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Małgorzata Filipczak, Tomasz Filipczak

On the comparison of the density type topologies generated by sequences and by functions

Abstract. In the paper we investigate density type topologies generated by functions f satisfying condition lim inf

x→0+ f(x)

x

> 0, which are not generated by any sequence.

2000 Mathematics Subject Classification: 54A10, 26A15, 28A05.

Key words and phrases: density points, density topology, comparison of topologies.

Through the paper we shall use standard notation: ℝ will be the set of real numbers, ℕ the set of positive integers, L the family of Lebesgue measurable subsets of ℝ and |E| the Lebesgue measure of a measurable set E. By Φ d (E) we shall denote the set of all Lebesgue density points of measurable set E (i.e. Φ d (E) = n x ∈ ℝ; lim h →0

+

|(x−h;x+h)∩E|

2h = 1 o

) and by T d the density topology consists of measurable sets satisfying E ⊂ Φ d (E). For any operators Φ, Ψ : L → L we write Φ ⊂ Ψ if Φ (E) ⊂ Ψ (E) for every E ∈ L. If Φ ⊂ Ψ and Φ 6= Ψ then we write Φ ⊈ Ψ.

We will consider two generalizations of Lebesgue density. First of them, called a density generated by a sequence, was introduced by J. Hejduk and M. Filipczak in [6]. For a convenience we will formulate definitions using decreasing sequences tending to zero, instead of nondecreasing sequences going to infinity.

Let e S be the family of all decreasing sequences tending to zero. We will denote sequences from e S by (a n ) or by hai. Let hai ∈ e S, E ∈ L and x ∈ ℝ. We shall say that x is an hai-density point of E (a right-hand hai-density point of E) if

n lim →∞

|E ∩ [x − a n ; x + a n ]|

2a n

= 1 ( lim

n →∞

|E ∩ [x; x + a n ]|

a n

= 1).

By Φ hai (E) (Φ + hai (E)) we will denote the set of all hai-density (right-hand hai-

density) points of E. In the same way one may define left-hand hai-density point of

E and the set Φ hai (E). Evidently, Φ hai (E) = Φ + hai (E) ∩ Φ hai (E).

(2)

In [6] it was proved that Φ hai is a lower density operator and the family T hai = 

E ∈ L; E ⊂ Φ hai (E)

is a topology containing the density topology T d . Moreover for a n = n 1 , Φ hai = Φ d

and T hai = T d .

For any pair of sequences hai and hbi from e S we denote by hai∪hbi the decreasing sequence consisting of all elements from hai and hbi. It is clear that hai ∪ hbi ∈ e S and that

Proposition 1 If Φ hai ⊂ Φ hbi then Φ hai∪hbi = Φ hai .

The second type of density we will observe are densities generated by functions.

We denote by A the family of all functions f : (0; ∞) → (0; ∞) such that (A1) lim

x→0

+

f (x) = 0, (A2) lim inf

x →0

+

f(x)

x < ∞, (A3) f is nondecreasing.

Let f ∈ A. We say that x is a right-hand f-density point of a measurable set E if

h→0 lim

+

|(x; x + h) \ E|

f (h) = 0.

By Φ + f (E) we denote the set of all right-hand f-density points of E. In the same way one may define left-hand f-density points of E and the set Φ f (E). We say that x is an f -density point of E if it is a right and a left-hand f-density point of E. By Φ f (E) we denote the set of all f-density points of E, i.e. Φ f (E) = Φ + f (E) ∩ Φ f (E).

For any f ∈ A, the family

T f = {E ∈ L; E ⊂ Φ f (E)}

forms a topology stronger than the natural topology on the real line (see [1, Th. 7]

and [4, Th. 1]).

Proposition 2 ([4, Prop. 4]) For each f, g ∈ A, an inclusion T f ⊂ T g holds if and only if Φ f ⊂ Φ g .

In [2] and [3] it has been shown that properties of f-density operator Φ f and f -density topology T f are strictly depended on lim inf

x →0

+

f(x)

x . In our paper we are interested in topologies generated by functions f ∈ A for which lim inf

x→0

+

f(x)

x > 0.

The family of all such functions we will denote by A 1 .

Topologies generated by functions from A 1 and from A \ A 1 have quite different

properties (for example they satisfy different separation axioms - see [3, Th. 5 and

(3)

Th. 7)]). On the other hand for any function f from A 1 properties of T f are similar to properties of topologies generated by sequences, so similar to properties of the density topology T d (compare [4, Th. 3], [9], [7] and [8]). Moreover

Proposition 3 ([4, Th. 5]) For any sequence hsi ∈ e S, the function f defined by a formula

f (x) = s n for x ∈ (s n+1 ; s n ] belongs to A 1 and Φ hsi = Φ f .

Corollary 4 For each hai , hbi ∈ e S, an inclusion T hai ⊂ T hbi holds if and only if Φ hai ⊂ Φ hbi .

In [4] we have constructed a function f ∈ A 1 such that Φ f 6= Φ hsi for each hsi ∈ e S. We will remain the definition of that function, omitting the proof, because we will construct a similar one in Theorem 11.

Example 5 ([4, Th. 6]) Let us define sequences hwi = (2, 2, 3, 3, 3, 4, 4, 4, 4, . . .) ,

hri = (1, 2, 1, 2, 3, 1, 2, 3, 4, . . .) , a 0 = 1, a n = a n −1

w 2 n for n ­ 1, b n = a n w n = a n −1

w n for n ­ 1.

Evidently

n lim →∞

a n −1

b n

= lim

n →∞

b n

a n = ∞.

The function f defined by a formula f (x) =

 a n −1 for x ∈ (b n ; a n −1 ] , b n r n for x ∈ (a n ; b n ] . belongs to A 1 and Φ f 6= Φ hsi for each hsi ∈ e S.

The function constructed above proves that the family 

T f ; f ∈ A 1 is big- ger than n

T hsi ; hsi ∈ e S o

. We will show that there exist continuum topologies from

 T f ; f ∈ A 1

\ n

T hsi ; hsi ∈ e S o

and that for any pair of sequences hai , hbi ∈ e S satis- fying T hai ⊈ T hbi there is a function f ∈ A 1 such that T hai ⊈ T f ⊈ T hbi and T f 6= T hsi

for hsi ∈ e S.

Set

f α (x) = f  x α

 and s α (n) = αs (n)

for f ∈ A 1 , hsi ∈ e S and α > 0. Obviously f α ∈ A 1 and hs α i ∈ e S.

(4)

Proposition 6 If Φ f = Φ hsi then Φ f

α

= Φ hs

α

i .

Proof It is sufficient to prove that for any measurable set E 0 ∈ Φ + f

α

(E) ⇐⇒ 0 ∈ Φ + hs

α

i (E) . If 0 ∈ Φ + f

α

(E) then

(0; x) ∩ α 1 E 0

f (x) =

1

α |(0; αx) ∩ E 0 | f α (αx)

x →0+

−→ 0,

and so 0 ∈ Φ + f 1

α E  = Φ + hsi α 1 E  . Hence

|(0; s α (n)) ∩ E 0 | s α (n) =

(0; s (n)) ∩ α 1 E 0 s (n)

n →∞

−→ 0,

which gives 0 ∈ Φ + hs

α

i (E).

Conversely, if 0 ∈ Φ + hs

α

i (E) then (0; s (n)) ∩ α 1 E 0

s (n) = | (0; s α (n)) ∩ E 0 | s α (n)

n→∞ −→ 0,

and consequently 0 ∈ Φ + hsi α 1 E  = Φ + f α 1 E  . Thus

|(0; x) ∩ E 0 |

f α (x) = α 0; α x 

α 1 E 0

f x α  x→0+ −→ 0,

which implies 0 ∈ Φ + f

α

(E).

Corollary 7 If Φ f / n

Φ hsi ; hsi ∈ e S o

then Φ f

α

/ n

Φ hsi ; hsi ∈ e S o

for any α > 0.

Theorem 8 If f is the function defined in Example 5 then Φ f

α

⊈ Φ f

β

for any α > β > 1.

Proof Since f is nondecreasing, we have f α ¬ f β and Φ f

α

⊂ Φ f

β

. Let (n i ) be an increasing sequence of positive integers such that r n

i

= 1 for every i. Define

E = ℝ \ [ i=1

βb n

i

; βb n

i

w n

i

 .

It is sufficient to show that

0 ∈ Φ f

β

(E) \ Φ f

α

(E) .

(5)

Without loss of generality, we can assume that for any n βa n < b n and βb n < αb n < βb n w n < a n −1 . If x ∈ (βb n

i

; βa n

i

−1 ] for some i then

(1) |(0; x) ∩ E 0 |

f β (x) ¬ βb n

i

w n

i

f 

x β

 = βb n

i

w n

i

a n

i

−1

= β

w n

i

.

If x ∈ (βa n

i

; βb n

i

] for some i then

(2) |(0; x) ∩ E 0 |

f β (x) < a n

i

f 

x β

 = a n

i

r n

i

b n

i

= 1 w n

i

.

If x ∈ (βa p ; βb p −1 ] and n i < p < n i+1 for some i then

(3) |(0; x) ∩ E 0 |

f β (x) < a p

r p b p ¬ 1 w p

. From (1)-(3) we conclude that 0 ∈ Φ f

β

(E).

On the other hand for x i = αb n

i

|(0; x i ) ∩ E 0 |

f α (x i ) ­ |(βb n

i

; αb n

i

)|

f (b n

i

) = (α − β) b n

i

r n

i

b n

i

= α − β > 0,

and consequently 0 / ∈ Φ f

α

(E).

In [4, Th. 1] it has been proved that for each function f ∈ A there is a continuous function g ∈ A such that Φ f = Φ g . Thus there is at most continuum different f- density topologies. Combining this result with Corollary 4, Corollary 7 and Theorem 8 we obtain

Corollary 9 The family 

T f ; f ∈ A 1

\ n

T hsi ; hsi ∈ e S o

has cardinality continuum.

In the next theorem we will compare densities generated by sequences. Let us formulate a useful lemma from [5]. Fix hai and hbi from e S. There is an unique sequence (k n ) of positive integers such that

b n ∈ (a k

n

+1 ; a k

n

]

for each n with b n < a 1 . From now on (k n ) will denote this unique sequence.

Lemma 10 ([5, Th. 7]). The following conditions are equivalent (a) Φ hai ⊂ Φ hbi .

(b) For arbitrary increasing sequence (n i ) of positive integers lim inf

i→∞

a k

ni

b n

i

< ∞ or lim inf i→∞ b n

i

a k

ni

+1 = 1.

(6)

Theorem 11 Let hai , hbi ∈ e S. If Φ hbi ⊈ Φ hai then there is f ∈ A 1 such that Φ hbi ⊂ Φ f ⊂ Φ hai and Φ f 6= Φ hsi for hsi ∈ e S.

Proof By Proposition 1 we can asume that hai is a subsequence of hbi. Since Φ hai ⊈ Φ hbi , there exists an increasing sequence (n i ) of positive integers such that

i lim →∞

a k

ni

b n

i

= ∞ and M = lim inf i

→∞

b n

i

a k

ni

+1 > 1.

Let us denote

β =



4

M ; M < ∞

2 ; M = ∞ .

Replacing (n i ) by a subsequence we can assume that (k n

i

) is increasing and for every i

(4) a b

kni

ni

> i 2 , a b

ni

kni +1

> β 3 and a b

ni

kni +1

< β 5 if M < ∞.

Let us define

hci = hai ∪ (b n

i

) ,

hri = (1, 2, 1, 2, 3, 1, 2, 3, 4, . . .) , g 1 (x) = a n for x ∈ (a n+1 ; a n ] , g 2 (x) = c n for x ∈ (c n+1 ; c n ] , g 3 (x) = b n for x ∈ (b n+1 ; b n ] ,

f (x) =

 r i b n

i

for x ∈ a k

ni

+1 ; b n

i

 , g 1 (x) for x / S

i=1 a k

ni

+1 ; b n

i

 .

Since 1 ¬ r i ¬ i 2 , f ∈ A 1 and g 3 ¬ g 2 ¬ f ¬ g 1 . Thus

Φ hbi = Φ g

3

⊂ Φ hci = Φ g

2

⊂ Φ f ⊂ Φ g

1

= Φ hai .

We will show that Φ f 6= Φ hsi for hsi ∈ e S. Suppose, contrary to our claim, that there is hsi ∈ e S such that

(5) Φ f = Φ hsi .

Let us consider the sets

T = 

i ∈ ℕ; ∃ m ∈ℕ s m 

β 3 a k

ni

+1 ; ib n

i

 , R = {r i ; i ∈ T } .

We will prove that the set R is bounded. Suppose it is not true and so T is infinite.

Let (t i ) be an increasing sequence consisting of all elements from T , i.e.

T = {t i ; i ∈ ℕ} .

(7)

Let m i be a fixed positive integer such that s m

i

h

β 3 a k

nti

+1 ; t i b n

ti

i .

We will show that

(6) s m

i

< 2b n

ti

for almost every i. Suppose on the contrary that there is an increasing sequence (p i ) of positive integers such s m

pi

­ 2b n

tpi

for every i. Hence

a k

ntp

i

s m

pi

­ t 2 p

i

b n

tpi

t p

i

b n

tpi

= t p

i

­ p i ­ i

and so

i lim →∞

a k

ntp

i

s

mpi

= ∞ and

lim inf

i →∞

s

mpi

b n

tpi

­ 2.

This, by Lemma 10, contradicts the assumption that Φ hci ⊂ Φ hsi and finishes the proof of (6).

Now we show that there are real numbers ε > δ > 0 such that (7) a k

nti

+1 < δb n

ti

< εb n

ti

< s m

i

for almost every i. If M = lim inf

i →∞

b

ni

a

kni +1

< ∞ then by (4) it is sufficient to set ε = β 1

2

and δ = β 1

3

. If M = ∞, then obviously it is sufficient to show that for some positive ε inequality

εb n

ti

< s m

i

holds for almost every i. Suppose on the contrary that there is an increasing sequence (p i ) of positive integers such is m

pi

< b n

tpi

for every i. Hence

i lim →∞

b n

tpi

s m

pi

= ∞.

and

lim inf

i →∞

s m

pi

a k

ntp

i

+1 ­ β 3 > 1.

which also contradicts the assumption that Φ hci ⊂ Φ hsi and ends the proof of (7).

By our assumptions, the set R is not bounded. Thus there exists an increasing sequence (p i ) of positive integers such that

i→∞ lim r t

pi

= ∞.

(8)

Put

A = [ i=1

 δb n

tpi

; εb n

tpi

 .

From (6) and (7) it follows that A ∩ 0; s m

pi



s m

pi

­ εb n

tpi

− δb n

tpi

2b n

tpi

= ε − δ 2 > 0 for almost every i, and so

(8) 0 / ∈ Φ + hsi (A 0 ).

We will show that 0 ∈ Φ + f (A 0 ). Let x ∈ (a j ; a j −1 ]. If j = k n

tpi

for some i then

(9) |A ∩ (0; x)|

f (x) ¬ εb n

tpi

r t

pi

b n

tpi

= ε r t

pi

.

On the other hand if k m

ni

< j < k m

ni+1

for some i then

(10) |A ∩ (0; x)|

f (x) ¬ εb n

tpi+1

a j+1 ¬ εb n

tpi+1

a k

ntp

i+1

¬ ε

t 2 p

i+1

¬ ε (i + 1) 2 .

From (5), (9) and (10) it follows that 0 ∈ Φ + f (A 0 ) = Φ + hsi (A 0 ), contrary to (8). Hence we conclude that R is bounded.

Let L be a positive integer such that L > sup R,

(p i ) be an increasing sequence of positive integers for which r p

i

= L

and

B = [ i=1

 1

β b n

pi

; b n

pi

 .

Since

B ∩ 0; b n

pi



f (b n

pi

) ­ b n

pi

β 1 b n

pi

r p

i

b n

pi

= 1 − 1 β

L > 0,

(11) 0 / ∈ Φ + f (B 0 ).

We will prove that 0 ∈ Φ + hsi (B 0 ). By definition of (p i ), p i ∈ T for every i and / consequently

s m / h

β 3 a k

npi

+1 ; p i b n

pi

i

(9)

for m, i ∈ ℕ. Let us consider any term s m of hsi. There is a positive integer j such that s m ∈ (a j ; a j−1 ]. If j = k n

pi

for some i then

s m < β 3 a k

npi

+1 or s m > p i b n

pi

. In the first case we have

(12) |B ∩ (0; s m )|

s m ¬ b n

pi+1

a k

npi

+1 ¬ b n

pi+1

a k

npi+1

¬ 1

p 2 i+1 ¬ 1 (i + 1) 2 , and in the second

(13) |B ∩ (0; s m )|

s m ¬ b n

pi

p i b n

pi

¬ 1 i . Moreover, if k n

pi

< j < k n

pi+1

, then

(14) |B ∩ (0; s m )|

s m ¬ b n

pi+1

a j+1 ¬ b n

pi+1

a k

npi+1

¬ 1

p 2 i+1 ¬ 1 (i + 1) 2 .

From (5) and (12)-(14) it follows that 0 ∈ Φ + hsi (B 0 ) = Φ + f (B 0 ), contrary to (11).

Corollary 12 If T hbi ⊈ T hai then there is f ∈ A 1 such that T hbi ⊂ T f ⊂ T hai and the topology T f is generated by no sequence.

References

[1] M. Filipczak, T. Filipczak, A generalization of the density topology, Tatra Mt. Math. Publ.

34 (2006), 37–47.

[2] M. Filipczak, T. Filipczak, Remarks on f-density and ψ-density, Tatra Mt. Math. Publ. 34 (2006), 141–149.

[3] M. Filipczak, T. Filipczak, On f-density topologies, Topology Appl. 155 (2008), 1980–1989.

[4] M. Filipczak, T. Filipczak, Density topologies generated by functions and by sequences, Tatra Mt. Math. Publ. 40 (2008), 103–115.

[5] M. Filipczak, T. Filipczak, J. Hejduk, On the comparison of the density type topology, Atti Sem. Mat. Fis. Univ. Modena 52 (2004), 37–46.

[6] M. Filipczak, J. Hejduk, On topologies associated with the Lebesgue measure, Tatra Mt. Math.

Publ. 28 (2004), 187–197.

[7] J.C.Oxtoby, Measure and Category, Springer-Verlag, New York Heidelberg Berlin, 1980.

[8] S. Scheinberg, Toplogies which generate a complete measure algebra, Adv. Math. 7 (1971), 231–239.

[9] W. Wilczyński, Density topologies, in: Handbook of Measure Theory, Elsevier Science B. V.,

Amsterdam, 2002, 675–702.

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Małgorzata Filipczak

Faculty of Mathematics and Computer Sciences, Łódź University ul. Stefana Banacha 22, 90-238 Łódź, Poland

E-mail: malfil@math.uni.lodz.pl Tomasz Filipczak

Institute of Mathematics, Łódź Technical University ul. Wólczańska 215, 93-005, Łódź, Poland

E-mail: tfil@math.uni.lodz.pl

(Received: 20.06.2008)

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