ACTA ARITHMETICA LXIX.2 (1995)
A χ -analogue of a formula of Ramanujan for ζ(1/2)
by
Shigeki Egami (Toyama)
To the memory of Professor Norikata Nakagoshi
In his famous Notebooks ([4]) Ramanujan stated the following formula for ζ(1/2): For τ > 0,
X ∞
n=1
1
e τ n
2−1 = 1 6τ + 1
2 r π
τ ζ
1 2
+ 1
4
+ 1 2
r π τ
X ∞
n=1
√ 1 n
sinh(2π p
πn/τ ) − sin(2π p πn/τ ) cosh(2π p
πn/τ ) − cos(2π p
πn/τ ) − 1
.
Berndt and Evans ([2], see also [1]) gave a proof of this formula by using the Poisson summation formula. The purpose of this paper is to show a similar formula for the value L(1/2, χ) of Dirichlet L-functions. Our proof based on the Mellin transform is substantially different from [2].
The motivation for this work came from a discussion with Masanori Katsurada. The author would like to thank him.
Let q be a positive integer, χ a primitive Dirichlet character modu- lo q, and L(s, χ) the Dirichlet L-function for χ. Furthermore, we will use the following standard notation:
E(χ) =
1 if χ is principal, 0 otherwise, W (χ) =
√ qg(χ) −1 for χ(−1) = 1, i √
qg(χ) −1 for χ(−1) = −1, where
g(χ) = X
a mod q
χ(a)e 2πia/q . Then our result can be stated as follows:
[189]
190 S. Egami
Theorem. For τ > 0, X
k mod q
χ(k) X ∞
n=1
e −kn
2τ 1 − e −qn
2τ
= E(χ)π 2 6τ − 1
2 L(0, χ) + 1 2
r π τ L
1 2 , χ
+ 1
2 r π
τ W (χ)
× X ∞
n=1
χ(n) √ n
sinh(2π p
πn/(qτ ) − χ(−1) sin(2π p
πn/(qτ )) cosh(2π p
πn/(qτ )) − cos(2π p
πn/(qτ )) − 1
.
P r o o f. First we express the left hand side of the above equation by the inverse Mellin integral:
I(τ, χ) = X
k mod q
χ(k) X ∞
n=1
e −kn
2τ
1 − e −qn
2τ = X
k mod q
χ(k) X ∞
m=1
X ∞
n=1
e −(kn
2τ +qmn
2τ )
= X ∞
n=1
X ∞
m=1
χ(m)e −τ n
2m = 1 2πi
R
(c)
Γ (s)ζ(2s)L(s, χ)τ −s ds, where c > 1 and R
(c) denotes the integral along the line <s = c. Shifting the line of integration to <s = 1/2 − c and changing the variable s ↔ 1/2 − s we have
I(τ, χ) = 1 2πi
R
(c)
Γ
1 2 − s
ζ(1 − 2s)L
1 2 − s, χ
τ −1/2+s ds + R(τ, χ),
where R(τ, χ) denotes the sum of the residues at s = 1, 1/2, and 0,
R(τ, χ) = E(χ)π 2 6τ + 1
2 r π
τ L
1 2 , χ
− L(0, χ).
Using the functional equations for ζ(s) and L(s, χ) (see e.g. [3], p. 59 and p. 71) we have
I(τ, χ) − R(τ, χ) = W (χ) πi
R
(c)
Γ (2s)ζ(2s)L
1 2 + s, χ
×
cos
πs 2
− χ(−1) sin
πs 2
qτ (2π) 3
s ds
= W (χ) 2πi
X ∞
m,n=1
R
(2c)
Γ (s)
r qτ
(2π) 3 m 2 n
s
×
cos
πs 4
− χ(−1) sin
πs 4
ds.
A formula of Ramanujan 191
In order to calculate each integral in the above double series we note that 1
2πi
R
(c)
Γ (s)
cos(πs/4) sin(πs/4)
x −s ds = e −x/
√ 2
cos(x/ √ 2) sin(x/ √
2)
,
which can easily be obtained from the well known formula:
e −(x+iy) = 1 2πi
R
(c)
Γ (s)(x + iy) −s ds (x, c > 0).
Then we observe I(τ, χ) − R(τ, χ)
= W (χ) X ∞
n=1
χ(n) √ n
X ∞
m=1
e −2π √
πnqτ