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LECTURE OUTLINE

1.

Ways of reaching saturation

• vertical motion

(2)

Fundamentals of Atmospheric Physics, M.L. Salby; Salby

A Short Course in Cloud Physics, R.R. Rogers and M.K. Yau; R&Y

Thermodynamics of Atmospheres and Oceanes,

J.A. Curry and P.J. Webster; C&W

Salby, Chapter 5 C&W, Chapter 6

R&Y, Chapter 4

(3)

/34 3

Chapter 2: Clouds as Fluids

Siebesma, A., Bony, S., Jakob, C., & Stevens, B. (Eds.). (2020). Clouds and Climate: Climate Science's Greatest Challenge. Cambridge: Cambridge University Press. doi:10.1017/9781107447738

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THERMODYNAMIC IN VERTICAL MOTION

1.

Lifting condensation level (LCL)

2.

Dew-point temperature variation in vertical motion

3.

Pseudo-adiabatic process

§ saturated adiabatic lapse rate

§ water condensed in pesudo-adiabatic process

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/34 5

A parcel that moves vertically expands or contracts to preserve its mechanical equilibrium (adjust its pressure to the environmental pressure). It results in work being performed.

Compensating this work is a change of internal energy, which alters the temperature and hence the saturation vapor pressure.

The change of saturation vapor pressure (assuming Llv=const):

The saturation specific humidity varies with pressure and temperature:

The saturation specific humidityincreases with decreasing pressure (increase of altitude).

However, qs decreases sharply with decreasing temperature, which likewise accompanies upward motion.

Even though an ascending parcel’s pressure decreases exponentially with altitude, the temperature dependence prevails, so itssaturation specific humidity decreases

monotonically with altitude.

ln 𝑒!

𝑒!" = −𝐿#$

𝑅$ 1

𝑇 − 1 𝑇"

𝑞! = 𝜀 𝑒! 𝑝 𝑞!" = 𝜀 𝑒!"

𝑝"

𝑞!

𝑞!" = 𝑒!- 𝑒!"

𝑝-

𝑝" = exp −𝐿#$

𝑅$ 1

𝑇 − 1 𝑇"

𝑝𝑝"

(6)

Lifting condensation

level

(7)

/34 7

As it rises, the parcel performs work at the expense of its internal energy.

The parcel’s temperature decreases at the dry adiabatic lapse rate Gd.

The decrease of temperature is attended by a reduction of saturation specific humidity 𝑞!. The parcel’s actual specific humidity 𝑞$ and potential temperature q remain constant.

Sufficient upward displacement will reduce the saturation specific humidity to the actual specific humidity.

The elevation where 𝑞$ = 𝑞! for the first time is referred to as the lifting condensation level (LCL).

qv z

qv0

qv qs

qs(z) qv(z)

LCL

Dq(z) Consider a moist air parcel ascending in thermal convection.

Under unsaturated conditions, the parcel’s specific humidity and saturation specific humidity satisfy 𝑞$ < 𝑞!

(8)

The lifting condensation level defines the base of cumulus clouds that are fueled by air originating at the surface.

Below the LCL, the parcel’s thermodynamic behavior can be regarded as adiabatic because the timescale for vertical motion (from minutes in cumulus convection to 1 day in sloping convection) is small compared to the characteristic timescale for heat transfer.

qv z

qv0

qv qs

qs(z) qv(z)

LCL

Dq(z)

(9)

Position of the LCL

/34 9

As air expands adiabatically and cools, the relative humidity (f) increases as the temperature and saturation mixing ratio decrease.

We will find coordinates of the LCL 𝑇%&%, 𝑝%&% – the point where the air becomes saturated.

Using Dalton’s law of partial pressure, that states that the total pressure exerted by a

mixture of gases is equal to the sum of the partial pressures that would be exerted by each constituents alone if it filled the entire volume at the temperature of the mixture.

Therefore: 𝑑 ln 𝑝 = 𝑑 ln 𝑒 . 𝑓 = 𝑒

𝑒!

𝑑 ln 𝑓 = 𝑑 ln 𝑒 − 𝑑 ln 𝑒!

𝑝' = 𝑚'𝑅'𝑇 𝑉 𝑑𝑝'

𝑝' = 𝑑𝑇 𝑇

(10)

The First Law of thermodynamics for an adiabatic process in enthalpy form:

Using the Clausius-Clapeyron equation:

Because 𝑑 ln 𝑝 = 𝑑 ln 𝑒 :

The change of relative humidity fulfils the following equation:

𝑐(𝑑𝑇 = 𝑣𝑑𝑝 𝑐(𝑑𝑇 = 𝑅𝑇

𝑝 𝑑𝑝 𝑑 ln 𝑝 = 𝑐(

𝑅 𝑑 ln 𝑇 𝑑 ln 𝑒 = 𝑐(

𝑅 𝑑 ln 𝑇 𝑑 ln 𝑒! = 𝐿#$

𝑅$𝑇𝑑 ln 𝑇

𝑑 ln 𝑓 = 𝑑 ln 𝑒 − 𝑑 ln 𝑒!

𝑑 ln 𝑓 = 𝑐(

𝑅 𝑑 ln 𝑇 − 𝐿#$

𝑅$𝑇 𝑑 ln 𝑇

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/34 11

We will integrate the equation from initial conditions to conditions where saturation is attained, indicated by f=1 and 𝑇 = 𝑇%&%, where 𝑇%&% is the saturation temperature. We will assume that Llv=const.

Equation can be solved numerically to obtain 𝑇%&%.

The saturation pressure can be obtained from the dry adiabat equation:

9

)

*

𝑑 ln 𝑓+ = 9

, ,!"!

𝑐(

𝑅 − 𝜀𝐿#$

𝑅𝑇 𝑑 ln 𝑇+

− ln 𝑓 = 𝑐(

𝑅 ln𝑇%&%

𝑇 + 𝜀𝐿#$

𝑅

1

𝑇%&% − 1 𝑇

𝑝%&% = 𝑝 𝑇%&%

𝑇

.#- /

(12)

An approximate equation for 𝑇%&% given initial values of T and f, is given by Bolton (1980).

f T Ts ps

0,1 0 -16 815

0,1 10 -7 806

0,1 20 2 797

0,1 30 10 788

0,3 0 -8 896

0,3 10 1 891

0,3 20 10 886

0,3 30 19 880

0,5 0 -5 938

0,5 10 5 935

0,5 20 14 932

0,5 30 24 929

0,7 0 -3 968

0,7 10 7 966

0,7 20 17 964

0,7 30 27 962

𝑇%&% = 1

𝑇 − 55 −1 ln 𝑓 2840

+ 55, 𝑇 = 𝐾

(13)

Variation of dew-point

temperature with altitude

(14)

During adiabatic ascent, the water vapor specific humidity, qv, remains constant until saturation occurs.

The dew-point temperature decreases slightly during the ascent as pressure decreases.

We will calculate how the dew-point temperature changes during ascent of non-saturated adiabatic parcel.

The dew-point temperature fullfils the equation:

The hydrostatic equation.

From the Dalton’s law: 𝑑 ln 𝑝 = 𝑑 ln 𝑒

For typical atmospheric values dTd/dz is

approximately 1/6 of the dry adiabatic lapse rate.

𝑑 ln 𝑒 = 𝜀𝐿#$

𝑅𝑇01 𝑑𝑇0 𝑑𝑝 = −𝜌𝑔𝑑𝑧 ⟶ 𝑑 ln 𝑝 = − 𝑔

𝑅𝑇𝑑𝑧 𝑝 = 𝑅𝑇𝜌

𝑑 ln 𝑒 = − 𝑔 𝑅𝑇 𝑑𝑧 𝜀𝐿#$

𝑅𝑇01 𝑑𝑇0 = − 𝑔 𝑅𝑇 𝑑𝑧 𝑑𝑇0

𝑑𝑧 = − 𝑇01𝑔

𝜀𝐿#$𝑇 E 𝑐(

𝑐( ≅ − 𝑇01𝑐(

𝜀𝐿#$𝑇 E Γ0 Γ0 = 𝑔

𝑐(0 ≈ 𝑔 𝑐(

𝑇!"𝑐#

𝜀𝐿$%𝑇 280" ) 1004

0.622 ) 2.5 ) 10& ) 300 = 0.166 ≈ ⁄1 6

(15)

/34 15

Equation of change of the dew-point temperature can be written in form of a change of dew-point deficit: T-Td

When T=Td, the saturation level has been reached, and a value of zLCL can be determined by integrating form initial values (0,T0-Td0) to the saturation state (zLCL,0).

T0-Td0 is the dew-point depression at the surface.

At saturation level, T becomes equal to Td (and to TLCL).

The lifting condensation level (LCL), zLCL corresponds to the level of the saturation pressure ps.

𝑑𝑇0

𝑑𝑧 = − 𝑇01𝑐(

𝜀𝐿#$𝑇 E Γ0 ⟶ 𝑑𝑇

𝑑𝑧 − 𝑑𝑇0

𝑑𝑧 = −Γ0 + 𝑇01𝑐( 𝜀𝐿#$𝑇 E Γ0 𝑑 𝑇 − 𝑇0

𝑑𝑧 = − 1 − 𝑇01𝑐(

𝜀𝐿#$𝑇 E Γ0

9

,$2,%$

"

𝑑 𝑇 − 𝑇0 = − 9

"

3!"!

1 − 𝑇01𝑐(

𝜀𝐿#$𝑇 Γ0𝑑𝑧

(16)

For a parcel lifted from the surface, the value of zLCL can be estimated (assuming 𝑑𝑇0⁄𝑑𝑧 = − ⁄1 6 Γ0):

Calculation of the lifting condensation level provides a good estimate of the cloud height for clouds that form by adiabatic ascent.

𝑧%&% ≈ 0.12 𝑇" − 𝑇0" km

(17)

ADIABATIC

AND PSEUDO-ADIABATIC PROCESSES

1.

Wet adiabatic lapse rate / saturated adiabatic lapse rate

2.

Pseudo-adiabatic process

3.

Water condensed in pseudo-adiabatic process

(18)

Wet adiabatic lapse rate

𝑑ℎ = 𝑐(𝑑𝑇 + 𝐿#$𝑑𝑞$

𝑑ℎ = 𝛿𝑞 + 𝑣𝑑𝑝

First Law of thermodynamics for adiabatic processes

𝑐(𝑑𝑇 + 𝐿#$𝑑𝑞$ − 𝑣𝑑𝑝 = 0

Water vapor is saturated 𝑞$ = 𝑞! 𝑇, 𝑝

𝑑𝑞$ = 𝑑𝑞! = 𝜕𝑞!

𝜕𝑇 𝑑𝑇 + 𝜕𝑞!

𝜕𝑝 𝑑𝑝

If expansion work occurs fast enough the heat transfer with the environment remains negligible.

If no moisture precipitates out, the parcel is closed and and its behavior above the LCL is described by a reversible saturated adiabatic process.

(19)

/34 19

𝑐(𝑑𝑇 + 𝐿#$ 𝑞!

𝑇 𝛽,𝑑𝑇 − 𝐿#$ 𝑞!

𝑝 𝛽(𝑑𝑝 − 𝑣𝑑𝑝 = 0 𝑑𝑝 = −𝜌𝑔𝑑𝑧

𝑣𝑑𝑝 = −𝑔𝑑𝑧 𝑑𝑝 = − 𝑝

𝑅𝑇𝑔𝑑𝑧 𝑐( + 𝐿#$ 𝑞!

𝑇 𝛽, 𝑑𝑇 + 𝐿#$ 𝑞!

𝑅𝑇𝛽( + 1 𝑔𝑑𝑧 = 0

Γ! = −𝑑𝑇

𝑑𝑧 = 𝑔 1 + 𝑞!𝛽( 𝐿#$

𝑅𝑇 𝑐( + 𝑞!𝛽, 𝐿#$

𝑇 Saturated moist adiabatic lapse rate:

It is convenient to express the partial derivatives of 𝑞! as logarithmic partial derivatives:

𝜕𝑞!

𝜕𝑇 = 𝑞! 𝑇

𝜕 ln 𝑞!

𝜕 ln 𝑇

𝜕𝑞!

𝜕𝑝 = 𝑞! 𝑝

𝜕 ln 𝑞!

𝜕 ln 𝑝 𝛽, = 𝜕 ln 𝑞!

𝜕 ln 𝑇 𝛽( = −𝜕 ln 𝑞!

𝜕 ln 𝑝 𝑑𝑞! = 𝑞!

𝑇 𝛽,𝑑𝑇 − 𝑞!

𝑝 𝛽(𝑑𝑝

(20)

We will calculate 𝛽( and 𝛽,.

𝑞! = 𝜀𝑒!

𝑝 − 1 − 𝜀 𝑒! = 𝜀 𝑒! 𝑝

1 − 1 − 𝜀 𝑒! 𝑝

𝜕𝑞!

𝜕𝑝 = −𝑞!

𝑝 1 + 1 − 𝜀 𝜀 𝑞! 𝛽( = −𝜕 ln 𝑞!

𝜕 ln 𝑝 = 1 + 1

𝜀 − 1 𝑞! ≈ 1

𝜕𝑞!

𝜕𝑇 = 1 𝑒!

𝑑𝑒!

𝑑𝑇 𝑞! + 1 − 𝜀 𝜀

1 𝑒!

𝑑𝑒! 𝑑𝑇 𝑞!1 𝛽, = 𝜕 ln 𝑞!

𝜕 ln 𝑇 = 𝑇𝑑 ln 𝑒!

𝑑𝑇 1 + 1 − 𝜀

𝜀 𝑞! = 𝑇𝑑 ln 𝑒! 𝑑𝑇 𝛽( 𝛽, = 𝐿#$

𝑅$𝑇 𝛽( ≈ 5 400 𝐾 𝑇

𝑑 ln 𝑒!

𝑑𝑇 = 𝐿#$

𝑅$𝑇1 Clausius-Clapeyron equation

𝛽(

𝛽,

(21)

Saturated moist adiabatic lapse rate

/34 21

Γ! = 𝑔 1 + 𝑞!𝛽, 𝑅$ 𝑅 𝑐( + 𝑞!𝛽, 𝐿#$

𝑇

Γ! = 𝑐(0 𝑐(0

𝑔 𝑐(

1 + 𝑞!𝛽, 𝑅$ 𝑅 1 + 𝑞!𝛽, 𝐿#$

𝑐(𝑇

Γ0 = 𝑔 𝑐(0

Γ! ≡ −𝑑𝑇

𝑑𝑧 = 𝛾Γ0 𝛾 = 𝑐(0

𝑐(

1 + 𝑞!𝛽, 𝑅$ 𝑅 1 + 𝑞!𝛽, 𝐿#$

𝑐(𝑇

𝑐( = 𝑞0𝑐(0 + 𝑞!𝑐($ + 𝑞#𝑐# 𝑅 = 𝑞0𝑅0 + 𝑞!𝑅$

𝛽, = 𝐿#$

𝑅$𝑇 𝛽( ≈ 5 400 𝐾 𝛾 ≤ 1 𝑇

(22)

If no moisture precipitates out, the parcel is closed and and its behavior above the LCL is described by a reversible saturated adiabatic process.

The process depends weakly on the abundance of condensate present (e.g., on how much the system’s enthalpy is represented by condensate).

Because the condensate is present is present only in trace abundance, the variation of condensate unnecessarily complicates the parcel’s description under saturated conditions.

A simplification is proposed

Pseudo-adiabatic process: the system is treated as open and condensate is removed (added) immediately after (before) it is produced (destroyed).

(23)

/34 23

A pseudo-adiabatic change of state may be constructed in two legs:

1. Reversible saturated adiabatic expansion (compression), which results in the

production (destruction) of condensate of mass dmc and a commensurate release (absorption) of latent heat to (from) the gas phase

2. Removal (addition) of condensate of mass dmc

(24)

Wet adiabatic vs pseudo-adiabatic lapse rate

Γ! = 𝛾Γ0 𝛾 = 𝑐(0 𝑐(

1 + 𝑞!𝛽, 𝑅$ 𝑅 1 + 𝑞!𝛽, 𝐿#$

𝑐(𝑇

𝑐( = 𝑞0𝑐(0 + 𝑞!𝑐($ + 𝑞#𝑐# 𝑅 = 𝑞0𝑅0 + 𝑞!𝑅$

Wet adiabatic lapse rate:

𝑞0 + 𝑞! + 𝑞# = 1 and 𝑞0 = 𝑐𝑜𝑛𝑠𝑡 , 𝑞! + 𝑞# = 𝑐𝑜𝑛𝑠𝑡

Pseudo-adiabatic lapse rate:

𝑞# = 0, 𝑞0+𝑞! = 1

(25)

Simplified version of Γ !

/34 25

Γ! = 𝛾Γ0 𝛾 = 𝑐(0 𝑐(

1 + 𝑞!𝛽, 𝑅$ 𝑅 1 + 𝑞!𝛽, 𝐿#$

𝑐(𝑇

⟶ 𝛾 = 1 + 𝑞!𝐿#$

𝑅0𝑇 1 + 𝑞!𝐿1#$

𝑐(0𝑅$𝑇1 In many textbooks a simplified version of Γ! is presented.

𝑅 ⟶ 𝑅0 𝑐( ⟶ 𝑐(0

(26)

Non-dimensional lapse rate 𝛾

pressure: 1 000 hPa

the air initially saturated at 300 K

Γ! = 𝛾Γ0

𝛾 = 𝑐(0 𝑐(

1 + 𝑞!𝛽, 𝑅$ 𝑅 1 + 𝑞!𝛽, 𝐿#$

𝑐(𝑇 Γ! < Γ0

(27)

Non-dimensional lapse rate 𝛾

pressure: 800 hPa

the air initially saturated at 300 K

/34 27

Γ! = 𝛾Γ0

𝛾 = 𝑐(0 𝑐(

1 + 𝑞!𝛽, 𝑅$ 𝑅 1 + 𝑞!𝛽, 𝐿#$

𝑐(𝑇 Γ! < Γ0

(28)

Non-dimensional lapse rate 𝛾

pressure: 1000 hPa

pressure: 800 hPa

the air initially saturated at 300 K

Γ! = 𝛾Γ0

𝛾 = 𝑐(0 𝑐(

1 + 𝑞!𝛽, 𝑅$ 𝑅 1 + 𝑞!𝛽, 𝐿#$

𝑐(𝑇 Γ! < Γ0

(29)

Difference between pseudo-adiabatic and simplified pseudo-

adiabatic normalised lapse rates

pressure: 1 000 hPa

the air initially saturated at 300 K

/34 29

Γ! = 𝛾Γ0

𝛾 = 𝑐(0 𝑐(

1 + 𝑞!𝛽, 𝑅$ 𝑅 1 + 𝑞!𝛽, 𝐿#$

𝑐(𝑇 Γ! < Γ0

(30)
(31)

Water condensed in adiabatic process

/34 31

Adiabatic enthalpy equation of a closed system:

dry air, water vapor, condensed water: 𝑑ℎ = 𝑐(𝑑𝑇 + 𝐿#$𝑑𝑞! ; 𝑑ℎ = 𝛿𝑞 + 𝑣𝑑𝑝 0 = 𝑐(𝑑𝑇 + 𝐿#$𝑑𝑞! − 𝑣𝑑𝑝

𝑑𝑞# = −𝑑𝑞! = 𝑐(

𝐿#$ 𝑑𝑇 − 𝑣

𝐿#$ 𝑑𝑝 𝑑𝑝 = −𝑔

𝑣 𝑑𝑧 𝑑𝑞# = 𝑐(

𝐿#$ 𝑑𝑇 + 𝑔 𝐿#$ 𝑑𝑧

𝑑𝑞# = 𝑐( 𝐿#$

𝑑𝑇

𝑑𝑧 + 𝑔

𝑐( 𝑑𝑧 Γ0 = 𝑔

𝑐(0 ≈ 𝑔

𝑐( , Γ! = −𝑑𝑇 𝑑𝑧

𝑑𝑞# ≅ 𝑐(

𝐿#$ Γ0 − Γ! 𝑑𝑧

(32)

The amount of water condensed in a rising adiabatic parcel increases with the height above the cloud base and increases with increasing temperature at the cloud base.

For shallow clouds (cloud depth not bigger than ca. 300-500 m, for instance stratocumulus clouds) it can be assumed that the amount of condensed water increases linearly with height above the cloud base (h).

The rate of this increase (𝑐4) is approximately constant and depends on temperature and pressure at the cloud base.

Liquid Water Content (LWC) is the amount of liquid water per unit volume:

For shallow clouds one can assume that the air density is constant, therefore:

𝐿𝑊𝐶 = 𝑐5 𝑇, 𝑝 E ℎ ; 𝑐5 = 𝜌 𝑐(

𝐿#$ Γ0 − Γ! 𝑔 𝑚6 𝑞# ℎ = 𝑐4 𝑇, 𝑝 E ℎ ; 𝑐4 = 𝑐(

𝐿#$ Γ0 − Γ! 𝑔 𝑘𝑔 E 𝑚

𝐿𝑊𝐶 = 𝑞# E 𝜌 ; 𝜌 − density of the air

(33)

/34 33

20m 60m 100m 140m 180m

17m 51m 85m 119m 153m N=50 cm-3

Hbase=1278 m N=255 cm-3

Hbase=844 m

𝑐5 = 1.9 E 1027 𝑔

𝑚6 𝑐5 = 2 E 1027 𝑔

𝑚6

(34)

𝑐! = 1.7 & 10"# 𝑔 𝑘𝑔 & 𝑚

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