ P

n(k)j−1,nj+l,j

k−1

, ϕ

k−1

)

×

n

X

j−1 i=0

P

i,n(k)j,j

k−1

, ϕ

k−1

)(a(τ

k−1

)f

j

k

))

i

=

n

X

j−1 i=0

P

i,n(k)j+l+1,j

k−1

, ϕ

k−1

)(a(τ

k−1

)f

j

k

))

i

. So we get

P

i,n(k)j+l+1,j

(z, y ) := P

i−1,n(k) j+l,j

(z, y ) + P

n(k)j−1,nj+l,j

(z, y )P

i,n(k)j,j

(z, y ), where P

−1,n(k)

j+l,j

(z, y ) := 0.

By induction it follows that P

i,n(k)

j+l+1,j

∈ O

K

[z, y ] and d

z

(P

i,n(k)

j+l+1,j

) ≤ (n

j

+ l + 1 − i)d

z

(P ), d

y

(P

i,n(k)

j+l+1,j

) ≤ (n

j

+ l + 1 − i)d

y

(P ), L(P

i,n(k)

j+l+1,j

) ≤ 2

l+1

L(P )

nj+l+1−i

.

In the reduction step we replace R(τ

k

, ϕ

k

) =: R

0

k

, ϕ

k

) for an arbitrary polynomial R ∈ O

K

[z, y ] inductively by R

l

k−l

, ϕ

k−l

) and finally get a polynomial R

k

with almost the same bounds for |R

k

(α, f (α))|, the degrees and the height of R

k

as R

0

.

Lemma 10. Suppose k ∈ N and R ∈ O

K

[z, y ]. Then there exists a poly- nomial

R

(z, u, y ) := X

µ∈M

R

µ

(z, u)y

µ

∈ O

K

[z, u, y ] with M := {0, 1, . . . , n

1

− 1} × . . . × {0, 1, . . . , n

k

− 1} and

d

yj

(R

) ≤ n

j

− 1 (j = 1, . . . , m), d

z

(R

µ

) ≤ dd

z

(R) + d

z

(P )d

y

(R), d

u

(R

µ

) ≤ d

y

(P )d

y

(R),

L(R

µ

) ≤ L(R)L(P )

dy(R)

2

dy(R)

(10)

such that

a(τ

k−1

)

dy(R)

R(τ

k

, ϕ

k

) = R

k−1

, ϕ

k−1

, a(τ

k−1

k

).

P r o o f. From the representation R(z, y ) :=

d

X

z(R) i=0

X

|j|≤dy(R)

R

i,j

z

i

y

j

we get, by Lemma 9, a(τ

k−1

)

dy(R)

R(τ

k

, ϕ

k

) =

d

X

z(R) i=0

X

|j|≤dy(R)

R

i,j

τ

ki

a(τ

k−1

)

dy(R)−|j|

(a(τ

k−1

k

)

j

= X

µ∈M

R

µ

k−1

, ϕ

k−1

)(a(τ

k−1

k

)

µ

, where

R

µ

(z, u) :=

d

X

z(R) i=0

X

|j|≤dy(R)

R

i,j

z

di

a(z)

dy(R)−|j|

P

µ(k)

1,j1,1

(z, u) · . . . · P

µ(k)

m,jm,m

(z, u).

Now the bounds for the partial degrees d

yj

are obvious. From Lemma 9 we get

d

z

(R

µ

) ≤ dd

z

(R) + d

z

(P )d

y

(R) + d

z

(P ) max

n X

m

i=1

(j

i

− µ

i

)

+

− j

i

: |j| ≤ d

y

(R) o

≤ dd

z

(R) + d

z

(P )d

y

(R)

and similarly we derive the upper bound for d

u

. The length can be bounded in an analogous way by

L(R

µ

) ≤ L(R)2

max{Pmi=1(ji−ni)+:|j|≤dy(R)}

L(P )

dy(R)

≤ L(R)L(P )

dy(R)

2

dy(R)

.

Lemma 11. Suppose that R

∈ O

K

[z, u, y ] is the polynomial in Lemma 10. Then there exist polynomials U

1

, . . . , U

β

∈ O

K

[z, u] such that

R

∗β

+ U

1

R

∗β−1

+ . . . + U

β

= 0 at the point (z

0

, u

0

, y

0

) := (τ

k−1

, ϕ

k−1

, a(τ

k−1

k

) and

d

z

(U

l

) ≤ βdd

z

(R) + βd

z

(P )(d

y

(R) + |n|), d

u

(U

l

) ≤ βd

y

(P )(d

y

(R) + |n|),

L(U

l

) ≤ exp(c

13

(d

z

(R) + d

y

(R)))H(R)

β

.

(11)

P r o o f. With R

(z, u, y ) := P

µ∈M

R

µ

(z, u)y

µ

as in Lemma 10 we put for ν ∈ M ,

R

k−1

, ϕ

k−1

, a(τ

k−1

k

)(a(τ

k−1

k

)

ν

= X

µ∈M

R

µ

k−1

, ϕ

k−1

)(a(τ

k−1

k

)

µ+ν

= X

λ∈M

R

λ,ν

k−1

, ϕ

k−1

)(a(τ

k−1

k

)

λ

, with (cf. Lemma 9)

R

λ,ν

(z, u) := X

µ∈M

R

µ

(z, u)P

λ(k)

111,1

(z, u) · . . . · P

λ(k)

mmm,m

(z, u).

The degrees and length of R

λ,ν

can be bounded by Lemmas 9 and 10:

d

z

(R

λ,ν

) ≤ max

µ∈M

n

d

z

(R

µ

) + X

m j=1

d

z

(P

λ(k)

jjj,j

) o

≤ dd

z

(R) + d

z

(P )d

y

(R) + d

z

(P ) max

µ∈M

n X

m

j=1

j

+ ν

j

− λ

j

)

+

o

≤ dd

z

(R) + d

z

(P )(d

y

(R) + |n| + |ν| − |λ|).

Similarly

d

u

(R

λ,ν

) ≤ d

y

(P )(d

y

(R) + |n| + |ν| − |λ|),

L(R

λ,ν

) ≤ L(R)L(P )

dy(R)+|n|+|ν|−|λ|

2

dy(R)+|ν|

≤ γ

1

L(R)γ

2dy(R)

, where the constants γ

1

, γ

2

∈ R

+

depend only on P and n.

Thus the system of β linear equations with β unknowns, X

λ∈M

{R

λ,ν

k−1

, ϕ

k−1

) − δ

λ,ν

R

k−1

, ϕ

k−1

, a(τ

k−1

k

)}ω

λ

= 0, where

δ

λ,ν

:=

n 1 if λ = ν, 0 else

is the generalized Kronecker symbol, has for ω := (ω

λ

)

λ∈M

a nontrivial solution

ω

λ

:= (a(τ

k−1

k

)

λ

.

Hence the determinant of the matrix of coefficients must vanish at the point

(z

0

, u

0

, y

0

) := (τ

k−1

, ϕ

k−1

, a(τ

k−1

k

), and the expansion of the determinant

with respect to the powers of R

k−1

, ϕ

k−1

, a(τ

k−1

k

) implies

(12)

0 = det(R

λ,ν

− δ

λ,ν

R

)

λ,ν∈M

= ±(R

∗β

+ U

1

R

∗β−1

+ . . . + U

β

) with polynomials U

l

∈ O

K

[z, u ].

Since the polynomials U

l

are sums of products of the form R

λ1,σ(λ1)

· . . . · R

λs,σ(λs)

,

where λ

1

, . . . , λ

s

∈ M are pairwise distinct and σ := (σ

1

, . . . , σ

m

) is a per- mutation of {0, . . . , n

1

− 1} × . . . × {0, . . . , n

m

− 1}, for l ∈ {1, . . . , β} we get

d

u

(U

l

) ≤ max

σ

n X

λ∈M

d

u

(R

λ,σ(λ)

) o

≤ βd

y

(P )(d

y

(R) + |n|)

because X

λ∈M

(|λ| − |σ(λ)|) = 0.

By analogy we obtain d

z

(U

l

) ≤ max

σ

n X

λ∈M

d

z

(R

λ,σ(λ)

) o

≤ βdd

z

(R) + βd

z

(P )(d

y

(R) + |n|).

The length of U

l

can be bounded by

L(U

l

) ≤ β! max{L(R

λ,ν

) : λ, ν ∈ M }

β

, with

L(R

λ,ν

) ≤ exp(c

13

(d

z

(R) + d

y

(R)))H(R).

Lemma 11 is proved.

Now the necessary tools for the reduction step from R

0

to R

k

are com- plete, and we prove for j = 0, . . . , k the existence of polynomials R

j

O

K

[z, y ] such that for j = 0,

(6) d

z

(R

0

) := d

1,0

, d

y

(R

0

) := d

2,0

, log H(R

0

) := H

0

, exp(−ψ

1

(0)) ≤ |R

0

k

, ϕ

k

)| ≤ exp(−ψ

2

(0)), and for j ≥ 1:

d

y

(R

j

) =: d

2,j

≤ βd

y

(P )(d

2,j−1

+ |n|), (7)

d

z

(R

j

) =: d

1,j

≤ βdd

1,j−1

+ βd

z

(P )(d

2,j−1

+ |n|), (8)

log H(R

j

) =: H

j

≤ βH

j−1

+ c

14

(d

1,j−1

+ d

2,j−1

).

(9)

Here the constant c

14

> 0 depends only on f and α and (10) exp(−ψ

1

(j)) ≤ |R

j

k−j

, ϕ

k−j

)| ≤ exp(−ψ

2

(j)).

The functions ψ

1

, ψ

2

satisfy for j ≥ 1 the following recurrence equalities:

ψ

1

(j) := βψ

1

(j − 1) + βH

j−1

+ c

15

(d

1,j−1

+ d

k−j

d

2,j−1

) + log β, (11)

ψ

2

(j) := ψ

2

(j − 1) − βH

j−1

− c

16

(d

1,j−1

+ d

2,j−1

) − log β

(12)

(13)

provided that

(13) ψ

2

(0) ≥ c

17

β

k

(H

0

+ d

k

(d

1,0

+ d

2,0

)),

where c

15

, c

16

, c

17

∈ R

+

are suitable constants depending only on f and α.

The existence of the polynomials will be proved in the next section. First we will derive upper bounds for d

1,j

, d

2,j

, H

j

and ψ

1

(j) and a lower bound for ψ

2

(j).

Obviously (7) implies

d

2,j

≤ γ

0

(βd

y

(P ))

j

(d

2,0

+ |n|) ≤ c

18

(βd

y

(P ))

j

d

2,0

,

and for d

1,j

we get inductively (note that d > d

y

(P ) by the condition of Theorem 1)

d

1,j

≤ (βd)

j

d

1,0

+ βd

z

(P )

j−1

X

i=0

(βd)

i

(d

2,j−i−1

+ |n|) ≤ c

19

(βd)

j

(d

1,0

+ d

2,0

).

For H

j

, the logarithm of the height of R

j

, we get in a similar way H

j

≤ β

j

H

0

+ γ

1

j−1

X

i=0

β

i

(d

1,j−i−1

+ d

2,j−i−1

) ≤ β

j

H

0

+ c

20

(d

1,0

+ d

2,0

)(βd)

j

. Now we can easily deduce from (11) and the above estimates that

ψ

1

(k) = β

k

ψ

1

(0) (14)

+

k−1

X

i=0

β

i

{βH

k−i−1

+ c

15

(d

1,k−i−1

+ d

i

d

2,k−i−1

) + log β}

≤ β

k

ψ

1

(0) + kβ

k

H

0

+ c

21

(βd)

k

(d

1,0

+ d

2,0

).

In a similar way (cf. (13)) we can derive a lower bound for ψ

2

(k):

ψ

2

(k) = ψ

2

(0) −

k−1

X

i=0

{βH

k−i−1

+ c

16

(d

1,k−i−1

+ d

2,k−i−1

) + log β}

(15)

≥ ψ

2

(0) − c

22

β

k

(H

0

+ d

k

(d

1,0

+ d

2,0

)).

Now we prove by induction on j = 0, . . . , k the existence of a sequence of polynomials R

j

∈ O

K

[z, y ] satisfying the conditions (6)–(10). For j = 0, this is a consequence of Lemmas 5 and 6 with R

0

:= R and

(16) d

1,0

, d

2,0

≤ N, H

0

≤ c

3

N

(m+1)L

, ψ

1

(0) := c

10

νd

k

, ψ

2

(0) := c

11

νd

k

provided that d

k

≥ c

9

ν

L

for a suitable constant c

9

> 0. Now suppose that

the assertions are true for j − 1 (j ∈ {1, . . . , k}). We apply Lemmas 10

and 11 with R replaced by R

j−1

. This yields the existence of polynomials

(14)

U

1

, . . . , U

β

∈ O

K

[z, u] with

d

z

(U

l

) ≤ βdd

1,j−1

+ βd

z

(P )(d

2,j−1

+ |n|), d

u

(U

l

) ≤ βd

y

(P )(d

2,j−1

+ |n|),

log H(U

l

) ≤ γ

1

(d

1,j−1

+ d

2,j−1

) + βH

j−1

for l = 1, . . . , β such that

R

∗βj−1

+ U

1

R

j−1∗β−1

+ . . . + U

β

= 0

for (z

0

, u

0

, y

0

) := (τ

k−j

, ϕ

k−j

, a(τ

k−j

k−(j−1)

). Here R

j−1

∈ O

K

[z, u, y ] is defined analogously to Lemma 10 by

a(τ

k−j

)

d2,j−1

R

j−1

k−(j−1)

, ϕ

k−(j−1)

)

= R

j−1

k−j

, ϕ

k−j

, a(τ

k−j

k−(j−1)

).

The induction hypothesis together with the fact that −γ

2

d

k

≤ log |a(τ

k

)| ≤ γ

3

for k ∈ N

0

, implies

−ψ

1

(j − 1) − γ

4

d

k−j

d

2,j−1

≤ log |R

j−1

k−j

, ϕ

k−j

, a(τ

k−j

k−(j−1)

)|

≤ − ψ

2

(j − 1) + γ

5

d

2,j−1

.

For l = 1, . . . , β we obtain by a standard estimate together with Lemma 11,

|U

l

k−j

, ϕ

k−j

)| ≤ L(U

l

) max{1, |τ

k−j

|, |ϕ

1,k−j

|, . . . , |ϕ

m,k−j

|}

dz(Ul)+du(Ul)

≤ exp(βH

j−1

+ γ

6

(d

1,j−1

+ d

2,j−1

)), where the constant γ

6

∈ R

+

depends only on f and α.

By (13) and (16) we see that

ψ

2

(j − 1) − (βH

j−1

+ γ

7

(d

1,j−1

+ d

2,j−1

) + log β) > 0 and by Lemma 7 we get the existence of l

0

∈ {1, . . . , β} such that

log |U

l0

k−j

, ϕ

k−j

)| ≤ − ψ

2

(j − 1) + γ

8

d

2,j−1

+ βH

j−1

+ γ

9

(d

1,j−1

+ d

2,j−1

) + log β

≤ − ψ

2

(j − 1) + βH

j−1

+ c

16

(d

1,j−1

+ d

2,j−1

) + log β

= − ψ

2

(j) and

log |U

l0

k−j

, ϕ

k−j

)|

≥ − βψ

1

(j − 1) − γ

10

βd

k−j

d

2,j−1

− βH

j−1

− γ

11

(d

1,j−1

+ d

2,j−1

) − log β

≥ − βψ

1

(j − 1) − βH

j−1

− c

15

(d

1,j−1

+ βd

k−j

d

2,j−1

) − log β

= − ψ

1

(j).

(15)

Thus we put R

j

(z, y ) := U

l0

(z, y ) ∈ O

K

[z, y ] and see that (6)–(10) are proved for the polynomial R

j

.

4. Proof of Theorem 1. Now the necessary tools for the proof of Theorem 1 are complete. From the preceding section with j = k we know that for k, N ∈ N sufficiently large with

d

k

≥ c

9

ν

L

, (17)

νd

k

≥ c

23

β

k

(N

(1+m)L

+ d

k

N ) (18)

for sufficiently large constants c

9

, c

23

> 0, there exist polynomials R

k

O

K

[z, y ] with

d

z

(R

k

) ≤ c

24

(βd)

k

N, (19)

d

y

(R

k

) ≤ c

18

(βd

y

(P ))

k

N, (20)

log H(R

k

) ≤ c

25

(βd)

k

N, (21)

−c

26

(βd)

k

ν ≤ log |R(α, f (α))| ≤ −c

27

d

k

ν.

(22)

The estimates for the degrees (19) and (20) are obvious from (16) and the above estimates. The upper bound for the height (21) of R

k

and a lower bound for the right-hand side of (22) could be derived from (18) and (15).

With (14) and (16) it follows from (18) that

ψ

1

(k) ≤ γ

1

β

k

d

k

ν + γ

2

k

(N

(1+m)L

+ d

k

N ) ≤ γ

1

β

k

d

k

ν + γ

3

kd

k

ν and this gives the left-hand inequality of (22); note that β ≥ 2.

In order to use Lemma 8 we define the polynomials (Q

k

)

k0≤k≤k1

∈ O

K

[ y ] by

Q

k

(y ) := D

dz(Rk)

R

k

(α, y ), where D ∈ N is a denominator of α.

Because of (18) and (19) and the condition d

y

(P ) < d we obtain, for k ∈ N,

d

y

(Q

k

) ≤ c

18

(βd

y

(P ))

k

N, log H(Q

k

) ≤ c

28

(βd)

k

N,

log |Q

k

( f (α))| ≤ − c

29

d

k

ν + c

30

(βd)

k

N ≤ −c

31

νd

k

, log |Q

k

( f (α))| ≥ − c

32

ν(βd)

k

.

Now for N ∈ N we define a number M ≥ N by ν := c

4

M

m+1

and for

positive integers k

0

≤ k ≤ k

1

, where k

0

< k

1

will be specified later, we

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