BANACH CENTER PUBLICATIONS, VOLUME 37 INSTITUTE OF MATHEMATICS POLISH ACADEMY OF SCIENCES
WARSZAWA 1996
THE DOUADY–EARLE EXTENSION OF QUASIHOMOGRAPHIES
K E N - I C H I S A K A N
Dept. of Mathematics, Osaka City University Sugimoto, Sumiyoshi-ku, Osaka,
Japan
J ´ O Z E F Z A J A ¸ C
Institute of Mathematics, Polish Academy of Sciences Narutowicza 56, PL-90-136 L´ od´ z, Poland
Abstract. Quasihomography is a useful notion to represent a sense-preserving automor- phism of the unit circle T which admits a quasiconformal extension to the unit disc. For K ≥ 1 let A
T(K) denote the family of all K-quasihomographies of T . With any f ∈ A
T(K) we asso- ciate the Douady–Earle extension E
fand give an explicit and asymptotically sharp estimate of the L
∞norm of the complex dilatation of E
f.
Introduction. Let A
Tdenote the family of all sense-preserving automorphisms of the unit circle T . With any f ∈ A
Twe associate the Douady–Earle extension E
fwhich is a homeomorphic automorphism of the unit disc ∆ and has a continuous extension to f on the boundary T = ∂∆ (see [DE] and [LP]). If z ∈ ∆ and f ∈ A
T, then E
f(z) is the unique w ∈ ∆ such that
(0.1)
Z
T
f (ζ) − w 1 − wf (ζ)
(1 − |z|
2)
|z − ζ|
2|dζ| = 0.
Moreover, the correspondence f 7→ E
fis conformally natural in the sense that (0.2) E
h1◦f ◦h2= h
1◦ E
f◦ h
2holds for any f ∈ A
Tand all M¨ obius transformations h
1, h
2, which map ∆ onto itself.
1991 Mathematics Subject Classification: Primary 30C50; Secondary 30C55.
The second author is greatly indebted to the Committee of the Osaka City University Foun- dation for financial support and hospitality during his visit in Japan when this research was completed in a very fruitful cooperation with Professor Ken-ichi Sakan.
The paper is in final form and no version of it will be published elsewhere.
[35]
The property that a given f ∈ A
Tadmits a quasiconformal extension to ∆ is equiva- lent to the assumption that f is a quasihomography (see [Z1]). For K ≥ 1, we denote by A
T(K) the family of all f ∈ A
Tthat are K-quasihomographies (see Chap. 1).
Starting with an automorphism f of T , which is the boundary automorphism of a given K-quasiconformal mapping of ∆ onto itself, Douady and Earle proved that, given ε > 0, there exists δ > 0 such that K(E
f) ≤ 4
3+εfor 1 ≤ K ≤ 1 + δ (see [DE, Corollary 2]).
Their explicit estimate starts from 4 · 10
8e
35, for K near 1.
Making some refinements and using more subtle tools, Partyka obtained an asymptot- ically sharp estimate for K(E
f) (see [P1, Theorem 3.1]), improving the result of Douady and Earle for 1 ≤ K < 50. Using the notion of quasisymmetry for unit circle, intro- duced by Krzy˙z [K], he considered also, as the starting point, a given ρ-quasisymmetric automorphism f of T .
It is very natural from different points of view if we may extend an automorphism f of T that satisfies certain condition on T only, and next to study how particular properties of such an f effects the extension.
Rotation, but not conformally invariant notion of quasisymmetry of T , mentioned above, is meaningless in these considerations. This is mostly because neither there exists ρ ≥ 1 such that boundary values of M¨ obius automorphisms of ∆ are ρ-quasisymmetric (see [Z1, Example]), nor ρ-quasisymmetric automorphisms of T represent uniformly boundary values of K-quasiconformal automorphisms of ∆, for any K ≥ 1.
We assume that a given automorphism f of T is a K-quasihomography (≡ 1-dimen- sional K-quasiconformal mapping) of T , K ≥ 1. The family A
T(K), K ≥ 1, representing uniformly K-quasiconformal mappings, with the same K of necessity, is conformally invariant under composition and thus very natural with respect to the Douady–Earle extension.
Developing in Sect. 1 the argument of normal families in A
Tin a way related to the Douady–Earle extension and introducing necessary functionals, defined on families of K-quasihomographies of T , we estimate in Theorem 3 the L
∞-norm of the complex dilatation µ
Effor the Douady–Earle extension of a given K-quasihomography f of T , with K close to 1. In Corollary 3 we describe an asymptotically sharp estimate of K(E
f), expressed explicitly by (2.20), for K close to 1.
In order to be in contact with results mentioned above we give, in Theorem 2, a relation between some important families in A
T(K) and functions ρ-quasisymmetric on the unit circle.
1. Normal families in A
T. Let ∆ be the unit disc in the complex plane C and T =
∂∆ be the unit circle. We consider the family A
Tof all sense-preserving automorphisms of T as a subspace of the Banach space C
Tof all complex-valued continuous functions on T , with the supremum norm. In this section, we first discuss normality of certain subfamilies of A
T. As an application, we shall then show that some subfamilies of K- quasihomographies on T , which play an important role for our purpose, turn out to be families of ρ-quasisymmetric functions of T where ρ depends on K only.
For f ∈ A
T, we denote by E
fthe Douady–Earle extension of f to ∆.
Lemma 1. The functional E
f(0) is continuous on A
T. ([DE, Prop. 2]).
For every r, 0 ≤ r < 1, we denote by F
T(r) the family of all f ∈ A
Tsatisfying
|E
f(0)| ≤ r. A family F in A
Tis said to be a normal family if F is relatively compact in A
T. Thus a family F in A
Tis a normal family if and only if for any infinite sequence {f
n} in F , there exists a subsequence {f
nl} which converges to some f in A
T.
Lemma 2. Let F be a family in A
T. Then F is normal family in A
Tif and only if F is equicontinuous on T and there exists r, 0 ≤ r < 1, such that F ⊂ F
T(r), where F is the closure of F in the Banach space C
T.
P r o o f. We note that by the Ascoli–Arzela’s theorem, a family G in C
Tis a normal family in C
Tif and only if G is uniformly bounded and equicontinuous on T . Suppose that F is a normal family in A
T. By definition, it then follows that F is compact and F ⊂ A
T. Thus, by Lemma 1, there exists some f
0∈ F such that |E
f0(0)| = sup
f ∈F|E
f(0)|. Then F is equicontinuous and F ⊂ F
T(r), where r = |E
f0(0)|.
On the contrary, suppose that F is equicontinuous on T and that F ⊂ F
T(r) for some r, 0 ≤ r < 1. Then F is a normal family in C
T, that is, F is compact in C
T. Since F ⊂ F
T(r) ⊂ A
T, then F is a normal family in A
T. q.e.d.
For K ≥ 1, we denote by A
T(K) the family of all f ∈ A
Tsuch that (1.1) Φ
1/K([z
1, z
2, z
3, z
4]) ≤ [f (z
1), f (z
2), f (z
3), f (z
4)] ≤ Φ
K([z
1, z
2, z
3, z
4]) holds for every ordered quadruple of distinct points z
1, z
2, z
3, z
4∈ T , where
[z
1, z
2, z
3, z
4] = z
3− z
2z
3− z
1: z
4− z
2z
4− z
1 1/2is the real-valued cross-ratio of {z
1, z
2, z
3, z
4} (see [Z1]). Moreover, Φ
Kin (1.1) is the Hersch–Pfluger distortion function defined by
(1.2) Φ
K(t) = µ
−11
K µ(t)
where
π2µ(t) stands for the conformal modulus of ∆ \ [0; t], 0 ≤ t < 1. The function µ can be expressed in the form:
(1.3) µ(t) = K( √
1 − t
2)
K(t) , 0 < t < 1, where
K(t) = Z
π/20
(1 − t
2sin
2ϕ)
−1/2dϕ
is the elliptic integral of the first kind. Every f ∈ A
T(K) is called a K-quasihomography of T .
For every K ≥ 1 and r, 0 ≤ r < 1, we denote by A
T(K, r) the family of all f ∈ A
T(K) satisfying |E
f(0)| ≤ r. Obviously, A
T(K, r) = A
T(K) ∩ F
T(r). For a ∈ ∆, we put
(1.5) h
a(z) = z − a
1 − az .
Lemma 3. Suppose a
n∈ ∆ converges to e
iθ∈ T as n tends to infinity. Then the function h
an(z) converges to −e
iθuniformly on every compact set S in ∆ \ {e
iθ}, as n tends to infinity.
P r o o f. Let S be any compact set in ∆ \ {e
iθ}, and let c
0= dist(e
iθ, S). For any ε, 0 < ε < c
0, there exists n
0such that |a
n− e
iθ| < ε/2, for all n ≥ n
0. Then, for every z ∈ S, we have
(1.6) |1 − a
nz| ≥ |1 − e
−iθz| − |(a
n− e
−iθ)z| ≥ |e
iθ− z| − |a
n− e
−iθ| ≥ c
0/2.
For every z ∈ S and n ≥ n
0, it then follows from (1.6) that
|h
an(z) + e
iθ| ≤ |e
iθ− a
n| + |e
−iθ− a
n|
|1 − a
nz| ≤ 2ε/c
0.q.e.d.
Now we have the following
Theorem 1. For every K ≥ 1 and r, 0 ≤ r < 1, the family A
T(K, r) is compact in A
T(K).
P r o o f. Let A
◦T(K) be the family of all f ∈ A
T(K), K ≥ 1, normalized by f (z) = z for every z such that z
3= 1. As it is known, A
◦T(K) is compact in A
T(K) (see [Z2]).
Let {f
n} be an infinite sequence in A
T(K, r). Then there exist a
n∈ ∆ and ϕ
n∈ R, such that g
n:= e
iϕnh
an◦ f
nbelongs to A
◦T(K) for every n. Taking a subsequence, if necessary, we may assume g
n→ g ∈ A
◦T(K), a
n→ a
0∈ ∆ and e
iϕn→ e
iϕas n → ∞. By Lemma 1, E
gn(0) converges to E
g(0). If |a
0| = 1 and a
0= e
iθfor some θ ∈ R, then, since |E
fn(0)| ≤ r, Lemma 3 and conformal naturality of the Douady–
Earle extension imply that E
gn(0) = e
iϕnh
an(E
fn(0)) converges to e
i(ϕ−θ)as n → ∞.
This contradiction shows that a
0∈ ∆ and that f
n= h
−an◦ e
−iϕng
n(z) converges to f
0(z) := h
−a0e
−iϕg(z) ∈ A
T(K). Hence, by Lemma 1, f
0∈ A
T(K, r), and thus A
T(K, r)
is compact in A
T(K). q.e.d.
In view of Lemma 2, we can easily obtain the following:
Corollary 1. For every K ≥ 1 and r, 0 ≤ r < 1, the family A
T(K, r) is equicontin- uous on T .
Corollary 2. Let K ≥ 1 and let F be a family in A
T(K). Then F is a normal family (resp. compact ) in A
T(K) if and only if there exists some r, 0 ≤ r < 1, such that F is a subfamily (resp. a closed subfamily) of A
T(K, r).
For every z ∈ T and f ∈ A
T(K), K ≥ 1, we denote by θ
f(z) the angle of the arc on T directed counterclockwise from f (z) to f (−z). In this sense θ
f(z) = arg
f (−z)f (z)and we note that θ
f(−z) = 2π − θ
f(z). By continuity of f , there exists z
f∈ T such that
(1.7) θ
f(z
f) = min
z∈T
θ
f(z).
For every r, 0 ≤ r < 1, we define
(1.8) θ(K, r) := inf
f ∈AT(K,r)
min
z∈T
θ
f(z).
Lemma 4. For every K ≥ 1 and r, 0 ≤ r < 1, there exist f
0∈ A
T(K, r) and z
0∈ T
such that θ
f0(z
0) = θ(K, r).
P r o o f. By (1.7) and (1.8) there exist f
n∈ A
T(K, r), and z
n∈ T satisfying
(1.9) θ(K, r) = lim
n→∞
θ
fn(z
n) and
(1.10) θ
fn(z
n) = min
z∈T
θ
fn(z).
By Theorem 1, we may assume that f
n→ f
0∈ A
T(K, r) in A
T(K) and that z
n→ z
0∈ T as n → ∞. Then
(1.11) lim
n→∞
θ
fn(z
n) = θ
f0(z
0) and
(1.12) lim
n→∞
θ
fn(z
f0) = θ
f0(z
f0).
By (1.10) θ
fn(z
f0) ≥ θ
fn(z
n), then by (1.11) and (1.12) we obtain (1.13) θ
f0(z
f0) ≥ θ
f0(z
0).
By (1.7), (1.13), (1.9) and (1.11) we then have θ
f0(z
f0) = θ
f0(z
0) = θ(K, r). q.e.d.
Lemma 5. For every r, 0 ≤ r < 1, the correspondence K 7→ θ(K, r) is lower semi- continuous in 1 ≤ K < ∞. Moreover , the function θ(K, 0) is continuous at K = 1 and lim
K→1θ(K, r) = θ(1, 0) = π.
P r o o f. Let {K
n}, K
n≥ 1, be a sequence converging to K
0as n → ∞. Then, by Lemma 4, there exist f
n∈ A
T(K
n, r) and z
n∈ T such that θ
fn(z
n) = θ(K
n, r). By Theorem 1, we may assume that f
n→ f
0∈ A
T(K
0, r) and that z
n→ z
0∈ T as n → ∞.
In a way similar to the proof of Lemma 4, we have
(1.14) lim
n→∞
θ(K
n, r) = θ
f0(z
0) = θ
f0(z
f0) ≥ θ(K
0, r).
Therefore, lim
K→K0
θ(K, r) ≥ θ(K
0, r). Next, suppose r = 0. Then A
T(1, 0) = { f
θ: 0 ≤ θ < 2π }, where f
θ(z) = e
iθz. In particular, θ
f(z) = π for every f ∈ A
T(1, 0) and every z ∈ T . Hence, θ(1, 0) = π and (1.14) implies that lim
Kn→1θ(K
n, 0) = θ(1, 0) = π. q.e.d.
Following Krzy˙z [K], we say that f ∈ A
Tis ρ-quasisymmetric, ρ ≥ 1, if the inequality 1ρ ≤ |f (I
1)|/|f (I
2)| ≤ ρ
holds for each pair of open, adjacent arcs I
1, I
2⊂ T such that 0 < |I
1| = |I
2| ≤ π, where
| · | denotes the Lebesgue measure on T .
Denote by Q
T(ρ) the family of all ρ-quasisymmetric functions in A
T. It is worth while to mention that Q
T(ρ) is not conformally invariant and that quasisymmetric functions of T represent non-uniformly the boundary values of quasiconformal automorphisms of ∆ (see [Z2]). This and other properties makes ρ-quasisymmetry of T not closely related to quasiconformality of ∆, and technically similar to ρ-quasisymmetry of R only.
For K ≥ 1, we recall the distortion function λ(K) := Φ
2K(1/ √
2)/Φ
21/K(1/ √ 2),
where Φ
Kis given by (1.2). By Theorem 2.9 from [Z2, Chap. II], (1.7), (1.8) and Lemma 5,
we obtain the following:
Theorem 2. For every K ≥ 1 and r, 0 ≤ r < 1, there exists a constant ρ = ρ(K, r) such that A
T(K, r) ⊂ Q
T(ρ) and ρ ≤ λ(K)cot
2(θ(K, r)/4). In particular , lim
K→1ρ(K, 0) = 1.
2. The maximal dilatation of the Douady–Earle extension of f ∈ A
T(K).
Let K ≥ 1 and f ∈ A
T(K). We note that by (0.1) f ∈ A
T(K, 0) if and only if f satisfies Z
T
f (ζ)|dζ| = 0.
If f ∈ A
T(K, 0) then there exist a = a(f ) ∈ ∆ and ϕ = ϕ(f ) ∈ R such that
(2.1) e
iϕh
a◦ f ∈ A
0T(K),
where h
ais the function defined by (1.5), whereas a(f ) and e
iϕ(f )are uniquely determined by (2.1).
Define
(2.2) C(K) = sup
f ∈A0T(K)
sup
ζ∈T
|ζ − E
f(0)|
|f (ζ) − E
f(0)| .
Lemma 6. For every K ≥ 1, there exist f
K∈ A
0T(K) and ζ
K∈ T such that C(K) = |ζ
K− E
fK(0)|
|f
K(ζ
K) − E
fK(0)| .
Furthermore, C(K) is increasing and right continuous in 1 ≤ K < ∞. In particular , C(K) tends to 1 as K → 1.
P r o o f. For f ∈ A
0T(K) set
(2.3) l(f ) = sup
ζ∈T
|ζ − E
f(0)|
|f (ζ) − E
f(0)| . By the continuity of the correspondence ζ 7→
|f (ζ)−E|ζ−Ef(0)|f(0)|
, there exists ζ = ζ(f ) ∈ T such that the supremum in (2.3) is attained at this point. Hence, by (2.2) there exist f
n∈ A
0T(K) and ζ
n= ζ(f
n) satisfying
(2.4) lim
n→∞
l(f
n) = C(K) and
(2.5) l(f
n) = |ζ
n− E
fn(0)|
|f
n(ζ
n) − E
fn(0)| .
Taking a subsequence, if necessary, we may assume that ζ
n→ ζ
0, and that f
n→ f
0∈ A
0T(K) with respect to the supremum norm as n → ∞. Then, by Lemma 1, E
fn(0) tends to E
f0(0) as n → ∞. Hence, by (2.4) and (2.5), we have
(2.6) C(K) = |ζ
0− E
f0(0)|
|f
0(ζ
0) − E
fo(0)| .
By (2.2) the function C(K) is clearly increasing. Let K
0≥ 1 be fixed and let K
n& K
0. By (2.6), there exist ζ
Kn∈ T and f
Kn∈ A
0T(K
n) such that
(2.7) C(K
n) = |ζ
Kn− E
fKn(0)|
|f
Kn(ζ
Kn) − E
fKn(0)| .
We may assume that f
Kntends to f
I∈ A
0T(K
0), and ζ
Kntends to ζ
I∈ T as n → ∞.
From (2.7) it follows that
n→∞
lim C(K
n) = |ζ
I− E
fI(0)|
|f
I(ζ
I) − E
fI(0)| ≤ C(K
0).
This implies that lim
n→∞C(K
n) = C(K
0). Clearly, C(1) = 1 and thus lim
K→1C(K) =
1. q.e.d.
For K ≥ 1, define m(K) = sup
f ∈AT(K,0)|a(f )| and
(2.8) M (K) = max
0≤t≤1
[Φ
2K( √ t) − t]
where a(f ) is defined by (2.1) and Φ
Kis given by (1.2). Introduced by the second author functional M (K) was investigated in relation with certain functionals defined on families of K-quasihomographies of the real line and the unit circle T (see [Z1]). Surprisingly to both the authors, the following equality
M (K) = 2Φ
2√K
(1/ √ 2) − 1
was obtained by Partyka [P3]. This is a one of the truly few final results on special functions in quasiconformal theory, which may have some further consequences.
By Lemma 2.1 from [Z2, Chap. II] we have
Lemma 7. For each K ≥ 1 and f ∈ A
0T(K) the following inequality
(2.9) |f (z) − z| ≤ 4
√
3 M (K) holds for every z ∈ T .
Now we prove
Lemma 8. For every K ≥ 1, we have m(K) < 1. Moreover ,
(2.10) m(K) ≤ 4
√ 3 M (K)C(K).
In particular , m(K) → 0 as K → 1.
P r o o f. If f ∈ A
T(K, 0), then g := e
iϕ(f )h
a(f )◦ f ∈ A
0T(K). Furthermore, by (0.2), we have E
g(0) = −a(f )e
iϕ(f ), and thus |E
g(0)| = |a(f )|. Conversely, if g ∈ A
0T(K) and E
g(0) = b, then h
b◦ g ∈ A
T(K, 0). Thus, the equality g = h
−b◦ h
b◦ g implies that
|E
g(0)| = |b| = | − b| = |a(h
b◦ g)|. The above observation shows that
(2.11) m(K) = sup
f ∈A0T(K)
|E
f(0)|.
By Lemma 1, the correspondence f 7→ |E
f(0)| is continuous on A
T. Since A
0T(K) is compact in A
T, then (2.11) implies that there exists some f
K∈ A
0T(K) such that m(K) =
|E
fK(0)|. Since µ
−1(1) = 1/ √
2, by (2.8), (2.9), the last equality and Lemma 1, we then see that m(K) < 1 and that m(K) tends to 0 as K → 1.
Let f ∈ A
0T(K) and put a = E
f(0). We then obtain (2.12)
Z
T
ζ − a 1 − aζ |dζ| +
Z
T
f (ζ) − a
1 − af (ζ) − ζ − a 1 − aζ
|dζ| = 0.
Since
Z
T
ζ − a
1 − aζ |dζ| = 1 i
Z
T
ζ − a
ζ(1 − aζ) dζ = −2πa, it follows from (2.12) that
(2.13) |a| ≤ 1
2π Z
T
ω(ζ) (1 − |a|
2)
|ζ − a|
2|dζ|, where ω(ζ) =
|f (ζ)−ζ||ζ−a||f (ζ)−a|
. The right-hand side of (2.13) is equal to W (a), where W (z) is a harmonic extension of w(ζ) into ∆. By (2.9) and (2.13), we thus have
|a| ≤ max
ζ∈T
|ω(ζ)| = max
ζ∈T
|f (ζ) − ζ| |ζ − a|
|f (ζ) − a| ≤ 4
√ 3 M (K)C(K).
This, in view of (2.11), gives (2.10). q.e.d.
For f ∈ A
T(K, 0), we put
A = A(f ) = 1 2π
Z
T
ζf (ζ) |dζ|, B = B(f ) = 1
2π Z
T
ζf (ζ) |dζ|, C = C(f ) = 1
2π Z
T
f (ζ)
2|dζ|
and
(2.14) S(K) = 4
√ 3 M (K)C(K).
Lemma 9. For each K ≥ 1 and f ∈ A
T(K, 0) the following inequalities hold ; (2.15) |B| ≤ S(K), |C| ≤ 2S(K) + S(K)
2, |A| ≥ 1 − S(K)
2− S(K).
Moreover , the third estimate is essential for K ≥ 1 satisfying S(K) < ( √
5 − 1)/2.
P r o o f. Let f ∈ A
T(K, 0) and let g = e
iϕ(f )h
a(f )◦ f , b = −a(f )e
iϕ(f ). Then, g ∈ A
◦T(K), E
g(0) = b, and we see that
e
iϕ(f )f (ζ) = [g(ζ) − b]/[1 − bg(ζ)].
As in the proof of Lemma 8, we have
|B| = 1 2π
Z
T
ζe
iϕ(f )f (ζ) |dζ|
= 1 2π
Z
T
ζ g(ζ) − b 1 − bg(ζ)
|dζ|
= 1 2π
Z
T
ζ g(ζ) − b
1 − bg(ζ) − ζ − b 1 − bζ
|dζ|
≤ 1 2π
Z
T
|g(ζ) − ζ||1 − bζ|
|1 − bg(ζ)| · (1 − |b|
2)
|ζ − b|
2|dζ|
≤ 4
√ 3 M (K)C(K) = S(K).
Similarly, by Lemma 8, we obtain
|C| = 1 2π
Z
T
e
i2ϕ(f )f (ζ)
2|dζ|
= 1 2π
Z
T
( g(ζ) − b 1 − bg(ζ)
2− ζ − b 1 − bζ
2)
|dζ| + 2πb
2≤ |b|
2+ 2 2π
Z
T
g(ζ) − b
1 − bg(ζ) − ζ − b 1 − bζ
|dζ| ≤ S(K)
2+ 2S(K).
Since
1 2π
Z
T
ζ ζ − b 1 − bζ
|dζ| = 1 2πi
Z
T
ζ − b
(1 − bζ)ζ
2dζ = 1 − |b|
2, we have
|A| = 1 2π
Z
T
ζe
iϕ(f )f (ζ) |dζ|
= 1 2π
Z
T
ζ g(ζ) − b 1 − bg(ζ)
|dζ|
= 1 2π
Z
T
ζ g(ζ) − b
1 − bg(ζ) − ζ − b 1 − bζ
|dζ| + 2π(1 − |b|
2)
≥ 1 − |b|
2− 1 2π
Z
T
g(ζ) − b
1 − bg(ζ) − ζ − b 1 − bζ
|dζ| ≥ 1 − S(K)
2− S(K).q.e.d.
R e m a r k 1. For K ≥ 1 satisfying S(K) < ( √
5 − 1)/2, we have |A| > 0.
3. An estimation of the dilatation. For K ≥ 1 we define k
∗(K) = sup
f ∈AT(K,0)