F U N D A M E N T A MATHEMATICAE
152 (1997)
Correction to the paper
“The Bohr compactification, modulo a metrizable subgroup”
(Fund. Math. 143 (1993), 119–136)
by
W. W. C o m f o r t (Middletown, Conn.), F. Javier T r i g o s - A r r i e t a (Bakersfield, Calif.),
and Ta-Sun W u (Cleveland, Ohio)
Given a LCA group G and a closed subgroup N of its Bohr compactifi- cation bG, let r : G ³ G
+⊆ bG be the identity function (so G
+denotes G with the topology inherited from bG), and with π : bG ³ bG/N let φ = π ◦ r. The principal positive contribution of our paper [1] is Theorem 2.10, which asserts that every LCA group G strongly respects compactness in the sense that for every subset A of G and for every closed metrizable subgroup N of bG, the set φ[A] is compact (in bG) if and only if A·(N ∩G) is compact (in G). [This result generalizes a celebrated theorem of Glicksberg [3], which is in fact the case N = {1
G}.]
Crucial to our proof of Theorem 2.10 is Lemma 2.9, which is this special case: G is discrete.
We are indebted to Jorge Galindo and Salvador Hern´andez of Universitat Jaume I (Castell´on, Spain) for informing us that the proof given in [1] of Lemma 2.9 is misleading and perhaps incorrect. Accordingly, we herewith propose the following modification of the proof of that Lemma.
Let A ⊆ G with φ[A] compact. Since G ∩ N is compact (cf. [1](2.5)) it is enough to show that A itself is compact, i.e., is finite. Suppose instead that
|A| ≥ ω, let G
0be the subgroup of G generated by some countably infinite subset A
0of A, and define G
0= G ∩ (bG
0· N ) and A
0= A ∩ G
0; evidently from A
0⊇ A
0we have |A
0| ≥ ω. From bG
0= G
0bG⊆ bG
0· N and
b(G
0/G
0) = bG
0/bG
0⊆ (bG
0· N )/bG
0= N/(N ∩ bG
0) (cf. [4](5.33)) it follows that b(G
0/G
0) is metrizable, so that G
0/G
0is finite; hence G
0is
[97]