OFFICE OF NAVAL RESEARCH Technische Hogeschool DEPARTMENT OF THE NAVY
Deift
CONTRACT NONR-220(35)
SPINUP OF A CONTAINED FLUID
BY
GIULIO VENEZIAN
DIVISION OF ENGINEERING AND APPLIED SCIENCE
CALIFORNIA INSTITUTE OF TECHNOLOGY
PASADENA, CALIFORNIA
Office of Naval Research Department of the Navy
Contract Nonr 220(35)
SPIN-UP OF A CONTAINED FLUID
by
Giulio Venezian
Reproduction in whole or in part is permitted for any purpose of the United States Government
This document has been approvied for public
release and sale; its distribution is unlimited.
Division of Engineering and Applied Science
California Institute of Technology Pasadena, California
'Present Address - Univ. of Hawaii
When a container filled with fluid rotates uniformly, the fluid ultimately reaches a state of rigid body rotation with the same angular velocity as the container. The process whereby the fluid changes its angular velocity from an initial value to a final one when the walls of the
container are given a corresponding change is called up (or
spin-down if the final angular speed is less than the initial one). In a more
general sense, the spin-up process is involved in the approach to steady
state of all contained fluid motions in which the final state is dominated
by rotation. We shall adopt this wider view here.
In all spin-up phenomena, the steady state is reached not by viscous diffusion but by an internal circulation produced by the Ekman layer suction. It was shown in the first of these seminars(U that the
time constant associated with the decay of motion in a contained fluid is
proportional to Ez, where E = vh2 is the Ekman number.
The characteristic time for viscous diffusion, on the other hand, ispro-portional to E and since in most applications E is very small, a time
scale of order E2 is much shorter than one of order E. Spin-up is
and
-2-The Ekman layer and its formation
In 1905, Ekman2 investigated the effect of the motion of a rigid
boundary on the flow of a rotating fluid. In particular, he considered the
motion that is produced in a fluid adjacent to an infinite flat plate when the
plate, as viewed ìn a rotating reference frame, is moved rectilinearly in
its own plane.
The simplest example of such a motion is the following. A homo-geneous fluid occupies the space above a rigid plane located at z = 0.
Far away from the plane the fluid is in a state of rigid body rotation with an angular velocity 2, parallel to the z axis. Relative to a reference
frame rotating with the same angular velocity 2, the plane is moving
with a constant velocity U along the x axis. We are interested in the
motion of the fluid.
The equations of motion of a fluid relative to a rotating frame are:
+v.Vv +2X
=-Vp+vV2v
(1)Vv
= O . (2)Let u,v,w be the components of y along the x,y,z axes.
For the problem at hand we seek a solution of Eqs. (1) and (2) subject to thecon-ditions
u=U
,v=w=0
on z=0and
u=v=w=0
at z=which are functions of z only. In that case Eq. (2) states that
8z
and, in view of the boundary conditions, w = O throughout. This
elimi-nates the non-linear advection term, and the equations for u and y are
simply d2uV-+ZV=O
, (3) dz2 d2y-
2Çu=0 (4) dz2The linear combination u u + iv then satisfies
dk
v__±+2iu =0
dz2 + so that -(l+i)zf u+ = ¡Jewhere we have made use of the boundary conditions at z = O
and z
=The real and imaginary parts of this expression then give u and y: - z
u = ¡Je cosXz , (6)
->.z
y = -tJe sinXz (7)
where X = (Wv)2. When y is small,
u and y drop rapidly to zero
and are significant only in a thin layer of thickness (v/2)2 . This layer
is called the Ekman layer.
As the plate drags fluid along, the Coriolis force deflects the fluid to the right so that there is a mass transport in the -y direction as well as in the x-direction. The two mass fluxes are equal, since
so that and i 1 v U(l -i)
udz
= oi
Qx =Çj
a=('12
o Q yrc
vdz o-4-The net transport of fluid is thus at 45° to the motion of the plate. With slight modifications, these results hold for a uniform flow
over a stationary flat plate. A flow with velocity U in the x direction
in the bulk of the fluid can be maintained by a pressure field p = 22Uy. The velocity then has to drop to zero at the wall and this is accomplished in the Ekman layer. The expression for u in this case is
-(l+i)X z
u = TJ(l-e
with corresponding expressions replacing Eqs. (6) - (9).
One important question that arises, and which was discussed by
Ekman in his paper, is how the steady state solutions given by Eqs. (6) and (7) are attained when the plate is initially at rest and at t = O it is
impulsively given the velocity U. For this problem, Eq. (5) is replaced by
au+ a2u
-4-V
-+ (10)
subject to u+ = O for t < O,
and u, = U at
1z = O for t> O.
This problem can be solved by Laplace transforms. Let
= iT(s) + i(s) be the Laplace transform of u+ then
(8)
V = (s+2i)u+ a Z
with =
U/s at z
= O. ThereforeIs + 2 i2 -z'
'1
e
The inverse transform is found in tables of Laplace transforms, with the result + (1+i)f j =
s:
dz = I Uy2 sjs+2i2 (12) (14)The inverse transform of this expression is
=
()2U(l-i)erf{(l+i)]
, (15)u = U
-
e-(l+i)Xzerfcii z2/
+ U e(l+i)Xz erfci z
2f
The error function complement is defined as
erfcu = Ç
edx
(13)and it is equal to 0, 1, or
2 when u is equal to
, O, orEquation (12) thus tends to the correct values for t =
O and t
= oo Thedetails of how the final state is achieved can be obtained from the asymp-.
totic behavior of the error function. Briefly, the results are that the layer forms in a time of order i
/,
that is, in a few revolutions,al-though the inertial oscillations generated by the impulsive motion of the boundary last much longer. These results can also be obtained by ignoring the detailed structure of the flow and looking only at the mass
flux. From Eq. (11),
U u+ s
-6-I which may be separated into real and imaginary parts in terms Fresnel
integrals.
For large values of x,
i -X2
erfx'l
e so thati
1 vi2()
U(ii)[i
[zt
andFor small values of x,
1 31
erfxr.x
-x
so that
Q
-UJic2t
y 3 Tr
The time in which the mass flux builds up from zero at t = O to the final
value can be estimated by extrapolation of these equations. This gives a
time which is a fraction 1/2. What happens in fact is that there is a considerable overshoot followed by oscillations of frequency Z2 about the final value which decay in amplitude as
For our purposes, it is sufficient to note that the Ekman layers are established very rapidly. If one is willing to forego a detailed
(18) (19) or Q
u[l
+ sin 22t (16) J2iî2t7cos2t
X and Q y2)
U /2 Tr2t (17)examination of their formation, they can be regarded as formed instant-aneously, as compared to the other time scales involved. At the same time one should keep in mind that in the case of the earth, a few revolu-tions means a few days. It may seem unreasonable to regard such a
period as short, but it is if the other time scales are measured in months or years.
Ekman layer suction
The flows we have just discussed are exact solutions of the Navier
Stokes equations. In them, rapid spatial variations in the fluid velocity occur only in a layer of thickness ô = (v/2)2. If this thickness is small
when compared to the geometrical dimensions of the system being con-sidered, such as the curvature of the wallor separation between walls, it can be expected that a good approximation to the flow may be obtained from equations similar to Eqs. (3) and (4).
Two requirements have to be met.
If h is a characteristic
dimension parallel to 2, the Ekman number is E v/2hZ, and thus
the condition that ô « h means that E « 1. The second condition is that the non-linear advection terms must be negligible. The flows considered
in the previous section were parallel, and the non-linear terms were
exactly zero. Since we can no longer expect this to be the case we must
require that in some sense vVv should be small compared to, say
Z X y. If 13 is a characteristic velocity (relative to rigid body
rota-tion) this means that the ratio E = U/22L should be small, where L is
some typical dimension perpendicular to 2. This ratio is called the
-8-If these conditions are met, a set of equations which are correct
up to terms of order E and
can be derived for the flow adjacent tothe wall.
Let y
= VT + VN be the velocity relative to the interior fluid where VT is tangential to the wall and VN is normal to the wall. Let n be a coordinate normal to the wall and = nIó. Then the tangential part of the momentum equation becomesI
+ 2X
=SV
at
while the normal component simply gives the pressure, and is not
important for our purposes. The equatiön of continuity reads
SVN
= - o V. VT
These are the boundary layer equations, except that, as it was discussed in the preceding section, the first term can be omitted in Eq. (20) if the
time required for the boundary layer to form can be neglected.
By assumption y exists only in the boundary layer and is zero for large values of . At the wall, y added to the velocity V of the
interior flow must be equal to the wall velocity. Note that VN is of
order E2 smaller than
VTTo illustrate the use of these equations, consider the steady flow that exists in a rotating fluid over a flat plate, when the plate is given an
additional angular velocity i&2. Let the plate be at
z = O and let u,v,w
be the velocity components in cylindrical coordinates.
The interior flow (for zero Ros sby number) satisfies the inviscid
and But so that and
ia(s)
+-C
r 8r
arFrom Eq. (23) and the boundary condition u+ = iM2r at r = o,
= ir
el+
Similarly from Eq. (24) and the condition that W = O at = O,
=-W(r)-ó
Ç 1 a- (ru)d
(26)Now, w(oc) O, and hence
/b OC W(r) = 1 a
(r)d
o(1+i)2r
Zd= -S2r
- 22V = - 8r 22U = O (22) ap - azwhere we have made use of the axial symmetry. The equation of continuity is simply 3W/Sz = O since ¡J = O. Thus the interior flow can be satis-fied by any flow field (O, V(r), W(r) ). The angular velocity of the fluid
at z = has been specified as zero, so what remains is W(r).
The boundary layer equations are:
ar +
-lo-W(r) = - . (27)
Thus there is a uniform suction of fluid into the boundary layer. The suction is proportional to y2 and to the excess vorticity of the wall
velocity as compared to that of the fluid.
Non-linear effects in the boundary layer
The problem we have just considered has a similarity solution which reduces the full non-linear equations to ordinary differential
equations, which can be solved numerically. The similarity solution was
found by von
Karman3,
who also solved the resulting equations byap-proximate methods. A numerical solution was later given by Cochran4.
(5)
More recently Rogers and Lance gave numerical results for the full
range of relative rotation rates between the fluid and the plate when the
angular velocities are in the same direction. Cochran had considered only the case where the plate is rotating and the fluid at infinity is not.
Bodewadt6 had considered the opposite case.
The key to the von Karman solution can be seen from the ap-proximate treatment of the preceding section. The velocity components
parallel to the plate are both proportional to
r, while w is only a
function of z Under these conditions, the components of the non-linearterm v.Vv, while non-zero,have the
same dependence on r as the corresponding components of y The linearized equations are not anexact solution, but there is an exact solution with the same r dependence.
Moreover, z and y appear only in the combination zIó, so that 6 is
is often used to introduce the notion of boundary layers, and is much more familiar to fluid dynamicists than Ekman flow. For example, Schlichting's book on boundary layer theory7 treats Karman flow but
does not mention Ekman flow. The details are found in any of the papers cited as well as in many textbooks.
The result that concerns us is the dependence of the suction on
the Rossby number. Figure 1 is plotted from the numerical data in
Rogers and Lance.
It shows the value of -w()/2ó plotted versus the
ratio w/2, where w is the angular velocity of the fluid at infinity and
-12-represents the linearized approximation given by Eq. (27).
It can be seen that the linearized approximation is quite good over
a large range of Rossby numbers. Even when the fluid at infinity is at rest a fairly good estimate is obtained. The correction for small Rossby numbers is found in Rogers and Lance. It is
-w(cc)/2ó =
- 0. 3+
0.0875E3 + 0(é) , (28)wh e r e
The corrections are small, and if necessary can be carried in the analysis
in a form equivalent to Eq. (28), Alternatively Eq. (28) may be used to
estimate the error involved in the linearization.
A much more difficult error to estimate is the error incurred in
the local nature of the linearized Ekman layer. In the analysis given in the preceding section, the flow at any point in the boundary layer is deter-mined exclusively by the difference be tween the velocities of the wall and interior flow over that point. The suction is determined from the diver-gence of the Ekman layer transport and depends only on the first
deriva-tives, since it is proportional to the difference between the wall vorticity
and interior vorticity over that point. For moderate Ros sby numbers, and particularly over regions in which the fluid vorticity changes rapidly,
the boundary layer is definitely non-local. We shall return to this point
later,
Spin-up between parallel planes
The earliest theoretical study of spin-up appears to have been done by Bondi and Lytt1eton8 in their investigation of the role of the
liquid core in the dynamics of the secular retardation of the earth. They
concluded that the motion of the core lagged behind that of the mantle by a time essentially equal to the spin-up time. Later a thorough study of linearized spin-up was made by Greenspan and
Howard9 for
a generalaxially symmetric container. More recent publications include those of
Greenspan0 and Pedlosky and Greenspan('U for non-ially symmetric
containers.
The spin-up of a fluid contained between parallel planes was con-sidered in detail by Greenspan and Howard. It is probably the simplest example of spin-up, although it lacks some essential features because
of the absence of lateral walls. The simplicity derives from the fact that,
as in Karman flow, the r dependence is trivial,
u and y are
proportion-al to
r,
while w does not depend on r. Under the circumstances, theequations of motion involve only
z and t,
and the linearized problemcan be solved exactly, although not in closed form. The non linear problem also involves functions of z and t only and can be solved
numerically. This was done by
Pearson2.
We shall only give theapproximate results, using boundary layer theory.
The problem is that of a fluid contained between the planes
z = -h/Z and z = h/2.
At t = O, the fluid is rotating at an angular speed- M2, and the angular velocity of the plates is impulsively increased to 2. We want to find the subsequent motion of the fluid. The equations which
govern the interior flow are
3V
Z2V-at_
-=0 (29)
aW_
ap-
-14-where we have made use of the axial symmetry. Now, W is produced
i
by the Ekman layer suction so it is of order E2,
and since U is
con-nected to W by the equation of continuity, U is of the same order. Thus the term au/at is certainly negligible compared to 22V, In the
second of these equations, both terms must be of the same order since
V must change in time and [J cannot be zero if fluid is to be conserved.
It follows that 8/at is of order E2.
The third expression then equates8P/Oz to a quantity of order E,
and since 3P/8r is of order
1, theleft hand side may be put equal to zero. Equations (29) are therefore replaced by
22V=
+22U=0
(30)0-Except for the presence of the av/at term these are the same as Eqs.
(22).
The interior flow is thus satisfied by functions U, V, P which
depend only on r and t, and W which depends linearly on z (to satisfy
continuity) This flow must be connected to the boundary conditions by Ekman layers of the type described in Eqs. (23) - (27).
At z = -h/2,
the Ekman suction requires that
In both cases, since the boundary is rotating faster than the interior which is the analog of Eq. (27). Similarly, at z = h/2, the condition is
W=--(rV)
(32)'
(V < O), fluid is ejected radially along the boundary layer and must be
supplied to the layer from the interior.
This requires a negative W at
the lower boundary and a positive one at the upper boundary.
Since W is linear in
z,W=-z--(rV)
The equation of continuity then gives
---- (rU)=---(rV)
r8r
hrar
so thatU=rV
This indicates that for V < O a radial influx is needed in the interior
fl"w to make up for the fluid that is leaving the boundary layer.
Finally, the equation for V becomes
(35)
and since V = -A2r at
t = O,2Th t
V=-A2re
h (36)The corresponding expressions for U and W can then be obtained from
Eqs. (33) and (34). The spin-up time is the decay time in Eq. (36), that
1.
is, h/ZQ5 = E2/22.
The physical mechanism for the spin-up process is therefore the following: since the interior fluid is initially rotating at a slower rate
than the boundaries, fluid is ejected by the walls along both Ekman layers. The fluid transported outward flows with a velocity of order 1 in a layer
-16-i
i
of thickness proportional to E2,
so the mass transport is of order E2.
This requires an equal and opposite mass transport, this time in a layer
with a thickness of order 1, so the radial velocity is proportional to
E. The incoming fluid comes from regions of higher angular momenftm, and since the interior flow is essentially inviscid, the angular momentum
is conserved. In this way the interior flow is speeded up until it rotates at the same angular velocity as the plates and the Ekman suction ceases.
Non-linear spin-up in a cylinder
Linearized spin-up in a cylinder was considered by Greenspan
and Howard. The non-linear case can be treated with equal ease,
pro-vided one assumes that the flow in the Ekman layers may be linearized. This approach was used by
Wedemeyer3
and is presented here with some extensions by Ingersoll andVenezian4,
Wedemeyer considered only spin-up from rest. We shall look at
the general case when spin-up is from an initial angular velocity w to a
final angular velocity 2, with the axis of rotation parallel to the axis of
the cylinder. Since the Rossby number is no longer small, there is no advantage in referring the flow to rotating coordinates, so we shall use an inertial frame of reference.
The equations of motion for axially symmetric flow, including
r
non-linear terms are:
au 8u y2
+u+w---
+ u (37)8r 8z r - 8r r2
8v
+u +w+ =v
8v 8v uy (Va - (38)In view of Eq. (42), however, V is not a function of z so that the last term of Eq. (41a) is zero and that equation is replaced by
SV
+ -- (rV)=0
US
Moreover, it follows that U must also be a function of
r and
t only,and hence W is again linear in z
The Ekman layers on the flat lids of the cylinder at z = ± h/2
are treated in the same manner as before. The results are the same as Eqs. (31) - (33), except that they must be referred to the inertial frame.
W,
of course, is the same, but V must be replaced by V -
2r.Cor-responding to Eqs. (33) and (34) we now have
zó 1 8
(rV-r2)
--
-7i:-and Sw 3w - + v2w- +u - +w - =
St Sr Sz SzFor the reasons discussed in the previous section, we expect that
in the interior flow U, W and S/St are of order E2.
To leading order,so that Eq. (41) becomes
U=(V-2r)
(39)
Eqs. (37) - (39) then simplify to
+
U/-y
+ V2 SP 0 (40) (41a) (42) r -W Sr = St Srr)
0-Sz - Sz
-18-8V
-+--2(rV)=O
6 V 8. (45)
This will be called Wedemeyer's equation. It contains within it the entire physical description of the spin-up process.
Wedemeyer's equation simplifies somewhat if the angular momentum density G rV is used instead of the azimuthal velocity.
The resulting equation is
8G 6 (GÇ2rz)8G_
-This equation can be solved by the method of characteristics. Indeed,
when the equation is written in this form it is clear G is constant along
a characteristic, i e. a line in the r-t plane such that
dt h r
dr -
Ç2r2-GSince G is constant along such a line, Eq. (47) can be integrated directly
to give
t=
h log(2rZG) + F(G) (48)where the constant of integration may vary with G.
On the initial line t = O, G = wr2.
This value of G is carried
along each characteristic curve, so thatF(wr2) = log(2w)rZ
or
F(G) =
log - G
O)
Hence, Eq. (48) becomes
In the case of spin-up, when < 2, Eq. (49) carries only the values
O G wa2. The characteristic that carries the value G = wa2
starts
at r = a at
t = O and is subsequently given by r = r0(t), wherei
rw 2-w -Z62t/h1 2 (50)
r
=aI+---- e
J
o
For t> O,
r0 is less than a and thus Eq. (49) represents the value of
G only for
r < r0. For r > r,
all the values of G between wa2 andQaZ have to be filled up, by a fan of characteristic lines all of which
start at r = a.
In this case, F(G) = log(a2-G) so that 2r2 _ÇZ -Zó2t/h G= - Z 6 Qt / h 1 -eThe motion described by these equations has several interesting
properties. The flow is divided into two regions by a moving front located at r = r0(t). This front starts at the outer wall, and gradually
moves in to the position r/a = (/2). The flow inside the front rotates
rigidly with an angular velocity that increases from w to 2, as it can
be seen from Eq. (49).
If the spin-up is from rest, G is zero in the
entire region
r < r0 for all time.
This region, however, shrinks tozero radius as
t - oc, so that the entire fluid eventually spins up.In the region between the front and the wall, the azimuthal velocity consists of two terms, one proportional to r and one to i Ir.
-20-These are such that the azimuthal velocity is 2a at the wall, and o.a2/r
at r. The latter value is the same as that reached at
r by the velocityon the other side of the front.
Thus U and V are continuous across
the front. The derivatives, however, are not continuous so the front is
a moving shear layer. U at the shear layer is equal to dr0/dt,
itsvelocity of advance, so that no fluid crosses it. The fluid that pushes the layer inward is the fluid that has been sucked into the Ekman layers
in the region r < r, has been ejected
outward in the layers acquiringangular momentum in the process, and is ttxen ejected from the Ekman
layers in the region r > r0.
In the case of flow between parallel plates, the front does not exist, since fluid of higher angular momentum is always available at
larger and larger r This feature is a consequence of the infinite
extent of the plates. In the case of spin-up from rest, however, the
model breaks down unless time dependent Ekman layers are used, since
there is no reservoir of angular momentum. No such breakdown occurs
in the finite cylinder since the side walls act as constraint forcing the fluid
sucked into the Ekman layer to return to the interior.
The behavior of the flow during spin-down is markedly different from that during spin-up. If w > , the flow no longer divides into two
regions and Eq. (49) describes the entire flow. The dividing characteristic
moves towards increasing r, and thus it has no physical significance.
In this case there is only one shear layer, which remains attached to the
wall.
In the discussion of the cylinder given by Greenspan and Howard, they found no difference between spin-up and spin-down. The reason for
this is that the shear layer moves only from r
a to
r = a(w/2)2 =E = O, the shear layer does not move away from the wall at all.
Non-linear spin-up in an axially symmetric container
Wedemeyer's theory can be extended to the case of an axially
'symmetric container. A brief account of this will be given here. Further details appear in Ref. 14. Let the walls be at
z = f(r) and z = -g(r),
so that the height of the container is given by h(r) = f(r) + g(r). The
linearized Ekman layers for this configuration were treated by Greenspan and Howard. When they are taken into account, Eq. (46) is replaced by
+ (G-2r2)
9
= O at r where ii
t '4(1+f)+(1+g
) o = 2(f+g)G is constant along the characteristics, which have a slope dt
dr -
rThe initial conditions can be incorporated into this expression by writing
t as a definite integral.
For r < r(t),
t= -
r r dr (54)while for r > r(t),
ca
rdr
r
(r)(rZG)
o
where a is the radius of the container.
The characteristic r (t) is the o
-22-one that carries the value G = waZ and is thus given by
t=
rdr
(56)r
For the special case in which f = g = h/2, Eqs. (55) - (57) are equivalent to Eqs. (49) - (51).
The character of the flow is substantially the same as in the case
of the cylinder. For spin-up, there are two distinct regions separated by a shear layer.
A non-linear theory of spin-up for axially symmetric containers was also developed by Greenspan and
Weinbaum5.
It consists of asystematic expansion in powers of of both the interior flow and the Ekman layers. This is in contrast with the theory just discussed, in which the Ekman layers are treated as linear, while the resulting interior
equations are then solved exactly. To a certain extent this could be
remedied by allowing ,u to be a function of G as well as r, according
to an expansion similar to Eq. (28). The main error, however, is that ¡L is really non-local and must depend not only on G but on its
deriva-tives as well. This may well be the source of serious error near the shear layer.
On the other hand, the approach of Greenspan and Weinbaum
suf-fers from its drawbacks as well. A moving shear layer is an essentially non-linear feature, which cannot appear in a power series expansion. Moreover, the expansion fails near h = O. The Wedemeyer approach
has the advantage that the physical situation is more readily appreciated and is not hidden in interminable algebra. The real test of the theory, however, rests on the presence or absence of the moving shear layer. In this respect, experiments favor the non-linear theory discussed here.
References
1. Venezian, G. Seminar of 4/9/68.
Z. Ekman, V.W.,, Arkiv. Math. Ast. Fys. Vol. Z, No. 11 (1905).
von Karman, T,, ZAMM1, 244 (1921)
Cochran, W,G,, Proc. Camb. Phil. Soc. 30, 365 (1934).
Rogers, M.H. and Lance, G.N., J. Fluid Mech. 7, 617 (1960).
Bodewadt, IJ.T., ZAMMZO, 241 (1940).
Schlichting, H, Boundary Layer Theory, (McGraw Hill Book Co., New York, 1960) P. 83.
Bondi, H. and Lyttleton, R.A., Proc, Camb. Phil. Soc. 44, 345
(1 948).Greenspan, H.P. and Howard, L.N., J. Fluid Mech. 17, 385 (1963). Greenspan, H.P., J. Fluid Mech. 20, 673 (1960).
Pedlosky, J. and GreenspanH.P., J. Fluid Mech. 27, 291 (1967).
12, Pearson, C.E., Sperry Rand Res. Center Report RR-64-41 (1964).
Wedemeyer, E.H. , J. Fluid Mech. 20, 383 (1964).
Ingersoll, A. and Venezian, G., unpublished.
Greenspan, H. P. and Weinbaum, S,,, J. Math, and Phys. 44, 66 (1965).
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DDIFORTMNOV 65
1473
I (PAGE 1) Uncias s if je dDOCUMENT CONTROL DATA - R & D
Secur,ty classification of rUle, body of abstract and indexing' annot8lic,rl n,ust be entered s'hen the overall report is classified) ORIGINA TING ACTIVITY (corporate author)
California Institute of Technology
Division of Engineering and Applied Science
2e. REPORT sEcuRITY CLASSIFICATION
Unclassified
2b. GROUP
Not applicable
3. REPORT TITLE
SPIN-UP OF A CONTAINED FLUID 4. OESCRIPTIVENOTES(TtpeofreportandinC1usivedateS)
Technical Report
5. AU THORIS) (First name, middle initial. last name)
Venezian, Giulio
6. REPORT DATE
March 1969
78. TOTAL NO. OF PAGES
23
7b. NO. OF REPS
15
Sa. CONTRAC T OR GRANT NO. Nonr 220(35) b. PROJECT NO.
C.
d.
Sa. ORIGINATORS REPORT NUMBER(S)
97-17
Sb. OTHER REPORT NO(S) (Any other numbers that may be assigned this report)
10. DISTRIBUTION STATEMENT
This document has been approved for public release and sale; its distribution is unlimited.
I. SUPPLEMENTARY NOTES 12. SPONSORING MILITARY AC TI VITY
Office of Naval Research
3. ABSTRACT
In all spin-up phenomena, the steady state is reached not by viscous
diffusion but by an internal circulation produced by the Ekman layer suction. It
was shown in the first of these seminars(U that the time constant associated with
the decay of motion in a contained fluid is proportional to E2, where E = vh2
is the Ekman number. The characteristic time for viscous diffusion, on the other
hand, is proportional to E and since in most applications E is very small, a
time scale of order E2 is much shorter than one of order E. Spin-up is
there-fore the more effective of two mechanisms.
Uncias sified Security Classification
D D I NOV 6S JFORM 1473 (BACK)
(PAGE 2)
Uncias sified
Security Classific atior
KEY WORDS LINK A LINK B LINK C
ROLE WT ROLE Wr ROLE WT
Viscous Flow - unsteady
Rotating flow Boundary layer