POLONICI MATHEMATICI LXXIV (2000)
On extendability of invariant distributions ∗ by Bogdan Ziemian
Abstract. In this paper sufficient conditions are given in order that every distribution invariant under a Lie group extend from the set of orbits of maximal dimension to the whole of the space. It is shown that these conditions are satisfied for the n-point action of the pure Lorentz group and for a standard action of the Lorentz group of arbitrary signature.
1. Notation and definitions. Let M be a p-dimensional Hausdorff analytic manifold and let R : G×M → M be a smooth action of a connected Lie group G on M . We shall denote by M/G the orbit space of the action R and by π the natural projection M → M/G. For every subset A ⊂ M , Inv A will stand for the set π
−1(π(A)). Orbits of maximal dimension will be called non-singular . The remaining orbits will be termed singular . An orbit θ is said to be regular if the submanifold topology on θ coincides with the topology induced from M (see [17], p. 68).
Two sets A
1and A
2are said to be non-separable iff any invariant neigh- bourhoods of A
1and A
2have a non-empty intersection. An orbit θ is called separable iff there is no orbit e θ 6= θ such that θ and e θ are non- separable.
A set E ⊂ R
pis called semianalytic iff every point x ∈ E possesses a neighbourhood U such that
E ∩ U = [
p i=1\
qj=1
{g
ij> 0} ∩ {f
i= 0}
with g
ij, f
ianalytic on U . A function f is called semianalytic iff its graph is a semianalytic set.
2000 Mathematics Subject Classification: Primary 46F10; Secondary 22F05, 22E99.
Key words and phrases : invariant distribution, Hausdorff partition, foliation.
∗
Editors’ remark . This paper was a part of the author’s thesis which appeared as a preprint of the Mathematical Institute of the Polish Academy of Sciences in 1981.
[13]
The Sobolev space H
m, m ∈ N, is the completion with respect to the norm |f |
m= P
|α|≤m
T
|D
αf (x)| dx of the space of all smooth functions f such that |f |
mis finite.
All remaining symbols and definitions can be found in [17].
2. Hyperbolic sets and their properties
Definition 1. Let Z be the set of singular orbits in M (
1). We shall say that Z is hyperbolic in M if
(a) for every compact set K ⊂ M there exists a compact set V
K, V
K∩ Z 6= ∅, such that for every non-singular orbit θ if θ ∩ K 6= ∅ then θ ∩ V
K6= ∅,
(b) the orbits in M \ Z are regular.
Definition 2. We say that Z is strongly hyperbolic if Z is hyberbolic and the set B of all orbits in M \Z non-separable from Z has empty interior.
Proposition 1. Let Z be hyperbolic and let θ be an orbit such that θ 6∈ B. Then every distribution u on M \ Z with supp u ⊂ θ extends to a disrtibution on M .
P r o o f. Since θ 6∈ B there exist open invariant sets U
1and U
2, U
1∩ U
2= ∅, such that Z ⊂ U
1, θ ⊂ U
2. Let ω ∈ Ω
0p(M ), the set of smooth compactly supported densities on M . Select a ϕ ∈ C
∞(M ) such that ϕ = 1 in a neighbourhood of θ and supp ϕ ⊂ U
2. Then ϕ · ω ∈ Ω
0p(U
2) and we define
e
u[ω] = u[ϕ · ω].
u is the desired extension of u. e
Proposition 2. If Z is hyperbolic then for every compact set K ⊂ M and every open covering {U
β}
β∈Bof the set K \Z by invariant sets U
βthere exist a finite number of indices β
1, . . . , β
rsuch that
K \ Z ⊂ [
r i=1U
βi.
P r o o f. By Definition 1 there exists a compact set V
K⊂ M \ Z with π(K) ⊂ π(V
K). The set V
Kbeing compact, there exist indices β
1, . . . , β
rsuch that V
K⊂ S
ri=1
U
βi. Since the set S
ri=1
U
βiis invariant the assertion follows.
Remark 1. If we assume that U \ Z consists of regular orbits then also the converse of Proposition 2 is true.
Definition 3. Let Z be the set of singular orbits in M . Let K ⊂ M be a compact subset of M with Int K 6= ∅ and K ⊂ U , an open neighbour- hood. Suppose A
1, . . . , A
ris an open covering of K \ Z. A family {ϕ
i}
ri=1(
1) Then Z is a closed subset of M .
of functions ϕ
i∈ C
∞(U \ Z) will be called a partition of unity on K \ Z subordinate to the covering {A
i}
ri=1iff
(a) ϕ
i≥ 0 for i = 1, . . . , r,
(b) K ∩ supp ϕ
i⊂ A
i, i = 1, . . . , r, (c) P
ri=1
ϕ
i= 1 on K \ Z,
(d) if ψ
j→ ψ
0in C
0∞(U ) as j → ∞, supp ψ
j⊂ K \ Z, then for every i, ϕ
iψ
j→ ϕ
iψ
0in C
0∞(U ) as j → ∞.
Theorem 1. Let M = R
p. Let Z be the set of hyperbolic orbits in M.
Fix a compact set K in M with non-empty interior. Put U
1= {x ∈ M : dist(x, K) < 2}. Suppose that there exists an open covering {A
i}
ri=1of the set U
1\ Z (
1) consisting of sets whose complements A
ciin M are semian- alytic. Then there exists a partition of unity on K \ Z subordinate to the covering {A
i}
ri=1of K.
P r o o f. Define
e δ(x) = max(dist(x, A
c1), . . . , dist(x, A
cr)), x ∈ U
1.
We observe that e δ is a semianalytic function since the distance from a semianalytic set and the maximum of semianalytic functions are also semi- analytic.
The function e δ can vanish only on Z for if we take an arbitrary compact set K
1⊂ U
1\ Z then {A
i}
ri=1is an open covering of K
1and there exists an ε > 0 such that for every x ∈ K
1the ball centred at x with radius ε is contained in one of the A
i’s and so we have e δ(x) ≥ ε for x ∈ K
1.
Put δ(x) = min(1, e δ(x)), x ∈ U
1, and define U = {x ∈ M : dist(x, K)
< 1}. It follows from the inequality of Lojasiewicz ([7], p. 85) that there exist positive constants e C and ea such that
(1) δ(x) ≥ e C(dist(x, Z))
aefor x ∈ U.
We shall now construct the required partition of unity on K. To this end we put
A
δi= {x ∈ A
i: dist(x, A
ci) > δ(x)/2}.
We assert that S
ri=1
A
i= S
ri=1
A
δi. To prove this we have to show that S
ri=1
A
i⊂ S
ri=1
A
δi, the converse inclusion being obvious. So we take x ∈ S
ri=1
A
i. Let {i
1, . . . , i
s} be the set of all indices 1 ≤ i ≤ r such that x ∈ A
i1∩. . .∩A
is. The definition of e δ implies that there exists an i
0∈ {i
1, . . . , i
s} such that dist(x, A
ci0) = e δ(x) and so x ∈ A
δi0, which was to be proved.
(
1) The overbar denotes closure.
The partition is now easily constructed. Let χ
ibe the characteristic function of the set A
iand let
ϕ(x) =
e
−1/(1−|x|2), |x| < 1,
0, |x| ≥ 1.
For x ∈ U \ Z we define (2) η
i(x) = d
\
Rp
δ(y) 4
−2pϕ
4(y − x) δ(y)
χ
i(y) dy where
d =
\Rp
ϕ(x) dx
−1sup
x,y∈U1
J
4(y − x) δ(y)
·
δ(y) 4
2p.
The integral in (2) makes sense since for a fixed x ∈ U \ Z the set {y :
|y − x| ≤ δ(x)} is compact and does not intersect Z. We also observe that
(3) d
\
Rd
δ(y) 4
−2pϕ
4(y − x) δ(y)
dy ≥ 1 for x ∈ U \ Z,
which follows by substitution z(y) = 4(y − x)/δ(y) from the fact that z is
“onto” R
pand the integrand is non-negative.
From (2) we see that η
i∈ C
∞(U \ Z) (since δ(y) > 0 on U \ Z) and (supp η
i) ∩ K ⊂ A
i. It remains to normalize η
iso we put
ϕ
i= η
iP
r i=1η
i.
The above properties of η
iimply in view of (3) that the ϕ
isatisfy items (a)–(c) of Definition 3. To prove (d) we first show that for every multiindex α there exist positive constants C and a such that
(4)
∂
αϕ
i(x)
∂x
α≤
C
(dist(x, Z))
afor x ∈ K \ Z, i = 1, . . . , r.
Inequality (4) is proved by induction on the length |α| of α. For α = 0 we see from the definition of ϕ
ithat
|ϕ
i(x)| ≤ 1, x ∈ U \ Z.
We now prove (4) for α = (1, 0
′), 0
′∈ R
p−1. Set h = P
ri=1
η
i. Since h ≥ 1 on U \ Z by (3), we have
∂ϕ
i∂x
1≤
∂η
i∂x
1+
X
r j=1∂η
j∂x
1.
Thus it suffices to prove (4) for the functions η
iinstead of ϕ
i.
By differentiating (2) we find
∂η
i∂x
1= d
\
U
4 δ(y)
2p+1∂
∂z
1ϕ
4(y − x) δ(y)
χ
i(y) dy for x ∈ K \ Z.
Hence by (1) for x ∈ K \ Z we get
∂η
i(x)
∂x
1≤ C
2\
U
1
(dist(y, Z))
a(2p+1)e∂ϕ
∂z
14(y − x) δy
χ
i(y) dy
≤ C
3\
U ∩{y:|x−y|≤δ(y)/4}
dy
(dist(y, Z))
ea(2p+1)≤ C
3\
U ∩{y:dist(y,Z)≥dist(x,Z)/2}
dy
(dist(y, Z))
a(2p+1)e≤ C
41
(dist(x, Z))
a(2p+1)e\
U
dy (where C
2, C
3, C
4are suitable positive constants).
To prove the penultimate inequality it is enough to show that {y : |x − y| ≤ dist(y, Z)/4} ⊂ {y : dist(y, Z) ≥ dist(x, Z)/2}, which is equivalent, after passing to complements, to
{y : dist(y, Z) < dist(x, Z)/2} ⊂ {y : |x − y| > dist(y, Z)/4}.
To prove the last inclusion suppose conversely that for a certain y such that dist(y, Z) < dist(x, Z)/2 we have |x − y| ≤ dist(y, Z)/4. Let w ∈ Z be such that dist(y, Z) = |y − w|. Then |y − w| < dist(x, Z)/2 and |x − y| <
dist(x, Z)/8, hence |x − w| <
58dist(x, Z), which is impossible since w ∈ Z.
Finally, we state a well-known general lemma which shows how (4) im- plies (d) of Definition 3.
Lemma 1. Let Z be a closed subset of R
p, K a compact subset of R
pand U an open neighbourhood of K. If a function ϕ ∈ C
∞(U \ Z) satisfies (4) for every α then for every function ψ ∈ C
0∞(K) flat on Z, we have
(i) ψϕ ∈ C
0∞(R
p) and is flat on Z ,
(ii) |∂
α(ψϕ)/∂x
α| ≤ Ckψk
mfor certain constants C > 0, m ∈ N depend- ing only on α where
kψk
m= X
|β|≤m
sup
x∈K
∂
βψ
∂x
β(x) .
P r o o f. This follows from Taylor’s formula (see [8], p. 154).
Remark 2. Since Theorem 1 has a local character its proof generalizes
easily to the case where M is an analytic manifold.
3. Theorems on extendability of invariant distributions. In what follows M will be a fixed G-manifold as in Section 1. We also retain all notation and definitions from [17] (e.g. K
α, N
αetc.)
Theorem 2. Let the set Z of singular orbits be hyperbolic in M. Let {N
α}
α∈Abe the Hausdorff partition of the manifold (M \ Z)/G. Suppose that
(a) for every non-singular orbit θ there exists an invariant neighbour- hood U
θsuch that π(U
θ) ⊂ N
αfor some α, π(U
θ)
Nαis compact and the complement of U
θin M is a semianalytic set,
(b) for every sequence ω
j∈ Ω
0p(π
−1(N
α)) convergent to zero in Ω
0p(M ), K
αω
jis convergent to zero locally uniformly with all derivatives on N
α.
Then every G-invariant distribution on M \ Z extends to a distribution on M .
P r o o f. Let u be an invariant distribution on M \Z. Then by Theorem 2 of [17] there exists a unique distribution {T
α}
α∈Aon N = (M \ Z)/G such that
u[ω] = T
α[K
αω], ω ∈ Ω
0p(π
−1(N
α)).
Let ω
j∈ Ω
0p(M \ Z), ω
j→ 0 in Ω
0p(M ) as j → ∞. Let K be a compact set containing all supp ω
j. Choose an open neighbourhood U
1of K with compact closure U
1. The sets {U
θ} form an invariant covering of U
1and by Proposition 2 we can select a finite subcovering {U
θi}
ri=1.
Next we apply the “manifold version” of Theorem 1 to obtain a partition of unity {ϕ
i}
ri=1on K \ Z subordinate to the covering {U
θi}
ri=1. Let α
i∈ A correspond to U
θias in (a). We observe that for every j,
u[ω
j] = X
r i=1T
αi[a
ij] where a
ij= K
αi(ϕ
iω
j).
Thus in order to prove that u[ω
j] → 0 it is enough to show that for every fixed i, a
ij→ 0 in Ω
0p−n(N
αi) as j → ∞. Since ω
j→ 0 in Ω
0p(M ) we infer from condition (d) of Definition 3 that for every i, ϕ
iω
j→ 0 in Ω
0p(M ).
From the definition of the operation K
αwe see that supp a
ij⊂ π(U
θi)
Nαi, which is compact by (a). From this and (b) we conclude that a
ij→ 0 in Ω
0p−n(N
αi) for every i = 1, . . . , r.
Now, we construct the required extension. To this end let U ⊂ M be an
open set with U compact. By the above, the sets Ω
0p(U \Z) ⊂ Ω
0p(U ) satisfy
the assumptions of the Hahn–Banach theorem. It follows that there exists
a distribution e u extending u|
U \Zto U . Taking successive open sets U and
gluing the distributions thus obtained we get the required extension. This ends the proof of the theorem.
Remark 2. The extension which exists by Theorem 2 need not be in- variant. In fact an example given in [3] shows that there exist invariant distributions which are extendable but which have no invariant extensions.
Theorem 3. Let the set Z be strongly hyperbolic. If for every sequence ω
j∈ Ω
0p(π
−1(N
α)) with ω
j→ ω
0in Ω
0p(M ) as j → ∞ the form K
αω
0is C
∞on N
αthen K
αω
jconverges to K
αω
0locally uniformly together with all derivatives.
P r o o f. Let ω
j∈ Ω
0p(π
−1(N
α)), ω
j→ ω
0in Ω
0p(M ). We have to show that L
tr(K
αω
j) → L
tr(K
αω
0) locally uniformly on N
αfor every C
∞linear differential operator L on N .
Let x ∈ N
αand let H be a coordinate system around x. We define a distribution δ
xH= δ
H(x)◦ H
−1where δ
ais the Dirac delta in R
p−nat the point a. Suppose that a
j= L
tr(K
αω
j) is not locally uniformly convergent to a
0= L
tr(K
αω
0) on N
α. Then there exists an ε
0> 0 such that for every j = 1, 2, . . . there exists an x
j∈ N
α\ B (see Definition 2) such that
(5) |δ
xHjj[L
tr(a
j) − L
tr(a
0)]| ≥ ε
0(H
ja coordinate system around x
j). Put
∆
j[η] = e
jδ
xHjj[L
tr(K
αη)] for η ∈ Ω
p0(M \ Z) where e
j= ± is such that ∆
j[a
j− a
0] ≥ ε
0.
We observe that ∆
jis a distribution on M \ Z with support in π
−1(x
j).
In view of Proposition 1, ∆
jextends to a distribution e ∆
jon M (because x
j6∈ B). By assumption if ω ∈ Ω
0p(π
−1(N
α)) (the closure of Ω
0p(π
−1(N
α)) in Ω
0p(M )) then K
αω is C
∞on N
α, hence there is a constant C
ωsuch that (6) |δ
xHjj[L
tr(K
αω)]| ≤ C
ω, j = 1, 2, . . .
From (6) we see that e ∆
j, j = 1, 2, . . . , satisfy the assumptions of the Banach–Steinhaus theorem on Ω
0p(π
−1(N
α)). It follows from that theorem that max
i∈N∆ e
iis a continuous operation on Ω
0p(π
−1(N
α)) (not a distribu- tion since max is not additive). Thus in particular max
i∈N∆
i[ω
j− ω
0] → 0 as j → ∞, which contradicts (5).
In an analogous way one proves the following “converse” of Theorem 2.
Theorem 4. Let Z be hyperbolic. If for every sequence ω
j∈ Ω
0p(π
−1(N
α)) such that ω
j→ ω
0in Ω
0p(M ), K
αω
0is of class C
∞on N
αand if every invariant distribution on M \ Z extends to a distribution on M then K
αω
jconverges to K
αω
0locally uniformly with all derivatives.
We now establish conditions under which (b) of Theorem 2 is satisfied.
Theorem 5. Let {(H
k, A
k)} be a family of coordinate systems covering M \ Z and such that:
(a) the coordinates H
k1, . . . , H
kp−nof the vector function H
kare constant along orbits in M ,
(b) H
ki, i = 1, . . . , p, extend to invariant analytic functions on M (de- noted by the same symbol ),
(c) for each k there exists an α
k∈ A such that π(A
k) ⊂ N
αk.
If ω
j∈ Ω
0p(M \ Z), supp ω
j⊂ A
k, ω
j→ 0 in Ω
0p(M ) then K
αkω
j→ 0 as j → ∞ locally uniformly with all derivatives on N
k.
P r o o f. Fix a coordinate system (H
k, A
k) and let α
kbe such that π(A
k)
⊂ N
αk.
In view of the Sobolev lemma ([10], p. 197) it suffices to show that locally K
αkω
j→ 0 in H
mfor all m (H
mis the Sobolev space). Let (Φ
k, π(A
k)) be the coordinates on N
αkinduced by (H
k, A
k) (see [17], p. 69). Define K = K
αk, H = H
k, A = A
k, s
i= H
i, i = 1, . . . , p − n, y
i= H
p−n+ifor i = 1, . . . , n. Then by (a), Kω
jhas the following form in the coordinate system Φ:
(Kω
j)(s
1, . . . , s
p−n) =
\
Rn
ω
jJH
◦ H
−1(s
1, . . . , s
p−n, y
1, . . . , y
n) dy where JH is the Jacobian of H. Let us compute
∂
∂s
1(Kω
j)(s) =
\
Rn
∂
∂s
1ω
jJH
◦ H
−1(s, y)
dy.
We have (7)
∂
∂s
1ω
jJH
◦ H
−1(s, y)
◦ H = ω
jw
0(JH)
2+ X
p i=1∂ωj
∂xi
w
i(JH)
2.
where in view of (b), w
i, i = 0, 1, . . . , p, are analytic functions in a neigh- bourhood of A. Let Z
1be the set of zeros of the function JH. Then Z
1is disjoint from A and from the Lojasiewicz inequality
|JH(x)| ≥ C(dist(x, Z
1))
a, x ∈ D,
where D is a compact subset of M containing all supp ω
jand C, a are positive constants. Since ω
jare flat on Z
1we know from Lemma 1 that there are constants e C, e C such that e
(8)
ω
jJH
≤ Ckω e
jk
m,
1 JH
∂ω
j∂x
i≤ Ckω ee
jk
mfor some m ∈ N.
Set
(9) ω
j= ω
jw
0JH + 1 JH
X
p j=1∂ω
j∂x
iw
i.
Then from (7) and (8) we see that (∂/∂s
1)Kω
j= Kω
jwith ω
j∈ Ω
0p(M \Z) and ω
j→ 0 in Ω
0p(M ).
Now it is easy to show that
\
∂
∂s
1Kω
jds → 0.
Namely we have
\
∂
∂s
1Kω
jds =
\
|Kω
j| ds ≤
\
K|ω
j| ds =
\
|ω
j| → 0.
Take a point θ ∈ N
αkand a coordinate system e Φ around θ in N
αk. Sup- pose that e Φ is induced by one of the coordinate systems (H
k, A
k). Denote that system by ( e H, e A). Let h be the characteristic function of an invariant open neighbourhood U of θ such that π(U )
Nα⊂ π( e A). Then K(hω
j) = Kω
jin a neighbourhood of θ and supp K(hω
j) ⊂ π( e A). We shall prove that K(hω
j) is convergent to zero on π(U ) in H
mfor every m.
Denote by ∂/∂es
ithe differentiations in the coordinate system e Φ. Let Ψ = e H ◦ H
−1. Then the transition mapping R for Φ and e Φ has the form
R(s) = (Ψ
1(s, y), . . . , Ψ
p−n(s, y))
where y is an arbitrary point such that (s, y) belongs to the domain of Ψ . Thus the Jacobi matrix DR has the form
(DR)(s) = (b
ij(s))
i,j=1,...,p−nwhere b
ij(s) =
∂Ψ∂sij
(s, y) and is independent of y. Let (a
ij) be the inverse matrix to (b
ij). Then to the differentiation ∂/∂es
1in the coordinate system Φ there corresponds in the coordinate system Φ the operator e
L =
p−n
X
i=1
a
i1∂
∂s
i(
∂ e∂s1
(ϕ ◦ R
−1) = (Lϕ) ◦ R
−1). We want to show that a
ij◦ H is of the form
A
ij/B
ijwhere A
ijand B
ijare analytic functions of M and B
ijcan be zero
on the set on which all hω
jare flat. To this end we observe that it follows
from the forms of the mappings H and e H and the formula for the inverse
of a matrix that b
ij◦ H = D
ij/JH where D
ijis an analytic function on M .
Hence
a
ij◦ H =
C
ij(JH)
p−n−1B
ij(JH)
p−nwhere C
ijand B
ijare analytic functions on M .
To obtain the required representation observe that B
ijcan vanish on the set on which all hω
jare flat. This follows from the fact that (JR) ◦ H = B
ij/(JH)
p−nis constant along orbits and JH is not zero on A.
We compute
LK(hω
j)(s) =
p−n
X
i=1
a
i1∂
∂s
iK(hω
j)(s) =
p−n
X
i=1
a
i1K(hω
j)(s)
=
p−n
X
i=1
\
Rn
a
i1(s)
hω
jJH
◦ H
−1(s, y) dy
=
p−n
X
i=1
\
Rn
A
i1hω
jB
i1JH
◦ H
−1(s, y) dy.
Define
e ω
j=
p−n
X
i=1
A
i1hω
jB
i1.
In the same way as in the case of e ω
jwe show that e ω
j→ 0 in Ω
0p(M ) so that
\