BANACH CENTER PUBLICATIONS, VOLUME 52 INSTITUTE OF MATHEMATICS POLISH ACADEMY OF SCIENCES
WARSZAWA 2000
KLEIN-GORDON TYPE DECAY RATES FOR WAVE EQUATIONS
WITH TIME-DEPENDENT COEFFICIENTS
M I C H A E L R E I S S I G
Faculty of Mathematics and Computer Science Technical University Bergakademie Freiberg
Bernhard von Cotta Str. 2 09596 Freiberg, Germany E-mail: reissig@mathe.tu-freiberg.de
K A R E N Y A G D J I A N
Institute of Mathematics, University of Tsukuba Tsukuba, Ibaraki 305, Japan
E-mail: yagdjian@math.tsukuba.ac.jp
Abstract. This work is concerned with the proof of L
p− L
qdecay estimates for solutions of the Cauchy problem for the Klein-Gordon type equation u
tt− λ
2(t)b
2(t)(4u − m
2u) = 0 . The coefficient consists of an increasing smooth function λ and an oscillating smooth and bounded function b which are uniformly separated from zero. Moreover, m
2is a positive constant. We study under which assumptions for λ and b one can expect as an essential part of the decay rate the classical Klein-Gordon decay rate
n2(
1p−
1q) .
1. Introduction. To prove global existence results for the solutions of the Cauchy problem for nonlinear wave equations so-called L
p− L
qdecay estimates for the solutions of the linear wave equation play an essential role [7],[8],[11]. That is the following estimate for the solution u = u(t, x) of the Cauchy problem
u
tt− 4u = 0, u(0, x) = 0, u
t(0, x) = u
1(x),
where u
1= u
1(x) belongs to C
0∞(R
n) (see [16]): there exist constants C and M depending on p and n such that
ku
t(t, ·)k
Lq(Rn)+ k∇u(t, ·)k
Lq(Rn)≤ C(1 + t)
−n−12 (1p−1q)ku
1k
WMp (Rn)
, (1.1) where 1 < p ≤ 2 and 1/p + 1/q = 1.
2000 Mathematics Subject Classification: Primary 35L15, 35Q40; Secondary 35B05.
The paper is in final form and no version of it will be published elsewhere.
[189]
In a series of papers [12],[13],[14],[15] the authors considered the question if a similar estimate holds for the solution of a strictly hyperbolic Cauchy problem, where the strictly hyperbolic operator is homogeneous, of second order and has time-dependent coefficients.
To explain the results let us choose the Cauchy problem for the model equation
u
tt− λ
2(t)b
2(t) 4 u = 0, u(t
0, x) = u
0(x), u
t(t
0, x) = u
1(x), (1.2) where λ = λ(t) is an increasing function (improving influence on L
p−L
qdecay estimates) and b = b(t) is a 1-periodic, non-constant, smooth, and positive function (deteriorating influence on L
p− L
qdecay estimates). There exists an interesting action and reaction between both influences. If the growth of λ dominates the oscillating part, then we can prove inequalities similar to (1.1). In opposite to this, if the oscillating part dominates the growth, then we can only prove uniformly for all smooth data with compact support estimates which are very near to the energy inequality for the solution of (1.2) which is obtained by Gronwall’s inequality.
Example 1.1. Let us consider the Cauchy problem
u
tt− exp(2t
α)b
2(t) 4 u = 0, u(t
0, x) = u
0(x), u
t(t
0, x) = u
1(x),
where b = b(t) is a 1-periodic, non-constant, smooth and positive function. Then we have:
• in general no L
p− L
qdecay estimates if α < 1/2,
• L
p− L
qdecay estimates if α > 1/2,
• the critical case: L
p− L
qdecay estimates if α = 1/2 and the spatial dimension n is large enough.
Now let us turn to the Cauchy problem for the Klein-Gordon equation (wave equation with a non-vanishing constant mass m)
u
tt− 4u + m
2u = 0, u(0, x) = 0, u
t(0, x) = u
1(x). (1.3) The term m
2u guarantees a
12(
1p−
1q) higher decay-rate in (1.1). We can explain this improvement as follows. One can use the representation of the solution of (1.3) by the aid of Fourier multipliers including the mass in the phase functions (see [5]). After partial Fourier transformation we obtain (v = ˆ u)
v
tt+ (|ξ|
2+ m
2)v = 0, v(0, x) = 0, v
t(0, x) = ˆ u
1. For the solution v = v(t, ξ) we have the explicit representation
v = v(t, ξ) = i 2
e
−ithξimu ˆ
1(ξ) hξi
m− e
ithξimu ˆ
1(ξ) hξi
m, u = u(t, x) = i
2 F
−1e
−ithξimu ˆ
1(ξ) hξi
m− e
ithξimu ˆ
1(ξ) hξi
m, respectively, where hξi
m:= (|ξ|
2+ m
2)
1/2. For the Fourier multiplier
F
−1e
−ithξimˆ u
1(ξ) hξi
mwe get the L
p− L
qdecay estimate
ku
t(t, ·)k
Lq(Rn)+ k∇u(t, ·)k
Lq(Rn)≤ C(1 + t)
−n2(1p−1q)ku
1k
WMp (Rn)
, (1.4) where 1 < p ≤ 2, 1/p + 1/q = 1 and M is suitably chosen.
The goal of the present paper is to study L
p− L
qdecay estimates for the solutions of the Cauchy problem for Klein-Gordon type equations with time-dependent coefficients.
More precisely, we will consider the Cauchy problem
u
tt− λ
2(t)b
2(t) 4 u + λ
2(t)b
2(t)m
2u = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x) (1.5) with C
∞-data having compact support while m
2is positive and constant. On the one hand we are interested in the interplay oscillations via growth, that is, the influence of λ = λ(t) and b = b(t). Do we have a similar example to Example 1.1. On the other hand we are interested if the mass term guarantees the better decay rate
n2(
1p−
1q).
We will call an equation of Klein-Gordon type if in the decay rate of the solution to (1.5) there appears the term
n2(
1p−
1q) (see (1.4)). Thus we can formulate the main question:
Under which conditions for λ = λ(t) and b = b(t) is the differential equation from (1.5) of Klein-Gordon type?
The main results of this paper lead to the following example (compare with Exam- ple 1.1).
Example 1.2. Let us consider the Cauchy problem
u
tt− exp(2t
α)b
2(t)(4u − m
2u) = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x),
where b = b(t) is a 1-periodic, non-constant, smooth, positive function and m
2is a positive constant. Then we have:
• in general no L
p− L
qdecay estimates if α ≤ 0,
• L
p− L
qdecay estimates if α > 0 (see Example 2.2).
Before we begin to derive L
p− L
qdecay estimates for the solutions of the Cauchy problem (1.5) we formulate a result which shows that oscillations in the coefficients may destroy L
p− L
qdecay estimates. The statement of this theorem can be proved as in [12].
Theorem 1.1. Consider the Cauchy problem
u
tt− b
2(t) 4 u + m
2b
2(t)u = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x),
where b = b(t) defined on R is a 1-periodic, non-constant, smooth, and positive function.
Then for every given b(t) there is positive constant m such that there are no constants q, p, C, L, and a nonnegative function f defined on N such that for every initial data u
0, u
1∈ C
0∞(R
n) the estimate
ku
t(k, ·)k
Lq(Rn)+ k∇u(k, ·)k
Lq(Rn)≤ Cf (k)(ku
0k
WL+1p (Rn)
+ ku
1k
WL p(Rn)) is fulfilled for all k ∈ N while f (k) → ∞, ln f (k) = o(k) as k → ∞.
2. Klein-Gordon type model equations. We have in mind the functions λ =
λ(t) = exp(t
α) and b = b(t) from Example 1.1, α ∈ (0, 1]. Then b = b(t) satisfies for
large t
|D
tkb(t)| ≤ C
kλ(t)(Λ(t))
−βk, k = 1, 2, . . . , (2.1) where β ≤ 1 while Λ(t) := R
t0
λ(τ )dτ . We will consider as a model Cauchy problem of Klein-Gordon type the following one:
u
tt− λ
2(t)b
2(t)(4u − m
2u) = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x). (2.2) Then we make the assumptions
(A1): the functions b = b(t) and λ = λ(t) belong to C
∞([0, ∞));
(A2): the functions b = b(t) and λ = λ(t) are bounded from below by a positive constant;
(A3): there exist positive constants d
k, k ∈ N
0, such that for t ∈ (0, ∞) λ
0(t) ≥ 0, |D
tkλ(t)| ≤ d
kλ(t) Λ(t)
kλ(t), t > 0, (2.3) where Λ(t) := R
t0
λ(τ )dτ ;
(A4): the function b = b(t) is not necessarily periodic, there exist positive constants c
k, k ∈ N
0, and a nonnegative constant 1/2 ≤ β ≤ 1 such that for t ∈ (0, ∞)
c
0≤ b
2(t) ≤ c
1, |D
ktb(t)| ≤ c
kλ(t)(Λ(t))
−βk, k ≥ 1.
Under these assumptions we prove L
p− L
qdecay estimates for the solutions to (2.2).
Theorem 2.1. Assume that the conditions (A1) to (A4) are satisfied, in (A4) we suppose β ∈ (1/2, 1], for the Cauchy problem
u
tt− λ
2(t)b
2(t)(4u − m
2u) = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x).
Here m
2is a positive constant and u
0, u
1are compactly supported smooth data. Then we get with L = [n(
1p−
1q)] + 1, 1 < p ≤ 2,
1p+
1q= 1, the L
p− L
qestimate
ku
t(t, ·)k
Lq(Rn)+ λ(t)k∇u(t, ·)k
Lq(Rn)≤ C p
λ(t) 1 + Λ(t)
−n2(1p−1q)ku
0k
WL+1p (Rn)
+ ku
1k
WL p(Rn).
Theorem 2.2. Assume that the conditions (A1) to (A4) are satisfied, in (A4) we suppose β = 1/2, for the Cauchy problem
u
tt− λ
2(t)b
2(t)(4u − m
2u) = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x).
Then we get with L = [n(
p1−
1q)] + 1, 1 < p ≤ 2,
1p+
1q= 1, the L
p− L
qestimate ku
t(t, ·)k
Lq(Rn)+ λ(t)k∇u(t, ·)k
Lq(Rn)≤ C p
λ(t) 1 + Λ(t)
C0,0m −n2(p1−1q)ku
0k
WL+1p (Rn)
+ ku
1k
WL p(Rn).
The constant C
0,0is introduced in Corollary 5.1. It depends on the behaviour of λ and β and its first two derivatives on the interval [0, ∞).
Remark 2.1. If in Theorem 2.2 the spatial dimension n is large enough, namely n > 2C
0,0/m, then there exist p and q such that L
p− L
qdecay estimates hold for u
t/ √
λ and for √
λ∇u. In opposite to the case β = 1/2 we obtain in the case β ∈ (1/2, 1] without restrictions L
p− L
qdecay estimates for u
t/ √
λ and for √
λ∇u.
Example 2.1. Let us consider the Cauchy problem
u
tt− (1 + t)
2lb
2(t)(4u − m
2u) = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x),
where b = b(t) is a 1-periodic, non-constant, smooth, positive function and m
2is a positive constant. Then we have:
• L
p− L
qdecay estimates if l > 1,
• the critical case: L
p− L
qdecay estimates if l = 1 and the spatial dimension n is large enough.
Example 2.2. Let us consider the Cauchy problem
u
tt− exp(2t
α)b
2(t)(4u − m
2u) = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x),
where b = b(t) is a 1-periodic, non-constant, smooth, positive function and m
2is a positive constant. Then we have:
• in general no L
p− L
qdecay estimates if α ≤ 0,
• L
p− L
qdecay estimates if α > 0.
Remark 2.2. In a forthcoming paper we will study Example 2.1 for l < 1. We expect that in general there are no L
p− L
qdecay estimates for the solutions of
u
tt− (1 + t)
2lb
2(t)(4u − m
2u) = 0, u(0, x) = u
0(x), u
t(0, x) = u
1(x) (compare Examples 1.1 and 2.1).
3. Tools of the approach
3.1. Zones. We split the set [0, ∞) × (R
n\ {0}) in subdomains which will be called zones. To do this we define for ξ ∈ R
nthe function t = t
hξi(t
hξi= t(hξi
m)) by
Λ(t
hξi)
βhξi
m= N, (3.1)
where β is from assumption (A4) while N ≥ 1 is a positive constant to be determined later. We define the pseudodifferential zone
Z
pd(N ) := {(t, ξ) ∈ [0, ∞) × R
n\ {0} : 0 ≤ t ≤ t
hξi} (3.2) and the hyperbolic zone
Z
hyp(N ) := {(t, ξ) ∈ [0, ∞) × R
n\ {0} : t
hξi≤ t}. (3.3) It is evident that if N
1≤ N
2then Z
hyp(N
2) ⊂ Z
hyp(N
1) while Z
pd(N
1) ⊂ Z
pd(N
2).
Lemma 3.1. Define the function t = t(p) as a solution to Λ(t
hpi)
βhpi
m= N . Then
|D
pkt
hpi| ≤ C
khpi
−kmΛ(t
hpi)
λ(t
hpi) (3.4)
for all p ≥ 0 and k ≥ 0, where the constants C
kare independent of N . Proof. We have
dt
hpidp = − 2
β p hpi
2mΛ(t
hpi)
λ(t
hpi) .
Thus we get the estimate
dt
hpidp
≤ C
1hpi
−1mΛ(t
hpi) λ(t
hpi) .
By induction we can prove the statement for all k ≥ 0. The constants C
kare independent of N .
3.2. Classes of symbols. For the further considerations we need suitable classes of symbols which are defined only in the hyperbolic zone Z
hyp(N ).
Definition 3.1. For real numbers r
1, r
2, r
3; β ∈ (0, 1]; we denote by S
m,β{r
1, r
2, r
3} the set of all symbols a = a(t, ξ) ∈ C
∞(Z
hyp(N )) satisfying
|D
ltD
ξαa(t, ξ)| ≤ C
α,lhξi
rm1−|α|λ(t)
r2λ(t)(Λ(t))
−βr3+l(3.5) for all (t, ξ) ∈ Z
hyp(N ), all multi-indices α and all l with constants C
α,lindependent of N .
Let us summarize some simple rules of the symbolic calculus.
1. S
m,β{r
1, r
2, r
3} ⊂ S
m,β{r
1+ k, r
2+ k, r
3− k} for k ≥ 0;
2. if a(t, ξ) ∈ S
m,β{r
1, r
2, r
3} and b(t, ξ) ∈ S
m,β{k
1, k
2, k
3}, then a(t, ξ)b(t, ξ) ∈ S
m,β{r
1+ k
1, r
2+ k
2, r
3+ k
3};
3. if a(t, ξ) ∈ S
m,β{r
1, r
2, r
3}, then D
ta(t, ξ) ∈ S
m,β{r
1, r
2, r
3+ 1};
4. if a(t, ξ) ∈ S
m,β{r
1, r
2, r
3}, then D
αξa(t, ξ) ∈ S
m,β{r
1− |α|, r
2, r
3}.
4. Consideration in the pseudodifferential zone Z
pd(N ). Let us consider (2.2).
After partial Fourier transformation we get (keep the same notation for the Fourier transforms)
D
2tu − λ
2(t)b
2(t)hξi
2mu = 0, u(0, ξ) = u
0(ξ), D
tu(0, ξ) = 1 i u
1(ξ).
Setting U = (U
1, U
2)
T:= (λ(t)hξi
mu, D
tu)
Tthe last equation can be transformed to the system of first order
D
tU −
0 λ(t)hξi
mλ(t)b
2(t)hξi
m0
U − D
tλ(t) λ(t)
1 0 0 0
U = 0.
We are interested in the fundamental solution to the Cauchy problem for that system, this is the matrix-valued solution U = U (t, s, ξ) to the Cauchy problem
D
tU −
0 λ(t)hξi
mλ(t)b
2(t)hξi
m0
U − D
tλ(t) λ(t)
1 0 0 0
U = 0, (4.1)
U (s, s, ξ) = I (identity matrix). (4.2)
Using the matrizant we obtain for U (t, s, ξ) the explicit representation U (t, s, ξ) = I +
∞
X
k=1
Z
t sA(t
1, ξ) Z
t1s
A(t
2, ξ) . . . Z
tk−1s
A(t
k, ξ)dt
k. . . dt
1, where
A(t, ξ) :=
0 λ(t)hξi
mλ(t)b
2(t)hξi
m0
+ D
tλ(t) λ(t)
1 0 0 0
.
In contrast to the considerations for the wave equations with m ≡ 0 we can make use of the advantage that
t
hξi≤ t
h0i=: t
m,N(4.3)
uniformly for all ξ ∈ R
n\ {0}, where we take account of the monotonicity of Λ(t). The function λ = λ(t) is positive. This helps to estimate the norm of the second matrix by a constant maybe depending on N . The norm of the integral over the first matrix can be estimated in Z
pd(N ) by
C Z
ts
λ(τ )hξi
mdτ ≤ CΛ(t
hξi)hξi
m≤ CN (Λ(t
hξi))
1−β≤ CN (Λ(t
m,N))
1−β, where we used (4.3). Consequently, kU (t, s, ξ)k ≤ C
0(N ) for (t, ξ) ∈ Z
pd(N ).
In the same way we estimate kD
tkD
ξαU (t, s, ξ)k.
Proposition 4.1. For every k and α the following estimate holds:
kD
ktD
αξU (t, 0, ξ)k ≤ C
α,k,Nhξi
−|α|m(λ(t)hξi
m)
kfor all (t, ξ) ∈ Z
pd(N ). The constants C
α,k,Ndepend on N .
5. Consideration in the hyperbolic zone Z
hyp(N )
5.1. Diagonalization modulo S
m,β{−M, −M, M + 1}. We carry out a diagonalization process to get estimates for the solution of (4.1), (4.2).
Let us define the matrices M
−1(t) := 1
pλ(t)b(t)
1 1
−b(t) b(t)
, M (t) := 1 2
s λ(t) b(t)
b(t) −1 b(t) 1
. (5.1) Substituting U = M
−1V some calculations transform (4.1) into the first-order system
D
tV − λ(t)b(t)hξi
m−1 0
0 1
V − D
tλ(t) λ(t)
1 0 0 1
V − 1
2
D
t(λ(t)b(t)) λ(t)b(t)
0 1 1 0
V = 0.
We denote
τ
1(t, ξ) := −λ(t)b(t)hξi
m+ D
tλ(t) λ(t) , τ
2(t, ξ) := λ(t)b(t)hξi
m+ D
tλ(t)
λ(t) . With some positive number c we have
|τ
2(t, ξ) − τ
1(t, ξ)| ≥ cλ(t)hξi
m. (5.2) The matrix
−λ(t)b(t)hξi
m−1 0
0 1
belongs to S
m,β{1, 1, 0}. But the matrix D
t(λ(t)b(t))
λ(t)b(t) I
belongs even to S
m,β{0, 0, 1}. Thus we got the diagonalization mod S
m,β{0, 0, 1} in the
form
D
tV − D(t, ξ)V + B(t, ξ)V = 0, (5.3) where
D(t, ξ) := τ
1(t, ξ) 0 0 τ
2(t, ξ)
, B(t, ξ) := − 1 2
D
t(λ(t)b(t)) λ(t)b(t)
0 1 1 0
.
We will carry out further steps of perfect diagonalization, namely diagonalization modulo S
m,β{−M, −M, M + 1} for some given nonnegative integer M . The next propo- sition shows that this is possible for every nonnegative integer M .
Proposition 5.1. For a nonnegative integer M there exist matrix-valued functions N
M(t, ξ) ∈ S
m,β{0, 0, 0}, F
M(t, ξ) ∈ S
m,β{−1, −1, 2}, R
M(t, ξ) ∈ S
m,β{−M, −M, M +1}
such that the following operator-valued identity holds in Z
hyp(N ):
(D
t− D(t, ξ) + B(t, ξ))N
M(t, ξ) = N
M(t, ξ)(D
t− D(t, ξ) + F
M(t, ξ) − R
M(t, ξ)), (5.4) where the matrix F
Mis diagonal while the matrix N
M∈ S
m,β{0, 0, 0} is invertible and its inverse matrix N
M−1(t, ξ) ∈ S
m,β{0, 0, 0} too, provided that the parameter N is sufficiently large.
Proof. We look for N
M= N
M(t, ξ) and F
M= F
M(t, ξ), M ≥ 1, having the repre- sentations
N
M(t, ξ) =
M
X
r=0
N
(r)(t, ξ), F
M(t, ξ) =
M −1
X
r=0
F
(r)(t, ξ),
where N
(0):= I, B
(0):= B, F
(r):= diag (B
(r)), F
(0)(t, ξ) ≡ 0, N
(r+1):=
0 B
12(r)/(τ
1− τ
2) B
(r)21/(τ
2− τ
1) 0
,
B
(r+1):= (D
t− D + B) X
r+1µ=0
N
(µ)−
r+1X
µ=0
N
(µ)D
t− D +
r
X
µ=1
F
(µ)for r = 0, 1, . . . , M − 1. Using (5.1) we have N
(1)∈ S
m,β{−1, −1, 1} . For B
(1)we obtain the relation
B
(1)= B + [N
(1), D] + D
tN
(1)+ BN
(1).
The sum of the first two matrices vanishes, while the last two summands belong to S
m,β{−1, −1, 2} due to the rules of the symbolic calculus from Subsection 3.2. Hence B
(1)∈ S
m,β{−1, −1, 2} .
Supposing B
(r)∈ S
m,β{−r, −r, r + 1} we apply the principle of induction to show the statement for B
(r+1). On the one hand we have from the construction
N
(r+1)∈ S
m,β{−(r + 1), −(r + 1), r + 1} and F
(r)∈ S
m,β{−r, −r, r + 1}.
On the other hand, B
(r+1)= B
(r)+ [N
(r+1), D] − F
(r)+ D
tN
(r+1)+ BN
(r+1)+ N
(r+1)r
X
µ=0
F
(µ)− X
r+1µ=0
N
(µ)F
(r).
Moreover, we have B
(r)+ [N
(r+1), D] − F
(r)= 0. The sum of the other terms and consequently B
(r+1)belong to S
m,β{−(r + 1), −(r + 1), r + 2}.
Thus we have shown N
(r)∈ S
m,β{−r, −r, r}, that is with Definition 3.3.1 kN
(r)(t, ξ)k ≤ C
r1
(Λ(t))
βhξi
m r≤ C
r1 N
r, (t, ξ) ∈ Z
hyp(N ), r = 0, . . . , M.
This implies
M
X
r=1
N
(r)(t, ξ)
≤
M
X
r=1
C
r1 N
r,
where C
ris independent of N . A sufficiently large N provides kN
M− Ik ≤ 1/2 in Z
hyp(N ) and consequently the statements concerning N
Mand N
M−1. Finally let us de- fine R
M:= −N
M−1B
(M ). This matrix belongs obviously to S
m,β{−M, −M, M + 1}. The proposition is proved.
5.2. Estimates for the fundamental solution. Let us consider the system (D
t− D + F
M− R
M)W = 0. Let E
2= E
2(t, r, ξ) be the matrix-valued function
E
2(t, r, ξ) =
exp
i
Z
t r−λ(s)b(s)hξi
m+ 1 i
λ
0(s) λ(s)
d s
0
0 exp
i
Z
t rλ(s)b(s)hξi
m+ 1 i
λ
0(s) λ(s)
d s
.
Hence
E
2(t, r, ξ) = λ(t) λ(r)
exp
−i Z
tr
λ(s)b(s)hξi
md s
0
0 exp
i
Z
t rλ(s)b(s)hξi
md s
. (5.5)
Let us define the matrix-valued function
R
M(t, r, ξ) = −F
M(t, ξ) + E
2(r, t, ξ)R
M(t, ξ)E
2(t, r, ξ).
Lemma 5.1. The matrix-valued function R
M= R
M(t, r, ξ) satisfies for every l and α the estimate
k∂
tl∂
ξα(R
M(t, r, ξ) + F
M(t, ξ)) k ≤ C
M,l,α(λ(t)hξi
m)
lΛ(t)
|α|× λ(t) (Λ(t))
−βΛ
β(t)hξi
m−M(5.6) with constants C
M,l,αindependent of N .
Corollary 5.1. The matrix-valued function R
M(t, r, ξ) satisfies for every given l and α, |α| ≤ β(M − 1), in Z
hyp(N ) the estimate
k∂
tl∂
ξαR
M(t, r, ξ)k ≤ C
M,l(λ(t)hξi
m)
lhξi
−|α|mλ(t) Λ
2β(t)hξi
mwith constants C
M,lindependent of N .
Proof. Applying Proposition 5.1 and Lemma 5.1 gives
k∂
lt∂
ξαR
M(t, r, ξ)k ≤ k∂
tl∂
ξα(R
M(t, r, ξ) + F
M(t, ξ)) k + k∂
tl∂
ξαF
M(t, ξ)k
≤ C
M,l(λ(t)hξi
m)
lΛ(t)
|α|λ(t) (Λ(t))
−βΛ
β(t)hξi
m −M+ C
M,l(λ(t)hξi
m)
lhξi
−|α|mλ(t)
Λ
2β(t)hξi
m1
Λ
β(t)hξi
m l.
In Z
hyp(N ) we can estimate for |α| ≤ β(M − 1) a part of the first term of the right-hand side in the following way:
Λ(t)
|α|λ(t) (Λ(t))
−βΛ
β(t)hξi
m −M≤ hξi
−|α|mλ(t)
Λ
2β(t)hξi
m(Λ(t)hξi
m)
|α|1
Λ
β(t)hξi
m M −1≤ hξi
−|α|mλ(t) Λ
2β(t)hξi
m1
Λ
β(t)hξi
m M −1−|α|/|β|≤ hξi
−|α|mλ(t) Λ
2β(t)hξi
m.
In the last inequality we used the definition of Z
hyp(N ), especially N ≥ 1. This definition helps to estimate the second term of the right-hand side, too. The corollary is proved.
With the aid of R
Mwe define the matrix-valued function Q
M(t, t
hξi, ξ)
:=
∞
X
j=1
i
jZ
tthξi
R
M(t
1, t
hξi, ξ)dt
1Z
t1thξi
R
M(t
2, t
hξi, ξ)dt
2. . . Z
tj−1thξi
R
M(t
j, t
hξi, ξ)dt
jfor t ≥ t
hξi.
Lemma 5.2. The matrix-valued function Q
M(t, t
hξi, ξ) satisfies for all α, |α| ≤ β(M − 1), β ∈ (1/2, 1], the estimates
k∂
ξαQ
M(t, t
hξi, ξ)k ≤ C
Mhξi
−|α|m(5.7) with a constant C
Mindependent of N .
Sketch of proof. Using Corollary 5.1 for |α| = 0 and l = 0 we obtain kQ
M(t, t
hξi, ξ)k ≤ exp
Z
t thξiC
0,0λ(s) Λ
2β(s)hξi
mds
= exp
C
0,01 1 − 2β
Λ
1−2β(t) hξi
m− C
0,01 1 − 2β
Λ
1−2β(t
hξi) hξi
m≤ exp
C
0,01 2β − 1
1 Λ
2β−1(t
hξi)hξi
m≤ exp
C
0,01 2β − 1
1 m
.
This proves the statement for α = 0. Now let us form |α| derivatives, |α| ≤ β(M − 1). Then
∂
ξαQ
M(t, t
hξi, ξ)
=
∞
X
j=1
i
j∂
ξαZ
t thξiR
M(t
1, t
hξi, ξ) Z
t1thξi
R
M(t
2, t
hξi, ξ) . . . Z
tj−1thξi
R
M(t
j, t
hξi, ξ) dt
j. . . dt
1. Straightforward calculations lead to the statement for |α| ≤ β(M −1). But the main point is that Lemma 3.1 and Corollary 5.1 allow to follow the lines of the proof of Lemmas 3.2.15 and 3.2.16 from [15].
Now let us turn to the case β = 1/2. Without new difficulties one can prove the next result.
Lemma 5.3. The matrix-valued function Q
M(t, t
hξi, ξ) satisfies for all α, |α| ≤ β(M − 1), β = 1/2, the estimates
k∂
ξαQ
M(t, t
hξi, ξ)k ≤ C
M(Λ(t))
C0,0/mhξi
−|α|m(5.8) with a constant C
Mindependent of N , where C
0,0is the constant from Corollary 5.1.
The matrix-valued function W(t, t
hξi, ξ) = E
2(t, t
hξi, ξ)(I + Q
M(t, t
hξi, ξ)) solves the Cauchy problem
(D
t− D + F
M− R
M)W = 0, W(t
hξi, t
hξi, ξ) = I, t ≥ t
hξi.
Applying the transformations which bring the system for the fundamental solution to the above one, we obtain that
U (t, 0, ξ)
= M
−1(t)N
M(t, ξ)E
2(t, t
hξi, ξ)(I + Q
M(t, t
hξi, ξ))N
M(t
hξi, ξ)
−1M (t
hξi)U (t
hξi, 0, ξ) for t ≥ t
hξi.
To estimate the derivatives of U (t, 0, ξ) with respect to ξ we have to estimate all fac- tors. We get estimates for N
M(t, ξ), and N
M(t
hξi, ξ)
−1from Proposition 5.1 and Lemma 3.1. Using Lemma 3.1 and condition (A4) it follows that M (t
hξi) belongs to S
m,β{0, 0, 0}.
From Lemma 5.2 we have estimates for Q
M(t, t
hξi, ξ). Finally, derivatives of U (t
hξi, t
0, ξ) can be estimated by Proposition 4.1. Hence it remains to estimate
E
2(t, t
hξi, ξ) = E
2(t, 0, ξ)E
2(0, t
hξi, ξ).
For E
2(0, t
hξi, ξ) we have the explicit representation
E
2(0, t
hξi, ξ) = λ(0) λ(t
hξi)
exp
ihξi
mZ
thξi 0λ(s)b(s) d s
0
0 exp
−ihξi
mZ
thξi0
λ(s)b(s) d s
.
A careful calculation shows that k∂
ξαE
2(0, t
hξi, ξ)k ≤ C
αhξi
−|α|m. Summarizing we obtain the next results.
Proposition 5.2. Let us suppose that the assumptions (A1) to (A4) are satisfied with
β ∈ (1/2, 1] in (A4). Then the fundamental solution U = U (t, 0, ξ) can be represented as
follows:
U (t, 0, ξ)
= U
−(t, 0, ξ) exp
− ihξi
mZ
t0
λ(s)b(s)ds
+ U
+(t, 0, ξ) exp
ihξi
mZ
t 0λ(s)b(s)ds
, where the matrix-valued amplitudes U
−and U
+satisfy for |α| ≤ β(M − 1) the estimates
k∂
ξαU
±(t, 0, ξ)k ≤ C
Mp
λ(t)hξi
−|α|m, (t, ξ) ∈ Z
hyp(N ).
Proposition 5.3. Let us suppose that the assumptions (A1) to (A4) are satisfied with β = 1/2 in (A4). Then the fundamental solution U = U (t, 0, ξ) can be represented as follows:
U (t, 0, ξ)
= U
−(t, 0, ξ) exp
− ihξi
mZ
t 0λ(s)b(s)ds
+ U
+(t, 0, ξ) exp
ihξi
mZ
t 0λ(s)b(s)ds
, where the matrix-valued amplitudes U
−and U
+satisfy for |α| ≤ β(M − 1) the estimates
k∂
αξU
±(t, 0, ξ)k ≤ C
Mp λ(t)(Λ(t))
C0,0/mhξi
−|α|m, (t, ξ) ∈ Z
hyp(N ), where C
0,0is the constant from Corollary 5.1.
6. Solutions to the Cauchy problems. Summarizing all the calculations of the previous sections we arrive at the following results.
Theorem 6.1. Under the assumptions (A1) to (A4), we suppose β ∈ (1/2, 1] in (A4), let us consider the Cauchy problem
u
tt+ λ
2(t)b
2(t)hξi
2mu = 0, u(0, ξ) = u
0(ξ), u
t(0, ξ) = u
1(ξ).
Then the solution can be written as
u(t, ξ) = a
−0(t, 0, ξ)u
0(ξ) exp
− i Z
t0
λ(s)b(s)hξi
mds
+ a
+0(t, 0, ξ)u
0(ξ) exp
i
Z
t 0λ(s)b(s)hξi
mds
+ a
−1(t, 0, ξ)u
1(ξ) exp
− i Z
t0
λ(s)b(s)hξi
mds
+ a
+1(t, 0, ξ)u
1(ξ) exp
i
Z
t 0λ(s)b(s)hξi
mds
, where we have
|a
±0(t, 0, ξ)| ≤ C 1
λ(t) , (t, ξ) ∈ Z
pd(N ),
|a
±1(t, 0, ξ)| ≤ C 1
λ(t)hξi
m, (t, ξ) ∈ Z
pd(N ),
|∂
αξa
±0(t, 0, ξ)| ≤ C
M1
pλ(t) hξi
−|α|m, (t, ξ) ∈ Z
hyp(N ),
|∂
αξa
±1(t, 0, ξ)| ≤ C
M1
pλ(t) hξi
−(|α|+1)m, (t, ξ) ∈ Z
hyp(N ),
for all α, |α| ≤ β(M − 1). Moreover, we obtain u
t(t, ξ) = b
−0(t, 0, ξ)u
0(ξ) exp
− i Z
t0
λ(s)b(s)hξi
mds
+ b
+0(t, 0, ξ)u
0(ξ) exp
i
Z
t 0λ(s)b(s)hξi
mds
+ b
−1(t, 0, ξ)u
1(ξ) exp
− i Z
t0
λ(s)b(s)hξi
mds
+ b
+1(t, 0, ξ)u
1(ξ) exp
i
Z
t 0λ(s)b(s)hξi
mds
, where we have
|b
±0(t, 0, ξ)| ≤ Chξi
m, (t, ξ) ∈ Z
pd(N ),
|b
±1(t, 0, ξ)| ≤ C, (t, ξ) ∈ Z
pd(N ),
|∂
ξαb
±0(t, 0, ξ)| ≤ C
Mp λ(t)hξi
−(|α|−1)m, (t, ξ) ∈ Z
hyp(N ),
|∂
ξαb
±1(t, 0, ξ)| ≤ C
Mp λ(t)hξi
−|α|m, (t, ξ) ∈ Z
hyp(N ), for all α, |α| ≤ β(M − 1).
Theorem 6.2. Under the assumptions (A1) to (A4), we suppose β = 1/2 in (A4), let us consider the Cauchy problem
u
tt+ λ
2(t)b
2(t)hξi
2mu = 0, u(0, ξ) = u
0(ξ), u
t(0, ξ) = u
1(ξ).
Then the solution u = u(t, ξ) and its derivative u
t= u
t(t, ξ) possess the same representa- tions as in the previous theorem. The amplitudes satisfy the same estimates if we replace C
Mby C
M(Λ(t))
C0,0/m, where C
0,0is the constant from Corollary 5.1.
7. Littman-type lemmas. To derive L
p−L
qdecay estimates for Fourier multipliers in the next section we need the following two Littman-type lemmas.
Proposition 7.1. Let us suppose that the function a = a(t, ξ) has uniformly for all t ∈ [t
m,N, ∞) (we choose t
m,Nfrom (4.3)) a support (with respect to ξ) contained in a compact set K ⊂ R
n. Moreover, assume that
|∂
ξαa(t, ξ)| ≤ Chξi
−|α|mfor |α| ≤ n + 1, (t, ξ) ∈ [t
m,N, ∞) × K.
Then
kF
−1(e
ihξimR
t0λ(s)b(s)ds
a(t, ξ))k
L∞(Rn)≤ CΛ(t)
−n2for all t ∈ [t
m,N, ∞), (7.1) where the constant C depends on sup{|ξ| : ξ ∈ K} only.
Proof. We have to estimate sup
x∈Rn
Z
Rn
e
ix·ξ+ihξimR
t0λ(s)b(s)ds
a(t, ξ)dξ
for all t ∈ [t
m,N, ∞). There are two unbounded parameters, the scalar t (and, conse- quently, the function τ = τ (t) := R
t0
λ(s)b(s)ds is unbounded) and the vector x ∈ R
nin
the last integral. We are going to get an estimate which is independent of x ∈ R
nand
t ∈ [t
m,N, ∞).
Let us denote Φ(t, x, ξ) := x +
hξiξm
τ . Then there exist constants δ
1and δ
2such that
|Φ(t, x, ξ)| ≥ δ
2τ for |x| ≥ δ
1τ . With L e
ix·ξ+ihξimR
t0λ(s)b(s)ds
= e
ix·ξ+ihξimR
t0λ(s)b(s)ds
, L = 1
|Φ|
2n
X
r=1
Φ
r∂
∂ξ
r, we obtain for an arbitrary N ≤ n + 1 the inequality
Z
Rn
e
ix·ξ+ihξimR
t0λ(s)b(s)ds
a(t, ξ)dξ
≤ C
NΛ(t)
−N(7.2)
for all {(t, x) : t ∈ [t
m,N, ∞), |x| ≥ δ
1τ }. Here we need N derivatives of a = a(t, ξ) with respect to ξ.
For |x| ≤ δ
1τ we rewrite with y := x/τ and the inverse function t = t(τ ) sup
|x|≤δ1τ
Z
Rn
e
ix·ξ+ihξimR
t0λ(s)b(s)ds
a(t, ξ)dξ
= sup
|x|≤δ1τ
Z
Rn
e
ix·ξ+ihξimτa(t(τ ), ξ)dξ
= sup
|y|≤δ1
Z
K
e
iτ (y·ξ+hξim)a(t(τ ), ξ)dξ . For the stationary points of the phase function we get the relation
y + ξ hξi
m= 0. (7.3)
The Hessian H
ϕof the phase function ϕ = ϕ(y, ξ) = y · ξ + hξi
mhas the elements (H
ϕ)
jk= δ
jk− ξ
jξ
khξi
−2m. Thus the stationary points are non-degenerate ones. If |y| ≥ 1, then there is no stationary point. If |y| < 1, then a stationary point is given by
ξ = − m
p1 − |y|
2y, ξ ∈ K.
Without loss of generality one can choose K as a ball of the radius R. Then one has
|y| ≤ R
√ R
2+ m
2.
Therefore we choose for y some direction e
0= y
0/|y
0| and consider only points y belong- ing to the segment [0, R/ √
R
2+ m
2] of this direction. We are going to get an estimate independent of any direction. To simplify notations we set y
0= (−1, 0, . . . , 0). Thus we can restrict ourselves to the consideration of the integral
Z
|ξ|≤R
e
iτ (−zξ1+hξim)a(t(τ ), ξ)dξ, z ∈ [0, R/ p
R
2+ m
2] with the critical point
ξ =
m
√ 1 − z
2z, 0, . . . , 0
smoothly depending on z ∈ [0, R/ √
R
2+ m
2]. We are going to get an estimate uniform with respect to z ∈ [0, R/ √
R
2+ m
2].
The consideration of the asymptotic behaviour of the integral depending on the large parameter τ and parameter z is quite standard and follows with the arguments used in the method of stationary phase (see for instance, [3], [18]). We fix a point z = z
0∈ [0, R/ √
R
2+ m
2] and will get an estimate independent of z
0. In the small
neighbourhood of the non-degenerate critical point ξ
0= (mz
0/p1 − z
20, 0, . . . , 0) we use Morse lemma. Then there are a neighbourhood U of 0 ∈ R
n(independent of z
0) and a ball V (independent of z
0) and a diffeomorphism H
z0: V + ξ
0−→ U (y = H
z0(ξ)) depending smoothly on the parameter z
0∈ [0, R/ √
R
2+ m
2] such that for ϕ(z
0, ξ) = −zξ
1+ hξi
mone has
ϕ ◦ H
−1z0
(y) = ϕ(z
0, ξ
0) + 1
2 y
12+ . . . + y
2nfor all y ∈ U.
Moreover, the Jacobian of the diffeomorphism is uniformly bounded, that is there is a constant C such that
D H
−1z0(y) D y
≤ C for all z
0∈ [0, R/ p
R
2+ m
2].
For the integral under consideration we write Z
|ξ|≤R
e
iτ (−z0ξ1+hξim)a(t(τ ), ξ)dξ = Z
|ξ|≤R
e
iτ (−z0ξ1+hξim)χ(ξ)a(t(τ ), ξ)dξ
+ Z
|ξ|≤R
e
iτ (−z0ξ1+hξim)(1 − χ(ξ))a(t(τ ), ξ)dξ, where the cut-off function χ ∈ C
0∞(ξ
0+ V ) and χ(ξ) ≡ 1 if ξ ∈ C
0∞(ξ
0+ V /2). For the last integral it is easily seen that for every given N ≤ n + 1 there is constant C
Nsuch that
Z
|ξ|≤R
e
iτ (−z0ξ1+hξim)(1 − χ(ξ))a(t(τ ), ξ)dξ = C
Nτ
−Nfor all z
0∈ [0, R/ p
R
2+ m
2].
For the first one we write Z
|ξ|≤R
e
iτ (−z0ξ1+hξim)χ(ξ)a(t(τ ), ξ)dξ
= Z
U
e
iτ (ϕ(z0,ξ0)+12|y|2)χ H
−1z0(y)a t(τ ), H
−1z0(y)
D H
−1z0(y) D y
dy
= e
iτ ϕ(z0,ξ0)Z
Rn
e
iτ12|y|2χ H
−1z0(y)a t(τ ), H
−1z0(y)
D H
−1z0(y) D y
dy.
Hence, we obtain for a smooth function u(τ, y, z
0) having compact support with respect to y uniformly with z
0∈ [0, R/ √
R
2+ m
2], τ ∈ [τ
0, ∞), the representation Z
Rn
e
iτ|y|22u(τ, y, z
0) dy = (2π)
n2e
iπn4τ
−n2N −1
X
k=0
τ
−kk!
i 2 4
y ku(τ, 0, z
0) + S
N(u, τ, y, z
0),
where
|S
N(u, τ, y, z
0)| ≤ C
ε(N !)
−1τ
−n2−N1 2 4
y Nu(τ, y, z
0)
Hn2+ε(Rny)
for any ε > 0. The special choice N = 1 completes the proof of the proposition.
Proposition 7.2. Let φ = φ(s) be a C
∞-function having compact support in {s ∈ R ; s ∈ [c
0, c
1] }, c
0> 0. Then for t ∈ (0, t
m,N] and large τ
kF
−1
e
iτ Λ(t)|ξ|q
1+(m Λ(t)τ |ξ| )2
φ p
|ξ|
2+ (m Λ(t)/τ )
2
k
L∞(Rn)≤ C(1 + τ Λ(t))
−n−12X
|α|≤n
kD
αξφ p
|ξ|
2+ (m Λ(t)/τ )
2k
L∞(Rn).
Proof. For τ ≥ τ
0, τ
0large, we obtain c
0(τ
0) ≤ |ξ| ≤ c
1(τ
0), c
0(τ
0) > 0, on the support of function φ uniformly for t ∈ (0, t
m,N]. One can write
F
−1
e
iτ Λ(t)|ξ|q
1+(m Λ(t)τ |ξ| )2
φ p
|ξ|
2+ (m Λ(t)/τ )
2
= F
−1
e
iτ Λ(t)|ξ|
e
iτ Λ(t)|ξ|(q
1+(m Λ(t)τ |ξ| )2−1)
φ p
|ξ|
2+ (m Λ(t)/τ )
2
. It is easy to see that on the support of φ for all t ∈ (0, t
m,N] and for all τ ≥ τ
0D
ξα
e
iτ Λ(t)|ξ|q
1+(m Λ(t)τ |ξ| )2−1
φ p
|ξ|
2+ (m Λ(t)/τ )
2
≤ C
α.
Then by means of the result of [9] we complete the proof of proposition in the way used to prove Lemma 4 [1].
8. L
p− L
qdecay estimates for Fourier multipliers. The representations for the solutions from Theorems 6.1 and 6.2 suggest the study of the model Fourier multiplier
F
−1e
iR
t0λ(s)b(s)hξimds
a(t, ξ)F (u
0)(ξ)
, u
0∈ C
0∞(R
n).
Theorem 8.1. Suppose that the following assumptions are satisfied for the amplitude function a = a(t, ξ):
|a(t, ξ)| ≤ C 1
λ(t) , (t, ξ) ∈ Z
pd(N ),
|∂
ξαa(t, ξ)| ≤ C
M1
pλ(t) hξi
−|α|m, |α| ≤ β(M − 1), (t, ξ) ∈ Z
hyp(N ).
If M ≥ (n + 1)/β + 1, then we have the decay estimate
F
−1e
iR
t0λ(s)b(s)hξimds
a(t, ξ)F (u
0)(ξ)
Lq(Rn)
≤ C 1
pλ(t) (1 + Λ(t))
−n2(1p−1q)ku
0k
WL p(Rn),
where L = [n(
1p−
1q)] + 1 .
Proof. a) t ∈ (0, t
m,N] : Let χ = χ(s) ∈ C
∞(R
1) be a function with χ(s) = 0 for s ≤ N, χ(s) = 1 for s ≥ 2N and 0 ≤ χ(s) ≤ 1. We begin to estimate
F
−1e
iR
t0λ(s)b(s)hξimds
(1 − χ(K(t)hξi
m)) a(t, ξ)
hξi
2rmF (u
0)(ξ)
,
where K(t) := Λ(t)
β. Using the transformations K(t)ξ = η and K(t)z = x we get I =
F
−1e
iR
t0λ(s)b(s)hξimds
(1 − χ(K(t)hξi
m)) a(t, ξ)
hξi
2rmF (u
0)(ξ)
q
Lq(Rn)
= K(t)
n+(2r−n)qZ
Rn
Z
Rn
e
iz·η+iK(t)1R
t0λ(s)b(s)(|η|2+K2(t)m2)1/2ds
(|η|
2+ m
2K
2(t))
r× (1 − χ((|η|
2+ K
2(t)m
2)
1/2))a
t, η
K(t)
F (u
0)
η K(t)
dη
q
dz
= K(t)
n+(2r−n)qF
−1e
iK(t)1R
t0λ(s)b(s)(|η|2+K2(t)m2)1/2ds
(|η|
2+ m
2K
2(t))
r×(1 − χ((|η|
2+ K
2(t)m
2)
1/2))a
t, η
K(t)
∗ F
−1F (u
0)( η K(t) )
q
Lq(Rn)
. With the notations
T
t:= F
−1
e
iK(t)1R
t0λ(s)b(s)(|η|2+K2(t)m2)1/2ds
(|η|
2+ m
2K
2(t))
r(1 − χ((|η|
2+ K
2(t)m
2)
1/2))a
t, η
K(t)
the norm I can be written in the form
I = K(t)
n+(2r−n)qT
t∗ F
−1F (u
0)
η K(t)
q
Lq(Rn)
.
The distributions F (T
t) belong to M
pqfor all 2r ≤ n(
1p−
1q) (see [6]). This follows from the facts that for t ∈ (0, t
m,N] the functions 1 − χ((|η|
2+ K
2(t)m
2)
1/2) have a uniformly compact support with respect to η, from |a(t,
K(t)η)| ≤ C on this support, from
meas {η : (|η|
2+ m
2K
2(t))
−r≥ l} ≤ meas {η : |η|
−2r≥ l}
= meas {η : |η| ≤ l
−2r1} ≤ Cl
−2rnand from Theorem 1.11 [6]. Consequently,
F
−1e
iR
t0λ(s)b(s)hξimds
(1 − χ(K(t)hξi
m)) a(t, ξ)
hξi
2rmF (u
0)(ξ)
≤ CK(t)
2r−n(1p−1q)ku
0k
Lp(Rn)(8.1) for all 2r ≤ n(
1p−
1q). To study
F
−1e
iR
t0λ(s)b(s)hξimds