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(1)

Dirac Equation

Karol Kołodziej

Institute of Physics University of Silesia, Katowice

http://kk.us.edu.pl

(2)

Schr¨ odinger Equation

The Schr¨odinger equation i ~∂ψ(~r , t)

∂t = −~2

2m ∇~2ψ(~r , t) + V (~r , t)ψ(~r , t) can be obtained by substituting

E → i ~∂

∂t, p → −i ~~~

in a non relativistic formula for the total mechanical energy of a particle

E = ~p2

2m + V (~r , t).

The Schr¨odinger equation describes motion of a non relativistic spinless particle of mass m in a field of the force

F (~~ r , t) = − ~∇V (~r , t).

Karol Kołodziej Dirac Equation 2/44

(3)

Schr¨ odinger Equation

The Schr¨odinger equation i ~∂ψ(~r , t)

∂t = −~2

2m ∇~2ψ(~r , t) + V (~r , t)ψ(~r , t)

can be obtained by substituting E → i ~∂

∂t, p → −i ~~~

in a non relativistic formula for the total mechanical energy of a particle

E = ~p2

2m + V (~r , t).

The Schr¨odinger equation describes motion of a non relativistic spinless particle of mass m in a field of the force

F (~~ r , t) = − ~∇V (~r , t).

(4)

Schr¨ odinger Equation

The Schr¨odinger equation i ~∂ψ(~r , t)

∂t = −~2

2m ∇~2ψ(~r , t) + V (~r , t)ψ(~r , t)

can be obtained by substituting E → i ~∂

∂t, p → −i ~~~

in a non relativistic formula for the total mechanical energy of a particle

E = ~p2

2m + V (~r , t).

The Schr¨odinger equation describes motion of a non relativistic spinless particle of mass m in a field of the force

F (~~ r , t) = − ~∇V (~r , t).

Karol Kołodziej Dirac Equation 2/44

(5)

Schr¨ odinger Equation

The Schr¨odinger equation i ~∂ψ(~r , t)

∂t = −~2

2m ∇~2ψ(~r , t) + V (~r , t)ψ(~r , t)

can be obtained by substituting E → i ~∂

∂t, p → −i ~~~

in a non relativistic formula for the total mechanical energy of a particle

E = ~p2

2m + V (~r , t).

(6)

Schr¨ odinger Equation

The kinetic energy of a free particle is given by a non relativistic formula

E = ~p2 2m

and the Schr¨odinger equation in this case takes the form

i ~∂ψ

∂t = −~2 2m ∇~2ψ.

The squared module of the wave function|ψ(~r , t)|2 is interpreted asprobability density of finding the particle in the spatial volume element d3r = dx dy dz around the point ~r at the time t.

Karol Kołodziej Dirac Equation 3/44

(7)

Schr¨ odinger Equation

The kinetic energy of a free particle is given by a non relativistic formula

E = ~p2 2m

and the Schr¨odinger equation in this case takes the form i ~∂ψ

∂t = −~2 2m ∇~2ψ.

The squared module of the wave function|ψ(~r , t)|2 is interpreted asprobability density of finding the particle in the spatial volume

3

(8)

Schr¨ odinger Equation

The kinetic energy of a free particle is given by a non relativistic formula

E = ~p2 2m

and the Schr¨odinger equation in this case takes the form i ~∂ψ

∂t = −~2 2m ∇~2ψ.

The squared module of the wave function|ψ(~r , t)|2 is interpreted asprobability density of finding the particle in the spatial volume element d3r = dx dy dz around the point ~r at the time t.

Karol Kołodziej Dirac Equation 3/44

(9)

Probability Current

We can define the probability current for a spinless non relativistic particle as the vector

S (~~ r , t) = −i ~ 2m

hψ∇ψ −~ ∇ψ~ ψi

which, together with the probability density|ψ(~r , t)|2, satisfies the following continuity equation

∂t|ψ(~r , t)|2+ ~∇ · ~S (~r , t) = 0.

(10)

Probability Current

We can define the probability current for a spinless non relativistic particle as the vector

S (~~ r , t) = −i ~ 2m

hψ∇ψ −~ ∇ψ~ ψi

which, together with the probability density|ψ(~r , t)|2, satisfies the following continuity equation

∂t|ψ(~r , t)|2+ ~∇ · ~S (~r , t) = 0.

Karol Kołodziej Dirac Equation 4/44

(11)

Relativistic Wave Equation

It seems that the simplest way to obtain a relativistic wave equation would be the following substitution

E → i ~∂

∂t, p → −i ~~~

to the relativistic relationship between momentum and energy of a particle of mass m

E2− ~p2c2 = m2c4, where c is the speed of light in vacuum.

(12)

Relativistic Wave Equation

It seems that the simplest way to obtain a relativistic wave equation would be the following substitution

E → i ~∂

∂t, p → −i ~~~

to the relativistic relationship between momentum and energy of a particle of mass m

E2− ~p2c2 = m2c4, where c is the speed of light in vacuum.

Karol Kołodziej Dirac Equation 5/44

(13)

Relativistic Wave Equation

Let us remind that the relationshipE2− ~p2c2 = m2c4 is Lorentz invariant, as it can be derived by calculating the inner (dot) product of the energy-momentum four vector

pµ=

E c, ~p



with itself.

The dot product of any two four vectors in Minkowski’s space time is by definition invariant with respect to Lorentz transformations.

Let us calculate

p2 = p · p = pµpµ= p0 2− ~p2 = E2 c2 − ~p2.

(14)

Relativistic Wave Equation

Let us remind that the relationshipE2− ~p2c2 = m2c4 is Lorentz invariant, as it can be derived by calculating the inner (dot) product of the energy-momentum four vector

pµ=

E c, ~p



with itself.

The dot product of any two four vectors in Minkowski’s space time is by definition invariant with respect to Lorentz transformations.

Let us calculate p2 = p · p =

pµpµ= p0 2− ~p2 = E2 c2 − ~p2.

Karol Kołodziej Dirac Equation 6/44

(15)

Relativistic Wave Equation

Let us remind that the relationshipE2− ~p2c2 = m2c4 is Lorentz invariant, as it can be derived by calculating the inner (dot) product of the energy-momentum four vector

pµ=

E c, ~p



with itself.

The dot product of any two four vectors in Minkowski’s space time is by definition invariant with respect to Lorentz transformations.

Let us calculate

p2 = p · p =pµpµ=

p0 2− ~p2 = E2 c2 − ~p2.

(16)

Relativistic Wave Equation

Let us remind that the relationshipE2− ~p2c2 = m2c4 is Lorentz invariant, as it can be derived by calculating the inner (dot) product of the energy-momentum four vector

pµ=

E c, ~p



with itself.

The dot product of any two four vectors in Minkowski’s space time is by definition invariant with respect to Lorentz transformations.

Let us calculate

p2 = p · p = pµpµ= p0 2− ~p2 =

E2 c2 − ~p2.

Karol Kołodziej Dirac Equation 6/44

(17)

Relativistic Wave Equation

Let us remind that the relationshipE2− ~p2c2 = m2c4 is Lorentz invariant, as it can be derived by calculating the inner (dot) product of the energy-momentum four vector

pµ=

E c, ~p



with itself.

The dot product of any two four vectors in Minkowski’s space time is by definition invariant with respect to Lorentz transformations.

Let us calculate

p2 = p · p = pµpµ= p0 2− ~p2 = E2 c2 − ~p2.

(18)

Relativistic Wave Equation

Let us remind that the relationshipE2− ~p2c2 = m2c4 is Lorentz invariant, as it can be derived by calculating the inner (dot) product of the energy-momentum four vector

pµ=

E c, ~p



with itself.

The dot product of any two four vectors in Minkowski’s space time is by definition invariant with respect to Lorentz transformations.

Let us calculate

p2 = p · p = pµpµ= p0 2− ~p2 = E2 c2 − ~p2.

Karol Kołodziej Dirac Equation 6/44

(19)

Relativistic Wave Equation

Let us remind that

E = γmc2, p = γm~~ v , where the Lorentz factor γ is given by

γ = 1

q 1 −~vc22

.

Hence

p2= E2

c2 − ~p2 =

γ2m2c2− m2~v2= m2c2γ2 1 −~v2 c2

!

=m2c2.

(20)

Relativistic Wave Equation

Let us remind that

E = γmc2, p = γm~~ v , where the Lorentz factor γ is given by

γ = 1

q 1 −~vc22

.

Hence p2= E2

c2 − ~p2 =γ2m2c2− m2~v2=

m2c2γ2 1 −~v2 c2

!

=m2c2.

Karol Kołodziej Dirac Equation 7/44

(21)

Relativistic Wave Equation

Let us remind that

E = γmc2, p = γm~~ v , where the Lorentz factor γ is given by

γ = 1

q 1 −~vc22

.

Hence p2= E2

c2 − ~p2 = γ2m2c2− m2~v2=m2c2γ2 1 −~v2 c2

!

=

m2c2.

(22)

Relativistic Wave Equation

Let us remind that

E = γmc2, p = γm~~ v , where the Lorentz factor γ is given by

γ = 1

q 1 −~vc22

.

Hence p2= E2

c2 − ~p2 = γ2m2c2− m2~v2= m2c2γ2 1 −~v2 c2

!

=m2c2.

Karol Kołodziej Dirac Equation 7/44

(23)

Relativistic Wave Equation

Let us remind that

E = γmc2, p = γm~~ v , where the Lorentz factor γ is given by

γ = 1

q 1 −~vc22

.

Hence p2= E2

c2 − ~p2 = γ2m2c2− m2~v2= m2c2γ2 1 −~v2 c2

!

=m2c2.

(24)

Relativistic Wave Equation

We got the equation E2

c2 − ~p2 = m2c2,

which after multiplying its both sides by c2 gives our starting relationship E2− ~p2c2= m2c4.

Substituting

E → i ~∂

∂t, p → −i ~~~

in it we get the relativistic wave equation

"

−~2 2

∂(ct)2 + ~2∇~2

#

ϕ(t, ~x ) = m2c2ϕ(t, ~x ).

Karol Kołodziej Dirac Equation 8/44

(25)

Relativistic Wave Equation

We got the equation E2

c2 − ~p2 = m2c2,

which after multiplying its both sides by c2 gives our starting relationship E2− ~p2c2= m2c4.

Substituting

E → i ~∂

∂t, p → −i ~~~ in it we get the relativistic wave equation

"

2 2 2~2

#

2 2

(26)

Relativistic Wave Equation

We got the equation E2

c2 − ~p2 = m2c2,

which after multiplying its both sides by c2 gives our starting relationship E2− ~p2c2= m2c4.

Substituting

E → i ~∂

∂t, p → −i ~~~ in it we get the relativistic wave equation

"

−~2 2

∂(ct)2 + ~2∇~2

#

ϕ(t, ~x ) = m2c2ϕ(t, ~x ).

Karol Kołodziej Dirac Equation 8/44

(27)

Relativistic Wave Equation

Dividing both sides of the equation

"

−~2 2

∂(ct)2 + ~2∇~2

#

ϕ(t, ~x ) = m2c2ϕ(t, ~x )

by −~2 after having shifted m2c2ϕ(t, ~x ) to the l.h.s. we get the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0.

Let us define the time-space four vector x ≡ xµ= (x0, ~x ) = (ct, ~x ),then

2

∂(ct)2 − ~∇2 = 2

∂ x0 2 2

∂ x1 2 2

∂ x2 2 2

∂ x3 2 ≡ ,

(28)

Relativistic Wave Equation

Dividing both sides of the equation

"

−~2 2

∂(ct)2 + ~2∇~2

#

ϕ(t, ~x ) = m2c2ϕ(t, ~x )

by −~2 after having shifted m2c2ϕ(t, ~x ) to the l.h.s. we get the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0.

Let us define the time-space four vector x ≡ xµ= (x0, ~x ) = (ct, ~x ),then

2

∂(ct)2 − ~∇2 =

2

∂ x0 2 2

∂ x1 2 2

∂ x2 2 2

∂ x3 2 ≡ ,

Karol Kołodziej Dirac Equation 9/44

(29)

Relativistic Wave Equation

Dividing both sides of the equation

"

−~2 2

∂(ct)2 + ~2∇~2

#

ϕ(t, ~x ) = m2c2ϕ(t, ~x )

by −~2 after having shifted m2c2ϕ(t, ~x ) to the l.h.s. we get the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0.

Let us define the time-space four vector x ≡ xµ= (x0, ~x ) = (ct, ~x ),then

≡ ,

(30)

Relativistic Wave Equation

Dividing both sides of the equation

"

−~2 2

∂(ct)2 + ~2∇~2

#

ϕ(t, ~x ) = m2c2ϕ(t, ~x )

by −~2 after having shifted m2c2ϕ(t, ~x ) to the l.h.s. we get the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0.

Let us define the time-space four vector x ≡ xµ= (x0, ~x ) = (ct, ~x ),then

2

∂(ct)2 − ~∇2 = 2

∂ x0 2 2

∂ x1 2 2

∂ x2 2 2

∂ x3 2 ≡ ,

Karol Kołodziej Dirac Equation 9/44

(31)

Relativistic Wave Equation

Dividing both sides of the equation

"

−~2 2

∂(ct)2 + ~2∇~2

#

ϕ(t, ~x ) = m2c2ϕ(t, ~x )

by −~2 after having shifted m2c2ϕ(t, ~x ) to the l.h.s. we get the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0.

Let us define the time-space four vector x ≡ xµ= (x0, ~x ) = (ct, ~x ),then

(32)

Relativistic Wave Equation

where we have introduced symbol  to denote thed’Alembert operator.

Moreover, let us denote µ2 m2c2

~2 , then the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0

takes the simple form

 + µ2ϕ(x ) = 0. This is theKlein-Gordon wave equation.

Karol Kołodziej Dirac Equation 10/44

(33)

Relativistic Wave Equation

where we have introduced symbol  to denote thed’Alembert operator.

Moreover, let us denote µ2 m2c2

~2 , then the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0 takes the simple form

 + µ2ϕ(x ) = 0.

This is theKlein-Gordon wave equation.

(34)

Relativistic Wave Equation

where we have introduced symbol  to denote thed’Alembert operator.

Moreover, let us denote µ2 m2c2

~2 , then the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0 takes the simple form

 + µ2ϕ(x ) = 0.

This is theKlein-Gordon wave equation.

Karol Kołodziej Dirac Equation 10/44

(35)

Relativistic Wave Equation

where we have introduced symbol  to denote thed’Alembert operator.

Moreover, let us denote µ2 m2c2

~2 , then the equation

"

2

∂(ct)2 − ~∇2+m2c2

~2

#

ϕ(t, ~x ) = 0 takes the simple form

 + µ2ϕ(x ) = 0.

This is theKlein-Gordon wave equation.

(36)

Klein-Gordon Wave Equation

Despite being realistically invariant, the Klein-Gordon equation has some shortcomings which make it practicallyuseless for the sake of quantum mechanical description of a relativistic particle, as e.g.

electron.

We will discuss those shortcomings in the following.

If the wave function in the Klein-Gordon equation is complex, then we can define the probability current

jµ(x ) ≡ i [ϕ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )] ≡ (ρ(x ), ~j (x )), where we have introduced a shorthand notation for the differential operator

µ

∂xµ, µ

∂xµ.

Karol Kołodziej Dirac Equation 11/44

(37)

Klein-Gordon Wave Equation

Despite being realistically invariant, the Klein-Gordon equation has some shortcomings which make it practicallyuseless for the sake of quantum mechanical description of a relativistic particle, as e.g.

electron.

We will discuss those shortcomings in the following.

If the wave function in the Klein-Gordon equation is complex, then we can define the probability current

jµ(x ) ≡ i [ϕ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )] ≡ (ρ(x ), ~j (x )),

where we have introduced a shorthand notation for the differential operator

µ

∂xµ, µ

∂xµ.

(38)

Klein-Gordon Wave Equation

Despite being realistically invariant, the Klein-Gordon equation has some shortcomings which make it practicallyuseless for the sake of quantum mechanical description of a relativistic particle, as e.g.

electron.

We will discuss those shortcomings in the following.

If the wave function in the Klein-Gordon equation is complex, then we can define the probability current

jµ(x ) ≡ i [ϕ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )] ≡ (ρ(x ), ~j (x )), where we have introduced a shorthand notation for the differential operator

µ

∂xµ, µ

∂xµ.

Karol Kołodziej Dirac Equation 11/44

(39)

Klein-Gordon Wave Equation

Despite being realistically invariant, the Klein-Gordon equation has some shortcomings which make it practicallyuseless for the sake of quantum mechanical description of a relativistic particle, as e.g.

electron.

We will discuss those shortcomings in the following.

If the wave function in the Klein-Gordon equation is complex, then we can define the probability current

jµ(x ) ≡ i [ϕ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )] ≡ (ρ(x ), ~j (x )), where we have introduced a shorthand notation for the differential operator

µ

(40)

Klein-Gordon Wave Equation

Despite being realistically invariant, the Klein-Gordon equation has some shortcomings which make it practicallyuseless for the sake of quantum mechanical description of a relativistic particle, as e.g.

electron.

We will discuss those shortcomings in the following.

If the wave function in the Klein-Gordon equation is complex, then we can define the probability current

jµ(x ) ≡ i [ϕ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )] ≡ (ρ(x ), ~j (x )), where we have introduced a shorthand notation for the differential operator

µ

∂xµ, µ

∂xµ.

Karol Kołodziej Dirac Equation 11/44

(41)

Klein-Gordon Wave Equation

Exercise. Show that ∂µ is a covariant and ∂µ is a contravariant four vector.

The current jµ(x ) satisfies the following continuity equation

µjµ(x ) = 0.

In order to prove this statement let us first write down the Klein-Gordon equation for the complex conjugate wave function ϕ(x ).

To this end let us conjugate the Klein-Gordon equation



 + µ2ϕ(x ) = 0.

Where we have used the fact that both the d’Alembert operator  and the parameter µ2 are real.

(42)

Klein-Gordon Wave Equation

Exercise. Show that ∂µ is a covariant and ∂µ is a contravariant four vector.

The current jµ(x ) satisfies the following continuity equation

µjµ(x ) = 0.

In order to prove this statement let us first write down the Klein-Gordon equation for the complex conjugate wave function ϕ(x ).

To this end let us conjugate the Klein-Gordon equation



 + µ2ϕ(x ) = 0.

Where we have used the fact that both the d’Alembert operator  and the parameter µ2 are real.

Karol Kołodziej Dirac Equation 12/44

(43)

Klein-Gordon Wave Equation

Exercise. Show that ∂µ is a covariant and ∂µ is a contravariant four vector.

The current jµ(x ) satisfies the following continuity equation

µjµ(x ) = 0.

In order to prove this statement let us first write down the Klein-Gordon equation for the complex conjugate wave function ϕ(x ).

To this end let us conjugate the Klein-Gordon equation



 + µ2ϕ(x ) = 0.

Where we have used the fact that both the d’Alembert operator  and the parameter µ2 are real.

(44)

Klein-Gordon Wave Equation

Exercise. Show that ∂µ is a covariant and ∂µ is a contravariant four vector.

The current jµ(x ) satisfies the following continuity equation

µjµ(x ) = 0.

In order to prove this statement let us first write down the Klein-Gordon equation for the complex conjugate wave function ϕ(x ).

To this end let us conjugate the Klein-Gordon equation



 + µ2ϕ(x ) = 0.

Where we have used the fact that both the d’Alembert operator  and the parameter µ2 are real.

Karol Kołodziej Dirac Equation 12/44

(45)

Klein-Gordon Wave Equation

Exercise. Show that ∂µ is a covariant and ∂µ is a contravariant four vector.

The current jµ(x ) satisfies the following continuity equation

µjµ(x ) = 0.

In order to prove this statement let us first write down the Klein-Gordon equation for the complex conjugate wave function ϕ(x ).

To this end let us conjugate the Klein-Gordon equation



 + µ2ϕ(x ) = 0.

(46)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

Karol Kołodziej Dirac Equation 13/44

(47)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

=

i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

(48)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

Karol Kołodziej Dirac Equation 13/44

(49)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

(50)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

=

i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

Karol Kołodziej Dirac Equation 13/44

(51)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

(52)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

=

ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

Karol Kołodziej Dirac Equation 13/44

(53)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i

=0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

(54)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0,

where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

Karol Kołodziej Dirac Equation 13/44

(55)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0

ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

(56)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0

ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

Karol Kołodziej Dirac Equation 13/44

(57)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0 (x ) = −µ2ϕ(x ).

(58)

Klein-Gordon Wave Equation

Let us now calculate the four divergence of the current jµ(x )

µjµ(x ) = i ∂µ(x )∂µϕ(x ) − ∂µ(x )) ϕ(x )]

= i [∂µϕ(x )∂µϕ(x ) + ϕ(x )∂µµϕ(x )

−∂µµ(x )) ϕ(x ) − ∂µϕ(x )∂µϕ(x )]

= i [ϕ(x )ϕ(x) −  (ϕ(x )) ϕ(x )]

= ihϕ(x )(−µ2)ϕ(x ) + µ2ϕ(x )ϕ(x )i =0, where we have used the Klein-Gordon equation and its complex conjugate

 + µ2ϕ(x ) = 0 ϕ(x) = −µ2ϕ(x ),

 + µ2ϕ(x ) = 0

(x ) = −µ2ϕ(x ).

Karol Kołodziej Dirac Equation 13/44

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