ROCZNIKI POLSKIEGO TOWARZYSTWA MATEMATYCZNEGO Séria I: PRACE MATEMATYCZNE XXVI (1986)
H
e l e n aM
u sie l a k(Poznan)
Converse type inequalities for averaged moduli
of smoothness in Orlicz spaces generated by concave functions In [1] there was obtained a converse type inequality in generalized Orlicz space If2n generated by a convex (^-function, estimating the averaged modulus of smoothness in lf2n of order к for a bounded, measurable, 2 k - periodic function / by means of best one-sided approximations of / with trigonometric polynomials. Here, we obtain an analogous inequality in case of a real Orlicz space lf2n generated by a concave strongly s-convex (p- function with 0 < s ^ 1.
1.1. A function (p: R+~>R, is called s-convex with an se(0, 1) if (p{ocu + l3v) ^ as <p(u) + (p(r) for all u, v ^ 0, a, /? ^ 0, such that cts + fis — 1.
A function (p: R + -» R+ will be called strongly s-convex with an se(0, 1) if the function ф(и) = (p(ul/s) is convex. It is easily seen that a strongly s- convex function is s-convex. Obviously, if q> is strongly s-convex with an se(0, 1) and 0 < p ^ s, then (p is also strongly p-convex. Let us remark that if a (^-function (see [3], 1.9) is convex, then it is superadditive, and if it is concave, then it is subadditive. If (p satisfies condition (d 2) for all и ^ 0, i.e.,
<p(2u)/<p(u) is bounded for и ^ 0, then we shall write ф{и) — sup [<p (uv)/(p (i;)] ;
v>
0we have ф (м) < x for all и ^ 0. If q> is strongly s-convex (s-convex) and satisfies (Л2), then ф is strongly s-convex (s-convex), too.
An s-convex (^-function q> defines an s-convex modular M / ) = iv { \f(t)\)d t
0
in the space of measurable, 27r-periodic functions f generating the Orlicz space
Цт = {f- Q«,W) < 00 for some X > ° l ’ with an s-homogeneous F-norm
ll/IIJ = inf \u > 0: ^ ( u _1/s/ ) ^ l |
(see [3]).
1.2. For any 2я-periodic f one defines
£ ( - 1 r m( k) f { t + mh),
m= 0 W
cok(/, x; 5) = sup{|d{/(i)|: t, t + k h e lk0{x)}, where
/J(x) = ( x —jk ô , x + ^kô}, for ô > 0, к = 1 , 2 , . . . , and arbitrary real x.
In the case of measurable bounded f (ok{f, •; <$) is also measurable (see [5], p. 28). Thus, for such functions / we may introduce the averaged modulus of smoothness of order к in If2n:
S) = ||cok(f, •; Э Д
and a modular averaged modulus of smoothness of order к in If2n:
* * (/; <5) = e A ^ k if, •; <5))-
The modulus xk possesses the same properties as given in [1], Theorem 3, with obvious modifications sprung from the fact that in our case cp does not depend on the parameter.
13. P roposition . Let (p be a concave, strongly s-convex (p-function, 0 < s ^ 1, satisfying condition (A2) for all и ^ 0, and let
, , , <p(uv) ф(и) = sup——
t>> 0 <p(v) ф (u) = ф (u(2r 1)/2)
with an integer r ^ ( s + 2)/2s. Let 0 < kS^oc/n, where a > 0. Then the following inequalities hold for an arbitrary trigonometric polynomial T„ of
degree ^ n:
т1(тп-,& )< с.,геЛк»?т<к)) and
т,(Т„; Й) < max(C> r, 1)(W)**||7<%, where Ca r is a positive constant.
P ro o f. Following the notation of [2], Theorem 2, we shall write 2 m + 1
t = t(2r ln) 1 m
2rn
■k ,where m = 0, 1 ,..., 2r 1 n — 1. Then, applying Lemma 2 from [4], formula
(1.7), to the fcth derivative T^k) of the trigonometric polynomial Tn of degree
^ n, we obtain
\ n k)(t)\ ^
2rn~
1m= 0 I \ n k)(tj\ sin j n ( f - r j n sin — rm)
2 r - 1
2rn — 1
m= 0 where
Dr,n(t) sin j nt \ 2r 1
n sin j t J (K Un(t))i2r~l)12 >
with K ln given in [2], Lemma 2.
Now, we apply the formula
t + h H'l+A wm - i + h
AkhT„(t) = A\~n J { J ...( J T}m)(wm)dwm)...dw 2}dw1, m ^ k
f W1 wm~ 1
(see [6], p. 150), in the case m = k, obtaining
t + h w i + h wk - i + h
Akh T„(t) = J { J ...( J 7l k)(wk)dwk)...d w 2}dwl .
t V V J Wfc-1
Hence we have for t, t + k h e lk6{x)
x + kô/2
\AkhT M < m k~i j \m k](u)\du
x - k ô / 2
2rn — 1 x + kô/2
<(kô)k~l X |7?>(tJ J \DrJ u - t m)\du.
m = 0 x — kô/2
Thus,
2rn — 1 x + kô/2
( o M , x ; 6 ) ^ ( k S r l X |îï‘’( t j f
m = 0 x - k ô / 2
Hence, by subadditivity of (p and the definition of ф, we have
2n 2rn— 1 x + kô/2
if ( Г, ; 5) < f v - 1 X 17?> (tJI f |Д,,„ (u - rJ|Ai} dx
0 m= 0 x — kô/2
2n 2 rn — 1 x + kô/2
X <»>!(^)‘ |7Α,( U I( ^ ) - 1 f I D , J u - l J \ d u ) d x
0 m= O x - k ô / 2
2rn - 1 2
kx + kô/2
X «> ( \DrJv)\dv}dx,
m = О Ь x — kô/2
Prace Matematyczne 26.2
because Drn(u) is 2л-periodic. Denoting
A4 f ,n , Ч| /2л; kô 2n(j+ \) k ô \\
M j t k
= max< |Д.>и(м)|: u e ( - — y , ---+ y we obtain
2 tc
jc + J k ^ / 2Ф 1
0 kô x —kô/2
2тт n ^
\ D r . n ( v ) \ d v } d x ^ —
X
ф ( М ]гк) ../= «
But 0 ^
k ô^ oc/n, and so
M j t k^ Ca/(/ + l)2r 1 for every
j ,where Ca > 0 is independent of
j(see [6], p. 151). By s-convexity of
фwe thus have
ф ( М и ) ^ ф ( С а
1 1
ü + i p - n ^ ' ^ ^ ÿ + u 2’
and so
2 r"~1 2 tü 00 1
n j = i2
m= 0
я2 ___ 271 2Г"~1
= ~ т Ф { С а ) ~
£ <jo((^)k|7jfc,(OI}- 6 n ,„e0
Now, denoting = x,- = 2 tc //JV for j — 0, 1, 2, ..., iV—1, we have tj — x f r,l)
= n/2r n. Hence, defining
Q%(Tn) = ~ sup J] «pflr^x + jc,)!)
* 7 = 0
(see [2], 2), we get
2 k 2r”_1
62 ; n((kS)k T<k>)>— x <?{(/d5)w>(o)i}.
^ П 7 = 0 Hence
тГ(Т„; 5) ^ и 2 Ф { С , ) Т е ^ ( ( к 0 ) к V k>)- Consequently, applying [2], Theorem 2, we get
т ? (Т „ ;0 )а и 2Ф(С.)2'2г$(1 + 2жп/2' n) e„ ((kS)k 7?>)
= C „ e„((fa5)‘ T'k>), where Cxr = 5 it2
ф(CJ 22r ф (1 + 2n/2').
Let us write Car = max(Ca ,, 1); then
Qq> ) < - J - t U T . ; S) « e„((fa5)‘ 72**).
Taking in this inequality TJulls in place of Tn, where и > 0, we obtain
2.1. Now, we shall give an estimation of the modulus xk by means of one-sided approximations.
The best one-sided approximation in lf2n of a bounded, real-valued measurable, 27i-periodic function / by means of trigonometric polynomials of degree ^ n is defined as
where H + (/) is the set of trigonometric polynomials P of degree < n for which P { x ) ^ f{ x ) in <0, 2тг> and H~ (/) is the set of trigonometric polynomials Q of degree ^ n for which f (x) ^ Q(x) in <0, 2тг) (see [5], p.
242). Arguing as in [1], Theorem 7, it is easily shown that for every n there exist trigonometric polynomials P * e H ^ (f) and Q * e H ~ (f) such that
£„(/) = IIP*'-<2*11;.
2.2. T heorem . Let tp be a concave, strongly s-convex (p-J'unction independent of the parameter, where 0 < s ^ 1, satisfying condition (A2) for all и ^ 0. Let f be a bounded, measurable, 2n-periodic function. Then there holds the inequality
for n — 1, 2, 3, ..., with a constant CkrS > 0 depending on к and s.
P roof. We choose P * e H f( f) and Q * e H ~ (f) so that £ „ (/) = ll^î —ÔÎIIJ, л = 1,2, ... Arguing as in the proof of [1], Theorems 3 and 1 (3), we obtain for <5 > 0
By Proposition 1.3 applied to к — 1 and T„ — P* — Q* with a = 4n, r being the least integer satisfying the inequality r ^ ( s + 2)/2s, we obtain
Hence
E n( f ) = inf{||P-Q||‘ : Q e H ~ (/)},
But, by [2], Theorem 3, there is a constant C > 0 such that ll(J>? - e ? ) #IIJ < Crf\\P*-Q*\\i = Crf Ën(f).
Hence
T i ( P * - Q * ; ô ) ^ C maix(Catrt l)ôsnsË„(f) for 0 < S ^ 4 n / n . Consequently,
4 ( / ; <5K тк (P* ; (5) + Tk (e* ; Ô) + Cl En(/) for 0 < <5 ^ 4n/n, where Cl = [2skC max(Car, 1)(4л)*+1] 2b .
Now, adopting the same notation as in the proof of [1], Theorem 3:
U0(x) = P f(x )-P $ (x ), Uv(x) = PJv(x )-P J v -iW , v = 1, 2, ...
we have
m
^ < Z т* ( ^ ; <5).
v = 0
Applying Proposition 1.3 with a' = 4кк to the polynomial Uv of degree ^ 2V and then [2], Theorem 3, we obtain
Tk(U v; ô) ^ max(C«,„ l)(k<5)kl t / < %
^ C2 (k<5)ks 2ksv || 17V||* for 0 < <5 sc 4 tt / 2v,
where C2 = Ckmax(Catr, 1). Hence, arguing as in the proof of [1], Theorem 3, we get
m
ч(Р*2„;б) * z c 2{ k s r £ 2tovi|(7v||j,
v = 0
m
s:2C2(fa5)“ (£0(/) + I 2‘" £ ,,_ ,(/))
v — 1
for 0 < <5 ^ 4n/2m. Taking into account an analogous inequality for T*(@2m;<5)> we thus obtain
xk(f;S)^4C2(kSr(Ë0(n+ I 2*"Ê m , (/)) + C, £ ,„ (/) v= 1
for 0 < 5 ^ 4n/2m.
Now, it is easily seen that
> V - 1
2favÊ2,_ 1( / ) 2 ' 2ta 2‘" Ё 2>- , ( / ) 2 - ‘* -‘
Hence, taking C, = max(22ftï, 2*s+1), we get 2b ’ £ 2,_ 1( / K C J
for ks ^ 1, for ks < 1 .
Л***-1 £,(/)■
This implies
2 m — 1
тк( / ; й ) ^ 4 С 2(И)ь !Ёо(Л + 2‘*Ё ,(Л + Сз X мь _ г £»(Л} + с , £ 2, ( Л Д=2
2
m ~ 1 - 1< 4 C 2C3(fa5f !£0(Л + 2“ £ ,( Л + X ( v + i f - ‘ £ ,+ i ( f } +
V — I
+ Ct Ë2„ (f) for 0 < S < 4 7 i/2 " . Since Ê,,+1 (Л < £,(Л> we thus obtain
2m" i - l t k( / ; Ô K 12C2C3( ^ ) A s X (v+1
for 0 < <5 ^ 4 к / 2 т.
Now, let n be an arbitrary positive integer and let 2 m~ 1 ^ n < 2m; then тк ( / ; 2тс/и) ^ тк( / ; 4 n / 2 m)
i 2m -1 - l
« 1 2 C J C,(4tik)‘>-iS; X (.+ 1|‘- £ >( Л + С , £ г, Ш
2 V = 0
< 12C3 C3(4itfcf Jg"X (v + I f 1 ЕЛ Л + С, £„(/)•
r r
v= 0
It is easily calculated that
£ . ( Л < с * Т х (V+ i f - ‘ £ vm .
" v = 0
where
Thus,
C4
m ax(l, 2fcs) if Acs < 1,
1 if ks = 1,
ks if ks > 1.
4 \ f ; 2n
« 12C2 C3 (4 n * f 4
”x(V + i f - 1 ЁЛЛ + C, c 4 4
" x(V + i f - 1 ЁАЛ
n
v = 0
nv = 0
= % " Z ( v + if- ‘ £,a) П
у