Theoretical Chemistry
Marek Kręglewski
Wydział Chemii UAM
Course content
I. Experimental background of quantum mechanics II. Observables and operators
III. Models in quantum chemistry IV. Hydrogen atom and orbitals
V. Multi-electron atom, spin and Pauli Exclusion Principle VI. Molecule H2+
VII. Two-atomic molecules VIII. Ab initio calculation IX. Vibrations of molecules X. Rotations of molecules
Literature
1) Peter Atkins & Julio de Paula, Atkin’s Physical Chemistry (Part2),
Oxford University Press 2014
2) Andrew R.Leach, Molecular Modelling – Principles and
Applications, Pearson Education Limited 2001
3) Lucjan Piela, Idee chemii kwantowej, PWN, Warszawa 2001
4)
Włodzimierz Kołos, Chemia kwantowa, PWN, Warszawa 1991.
Black body emission spectrum
0 100 200 300 400 500 0 500 1000 1500 2000 2500 3000 3500 u(20) u(100)
1
8
,
3 2
kT he
h
c
T
u
Spectral density:Planck hypothesis (1900): ΔE=hν (quantum of energy)
h = 6,62∙10-34 J s c = 2,99792458∙108 m s-1 k = 1,380662∙10-23 J K-1
T
b
max
max
Photoelectric effect
(-) (+)
spark
hν The Lenard laws (1899)
1) The number of emitted electrons is proportional to the intensity of light 2) The maximum velocity of electrons
depends on wavelength not on intensity of light
Einstein formula (1905, Nobel prize in 1921):
hν = ½ m
ev
2+ W
Zn
„In fact, it seems to me that the observations on "black-body radiation", photoluminescence, the
production of cathode rays by ultraviolet light and other phenomena involving the emission or conversion of light can be better understood on the assumption that the energy of light is distributed discontinuously in space. According to the assumption considered here, when a light ray starting from a point is
propagated, the energy is not continuously distributed over an ever increasing volume, but it consists of a finite number of energy quanta, localised in space, which move without being divided and which can be absorbed or emitted only as a whole.”
Photoelectric effect
Es scheint mir nun in der Tat,
daß die Beobachtungen über die
„schwarze Strahlung‟, Photolumineszenz, die Erzeugung von
Kathodenstrahlen durch ultraviolettes Licht und andere die
Erzeugung
bez.
Verwandlung
des
Lichtes
betreffende
Erscheinungsgruppen besser
verständlich erscheinen unter der
Annahme,
daß die Energie des Lichtes diskontinuierlich im Raume
verteilt sei. Nach der hier ins Auge zu fassenden Annahme ist bei
Ausbreitung eines von einem Punkte ausgehenden Lichtstrahles die
Energie nicht kontinuierlich auf
größer und größer werden der
Räume verteilt, sondern es besteht dieselbe aus einer endlichen
Zahl von in Raumpunkten lokalisierten Energiequanten, welche sich
bewegen, ohne sich zu teilen und nur als Ganze absorbiert und
erzeugt werden können.
"Über einen die Erzeugung und Verwandlung des Lichtes betreffenden heuristischen Gesichtspunkt”. Albert Einstein, Annalen der Physik. Vol. 322 No. 6 (1905): 132–148.
Compton effect / scattering (1923)
θ φ λ λ’ me v A
m
c
m
h
e02426
,
0
10
426
,
2
2
sin
2
12 2
λ’ > λ
p
e= m
ev
p
f= h/λ
p
e= p
fm
ev = h/λ
Spectrum of the hydrogen atom
ΔE(i←j) = T
i– T
jλ = hc / ΔE
de Broglie hypothesis (1923)
h
p
Why is the duality not observed in classical mechanics? m = 2g v = 1000 m/s p = 2 kg m /s h = 6,62∙10-34 J s c = 2,99792458∙108 m /s λ = (6,62 ∙10-34 / 2) m = 3,31∙10-25 nm
p
h
Wave-particle duality: a key concept of
quantum mechanics
Uncertainty principle
2
p
xx
E
t
1923 - Werner Heisenberg Exact formula:4
2 2 2
p
xx
Wavefunction
Postulate I
All information about a system are included in its wavefunction.
The square of the wavefunction│ Ψ│2 describes the probability density
x
,
y
,
z
2dxdydz
1
Operators in Quantum Mechanics
Postulate II
Operators of position and momentumx
i
p
x
x
x
ˆ
ˆ
The operator is defined through its action on a function.
In order to build an operator of a complex physical quantity the positions and momenta in classical Newtonian expression are replaced by corresponding operators.
Hamiltonian – the operator of total mechanical energy
ˆ ˆ ˆ
ˆ( , , ) 2 1 ˆ ˆ ˆ ) , , ( 2 1 ) , , ( 2 ) , , ( 2 2 2 2 2 2 2 2 2 z y x V p p p m V T H z y x V p p p m z y x V m p z y x V v m E E E z y x z y x pot kin total Time evolution of a wavefunction
Postulate III
t
i
H
ˆ
If potential energy does not change with time the Schrödinger equation converts to:
E
H
ˆ
Time evolutionValues of observables
Postulate IV
If a wavefunction Ψ is the eigenfunction of the operator Â
a
A
ˆ
The experimental measurement can give the value a, only
.
Expectation (mean) value of the operator
dV
dV
A
A
ˆ
ˆ
A
ˆ
a
when Ψ is an eigenfunction of the operator Âa
A
ˆ
when Ψ is not an eigenfunctionModel 1: Free particle in space
x 2 2 2 2 2 2 22
2
1
0
2
ˆ
ˆ
ˆ
ˆ
0
2
0
2
dx
d
m
dx
d
i
m
m
p
V
T
H
m
p
mv
E
E
E
x x x pot kin total
E
x
dx
x
d
m
x
E
x
H
2
2 22
ˆ
iax iaxNe
x
Ne
x
2 1
Test of solutions:
m
a
E
ENe
e
Na
m
e
Na
e
ia
N
x
dx
d
Niae
x
dx
d
Ne
x
iax iax x i iax iax iax2
2
2 2 2 2 2 2 1 2 2 1 1
Model 2: Particle in a box
0 a x I V= II V=0 III V=
0 sin 2 0 ˆ x x a n a x x E H III II I 2 2 2 2 2ma n E The motion of a particle limited to the well <0,a>.
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 n2
Particle in a box
2 2 2 2 0 2 0 2 2 2 0 2 0 2 2 2 0 0 2 2 2 2 sin 2 sin 2 2 sin 2 sin sin 2 2 sin 2 sin 2 sin 2 2 sin 2 n ma dx x a n a dx x a n a n m a dx x a n a dx x a n dx d x a n m a dx x a n a x a n a dx x a n a dx d m x a n a E a a a a a a sin cos 1 sin 2 0
2 sin 2 sin 2 0 0 0 x dx a n a n i a dx x a n x a n a n i a dx x a n a dx d i x a n a p a a a x
2 2 2 2 0 2 2 0 2 2 2 0 2 2 2 2 2 cos 1 2 1 2 sin 2 sin 2 sin 2 n a dx x a n a n a dx x a n a n a dx x a n a dx d x a n a p a a a x Expectation values of energy, momentum, momentum squared and position
2 2 2 cos 2 2 1 2 sin 2 2 1 2 2 sin 2 2 1 2 sin 2 sin 2 sin 2 0 2 2 0 0 0 2 0 a a a x a n n a x a a dx x a n n a x a x a n n a x x a dx x a n x a dx x a n a x x a n a x a a a a a
Particle in a box
2 2 2 0 2 2 2 2 2 2 0 0 3 0 0 2 0 3 0 2 0 2 0 2 2 0 2 2 2 1 3 1 2 sin 2 2 2 3 2 cos 2 1 2 cos 2 1 3 2 sin 2 2 1 2 sin 2 1 3 1 2 cos 2 1 2 2 1 2 sin 2 sin 2 sin 2 n a x a n n a n a n a a dx x a n n a n x a n n a x n a dx x a n x n a a x a n n a x a x a dx x a n x a dx x a dx x a n x a dx x a n a x x a n a x a a a a a a a a a a
4 2 3 1 4 2 1 12 1 2 1 4 1 3 1 0 2 2 1 3 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 n n n n n a n a n a p p x x p p x x p p p p x x x x p p x x p x p p p x x x x x x x x x x x x x x x x x Test of the uncertainty principle for the particle in a box: Expectation values of position squared
Particle in a box
2 2 4 2 3 2 2 1 sin 2 x a Nx x x a Nx x x a Nx x x a Nx x x a n a x Eigenfunction (exact)Trial functions (approximate):
xa x a x a N a N a N a a a N x x a x a N dx x ax x a N dx x a x N a a a 5 1 5 5 2 5 2 5 5 5 2 0 5 4 3 2 2 0 4 3 2 2 2 0 2 2 30 30 30 1 30 5 4 2 3 5 4 2 3 2 x a x a x a N a N a N a a a N x x a x a N dx x ax x a N dx x a x N a a a 2 7 2 7 7 2 7 2 7 7 7 2 0 7 6 5 2 2 0 6 5 4 2 2 0 2 2 2 105 105 105 1 105 7 3 5 7 6 2 5 2
2 7 3 7 7 2 7 2 7 7 7 7 7 2 0 7 6 5 2 4 3 3 4 2 0 6 5 4 2 3 3 2 4 2 0 2 2 2 105 105 105 1 105 7 3 2 5 6 3 7 6 4 5 6 4 4 3 4 6 4 x a x a x a N a N a N a a a a a N x x a x a x a x a N dx x ax x a x a x a N dx x a x N a a a
1 630 5 1 3 2 7 6 2 1 9 1 5 6 4 7 6 8 4 9 4 6 4 4 2 4 4 9 2 9 2 0 5 4 6 3 7 2 8 9 2 0 4 4 5 3 6 2 7 8 2 0 7 6 2 5 3 8 6 2 4 4 2 0 2 2 2 2 a N a N x a x a x a x a x N dx x a x a x a ax x N dx ax x a x a x x a x a N dx x a x N a a a a 2 2 9 4 9 9 2 630 630 630 x a x a x a N a N Particle in a box
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 0 0.2 0.4 0.6 0.8 1 1.2 sin f1 f2 f3 f4 The graph of the eigenfunction and trial functionsParticle in a box
2 2 2 2 2 0 2 2 0 2 2 2 0 2 2 2 2 87 , 9 2 2 cos 1 2 1 2 2 sin 2 2 sin 2 2 sin 2 ma ma dx x a a m a dx x a a m a dx x a a dx d m x a a a a a 2 2 2 1 2ma E 2 2 9 4 2 7 3 2 7 2 5 1 630 105 105 30 sin 2 x a x a x x a x a x x a x a x x a x a x x a a x 2 2 0 3 2 2 5 0 2 5 5 0 2 2 2 5 2 10 3 2 2 30 2 30 30 2 30 ma x x a m a dx x a x m a dx x a x a dx d m x a x a a a a 2 2 0 5 4 3 2 2 7 0 4 3 2 2 2 7 0 2 2 7 2 7 0 2 2 2 2 7 2 14 5 6 4 8 3 2 2 105 6 8 2 2 105 6 2 2 105 105 2 105 ma x x a x a m a dx x ax x a m a dx x a x a x m a dx x a x a dx d m x a x a a a a a 2 2 0 5 4 3 2 2 3 2 7 0 4 3 2 2 3 2 7 0 2 2 7 2 7 0 2 2 2 2 7 2 14 5 6 4 16 3 14 2 4 2 105 6 16 14 4 2 105 6 4 2 105 105 2 105 ma x x a x a x a m a dx x ax x a x a m a dx x a x a x m a dx x a x a dx d m x a x a a a a a 2 2 2 2 0 7 6 5 2 4 3 3 4 2 9 0 6 5 4 2 3 3 2 4 2 9 2 2 0 2 2 2 9 2 2 9 0 2 2 2 2 2 9 2 12 7 12 6 36 5 38 4 16 3 2 2 630 7 12 6 36 5 38 4 16 3 2 2 630 12 36 38 16 2 2 630 12 12 2 2 630 630 2 630 ma m a x x a x a x a x a m a dx x ax x a x a x a m a dx x ax a x a x m a dx x a x a dx d m x a x a a a a a Two-dimensional box
x y a b 0 V=0 V= V= V= V=
y E
y y m x E x x m E E E E y y y m E x x x m E y y y m x x x m y x y x E y y x m x x y m y x E y x y m y x x m y x E y x y m x m y x y x y x E y x y m x m y y y x x x y x y y y x x x y y x x y x y x y x x y y x y x y x y x y x y x 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 2 1 2 1 2 1 2 / 2 2 2 2 2 2 , , , 2 2
x a n a x a n m n Ex n 2 sin 2 2 2 2 2 Two-dimensional box
x y a b 0 V=0 V= V= V= V=
y b k b x a n a y x b k a n m Enk nk , 2 sin 2sin 2 2 , 2 2 2 2 2 , Degenarate states: If a=b then E1,2= E2,1
y a a x a a y x a a m E 2 sin 2 sin 2 , 2 1 2 2 , 1 2 2 2 2 2 2 2 , 1
y a a x a a y x a a m E sin 2 2 sin 2 , 1 2 2 1 , 2 2 2 2 2 2 2 1 , 2 Hydrogen atom – classical picture
e cF
r
e
r
m
F
2
2 0 24
1
v
1 1510
.
6
1
s
T
1/2 6 1 010
.
2
4
v
ms
mr
e
eV
V
T
E
13
.
6
Reduced mass
motion of the reduced mass around a center of mass
mr
e
Mr
Nr
r
e
r
N
n
r
M
r
m
e2
N2
n r M m mM 2
M
m
mM
em
/
0.99945 (H)
0.99972 (D)
Hydrogen atom
2 2 2 2 2 2 2 2 2 2 2 ez
y
x
r
r
e
z
y
x
2
H
ˆ
Schrödinger equation:
)
z
,
y
,
x
(
E
)
z
,
y
,
x
(
H
ˆ
e
Spherical coordinates:
x = r sinθ cosφ
y = r sinθ sinφ z = r cosθ z P x y r θ φHydrogen atom 1
2
2
2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 22
2
ˆ
e j e j e j e e e e j j j jz
z
y
y
x
x
r
r
e
z
y
x
m
z
y
x
M
H
Center of mass coordinates: e j e e j j e j e e j j e j e e j j m M z m z M Z m M y m y M Y m M x m x M X Relative coordinates: 2 2 2 z y x r z z z y y y x x x j e j e j e x z y j e xe xj zj yj ze ye r
x
jy
jz
jx
ey
ez
e
E
c
x
jy
jz
jx
ey
ez
e
H
ˆ
,
,
,
,
,
,
,
,
,
,
Hydrogen atom 2
m M X x m M x X M m x M X M m M x X M m x m X M m m x M x m x X M m M x X M m M x X M m M x x X M m m x X M m m x X M m m x x X M m M x x x X x X x x X M m m x x x X x X x j e j e j j j e e e 1 1 1 2 2 2 1 2 1 2 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 Transformation of the Hamiltonian to the center of mass and relative coordinates
Similarly for Y, Z, y, z:
r e z y x Z Y X m M H e j 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ˆ Hydrogen atom 3
r
e
z
y
x
Z
Y
X
m
M
H
e j 2 2 2 2 2 2 2 2 2 2 2 2 2 2 22
2
ˆ
Schrödinger equation after the separation of coordinates:
)
,
,
(
)
,
,
(
ˆ
,
,
,
,
ˆ
z
y
x
E
z
y
x
H
Z
Y
X
E
Z
Y
X
H
e trans trans
Translation of atom relative motion of nucleus and electron
E
total=E
tr+E
x
j,
y
j,
z
j,
x
e,
y
e,
z
e
X
,
Y
,
Z
,
x
,
y
,
z
X
,
Y
,
Z
x
,
y
,
z
Hydrogen atom 4
Schrödinger equation:
)
z
,
y
,
x
(
E
)
z
,
y
,
x
(
H
ˆ
e
Współrzędne sferyczne: x = r sinθ cosφ y = r sinθ sinφ z = r cosθr
e
z
y
x
H
e 2 2 2 2 2 2 2 22
ˆ
2 2 2z
y
x
r
0≤r<, 0≤θ≤π, 0≤φ<2π z P x y r θ φHydrogen atom 5
r
e
sin
1
sin
sin
1
r
r
r
r
2
H
ˆ
2 2 2 2 2 2 2 e
)
,
,
r
(
E
)
,
,
r
(
H
ˆ
e
(
r
,
,
)
R
(
r
)
After the separation a set of 3 equations:
R
r
E
R
r
r
e
l
l
r
r
r
r
l
l
m
m
i
nlm n nlm lm lm m m
2 2 2 2 2 2 21
2
1
sin
sin
sin
1
The equation in spherical coordinates equations: azimuthal horizontal radialHydrogen atom 6
The boundary conditions generate quantum numbers
Asymuthal equation:
2
m=0,±1, ±2, ±3, … Horizontal equation:
Square-integrable l=0, 1, 2, 3, … m=-l,-l+1,…,0,…,+l Radial equation: R(r) Square-integrable n=1, 2, 3, … l=0,1,…,n-1 2 2 2 41
2
n
R
n
e
E
H
Energy of the hydrogen atom 2 1
4
109677
2
e
cm
R
H
Rydberg constant
2 2 1 0 43
.
109737
2
4
cm
e
m
R
e
Hydrogen atom 7
The wavefunctions of the H atom
nlm(
r
,
,
)
R
nl(
r
)
Y
lm
,
Radial functions: 0 2 5 0 2 3 0 2 3 2 0 21 2 0 0 20 0 10 6 2 1 ) ( 2 2 2 1 ) ( 2 ) ( a Zr a Zr a Zr re a Z r R e a Zr a Z r R e a Z r R a0 = 0,529 Ǻ = 0,529 · 10-10 m Bohr radius -0.5 0 0.5 1 1.5 2 2.5 0 5 10 15 R10 R20 R21 a0Hydrogen atom 8
Radial probability density: R2(r) r2
Volume element: dV = dx dy dz = r2 sinθ dr dθ dφ
-0.1 0 0.1 0.2 0.3 0.4 0.5 0.6 0 2 4 6 8 10 12 14 (R10*r)^2 (R20*r)^2 (R21*r)^2 Notice: For l=n-1 there is a single maximum at r=n2*a 0 Normalization integral:
0 0 2 0 2 2 2 2 0 0 2 0 21
sin
,
sin
,
,
nlmr
r
dr
d
d
R
r
r
dr
Y
lmd
d
[a0]Hydrogen atom 9
Qualitative graphs of orbitals of type: s, p, d
s
pz py px
dx2-y2 dxy dxz
Hydrogen atom 10
Linear combinations of atomic orbitals Atomic orbitals i a Zr p i a Zr p s a Zr p s a Zr s s a Zr s e re N e re N a Z N re N a Z N e a Zr N a Z N e N sin 2 1 sin 2 1 4 1 cos 2 4 1 2 1 0 0 2 5 0 2 3 0 2 3 0 2 2 1 21 2 2 211 0 2 2 2 210 0 2 2 0 2 200 0 1 1 100
0 0 0 0 0 0 2 2 2 2 2 2 2 2 2 2 2 2 1 21 211 1 21 211 sin sin 2 sin 2 cos sin 2 sin 2 2 2 1 a Zr p a Zr p i i a Zr p y a Zr p a Zr p i i a Zr p x ye N re N i e e re N p xe N re N e e re N p i Spin
The Stern-Gerlach experiment
The beam of silver atoms passing through the magnetic field Electron configuration of silver:
Ag: 1s2/2s22p6/3s23p63d10/4s24p64d10/5s1 ms = +½ ms = -½ magnet Spinorbital s s nlm m nlmm
State of an electron α βIndistinguishable particles
a,b – particles 1,2 - detectors a b 2 1Probability of detecting different particles P1=|φa(1) φb(2)|2
P2=|φa(2) φb(1)|2
If particles identical P1 = P2 , then: φa(1) φb(2) = ± φa(2) φb(1) The particles can interfere with each other.
Indistinguishable particles
The amplitude of interference of identical particles:
Bosons φa(1) φb(2) + φa(2) φb(1) integer spin
Fermions φa(1) φb(2) - φa(2) φb(1) half-integer spin
The wavefunction for fermions is antisymmetrical with respect to permutation: Φ(1,2,3,…) = - Φ(2,1,3,…)
If two fermions occur in the same state1=2, thus φa(1) φb(1) - φa(1) φb(1) ≡ 0 It is the content of the Pauli exclusion principle.
The wavefunction for bosons is symmetrical.
Multielectron atoms
7s
7p
6s
6p
6d
5s
5p
5d
5f
4s
4p
4d
4f
3s
3p
3d
2s
2p
1s
Electron shells: n = 1,2,3,… → K,L,M,… l = 0,1,2,…→ s,p,d,… Hund’s rule:For a given electron configuration, the lowest energy term is the one with the greatest value of spin multiplicity
Multielectron atoms
The electronic term 2S+1L J
2S+1 means multiplicity, where S is the total spin.
How to determine the values of L, J, S ? J = L+S, L+S-1, … , |L-S| The carbon atom electronic configuration 1s2 2s2 2p2
Closed shells give the total spin S = 0
l1 l2 s1 s2 m1 m2 ML L MS S 1 1 +½ -½ 1 1 2 2 0 0 ½ ½ 1 0 1 1 +1,0,-1, 0 1 ½ ½ 1 -1 0 0 +1,0,-1, 0 0 +½ -½ 0 0 0 0 ½ ½ 0 -1 -1 +1,0,-1, 0 +½ -½ -1 -1 -2 0 Terms: 3P 2, 3P1, 3P0, 1D2, 1S0
Helium atom1
12 2 2 2 1 2 2 2 2 2 2 2 2 2 2 2 2 1 2 2 1 2 2 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ˆ r e r e r e z y x m z y x m z y x M H e e j j j j 12 2 2 2 1 2 2 2 1 2 2 2 2 2 2 2 ˆ r e r e r e m m M H e e j j 12 2 2 1 2 2 2 2 ˆ r e r e m H i i i e e
The electronic Hamiltonian in the
approximation of the infinitely heavy nucleus
1,2 1
12 2 The one-electron approximation
1 1
1 1 11
Spinorbital = orbital * spin_function
1,2
2,1 1 2 1 2 1 , 2 2 1 2 1 2 , 1 1 2 2 1 1 2 2 1 Antisymmetrized multi-electron function
H
i i E
i r e m i H n n n i i e e ˆ 2 2Helium atom 2
1,2
1,2 1,2
1 2
1 2
2,1 2 1 2 , 1 1 , 2 2 1 2 1 2 1 2 , 1 1 2 2 1 1 2 2 1 a a s s Spinorbital function = orbital function * spin function
Symmetry of the orbital function
1 2 1 2
2,1 2 1 2 , 1 1 , 2 2 1 2 , 1 1 , 2 2 1 2 , 1 1 , 2 2 1 2 1 2 1 2 , 1 s s s s s s a a Symmetry of the spin function
2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 1 2 , 1 2 1 2 1 2 1 2 1 2 1 2 1 2 , 1 1 2 2 1 triplet 1 2 2 1 singlet and The singlet (S=0) and triplet (S=1) functionsMultielectron atoms
1 1 1 2 1 2 2 2 ˆ n i n i j ij n i i i e e r e r ne m H
2 1 2 1 2 1 2 1 2 , 1 2 2 1 1 2 1 1 2 2 1 2 1 Determinant form of the electron function for the helium atom
n n n n n n n n ... 2 1 ... ... ... ... ... 2 1 ... 2 1 ,..., 2 , 1 2 2 2 1 1 1 ! 1 The antisymmetrized function for the n electron system fulfills the Pauli exclusion principle
EHF : the Hartree-Fock energy – the lowest energy in the frame of one-electron approximation
Variational method
How to solve a Schrödinger equation when the exact solution is not possible? We search for a trail function Φ which gives the lowest ground state energy.
dV
S
dV
H
H
c
dV
dV
H
E
H
j i ij j i ij N i i i
* * 1 * *ˆ
ˆ
ˆ
If Φ is the same as ψ, then ε is equal to E0.If Φ is an approximation of ψ, then ε is higher than E0. Linear combinations method:
The best trial function Φ is searched as a linear
combination of functions φi, which form a set of basis functions. ε is minimized with respect to coefficients ci:
H
c
H
S
dla
i
N
c
i j ij ij j ii i
0
1
,...,
N
i
dla
c
i
0
1
,...,
The variational method for a particle in a box (1)
x c
x c
x x a x a x x a x a x 2 2 1 1 2 2 9 2 7 1 630 30 The basis functions φ1 i φ2 are normalized, thus
S11=1 i S22=1.
The set of secular equations:
0
0
22 2 21 21 1 12 12 2 11 1
H
c
S
H
c
S
H
c
H
c
The necessary conditions for the existence of non-trivial solutions:
0 0 22 12 12 11 21 12 21 12 22 21 21 12 12 11 H S H S H H S S S H H H S H S H H
The normalization of the function Φ(x):
1 2 1 2 2 1 2 2 2 1 2 1 2 1 2 2 2 2 2 1 2 1 2 2 2 1 1 2 *
S c c c c dx c c dx c dx c dx x c x c dx x dx x x The variational method for a particle in a box (2)
0
0
22 2 12 1 12 2 11 1
H
c
S
H
c
S
H
c
H
c
0
22 12 12 11
H
S
H
S
H
H
S
H
H
c
c
S
c
c
c
c
12 11 1 2 2 1 2 2 2 12
1
S
H
H
H
S
S
H
H
H
S
H
H
H
H
S
H
H
S
H
H
H
H
H
H
S
S
H
H
H
H
H
H
S
H
H
H
S
S
H
H
H
12 22 11 2 2 12 22 11 2 1 12 22 12 11 22 11 2 12 2 22 11 2 12 22 11 2 2 12 22 11 2 12 22 11 12 22 11 2 2 2 12 22 112
1
2
1
2
1
2
1
4
4
1
4
2
0
2
1
0
For every calculated energy ε1 or ε2 the set of equations on coefficients c1 i c2 is solved.
The variational method for a particle in a box (3)
The calculation of integrals :
14 21 3 140 20 70 84 35 21 30 7 1 2 1 5 3 4 1 21 30 7 6 3 5 3 4 21 30 3 3 630 * 30 630 30 0 7 6 5 2 4 3 7 0 3 2 2 3 3 0 7 2 2 9 5 21 12
a a a x x a x a x a a dx x ax x a a x a dx x a x a x a x a S S S
2 2 2 2 0 5 4 3 2 2 3 7 2 0 4 3 2 2 3 2 2 3 7 2 0 2 2 2 0 7 2 2 2 9 2 2 2 5 12 21 2 2 5 12 6 3 14 1 21 30 2 5 12 4 24 3 14 2 2 21 30 2 12 12 2 12 12 2 21 30 2 12 12 2 630 * 30 2 630 2 30 a m a m x x a x a x a a m dx x ax x a ax x a x a a m dx x ax a x ax a m dx x a x a dx d m x a x a H a a a a
2 2 2 2 0 5 4 3 2 7 2 0 4 3 2 2 0 7 2 5 2 2 2 2 2 9 21 21 2 2 5 2 1 3 2 21 30 2 5 2 4 4 3 2 21 30 2 2 2 21 30 2 30 2 630 a m a m x x a x a a m dx x ax x a a m dx x a x a dx d m x a x a H a a a
The variational method for a particle in a box (4)
The calculation of integrals :
14 21 3 S 2 2 21 12 21 2 2m a H H 2 2 0 2 2 9 2 2 2 2 2 9 22 2 2 0 5 2 2 2 5 11 12 2 630 2 630 10 2 30 2 30 a m dx x a x a dx d m x a x a H a m dx x a x a dx d m x a x a H a a
The set of secular equations:
0 12 21 2 21 2 10 0 ) 12 ( 14 21 3 21 2 0 ) 14 21 3 21 2 ( 10 14 21 3 14 21 3 2 1 2 1 c c c c
4 3,295017884
*(28/2) 102,13025038 869719621 , 9 ) 2 / 28 ( * 295017884 , 3 4 295017884 , 3 7 / 76 36 * 28 / 1 * 4 16 0 36 4 28 1 0 21 * 4 12 * 10 14 / 21 * 3 * 21 * 2 * 2 12 10 196 21 * 9 1 2 1 2 2 A solution:The integrals for energy
in units of 2
2
2ma
The variational method for a particle in a box (5)
Calculation of the linear combination coefficients:
2 1 1 2 1 2 1 1 2 1 2 1
19882025
,
0
80405626
,
0
19882025
,
0
80405626
,
0
14
/
21
*
2
*
247271562
,
0
*
2
247271562
,
0
1
1
247271562
,
0
14
/
21
*
3
*
869719621
,
9
21
*
2
869719621
,
9
10
869719621
,
9
c
c
c
c
c
c
c
S
H
H
c
c
S
c
c
c
c
12 11 1 2 2 1 2 2 2 12
1
The exact value of energy E1 for a particle in a box [in units of ]
1 1 2 1 9,869604401 E E
2 2 2ma The variational method for a particle in a box (6)
A graph of the functions:
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 0 0.5 1 1.5 sin f1 f2 f1+f2
The function sin(x) and the linear combination of functions φ1 and φ2 overlap in a scale of the graph
The Hartree-Fock method for an atom
1 1 1 2 1 2 2 2 ˆ n i n i j ij n i i i e e r e r Ze m H
n n n n n n n n ... 2 1 ... ... ... ... ... 2 1 ... 2 1 ,..., 2 , 1 2 2 2 1 1 1 ! 1
i
i
i
p
n
F
ˆ
p
p
p
1
,
2
,
3
,...,
p i p i p i p lub
1 1
2
2
1 ˆ 1 2 2 1 1 ˆ 2 1 ˆ 1 ˆ 1 ˆ 1 ˆ 1 ˆ 2 12 2 * 2 12 2 * 1 2 1 2 j i j i i j j i A A A e dV r e K dV r e J r e Z m h K J h F
One-electron operator Two-electron operators: Coulomb Exchange The orbital energyUnrestricted Hartree-Fock method (UHF)
pi
pi
pi
p
or
where: φp is real, and numbers of electrons with spin α and β are not equal Used for the open-shell systems (atoms or molecules)
(different orbital energies for spins α and β)
A form of the graph
Restricted Hartree-Fock (RHF)
Even number of electrons, equal number of electrons of spin α and β. The number of spinorbitals is twice as many as that of occupied orbitals.
i
i
i
i
i
i
p p p p
2 12 The number of spinorbitals is equal to
the number of electrons, wheras each orbital is occupied by two electrons.
LUMO (Lowest unoccupied molecular orbital)