r
P.J. Verbrugh
Unsteady Lifting Surfacé Theory fòr Ship Screw.
Report no. 68-036-AH April 1968 Part I : Text
UNSTEADY. LIFTING SURFACE THEORY for SHIP SCREWS by P.3. Verbrugh. Introduction.
DuMng the last years many reports on ship screws operating in a real wake have been published. The objective of this
continuingseries of theoretical investigations is to approximate
the physical reality ever closerby.studying more realistic mathematical models.
Early studies in this field were undertaken by Tim.man and: Van de Vooren [i] on unsteady rotating wings. Ritger and Breslin
[2] developed a strip theory, based upon the ùnsteady twodimensiona: airfoil theory of Von Karman and Sears [3], corrected for three-dimensional effects. Compared with experient, however, this theory was found to be inadequate for an unsteady propeller.
A better approximation for the unsteady propeller problem was given by Shiori and Tsakonas [k]. Their starting point was a threedimensional unsteady theory, formulated, by Hanaoka [5], a theory that leads to a quite complicated integral equation. Shiori and Tsakonas simplify this integrai equation according to the well-known Weissinger - method. They could not prove that the Weissinger model was fully satisfactory for the unsteady case.
More recently Tsakonas and Jacobs. [6] have solved the surface integral equation for a mathematical model n which the chordwise loading is taken. to be the lat-plate. distribution, with the.
boundary conditions satisfied by a weighted average over the chord
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In none of these theories, however, one has the ful]. freedom in choice of the chordwise pressure distribution; one is restricted to distributions of the type
a. CO° - o 2
wheref' is the chordwise angular coordinate ((p = O corresponds to the leading edge).
To overcoijie this objection one is logically led to the conclusion to apply a more rigorous three-dimensional unsteady lifting surface theory. This is what Laschka [7] did in his dissertation. It is true indeed that he applies his theory to vibrating wings, but his work proves it does no longer hold to say that the kernel involved is too complicated for numerical computations. Application of Nuithopp's [8] collocation method leads to a rather elegant solution.
The present report develops a consistent lifting surface theory fora ship's screw in a non-uniform flow. The method is based upon the integral equation derived by Sparenberg
[9]
and [10], by means of anacceleration potential. This theory leads to two equivalent integral equations, one following from avortex model, the other appearing when representing the liftig surface by a doublet layer. The first integral equation leads to Cauchy-singularities, the latter to Hadamard-singularities. The last representation is chosen here for further calculation. It is true indeed, that the Hadamard.-singularity needs some analytical work before we can start the numerical computations, but the other integral equation needs also a lot of preparatory work, moreover from a calculatory point of view this representation is less compact.
After giving a short review of the derivation of the integral equation the author continues making the kernel accessible for numerical computation by separating singular and non-sIngular parts in a similar way as Laschka does in his doctor's thesis. Finally a method is given for spanwise and chordwise integration.
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method. The pressure distributiön along the chord is represented by a series öl .Tschebyscheff-pOlyflOmialS, the integration of
which is carried out by numerical methods.
The author is very much indebted to Prof1 dr. ir. A.I. v.d.' Vooren, whose valuable suggestions and guidancewere of great. help in accòmplishing the work presented here. He also wishes to express his thanks to the members of the panel, Prof. dr. ir. J.D. van Nanen, Prof. dr. ir. J.A. .Sparenberg, Prof.. dr. R.
Ti.inman and Prof. dr. ir.'L. van Wijngaarden, underwhose super-vision the work has beenperformed.
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Formulation of the problem
The wake behind a ship, in which the screw operates, can
not be treated as a homogeneous flow. Although this flow is assumed to betixne-independ.ent, the rotating blades, which cut through
this disturbance, experience a time-dependent flow, provided the inhoniogeneous character of the flow is not axial symmetric. The
r
problem, therefore, must be attacked by non-steady lifting surface theory. For simplicity we assume no interactionbe-tween propeller and aftership. The coordinates that fit best
Fig. no. I in the theory are cylindrical
coordinates X ,
r ,
Lp. If we take the disturbance velocities to beinduced by the ship's hull,
inducedby the screw and
the homogeneous flow velocity,
the three orthogonal directions:
U
¡vo+vvt
J
W0
+The non-linear model is, from a mathematical point of view extremely difficult to treat, so.we assume the disturbance
velocities small compared with the undisturbed flow veiocityU.
¡1_jo
,f/o
LJ,V
u,o
we have for axial radial tangential:1.
Hydrodynanlic .equatiotisThe starting point of our thèory is the set of hydrodynamic equatiois
(us) (u
)ì
(LJ)
('4}
(L))*(1J)
rp
I
U)
T
(
-
(.\L ) (u)(' ) (V)('J)
d
4(V)
=t
(4) (u)(Ç)+
(Ve)
+(ì)ip(&JÇ»
The last assumption in the foregoing section simplifies these equations considerably. The linearized set of equations, taking into account the time_independency oU andu0.,'0 W0, is
-'
(2) ç
+
U
If we state f rther that thé pressure in the wake is a composition of the pressure due to 11e ship hull,,, which is continuous over the propeller plane:and the pressure due to the disturbance inducéd by the screw,
p ,
which is definitly nOtcontinuous at the propeller plane,we can, according to the superposition principle, decompose. the equations into
(3)
u
Uc-
j_
o
t-(4),
-ti-
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In the following we shall pay our attention to eq. (4),
:
combination with the
continuity
-equationan incompressible, irrotational fluid. we can define a velocity
potential. The pressure also satisfies the Laplacia.nApo,
which follows from eq. (4). (by differentiating the equations with respect tox,) andLp, dividing the last equation throughr and. by making use of eq. (5)), so that we can défine an acceleration
functionJ-3-P.
These two
functions
andy are relatêd by .(6)
a solution of which is given by
(7).
UJ00
U
assuming all disturbances zero at infinity.
2. Boundary conditions.
Consider a rotating helicoidal surface
J
(w., r. ii',
)
_ o.,-+
where i.represents the angular velocity. This surface does not
disturb an incoming flowU, o,ojfo . In a non-uniform flow,
however, it induces disturbance velocities u1,1 anthJ. Furthermore the screw blade P = O does not ly at the helical surface H = O, but differs slightly from it
fLc.,r,Lr
tj+Ab+E
The function
Fbçi-'iS
a measure for the deviation of the scroz-blade from the helical surface. This deviation inducesdisturbancesu,v andw . The sum of those disturbances is, as
2.2.
2.we defined earlieru 1+LJ2,VV1+V2 ,
and WW,i-W
To satisfy the boundáry conditions the velocity near the blade has to be tangeñtiai to the surface
Substituting the expression for F' and neglecting second and higher order terms, we obtain
(io)
c.-pUE+$1_c
If we takeS to be zero we arrive at the boundary condition for a cambered profile in a homogeneous flow
(ii)
u
ForE= O eq. (iO) yields the boundary condition for a flat plate in a non-homogeneous flow
(12)
_6u04-LJ,
U
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PROEFSTATION WAGENINGEN
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We can treat these equations seperately, according to the superposition principle (linearized model) and we will òciIpy ourselves first with the case, for which éq. (12) serves as a boundary condition: a rotating helicoidal surface in a non-homogeneous flow.
We now
try
to find a mathematicál representation for thissurface. The nbrmal direction of the surface H O is given by
(13)
(-1
I C being
/j»4\2.
V
+rJlLrb(f1.
after substitution of C and calculation of the partial derive.
tives we get .
o
'
U
Ç'TP+
r'
hence the disturbance velocity in the normal direction is
tor
-)
+
. UVu
.y
u +
which is zero according to eq. (12).
The normal acceleration. is . . .
1-
'42
iff 1UàLva-A.
Ì1L1.1).
.
.
c)L] U.s
rSu0.)+ U
+43 [.ru+iJ
From eq. (15) it follows that this is zero. Hence the normàl acceleration is independent of the side of the surface. From the hydrodynamic equations, the definition of the acceleration
.potentialand
the
result deduced from eq. (16) we can concludethatis continuous over the surface.
Knowing
that anybody inaioV'can
be replaced by a distribution of sources (sinks) and doublets, we choose in favour of the doublets, being the only distribution with a continuous normal derivative.. This means thatwe can represent the screwbiade (helical surfaòe) by a doublet-layer of pressure dipoles.
NEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
3. The velocity field.
The pressure field induced in a point with coordinates
(x,'-,) by a pressure pole of strength,A.tat a point (,çe) is
________
I'-.'c
e9))jk
From this expression we can derive the field of a pressure
doublet by differentiation in the direction normal to the helical
surface. This means that we have to calculate the inner product
of eq. (1k) and the partial derivatives of
CO% L9p)jL
with respect tof andO.
If. we, in the result,
replace9by4w., since the doublet
lies on the helical surface, we obtain
bc.,r,
(o
having the diménsion of a pressure pole times a length.
From eq. (6) we have for the velocity potential
I 2..
'j
J
(-af)t
Lt P--OQ
where the integration variableX has been replaced by X Ci
andis the new integration variable.
To obtain the velocity potential of the doublet layer we have
to integrate over the screwbiade, the range of integration being
r).x(Í)and r;fr0
where)andL(3,)determine the leading and. trailing edges,
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r andr0 the inner and. outer radii of the blade.
Keeping in mind, that the integration over the projection of the propeller blade in the plane, in stead of over the actual propeller blade, gives rise to the factor
øI
d
we get
I, I
The veloc±ty components can bed.erived from the velocity potential by differentiation with respect tox,r andL. We are not
interested in the radial component of the disturbance velocity, so we give only the expressions for the axial and. tangential components
I, 2
and.
3
and. form the expression for j.i-t./
Eq. (24) is valid. for one screwbiade. A n-bladed. screw we can represent by a set of helical surfaces 2.1C,k.e,),2.
We find the expression
forXu-/ for an arbitrary
screwbiade by replacing in eq.(2k)(fbyt2.1
The contribution of all the blades together is obviously a summation over the number ofblades,('), since we deal with a linearized theory
I, 5
The boundary condition, eq. (12) states that in the immediate neighbourhood of the propeller the velocities ind.aced by the propeller must cancel the distuibance induced by the ship's hull. However, to obtain the propeller induced. velocities in
a point lying at one of the helical surfaces, we meet with difficulties in the form of singularities in the integrand of expression (2), due to the fact, that the distance
R.=(f(.-
..ar1cosL9..4)3
between (u,r,iq) and. at least one of the points of the doubletlayer becomes zero. To overcome this difficulty we take the point (x,P,t) a small quantity,E, outside the helical
surface, thus lying at the surface?=o.c.f, and carry out the
limiting proces in such a way, that the integral does not loose its sense. This yields the integral equation
(26) II,.
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4. The singular behavior of the integral equation.
In order to investigate the correct we first take into account the fact that is periodic with a period
T,
so tbat'OT=.into a Fourier series
o,
IvnA3b
(27)
,(.ç'1)=.
/"rr('f)
1Inserting this in (26) we get
limit of equation (26), the doublet strength 2X. We therefore expand.
S3 : the remaining part
Wemay exclude fron our considerations the region S3,because
the integral remains finite everywhere within this region. An analogous reasoning shows that we only need take into account a small part from the interval(-o,-)for integration oven ,
namely that part, which includes the pointCo, say we take
where
g,Pe
o<.. The choice for seems unnecessarily complicated, but it originates from a transformation, which we will apply further on. That part of the integral on the righthand side 6f eq.(28)
which thenneeds further examination is
(28)
II, 2We now focus our attention to the term for k.0 at the right hand side of (28), which gives rise to a singularity in the
neighbourhood of t.o( 2t.)and-4r. To establish the behavior of this singularity, we divide the integration region into three parts
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(30) i
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PROEFSTATION WAGENINGEN NO. 68-036-AH
(29). II, 3
Investigation of eq. (29) shows that not all ternis in the integrand of the triple integral contribute to its singular behavior. In view of the integration interval of the inner
integral we can evaluate for sinailt the integrand. in a powerseries tot , keeping in mind. thatis small too. Only
those terms in the expansion will yield a non-zero contribution
to eq. (29) for?_oandE_o, which become infinite for
where.-I. This means that we can exclude from further considerations terms inthe integrand of order
withÇ-!. This is obvious for the terms containing positive powers of since these terms tend to zero forr-*o. It is also trivial for the case C, since these terms are
indépendent 0t and remain finite fort-O, while in the
limiting case j-0the integration interval of the outer
integral tends to zero. It needs a closer examination to show that it is even truè for the case p.-I. Integration of the terms in the integrand, containingt overt, under the assumption
tbatjr, yields an expression, from which we can, by
elementary calculations, extract a term lnI_rl . Only this part in the expression may cause trouble forJ But
since
11m.
We can also confirm the last part of the statement, that only
terms containingtwith4-%in the integrand of the inner
integral eventually give rise to the singular behavior of expression (29).
The substitution
=t_6
in the inner integral of eq. (29) leaves us an integral with a symmetric integration intervaland an integrand that contains odd. and even terms. So we can effectuate a further reduction of terms in the integrand,
since integration of an odd function over a symmetric interval yields zero result.
The remaining part, eq. (30), consists of integrals of the type
4-OC
oLTT
(p,)c)
It can be shown that the integral (31) is convergent
under
the conditionslo )c#i
2°.Ag and
F>0
.50
andThe terms in (30) which satisfy these conditiOns do not contribute to the result of the triple integral, eq. (29), in the case what can be shown by an analogous reasoning as above. We integrate the remaining terms in eq. (30) overg
and evaluate the results for small-r_1andE, which leads to
II, 5
Expanding,Mß,jin
a Taylor series in the neighbourhoodofpr. and substitutingr_f), we meet integrals of the type
j' _c1ts
(p,>o)
Again we can show that for
l
2°
and
>0
the integral (33) equals zero whenÇ-+o. The remaining part
of (32)
can
be integrated, resulting in(311-) III, i
We thus can replace (29) by
z 2.' 4 i
yr (c.o -
r
(35) Um
L. L
,P:k
;vn4
NEDERLANDSCH SCHEEPSBOUWKUNDIG BI.Z.
a similar way we
canshow.that the divergent part
0±'is given by
Lin_
-1-ev i-.r.'I,,
-(f,r)"°
which is a
mere extension of the upper integrationlimit
(35),.We now define .
(38).
as the Hadamard
principal
value of the, integral on the righth,and.side of (28). . , "
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5. Separating regular and singular parts.
In order to make the integral equation
(39)
III, '4.accessible to numerical calculations, we have to extract the singular part from the kernel, to treat this part
separately. We have already seen that the singular behavior of the .kernelKLz,r,,j))iS restricted to the term fork.Q. Noreover the term
(ko)
3 $
(orC Oi.1)(oft
-r3fr)
O.t),
jrrA.t
dC
{ri-AyÂ_3
t3'I
remains bounded forT0and=r. To show
this we only need consider the integral over the interval(O(,4-O), because ifthe integrand becomes infinite, it will occur within that
part of the interval, which containstC. Evaluation of the
integran.d in a powerseries totyields
('4i) 11 (r..y(ti. ¡rnO c:'c2':4 Lrr)2'(
O (te')
dtJJ_
J
Taking the limit forj'Dr before performing the integration, we can see easily, that the integral is bounded. The same holds when integrating first and taking-the limitr.r
afterwards. However, the latter sequence reveals the fact, that the integral is discontinuous, when integrating over
the pointtO forrP. . This is caused by the first term in the integrand
____ ______
______
r
(4.2)_cz-rr
r
(i +
J
-T
-
L _JThe magnitude of the discontinuity is
('4.3)
Having shown that eq. (40) contaiñs no singularity, we can pay full attèntion to the term
ri
(114) e.
dt
i)
[t-2+f-.
cctJ
Here again we need only to consider the
integrand in
theneighbourhood 0fto Evaluation in a powerseries totleads
to O
rr
tir)_4
).
J
L ii- L.j'
)t3 .Li cr)i- t
-The part
certainly is singular. To subtract this singularity.underthe integration sigñ ofthe kernel we extend the integration
interval of eq. (46) to(-o-), which is allowed, since
the integral exists for the lower limit-co.
The remaining terms in eq.
(45)
can be written slightly different(11.7)
IV,i
(4-8)
IV,. 2
Ít
can
be shown, simply by integration, that the termsL -
i.
-(r'
r
cit- -. . ,---
.
110.
t2dt
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are finite for1
r.
However, the integrals appear to be discontinuous, when
integrated over the pointtzOforf.r. The magnitude ofthe
discontinuity canbe calculated to be
I
t2.\2
.tu_Sor+I+O1r)rn
(I+or)i2.
The singular part of (47) and (48) is now reduced to
J
-
1.Extension of the integration interval can not simply be done, since the integral in eq. (53) does not converge for the lower
limit-. To remedy this we multiply the integrand
by
a factor that does .not change the character of the singularity forCo
, but effectuates the convergence of the integral forthe lower limit-oo.A factor, that satisfies all this is
z
/
\
P3 .
LT-j'J
,
wherer>r0
, so thatr7
t+2rp
fall possible values oft-
arlar .
The lastdemand
is just for mathematical reasons: it defines the integral.So we can write for (53)
I..
Y)rP135
(t)&p4.
We are now able to subtract the singular part of the kernel,
kL-)nosf)
, under the integral sign, leaving a regular kernel,cxr4).
Integrating the eq. (4k) and(54)
analyticallyover Twe obtain for the singular part of the kernel,ks.(.r.r),
Obviously the term
NEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
(58)
-
+(i+2p.)rn3p
rj
(r)
{r
is non-singular, so we add. (58) to
Kn.&rif)
Finally we can write for the integra], equationV'I
V,2
V,3
The singular part 01' the integral equation needs. some more investigation. In the next section we will try to express the singularities in a more explicit way.
NEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
(62)
6. Separating chordwise andspanwise singularities.
To simplify the calculations we introdue a set of
newvariables
lLr)
X
eL)
y
r..ç'Furthermore we suppose that,
can bé expanded in a Biriibamn
series
(63)
'i')c,
c()41jx'
where(C)are
linear cörubinations 6f Tschebyscheff polynomials
of the first kind. with the argumenti_.X.
(6L)
This enables, us to separate the variables
and
Ç'.Wé consider the first term in eq. (61)
Lrr)
L)
'ce.)
and substitute (62) and. (63) into (65)
v,z.
The integrand has a logarithmic singularity in the
second
derivative toYroroana>c'x, asis already stated by
Nuithopp
[8]. It seems advisable to treat the logarithmic
singularitr
NEDERLANDSCH SCHEEPSROUWKUNDIG. BLZ.
separately, so we will investigae therecise nature of ït.
Tó do so we evaluate h (X')and
°' x-x).
a powerseries to
(X._)C) .- However the
oordinate)C-X
is not a convenient variable to use for this expansion. In the first.placeZrnayexceed unity forY# o, which means that the point under consideration does not ly at the screwblade any longer.
NoreoverXdepends ony
We therefore prefer the variableX(y=o')=xsee
eq. (62)), sinceX,is independent 0frwhile the relationO.XI
d.oeshold.g
Thus evaluating j ande. in the neighbourhood
of)c.and substituting the results into (66), we get
VI, i
The part
. VI,.2
in (67) yields, when integrated, a term of order In view of the spanwise integration it is advisable to isolate this
logarithmic singularity, thus obtaining
VI,3
Returning to our original coordinates we can also write.
2.. i..Q
Q
L.
C
tr ..f
rp5
pwhere
(72) . . VI,.5
The áccent in
{('Y4 states differentiation with respect
(71) VI,
and
ÑEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
to the argument
IL
The next term to be. considered is
-
-(73)
(I+c.rf)a.J
1--
(?)-
j
'JThis integral gives rise to a logarithmic singularity
for alivalues
We can isolate this singularity in the following way, keeping
in' mind (63)
(7Li.) ' ' VII, i
The second integral can be calculated to be
'
VÏI, 2
Isolating the logarithmic singularity
'
vii, 3;
we can write (77) where (78') (80)9
Cr,.) ¶r',rp)i-E_
pDOvp
Pt:,o;n10--
'Lr)
p(f)
(1r)
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and
(79)
VII,To make
VIII,
a regular term, we subtractVIII, thus obtaining
'p
(8k) £
Crnp(f)
where and.This terni contains for.x-Oa1so a logarithmic singularity
£nJrrL
namely
(81)
VIII, 2
(2)
L.
to
The integrai equation finally takes the
forni
IX, 2
where. t'x1r.? is given by
(71) and
Lw..,v',r) by
VIP J OIP 4
tx,t-,rÇ
h
) IP Cj
P , .L-)
J Furthermore is(9)
Î
-'r"
R L, R s NEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.Lt)
fp&u1
&'Crf)
and respectively given by ('72), (78) and. (85)o FinallyIX,3
. (.zryi) and rp ,,,Í)respective1y given by
(79), (86) an(60). As long asJ+re.(9O)is equivalent
ithIx,
where
x,1
;which follows from eq. (77) and (84.). Eq. (91) is froni a
numerical viewpoint, easiér to handle, In the casef- however,
we have to use eq. (90) in which we sübstitute bfor. . For
n,p-) and Lz,r,rwe get
J
X,2
x, 3
and.(95) XI,
In the next section we shall occupy ourselves with the spanwise
integ-ration.
NEDERLANDSCH SCHEEPSBOUWKUNDIG .BLZ.
7. Spanwise integration.
To perform the spanwise integration we make use of the Nuithopp-procedure. We treat the three essentially d±fferént parts of (87) separately.'
cJ(îTh f0
ay
r0
j
F (y)
Jr...yi oL1çro
'Py)QLy
whereFi(Li+otrtL. CrnÇ)2
q::) 2O Jr2.cT)LL
CLy)
L-?srj')
We introduce a new coordinate
r0+fl _-r
cosGJ
2.which makes the integration liinitsoandt.. As a consequence
ø'=.Jr
0ie
-J ..p.. ro1.-_Pb.r;,s
z t.+r,..-r;r0-P
sLet)
16 .*-
!!ì ÇOOS.(r+ ¿)
- co b
Neglecting terms of order this last expression yields. for ¿
9
)
NÈDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
1ff 1 F,(e).e
- ' L 1 J
J
J (cot Br C e,.. O(loo)
r0-r1
fe
e de
(ioi)10fl5
FC9c
(99)Substitüting this in (96),. (97) and (98)we get
We start our calculations with expression (99.). We püt
(102)
gL)
being an interpolation function, determined by thecondition that
.r
Lgg.i,,...
where denotes the integration stations. The derivation
of1G
,..is given in appendix A. We give here the result only(103)
q
ce
L£Ir.X.9Irl)%
Inserting (102)
and (103)
in(99) we obtain(104)
. XI, 2Pcr4r is
, so that the integrals In (104) exist. inthe sense oP' Cauchy. Using Clauert's formula
r
bI3II
dNEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
1G I Ç G>%G
de =
G-cos
o we obtainn.
Ç
.sir A G ( .A e .sir 9 d O
ij
e,..- e? e
At
r
P1+1forL.r we have in a similar way
er-ec
hI
stA$r.[f
+5
d.9.=a'
)h.pf L...
coz OosB J
3tr%O1=
Furthermore
is .f.
-i'
e) Aen
i
'____
= -
-
£I9r
.t51v &r
U,_This r suit inserted in (1011.) cancels the term
.FiLe
so that (10k) leads to the simple expression
XI, 3
where
2rL
- .L
X
r
h*-
)=i
slriÖ,.
This sum is calculated in appendix B and yields
o
eri-e
der)_cr(er
rfP_r.(er'1OL4E)
2i.LGr)
2.NEDERLAN DSCH SCHEEPSBOUWICUNDÍG BLZ.
NO.
68-036-AH
NEDERLANOSCH SCHEEPSSOUWKUNDIG PROEFSTATION WAGENINGEN(107) ,
(I)
(108)
'r
L.').2iL.;r
e t
flf)
a
-e ersr
e
Q Jowe exclude th.e integrel
forÀ.i
. to treat this one in a differentYo For )we find
sn ), B
sn
OOcos.Od9
-OS9rOOSJ
fTt
T(10_I.i c;i(ìt)ocn 0
dO
=Ic.os e-.cc
I,L ?
T ECoS IÀ.#t)e._ coS. )OZT tcoA
9_cos(A_t)
el
cOS_CoS e
o(Lr
odd)
dO=
BLZ. 2 ?Tt r
j'(+a)s.
sin A. eT iin1
sP-L)
L °«- £-%
j
(ion)
pr,
_r
evén)
We apply the saine procedure to (100). Substituting
!°=Ê
0e).0)
in (loo) give.s
XI,
In calcuiaing ..the integrals
_
r.
r'i-/i-.I
BLZ. NEDÉRLANDSCH SCHEEPSBOUWKUNDIG
PROEFSTATION WAGENNGEN NO.
cos(A.#i
I
t)L+t
For
we find
-I
Ç.zre2licosOr
othe second term of which can be calculated as before, yielding
The first term goes as follows
2.
CeS (1_i) B!L
J.ncose.._cosOJdBj1n IISIfl8PL46
e.
c9=.
kjT0
.cL-..
)co2_cDOc& -
1-f: coeç.
ç, 11JcB+iJ
e.-e
ide
o-e
Pi+f
1n(snD)d9#J
1ns;nD)d9=
h
= 2.
1r
14-2 J2
L(.in e) d94fi
2.ln(SIn B)d e+j
ìnlsne1cìG
2L(s.n
d9+zLt1n(sine)a9#Ij
Finally we öbtain
(112)
-_rìj
£
where
(113) XI, 5
This sum can not be simplified anymore.
The integrals
eJerc
r+
o
in (iii) are all zero except for
. t2) oLi)
(il 4) = A'
_-r*I
The integral (loi) leads with
F3te'L
XII, I
Combining the thus found quadrature formulae for the three terms in eq. (87) we get for the integral equation
(117) XII, 2
The chordwise integration is the only thing left to take care off. This will be d.one in the next section.
NEDERLANDSCH SC-HEEPSBOUWKUÑDIG BLZ.
NEDERLANDSCH SCHEEPSBOUWKUN DIG
PROÉFSTATION WAGENINGEN
BLZ.
32
8. Chordwise integration
It is sometimes more convenient to handle problems, when they are formulated in dimensionless coordinatesánd parameters. So before going on integrating eq. (117) over the chord of the screwbiade, we return for a moment to eq. (28), in order to make the integral equation dimensionless. This can be done by dividing the geometric coordinates by some reference léngth,
say,-0: thus = , etc. Furthermore we replace by
tot
u
the so called reduced frequency, based on the screw radius. Also
- 4. U0
and .
= ) 1.00.
-rn O
u
Keeping in mind thatz1r etc. stand for.,r etc. we can just as weil omit this suffix,getting for the dimens.ionless integral equation
XIII, I
As a consequence we can write eq. (117) as adimensioniess equation XIII, 2 where XII], 3 XIII, LI. and XIV, 1
where we takeri. Furthermore is
_______
and dimensionless, because this is true for}.J(1f) .We now continue our line of attack, whici i the chordwise
integration of the integrals
iptf)
and'It is possible tO do this partly by. means of analytica methods, but for reasons o.f generality we prefer a pure nume±icai integration method designed by'Roinberg-Stiêfel [ii], which has the advantag.e that the integral can be calculated within an' accuracy, prescribed beforehand. Of course we have to write the integrands of the several integrals in such a way that the numerical method can be applied to them. This will be done. here.
a) First we consider the function
t(-rf)
The functionk
-R.fonta ins' fora square root singularity.
(12.3)
h t'x')T
tI_2..)C)4-.tp-i L1.é)
',tV'7( (i-x).where
(124)
X'-
-L1
.('x
*Lr))
The functions1L,_d2DÒare Tschebyschef f polynomials of the f irst kind of orderX with argument ¿i-ZX'). To eliminate this square root singularty we can introduce a new variable
X' -k
L_cop)
from which follows
XLIOS?
NEDERLANÖSCH SCHEEPSBOUWKUN DIG BLZ.
Substitution of (125) in (120) leads to a regular expreèsion
XIV, 2
with
=
(f
4.f- COS ('+i)
P
The derivative of with respect to its argument, which we need also in our further calculations, is given by
2- '
p
lt
-.scr)L?c.LI.cos9o)
For5pthe integrand shows a discontinuity
2. for
ìk-+ -rk -
Lj
(-FO'o
for
ZL)
Furthermore is (r..f £riIrjio.so we replace eq. (127)
forp-
by,bcr)
=
2J' {copIf'#c.os
1p
J'
In the.foregoing forinulaelis a function ofb) Next we consider
The expressions (128), (129)
and
(130) being known, the function ) r-p can be calculatedJ
XIV, 3
NEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
c) Finally we cOnsider the function
We havetwo distinct cases, viz.y.*.-and3r. The exPression,
foro.r,r is quite d.ifferent fron the one for.
for
s +
-J We start with the casej'r. Ilaking use of the expressions
(124),
(125) and: (126) we getXV. i
given by. (128),
(130)'
(131).The calculation of the eq. (122), which
ocòurs within the integrand äf sp Lxrj) , will be taken care off in the next section. At this point we
assumeQxi-being known as a numeriòai quantity. The calculation 91' eq.(133)
is now straight forward.This is not the case whenÎ_. We now have to integrate
the formulae
XV, 2
where
LL,r,,fis
now given by XVI, IApplying (124), (125) and (126) to (134), the last equation is transformed to
XVI, 2
the square root singularity being eliminated. is given, by
(131), withp' substituted for
The integrand in the expression for L'çiis discontinuous
at
LXXO
ç
.i.0)
, the limiting valtes beingNEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
nC)
L
The
functionL'X,rr)contains
a logarithmic singularity at.x..To remOve this singularity we proceed as follows. The integrals can be written (in the original coordinates) as
xvii,
in which the first integral is non-singular. Rewriting the second and third integral in the following way,
XVII, 2
we can calculate the second and fourth integral to be
-
L)oLa.[_.Er
LfLr9
(1ko)
E f-L-
kLP:)xJ
while the integrands of the first and third integrals tend to zero Thus we -get (again in the new coordinates)
(iki) XVII, 3
For the choice of the pivotal points over the chord we follow Muithopp's suggestion [8] (1/42)
.;X
-).jt')1
22+?
J;m.Er-A.
QJ*sr
LJ .Çbr.ip4T:
.1. I NEDERLANDSCH SCHEEPSBOUWKÚNDIG BLZ.NEDERLANDSCH SCHEEPSBOUWKUNDIG
PROEFSTATION WAGENINGEN NO.
68-036-AH
BLZ.
Integration orQL1i-j).
The integraiQ&x1r) gives rise to two difficulties0
First it is an improper integral, so that.it needs some manipula-tions to make this integra], accessible for numerical computamanipula-tions.
SecoÌidlcx,4,Y is the inner óne of adoubie integral..Since
the alcor compiler of the TR4-computer does not allow for. recursive calls and moreover it is not necessary the best ].ine of' attack to compute the double integral by aid of simple
double integration, we have to find another way out. It is easy to verify, that the integrand
which in the following will be denoted tends to
zero fort-co, which allows us to cut off the range of
integration below some fixed but arbitrarily choosen value
and.to approximate the integra].for_4t._-C2_ by analytical
means.
(1k3) Lr,ÍioLt
])Q
rp
Lr,1i) o
The first integral on the right-hand side consists of' two essentially different parts
(144)
Q1rirtct
Lr')+tatt
where (145)flLt)=L[
ko
*
iLo+.zic)
andsfr,Lr42.4 ct -r
tt+Ay'2- 2.v3)co(at 1.zT)
NEDERLANDSCH SCHEEPSBOUWKUNDIG
PROEFSTATION WAGENINGEN
(111.6)
The part B(t) is added to the part A(t) to keep the latter
finite fort=O .
But
sincé the range of integration (_oo,_C) does not containt=o we can treat both parts separately. B(t) can easily be integrated overt.-£2. (i 11.7) (1k8) For Imaginary part
1+ jrpD.t
r
l4-Pf)k
1r.
!Î
LIi.,-j
NO. 68-036-AH 2.f-.ot.
r'2
Ci)(c.i)rt.
t
¡i.r.j'
Idt
irr).J
fr+ (r")2.
_ocL
r
VøC ..L ? ILr'T
/+cr')
ft
+-
Li+&2ry J
(lk7a)
0c
i +o.J Ltti){c2..
(ii-.st)
í--L
j
the part A(t) we find an asymptotic expansion. The
2.
Lr)Z
I101 BLZ. 38(--
3L)
L 1-' 2.'r
.tLL1-c--i-'-j"
i-.1 2. 4. i+c integrand can be evaluated in a powerseries to tof negative powers.Separating real and. imaginary parts we obtain for the real part
rL1
(1k9)
p-coLcc+
1-ItI
Jrt
z
y
Ç,cctry
Lrf)3cos
rj'cs cttiic1
L
16ß2. z)
+__
3tn(tt-r
riJ
Ir ¡ t3
NEDERLANDSCH SCHEEPSBOUWKUNDIG
PROEFSTATION WAGENINGEN NO. 68-036-MI
BLZ.
39
IL[-J ko
00). 2
- CoS
Lot
i. + o (r i ir Lait 2.11'ÇIt')3
Jt1:#cLr+y
i
..].rrn
t+2Tldt
By partial integration we
can
throw back the firsttwo
terms of the integrand at the third one. This leads to the following expressions.Real part for
w-I
oes rn(c-
k)c'
!
cc Lrn)
(i5i){
î lLrrtH) Lrni-i)J -'--
'Ico.Lrn
i) 'c
k 9.Lrvl_I) I '1Forrni
andrn the formula is slightly different. For ypE.
J
(152)
.
[-&vyos (oM..
2.1c)+. L-
+
iS. tq For -{a.ry3ir2..(os2.
(153)
rfl.Lj,
etc.Lin
rn(O.Q..4.J.._
.&n Lmt
cxJ
J_Imfc2J.
4 2LrVH-1)4. W 2L'n..4)a,. 2. 2.
-
-r )
we
f Jt
k
w-(c_
213ffc,La
2.Tc:.L1
W2AL
N J(154)
For
(155)
I c.o(o.S2.-
____
viLcJ.
ic2(rv,_I).
i
wf
Lr?Zfr 1rnt7.c-
-zit3+[_j
)
f2
2.(.fl)-')t arn4-i)"o!
sCvr*)
J
L NLrni
. IjJ-
-Ñi
Z1
_.ìt)_J_
o(o.cL_.Z1t)i
k0
L '.p- f4_k
JCr2f)3J... [éT .sir
f c....)_ -L N(.L
2a)sn
Tc\Zj...
eci. L Lg q"J...Q1
ILFor
P7).9.rL
(ÖL .Q-
2._L cas
.Q.. - $_ N(,.
N JIko
(156)
k
_sf.._c)J..P 7sìr(r' ZI&(.L +.L4LpM
2c.
P4citz
t4k
w
%Z.k
)
Nj2i1
s..;The remainder terms are given by
wI
k
I
L.
Ç.c*.r'
a--o---
Ico1rrs+s) £5L__
21C11rr W ZLrrltI)Cu.
t4
J
NEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
NEDERLANDSCI4 SCHEEPSBOUWXUNDIG
PWEFSTATION WAGENINGEN NO.
68-O6-AH
-n
-cocor
.{+('*)} +f)21 Co5 (2at4.2x)
1t21
(i»r)
Co4(2t) '!(
)'j')
CoS(3+
t3
+...
-t;.
t 2) t a) W4t5
b.k
i
i.f4)2
+(,,'+ . CoS f(tm_i)&r.. .ti4t5
.:tp
M4)O_2EJ
t;
t;
pJ4t+32)t).c0s (t..+2x)}
-t;
t,
ïß+
pJso(m t).
Iw+lI)At 4 t4
(nit
-
í
t5
Sm (Piii-I)Ot + &xj + touI_i1 T.
t,,s;i (,r.i')x4nI + Sin [(ni.t
-...]
a
ti5
+ BLZ. ¿Il +-1
+ 41: +Sin (tar+..x)
t2A. ¡41 ¡1'4tp{sin(3ut42x)_sin (o.t+
t5
-'tp1
(tax)Sn(3ct
.i.1j)
t5.
1i(a+pt)
sin(r__p
(4t#!*
t)
¿-rNEDERLANOSCH SCHEEPSROUWKUNDtG PROEFSTATION WAGENINGEN
BLZ.
It can be shown that these remainder terms are of
orderÇ'(-'-Consider the expression
po0
J
..r r)
OJt r
rrAt
-.r
rrt
The last term on.the righthand side isof
orderO), as can
be easily seen fromt'
Zfrt
t
O6)
The first term needs a closer examination
s;f1 )
r'
r I wa ç(k2,)
Thus
t
.ts
(kt
SinT ct *
-p
wt
d-cStn t
ct
_)t
t5
2,tt Li-
(mo)ÇLr
ssit
dt +
)
ki
+Qf..L
I. ,2 ks) 1-ir
(eìtt
Matt +
)k Çdt.
Jr+ kx)
(fr.z
-(k.'
TI(kir
NO.68-036-AH
42 -w a1c I
Ar5
according to
Thus the concluion is that (14.4) can be computed sufficiently
accurate fortoo ,
without consuming too much running time. To overcome the second difficulty, integration of a double integral, we tabulate the inner integral and, when calculating the outer integral, find the wanted value of the inner integral by interpolation within the tabel. To tabulate the secondintegral on the righthand side of (14-3) to the argunient, the integration variable of the outer integral, we notice that
only occurs in the upper limit of the integral, so that tabulation means calculation of the integral for different values of the
upper limit. Instead of tabulating towe take the full upper
iimit,x4
as argument, which means a slight gain in computation time., since we do not have to tabulate the integral for each value of the parameterX. again.From eq. (131) and the integration limits of eq. (133) it
follows thatvarieswithin the intervai(Ly)xj))
of lengththe chordlength of the scewblade; the same holds fork, eq. (124.) and (126). This means that the value ofvaries
within the interval(_Ç1+». To prevent unnecessary computations
we need only tabulate the variable part of the integral for different values ; for the parts that is independent of...
one computation suffices
(-1 58)
ot.I..)JQ (ry
dt
The integrandJQv)in the first integral at the righthand side
NEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
behaves for a wide range oftquasi-periodic, i.e. with a fixed periodand a descending ainpi-itude. As long as the arguments of the trigonometric functions are not too great the best way to deal with an integral like this is to interateJO.(..fì) over each period separately, to keep terms of the saine order of magnitude together
(159)
J
JQ Ccit
J'i
L frj.t) dt
The second term at the
righthand
side of (158) needs tabulation to the argument%4. We divide the integration interval, in a number of parts, enought to garantee sufficient accuracy during interpolationand
compute the integral over every interval, including those from (1114)and. (159),
we find a table ofaequidistant points for the integral in (143) for different values
of the argunient. To make inteipolation at the endpoints of the
tabulation
interval_Qi.y)
i-eLj')) as accurate as possible, we compute one value ofQL,,p,y'ion each side outside the interval(_&f),.Qy)) The choice of-Q.is determined by the choice of eq and by the mutual distance of the tabulated points '.(160y.!L.
The calculation of the integrand
of(4leads
for -o
andP-to very inaccurate results if we maintain the form of the
integrand as given in eq. (111-5) and (111.6). This is caused by the
fact that the terms in eq. (111.5) and (111-6), if separately treated,
tend. to infinity fort-+0. In a computer subtraction of two almost equal, but very big numbers given rise to a considerable loss of
accuracy. To overcome this difficulty we evaluate (145) forko and small values oft
(t.tr,
wheret r is determined, after some experimental calculations)in a powerseries tot . This gives usthe possibility to remove the. ''infinite'' terms by analytical means. We have to continue
NEDERLANDSCH SCHEEPSBOUWKUNDIG BLZ.
NEDERLANDSCH SCHEEP$BOUWKUNDIG
PROEFSTATION WAGENINGEN NO. 68-036-AH
BLZ.
the expansion to rather high powers oft, to get
forTt9ra
reasonable accuracy. For we compute the integral in thc usual way. LI II2O .-'Z.r
2. '3,/j
d7c.t
n+i4*(i1.o:2)rr)
i_______
j.0'Lp
)j+
4..
(161 a(161b
f '+....L(rn#
'_____
C Lc2-r)
J
o(e_
. IQ (i.i.c-...LI+Oar )rt1/
+ IprtA. V"L 'z,2- 2'. 3(IAtr)t2.
4.0'.
¡\
2p%'Z.(i... (D+IOtfl2P.L1+C
)rfl )_
&r-! (+
io
LjOiJJ
ìrr,4t
cit...Sjp,Oct)XTCI
[t'1i-
i-.0C14j .,x)3]31i
t.c
r
tr,Lc1.2m)27
im(or'ic)
ttt1c.csLcAt1.*
21d33J
e.+
2.2\ 2.\ I+C r'NEDERLANDSCH SCHEEPSBOUWKUNDIG
PROEFSTATION WAGENINGEN No. 68-036-AH
BLZ.
46
The part (161b) represents those terms in the integrandQ(rçt'
which do not contain ''infinit&' terms fort-O.,so this
part needs no evaluation. The function sign
(r)
equals zero. for t.O .Since expression (161a) isspecial arrangements for that. To complete the integration with some remarks concerning the
not zerO, forto, we need
ofpL'xr,
we end. this section interpolation, which isnecessary to calculate the valueof the 'in.ner.integral
each time we compute the integrand of&çr).
An interpolation formula that sufficés is the threepoint.. Lagrange interpolation formula [12]. 'Since we can take the. coordinate, for which we .av to calculate the tabulated
function arbitrarily in the left or. right interval of the i.terpo1ation formula, we calculate. the
for both cases and take the arithmetic mean as the final result. At the ends of the. interpolation interval we are sometimes in a position .that we have only one way to calculate a value of .
QLn'
since we have only One way to apply the threepoint .NEDERLANDSCH SCHEEPSBOUWKUNDIG
PROEFSTATION WAGENINGEN NO. 68-036-AH
BLZ.
10. The solution of the integral equation.
We now return to eq.
(119),
in which we can compute the and. the coefficients to solve this equation. The functionsL1012 ,r19) andWLr,LM')
on the lefthand. side of eq. (119) are, as defined before, the axial and tangential disturbance velocities, dueto the ship's hull at the place of the screwdisc. The inhornogeneou
velocity field, in which the ships propeller operates (the
wake) is from the viewpoint of a screwblade a periodic function. Obviously the way to proceed is to develop the disturbance
velocities in a Fourierseries
00
{rt#o
X7)_f,
OHere use is made of the fact that there is a relation between
X.,i- ,& ande. , the point lying at the helical surface. The integra]
equation now takes a somewhat less complex form
ni't
.i.
.a.. ¿ .L1-+.!I
(2s-
2LÇ
We have to solve the integral equation for each harmonic
in the wake separately. The unknown coefficientsC.(r? are a
measure for the pressure distribution along the screwblade (they are the coefficient of the terms in the Birnbaumseries, which describes the chordwise pressure distribution.
Substituting the known values of for
certainand'in the lefthand side of eq. (163) and calculating
the known functions in the righthand side of eq. (163) for
cor-responding values òf.andr, we arrive at a set of linear
algebraic equations. The coordinates ( ,- ) represent a nunber of points along the screwblade,h in span- and?+I in chordwise
In other words we satisfy the integral equation in the pivotal
pòinto reduce the integral &quation to a set of linear algebraic.
equations, which can be solved applying one. of the wèll-known
methods. Tie coordinates of the pivotal points are given by
(IL.2) as far as the chordwise coordinates are concerned; for
the spanwise coordinates we take the stationpoints of the spanwise
integration
. . . . .(16k)
-?
.9ewhere
h+i a
1=
...3-7We. have already seen that eq. (163) delivers for each wake
harmonic
tWÒa set of equations. Thus we have to calculate the
coefficient matrix of this syste
for éachrvi separately, the.
rank ishtL'P*')
,the number of pivotal points. To gain some
rumling time, we do not compute the matrix elements row- or
colinnnwise, but in partmatrices of rankL'), the number of
pivotal points ovei the chord.
The matrix elements are complex numbers as long asrflO.
We can easIly convert a set of complex equations into a set
of real equations. It can b.e shown by elementary means that
(165)
N
.riJl. ).jx+)
(o+;6)
is aequivalent with
(166)
tri,., M'10
f/c.
t%f1.
fir'
The raflk o.f the. real set of equations is twice the rank of th ....
complex one.
The known lefthand. side of (163) consists for eachn of the
amplitude of one of the harmonic components, which charácterize
the velocity field of the wake. Since there are no or at least
very few measurements of the. xïistiirbance velocitie.s as. a function
of )., we assume the variation in axial direction small, so tiiat.
in our computáttons, the lefthands.ide of (163) is a Thnction. of
the span
. ... . .NDERLANDSCH SÇHEEPSBOUWKUNDG BLZ.
only. The measurements of the
disturbance velocities over the span do of course not
coincide with the coordinates of the pivotal points over the span. To
calculate the.amplitudesfor
these coordinates we make use of the
already mentIoned interpolatjo
formula..
The Solution of the set of equations finally is
peíforthéd
by applying the method of Crout, a modification of the
well-. known Gauss algorithme.
NEDERLAND$cH SCHEEPSBOUWKUNDIG BLZ.
PROEFSTATION . WAGENINGEN NO.
11. Extension of the theory to.. steady state calculations.
The casemo represents the homogeneous part in the velocity
field of the wake. Since we choose the rotating helical surface in such a way, that it does not generate a lift force in a
homogeneous flow, the solution for the case
r=O
is consequently the trivial one, the zero vector.A more significant solution we obtain, when we start from
the boundary condition (ii), whereU stands for an angle of incidence and eventually the camber of' a profile. This means that we replace in casern.=othe lefthand side of eq. (163) by
the known quantityEU-4. In the following we will derive the
meaning of this quantity more precisely.
Since we apply a linearized theory, the boundary conditions are satisfied on the projection of the screwblade to the helical surface, in stead of at the screwblade itself. If' we denote the angle between the helical surface and the screwblade
by5'
, the angle of incidence,., the angle between the helical surface and. the discplane byo((see fig.3,
pag 51) and the pitch angle bye',we can express,5in terms of pitch,I-') and reduced frequency,..
(16?)
aò_or
where
(168)
A simple calculation yields
-The chordlengthLr), which occurs in our formulae, is measured in axial direction, so that the relation between&Àand the
chord-lenght measured along the screwblade,k2L-) , is
Li-)
k 21r) *t-os)-e
p-,r. kiL-) csJ
(Z,,2.)
NEDERLANDSCH SCI4EEPSBOUWKUNDtG BLZ.
To find the abscissae of the leading and trailing edge,.resp. we calculate the position of the generator
Lrr.ir
Lpc.L)
the rake angle being the angle between the vertical an the generator of the. screwbiade. So we get for the leading, edge the abscis
cosft
1+T.rsir
and for the trailing edge of course
(172) .
L= ,Lr)
+
Chord lengthp-o
From the camber of the screwblade we can derive the local
angle of attackjj. We need tó know this angle to calculate
the ,lefthand side of the integral equation. We state'.tha
(13)r-
J3
Li+o'r''),This formula can be derived as follows. The équation of the helical surface is
(174)
that of the. screwbiade
(175),
heIicI Si-sr'
Fig.
'r
From the fig. 3 one can see that the
angle between the helicalsurface and the
1' plane, or between screwbiade and
YZ-plane is formally given by Li
i
ci»cIP'=CohS.
NEDERLANDSCH SCHEEPSBOUWKUÑDIG BLZ.
Applying this to eq.
(174)
and(175)
wecancaiculate)in
every point of the screwblade. by elementairy meansThe value ofJfoIlows from. the camber of the .screwblade profile
(sée fig..
3,
page51)
.. ...
= cambereffect
(q.e.d.).
Fig. 4
st
(176)
If'
we denote the plane in which the
chord of the screwbiade is lying,
by,
than is the angle between this
planeand the helical suiface
determined as), the angle
of attack
The local angle of attack,), is
expressed in terms used in Fig. 4,
defined by .
In a practical case the camber of a screwbiade is often said to be a parabola. the shape of which is characterized hyits height at the midchord.. The equation of the parabOla is. the
-
1°
.The derivative of this equation to the arguments' is
L_?o
OLsf
____
2 . Pç. L. Loc+furthermore
35 IOC?+Oc
Loci 5' L Ç)cr-r+EP_.
SoIn our linearized theory this expression simplifies to
NEDERLANDSCH SCHEEPSBOUWKUHDG BLZ.
(179)
X.
Eìcpressingthe coordinates in fractions of the chordlengthL=5-3 and. at the same time translatin the. coordinate system in such a way,that. the leading edge of the profile maps at the poInt
(o,o) we arrive at . .
-
(x-v)
whereT
and % Z!L.L s
L
For the X-coordinate we can take the same numerical values as are calculatéd. for the chordwise coordinates of the pivotal points., eq. (142)b Substituting eq. (169) and
(177)
in eq.(176),
we get . .XI+cr)
Consequently the lefthand. side of the integral equation finally
takes the form. . .
NEDERLANDSCH SCHEEPSBOLJWKUNDIG BLZ.
12. Formulae for some hydrodynamic quantities.
Apart from the pressure coefficients from the Birnbaumseries
C
J the values of which follow directly from thé solution rnpYjof the set of linear equations, we can compute sorne hydrodynamic. quantities as lift force (tbrust),moment and. application point. The lift force per section is
Ç.
. .C,Lr?,bC)QLX
The moment per section, as usual related to the. one quarter
chordpoint,is .
I
.Yflr)=ft
1.
C
."
.X1f&.%J
Applying eq. (125) and (128) we get after some. calculations
Lir)11'') C0
1r)mL}
CLr
The lift force as calculated in (180) is perpendicular to the flow (IA,o,o). The contribution of the lift force to the thrust (force in axial direction) is therefore
,LLrL
£L-).C,0L,-)
c.rILr)C,.,0Lr)
For the moment,fl)Lr), a simulár transformation holds
.Lr)OrZ
ic1()
'1
To find the total thrust of the screwpropeller, we sum the
contribution of each blade, which results only then in a non-zero force, when the number of blades corresponds with the wake
NÉDERLANDSCH. SCHEEPSBOUWKUNDIG BLZ.
NEDERLANDSCH SCHEEPSBOUWKUNDIG
PROEFSÏATION WAGENINGEN NO 68-036-AH..
.01-z.
55
harmonic
mXPJ
, )o12,...and integrate (1.82) over the span.Ñ .
(18k)
k10
.The point of application of the mean lift force per blade section is found from the fact that the moment related to this point will be zero.
C0JL1xll%_%:OOLfr)3::O.
For the abscis of the point of application follows
(185).
C,,Dfr)
To find the total torque we need the cOmponent Of the
lift force, which lies iri. the discplane. This is given in eq. (180) Multiplying this sectional liftforce by the radius.we get
after an anaiogous,.reso
fling
as before .4Q'
r4gr c
Lr otr
k0o
From eq. (181) and (186) we deduce the simple. relation
TL,
To calculate the bending inoinent,m, we note, that we get only a contribution, when the number of blades corresponds with the wake harmonic plus or minus one. .The components of the bending moment about the vertical and horizontal axis are
(1 88a) IT
1
'i
rr±
ti1c)
Çot
NEDÈRLANDSCH SCHEEPSBOUWKUN DIG
PROEFSTATION WAGENINGEN NO.68-036-AH
BLZT1
56.13. Resultl.
.
Numerical computations are made for a hypothetical case, the results of: whiöh, from a mathemat±cal point of view., were very satisfactory.
.
The screwpropelier isa two-bladed one, with elliptically shaped. blades. The hubrad.ius,v is .2.of the screwradius,r ,. .
which is 3.000 mm. In the developed. position the small BJCiS of '
the ellips (the greatest chord.length) is .2 of. the screwradius . too.The parameter of the helical surface,a-is calculated from the homogeneous flow velocity,1t, the angular velocity,c..O and the screwradius, respectively 7.5398 m/sec, 12.5662 rad/sec., and 3000mm. The rakeangle is taken to be zero.
The wake we composed 'of, apart from the homogeneous flow velocity,, the second harmonic of the Fourierseries only. 'The amplitude of this harmonic is choosen to depend linearly on
the radiùs-, being twenty percent of the undisturbed flow velocity at the tip and zéro at the root of the screwbiade.
To find an average lift in the undisturbed flow we take
the angle of attack,1to be 3 degrees, independent of ihe radius. The camber of the blade we takezero, i.e. the flät plate shape.
The resulting curves for the lift force per section as. function of the radius show for an increasing number óf pivotal points over the radius a good convergence and a reasonable
smoothness 'for more then'one pivotal point over the chord, (see fig. 5., age 57),
In. this diagram we plotted, the modulus
of the liftforce per blade section as a function of the radius i.n casein=oandm=2.
. ., .The, three dimensional effects tend to shift the point of. application slightly to the front, which is in agreement. with th& results of Truckenbrodt [iL], The running time per wake harmonic for a twobladed screwpropeller is about -O min. for 12 pivotal. points, all arranged along the span. For 2 resp. 3 pivotal points in chordwise direction (and 12 over the span) the running time
o .20 .10 o 0.2 .30
=0
.20 L ½Pu2t(r)t.
L Y2PU2L(r) m=2 O 0.2 QL 0.6 118 r LO ro PAGE .5?NETHERLANDS SHIP MODEL BASIN
WAGENINGEN
NO 68-036AH
08
- 1.0NEDERLANDSCH SCHEEPSBOUWKUNDIG
PROEFSTATION WAGENINGEN NO. 68-036-AH
ØLZ.
58
References.
Timman, R. and Vooren, A.I. van der:''Flutter of a hiicopter rotor rotating in its wake''. J.. Aero. Sci,
1957.
Ritger, P.D. and Breslin, J.P.: ''A theöry for the quasi-steady and unsteady thrust and torque of a propeller
in a ship wake''. S. I. T., D. L. Report 686, 1958..
Karman, von.Th. and Sears, W.R.:''Airfoi]. theory for non-uniform motion''o J.Aero. Sci., 1938.
Shirori, J. and Tsakonas, S.:''Three-dimeflSioflal approach to the
gust problem fora screw propeller''. S.I.-T., D,L
Report 940, 1963.
Hanaoka, T.: ''Thtroduction to the non-uniform hydrodynamics c6ncerning a screwpropeller''. J.Zos.Japan No.
109 and: ' 'On the integral equation concerning an
oscillating screw propeller by lifting line theory''. J.Zos.Japan No. 110, 1962.
Tsakonas, S. an.dJacobs, W.R.:''Unsteady lifting surface theory for a marine propeller of low pitch angle with chordwise loading distribution''..S.I.T., D.L. Report 944, 1964 and: ''Unsteady propeller liftin surface theory with finite number of chordwise modes.'' S.I.T., D.L. Report 1133, 1966.
Lasbka, B.: ''zur Theorie der harmonisch schwingenden tragende. FThche bei Unterschallanstrmung''. Dissertation T.H. Hünchen, 1962.
Nuithopp, H.: ''!'letbôds for calculating the lift distribution of
- wings (subsonic lifting surface theory). ARC, R.
Sparenberg, J.A.: ' 'Application of lifting surface theory. tó
ship screws''. Proc. K.N.A.W., Ser. B., 1959..
Sparenberg, J.A.
'Note on the ship screw in an inhomogeneous
field of.fiow'.' N.S.N.B. Nemoranduin, 1962.
Stiefel, E:''Einführung in die Numerische Nathematik''.
Teubner Verlag, Stuttgart 1961.
Kopal, Z.: ''Numerical Analysis'' Chapman & Hall, London,. 1955.
Triconi, F.G.: ' 'Vorlesungen iiber Orthogonaireihen'' Springer,
Berlin, 1955.
1. Truckenbrodt, E.:''Tragflchentheorie bei Irilcompressibler
Strömung'' Jahrbuch der Wissenschaftlichen
Gesellschaft fir Luftfahrt, 1953.
NEDERLANDSCH SCHEEPSBOUWKUNDIG BI-z.
Appendix A.
Derivation of the function 9)
71e try to Lind a polynomial which satisfies the. orthogonality relation on the interval ( o,'t'. ?'e know that the trigonometric functions A. 9 form a orthogonal and complete system on (oit) for X an integer
(A1
fit SIh
1. 8 s'n9 ae
= o (). dp.integerso
Putting %= cs 9 we have
S\n
where()
is a polynomial of degreeA-
.. The integral (A1)becomes (A2)
L'
2' TA-t ('u)sn2)LB
d=
Normalizing expressIon lt tdx.=o
we know thatA recurrence relation for (Ç 'x) is asily derived0
Analogous with
Sfl (.+!)
4 Sn
8 z s X 9 9 we have ) A- = A BLZ. NEDERLANOSCH SCHEEPSBOUWXUNDIG fPROEFSTATION 68-036-All 60NEDERLANDSCH SCHEEPSBOUWKUNDÎGi
PROEFSTATION WAGEÑINGEN
68-036-AH
BIZ.
61
so
[rc)
a=
o
where
is the Kronecker's symbol
Thus, putting
(A3)
.sn A.
DPA-i (%)
we have
()
M-I (ex) d L=
From (A3) follows immediately
(A14.) P
(i=J 2:' sn.A. &
Sr G
BO
that for instance
for
X.='
cP%
À= 3
Obviously the coefficient of
x
in
(is
2?'Applying the summation formula of Christoffel-Darboux [13], and usi
u-3-i-..-we
et
the same notation as Tricorni
nJ'
p
For 'xi and.
we take the zero's cf "i
(ejj
which are 1he
same as the zero's of sn (n+
0j
thus
GX1T
so that
n-'
'V=oPo normalize expression (A7) we calculate (Tricoini)
n-t