• Nie Znaleziono Wyników

1. Introduction. In this paper we consider the nonlinear partial differ- ential equations of the form

N/A
N/A
Protected

Academic year: 2021

Share "1. Introduction. In this paper we consider the nonlinear partial differ- ential equations of the form"

Copied!
7
0
0

Pełen tekst

(1)

POLONICI MATHEMATICI LXIX.2 (1998)

Poincar´ e theorem and nonlinear PDE’s

by Maria E. Pli´ s (Krak´ow)

Abstract. A family of formal solutions of some type of nonlinear partial differen- tial equations is found. Terms of such solutions are Laplace transforms of some Laplace distributions. The series of these distributions are locally finite.

1. Introduction. In this paper we consider the nonlinear partial differ- ential equations of the form

(1) P (D)u = f (u),

with f analytic at zero, f (0) = 0, and f

(0) 6= 0. This means that f(u) = P

m=1

c

m

u

m

with c

1

6= 0. The operator P (D) is a linear differential opera- tor P (∂/∂x), where P (z) = P (z

1

, . . . , z

n

) is a complex polynomial without constant term.

Our aim is to find the behaviour of a solution of the equation (1) at infinity, writing this solution as some series of integrals involving a solution of the linear part of (1), i.e.

(2) P (D)y = c

1

y.

The method of construction used here follows Bobylev [2] (see also Ros- ales [3]). They solve only evolution type nonlinear equations (KdV, sine- Gordon etc.) in this way. Applying essentially Bobylev’s idea to use the Poincar´e theorem on normal forms (see Arnold [1]) we can solve a wide enough class of equations (1). The same method can be used in the case of the right hand side of (1) being a function not only of u but also of the derivatives of u.

1991 Mathematics Subject Classification: 44A10, 46F20.

Key words and phrases : Laplace distributions, Laplace transforms, formal solutions.

Supported by KBN grant 2-P03A-006-08.

[99]

(2)

2. Construction of formal solutions. We can write (1) as P (D)u − c

1

u =

X

∞ m=2

c

m

u

m

.

Let Z = {(z

1

, . . . , z

n

) ∈ C

n

: P (z) − c

1

= 0 } and assume that Z contains a curve Z

⊂ Z described by

Z

= {z = (z

1

, . . . , z

n

) ∈ Z : z = z(k) = (z

1

(k), . . . , z

n

(k)), k ∈ R}, such that (Z

+ Z

) ∩ Z

= ∅. Let y = y(x

1

, . . . , x

n

) be a solution of the linear equation (2) given by the integral over Z

:

(3) y(x

1

, . . . , x

n

) =

\

−∞

e

−z1(k)x1−...−zn(k)xn

Φ(k) dk

with Φ being an arbitrary function such that the integral (3) makes sense for x = (x

1

, . . . , x

n

) large enough.

We use the following notations. Let Lu =

c1

1

P (D)u. We denote by H

m

for m ≥ 2 the special m-linear form H

m

[u

1

, . . . , u

m

] = c

m

c

1

u

1

(0) . . . u

m

(0).

Let u

x

(t) = u(x+t), x, t ∈ C

n

, and let Q(u

1

, . . . , u

m

) denote the function x 7→ Q[u

x1

, . . . , u

xm

], Q being an m-linear form.

Thus (1) and (2) can be written as

(4) u = Lu −

X

∞ m=2

H

m

(u, . . . , u) and

(5) y = Ly.

We are looking for a solution u represented by a formal series

(6) u = y +

X

∞ j=2

R

j

(y, . . . , y)

with some j-linear form R

j

. From (6) we get y = u −

X

∞ j=2

R

j

(y, . . . , y) (7)

= u − R

2

(u, u) + X

∞ m=3

X

m j=2

X

|p|=m, pk≥1

( −1)

sj+1

R

j

(R

p1

, . . . , R

pj

),

with the convention R

1

(u) = u, |p| = p

1

+ . . . + p

j

and s

j

= # {k : p

k

> 1 }.

(3)

Thus

Ly = Lu − LR

2

(u, u) (8)

− X

∞ m=3

X

m j=2

X

|p|=m, pk≥1

( −1)

sj+1

LR

j

(R

p1

, . . . , R

pj

).

From (6) and (5) we get u = Ly

+ X

∞ j=2

1

j {R

j

(Ly, y, . . . , y) + R

j

(y, Ly, . . . , y) + . . . + R

j

(y, . . . , y, Ly) }.

Now by (7) and (8) we have u = Lu − LR

2

(u, u) −

X

∞ m=3

X

m j=2

X

|p|=m

( −1)

sj+1

LR

j

(R

p1

, . . . , R

pj

)

+ X

∞ j=2

1

j {R

j

(Lu − LR

2

(u, u) − . . . , . . . , u − R

2

(u, u) − . . .) + . . . + R

j

(u − R

2

(u, u) . . . , . . . , Lu − LR

2

(u, u) . . .) }

= Lu − X

∞ m=2

X

m j=2

X

|p|=m

( −1)

sj+1

{LR

j

(R

p1

, . . . , R

pj

)

− 1

j (R

j

(LR

p1

, . . . , R

pj

) + . . . + R

j

(R

p1

, . . . , LR

pj

)) }.

Now we compare the mth order terms and obtain a recurrence system of equations for R

m

, m ≥ 2:

H

m

= X

m j=2

X

|p|=m

( −1)

sj+1

{LR

j

(R

p1

, . . . , R

pj

) (9)

− 1

j (R

j

(LR

p1

, . . . , R

pj

) + . . . + R

j

(R

p1

, . . . , LR

pj

)) }.

To find R

m

we use the Laplace transformation. To this end set e

q

(x) = e

−qx

(so, according to our previous notation, e

0q

(τ ) = e

−qτ

), and

λ(q) = L[e

0q

] (= L(e

q

)(0)), h

m

(q

1

, . . . , q

m

) = H

m

[e

0q1

, . . . , e

0qm

] = c

m

c

1

, r

m

(q

1

, . . . , q

m

) = R

m

[e

0q1

, . . . , e

0qm

].

Here obviously q, q

j

, x, τ ∈ C

n

for j = 1, . . . , m, therefore qx means the

scalar product.

(4)

Applying (9) to the system [e

0q1

, . . . , e

0qm

] we get, for m = 2, h

2

(q

1

, q

2

) = r

2

(q

1

, q

2

) 

λ(q

1

+ q

2

) −

12

(λ(q

1

) + λ(q

2

))  , and for m > 2, defining p

l

= p

1

+ . . . + p

l

(l = 1, . . . , j),

h

m

(q

1

, . . . , q

m

)

= X

m j=2

X

|p|=m

( −1)

sj+1

r

j

(q

1

+ . . . + q

p1

, . . . , q

p

j−1+1

+ . . . + q

m

)

× r

p1

(q

1

, . . . , q

p1

) . . . r

pj

(q

pj−1+1

, . . . , q

m

)

×



λ(q

1

+ . . . + q

m

)

− 1

j (λ(q

1

+ . . . + q

p1

) + . . . + λ(q

p

j−1+1

+ . . . + q

m

))

 . Therefore if ∆

j

(t

1

, . . . , t

j

) = λ(t

1

+ . . . + t

j

) −

1j

[λ(t

1

) + . . . + λ(t

j

)] then we have the recurrence system of formulas for r

m

, with q = (q

1

, . . . , q

m

):

(10)

 

 

 

 

 

 

 

 

 

 

 

 

r

2

(q)∆

2

(q) = c

2

/c

1

, r

m

(q)∆

m

(q) = c

m

/c

1

+ . . .

+

m−1

X

j=2

X

|p|=m

( −1)

sj+1

r

j

(q

1

+ . . . + q

p1

, . . . , q

p

j−1+1

+ . . . + q

m

)

× r

p1

(q

1

, . . . , q

p1

) . . . r

pj

(q

p

j−1+1

, . . . , q

m

)

× ∆

j

(q

1

+ . . . + q

p1

, . . . , q

p

j−1+1

+ . . . + q

m

).

Now, with y given by (3), we can write R

m

(y, . . . , y)(x)

= R

m

h

\

−∞

e

−z(k1)(x+τ1)

Φ(k

1

)dk

1

, . . . ,

\

−∞

e

−z(km)(x+τm)

Φ(k

m

) dk

m

i

=

\

Rm

e

−[z(k1)+...+z(km)]x

Φ(k

1

) . . . Φ(k

m

)R

m

(e

z(k)

(0)) dk

1

. . . dk

m

=

\

Rm

r

m

(z(k))e

−[z(k1)+...+z(km)]x

Φ(k

1

) . . . Φ(k

m

) dk.

Thus we have proved

Theorem. Assume that |∆

j

(t

1

, . . . , t

j

) | ≥ A > 0 on the set

W

j

(p

1

, . . . , p

j

) = {(t

1

, . . . , t

j

) : t

k

∈ p

k

Z

, k = 1, . . . , j }

(5)

for every j ∈ N, j ≥ 2 and every (p

1

, . . . , p

j

) ∈ N

j

. Then we have a solution u of (1) given by a formal series

(11) u(x) = X

∞ m=1

\

Rm

r

m

(z(k))Φ(k

1

) . . . Φ(k

m

)e

−[z(k1)+...+z(km)]x

dk, with r

m

defined by (10) and Φ as in (3).

3. Example. Consider the equation

(12) ∆u = ∂

2

u

∂x

21

+ ∂

2

u

∂x

22

= X

∞ j=1

c

j

u

j

. We can write it as

∆u − au = bu + X

∞ j=2

c

j

u

j

,

with a+b = c

1

, a > 0. Then P (D) = ∆ −a and λ(q) = q

12

+q

22

−a. We choose Z

= {(ik, √

a + k

2

) : k ∈ R} and we can see that Z

+ . . . + Z

= nZ

= {(ix, y) : y ≥ √

n

2

a + x

2

, x, y ∈ R} ⊂ C

2

, 2Z

∩Z

= ∅ and nZ

⊂ (n−1)Z

. Moreover, S

n=2

(C

2

\ nZ

) = C

2

. We have

λ(z(k

1

) + . . . + z(k

l

))

= (i(k

1

+ . . . + k

l

))

2

+ ( q

a + k

21

+ . . . + q

a + k

l2

)

2

− a

= (l − 1)a + X

1≤m<j≤l

2( p

a + k

2m

q

a + k

2j

− k

m

k

j

) ≥ (l

2

− 1)a > 0.

For t

l

∈ p

l

Z

(l = 1, . . . , r) and m = p

1

+ . . . + p

r

(r ≥ 2) we also have

r

(t

1

, . . . , t

r

)

= ∆

r

(z(k

1

) + . . . + z(k

p1

), . . . , z(k

p

r−1+1

) + . . . + z(k

m

))

= λ(z(k

1

) + . . . + z(k

m

)) − 1

r [λ(z(k

1

) + . . . + z(k

p1

)) + . . . + λ(z(k

p

r−1+1

) + . . . + z(k

m

))]



1 − 1 r

 m

2

+ 2

 1 − 1

r



a = r − 1

r (m

2

+ 2)a > 0.

So the assumptions of the Theorem are satisfied.

4. Locally finite representation of formal solutions. Assume now that there exists a linear map A : C

n

→C

n

such that A(Z

) ⊂ R

n+

. We define b

R

n+

= A

−1

(R

n+

). We consider the space L

(ω)

(R

n+

) of Laplace distributions

(6)

(of type ω ∈ R

n

, see [4] or [5]), supported by b R

n+

, and denote by L

(ω)

(b R

n+

) the space of test functions φ = ψ ◦ A for some ψ ∈ L

(ω)

(R

n+

).

Consider a functional S

1

defined for φ ∈ L

(ω)

(b R

n+

) by

(13) S

1

[φ] =

\

−∞

φ(z(k))Φ(k) dk

with Φ as in (3). Obviously y in (3) is the value of S

1

on φ(z) = e

−zx

. Now we assign to S

1

a defining function Ψ

1

:

Ψ

1

(z) = 1 (2πi)

n

S

1

 e

−(z−w)2

(z − w)

1



for z ∈ C

n

# b R

n+

:= A

−1

(C

n

# R

n+

), where by C

n

# R

n+

we understand (C \ R

+

)

n

. We can see by (13) that

Ψ

1

(z) = 1 (2πi)

n

\

−∞

e

−(z−z(k))2

(z − z(k))

1

Φ(k) dk.

Therefore, for φ ∈ L

(ω)

(b R

n+

), we can write (cf. [5]) S

1

[φ] = X

σ∈{−1,1}n

sgn σ lim

ε→0+

\

b

Rn+

φ(u)Ψ

1

(u + iσε) du.

Hence for the solution y of (2) we get the following formula:

y(x) = S

1

[e

−zx

]

= X

σ∈{−1,1}n

sgn σ lim

ε→0+

1 (2πi)

n

\

b

Rn+

\

−∞

e

−zx−(z+iσε−z(k))2

(z + iσε − z(k))

1

Φ(k) dk dz.

For m ≥ 2, the mth term of the formal solution u is the value on φ(z) = e

−zx

of the Laplace distribution S

m

given by

S

m

[φ] =

\

Rm

φ(z(k

1

) + . . . + z(k

m

))Φ(k

1

) . . . Φ(k

m

)r

m

(z(k)) dk

with r

m

given by (10). By analogy with the case m = 1, we obtain the defining function for S

m

:

Ψ

m

(z) = 1 (2πi)

n

S

m

 e

−(z−w)2

(z − w)

1



= 1

(2πi)

n

\

Rm

e

−(z−(z(k1)+...+z(km)))2

(z − (z(k

1

) + . . . + z(k

m

)))

1

Φ(k

1

) . . . Φ(k

m

)r

m

(z(k)) dk.

(7)

Hence we get

S

m

[e

−zx

] = X

σ∈{−1,1}n

sgn σ lim

ε→0+

\

b

Rn+

e

−zx

Ψ

m

(z + iσε) dz.

We see that for m ≥ 2, supp S

m

= mZ

, and R

m

(y, . . . , y)(x) = S

m

[e

−zx

].

So if (m + 1)Z

⊂ mZ

, then we have u(x) =

X

∞ m=1

S

m

[e

−zx

] = S[e

−zx

]

and this formal series is locally finite, that is, for every φ ∈ L

(ω)

(b R

n+

) with supp φ bounded, S[φ] is the sum of a finite number of terms. More precisely, let φ(x) = 0 for |x| ≥ M, x ∈ b R

n+

. Since we can find N ∈ N such that N Z

∩ {x : |x| < M} = ∅ we have S

m

[φ] = 0 for m ≥ N. So S[φ] = P

N−1

m=1

S

m

[φ].

References

[1] V. I. A r n o l d, Additional Topics in the Theory of Ordinary Differential Equations, Nauka, Moscow, 1978 (in Russian).

[2] A. B o b y l e v, Poincar´e theorem, Boltzmann equation and KdV-type equations, Dokl.

Akad. Nauk SSSR 256 (1981), 1341–1346 (in Russian).

[3] R. R. R o s a l e s, Exact solutions of some nonlinear evolution equations, Stud. Appl.

Math. 59 (1978), 117–151.

[4] Z. S z m y d t and B. Z i e m i a n, Laplace distributions and hyperfunctions on R

n+

, J.

Math. Sci. Tokyo 5 (1998), 41–74.

[5] B. Z i e m i a n, Generalized analytic functions with applications to singular ordinary and partial differential equations, Dissertationes Math. 354 (1996).

Institute of Mathematics Cracow Pedagogical University Podchor¸a˙zych 2

30-084 Krak´ ow, Poland E-mail: meplis@wsp.krakow.pl

Re¸ cu par la R´ edaction le 16.12.1996

evis´ e le 5.11.1997

Cytaty

Powiązane dokumenty

By means of a Riccati type transformation, necessary and sufficient conditions for the existence of eventually positive solutions and positive nonincreasing solutions are

Before we start the derivation of the fundamental pursuit equation in the electromagnetic and gravitational field, we remind the basic notions of the relativistic theory

The parameter σ α has appeared in many papers on exponential sums but we are not aware of an upper bound of the type (1.13) ever appearing before, even for the case of

Pinch [P] which, though based on the theory of linear forms in logarithms of algebraic num- bers, does not require high precision computations with algebraic numbers and

As mentioned in Section 5, the plan is to apply Theorem 3.1 to equations of the form (3.2) defined by certain minimal forms L ∈ L(T ).. Since we must apply transformations to the

We note that, at first glance, the results Carlitz achieves in [1] do not appear to be the same as Theorem 1 with α = 1.. It can be checked, however, that they are

In 1842 Dirichlet proved that for any real number ξ there exist infinitely many rational numbers p/q such that |ξ−p/q| &lt; q −2.. This problem has not been solved except in

In case µ = 0 of the ordinary Hermite transform the product formula (27) of GHP is not correct in case of even degree n of the polynomials, since they are connected with the