ON FINITE ELEMENT UNIQUENESS STUDIES FOR COULOMB’S FRICTIONAL CONTACT MODEL
P
ATRICKHILD
∗∗
Laboratoire de Mathématiques, Université de Savoie, CNRS UMR 5127, 73376 Le Bourget-du-Lac, France, e-mail:
hild@univ-savoie.frWe are interested in the finite element approximation of Coulomb’s frictional unilateral contact problem in linear elasticity.
Using a mixed finite element method and an appropriate regularization, it becomes possible to prove existence and unique- ness when the friction coefficient is less than Cε
2| log(h)|
−1, where h and ε denote the discretization and regularization parameters, respectively. This bound converging very slowly towards 0 when h decreases (in comparison with the already known results of the non-regularized case) suggests a minor dependence of the mesh size on the uniqueness conditions, at least for practical engineering computations. Then we study the solutions of a simple finite element example in the non- regularized case. It can be shown that one, multiple or an infinity of solutions may occur and that, for a given loading, the number of solutions may eventually decrease when the friction coefficient increases.
Keywords: Coulomb’s friction law, finite elements, mesh-size dependent uniqueness conditions, non-uniqueness example
1. Introduction and Problem Set-Up
Coulomb’s friction model is currently chosen in the nu- merical approximation of contact problems arising in structural mechanics. From a mathematical point of view, the study of the continuous model in elastostatics using the associated variational formulation obtained in (Du- vaut and Lions, 1972) leads to existence results when the friction coefficient is sufficiently small (Eck and Jarušek, 1998; Jarušek, 1983; Kato, 1987; Neˇcas et al., 1980). As regards the associated finite element model, it was proved in (Haslinger, 1983; 1984) that it always admits a solu- tion and that the solution is unique provided that the fric- tion coefficient is lower than a positive value vanishing as the discretization parameter decreases. Also in (Haslinger, 1983), a convergence result of the finite element model to- wards the continuous model was established. Besides, in the finite dimensional context, numerous studies and ex- amples of non-uniqueness using truss elements were ex- hibited, proving that the problem is in general not well posed (Alart, 1993; Janovský, 1981; Klarbring, 1990).
Our first aim in this paper is to study the influence of a specific regularization (i.e. the smoothing of the abso- lute value involved in the friction model) on the unique- ness conditions for the discrete problem. We consider a mixed finite element method in Section 2 and, denoting by h and ε the discretization and the regularization pa- rameters, respectively, we show in Section 3 that the prob- lem admits a unique solution if the friction coefficient is less than Cε
2| log(h)|
−1, and we notice that a bound of
only Ch
12can be obtained in the case of the exact model (i.e. when ε = 0). As a consequence, we note that if ε is chosen as a parameter slowly decreasing towards zero (as h decreases), then the bound of the non-regularized case becomes more satisfactory than the one arising from the exact model.
Our second aim, in Section 4, is to choose a par- ticular case of a finite dimensional problem in the non- regularized case: a simple example using finite elements.
We study this problem and show that it may admit one, multiple or an infinity of solutions. Such an example com- pletes and illustrates the already known results using truss elements, especially (Klarbring, 1990).
Let us now consider an elastic body occupying in the initial configuration a bounded subset Ω of R
2. The boundary ∂Ω of the domain Ω is supposed to be Lips- chitz and consists of three non-overlapping parts Γ
D, Γ
Nand Γ
C. The unit outward normal on ∂Ω is denoted by n = (n
1, n
2) and we set t = (n
2, −n
1). The body is submitted to volume forces f = (f
1, f
2) ∈ (L
2(Ω))
2on Ω and to surface forces F = (F
1, F
2) ∈ (L
2(Γ
N))
2on Γ
N. The part Γ
Dis embedded and we suppose that the surface measure of Γ
Ddoes not vanish. Initially, the body is in contact with a rigid foundation on the straight line segment Γ
C.
The unilateral contact problem with Coulomb’s fric-
tion consists in finding the displacement field u =
(u
i), 1 ≤ i ≤ 2 and the stress tensor field σ =
(σ
ij), 1 ≤ i, j ≤ 2, satisfying the following condi-
tions (1)–(4):
div σ(u) + f = 0 in Ω, σ(u)n = F on Γ
N, u = 0 on Γ
D,
(1)
where (div σ(u))
i= σ
ij,j, 1 ≤ i ≤ 2, the notation
,jdenotes the j-th partial derivative and the summation con- vention of repeated indices is adopted. The stress tensor field is linked to the displacement field by the constitutive law of linear elasticity
σ
ij(u) = λε
kk(u)δ
ij+ 2µε
ij(u), (2) where λ and µ are positive Lamé coefficients and ε
ij(u) = (1/2)(u
i,j+ u
j,i) denotes the linearized strain tensor field.
On the boundary ∂Ω, we write σ(u)n = σ
n(u)n + σ
t(u)t and u = u
nn + u
tt. Let F > 0 stand for the friction coefficient on Γ
C. The conditions on the contact zone Γ
Care as follows:
u
n≤ 0, σ
n(u) ≤ 0, σ
n(u) u
n= 0, (3)
|σ
t(u)| ≤ F |σ
n(u)|, |σ
t(u)| − F |σ
n(u)|u
t= 0, σ
t(u) u
t≤ 0. (4) Conditions (3) express unilateral contact and condi- tions (4) represent Coulomb’s friction. The closed convex cone K of admissible displacements is a subset in the Sobolev space (H
1(Ω))
2of the displacement fields sat- isfying the embedding and the non-penetration conditions
K = n
v = (v
1, v
2) ∈ V , v
n≤ 0 on Γ
Co , (5) where
V = n
v = (v
1, v
2) ∈ H
1(Ω)
2, v = 0 on Γ
Do . As is done in (Neˇcas et al., 1980), we consider the map- ping Φ : M → M with
M = n
α ∈ H
−12(Γ
C), α ≥ 0 o ,
defined for all g ∈ M as Φ(g) = −σ
n(u(g)), where u(g) ∈ K is the unique solution of the variational in- equality
u(g) ∈ K, Z
Ω
σ
iju(g) ε
ijv − u(g) dΩ + hF g, |v
t| − |u
t(g)|i
ΓC≥ Z
Ω
f
iv
i− u
i(g) dΩ
+ Z
ΓN
F
iv
i−u
i(g) dΓ, ∀v ∈ K, (6)
where h·, ·i
ΓCdenotes the duality pairing between the fractional Sobolev space H
12(Γ
C) (Adams, 1975) and its dual space H
−12(Γ
C). Following (Neˇcas et al., 1980;
Haslinger et al., 1996), a weak solution of the unilateral contact problem with Coulomb’s friction is a pair (u, γ), where γ is a fixed point of Φ and u is the unique solu- tion of the problem (6) with g = γ.
The first existence result for the unilateral contact problem with Coulomb’s friction in the case of a suffi- ciently small friction coefficient F was proved in (Neˇcas et al., 1980). Generalizations and/or improvements were established in (Eck and Jarušek, 1998; Jarušek, 1983;
Kato, 1987). The uniqueness seems to remain an open problem.
2. The Discrete Problem
We discretize the domain Ω with a family of triangula- tions ( T
h)
h, where the notation h > 0 stands for the dis- cretization parameter representing the greatest diameter of a triangle in T
h. The chosen space of finite elements of degree one is
V
h= n
v
h; v
h∈ C (Ω)
2, v
h|
T∈ (P
1(T ))
2∀T ∈ T
h, v
h= 0 on Γ
Do ,
where C (Ω) and P
1(T ) denote the space of continuous functions on Ω and the space of polynomial functions of degree one on T , respectively. We assume that the fam- ilies of monodimensional traces of triangulations on Γ
Care quasi-uniform in order to use inverse inequalities (Cia- rlet, 1991). Let W
hbe the range of V
hby the normal trace operator on Γ
C:
W
h= n
µ
h; µ
h= v
h|
ΓC· n, v
h∈ V
ho . Clearly, the space W
hinvolves functions which are con- tinuous and piecewise of degree one. We define M
has the closed convex cone of Lagrange multipliers express- ing non-negativity:
M
h= n
µ
h∈ W
h, µ
h≥ 0 o . For any u and v in (H
1(Ω))
2, define
a(u, v) = Z
Ω
σ(u) : ε(v) dΩ,
L(v) = Z
Ω
f · v dΩ + Z
ΓN
F · v dΓ.
Finally, let us mention that we still keep the notation v
h=
v
hnn + v
htt on the boundary ∂Ω, for any v
h∈ V
h.
To approximate Coulomb’s frictional contact prob- lem, we choose a mixed finite element method with a non- negative parameter ε regularizing the absolute value (the case ε = 0 corresponds to the non-regularized problem).
As in the continuous framework (6), the approximated problem requires the introduction of an intermediate set- ting with a given slip limit g
h∈ M
h. It consists in finding u
h∈ V
hand λ
h∈ M
hsuch that
a(u
h, v
h− u
h) + Z
ΓC
λ
h(v
hn− u
hn) dΓ +
Z
ΓC
F g
hq
v
ht2+ ε
2− q
u
2ht+ ε
2dΓ
≥ L(v
h− u
h), ∀v
h∈ V
h, Z
ΓC
(µ
h− λ
h)u
hndΓ ≤ 0, ∀µ
h∈ M
h.
(7)
In what follows, the problem (7) will be denoted by P
ε(g
h).
Remark 1. It can be checked that if (u
h, λ
h) solves (7), then u
his also a solution of the variational inequality which consists in finding u
h∈ K
hsatisfying
a(u
h, v
h− u
h) +
Z
ΓC
F g
hq
v
ht2+ε
2− q
u
2ht+ε
2dΓ ≥ L(v
h− u
h) for all v
h∈ K
h. Here K
hstands for a finite dimen- sional approximation of K defined in (5):
K
h= n
v
h∈ V
h, Z
ΓC
µ
hv
hndΓ ≤ 0, ∀µ
h∈ M
ho .
Problem P
ε(g
h) is also equivalent to finding a saddle-point (u
h, λ
h) ∈ V
h× M
hsatisfying
L (u
h, µ
h) ≤ L (u
h, λ
h) ≤ L (v
h, λ
h),
∀v
h∈ V
h, ∀µ
h∈ M
h, where
L (v
h, µ
h) = 1
2 a(v
h, v
h) + Z
ΓC
µ
hv
hndΓ
+ Z
ΓC
F g
hq
v
ht2+ ε
2dΓ − L(v
h).
From the results concerning saddle-point problems ob- tained in (Haslinger et al., 1996), the existence of such a saddle-point follows. Moreover, the V -ellipticity of a(·, ·) implies that the first argument u
his unique. Be- sides, if for any µ
h∈ W
hone has
Z
ΓC
µ
hv
hndΓ = 0, ∀v
h∈ V
h=⇒ µ
h= 0, (8)
then the second argument λ
his unique and P
ε(g
h) ad- mits a unique solution. Note that condition (8) is fulfilled because the space W
hcoincides with the space obtained from V
hby the normal trace operator on Γ
C.
It becomes then possible to define two maps: the first one denoted by Ψ
εhyielding the first component (i.e.
Ψ
εh(g
h) = u
h), and the other denoted by Φ
εhsuch that
Φ
εh: M
h−→ M
h, g
h7−→ λ
h,
where (u
h, λ
h) is the solution to P
ε(g
h). The intro- duction of this map allows us to define a solution to Coulomb’s discrete frictional contact problem.
Definition 1. A solution to Coulomb’s discrete regular- ized (resp. non-regularized) frictional contact problem is a solution to P
ε(λ
h) with ε > 0 (resp. ε = 0), where λ
h∈ M
his a fixed point of Φ
εh.
Set
V ˜
h= n
v
h∈ V
h, v
ht= 0 on Γ
Co . It is easy to check that the definition of k · k
−12,h
given by
kνk
−12,h
= sup v
h∈V
˜hZ
ΓC
νv
hndΓ kv
hk
1(9)
is a norm on W
h(since the condition (8) holds). The notation k · k
1represents the (H
1(Ω))
2-norm.
3. Existence and Uniqueness Studies
We are now interested in the existence and uniqueness study for the discrete problem. In order to establish the ex- istence, it suffices to show that the mapping Φ
εhadmits a fixed point in M
hby using Brouwer’s theorem. The uniqueness is ensured if the mapping is contractive. Such a technique was already used in the non-regularized case with discontinuous and piecewise constant Lagrange mul- tipliers (Haslinger, 1983; 1984). Our aim is to study the regularized case (and also the non-regularized one) when using Lagrange multipliers which are piecewise continu- ous of degree one.
Theorem 1. Let ε > 0. The following results hold:
(Existence) For any positive F , there exists a solution to Coulomb’s discrete regularized frictional contact prob- lem.
(Uniqueness) Assume that Γ
D∩ Γ
C= ∅. If F ≤
Cε
2| log(h)|
−1, then the problem admits a unique solu-
tion. The positive constant C depends on neither h
nor ε.
Proof. Let (u
h, λ
h) be the solution to P
ε(g
h). Taking v
h= 0 in (7) gives
a(u
h, u
h) + Z
ΓC
λ
hu
hndΓ
− Z
ΓC
F g
hε −
q
u
2ht+ ε
2dΓ ≤ L(u
h). (10)
Since g
h≥ 0, ε − pu
2ht+ ε
2≤ 0, and according to Z
ΓC
λ
hu
hndΓ = 0,
it follows from (10), the V -ellipticity of a(·, ·) and the continuity of L(·) that
αku
hk
21≤ a(u
h, u
h) ≤ L(u
h) ≤ Cku
hk
1, where α stands for the ellipticity constant of a(·, ·). Here, the constant C depends on the external loads f and F . Therefore using the trace theorem yields
ku
htk
H12(ΓC)
≤ C
0ku
hk
1≤ CC
0α . (11) Besides, the equality in (7) implies
a(u
h, v
h) + Z
ΓC
λ
hv
hndΓ = L(v
h), ∀v
h∈ ˜ V
h. Denoting by M
0the continuity constant of a(·, ·) yields Z
ΓC
λ
hv
hndΓ ≤ M
0ku
hk
1kv
hk
1+Ckv
hk
1, ∀v
h∈ ˜ V
h. As a result,
kλ
hk
−12,h
≤ M
0ku
hk
1+ C ≤ M
0α + 1
C.
So, we conclude that kΦ
εh(g
h)k
−12,h
≤ C
0, ∀g
h∈ M
h, (12) where C
0only depends on the applied loads f , F , and on the continuity and ellipticity constants of a(·, ·).
The existence result of Theorem 1 consists now in showing that the mapping Φ
εhis continuous.
Let (u
h, λ
h) and (u
h, λ
h) be the solutions to P
ε(g
h) and P
ε(g
h), respectively (where g
h∈ M
hand g
h∈ M
h). From (7), we get
a(u
h, v
h) + Z
ΓC
λ
hv
hndΓ = L(v
h), ∀v
h∈ ˜ V
h,
and
a(u
h, v
h) + Z
ΓC
λ
hv
hndΓ = L(v
h), ∀v
h∈ ˜ V
h,
which implies by subtraction that Z
ΓC
(λ
h− λ
h)v
hndΓ = a(u
h− u
h, v
h)
≤ M
0ku
h− u
hk
1kv
hk
1, ∀v
h∈ ˜ V
h, where the continuity of the bilinear form a(·, ·) was used.
So we get the following estimate:
kλ
h− λ
hk
−12,h
≤ M
0ku
h− u
hk
1. (13) Next, we show that Ψ
εhis continuous from M
hinto V
h. We consider again (u
h, λ
h) and (u
h, λ
h), the solu- tions to P
ε(g
h) and P
ε(g
h), respectively. We have
a(u
h, v
h− u
h) + Z
ΓC
λ
h(v
hn− u
hn) dΓ
+ Z
ΓC
F g
hq v
ht2+ ε
2− q
u
2ht+ ε
2dΓ
≥ L(v
h− u
h), ∀v
h∈ V
h, and
a(u
h, v
h− u
h) + Z
ΓC
λ
h(v
hn− u
hn) dΓ
+ Z
ΓC
F g
hq
v
ht2+ ε
2− q
u
2ht+ ε
2dΓ
≥ L(v
h− u
h), ∀v
h∈ V
h. Choosing v
h= u
hin the first inequality and v
h= u
hin the second one, from (7) we obtain
a(u
h, u
h−u
h)+
Z
ΓC
F g
hq
u
2ht+ε
2− q
u
2ht+ε
2dΓ
≥ L(u
h− u
h) and
a(u
h, u
h−u
h)+
Z
ΓC
F g
hq
u
2ht+ε
2− q
u
2ht+ε
2dΓ
≥ L(u
h− u
h).
Thus
a(u
h− u
h, u
h− u
h)
≤ Z
ΓC
F (g
h−g
h) q
u
2ht+ε
2− q
u
2ht+ε
2dΓ. (14) Consequently,
αku
h− u
hk
21≤ F kg
h− g
hk
H− 12(ΓC)
×
q
u
2ht+ ε
2− q
u
2ht+ ε
2H12(Γ
C)
. (15)
The next step consists in estimating the H
12-norm term in (15). To attain our ends, we need to use two lemmas:
Lemma 1. There exists a positive constant C satisfying kf gk
H12(ΓC)
≤ C
kf k
H12(ΓC)kgk
L∞(ΓC)+ kf k
L∞(ΓC)kgk
H12(ΓC)
. (16)
for all f and g in H
12(Γ
C) ∩ L
∞(Γ
C).
Proof. From the definition of the H
12(Γ
C)-norm (Adams, 1975), we have
kf gk
2H12(ΓC)
= kf gk
2L2(ΓC)+ Z
ΓC
Z
ΓC
f (x)g(x) − f (y)g(y)
2(x − y)
2dΓ dΓ.
Let us begin with bounding (roughly) the first term:
kf gk
2L2(ΓC)= Z
ΓC
f
2(x)g
2(x) dΓ
≤ kf k
2L2(ΓC)kgk
2L∞(ΓC). (17) The second term is handled as follows:
Z
ΓC
Z
ΓC
(f (x)(g(x)−g(y))+g(y)(f (x)−f (y)))
2(x − y)
2dΓ dΓ
≤ 2 Z
ΓC
Z
ΓC
f
2(x)(g(x) − g(y))
2(x − y)
2+ g
2(y) f (x) − f (y)
2(x − y)
2dΓ dΓ (18)
≤ 2
kf k
2L∞(ΓC)kgk
2H12(ΓC)
+kf k
2H12(ΓC)
kgk
2L∞(ΓC).
Putting together (17) and (18) establishes (16).
Lemma 2. For any real number p ∈ [1, ∞[, the following inequality holds:
kf k
Lp(ΓC)≤ C √ pkf k
H12(ΓC)
, ∀f ∈ H
12(Γ
C), (19) where C is independent of p.
Proof. see (Ben Belgacem, 2000).
Proof of Theorem 1 (continued). We consider the H
12- norm term in (15). Employing the estimate (16) gives
q
u
2ht+ ε
2− q
u
2ht+ ε
2H12(Γ
C)
=
(u
ht− u
ht) u
ht+ u
htp u
2ht+ ε
2+ pu
2ht+ ε
2H12(Γ
C)
≤ Cku
ht− u
htk
L∞(ΓC)×
u
ht+ u
htp u
2ht+ ε
2+ pu
2ht+ ε
2H12(Γ
C)
+ Cku
ht− u
htk
H12(ΓC)
×
u
ht+ u
htp u
2ht+ ε
2+ pu
2ht+ ε
2L∞(ΓC)
. (20)
In the previous estimate, we leave the third term un- changed whereas the last one is bounded by 1. It remains then to bound the first two terms, which is performed here- after. We begin with the first one:
ku
ht− u
htk
L∞(ΓC)≤ Ch
−1pku
ht− u
htk
Lp(ΓC)≤ C √
ph
−1pku
ht−u
htk
H12(ΓC)
, (21) for any p ∈ [1, ∞[. In (21), we used an easily recoverable inverse inequality (Ciarlet, 1991), as well as (19). The second term of (20) is bounded due to (16):
u
ht+ u
htp u
2ht+ ε
2+ pu
2ht+ ε
2H12(ΓC)
≤ Cku
ht+ u
htk
L∞(ΓC)×
1
p u
2ht+ ε
2+ pu
2ht+ ε
2H12(Γ
C)
+ Cku
ht+ u
htk
H12(ΓC)
×
1
p u
2ht+ ε
2+ pu
2ht+ ε
2L∞(ΓC)
≤ C √
ph
−1pku
ht+ u
htk
H12(ΓC)
×
1
p u
2ht+ ε
2+ pu
2ht+ ε
2H12(Γ
C)
+ 1
2ε ku
ht+ u
htk
H12(ΓC)
, (22)
where the first L
∞-norm term is bounded as in (21), whereas the other is roughly bounded by 1/2ε. Next, we develop the first H
12-norm term in (22):
1
p u
2ht+ ε
2+ pu
2ht+ ε
22
H12(ΓC)
=
1
p u
2ht+ ε
2+ pu
2ht+ ε
22
L2(ΓC)
+ Z
ΓC
Z
ΓC
1 (y − x)
2× 1
p u
2ht(x) + ε
2+ pu
2ht(x) + ε
2− 1
p u
2ht(y) + ε
2+ pu
2ht(y) + ε
2!
2dΓ dΓ.
It is easy to check that the L
2-norm term is less than meas(Γ
C)/4ε
2. Developing the previous integral, bound- ing then the denominator and using the estimate (a + b)
2≤ 2a
2+ 2b
2furnishes the following upper bound:
1 8ε
4Z
ΓC
Z
ΓC
p u
2ht(x) + ε
2− p
u
2ht(y) + ε
22(y − x)
2+
pu
2ht(x) + ε
2− pu
2ht(y) + ε
22(y − x)
2dΓ dΓ.
We use the estimate | √
a
2+ ε
2− √
b
2+ ε
2| ≤ |a − b| in the previous expression so that
1
p u
2ht+ ε
2+ pu
2ht+ ε
22
H12(ΓC)
≤ meas(Γ
C) 4ε
2+ 1
8ε
4ku
htk
2H12(ΓC)
+ ku
htk
2H12(ΓC)
.
Therefore we deduce from (11) that there exists a positive constant C satisfying
1
p u
2ht+ ε
2+ pu
2ht+ ε
2H12(Γ
C)
≤ C 1 ε + 1
ε
2. (23)
Applying (23) to (22) and using (11) and (20), we get
q
u
2ht+ ε
2− q
u
2ht+ ε
2H12(Γ
C)
≤ Cku
ht− u
htk
H12(ΓC)
× 1 + √
ph
−p11 ε + √
ph
−1p1 ε + 1
ε
2! .
Choosing p = − log(h) (h is assumed to be sufficiently small) in the previous estimate, we obtain
q
u
2ht+ ε
2− q
u
2ht+ ε
2H12(Γ
C)
≤ Cku
ht− u
htk
H12(ΓC)
× 1 +
√ − log h
ε + − log h
ε + − log h ε
2! . (24)
Inequality (15) together with (24) and the trace theorem becomes
ku
h− u
hk
1≤ CF kg
h− g
hk
H− 12(ΓC)
× 1 +
√ − log h
ε + − log h
ε + − log h ε
2! , (25)
which proves that the mapping Ψ
εhis continuous. This, together with (13), implies that Φ
εhis continuous. Then, from (12) and the Brouwer fixed point theorem, we con- clude the existence of at least one solution to Coulomb’s discrete regularized frictional contact problem.
We now consider the uniqueness. Under the assump- tion that Γ
D∩ Γ
C= ∅, it was proved in (Coorevits et al., 2002) that there exists a positive constant β (independent of h) satisfying
βkµ
hk
H− 12(ΓC)
≤ kµ
hk
−12,h
, ∀µ
h∈ W
h. (26) Assembling this result with (25) and (13) yields
kλ
h− λ
hk
H− 12(ΓC)
≤ CF kg
h− g
hk
H− 12(ΓC)
× 1 +
√ − log h
ε + − log h
ε + − log h ε
2! .
Supposing that h and ε are small enough, we deduce that
the mapping Φ
εhis contractive if the friction coefficient
F is less than Cε
2| log(h)|
−1. This completes the proof of the theorem.
The non-regularized case (i.e. ε = 0) is handled in the proposition that follows.
Proposition 1. Let ε = 0. The following results hold:
(Existence) For any positive F , there exists a solution to Coulomb’s discrete frictional contact problem.
(Uniqueness) Assume that Γ
D∩ Γ
C= ∅. If F ≤ Ch
12, then the problem admits a unique solution. The positive constant C is independent of h.
Proof. Estimates (12) and (13) remain still valid when ε = 0. The starting point of the analysis is (14):
a(u
h− u
h, u
h− u
h)
≤ Z
ΓC
F (g
h− g
h)(|u
ht| − |u
ht|) dΓ
≤ F kg
h− g
hk
L2(ΓC)k |u
ht| − |u
ht| k
L2(ΓC)≤ CF h
−12kg
h− g
hk
H− 12(ΓC)
ku
ht− u
htk
L2(ΓC)≤ C
0F h
−12kg
h− g
hk
H− 12(ΓC)
ku
h− u
hk
1, where an inverse inequality between L
2(Γ
C) and H
−12(Γ
C) was used. From the last bound, combined with (13) and (26), we deduce that
kλ
h− λ
hk
H− 12(ΓC)
≤ CF h
−12kg
h− g
hk
H− 12(ΓC)
. This proves the proposition.
Remark 2. 1. In the proof of Proposition 1, we are not able to remove the mesh dependent uniqueness condition, also when avoiding the L
2(Γ
C)-norms and using only H
12(Γ
C)-norms and H
−12(Γ
C)-norms. More precisely, there does not exist a positive constant C independent of h such that
k |g
h− g
h| k
H− 12(ΓC)
≤ Ckg
h− g
hk
H− 12(ΓC)
or
k |u
ht| − |u
ht| k
H12(ΓC)
≤ Cku
ht− u
htk
H12(ΓC)
. 2. The use of inverse inequalities in the proofs of Theo- rem 1 and Proposition 1 implies that it is not possible to generalize the calculus to the continuous problem.
4. The Study of a Simple Finite Element Example
We consider the triangle Ω of vertices A = (0, 0), B = (`, 0) and C = (0, `) with ` > 0. We define Γ
D= [B, C], Γ
N= [A, C], Γ
C= [A, B], and {X
1, X
2} de- notes the canonical orthonormal basis (see Fig. 1). We suppose that the volume forces f are absent and that the surface forces denoted by F = F
1X
1+ F
2X
2are such that F
1and F
2are constant on Γ
N.
N
C D
A B
C
n t
F
X
X
1 2
Γ
Γ Γ Ω
Fig. 1. Problem setting.
We suppose that Ω is discretized with a single finite element of degree one. Consequently, the finite element space becomes
V
h= n
v
h= (v
h1, v
h2) ∈ P
1(Ω)
2, v
h|
ΓD= 0 o . In this case, we have
M
h= n
g
h∈ P
1(Γ
C), g
h≥ 0, g
h(B) = 0 o . Clearly, V
his of dimension two and M
hbelongs to the space W
hof linear functions on Γ
Cvanishing at B, which is of dimension one. Moreover, since (8), or equiv- alently (9), is satisfied, it follows that the existence is en- sured for all ε ≥ 0 according to Theorem 1 and Proposi- tion 1.
Let v
h∈ V
hand µ
h∈ M
h. Then we denote by (V
T, V
N) the value of v
h(A), corresponding to the tangential and the normal displacements at point A, re- spectively (in our example, we have V
T= −v
h1(A) and V
N= −v
h2(A)). We also denote by Θ the value of µ
hat point A. Then, for any v
h∈ V
hand µ
h∈ M
h, we obtain
ε(v
h) = 1 2`
2V
TV
T+ V
NV
T+ V
N2V
N!
and
σ(v
h) = 1
`
(λ+2µ)V
T+λV
Nµ(V
T+V
N) µ(V
T+V
N) (λ+2µ)V
N+λV
T
.
Therefore
a(u
h, v
h) = 1 2
(λ + 3µ)(U
TV
T+ U
NV
N) + (λ + µ)(U
TV
N+ U
NV
T) and
L(v
h) = − 1
2 `(F
1V
T+ F
2V
N).
Besides,
Z
ΓC
µ
hv
hndΓ = ΘV
N` 3 and
Z
ΓC
F µ
h|v
ht| dΓ = F Θ|V
T|`
3 .
Let (u
h, λ
h) be a solution to the discrete unilateral con- tact problem with Coulomb’s friction and without regular- ization (i.e. with ε = 0 in (7)). As was mentioned above, the notation (U
T, U
N) stands for the value of u
h(A) (U
T= −u
h1(A) and U
N= −u
h2(A)). We also denote by Λ
0the value of λ
hat point A. To simplify the nota- tion and the forthcoming calculations, we set Λ = 2Λ
0/3.
The discrete unilateral contact problem with Coulomb’s friction and without regularization issued from (7) and Definition 1 consists then in finding (U
T, U
N, Λ) ∈ R
3such that
(λ+3µ)(U
TV
T+U
NV
N)+(λ + µ)(U
TV
N+U
NV
T) + Λ`V
N+ F Λ`|V
T|
≥ −`(F
1V
T+ F
2V
N), ∀V
T∈ R, ∀V
N∈ R, (λ + 3µ)(U
T2+ U
N2) + 2(λ + µ)(U
TU
N) + F Λ`|U
T|
= −`(F
1U
T+ F
2U
N),
Λ ≥ 0, U
N≤ 0, ΛU
N= 0, or equivalently,
(λ + 3µ)U
N+ (λ + µ)U
T+ Λ` = −`F
2, (λ + µ)U
N+ (λ + 3µ)U
T+ F Λ` ≥ −`F
1, (λ + µ)U
N+ (λ + 3µ)U
T− F Λ` ≤ −`F
1,
(λ + 3µ)(U
T2+ U
N2) + 2(λ + µ)(U
TU
N) + F Λ`|U
T|
= −`(F
1U
T+ F
2U
N), Λ ≥ 0, U
N≤ 0, ΛU
N= 0.
(27) Let us now look for solutions to (27). Clearly, a solution to (27) satisfies either U
N= 0 or Λ = 0.
(i) Case 1: U
N= 0. Equations (27) become
(λ + µ)U
T+ Λ` = −`F
2, (λ + 3µ)U
T+ F Λ` ≥ −`F
1, (λ + 3µ)U
T− F Λ` ≤ −`F
1, (λ + 3µ)U
T2+ F Λ`|U
T| = −`F
1U
T, Λ ≥ 0.
• Suppose that U
T= 0. Then
Λ = −F
2, F
2≤ 0, |F
1| ≤ F |F
2|.
• Suppose that U
T> 0. Then
(λ + µ)U
T+ Λ` = −`F
2, (λ + 3µ)U
T+ F Λ` = −`F
1, Λ ≥ 0.
– Assume that F 6= (λ + 3µ)/(λ + µ). Then
U
T= `(F F
2− F
1)
(λ + 3µ) − F (λ + µ) > 0,
Λ = (λ + µ)F
1− (λ + 3µ)F
2(λ + 3µ) − F (λ + µ) ≥ 0.
– Assume that F = (λ + 3µ)/(λ + µ). Then
∗ If F
1= F F
2, the solutions are
(λ + µ)U
T+ Λ` = −`F
2, U
T> 0, Λ ≥ 0.
∗ If F
16= F F
2, then there are no solutions.
• Suppose that U
T< 0. Then
(λ + µ)U
T+ Λ` = −`F
2, (λ + 3µ)U
T− F Λ` = −`F
1, Λ ≥ 0,
which gives
U
T= `(F F
2+ F
1)
−(λ + 3µ) − F (λ + µ) < 0,
Λ = −(λ + µ)F
1+ (λ + 3µ)F
2−(λ + 3µ) − F (λ + µ) ≥ 0.
(ii) Case 2: Λ = 0.
(λ + 3µ)U
N+ (λ + µ)U
T= −`F
2, (λ + µ)U
N+ (λ + 3µ)U
T= −`F
1, U
N≤ 0,
so that
U
T= ` (λ + µ)F
2− (λ + 3µ)F
14µ(λ + 2µ) ,
U
N= ` (λ + µ)F
1− (λ + 3µ)F
24µ(λ + 2µ) ≤ 0.
All the results are reported in the proposition that fol- lows. There are three cases which consist in compar- ing the friction coefficient F with the critical value (λ + 3µ)/(λ + µ) = 3 − 4ν (ν denotes Poisson’s ratio with 0 < ν < 1/2). The results are also depicted in Figs. 2–4.
Proposition 2. 1. If F < (λ + 3µ|/(λ + µ), then the problem (27) admits a unique solution:
(Separation) If F
2> ((λ + µ)/(λ + 3µ))F
1, then
U
T= ` (λ + µ)F
2− (λ + 3µ)F
14µ(λ + 2µ) , U
N= ` (λ + µ)F
1− (λ + 3µ)F
24µ(λ + 2µ) , Λ = 0.
(28)
(Stick) If |F
1| ≤ F |F
2| and F
2≤ 0, then
U
T= 0, U
N= 0, Λ = −F
2. (29) (Right slip) If F
2≤ ((λ + µ)/(λ + 3µ))F
1, F F
2+F
1>
0, then
U
T= `(F F
2+ F
1)
−(λ + 3µ) − F (λ + µ) ,
U
N= 0, Λ = −(λ + µ)F
1+ (λ + 3µ)F
2−(λ + 3µ) − F (λ + µ) .
(30)
(Left slip) If F
2≤ ((λ + µ)/(λ + 3µ))F
1, F F
2− F
1>
0, then
U
T= `(F F
2− F
1) (λ + 3µ) − F (λ + µ) ,
U
N= 0, Λ = (λ + µ)F
1− (λ + 3µ)F
2(λ + 3µ) − F (λ + µ) .
(31)
F F
Right slip
Stick Left slip
Separation
U = 0 U < 0
U =0 U =0 U = 0
U > 0
U < 0
NN
N N
T
T T
1 2
Fig. 2. Case F <
λ+3µλ+µ= 3 − 4ν. Problem (27) admits a unique solution.
F F
Separation U < 0
NRight slip U = 0
NU < 0
TInfinity of solutions from stick to left slip
Stick U =0
TU =0
N2
1
Fig. 3. Case F =
λ+3µλ+µ= 3 − 4ν. Problem (27) admits either a unique or an infinity of solutions.
F
Stick U =0
TU =0
NRight slip U = 0 U < 0
TN F2 solutions:
stick and left slip 3 solutions
stick, left slip and separation
Separation U < 0
N2 solutions:
stick and separation
1 2