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A SPECIAL CASE OF GENERALIZED HÖLDER FUNCTIONS

Maria Lupa

Institute of Mathematics, Czestochowa University of Technology Częstochowa, Poland

maria.lupa@im.pcz.pl

Abstract. In this paper some properties of a special case of generalized Hölder functions, which belong to the space ܹሾܽ,ܾሿ, are considered. These functions are r-times differenti- able and their r-th derivatives satisfy the generalized Hölder condition. The main result of the paper is a proof of the theorem that product of two functions belonging to the space

ܹሾܽ,ܾሿ also belongs to this space.

Keywords: Lipschitz condition, generalized Hölder condition, equivalency of norms

Introduction

In the paper we introduce a function space ,  and consider and prove some of its properties.

In the articles [1-4] the authors discussed Nemytskii operator determined on various function spaces (cf. also [5, 6]). For instance, it is shown there that in each function space , , , , ,  a generating function of this operator exists and is affine with respect to the second variable. A similar result is obtained in [7] for the , -space. These results are then applied in [8, 9] to prove the existence and uniqueness of the solution of a certain functional equation in , .

The space Wγ and its properties

Let [, ] be a closed interval, where ,  ∈ ,  < , ≔  − . We assume that the following condition is fulfilled

(Γ) : [0, ] → [0, ∞) is increasing and concave, γ(0) = 0, lim→ = 0, lim→ =  .

Definition 1.

Denote by ,  the set of all r-times differentiable functions, where  ∈ , defined on the interval ,  with values in , such that their r-th derivatives satisfy the following condition: there exists a constant  ≥ 0 such that

(2)

 − ()̅ ≤ | − ̅|, ̅,  ∈ [, ] (1) where  fulfils condition ().

Remark 1.

It is easily seen that [, ] contains the class of all r-times differentiable functions : ,  → , whose r-th derivatives satisfy the Lipschitz condition on [, ]. This class is denoted by  [, ]. Thus we have

 [, ] ⊂ [, ].

Remark 2.

Denote by  (0) the right derivative of γ at  = 0. By  we have 0 ≤ 0 ≤ +∞.

For  ∈ [, ] and by the condition  we obtain

 − ()̅ ≤ | − ̅| ≤  0| − ̅|, ̅,  ∈ [, ]

i.e.  fulfils an ordinary Lipschitz condition with the constant  =  0.

Thus if  ∈ [, ] and  0 is finite then  ∈  [, ]. In view of Remark 1 we get  ,  = [, ].

Therefore only the case  0 = +∞ is of interest.

Remark 3.

The functions of the form  = , where 0 < < 1,  ∈ [0, ], fulfil the assumption () and moreover  0 = +∞. Therefore the condition (1) is called the generalized Hölder condition or the  − Hölder condition.

Lemma 1.

If  ∈ ,  and  0 = +∞, then the functions  , where  =

= 0,1, … ,  − 1, fulfil the generalized Hölder condition with a function  and the constants  , = 0,1, … ,  − 1.

Proof.

By the condition  0 = +∞, we have  ≥  in a right neighbourhood of zero. Suppose that   ≥ . Then we have  ≥  for  ∈ 0, .

Let ( ) < . Define the function

  ≔ ,  ∈ [0, ] (2)

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It is easily seen that  fulfils the condition () and  ≤  () for  ∈ [0, ].

Moreover,  () ≥  for  ∈ 0, . Clearly, if a function  fulfils the generalized Hölder condition with the same function  such that ( ) < and with a constant

, then  fulfils the generalized Hölder condition with the function  , defined by (2), and the same constant .

Define

=  ≥ .

 ( ) < (3)

where  is defined by (2). Thus the functions ( ), where  = 0,1, … ,  − 1, fulfil the generalized Hölder condition with the function  defined by (3), i.e. for

̅,  ∈ [, ] we have

  − ( )̅ ≤  | − ̅| ≤  | − ̅|,  = 0,1, … ,  − 1.

This completes the proof.

Remark 4.

The space [, ] with the norm

‖‖ ≔ ∑    ()+#$ ሺೝሻ(|̅|)(ೝ)̅; , ̅%, ,  ≠ ̅& (4)

is a real normed vector space. Moreover, it is a Banach space ([5, 6]).

In the space [, ] we define the second norm by the formula

‖‖: =∑ sup∈, +

+ #$ ሺೝሻ(|̅|)(ೝ)̅; , ̅%, ,  ≠ ̅& (5) We will show the equivalence of norms (4) and (5).

Proposition 1.

The norms (4) and (5) are equivalent in [, ] and the following inequalities hold

‖‖ ≤ ‖‖≤ ‖‖ (6)

where

 ='(∑  ;∑ ( )  ) (7)

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Proof.

The inequality ‖‖ ≤ ‖‖ is obvious. For  ∈ [, ] define the constants

 ≔ #$ ሺೝሻ(|̅|)(ೝ)̅; , ̅%, ,  ≠ ̅&,

 ≔#$ ሺೖሻ|̅|ሺೖሻ̅; , ̅%, ,  ≠ ̅& ,  = 0,1, … ,  − 1.

Since for  ∈ [, ] the following inequalities hold sup

∈[,]() ≤  + ( )

sup∈[,] () ≤   +  ,  = 0,1, … ,  − 1, and by the mean value theorem we have

 ≤ sup

∈,   ,  = 0,1, … ,  − 1, thus we obtain

∈[,]sup  () ≤   +    + ⋯ +   +  ( ) In view of above inequalities we have

‖‖≤∑ sup∈, +

+ ∑    ∑  +(( ) ∑  + 1). In the case ( ) ≥ we obtain

( ) ∑  + 1≤∑ ( )  , then

‖‖≤∑ ( )  ‖‖.

In the case ( ) < we have

( ) ∑  + 1≤∑  , therefore

‖‖ ≤∑  ‖‖.

In view of (7) we obtain inequality (6). This completes the proof.

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Proposition 2.

If the function * and + belong to [, ], then their product * ∙ + also belongs to this space and there exists a constant > 0 such that

‖* ∙ +‖≤‖*‖ (8)

where

= max,,- , = max

 ,…, .‖+‖; sup

[,]+() + 2 sup

[,]+( )/

- =0

( )1



 ,…, max .0

( )1

 ‖+‖; sup

[,]+() + 2

( )sup

[,]+( )/

Proof.

For *, + ∈ [, ] we have

(*+) − (*+)̅ =

=∑ ( )*+ − ∑ (  )*̅+̅

   ≤

≤ sup

∈,|*| + − +̅ + +∑ () sup

∈,*

 + − +()̅ +

+∑ () sup

∈,+

   * − *̅ + sup,|+| * − *̅

Let  ,,  = 0, … ,  − 1, denote Lipschitz constants of the functions *() and + respectively, and by ,  denote  −Hölder constants of the functions *() and +() respectively. Put

2: = sup

,* ,  = 0, … , , 3: = sup

,+ ,  = 0, … , .

Thus by Lemma 1 we get

(*+) − (*+)̅ ≤ 2 | − ̅| + ∑ ( )2

  | − ̅| + +∑ ( )3

   | − ̅| + 3 | − ̅|, and by definition (3) of function  there is * ∙ + ∈ [, ].

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Using mathematical induction we prove the inequality (8).

For  = 1 we have

‖* ∙ +‖≤ sup

,|*| sup

,|+| + sup

,|*| sup

,|+ | + sup

,|* | sup

,|+| + + sup|* + + *+  − * ̅+̅ − *̅+′(̅)|

(| − ̅|) ≤

≤ sup

, |*|(sup

,|+| + sup

,|+′|) + sup

,|* | sup

,|+| + + sup

,|*| #$|+′ − +′̅|

(| − ̅|) + sup

,|+| #$|*′ − *′̅|

(| − ̅|) +

+ sup

,|* | #$|+ − +̅|

(| − ̅|) + sup

,|+ | #$|* − *̅|

(| − ̅|)

where supremes of the above rational expressions are for , ̅%, ,  ≠ ̅. (In the next inequalities in this proof the same notations are used).

If   ≥ then the following inequalities hold the function +:

#$|+ − +̅|

(| − ̅|) ≤#$|+ − +̅|

| − ̅| ≤ sup

,|+ | and the same for function *. From the above we obtain

‖* ∙ +‖≤ sup

, |*| .(sup

,|+| + sup

,|+ | + #$|+′ − +′̅|

(| − ̅|) /+ + sup

,|*′|(sup

,|+| + 2 sup

,|+ |) + #$|*′ − *′̅|

(| − ̅|) sup

,|+| ≤

≤‖*‖' .‖+‖; sup

,|+| + 2 sup

,|+ |/ = , ‖*‖

If   < , by (3) we have the following inequalities

#$|+ − +̅|

(| − ̅|) ≤#$|+ − +̅|

| − ̅| ≤ sup

,|+ | and using definition (2) we obtain

#$|+ − +̅|

(| − ̅|) ≤

 sup

,|+ | (similarly for the function *).

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Therefore we have

‖* ∙ +‖≤ sup

, |*| .≤ sup

, |*|(sup

,|+| + sup

,|+ | + #$|+′() − +′(̅ )|

| − ̅| /+

+sup, |*′|(sup

,|+| + 2

 sup

,|+ |) + #$|*′ − *′̅|

(| − ̅|) sup

,|+| ≤

≤‖*‖' .‖+‖; sup

,|+| + 2

 sup

,|+ |/ = - ‖*‖

Putting

 = max, ,-  we get the inequality (8) for  = 1.

Let functions *, + have ( + 1)-order derivatives. Denote by ‖∙‖, the norm ‖∙‖ for the functions k times differentiable. Suppose that the inequality (8) is true for

 ≥ 1,  ∈ , i.e.

‖* ∙ +‖, ≤‖*‖,

where

= max, ,-  , = max

 ,…,  .‖+‖, ; sup

[,]+() + 2 sup

[,]+( )/

- =0

( )1



 ,…,  max .0

( )1

 ‖+‖, ; sup

[,]+() + 2

( )sup

[,]+( )/

We prove that the inequality (8) holds for ( + 1). We have

‖* ∙ +‖,  ≤ sup

,|*| sup

,|+| + ‖* ∙ + , +‖*′ ∙ +‖,

If   ≥ then the following inequality holds

‖* ∙ +‖,  ≤ sup

,|*| sup

,|+| +

+‖*‖, max

 ,…,  .‖+′‖, ; sup

[,]+( ) + 2 sup

[,]+()/ + +‖*′‖, max

 ,…,  .‖+‖, ; sup

[,]+() + 2 sup

[,]+( )/

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Since

‖*‖, ≤‖*‖,  ; ‖*′‖, ≤‖*′‖, 

(the same inequalities hold for the function +) thus we have

‖* ∙ +‖,  ≤‖*‖,  max

 ,…, .‖+‖,  ; sup

,+ + 2 sup

,+ / =

=,  ‖*‖, 

In the case   < we have

‖*‖,

( ) ‖*‖,  ; ‖*′‖, ≤‖*′‖, 

(the same inequalities hold for the function +). Therefore

‖* ∙ +‖,  ≤ sup

,|*| sup

,|+| + +‖*‖, 0

( )1

 ,…,  max .0

( )1

 ‖+′‖, ; sup

[,]+( ) + 2

( )sup

[,]+()/ + +‖*′‖, 0

( )1



 ,…,  max .0

( )1

 ‖+‖, ; sup

[,]+() + 2

( )sup

[,]+( )/ ≤

≤‖*‖,  0

( )1

 ,…,  max .0

( )1

‖+‖,  ; sup

[,]+() + + 2

( )sup

[,]+( )/ = -  ‖*‖, 

Putting =',  ,-   we get the inequality (8) for ( + 1). This com- pletes the proof.

Conclusions

In this paper some properties of the Banach space [, ] have been presented.

They will be applied in the forthcoming papers.

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References

[1] Matkowska A., On characterization of Lipschitzian operator of substitution in the class of Hölders functions, Scientific of Łódź Technical Uniwersity1984, 17, 81-85.

[2] Matkowski J., Functional equations and Nemytskii operators, Funkcialaj Ekvacioj 1982, 25, 127-132.

[3] Matkowski J., Form of Lipschitz operators of substitution in Banach space of differentiable func- tions, Zeszyty Naukowe Politechniki Łódzkiej, Matematyka, 1982, 25, 127-132.

[4] Matkowski J., Miś J., On a characterization of Lipschitzian operators of substitution in the space BV[a,b], Math. Nachr. 1984, 117, 155-159.

[5] Appell J., Banaś J., Merentes N., Bounded Variation and Around, De Gruyter Studies in Non- linear Analysis and Applications, Volume 17, Würzburg 2014.

[6] Appell J., Zabrejko P.P., Nonlinear Superposition Operators, Cambridge University Press, Cam- bridge-New York-Port Chester-Melbourne-Sydney 1990.

[7] Lupa M., Form of Lipschitzian operator of substitution in some class of functions, Zeszyty Naukowe Politechniki Łódzkiej, Matematyka, 1990, 21, 87-96.

[8] Lupa M., On solutions of a functional equation in a special class of functions, Demonstratio Mathematica 1993, XXVI, 1, 137-147.

[9] Lupa M., Wγ - solutions of linear Iterative Functional Equations, Demonstratio Mathematica 1994, XXVII, 2, 417-425.

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