145 (1994)
Remarks on P κ λ -combinatorics
by
Shizuo K a m o (Osaka)
Abstract. We prove that { x ∈ P
κλ | x ∩ κ is almost x-ineffable} has p
∗(NIn
κ,λ<κ)- measure 1 and { x ∈ P
κλ | x ∩ κ is x-ineffable} has I-measure 1, where I is the complete ineffable ideal on P
κλ. As corollaries, we show that λ-ineffability does not imply complete λ-ineffability and that almost λ-ineffability does not imply λ-ineffability.
In [6], Jech introduced the notion of λ-ineffability and almost λ-inef- fability which are the P κ λ generalizations of ineffability. Next, Johnson [8]
introduced the notion of complete λ-ineffability. These properties can be characterized by certain ideals on P κ λ (see [3]). By the definitions, it fol- lows directly that λ-supercompact cardinals are completely λ-ineffable and that λ-ineffable cardinals are almost λ-ineffable. Johnson [8] showed that completely λ-ineffable cardinals are λ-ineffable.
Whether the converse implications also hold seems to be interesting.
Concerning this, Abe [1] proved that almost λ-ineffability and λ-ineffability are equivalent if λ > κ is an ineffable cardinal. It is not difficult to check that complete λ-ineffability does not imply λ-supercompactness. In this paper, we shall prove the following two theorems.
Theorem 4.1. If κ is λ <κ -ineffable, then {x ∈ P κ λ | x ∩ κ is almost x-ineffable} ∈ p ∗ (NIn κ,λ<κ) ∗ , where p denotes the projection from P κ λ <κ to P κ λ.
Theorem 4.2. Let I be a normal, (λ <κ , 2)-distributive ideal on P κ λ.
Then {x ∈ P κ λ | x ∩ κ is x-ineffable} ∈ I ∗ .
By using these theorems, we shall show that λ-ineffability does not im- ply complete λ-ineffability and that almost λ-ineffability does not imply λ-ineffability.
In the proofs of Theorems 4.1 and 4.2, we shall use the notion of strong normality (which was introduced by Carr [4]) and a certain correspondence
1991 Mathematics Subject Classification: Primary 03E55.
[141]
between P κ λ and P κ λ <κ . The strong normality and this correspondence will be dealt with in Sections 2 and 3, respectively. The two theorems will be proved in Section 4.
The author got the idea of the correspondence between P κ λ and P κ λ <κ from discussions with Prof. Y. Abe at Kanagawa University and would like to thank him.
1. Notation and terminology. Throughout this paper, κ denotes a regular uncountable cardinal, and λ a cardinal ≥ κ. Let J be an ideal on a set S. Then J ∗ denotes the dual filter of J and J + the set P(S) \ J . For any X ⊂ S, J + ¹X denotes J + ∩ P(X). For any f : S → T , f ∗ (J ) denotes the ideal {Y ⊂ T | f −1 Y ∈ J } on T .
Let A be a set such that κ ≤ |A|. Then P κ A is the set {x ⊂ A | |x| < κ}.
For each x ∈ P κ A, b x denotes the set {y ∈ P κ A | x ⊂ y & x 6= y}. I κ,A denotes the ideal {X ⊂ P κ A | X ∩ b y = ∅ for some y ∈ P κ A}. An element of I + κ,A is called unbounded. A subset of P κ A is called club if it is unbounded and closed under unions of increasing chains with length < κ. A subset X of P κ A is called stationary if X ∩C 6= ∅ for any club subset C of P κ A. NS κ,A denotes the ideal {X ⊂ P κ A | X is non-stationary}. A function f from X (⊂ P κ A) to A is called regressive if f (x) ∈ x for all x ∈ X \ {∅}. For any indexed family {X a | a ∈ A} of subsets of P κ A, the diagonal union 5 a∈A X a and the diagonal intersection 4 a∈A X a are the sets {x ∈ P κ A | x ∈ X a for some a ∈ x} and {x ∈ P κ A | x ∈ X a for all a ∈ x}, respectively. A κ-complete ideal on P κ A is said to be normal if it contains I κ,A and is closed under diagonal unions.
A subset X ⊂ P κ A is said to be A-ineffable, almost A-ineffable, and A-Shelah, respectively, if
∀f x : x →2 (for x ∈ X) ∃f : A →2 ({x ∈ X | f x ⊂ f } ∈ NS + κ,A ),
∀f x : x →2 (for x ∈ X) ∃f : A →2 ({x ∈ X | f x ⊂ f } ∈ I + κ,A ),
∀f x : x →x (for x ∈ X) ∃f : A →A ∀x ∈ P κ A ∃y ∈ X ∩ b x (f y ¹x = f ¹x).
Following Carr [2], [3], define
NIn κ,A = {X ⊂ P κ A | X is not A-ineffable},
NAIn κ,A = {X ⊂ P κ A | X is not almost A-ineffable}, NSh κ,A = {X ⊂ P κ A | X is not A-Shelah}.
Carr [2], [3] showed that these are normal ideals on P κ A and that NSh κ,A ⊂ NAIn κ,A . A cardinal κ is said to be A-ineffable (almost A-ineffable, A- Shelah) if NIn κ,A (NAIn κ,A , NSh κ,A ) is proper.
Let I be an ideal on P κ A and % a cardinal. Then I is said to be (%, 2)-
distributive if for any X ∈ I + and any family {{X α,0 , X α,1 } | α < %} of
disjoint partitions of X, there exist X 0 ∈ I + ¹X and f : % → 2 such that X 0 \ X α,f (α) ∈ I for all α < %. Note that this definition is equivalent to the usual definition of (%, 2)- (or (%, %)-)distributivity given in [8]. Following Johnson [8], we say that κ is completely A-ineffable if there exists a proper, normal, (|A|, 2)-distributive ideal on P κ A. By using the following theorem [8, Theorem 5.1], she proved that completely A-ineffable cardinals are A- ineffable.
Theorem 1.1. For any ideal I on P κ A containing I κ,A , the following statements are equivalent.
(a) I is normal and (|A|, 2)-distributive.
(b) ∀X ∈ I + ∀f x : x → 2 (for x ∈ X) ∃f : A → A ({x ∈ X | f x ⊂ f }
∈ I + ).
2. Strong normality. From now on, I denotes a proper, κ-complete ideal on P κ λ containing I κ,λ . In this section, we shall consider the strong normality of ideals on P κ λ which was introduced by Carr [4]. For x, y ∈ P κ λ, x ≺ y means that x ⊂ y and |x| < |κ ∩ y|. Following Carr [4], I is called strongly normal if
∀X ∈ I + ∀a x ≺ x (for x ∈ X) ∃a ∈ P κ λ ({x ∈ X | a x = a} ∈ I + ).
It is clear that strongly normal ideals are normal. Carr [4, Theorems 3.4, 3.5]
showed that, under the assumption that λ <κ = λ, the ideals NIn κ,λ , NAIn κ,λ and NSh κ,λ are strongly normal.
For x ∈ P κ λ, Q x denotes the set P κ∩x x (= {t ⊂ x | t ≺ x}). For any indexed family {X t | t ∈ P κ λ} of subsets of P κ λ, 4 t∈Pκλ X t denotes the set {x ∈ P κ λ | x ∈ X t for all t ≺ x}, and 5 t∈P
κλ X t the set {x ∈ P κ λ | x ∈ X t
for some t ≺ x}. We call 4 t∈Pκλ X t and 5 t∈P
κλ X t the strong diagonal intersection and union, respectively, of {X t | t ∈ P κ λ}. The following lemma is known [5] and can be easily verified.
Lemma 2.1 The following statements are equivalent.
(a) I is strongly normal.
(b) I is closed under strong diagonal unions.
Lemma 2.2. If I is normal and (λ, 2)-distributive, then I is strongly normal.
P r o o f. Let X ∈ I + and a x ≺ x for x ∈ X. For each x ∈ X, take β x ∈ x ∩ κ such that |a x | ≤ |x ∩ β x |. Since I is normal, we may assume that β x = β for all x ∈ X. For each α < λ, set
Y α,0 = {x ∈ X | α ∈ a x }, Y α,1 = {x ∈ X | α 6∈ a x },
W α = {Y α,0 , Y α,1 } ∩ I + .
Since W α is an I-partition of X for every α < λ, there exist g : λ → 2 and Z ∈ I + such that
Z ⊂ X and Z \ Y α,g(α) ∈ I for all α < λ.
Set Y = 4 α<λ Y α,g(α) . Since I is normal, Z \ Y ∈ I. So, Y ∈ I + . Set A = g −1 {0}. Then it is easy to see that a y = A ∩ y for all y ∈ Y and
|A| ≤ |β|. So, A ∈ P κ λ. Set Y 1 = Y ∩ b A. Then Y 1 ∈ I + and a y = A for all y ∈ Y 1 .
Define
S(I) = { 5
t∈P
κλ X t ∪ Y | ∀t ∈ P κ λ (X t ∈ I) & Y ∈ I}.
Lemma 2.3. Suppose that κ is an inaccessible cardinal. Then S(I) is the smallest strongly normal ideal containing I.
P r o o f. Since it is clear that S(I) is an ideal, we only verify that S(I) is strongly normal. So, let Y t ∈ S(I) (for t ∈ P κ λ). For each t ∈ P κ λ, take X t,s ∈ I (for s ∈ P κ λ) and A t ∈ I such that Y t ⊂ 5 s∈Pκλ X t,s ∪ A t . For each a ∈ P κ λ, let B a = S
s,t⊂a X t,s ∪ A a . Since κ is inaccessible, B a ∈ I for all a ∈ P κ λ. It is easy to check that
5
t∈P
κλ Y t ⊂ 5
a∈P
κλ B a ∪ (P κ λ \ b ω) ∈ S(I).
Corollary 2.4. Suppose that κ is an inaccessible cardinal. Then S(NS κ,λ ) = S(I κ,λ ).
For each τ : P κ λ → P κ λ, cl(τ ) denotes the set {x ∈ P κ λ | x 6= ∅ &
∀t ≺ x (τ (t) ⊂ x)}.
Lemma 2.5. Suppose that κ is an inaccessible cardinal. Let X ⊂ P κ λ.
Then the following statements are equivalent.
(a) X ∈ S(NS κ,λ ).
(b) There exists τ : P κ λ → P κ λ such that cl(τ ) ∩ X = ∅.
P r o o f. (a)⇒(b). Let X ∈ S(NS κ,λ ). By the previous corollary, we can take x a ∈ P κ λ (for a ∈ P κ λ) and b ∈ P κ λ such that
X ⊂ 5
a∈P
κλ (P κ λ \ b x a ) ∪ (P κ λ \ bb).
Let τ = hx a ∪ b ∪ ω | a ∈ P κ λi. Then cl(τ ) ∩ X = ∅.
(b)⇒(a). Suppose τ : P κ λ → P κ λ satisfies cl(τ ) ∩ X = ∅. For each a ∈ P κ λ, set Y a = P κ λ \ τ (a) ∧ . Let Y = 5 a∈Pκλ Y a . Then X ⊂ Y and Y ∈ S(I κ,λ ).
The following lemma is not needed later. However, it seems to be interest-
ing, because if κ is an inaccessible cardinal, then the set X = {x ∈ P κ λ | x∩κ
is an ordinal and cof(x∩κ) = ω} satisfies {x ∈ X | X∩Q x ∈ I κ∩x,x } ∈ NS + κ,λ .
Lemma 2.6. Suppose that κ is an inaccessible cardinal. Then {x ∈ X | X ∩ Q x ∈ I κ∩x,x } ∈ S(NS κ,λ ) for any X ⊂ P κ λ.
P r o o f. To get a contradiction, assume that there exists X ⊂ P κ λ such that
Y = {x ∈ X | X ∩ Q x ∈ I κ∩x,x } ∈ S(NS κ,λ ) + .
For each x ∈ Y , take a x ∈ Q x such that b a x ∩ X ∩ Q x = ∅. Since Y ∈ S(NS κ,λ ) + , there exists a ∈ P κ λ such that
Z = {x ∈ Y | a x = a} ∈ S(NS κ,λ ) + .
Take x, y ∈ Z such that x ≺ y. Then x ∈ X ∩ b a y ∩ Q y . A contradiction.
3. A correspondence between P κ λ and P κ λ <κ . From now on, we assume that κ is an inaccessible cardinal. Let θ = λ <κ and p : P κ θ → P κ λ denote the projection (i.e., p(y) = y ∩ λ).
Take a bijection h : θ → P κ λ. Define π = π(h) : P κ λ → P κ θ and q = q(h) : P κ θ → P κ λ by
π(x) = h −1 Q x for each x ∈ P κ λ, q(y) = [
h 00 y for each y ∈ P κ θ.
Set
C h = {y ∈ P κ θ | ∀α ∈ y (h(α) ≺ q(y)) & q(y) = p(y)}, The following lemma can be easily verified.
Lemma 3.1. (1) qπ(x) = x for any x ∈ b 2 (⊂ P κ λ).
(2) C h is a club of P κ θ (so, p 00 C h = q 00 C h is a club subset of P κ λ).
(3) y ⊂ πq(y) for any y ∈ C h .
(4) Y ∈ I κ,θ iff π −1 Y ∈ I κ,λ for any Y ⊂ rang(π).
Lemma 3.2. There exist x ∈ P κ λ and y ∈ P κ θ such that πq¹(rang(π)∩ b y) is the identity function and b x ⊂ q 00 (rang(π) ∩ b y).
P r o o f. Take α < θ such that h(α) = 2. Then it is easy to see that πq¹(rang(π) ∩ {α} ∧ ) is the identity function and b ω ⊂ q 00 (rang(π) ∩ {α} ∧ ).
Corollary 3.3. Let J be an ideal on P κ θ. If rang(π) ∈ J ∗ and I κ,θ ⊂ J , then π ∗ q ∗ (J ) = J .
Lemma 3.4. The following statements are equivalent.
(a) I is strongly normal.
(b) π ∗ (I) is normal.
P r o o f. (a)⇒(b). Assume that I is strongly normal. Let Y α ∈ π ∗ (I) for
α < θ. Set Y = 5 α<θ Y α . For each a ∈ P κ λ, set X a = π −1 Y h−1(a) ∈ I. Set
X = 5 a∈Pκλ X a . Then π −1 Y ⊂ X. Since X a ∈ I for all a ∈ P κ λ, it follows that X ∈ I. So, Y ∈ π ∗ (I).
(b)⇒(a). Assume that π ∗ (I) is normal. Let X a ∈ I for a ∈ P κ λ. Set X = 5 a∈Pκλ X a . For each α < θ, set Y α = π 00 X h(α) . Set Y = 5 α<θ Y α . Since π −1 Y α = X h(α) ∈ I for all α < θ, it follows that Y ∈ π ∗ (I). Since X ⊂ π −1 Y , we conclude that X ∈ I.
Corollary 3.5. If I is strongly normal, then NS κ,θ ⊂ π ∗ (I). In par- ticular , NS κ,θ ⊂ π ∗ (S(NS κ,λ )).
Lemma 3.6. Y ∈ NS κ,θ iff π −1 Y ∈ S(NS κ,λ ) for any Y ⊂ rang(π).
P r o o f. The implication ⇒ follows immediately from the above corollary.
To show the converse, let Y ⊂ rang(π) and X = π −1 Y ∈ S(NS κ,λ ). By Lemma 2.5, there exists τ : P κ λ → P κ λ such that cl(τ ) ∩ X = ∅. Define C ⊂ P κ θ by
C = {y ∈ C h | τ (h(α) ∩ λ) ⊂ p(y) for all α ∈ y}.
Then C is a club subset of P κ θ and C ∩ Y = ∅. So, Y ∈ NS κ,θ . Lemma 3.7. rang(π) ∈ NSh ∗ κ,θ .
P r o o f. To get a contradiction, assume that Y 0 = P κ θ\rang(π) ∈ NSh + κ,θ . Since C h is a club, Y = Y 0 ∩ C h ∈ NSh + κ,θ . Since, for all y ∈ Y , we have y ⊂ π(y ∩ λ) and y 6= π(y ∩ λ), we can take a y (for y ∈ Y ) such that
a y ≺ y ∩ λ and h −1 (a y ) 6∈ y for any y ∈ Y.
Since κ is θ-Shelah and cof(θ) ≥ κ, by the result of Johnson [8, Cor. 2.7], θ <κ = θ. So, NSh κ,θ is strongly normal. Hence, there is a ∈ P κ λ such that
Y 0 = {y ∈ Y | a y = a} ∈ NSh + κ,θ .
Then h −1 (a) 6∈ y for all y ∈ Y 0 . But this contradicts the fact that Y 0 is unbounded in P κ θ.
Theorem 3.8. Let Y ⊂ P κ θ and X = q −1 Y . Then:
(1) Y ∈ NIn + κ,θ iff
∀f x : Q x → 2 ( for x ∈ X) ∃f : P κ λ → 2 ({x ∈ X | f x ⊂ f } ∈ S(NS κ,λ ) + ).
(2) Y ∈ NAIn + κ,θ iff
∀f x : Q x → 2 (for x ∈ X) ∃f : P κ λ → 2 ({x ∈ X | f x ⊂ f } ∈ I + κ,λ ).
(3) Y ∈ NSh + κ,θ iff
∀f x : Q x → Q x (for x ∈ X) ∃f : P κ λ → P κ λ such that
∀x ∈ P κ λ ∃x 0 ∈ X ∩ b x (f x0¹Q x = f ¹Q x ).
P r o o f. By Lemmas 3.2 and 3.7, we may assume that Y ⊂ rang(π) and πq¹Y is the identity function.
(1⇒) Let f x : Q x → 2 for x ∈ X. Define g y : y → 2 (for y ∈ Y ) by g y (α) = f q(y) (h(α)) for any α ∈ y. Since Y ∈ NIn + κ,θ , there exists g : θ → 2 such that Y 0 = {y ∈ Y | g y ⊂ g} ∈ NS + κ,θ . Set X 0 = q 00 Y 0 . By Lemma 3.6, X 0 ∈ S(NS κ,λ ) + . Define f : P κ λ → 2 by f (t) = g(h −1 (t)) for all t ∈ P κ λ.
Then it is easy to see that f x ⊂ f for all x ∈ X 0 . So, {x ∈ X | f x ⊂ f } ∈ S(NS κ,λ ) + .
(1⇐) Let g y : y → 2 for y ∈ Y . Define f x : Q x → 2 (for x ∈ X) by f x (a) = g π(x) (h −1 (a)) for any a ∈ Q x . By the hypothesis, there exists f : P κ λ → 2 such that X 0 = {x ∈ X | f x ⊂ f } ∈ S(NS κ,λ ) + . Set Y 0 = π 00 X 0 . By Lemma 3.6, Y 0 ∈ NS + κ,θ . Define g : θ → 2 by g(α) = f (h(α)) for all α < θ.
Then it is easy to see that g y ⊂ g for all y ∈ Y 0 . So, {y ∈ Y | g y ⊂ g} ∈ NS + κ,θ . (2), (3) Similar to (1).
Theorem 3.9. The following statements are equivalent.
(a) κ is completely θ-ineffable.
(b) There exists a proper , normal ideal I on P κ λ which satisfies the (θ, 2)-distributive law.
P r o o f. (a)⇒(b). Assume that (a) holds. Take a proper normal ideal J on P κ θ such that J satisfies the (θ, 2)-distributive law. Set I = q ∗ (J ). Since rang(π) ∈ J ∗ , I is the desired ideal in (b).
(b)⇒(a). Let I be an ideal on P κ λ which satisfies (b). Set J = π ∗ (I).
Since I is strongly normal, J is the desired ideal in (a).
4. Theorems. As in the previous section, θ denotes λ <κ and p : P κ θ → P κ λ the projection. In this section, we prove the following theorems.
Theorem 4.1. {x ∈ P κ λ | x ∩ κ is almost x-ineffable} ∈ p ∗ (NIn κ,θ ) ∗ . Theorem 4.2. Let I be a normal, (θ, 2)-distributive ideal on P κ λ. Then {x ∈ P κ λ | x ∩ κ is x-ineffable} ∈ I ∗ .
For Theorem 4.2, in the case of original ineffability, Johnson [7, Cor. 4]
proved a stronger result.
Theorem 4.1 has the following corollary.
Corollary 4.3. Let κ be the least cardinal α such that α is almost α + -ineffable. Then κ is not κ + -ineffable.
P r o o f. To get a contradiction, assume that κ is κ + -ineffable. By a result of Johnson [8], (κ + ) <κ = κ + . So, p ∗ (NIn κ,κ+) is proper. Since {x ∈ P κ κ + |
|x| = (x ∩ κ) + } ∈ p ∗ (NIn κ,κ+) ∗ , by Theorem 4.1, there exists x ∈ P κ κ + such
that x ∩ κ is almost x-ineffable and |x| = (x ∩ κ) + . Since x ∩ κ < κ, this
contradicts the choice of κ.
By using a similar argument, the next corollary follows from Theo- rem 4.2.
Corollary 4.4. Let κ be the least cardinal α such that α is α + -ineffable.
Then κ is not completely κ + -ineffable.
First we prove Theorem 4.1. Before starting the proof, we show the following lemma.
Let h : θ → P κ λ be a bijection, π = π(h), and q = q(h).
Lemma 4.5. Let X ∈ q ∗ (NIn κ,θ ) + and, for each t ∈ P κ λ, W t be a family of disjoint subsets of X such that |W t | < κ and X \ S
W t ∈ I κ,λ . Then there exists σ ∈ Q
t∈P
κλ W t such that 4
t∈P
κλ
σ(t) ∈ S(NS κ,λ ) + . P r o o f. Take an enumeration hA s | s ∈ P κ λi of S
t∈P
κλ W t . For each x ∈ X, define f x : Q x → 2 by
f x (s) =
0 if x ∈ A s , 1 if x 6∈ A s . By Theorem 3.8(3), there exists f : P κ λ → 2 such that
Z = {x ∈ X | f x ⊂ f } ∈ S(NS κ,λ ) + .
Claim 1. ∀t ∈ P κ λ ∀A ∈ W t (Z \ A ∈ NS + κ,λ ⇒ Z ∩ A ∈ NS κ,λ ).
P r o o f. Let t ∈ P κ λ and A ∈ W t and Z \ A ∈ NS + κ,λ . Take s ∈ P κ λ such that A = A s . Take x ∈ P κ λ such that s ∈ Q x . Then, since Z \ A ∈ NS + κ,λ , we have (Z \ A) ∩ b x 6= ∅. So, f (s) = 0. Hence, Z ∩ A ∩ b x = ∅.
Claim 2. ∀t ∈ P κ λ ∃! A ∈ W t (Z \ A ∈ NS κ,λ ).
P r o o f. Let t ∈ P κ λ. The uniqueness follow from the assumption that W t is disjoint. The existence follows from Claim 1 and the fact that Z ∩ S
W t ∈ S(NS κ,λ ) + .
By Claim 2, take σ ∈ Q
t∈P
κλ W t such that Z \ σ(t) ∈ NS κ,λ for any t ∈ P κ λ. Then σ is as required.
P r o o f o f T h e o r e m 4.1. To get a contradiction, assume that X = {x ∈ P κ λ | x ∩ κ is not almost x-ineffable} ∈ p ∗ (NIn κ,θ ) + . Without loss of generality, we may assume that qπ¹X is the identity function on X and p¹π 00 X = q¹π 00 X. For each x ∈ X, take f t x : t → 2 (for t ∈ Q x ) such that
∀f : x → 2 ({t ∈ Q x | f t x ⊂ f } ∈ I κ∩x,x ).
For each t ∈ P κ λ, define A t (e) (for e ∈ t 2) by A t (e) = {x ∈ X | t ∈ Q x
& f t x = e}, and set W t = {A t (e) | e ∈ t 2}. By Lemma 4.5, there exists σ ∈ Q
t∈P
κλ W t such that Z = 4
t∈P
κλ
σ(t) ∈ S(NS κ,λ ) + .
For each t ∈ P κ λ, take e t ∈ t 2 such that σ(t) = A t (e t ). Then
∀x ∈ Z ∀t ∈ Q x (f t x = e t ).
Since X ∈ p ∗ (NIn κ,θ ) + ⊂ NIn + κ,λ , there exists e : λ → 2 such that X 0 = {x ∈ X | e x ⊂ e} ∈ NS + κ,λ . Take τ : P κ λ → P κ λ such that
∀t ∈ P κ λ ∃s ∈ X 0 (t ⊂ s ≺ τ (t) ∈ X 0 ).
Since Z ∈ S(NS κ,λ ) + , there is x ∈ Z such that x ∈ cl(τ ). Set f = e¹x. Then it is easy to see that {t ∈ Q x | f t x ⊂ f } ∈ I + κ∩x,x . But this contradicts the choice of {f t x | t ∈ Q x }.
Next, we shall prove Theorem 4.2. The following lemma is an analogue of a result of Johnson [8, Theorem 5.1] and can be proved by a similar argument. But for the convenience of the reader, we give a proof.
Lemma 4.6. The following statements are equivalent.
(a) I is normal and satisfies the (θ, 2)-distributive law.
(b) Whenever X ∈ I + and A x ⊂ Q x (for x ∈ X), there exists A ⊂ P κ λ such that {x ∈ X | A ∩ Q x = A x } ∈ I + .
P r o o f. (a)⇒(b). For each t ∈ P κ λ, set
X t,0 = {x ∈ X | t ∈ A x }, X t,1 = {x ∈ X | t 6∈ A x }, W t = {X t,0 , X t,1 }.
Take g : P κ λ → 2 and Z ∈ I + such that Z \X t,g(t) ∈ I for each t ∈ P κ λ. Set A = g −1 {0} and Z 1 = 4 t∈Pκλ X t,g(t) . It is easy to check that A ∩ Q x = A x for all x ∈ Z 1 . Since I is strongly normal, Z \ Z 1 ∈ I. So, Z 1 ∈ I + .
(b)⇒(a). Normality can be easily proved. So, we must only show dis- tributivity. Suppose that X ∈ I + and W t is an I-partition of X with
|W t | ≤ 2, for each t ∈ P κ λ. Without loss of generality, we may assume that W t = {X t,0 , X t,1 } is a disjoint partition of X for all t ∈ P κ λ. For each x ∈ X, define A x = {t ∈ Q x | x ∈ X t,0 }. By (b), there exists A ⊂ P κ λ such that
X 0 = {x ∈ X | A ∩ Q x = A x } ∈ I + . Define g : P κ λ → 2 by
g(t) =
0 if x ∈ A,
1 if x 6∈ A.
We claim that X 0 \ X t,g(t) ∈ I for all t ∈ P κ λ. So, let t ∈ P κ λ. Take x ∈ P κ λ such that t ∈ Q x . Then it is easy to check that (X 0 \ X t,g(t) ) ∩ b x = ∅. Hence, X 0 \ X t,g(t) ∈ I κ,λ ⊂ I.
Lemma 4.7. Suppose that I is (θ, 2)-distributive. Then {x ∈ X | X ∩ Q x ∈ NS κ∩x,x } ∈ I for any X ⊂ P κ λ.
P r o o f. To get a contradiction, suppose that there exists X ⊂ P κ λ such that
X 0 = {x ∈ X | X ∩ Q x ∈ NS κ∩x,x } ∈ I + .
For each x ∈ X 0 , take C x ⊂ Q x such that C x is club in Q x and C x ∩ X
∩ Q x = ∅. Since I satisfies the (θ, 2)-distributive law, by Lemma 4.6 there is D ⊂ P κ λ such that
X 1 = {x ∈ X 0 | C x = D ∩ Q x } ∈ I + .
Then D is club in P κ λ. So, take t, x ∈ D ∩ X 1 such that t ≺ x. Then t ∈ D ∩ Q x = C x . But this contradicts the fact that C x ∩ X ∩ Q x = ∅.
P r o o f o f T h e o r e m 4.2. To get a contradiction, assume that X = {x ∈ P κ λ | x ∩ κ is not x-ineffable} ∈ I + .
For each x ∈ X, take f t x : t → 2 (for t ∈ Q x ) such that
∀f : x → 2 ({t ∈ Q x | f t x ⊂ f } ∈ NS κ∩x,x ).
For each t ∈ P κ λ, define A t (g) ⊂ P κ λ (for g ∈ t 2) by A t (g) = {x ∈ X | t ∈ Q x & f t x = g} and set W t = {A t (g) | g ∈ t 2}∩I + . Since W t is an I-partition of X for all t ∈ P κ λ, there exist σ ∈ Q
t∈P
κλ W t and X 0 ∈ I + such that X 0 ⊂ X and X 0 \ σ(t) ∈ I for all t ∈ P κ λ.
Set X 1 = 4 t∈Pκλ σ(t). Since I is strongly normal, X 1 ∈ I + . For each t ∈ P κ λ, take g t : t → 2 such that σ(t) = A t (g t ). Since X 1 ∈ I + , there exists g : λ → 2 such that
X 2 = {x ∈ X 1 | g x ⊂ g} ∈ I + . By Lemma 4.7,
X 3 = {x ∈ X 2 | X 2 ∩ Q x ∈ NS + κ∩x,x } ∈ I + .
Take x ∈ X 3 . Then it is easy to check that X 2 ∩ Q x ⊂ {t ∈ Q x | f t x ⊂ g¹x}.
So, {t ∈ Q x | f t x ⊂ g¹x} ∈ NS + κ∩x,x . But this contradicts the choice of {f t x | t ∈ Q x }.
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DEPARTMENT OF MATHEMATICS UNIVERSITY OF OSAKA PREFECTURE GAKUEN-CHOU, SAKAI, JAPAN
E-mail: KAMO@CENTER.OSAKAFU-U.AC.JP