A N N A L E S S O C I E T A T I S M A T H E M A T I C A L P O L O N A E S e r i e s I : C O M M E N T A T I O N E S M A T H E M A T I C A E X V I I ( 1 9 7 3 )
R O C Z N I K I P O L S K I E G O T O W A R Z Y S T W A M A T E M A T Y C Z N E G O S é r i a I : P R A C E M A T E M A T Y C Z N E X V I I ( 1 9 7 3 )
J
a nL
t jc h te r(Krakow)
Determination oî the linear non-homogeneous geometric objects oî the type [m, n, 2], where m < w
Let M be an w-dimensional manifold an p a point of M. Any dif
ferentiable transformation of local coordinates (af ) -> (ya) in a neighborhood of p involves a system of real numbers
where (*)
A a а dya
** dxP (p)
- 92 ya Pa dxpdxv (p)
det[Аа р] Ф 0 and Aa Py = Aa v?.
The differential geometric object of the second class at the point ре Ж has a transformation formula
со1' = Ф A a p, А а Ру), I , Г = 1, m, P, V = •••>
where со1, со1' are the components of the object in coordinates (xa) and (Уа), respectively. We say they are of the type [m, n, 2]. If the functions Ф 1 are linear with respect to со 1 the object is said to be linear. Hence the general transformation formula of the geometric differential and linear object of the second class is the following
W <оГ +
Write L = (Ap, Apy). The set of all such number system fulfilling con
ditions (*), forms the full differential group L \ with composition law (2) {A’„ А°„У)-(В°„, Щу) = (A°BJ, A%B}r + A l xB“ f Bly).
(2) comes from the differentiation law for composed functions. The transformation formula (1) can be written in the matrix form
(3) 00 = F{L)co + g{L),
where F and g are matrices of dimensions m x m and m x 1, respectively, and Le L%. The subgroup
L' = {(Aa p, 0)}, det [A“] Ф 0
is isomorphic to the linear group GL (n, B) and the subgroup x" = {(a?, A?,)}
is additive in the sense that if Lx = (<5£, AaPy), L 2 = (ôp, Ba py) belong to L", then by (2)
(4) L XL 2 = Apy -\-Bpy).
One easily checks the following decomposition (5) {A}, A a py) = (Aa p, 0)(0a p, I “A$y), where [Л“] is the inverse matrix to [A®].
The problem of determination of the geometric objects considered is equivalent to solving the system of matrix functional equations
(
6) F( LXL 2) = F( L x ) F( L2), (7) g(LxL 2) = F ( L x)g(L2) + g(Lx), L x, L 2e L l ([2]).
We shall consider the case where m < n, because if m < n equation (
6) is not solved completely so far. Then, as it has been shown in [
8], the general solution of equation (
6) depends only on the matrix parameters Ap, i.e. on the elements of the subgroup L ', and fulfils the equation
(
8) Ф(Аа гЩ) =Ф(АЧ)Ф(Щ).
Using this fact, the equation (7) may be written as follows
(9) / ( X A ) = # i ( ^ ) + y K (X! ) + / ( X 1),
where L x = [Ap, Aa py).
In the case m = 1 equations (
6) and (7) have been considered by M. Kucharzewski and M. Kuczma in [3], [4] who aimed at determination of the linear geometric objects of the type [
1, w, s] (s >
2) i.e. with one component and of the class s. The objects are submitted to transforma
tion law
(10) со' = f(L)a> + g(L), L e L sn.
The authors, mentioned above, have shown that, if n = 1 the objects (10) exist (non-trivially) only if s < 3 and they are following
(a) if s =
1о/ = <р(Хг)а> + c [ ( p ( X x) — 1]
N on-homogeneous geometric objects 139
or
Co' = ft) + ln |ç9(J[’1)| , (b) if s = 2
, 1 x
со = ----со + A: „
X! X.
(c) if s = 3
1 3 X 2 ! X 3 / 1
ft) = ft)---Г----z r r “H & “b C I -r^2 — 1 I •
X 2 2 X} X? \X
Here is Х г = d£' /d£, X 2 = d?£'/d£2, X 3 = d3£'/d£3, <p(x) is an arbi
trary function satisfying the equation cp{xy) — q>{x)cp(y), and c , k are
constants. *
If n > 1 there are no geometric objects (10) of the class s ^ 2, [3].
In the present paper we shall generalize these results in the case 2 < m < n and s — 2.
In the case m = n equation (7) takes the form
<H) f ( L ,£, ) = ^ ( A J ) / ( i î) + / ( X 1), a,fi = 1,
Write
X = [AJ], X(X) = Щ ( А ) ] , g = [у“].
Then equation (11) can be written in the matrix form g(LiL2) = F (A)g(L2) + g(L г), and now (6) and (7) take the form
(12) F(AB) = F(A)F(B),
(13) g(Lt L,) ^ F ( A ) g ( L 2) + g(L1).
The general solution of (12) for arbitrary m < n has been found by M. Kucharzewski and A. Zajtz in [6] and it looks as follows
(H) F {A) = <p(J)GAG~1,
(15) X(A) =<p(J)G(ATr 1 G - \
(16) F (A) = G(J), J = detA.
Here <p(J) is a scalar multiplicative function: cpiJxJ^) = <p{Ji)(p(^ 2 )f
G{J) is a matrix multiplicative function, and G is an arbitrary non-singular
constant matrix. Herewith we are interested in the solutions of equation
(13). Substituting one of the known functions F{ J in (13) we shall de-
termine the desired g. For F = CFC
1we get g — Cg, [5]; so we can simply put C = F in (14), (15) and we shall only consider the cases
(17) F (A) = <P(J)A,
(18) F (A) = <P(J)(ATГ
1(19) F (A) = G(J),
because if С Ф E we get an equivalent solution g = Cg, g being solution for C = F. The forms (17) and (18) possible only if m = n, and (19) is valid for arbitrary m < n (*).
1. Non-existence of linear non-homogeneous objects with F (A)
= <p(J)A. Write
(
2 0) _ д ( А ) ^ д ( А ^ ,
0),
(
2 1) f W = g W , A % ) ,
where A = [A£], X = (Aa Py). Let L x — (ôp, Aa Py), L 2 = (Щ, 0). In virtue of (13) we have
(22) g i L M = F(ôp)g(Ba p, 0) + д(Г„ Aa Py) = F( F) g( B) +f ( X)
= Eg ( B) +f ( X) . By (
2)
(23) £ .£ » = ( Щ, А%. ЦЦ) .
On the other hand, using decomposition (5), we get for (23) (24) L XL % ^ { В а р, Щ 0 % Щ А ^ В х рВ^у),
where [B°] is the inverse matrix to [Б“]. Putting (24) into (13) we obtain (25) g(LxL 2) = Ж { Щ / { Ц А Ъ В № ) + д{Щ).
Comparing the right-hand sides of (
2 2) and (25) we come to the equality
(26) }(A%) = 1'(Ц т Щ А 1В *В »г).
Denote briefly
(27) X = U%,), 7 = (B}r).
Let L z = ( 6 %, Aa Py), L
4= (dp, Ba Py). According to (4) and (21) g(L 3 L,) = f(A a Py + Ba Py)
(1) This is the unique solution of (12) when m < n.
N on-homogeneous geometric objects 141
and with the notations (27)
(28) g(LaL4) = / ( Х + Г ) .
On the other hand, by (13)
(29) g(LaLA) = F(E)g(L,) + g(L,) = f ( Y ) + f ( X ) . Comparing (28) and (29) we get
(30) f ( X + Y) = f ( X ) + f ( Y).
Substituting F(B) = <p{J)B into (26) we obtain taking / = (//i)/i==i>...>n (31) f (Ха ру) = (p ( j ) B * r {Ва гх \ л т >
or briefly
(32) / ( X) =<ри)ВДЩХ1„В‘ В>).
We are to prove that f { X) = 0. '
Now let denote a fixed argument different from zero and the others are supposed to be zero(2). We choose
(33)
vqi
В = >
9
n_Qi • • • Qn >
i.e. J = det В = 1. The indices a, /?, y (/? < y) being fixed, we shall write f ( X % ) = f ( 0 , . . . , 0 , l - fr, 0 , . . . , 0 ) .
Putting (33) into (31) we get
Г Л у ) = Qn f l — XïrQeQy) (no summation on g and a).
f ( X) being an additive function, it holds f( rX) = rf(X) for any rational number r (3). Supposing дрду/да to be rational, we have
(34) П Щу ) = / " W -
9
a(*) W e consider only the essential argum ents X a ^ for /5 < y.
(8) Because no regularity assum ption was made on the function g and we w ant
v.86 the relation f ( r X ) — r f ( X ) we h ave to confine ourselves to r rational. Otherwise
the calculation would he simplier.
We shall use the folowing system of equations
(35) e
1-.-e» = i , Р Ф 1
Qa
for the unknown q x, Qn. We shall show that system (35) has always, a solution except for the two following cases:
I. n = 2 , [л — a, and (ft, a) is a permutation of (1,
2).
II. n = 2 , [л Ф a and ft = y = a.
(a) Assume n > 2 . Let
1
i 4 a
В = 2 P
2 У
1
if а Ф ft, у and
4 l
1
1
В = 2 P
2 У
1
iî a = ft or a — y.
Then equation (35) are fulfiled with Qy/Qa rational and p Ф 1.
(b) Assume n — 2 , ц = a, ft = y. Now (35) takes the form
Qi ' Qz — 1 > Qp = P } P Ф 1 •
N on-homogeneous geometric objects 143
We can put qp —
2and the other q equal to If n =
2, Ц Ф a, ft Ф y, we choose
...
1= ft = a ... 2 = y = p
Then QsQ — QxQi = 1 and = — = ---- or 16. Thus, in the
Qa Qa
1 6cases above considered, we can always find a rational solution of equation (35).
But if (35) holds, equation (34) takes the form f ( X ° fy) = р Г(Х%), р ф î , and hence
(3 6) = о .
27ow we shall consider both cases I and II simultaneously. Let
(37) х\г Ф
0and the others X x fXV =
0(/и < r). We choose
0 1 0 - 1
(38) В В =
1 0 1 0
Putting (37) and (38) in (32) we get
(39) f ( o , x l
2 0, . - . ,
0) = B l f ( Y l
"where
(40) К = T
2p v B ri BT
2According to (37) and (38)
1
.
Ï Î
1= ГЬ = B \ X \ x B\'B\* = В \ Х \ гВ\В\ + В \ Х \ хВ\В\
= - * i i = - X l 2.
The others Х^у =
0. Using it in (39) we have
(41) f (
0, X
12,
0, . . . ,
0) = /
2(
0, .. .,
0, - X î
2,
0),
^here — X \2 is in the place L^).
(37) being still valid, we choose in turn
1 1
, в = ^ + 1 —l
q e + i_ ,—Q
B y (32)
(43) f ( 0 , X { 2 , 0 , . . . , 0 ) + where Y \v is defined by (40).
According to the results obtained by now, we can state that, if n =
2, the function
/ 1may depend only on Y \2 provided I, and on Y
22provided II.
Similarly f 2 depends on Y \2 and Y}x.
Thus the left-hand side of (43) is equal to 0 and we get 0 = B 2 f ( 0, Y\2, 0, . . . , 0, Y ^ + B t f i Y l , , 0, ..., 0, Y\2, 0).
Using additivity of / we obtain from this
(44) 0 = B j/
1(0, Y\2, 0, .. . ,
0) + -B
2/ x(
0, ...,
0, Y 2 22) +
+ B 2 2 f ( 0 , Y 1 n,0 , . . . , 0 ) - Y B 2 2 f ( 0 , . . . , 0 , r i , 0).
From (40) and (42) we get
П = B \X li r Bl'B\> = B lX l.B lB l + Bl X^Bl Bl
— %B\B\B\X \2 = 2 ( q -\-1) q X{2, (45) Y
}3= (? +
1)(
2é > +
1)A}2,
Y
12= q (2 q -{-2)X12, Y
22= —2^(^ + l)X }2.
We substitute (45) and (42) in (44) and suppose q to be rational.
For the sake of brevity, denote P 0 , X }
2, 0 , . . . , 0 ) ,
Q = f { 0 , . ..,
0, X \2), X \2 is in place ^ , R = f ( X \ 2, 0, .. . , 0), X \2 is in place
8 - = /
2(0, ... , 0, X \2i 0), X \2 is in place
X on-homogeneous geometric objects 145
After the substitution we get
0
= + + — 2 q 2 ( q -}- 1 )Q +
2(^ + l) ( p - |- l) i
2—
Hence, by a simple computation
0
= - 2 Q q *+{ 2P + 2 R - 2 8 ) q + P + 2 R - 2 8 . Since q is an arbitrary rational number, it implies
(a) II
0(b) 2P + 2 R - 2 8 =
0,
(c) P + 2 R - 28 = 0.
Prom (b) and (c) we obtain P —
0, R 8 . But in view of (41) P — — 8 , hence R = 8 — 0.
So we have proved that the functions f* vanish also in cases I, II.
Thus we have finally
(46) f ( 0 ...0 , r fr, 0 , . . . , 0 ) — 0, fx = l , . . . , n , for any a, /3, y.
The sequence of arguments (Х\г, X a Py, X^n) can be decom
posed as follows:
(XJi, 0, . . . , 0 ) + (0, . . . , 0, X a Py, 0, . . . , 0) + ... + (0, . . . , 0, Xnn), each sequence containing at most one non-vanishing argument, and by the additivity of / we get
(47) f ( X 1 u , . . . , X ^ , . . . , X - n) = f ( X j 1, 0, . . . , 0) +
+ . . . + Г (
0, . . . ,
0, х ^ ,
0, . . . ,
0) + . . . + Г (
0, . . . ,
0, х : п).
In view of (46) the vector-function / vanishes
(48) f ( X ) = 0
for any X =
Let L = (A%,
0), L' = («J, A °A}y).
Then
L = L - L ’ = (A%, A%) and
g(L) = g(LL') = g [(A 4 , 0)(d}, 3%A},)]
10 — R o c z n i k i P T M — P r a c e M a l e m a t y c z n e X V I I
and by (13)
(49) g{L) = F(A)g{L') + g(L)
= F ( A ) f ( I a TA}y) + g(Aap, 0), A = [Aa p].
If F(A) =( p ( J ) A, then (48) holds and we obtain g{L) = g{L) = g (A).
Thus the function g does not depend on A a Py and fulfils the equation g{LxL % ) = F{ Lx)g{L 2 ) +g{Li ) .
We proved the following
S tatem ent
1. The general solution of equation (13), when F (A)
= <p(J)A, does not depend on the parameters Aa Py and it holds
where g fulfils (50).
In the terms of the theory of geometric objects it means:
S tatem ent 1'. There are no linear non-homogeneous geometric objects of the type [n, n, 2] in the case F (A) — <p{J)A.
2. Non-existence of linear non-homogeneous objects in the case F(A) = (p(J)(AT)~l, if cp{J) Substituting F ( B ) = cp(J)(BT)~l into (26) and adding equation (30) we get the following system of functional equations
It means that g {A) fulfils the equation
(50) g(A гА 2) = F i A J g i A J + giAj).
g(Aa p, A a Py) = g{Ap)t
(52)
(51) f { X % + Y % ) = f m y) +f { Y%) , f ( X a Py) =<р(Т)(Вт)~1Д Щ Х 1 вВ>В*у), where is desired.
We rewrite equation (52) in coordinates
(53) Л(-Цу) = p { J ) B a j a{^xx \ eBx pBi).
Putting В = q E ( q Ф 1) we get (54)
(4) The case <p(J) = 1 is treated in section 4.
Non-bomogeneous geometric objects 147
One can express (64) briefly
(65) f ( X ) = ? ( e n) - f ( e X ) , or f ( eX ) =
e <p(e)
L
e m m a1 . / is a linear function of the vector-argument X.
P roof. Let X 0 = (0, 0 , 1 , 0, 0), where 1 is in a fixed place and let c„ = /Д Х 0).
Prom (55)
Q
fp ( q X o ) ^ / nT си’ № =
1» • * • > n • But
/ , ( A ) = / „ (
0, o, Q,
0, ... ,
0) = y„(g).
If = 0, then = 0 and if # 0, then — y>„(e) = . ---
2
ФхЯ )
is a multiplicative function. But — ^ ( q ) is also an additive one because
f j e ^ o ) is- c“ .
It is well known that any multiplicative and additive real-valued function of a real variable is continuons and equal to identity, so — w(@)
= q
, =
cm qis linear(5). Gft
Thus any function
• • • >
0> ’
0> • • • >
0)> fi
1) •••) n
is linear, from which and from the additivity of / our statement folows immediately.
/ being linear, we have f{gX) = gf(X) and from (55) /(X ) = cp{Qn)f{X)
for any X and q . Thus, if <p(J) ф 1, for some q is у{дп) ф 1 and, con
sequently f { X) = 0. Similarly, as in section 1 we get the following
S
t a t e m e n t2 . Any solution of equation (13) in the case where F (A)
= <p(J)(A T)~1 and (p{J) Ф 1 does not depend on the parameters A a Py.
S
t a t e m e n t2 '. There are no linear non-homogeneous geometric objects of type [n, n, 2] when F (A) = (p(J)(AT)~1, cp(J) Ф 1.
(5) It is still valid for см — 0.
3. Non-existence of the linear non-homogeneous objects in the case F(A) = G(J), J = D etA, m ^ n . Substituting F(B) — G{J) and enclosing equation (30) (6) we get the equations
(
6 6) Я Х Ъ + Х у = /(X ?,) + / ( Щу) ,
(57) / ( Z y
where / is desired.
If 1? is an unimodular matrix, so J = 1, then G (1) — E because of multiplicativity and non-singularity of G(J). Thus equation (57) takes the from
(58) f(X%,) = / ( В Д е^ Б £ ).
Choosing В as in (33) we get from (58)
(59) / ( o , . . . , o , Z
5, , o , . . . , o ) = / ( o , . . . , o , i z j , e <iey, o , . . . , o j . For we can always find Qlt ..., Qn, such that
(60) •••£« =
1? — QpQY =
1 2. Qa
Substituting дг, Qn, that satisfy (60), into (59) and using ad
ditivity of / we have
/ ( 0
, .. . ,
0, XpY,
0, ...,
0) =
2/ (
0, ...,
0, Xfo,
0, ...,
0).
And hence
/ (
0, •••,
0, Xfo,
0, ...,
0) =
0from which, as previously, it follows f { X) = 0.
Thus the function g does not depend on A a Pv and fulfils the equation g{Aa dBD = G(J)g{Ba p) + g { A );).
So we come to the similar conclusion as in statements 1, 3/ and
2,
2' and the title of this section is substantiated.
4. Determination of linear non-homogeneous geometric objects of the second class, when F (A) = (AT)~1. In this case we have to solve the following system of functional equations
f(X% ,+ Y%) = / ( X J , ) + / ( Y p , f(Xpv) =
(6) Valid also in the case m < n.
N on-homogeneous geometric objects 149
or in coordinates
(61) / „ ( x ^ + r j , ) = /„ ( Х
2„ ) + / „ ( у у ,
(62) /„(XJ,)
Lemma 1 holds in this case, so the functions / м(ХРу) are linear, and knowing it, we can confine ourselves to equation (62).
Let a, ft, у (ft < y) he fixed, X Py Ф 0 and the other X = 0. Put
1
(63) [ ^ ] = P . . . f t
1
Here the r, p, q can coincide, if the a, ft, у do.
Substituting (63) in (62) we get 6 4
(a) f» = /» if p Ф a, ft, у
( b )
1
-
fa
11
^ II if p = a,
(e)
1»
U = j ff if II
( d )
1
~
fy = —fy q if P = У,
w h e r e
/л *=/„(<>,..- , о , х ъ ,
0 , . . . , 0 )and/,, = /„((>,.
We shall show that
(64) /„(
0, . . . ,
0, Х ^ ,
0, . . . ,
0) =
0, provided one of the following cases holds
1 p Ф a, ft, y,
2
° a, ft, у different,
3° а Ф ft = y,
4° a = p, p ф y.
Ad
1°. For p Ф a, f i , y we have
(65) /„( 0 , . . . , 0 , X ^ , 0 , . . . , 0 ) /J O , • • • i b> pq
, o , . . . , o ).
Taking — = 2 we easily get (64) because of the linearity of /.
r
Ad
2°. a, ft, у different. We put r —
1in (b), p —
1in (c) and q =
1in (d). Then
(b) /«( o,.. ..,0) = /«( 0,.. ., 0 ,pqX%, 0, .. .,0), (c) Л(ь,. .., 0, Xpy , о, ...,0) =л(°> ••-, 0,-^xj,, °. •'
- ° ) (d) Л(о ,-
оN
О..,0) II
o.,o,^x?,,,o,.
r - ° )
Taking pq, — , — = 2 in the above equalities, respectively, we get q p r r
the same conclusion as in
1°.
Ad 3°. а Ф /? = y, so p ~ q. ÏJow we put r = 1 in (b), p = 1 in (c) and q = 1 in (d). Then
(a) /„ (
0, . . . ,
0,X J(),
0, . . . ,
0) = / „ |o , . . . ,
0, ^ Х “ да,
0, . . . , о | , (b) /„(»,
0, X%,
0,
0) = / „ (
0,
0 0,
0), (c) • • • ) o, • • • > о) —
/ 0f o ? ..., o, o , ..., o), (d) / , (
0,
0, X%,
0,
0) = / J o , .. . .
0,
0, oj.
p 2
1Letting — , p 2, — be equal
2, respectively, we easily get (64) in any of these cases.
Ad 4°. a --
f î , И'7^
У,SO r
=p. Then * (b) / . ( 0 , . . . ,
0, X “„ ,
0, . . .,b) = - / - ( o , ..
r ..,
0, qXa ay,
0, . . . ,
0)
(c)
M o ,. . .
,b
, X a y ,b
, •• • ? b) =
—p
M o ,• .., 0, qXa av, 0, . . . , b)
(d)
M o ,. . . ? b , ,
0, .. . ,
0)
= M o , o ,q x a ay ,
0, ... , 0 ) .
We put here r = p = 1, q
---
2and obtain (64).
N on-homogeneous geometric objects 151
So we see that f M(0, . .. , 0, Xpy, 0, .. ., 0) can be Ф 0 only if a =
0, 1 * = y.
Thus depends only on arguments X a afi, a — 1 , .. ., n , being linear, it is a linear combination of X ^ with constant coefficients (7“, so is of the form
П (
6 6) /„(x ii> •••> K , , - - ) =
a = l
We shall show that the matrix [C“] looks as follows
(67)
d c c ... c c d c ... c r a =
G G ... G d In fact, let
(
6 8) X a al = ... = X a afi = ... = X a an Ф 0 (a - fixed), and the other X ^ = 0 for 0 Ф a, fi = 1, .. ., n.
Fix
0Ф a and put
1
(69) Щ \ =
0 1
...a
1 0
...
0• /
1
i.e. [Ba p\ is the permutation matrix of indices a and 0. It is Bp — Putting (
6 8) in (62) and taking into account that depends only on we obtain
/ „ ( 0 , . . . , 0 , X a » „ 0 , . . . , 0 ) = £ • / , ( 0 , . . . , 0 , Ylw 0 , . . . , 0 , Y l , 0 , Y£„,
0), where
(70) Y l = Bl,X'4 V B ’J B ? .
N ba
Using (
6 8) and (69) we conclude from (70), that only the following Y x X[i can be Ф 0,
K ( = X ap) if A* = a,
? Ь ( = Х а аа) if
and all the variables are equal to the fixed X*x.
Hence
(71) /„( 0 , . . . , 0 , X ^ , 0 , . . . , 0 )
..,
0, Хрц,
0, . . . ,
0) if fx Ф «? P, / , (
0, . . . , o , x J L , o , . . . ,
0) if fx = ./„(
0, . ..,
0, X ,
0, . . . ,
0) if [x =
0. But in view of (
6 6)
/Д 0 , 0, X Xft, 0, 0) = C*Xlp (no summation on A).
So equalities (71) take the form
pP yP if (x Ф a, /?,
(72) Г\а ■p'a _ pP yP
Vp XPa if fx = a, pP yP
1 PP if P = P- We have here:
Y l = Y l = Y’„ = XI, ф 0.
Comparing the corresponding coefficients in (72) one obtains
(73) = c l ,
(74) Cl = <??,
(75) c? = Of.
Equality (73) means the elements in rows of the matrix [0“] are equal, apart from a = /?. (74) denotes the equality of elements in the main diagonal, and (75) the symmetric of [0“]. All in all, the matrix [0“] is of form (67).
Consequently, formula (
6 6) takes now the form П
(76) f , ( X) = c ^ X ‘, + d X ^ ,
a = l
where c, d are some constants.
N on-homogeneous geometric objects 153
We are going to prove that c = d. Since (76) satisfies equation (62) so we have
П
(77) e ^ X ^ + d X ^ = Щ\с ] ? Щ Х 1 л В:1В? + аЩХ1л В?В1*\.
а ф ц a = 1
а ф е
After a simple calculation we get for the right-hand side of (77)
11 ^
(78) P = с ] ? Щ Щ Х \ х В11В? + ( й - с ) Щ В ‘тВ \ ' В ? Х \ п .
a — l
And using the relations
(79) = B*TB Ï = ÔÏ,
we get
P = od'/ô?Xl 1T2 + (d-c)ô^ô'l? Xl iXî = c 2 x i t + ( d - c ) 2 x i f .
X X
Coming back to (77) we obtain
(80) о £ x i , + (d-c)X»m = c ^ X l , + ( d - e ) ] j x % .
X X X
Let =
0and X x % ll —
1if т Ф g (then = n — 1 ) ; from (80)
X
0
= (d — c) = (d — c)(n —
1).
T
Hence for n >
2it must be d = c, q.e.d.
So we get from (76)
П
да) f „ ( x ) = c ] ? x : „ = c x : r .
a = 1
Putting F (A) = {ATy 1 in (49) we have
g{A^,X%) = ( l ^ - V ^ r ^ + A ^ ) , where h(Ap) = g(Aa p, 0) and in coordinates
(82) 9ГЩ , X%) = 2 ‘J Q(A °X }y) + hlt(A°fl).
Taking into consideration (81) we have from (82) (83) % (2 } ,X°fy) = cA°„A° X ’ae + %„ (A°„).
Here is a solution of the equation
(81) К ( 2 Щ ) = 2 ’М Щ ) + h„(Aî).
Now, we shall show that the yector-function g defined by (83) satis
fies the functional equation (13), where F (A) = (A T)~l for arbitrary c, i.e. the equation
(85) gr {(A<i, XJy)(RJ, Y%)] = Ае„д,(Щ, ХЪ) + д„(АЬ Х Ъ)- According to (
2) the left-hand side of (85) is equal to
(