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S. B A D R A O U I (Guelma)

BEHAVIOUR OF GLOBAL SOLUTIONS FOR A SYSTEM OF REACTION-DIFFUSION EQUATIONS FROM COMBUSTION THEORY

Abstract. We are concerned with the boundedness and large time be- haviour of the solution for a system of reaction-diffusion equations mod- elling complex consecutive reactions on a bounded domain under homoge- neous Neumann boundary conditions. Using the techniques of E. Conway, D. Hoff and J. Smoller [3] we also show that the bounded solution converges to a constant function as t → ∞. Finally, we investigate the rate of this convergence.

1. Introduction. In this paper we investigate the asymptotic behaviour of global solutions for the following reaction-diffusion system:

(1.1) ∂Y

1

∂t = d

0

∆Y

1

− d

1

Y

1

Y

2

f

1

(T ), x ∈ Ω, t > 0, (1.2) ∂Y

2

∂t = d

2

∆Y

2

+ d

3

Y

1

Y

2

f

1

(T )

− d

4

Y

2

f

2

(T ) − d

5

Y

2

− d

6

Y

22

, x ∈ Ω, t > 0,

(1.3) ∂T

∂t = d

7

∆T + d

8

Y

1

Y

2

f

1

(T )

+ d

9

Y

2

f

2

(T ) + d

10

Y

2

+ d

11

Y

22

, x ∈ Ω, t > 0, (1.4) ∂Y

1

∂ν = ∂Y

2

∂ν = ∂T

∂ν = 0, x ∈ ∂Ω, t > 0, (1.5) (Y

1

, Y

2

, T )(x, 0) = (Y

10

, Y

20

, T

0

)(x), x ∈ Ω,

1991 Mathematics Subject Classification: 35K57, 35B40, 35B45.

Key words and phrases: reaction-diffusion equations, boundedness, global existence, large time behaviour.

[133]

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where Ω is a bounded domain in R

n

with boundary ∂Ω, such that ∂Ω is a C

m

hypersurface separating Ω from R

n

/Ω (m ≥ 1), d

j

(j = 0, 1, . . . , 11) are positive constants, f

i

(i = 1, 2) are given by the Arrhenius law

f

i

(T ) = B

i

exp(−E

i

/T ),

where B

i

, E

i

are constants, and E

i

denotes the activation energy.

This system of reaction-diffusion equations arises as a model of chain branching and chain breaking kinetics of reactions with complex chemistry.

Here Y

1

is the concentration of fuel, Y

2

is the concentration of radicals, and T is the dimensionless temperature. Y

1

, Y

2

and T depend on x and t where (x, t) ∈ Ω × R

+

.

Under suitable conditions (see (CD) in Section 3), it is expected that (1.1)–(1.5) has a unique global solution (Y

1

, Y

2

, T ) and this solution tends to an equilibrium state uniformly in x as t → ∞.

We will show that (Y

1

(t), Y

2

(t), T (t)) approaches an equilibrium state (0, 0, T

) in C

µ

(Ω)

3

as t → ∞ for every µ ∈ [0, 2), where T

is a con- stant, and we will consider the rate of this convergence, by means of in- tegral equations, fractional powers of operators, Poincar´e’s inequality and some imbedding theorems.

2. Preliminary results. We state some results needed in the sequel.

Lemma 2.1. Let (E, k · k

E

) and (F, k · k

F

) be two real Banach spaces with continuous inclusion E ⊂ F . Let A be a linear operator generating a strongly continuous semigroup G(t) in E such that:

(i) G(t)E ⊂ F for all t > 0,

(ii) there exists θ ∈ [0, 1) such that kG(t)ϕk

F

≤ ct

−θ

kϕk

E

for all t > 0.

Moreover , let p > 1/(1 − θ), f ∈ L

ploc

(R

+

, E) and sup

t≥0

kf k

Lp(t,t+1;E)

< ∞. Let u be a mild solution on R

+

of du

dt = Au(t) + f (t).

If u ∈ L

(0, ∞; E), then u(t) ∈ F for all t > 0 and u ∈ C

B

(δ, ∞; F ) for all δ > 0, where C

B

(δ, ∞; F ) is the space of all continuous functions u : (δ, ∞) → F such that sup{ku(t)k

F

: t ≥ δ} < ∞.

For the proof, see [4].

Lemma 2.2. Let G(t) be the semigroup generated by the operator d∆

in L

p

(Ω). Then for all 1 ≤ p < q ≤ ∞ and all ϕ ∈ L

p

(Ω) we have G(t)ϕ ∈ L

q

(Ω) and

kG(t)ϕk

q

≤ c(p, q)t

−(n/2)(1/p−1/q)

kϕk

p

.

For the proof, see [2].

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3. Global existence and positivity. Throughout this paper, the following assumptions are in force:

(CD) (i) d

j

(j = 0, 1, . . . , 11) are positive constants,

(ii) Y

10

, Y

20

and T

0

are nonnegative measurable functions such that 0 ≤ Y

10

(x), Y

20

(x), T

0

(x) ≤ M

0

for almost every x ∈ Ω, for some positive constant M

0

.

Theorem 3.1. Assume (CD). Then there exists a unique nonnegative global solution (Y

1

, Y

2

, T ) for (1.1)–(1.5) which is smooth in Ω × (0, ∞).

P r o o f. For each 1 < p < ∞ and j ∈ {1, 2, 3} define the linear operator A

j,p

on L

p

(Ω) by

(3.1) D(A

j,p

) = {u ∈ W

2,p

(Ω) : (∂u/∂ν)|∂Ω = 0}, A

1,p

u = d

0

∆u, A

2,p

u = d

2

∆u, A

3,p

u = d

7

∆u,

where W

2,p

(Ω) is the usual Sobolev space. It is well known that A

j,p

gen- erates a compact, analytic contraction semigroup G

j,p

(t), t ≥ 0, of bounded linear operators on L

p

(Ω) (see, e.g., Amann [2]).

For the local existence we write (1.1)–(1.3) as a system of integral equa- tions via the variation of constants formula. For simplicity we set

F

1

(Y

1

, Y

2

, T )(t)(·) = − d

1

Y

1

(t)Y

2

(t)f

1

(T (t))(·),

F

2

(Y

1

, Y

2

, T )(t)(·) = (d

3

Y

1

(t)Y

2

(t)f

1

(T (t)) − d

4

Y

2

(t)f

2

(T (t))

− d

5

Y

2

(t) − d

6

Y

22

(t))(·),

F

3

(Y

1

, Y

2

, T )(t)(·) = (d

8

Y

1

(t)Y

2

(t)f

1

(T (t)) + d

9

Y

2

(t)f

2

(T (t)) + d

10

Y

2

(y) + d

11

Y

22

(t))(·),

for x ∈ Ω, t > 0; we then have Y

1

(t) = G

1,p

(t)Y

10

+

t

\

0

G

1,p

(t − τ )F

1

(Y

1

(τ ), Y

2

(τ ), T (τ )) dτ, (3.2)

Y

2

(t) = G

2,p

(t)Y

20

+

t

\

0

G

2,p

(t − τ )F

2

(Y

1

(τ ), Y

2

(τ ), T (τ )) dτ, (3.3)

T (t) = G

3,p

(t)T

0

+

t

\

0

G

3,p

(t − τ )F

3

(Y

1

(τ ), Y

2

(τ ), T (τ )) dτ.

(3.4)

For each α > 0 define the operator B

j,p

= I − A

j,p

. Then the fractional

powers B

−αj,p

= (I −A

j,p

)

−α

exist and are injective, bounded linear operators

on L

p

(Ω) (see Pazy [8]). Let B

αj,p

= (B

j,p−α

)

−1

and X

j,pα

= D(B

j,pα

), the

domain of B

j,pα

. Then X

j,pα

is a Banach space with the graph norm kuk

α

=

kB

αj,p

wk

p

, and for α > β ≥ 0, X

j,pα

is a dense subspace of X

pβ

with the

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inclusion X

j,pα

⊂ X

j,pβ

compact (we use the convention X

p0

= L

p

(Ω)). Also if 0 ≤ α < 1 we have

(3.5) X

j,pα

⊂ C

µ

(Ω) for every 0 ≤ µ < mα − n/p.

Note that this inclusion is valid even if p = 1 (see Henry [5], p. 39).

In addition, G

j,p

and B

j,pα

have the properties summarised in the follow- ing lemma.

Lemma 3.2. The operators G

p

and B

pα

satisfy (i) G

j,p

(t) : L

p

(Ω) → X

j,pα

for all t > 0,

(ii) G

j,p

(t)B

αj,p

u = B

j,pα

G

j,p

(t)u for every u ∈ X

j,pα

,

(iii) kG

j,p

(t)uk

α

≤ C

1

(α)t

−α

e

−t

kuk

p

for every t > 0 and u ∈ L

p

(Ω), (iv) k(G

j,p

(t) − I)uk

p

≤ C

2

(α)t

α

kuk

α

for 0 < α ≤ 1 and u ∈ X

j,pα

. The proof can be found in Pazy [8].

Select 0 < α < 1 and p > 1 so that (3.5) holds, and use the tech- niques of Pazy [8] to show that there exists a unique noncontinuable solution (Y

1

, Y

2

, T ) to (3.2)–(3.4) for Y

10

∈ X

1,pα

, Y

20

∈ X

2,pα

and T

0

∈ X

3,pα

. The solution satisfies

Y

1

∈ C([0, δ]; X

1,pα

) ∩ C

1

((0, δ); L

p

(Ω)), Y

2

∈ C([0, δ]; X

2,pα

) ∩ C

1

((0, δ); L

p

(Ω)), T ∈ C([0, δ]; X

3,pα

) ∩ C

1

((0, δ); L

p

(Ω)),

for some δ > 0; and we have kY

1

(t)k

+ kY

2

(t)k

+ kT (t)k

→ ∞ as t → t

max

if t

max

< ∞.

Suppose now that (Y

10

, Y

20

, T

0

) ∈ L

(Ω)

3

and let {Y

10k

}

k=1

be a se- quence in X

1,pα

, {Y

20k

}

k=1

a sequence in X

2,pα

and {T

0k

}

k=1

a sequence in X

3,pα

such that Y

10k

, Y

20k

, T

0k

≥ 0 and kY

10k

− Y

10

k

p

→ 0, kY

20k

− Y

20

k

p

→ 0 and kT

0k

− T

0

k

p

→ 0 as t → ∞. Using the equation (3.2) and the properties of A

1,p

stated in Lemma 3.2, it follows for α ≤ β < 1 that

kY

1k

k

β

≤ C

β

t

−β

kY

10k

k

p

+

t

\

0

C

β

(t − τ )

−β

kF

1

(Y

1k

(τ ), Y

1k

(τ ), Y

1k

(τ ))k

p

dτ for all t ∈ [0, t

kmax

), where t

kmax

is the maximal time of existence for the system (1.1)–(1.5) with initial conditions 0 ≤ (Y

10k

, Y

20k

, T

0k

) ∈ X

1,pα

× X

2,pα

× X

3,pα

. From these estimates one can deduce the existence of a C

β

such that

max{kY

1k

(t)k

β

, kY

2k

(t)k

β

, kT

k

(t)k

β

} ≤ C

β

t

−β

for all t ∈ [0, δ], k ≥ 1; thus {(Y

1k

(t), Y

2k

(t), T

k

(t))}

k=1

is contained in

a bounded subset of X

1,pβ

× X

2,pβ

× X

3,pβ

for each t ∈ (0, δ]. So by the

compact imbedding of X

j,pβ

in X

j,pα

(j = 1, 2, 3) for α < β < 1, we see that

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for each t ∈ (0, δ] the sequences {Y

1k

(t)}

k=1

, {Y

2k

(t)}

k=1

and {T

k

(t)}

k=1

contain convergent subsequences {Y

1k,i

(t)}

i=1

, {Y

2k,i

(t)}

i=1

and {T

k,i

(t)}

i=1

in X

1,pα

, X

2,pα

and X

3,pα

respectively.

Now define Y

1

(t) = lim

i→∞

Y

1k,i

(t), Y

2

(t) = lim

i→∞

Y

2k,i

(t), T (t) = lim

i→∞

T

k,i

(t) for each t ∈ [0, δ]. Then (Y

1

(t), Y

2

(t), T (t)) satisfies (3.2)–(3.4) for each t ∈ [0, δ]. Replacing [0, t

max

) with [δ, t

max

) and (Y

10

, Y

20

, T

0

) by (Y

1

(δ), Y

2

(δ), T (δ)) and using the results already established when (Y

10

, Y

20

, T

0

) ∈ X

1,pα

× X

2,pα

× X

3,pα

, we find that there is a unique, classical noncontinuable solution (Y

1

(t), Y

2

(t), T (t)) on Ω × [0, t

max

), for every (Y

10

, Y

20

, T

0

) ∈ (L

(Ω))

3

.

Since F

1

(0, Y

2

, T ) ≥ 0, F

2

(Y

1

, 0, T ) ≥ 0 and F

3

(Y

1

, Y

2

, 0) ≥ 0 it follows that Y

1

(t), Y

2

(t) and T (t) have nonnegative values on Ω (see [10]), and by the maximum principle we have

(3.6) kY

1

(t)k

≤ kY

10

k

for all t ∈ [0, t

max

).

Multiplying (1.2) by Y

2p−1

and integrating the result over Ω × (0, t) we obtain

1 n

d dt

\

Y

2p

dx ≤ c

\

Y

2p

dx, where c = d

3

kY

10

k

kf

1

(T (t))k

, hence

\

Y

2p

dx ≤ |Ω| kY

20

k

e

npt

for all t < t

max

. We can then deduce

(3.7) kY

2

(t)k

≤ e

ct

kY

20

k

for all t < t

max

.

From the expression of F

3

(Y

1

, Y

2

, T ) and (3.7) we can find two positive numbers c

1

and c

2

such that

(3.8) kF

3

(Y

1

(T ), Y

2

(T ), T (t))k

≤ e

ct

(c

1

+ c

2

e

ct

) for all t < t

max

, where c

1

= B

1

d

8

kY

10

k

+ d

9

B

2

+ d

10

and c

2

= d

11

kY

20

k

.

From (3.4) and (3.8) we obtain kT (t)k

≤ kT

0

k

+

t

\

0

e

(c

1

+ c

2

e

) dτ, from which we have

(3.9) kT (t)k

≤ kT

0

k

+ c

1

c (e

ct

− 1) + c

2

2c (e

2ct

− 1) for all t < t

max

.

Inequalities (3.6), (3.7) and (3.9) contradict the fact that t

max

< ∞, hence

t

max

= ∞.

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4. Boundedness of the solution. In fact, the solution obtained in Theorem 3.1 is uniformly bounded over Ω × (0, ∞).

Theorem 4.1. Assume (CD). Then there exists a positive number M such that

(4.1) (4.2)

0 ≤ Y

1

(x, t) ≤ kY

10

k

for x ∈ Ω, t ≥ 0, 0 ≤ Y

2

(x, t), T (x, t) ≤ M for x ∈ Ω, t ≥ 0.

P r o o f. The function Y

1

is uniformly bounded by kY

10

k

by the maxi- mum principle.

Let B(x, t) = d

3

Y

1

(x, t)f

1

(T (x, t))− d

4

f

2

(T (x, t))− d

5

− d

6

Y

2

(x, t). Then we can write

∂Y

2

∂t = d

2

∆Y

2

+ B(x, t)Y

2

with B(x, t) ≤ a (for example a = d

3

kY

10

kB

1

) and B(x, t) is locally Lipschitz in (x, t). Moreover, Y

2

∈ L

(R

+

, L

1

(Ω)). In fact, integrating (1.1) over Ω × (0, t) we obtain

(4.3)

\

Y

1

(x, t) dx =

\

Y

10

(x) dx − d

1 t

\

0

\

Y

1

(x, τ )Y

2

(x, τ )f

1

(T (x, τ )) dx dτ, which implies

(4.4)

t

\

0

\

(Y

1

Y

2

f

1

(T ))(x, τ ) dx dτ ≤ |Ω|

d

1

kY

10

k

for all t ≥ 0, where |Ω| is the Lebesgue measure of Ω. Similarly, we get (4.5)

\

Y

2

(x, t) dx

\

Y

20

(x) dx + d

3 t

\

0

\

(Y

1

Y

2

f

1

(T ))(x, τ ) dx dτ for all t ≥ 0.

From (4.4) and (4.5) we obtain (4.6) kY

2

(t)k

1

≤ |Ω|



kY

20

k

+ d

3

d

1

kY

10

k



for all t ≥ 0.

An application of the result of Alikakos ([1], §3) shows that Y

2

(t) is uniformly bounded over Ω × (0, ∞):

(4.7) kY

2

(t)k

≤ K for all t ≥ 0,

for some K > 0.

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Now, integrating (1.3) over Ω × (0, t) we obtain

\

T (x, t) dx =

\

T

0

(x) dx + d

8 t

\

0

\

(Y

1

Y

2

f

1

(T ))(x, τ ) dx dτ (4.8)

+ d

9 t

\

0

\

(Y

2

f

2

(T ))(x, τ ) dx dτ

+ d

10 t

\

0

\

Y

2

(x, τ ) dx dτ + d

11 t

\

0

\

Y

22

(x, τ ) dx dτ.

Integrating (1.2) over Ω × (0, t) we obtain (4.9)

\

Y

2

(x, t) dx + d

4

t

\

0

\

(Y

2

f

2

)(x, τ ) dx dτ + d

5

t

\

0

\

Y

2

(x, τ ) dx dτ

+ d

6 t

\

0

\

Y

22

(x, τ ) dx dτ = d

3 t

\

0

\

(Y

1

Y

2

)(x, τ ) dx dτ +

\

Y

20

(x) dx, from which we deduce that

(4.10)

\

0

\

(Y

2

f

2

)(x, τ ) dx dτ < ∞ and

\

0

\

Y

22

(x, τ ) dx dτ < ∞.

From (4.4)–(4.7) and (4.10) in (4.8) we obtain (4.11)

\

T (x, t) dx ≤ C for all t ≥ 0, i.e., T ∈ L

(R

+

, L

1

(Ω)).

To prove that T ∈ L

(R

+

, L

(Ω)) we distinguish two cases. We define S

p

(t) ≡ G

3,p

(t).

Case 1: n = 1, i.e., Ω = (a, b) ⊂ R. In this case we take E := L

1

(Ω) and F = C(Ω). Then Lemma 2.2 shows that

(4.12) kS

1

(t)ϕk

≤ ct

−1/2

kϕk

1

for all ϕ ∈ L

1

(Ω).

Take α = 3/4; from Lemma 2.2 and (3.5) we have S

1

(t)L

1

(Ω) ⊂ C(Ω).

Applying Lemma 2.1, we conclude that T ∈ C

B

(δ, ∞; C(Ω)) for all δ > 0, hence from the result concerning the local existence we obtain

kT (t)k

≤ C for all t ≥ 0.

Case 2: n ≥ 2. Let q

1

= 1, q

r

= n/(n − r) and E = L

qr

(Ω), F =

L

qr+1

(Ω) for r ∈ {1, . . . , n−1}. We have T ∈ C

B

(R

+

, L

q1

(Ω)), S

q1

(t)L

q1

(Ω) ⊂

L

q2

(Ω) and kS

q1

(t)ϕk

q2

≤ ct

−1/2

kϕk

q1

. Application of Lemma 2.1 gives

T ∈ C

B

(R

+

, L

q2

(Ω)). Next we take E = L

q2

(Ω) and F = L

q3

(Ω) to ob-

tain T ∈ C

B

(R

+

, L

q3

(Ω)). Continuing this process we finally have T ∈

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C

B

(R

+

, L

n

(Ω)). In the last iteration we take E = L

n

(Ω) and F = C(Ω).

As S

n

(t)L

n

(Ω) ⊂ X

3,nα

and kS

n

(t)ϕk

≤ ct

−1/2

kϕk

n

for all ϕ ∈ L

n

(Ω) and T ∈ C

B

(R

+

, L

n

(Ω)), from Lemma 2.1 we conclude that T ∈ C

B

(R

+

; C(Ω)).

5. Asymptotic behaviour. First, let us establish a preparatory lemma. Consider the problem

(P)  ∂u/∂t + Au = ϕ(t),

u(0) = u

0

,

where −A generates an analytic semigroup G(t) in a Banach space (X, k · k) with Re σ(A) > a > 0. We have the following lemma.

Lemma 5.1. Let X be a Banach space. If ϕ ∈ L

(R

+

, X) and the problem (P) has a bounded global solution u ∈ L

(R

+

, X) then for all 0 <

α < 1 we have

(A) sup

t≥δ

kA

α

u(t)k ≤ C(α, δ) for any δ > 0, and

(B) the function t 7→ A

α

u(t) is H¨ older continuous from [δ, ∞) to X for any δ > 0.

P r o o f. The solution u of (P) satisfies the integral equation u(t) = G(t)u

0

+

t

\

0

G(t − τ )ϕ(τ ) dτ, t > 0.

Applying A

α

to both sides yields kA

α

u(t)k ≤ kA

α

G(t)u

0

k +

t

\

0

kA

α

G(t − τ )ϕ(τ )k dτ.

From this and Lemma 3.2, we obtain kA

α

u(t)k

p

≤ C

1

(α)t

−α

e

−at

ku

0

k +

t

\

0

C

1

(α)(t − τ )

−α

e

−a(t−τ )

kϕ(τ )k dτ

≤ C

1

(α)ku

0

k + C

1

(α)M Γ (1 − α)a

α−1

.

Here Γ is the gamma function of Euler. Hence kA

α

u(t)k is uniformly bounded on [δ, ∞) for any δ > 0.

To prove (B), we have

kA

α

u(t + h) − A

α

u(t)k ≤ k(G(h) − I)A

α

G(t)u

0

k +

t+h

\

t

kA

α

G(t + h − τ )ϕ(τ )k dτ

+

t

\

0

k(G(h) − I)A

α

G(t − τ )ϕ(τ )k dτ.

(9)

Set

I

1

= k(G(h) − I)A

α

G(t)u

0

k, I

2

=

t+h

\

t

kA

α

G(t + h − τ )ϕ(τ )k dτ,

I

3

=

t

\

0

k(G(h) − I)A

α

G(t − τ )ϕ(τ )k dτ.

From the inequalities of Lemma 3.2, there exist two constants C

1

(α), C

2

(α) such that

I

1

≤ C

1

(α + β)C

2

(α)t

−1

e

−at

ku

0

kh

β

, I

2

≤ M C

1

(α)h

1−α

,

I

3

≤ M C

1

(α + β)C

2

(β)Γ (1 − α − β)a

α+β−1

h

β

,

where M = sup

t≥0

kϕ(t)k

p

for every 0 < β < 1. Taking β < 1 − α, we then have for all t ≥ δ,

kA

α

u(t + h) − A

α

u(t)k ≤ C(α, ku

0

k) max{h

β

, h

1−α

}.

Remark . As a consequence of this lemma, the function t 7→ A

α

u(t) is uniformly continuous.

The following proposition is also useful in the sequel.

Proposition 5.2. For any δ > 0, the family {Y

1

(t) : t ≥ δ} is relatively compact in C(Ω).

P r o o f. We have ∂Y

1

/∂t = d

0

∆Y

1

+ F

1

(Y

1

, Y

2

, T ) where F

1

(Y

1

, Y

2

, T ) =

−d

1

Y

1

Y

2

f

1

(T ). There is a positive constant N such that kF

1

(Y

1

, Y

2

, T )k

≤ N for all t ≥ 0. Let 0 < ε < 1 and t > ε. Then we can write Y

1

(t) = G

1,∞

(ε)Y

1

(t−ε)+[Y

1

(t)−G

1,∞

(ε)Y

1

(t−ε)], where G

1,∞

(t) is the semigroup generated by d

0

∆ with homogeneous Neumann boundary conditions in the Banach space C(Ω). We set

Y

(t) = G

1,∞

(ε)Y

1

(t − ε) and Y

(t) = Y

1

(t) − G

1,∞

(ε)Y

1

(t − ε).

Then {Y

(t) : t ≥ δ} is relatively compact in C(Ω) since {Y

1

(t − ε) : t ≥ δ}

is bounded and G

1,∞

(δ) is a compact operator. Also, kY

(t)k

=

t

\

t−ε

G

1,∞

(t − s)F

1

(Y

1

, Y

2

, T )(s) ds

≤ εN,

therefore {Y

1

(t) : t ≥ 1} is totally bounded, hence {Y

1

(t) : t ≥ 1} is relatively

compact in C(Ω). As {Y

1

(t) : δ ≤ t ≤ 1} is compact in C(Ω), it follows

that {Y

1

(t) : t ≥ δ} is relatively compact in C(Ω). The same holds true for

{Y

2

(t) : t ≥ δ} and {T (t) : t ≥ δ}.

(10)

Theorem 5.3. Under the assumptions (CD) we have

(5.1) lim

t→∞

kY

1

(t)k

= 0, lim

t→∞

kY

2

(t)k

= 0 and there exists a positive constant T

such that

(5.2) lim

t→∞

kT (t) − T

k

= 0.

P r o o f. From (1.1) we have

(5.3) d

dt

\

Y

1

(x, t) dx = −d

1

\

(Y

1

(t)Y

2

(t)f

1

(T (t)))(x) dx ≤ 0, hence the function t 7→

T

Y

1

(x, t) dx is nonincreasing. Let Y

1

be a constant such that

(5.4) lim

t→∞

\

Y

1

(x, t) dx = Y

1

. From (1.2) we have

(5.5) d dt

\

Y

2

(x, t) dx =

\

(d

3

Y

1

Y

2

f

1

(T )−d

4

Y

2

f

2

(T )−d

5

Y

2

−d

6

Y

22

)(x, t) dx.

From (5.3) and (5.5) we deduce (5.6) d

dt

\

 1 d

1

Y

1

+ 1 d

3

Y

2



(x, t) dx

= −

\

 d

4

d

3

Y

2

f

2

(T ) + d

5

d

3

Y

2

+ d

6

d

3

Y

22



(x, t) dx ≤ 0, from which we infer that there is a constant K such that

(5.7) 1

d

1

\

Y

1

(x, t) dx + 1 d

3

\

Y

2

(x, t) dx → K as t → ∞.

Combining (5.1) and (5.7) we conclude that there is a positive constant Y

2

such that

(5.8) lim

t→∞

\

Y

2

(x, t) dx = Y

2

.

Integrating (5.6) over (0, ∞) we conclude that there is a constant C such that

(5.9)

\

0

\

Y

2

(x, τ ) dx dτ ≤ C.

Combining (5.8) and (5.9) we find that Y

2

= 0, whence

(5.10) lim

t→∞

\

Y

2

(x, t) dx = 0.

(11)

As Y

2

(x, t) ≥ 0, the invariance principle of La Salle [5] and (5.10) imply lim

t→∞

kY

2

(t)k

= 0.

Multiplying (1.1) by Y

1

and integrating over Ω and using Poincar´e’s inequality we obtain

d dt

\

Y

12

(x, t) dx ≤ −c

\

Y

12

(x, t) dx for some positive constant c > 0, from which we deduce (5.11) kY

1

(t)k

22

≤ e

−ct

kY

10

k

22

.

Also, as a consequence of the maximum principle we have (5.12) kY

1

(t)k

≤ kY

1

(s)k

for t ≥ s > 0.

According to Proposition 5.2, {Y

1

(t) : t ≥ δ} is relatively compact in C(Ω) for all δ > 0; so from this, (5.11) and (5.12) we have

(5.13) lim

t→∞

kY

1

(t)k

= 0.

Multiplying (1.2) by Y

2

and integrating over Ω × (0, t) we have (5.14) kY

2

(t)k

22

+ 2d

2

t

\

0

k∇Y

2

(τ )k

22

dτ + 2d

4 t

\

0

\

Y

22

f

2

(T ) dx dτ

+ 2d

5 t

\

0

kY

2

(τ )k

22

dτ + 2d

6 t

\

0

\

Y

23

dx dτ

= kY

20

k

22

+ 2d

3 t

\

0

\

Y

1

Y

22

f

1

(T ) dx dτ.

Similarly for (1.3), (5.15) kT (t)k

22

+ 2d

7

t

\

0

k∇T (τ )k

22

= kT

0

k

22

+ 2d

8 t

\

0

\

Y

1

Y

2

T f

1

(T ) dx dτ

+ 2d

9 t

\

0

\

Y

2

T f

2

(T ) dx dτ

+ 2d

10 t

\

0

\

Y

2

T dx dτ + 2d

11 t

\

0

\

Y

22

T dx dτ.

By (4.4) and as Y

1

, Y

2

and T are uniformly bounded, it follows from (5.14)

(12)

and (5.15) that ∇Y

2

, ∇T ∈ L

2

(R, L

2

(Ω)), i.e.

(5.16)

\

0

k∇Y

1

(τ )k

22

dτ < ∞,

\

0

k∇Y

2

(τ )k

22

dτ < ∞,

\

0

k∇T (τ )k

22

dτ < ∞.

For the equation (1.1) for example, we define the operator B

p

as follows:

D(B

p

) = {u ∈ W

2,p

(Ω) : (∂u/∂ν)|∂Ω = 0}, B

p

u = (−d

0

∆ + a)u, with a fixed positive real number a > 0. It is well known that −B

p

generates an analytic semigroup and Re σ(B

p

) > a > 0. Also, if we set ϕ(t) = aY

1

(t)+

F

1

(Y

1

, Y

2

, T )(t), then ϕ ∈ L

(R

+

, L

p

(Ω)). Application of Lemma 5.1 then implies

(5.17) sup

t≥δ

kB

αp

Y

1

(t)k

p

≤ C(p, α, δ) for any δ > 0, and

(5.18) t 7→ B

pα

Y

1

(t) is uniformly continuous from [δ, ∞) to L

p

(Ω) for any δ > 0.

The same holds for Y

2

and T .

By (5.18) we find that t 7→ k∇Y

1

(t)k

2

, t 7→ k∇Y

2

(t)k

2

and t 7→ k∇T (t)k

2

are uniformly continuous on [δ, ∞) by choosing p = 2 and suitable α ∈ (0, 1) and m. From this and (5.16), Lemma 5.1 gives

(5.19) lim

t→∞

k∇Y

1

(t)k

2

= 0, lim

t→∞

k∇Y

2

(t)k

2

= 0, lim

t→∞

k∇T (t)k

2

= 0.

The interested reader can see [7] for details.

Since {T (t) : t ≥ δ} is compact in C(Ω) it follows that there is a sequence {t

k

} such that

tk

lim

→∞

T (t

k

) = T

in C(Ω),

where T

is a constant. Owing to the Poincar´e inequality (see [11]) we have λ

T (t) − |Ω |

−1

\

T (x, t) dx

2

2

≤ k∇T (t)k

22

.

Here λ is the smallest positive eigenvalue of −∆ with homogeneous Neumann boundary conditions on ∂Ω. Since the limit T

is uniquely determined we have

t→∞

lim T (t) = T

in C(Ω).

6. Rates of convergence. In this section we study the rates of con- vergence obtained in Theorem 5.3.

Theorem 6.1. Assume (CD). Then for given µ ∈ [0, 2), there exist

K

1

(µ), K

2

(µ), K(µ) > 0 and ̺, σ, ω > 0 such that

(13)

kY

1

(t)k

Cµ(Ω)

≤ K

1

(µ)e

−̺(t−t)

, kY

2

(t)k

Cµ(Ω)

≤ K

2

(µ)e

−σ(t−t)

, kT (t)k

Cµ(Ω)

≤ K(µ)e

−ω(t−t)

,

for some t

> 0, as t → ∞, where 0 < σ < d

5

, ̺ = min{σ, d

0

λ}, ω = min{σ, d

7

λ} and λ is the smallest positive eigenvalue of −∆ with homoge- neous Neumann boundary condition on ∂Ω.

Let us recall the following two lemmas.

Lemma 6.2. For 1 < p < ∞ and d > 0, let L

p

be the operator defined by D(L

p

) = {u ∈ W

2,p

(Ω) : (∂u/∂ν)|∂Ω = 0}, L

p

u = −d∆u, and let the operators Q

0

, Q

+

: L

p

(Ω) → L

p

(Ω) be defined by

Q

0

u = 1

|Ω|

\

u(x) dx, Q

+

u = u − Q

0

u.

Define the operator L

p+

as L

p+

≡ L

p

|Q

+

L

p

(Ω), the restriction of L

p

to Q

+

L

p

(Ω). Then there exists a constant C

3

(α) > 0 such that for u ∈ L

p

(Ω) and t > 0,

kL

αp+

e

−tLp+

Q

+

uk

p

≤ C

3

(α)q(t)

−α

e

−dλt

kQ

+

uk

p

,

where q(t) = min{t, 1} and λ is the smallest positive eigenvalue of −∆ with homogeneous Neumann boundary conditions on ∂Ω.

Lemma 6.2 is proved by Rothe [9].

Lemma 6.3. For α ∈ [0, 1) and β > 0, there exists a constant C(α, β) > 0 such that

t

\

0

q(ξ)

−α

e

βξ

dξ ≤ C(α, β)e

βt

. For the proof, see [6].

Proof of Theorem 6.1. For 1 < p < ∞ we take the operators D(A

p

) = D(B

p

) = D(R

p

) = {u ∈ W

2,p

(Ω) : (∂u/∂ν)|∂Ω = 0}, A

p

u = −d

0

∆u, B

p

= −(d

2

∆ − d

5

)u, R

p

= −d

7

∆u.

By Theorem 5.3 we already know that Y

1

(t) → 0 and Y

2

(t) → 0 in C(Ω) as t → ∞, hence for any ε > 0 there exists a constant t

> 0 such that (6.1) d

3

Y

1

f

1

(T ) < ε for all t ≥ t

.

We take 0 < ε < d

5

.

(I) The decay rate of kY

2

(t)k

p

. From (1.2) and (6.1) we get

(6.2) ∂Y

2

∂t ≤ d

2

∆Y

2

− (d

5

− ε)Y

2

, t > t

.

(14)

Multiplying both sides by Y

2p−1

for p ∈ [1, ∞), integrating over Ω and using Green’s formula, we obtain

(6.3) d

dt kY

2

(t)k

pp

≤ −p(d

5

− ε)kY

2

(t)k

pp

for t > t

, which leads to

kY

2

(t)k

p

≤ kY

2

(t

)k

p

e

−(d5−ε)(t−t)

for t > t

. The H¨older inequality then yields

(6.4) kY

2

(t)k

p

≤ M |Ω|

1/p

e

−(d5−ε)(t−t)

for t > t

, where M is the positive number appearing in (4.2).

(II) The decay rate of kY

2

(t)k

Cµ(Ω)

. To investigate the decay rate of kY

2

(t)k

Cµ(Ω)

, we treat the following integral equation which is equivalent to (1.2) with (1.4) for t > t

:

∂Y

2

∂t = d

2

∆Y

2

− d

5

Y

2

+ F (Y

1

, Y

2

, T ),

where F (Y

1

, Y

2

, T ) = d

3

Y

1

Y

2

f

1

(T ) − d

4

Y

2

f

2

(T ) − d

6

Y

22

. Let G

p

(t) be the semigroup generated by −B

p

. Then

(6.5) Y

2

(t) = G

p

(t − t

)Y

2

(t

) +

t

\

t

G

p

(t − τ )F (τ ) dτ, t > t

. From Lemma 3.2(iii), we obtain

(6.6) kB

pα

Y

2

(t)k

p

≤ C

1

(α)q(t − t

)

−α

e

−d5(t−t)

kY

2

(t

)k

p

+ d

3

M B

1

J

1

(t), where

J

1

(t) =

t

\

t

kG

p

(t − τ )k

Lp(Ω)→Lp(Ω)

kY

2

(τ )k

p

dτ.

It is sufficient to estimate J

1

(t). By (6.4) and Lemmas 3.2 and 6.3 we have

J

1

(t) ≤ C

1

(α)M |Ω|

1/p

t−t\

0

q(t − t

− τ )

−α

e

−(d5−ε)τ

dτ (6.7)

≤ C

1

(α)M |Ω|

1/p

e

−(d5−ε)(t−t)

for t ≥ t

.

Consequently, the imbedding D(B

αp

) ⊂ C

µ

(Ω) ensures the existence of a

constant K

2

(µ) > 0 such that for every 0 < σ < d

5

there is t

> 0 such that

(6.8) kY

2

(t)k

Cµ(Ω)

≤ K

2

(µ)e

−σ(t−t)

for t > t

.

(15)

(III) The decay rate of kY

1

(t)k

Cµ(Ω)

. First we write Y

1

(t) = Q

0

Y

1

(t) + Q

+

Y

1

(t), where

Q

0

Y

1

(t) = 1

|Ω|

\

Y

1

(x, t) dx, Q

+

Y

1

(t) = Y

1

(t) − Q

0

Y

1

(t).

We see from (4.3) and the fact that Y

1

→ 0 as t → ∞ in C(Ω) that Q

0

Y

1

(t) ≡ 1

|Ω|

\

Y

1

(x, t) dx (6.9)

= 1

|Ω|

\

Y

10

(x, t) dx − d

1

|Ω|

t

\

0

\

(Y

1

Y

2

f

1

)(x, τ ) dx dτ

= d

1

|Ω|

\

t

\

(Y

1

Y

2

f

1

)(x, τ ) dx dτ

≤ d

1

|Ω| B

1

M

0

\

t

\

Y

2

(x, τ ) dx dτ

≤ d

1

B

1

M

0

\

t

e

−σ(τ −t)

≤ 1

̺ d

1

B

1

M

0

e

−̺(t−t)

for t > t

.

Next, we study the decay of Q

+

Y

1

(t). We consider the integral equation associated with (1.1) and apply A

αp+

Q

+

to get

A

αp+

Q

+

Y

1

(t) = G

1,p+

(t − t

)Q

+

Y

1

(t

) − d

1 t

\

t

G

1,p+

(t − τ )(Q

+

Y

1

Y

2

f

1

)(τ ) dτ for t > t

. By Lemma 6.2, we get

kA

αp+

Q

+

Y

1

(t)k

p

≤ C

3

(α)q(t − t

)

−α

e

−d0λ(t−t)

kQ

+

Y

1

(t

)k

p

(6.10)

+ M B

1

d

1

C

3

(α)kQ

+

kJ

2

(t) for t > t

, where J

2

(t) =

Tt

t

q(t−τ )

−α

e

−d0λ(t−τ )

kY

2

(τ )k

p

dτ for t > t

and kQ

+

k is the norm of the linear operator Q

+

: L

p

(Ω) → L

p

(Ω). Here Q

+

Y

1

(t

) ∈ D(A

αp+

) because t > t

and by the smoothness of Y

1

(t

). By Lemma 6.3,

J

2

(t) =

t

\

t

q(t − τ )

−α

e

−d0λ(t−τ )

kY

2

(τ )k

p

dτ (6.11)

≤ M |Ω|

1/p

t−t

\

0

q(ξ)

−α

e

−d0λξ

≤ C(α, d

0

λ)e

−d0λ(t−t)

for t > t

.

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