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155 (1998)

A polarized partition relation and failure of GCH at singular strong limit

by

Saharon S h e l a h (Jerusalem and New Brunswick, N.J.)

Abstract. The main result is that for λ strong limit singular failing the continuum hypothesis (i.e. 2

λ

> λ

+

), a polarized partition theorem holds.

1. Introduction. In the present paper we show a polarized partition theorem for strong limit singular cardinals λ failing the continuum hypoth- esis. Let us recall the following definition.

Definition 1.1. For ordinal numbers α

1

, α

2

, β

1

, β

2

and a cardinal θ, the polarized partition symbol

 α

1

β

1



 α

2

β

2



1,1

θ

means that if d is a function from α

1

× β

1

into θ then for some A ⊆ α

1

of order type α

2

and B ⊆ β

1

of order type β

2

, the function d¹A×B is constant.

We address the following problem of Erd˝os and Hajnal:

(∗) if µ is strong limit singular of uncountable cofinality with θ < cf(µ),

does 

µ

+

µ



 µ µ



1,1

θ

?

The particular case of this question for µ = ℵ

ω1

and θ = 2 was posed by Erd˝os, Hajnal and Rado (under the assumption of GCH) in [EHR, Prob- lem 11, p. 183]). Hajnal said that the assumption of GCH in [EHR] was not crucial, and he added that the intention was to ask the question “in some, preferably nice, Set Theory”.

1991 Mathematics Subject Classification: Primary 03E05, 04A20, 04A30.

Research partially supported by “Basic Research Foundation” administered by The Israel Academy of Sciences and Humanities. Publication 586.

[153]

(2)

Baumgartner and Hajnal have proved that if µ is weakly compact then the answer to (∗) is “yes” (see [BH]), also if µ is strong limit of cofinality

0

. But for a weakly compact µ we do not know if for every α < µ

+

:

 µ

+

µ



 α µ



1,1

θ

.

The first time I heard the problem (around 1990) I noted that (∗) holds when µ is a singular limit of measurable cardinals. This result is presented in Theorem 2.2. It seemed likely that we could combine this with suitable collapses, to get “small” such µ (like ℵ

ω1

) but there was no success in this direction.

In September 1994, Hajnal reasked me the question putting great stress on it. Here we answer the problem (∗) using methods of [Sh:g]. But instead of the assumption of GCH (postulated in [EHR]) we assume 2

µ

> µ

+

. The proof seems quite flexible but we did not find out what else it is good for.

This is a good example of the major theme of [Sh:g]:

Thesis 1.2. Whereas CH and GCH are good (helpful, strategic) assump- tions having many consequences, and, say, ¬CH is not, the negation of GCH at singular cardinals (i.e. for µ strong limit singular 2

µ

> µ

+

, or the really strong hypothesis: cf(µ) < µ ⇒ pp(µ) > µ

+

) is a good (helpful, strategic) assumption.

Foreman pointed out that the result presented in Theorem 1.2 below is preserved by µ

+

-closed forcing notions. Therefore, if

V |=

 λ

+

λ



 λ λ



1,1

θ

then

V

Levy(λ+,2λ)

|=

 λ

+

λ



 λ λ



1,1

θ

.

Consequently, the result is consistent with 2

λ

= λ

+

& λ is small. (Note that although our final model may satisfy the Singular Cardinals Hypothesis, the intermediate model still violates SCH at λ, hence needs large cardinals, see [J].) For λ not small we can use Theorem 2.2.

Before we move to the main theorem, let us recall an open problem important for our methods:

Problem 1.3. (1) Let κ = cf(µ) > ℵ

0

, µ > 2

κ

and λ = cf(λ) ∈ (µ, pp

+

(µ)). Can we find θ < µ and a ∈ [µ ∩ Reg]

θ

such that λ ∈ pcf(a), a = S

i<κ

a

i

, a

i

bounded in µ and σ ∈ a

i

V

α<σ

|α|

θ

< σ? For this it is

enough to show :

(3)

(2) If µ = cf(µ) > 2

but W

α<µ

|α|

≥ µ then we can find a ∈ [µ ∩ Reg]

such that λ ∈ pcf(a). (In fact, it suffices to prove it for the case θ = ℵ

1

.)

As shown in [Sh:g] we have

Theorem 1.4. If µ is strong limit singular of cofinality κ > ℵ

0

and 2

µ

> λ = cf(λ) > µ then for some strictly increasing sequence hλ

i

: i < κi of regulars with limit µ, Q

i<κ

λ

i

/J

κbd

has true cofinality λ. If κ = ℵ

0

, this still holds for λ = µ

++

.

[More fully, by [Sh:g, II, §5], we know pp(µ) =

+

2

µ

and by [Sh:g, VIII, 1.6(2)], we know pp

+

(µ) = pp

+Jbd

κ

(µ). Note that for κ = ℵ

0

we should replace J

κbd

by a possibly larger ideal, using [Sh 430, 1.1, 6.5] but there is no need here.]

Remark 1.5. Note that the problem is a pp = cov problem (see more in [Sh 430, §1]); so if κ = ℵ

0

and λ < µ

1

the conclusion of 1.4 holds; we allow J

κbd

to be increased, even “there are < µ

+

fixed points < λ

+

” suffices.

2. Main result

Theorem 2.1. Suppose µ is strong limit singular satisfying 2

µ

> µ

+

. Then:

(1)

 µ

+

µ



 µ + 1 µ



1,1

θ

for any θ < cf(µ).

(2) If d is a function from µ

+

× µ to θ and θ < µ then for some sets A ⊆ µ

+

and B ⊆ µ we have otp(A) = µ + 1, otp(B) = µ and the restriction d¹A × B does not depend on the first coordinate.

P r o o f. (1) This follows from part (2) (since if d(α, β) = d

0

(β) for α ∈ A, β ∈ B, where d

0

: B → θ, and |B| = µ, θ < cf(µ) then there is B

0

⊆ B with |B

0

| = µ such that d

0

¹B is constant and hence d¹A × B

0

is constant as required).

(2) Let d : µ

+

× µ → θ. Let κ = cf(µ) and µ = hµ

i

: i < κi be a continuous strictly increasing sequence such that µ = P

i<κ

µ

i

, µ

0

> κ + θ.

We can find a sequence C = hC

α

: α < µ

+

i such that:

(A) C

α

⊆ α is closed, otp(C

α

) < µ, (B) β ∈ nacc(C

α

) ⇒ C

β

= C

α

∩ β,

(C) if C

α

has no last element then α = sup(C

α

) (so α is a limit ordinal) and any member of nacc(C

α

) is a successor ordinal,

(D) if σ = cf(σ) < µ then the set

S

σ

:= {δ < µ

+

: cf(δ) = σ & δ = sup(C

δ

) & otp(C

δ

) = σ}

is stationary

(4)

(possible by [Sh 420, §1]); we could have added

(E) for every σ ∈ Reg ∩µ

+

and a club E of µ

+

, for stationary many δ ∈ S

σ

, E separates any two successive members of C

δ

.

Let c be a symmetric two-place function from µ

+

to κ such that for each i < κ and β < µ

+

the set

a

βi

:= {α < β : c(α, β) ≤ i}

has cardinality ≤ µ

i

and α < β < γ ⇒ c(α, γ) ≤ max{c(α, β), c(β, γ)} and α ∈ C

β

& µ

i

≥ |C

β

| ⇒ c(α, β) ≤ i

(as in [Sh 108], easily constructed by induction on β).

Let λ = hλ

i

: i < κi be a strictly increasing sequence of regular cardinals with limit µ such that Q

i<κ

λ

i

/J

κbd

has true cofinality µ

++

(exists by 1.4 with λ = µ

++

≤ 2

µ

). As we can replace λ by any subsequence of length κ, without loss of generality (∀i < κ)(λ

i

> 2

µ+i

). Lastly, let χ = i

8

(µ)

+

and <

χ

be a well ordering of H(χ)(:= {x : the transitive closure of x is of cardinality < χ}).

Now we choose by induction on α < µ

+

sequences M

α

= hM

α,i

: i < κi such that:

(i) M

α,i

≺ (H(χ), ∈, <

χ

),

(ii) kM

α,i

k = 2

µ+i

and

µ+i

(M

α,i

) ⊆ M

α,i

and 2

µ+i

+ 1 ⊆ M

α,i

, (iii) d, c, C, λ, µ, α ∈ M

α,i

, hM

β,j

: β < α, j < κi ∈ M

α,i

, S

β∈aαi

M

β,i

M

α,i

and hM

α,j

: j < ii ∈ M

α,i

, S

j<i

M

α,j

⊆ M

α,i

, (iv) hM

β,i

: β ∈ a

αi

i belongs to M

α,i

.

There is no problem to carry out the construction. Note that actually clause (iv) follows from (i)–(iii), as a

αi

is defined from c, α, i. Our demands imply that

[β ∈ a

αi

⇒ M

β,i

≺ M

α,i

] and [j < i ⇒ M

α,j

≺ M

α,i

] and a

αi

⊆ M

α,i

, hence α ⊆ S

i<κ

M

α,i

. For α < µ

+

let f

α

Q

i<κ

λ

i

be defined by f

α

(i) = sup(λ

i

∩ M

α,i

). Note that f

α

(i) < λ

i

as λ

i

= cf(λ

i

) > 2

µ+i

= kM

α,i

k. Also, if β < α then for every i ∈ [c(β, α), κ) we have β ∈ M

α,i

and hence M

β

∈ M

α,i

. Therefore, as also λ ∈ M

α,i

, we have f

β

∈ M

α,i

and f

β

(i) ∈ M

α,i

∩ λ

i

. Consequently,

(∀i ∈ [c(β, α), κ))(f

β

(i) < f

α

(i)) and thus f

β

<

Jbd κ

f

α

. Since {f

α

: α < µ

+

} ⊆ Q

i<κ

λ

i

has cardinality µ

+

and Q

i<κ

λ

i

/J

κbd

is µ

++

-directed, there is f

Q

i<κ

λ

i

such that (∗)

1

(∀α < µ

+

)(f

α

<

Jbd

κ

f

).

(5)

Let, for α < µ

+

, g

α

κ

θ be defined by g

α

(i) = d(α, f

(i)). Since |

κ

θ| < µ <

µ

+

= cf(µ

+

), there is a function g

κ

θ such that

(∗)

2

the set A

= {α < µ

+

: g

α

= g

} is unbounded in µ

+

. Now choose, by induction on ζ < µ

+

, models N

ζ

such that:

(a) N

ζ

≺ (H(χ), ∈, <

χ

),

(b) the sequence hN

ζ

: ζ < µ

+

i is increasing continuous, (c) kN

ζ

k = µ and

κ>

(N

ζ

) ⊆ N

ζ

if ζ is not a limit ordinal, (d) hN

ξ

: ξ ≤ ζi ∈ N

ζ+1

,

(e) µ + 1 ⊆ N

ζ

, S

α<ζ, i<κ

M

α,i

⊆ N

ζ

and hM

α,i

: α < µ

+

, i < κi, hf

α

: α < µ

+

i, g

, A

and d belong to the first model N

0

.

Let E := {ζ < µ

+

: N

ζ

∩ µ

+

= ζ}. Clearly, E is a club of µ

+

, and thus we can find an increasing sequence hδ

i

: i < κi such that

(∗)

3

δ

i

∈ S

µ+

i

∩ acc(E) (⊆ µ

+

) (see clause (D) at the beginning of the proof).

For each i < κ choose a successor ordinal α

i

∈ nacc(C

δi

) \ S

j

+ 1 : j < i}.

Take any α

∈ A

\ S

i<κ

δ

i

.

We choose by induction on i < κ an ordinal j

i

and sets A

i

, B

i

such that:

(α) j

i

< κ and µ

ji

> λ

i

(so j

i

> i) and j

i

strictly increasing in i, (β) f

δi

¹[j

i

, κ) < f

α

i+1

¹[j

i

, κ) < f

α

¹[j

i

, κ) < f

¹[j

i

, κ),

(γ) for each i

0

< i

1

we have c(δ

i0

, α

i1

) < j

i1

, c(α

i0

, α

i1

) < j

i1

, c(α

i1

, α

)

< j

i1

and c(δ

i1

, α

) < j

i1

, (δ) A

i

⊆ A

∩ (α

i

, δ

i

), (ε) otp(A

i

) = µ

+i

, (ζ) A

i

∈ M

δi,ji

, (η) B

i

⊆ λ

ji

, (θ) otp(B

i

) = λ

ji

,

(ι) B

ε

∈ M

α

i,ji

for ε < i, (κ) for every α ∈ S

ε≤i

A

ε

∪ {α

} and ζ ≤ i and β ∈ B

ζ

∪ {f

(j

ζ

)} we have d(α, β) = g

(j

ζ

).

If we succeed then A = S

ε<κ

A

ε

∪{α

} and B = S

ζ<κ

B

ζ

are as required.

During the induction at stage i concerning (ι), if ε + 1 = i then for some j < κ, B

ε

∩M

α

i,j

has cardinality λ

jε

, hence we can replace B

ε

by a subset of the same cardinality which belongs to the model M

α

i,j

if j is large enough such that µ

j

> λ

i

; if ε + 1 < i then by the demand for ε + 1, we have W

j<κ

B

ε

∈ M

α

i,j

. So assume that the sequence h(j

ε

, A

ε

, B

ε

) : ε < ii has already been defined.

We can find j

i

(0) < κ satisfying requirements (α), (β), (γ) and (ι) and such that V

ε<i

λ

jε

< µ

ji(0)

. Then for each ε < i we have δ

ε

∈ a

αji

i(0)

and

(6)

hence M

δε,jε

≺ M

α

i,ji(0)

(for ε < i). But A

ε

∈ M

δε,jε

(by clause (ζ)) and B

ε

∈ M

α

i,ji(0)

(for ε < i), so {A

ε

, B

ε

: ε < i} ⊆ M

α

i,ji(0)

. Since

κ>

(M

α

i,ji(0)

) ⊆ M

α

i,ji(0)

(see (ii)), the sequence h(A

ε

, B

ε

) : ε < ii belongs to M

α

i,ji(0)

. We know that for γ

1

< γ

2

in nacc(C

δi

) we have c(γ

1

, γ

2

) ≤ i (remember clause (B) and the choice of c). As j

i

(0) > i and so µ

ji(0)

≥ µ

+i

, the sequence

M

:= hM

α,ji(0)

: α ∈ nacc(C

δi

)i

is ≺-increasing and M

¹α ∈ M

α,ji(0)

for α ∈ nacc(C

δi

) and M

α

i,ji(0)

ap- pears in it. Also, as δ

i

∈ acc(E), there is an increasing sequence hγ

ξ

: ξ < µ

+i

i of members of nacc(C

δi

) such that γ

0

= α

i

and (γ

ξ

, γ

ξ+1

) ∩ E 6= ∅, say β

ξ

∈ (γ

ξ

, γ

ξ+1

) ∩ E. Each element of nacc(C

δ

) is a successor ordinal, so every γ

ξ

is a successor ordinal. Each model M

γξ,ji(0)

is closed under se- quences of length ≤ µ

+i

, and hence hγ

ζ

: ζ < ξi ∈ M

γξ,ji(0)

(by choos- ing the right C and δ

i

’s we could have managed to have α

i

= min(C

δi

),

ξ

: ξ < µ

+i

} = nacc(C

δ

), without using this amount of closure).

For each ξ < µ

+i

, we know that

(H(χ), ∈, <

χ

) |= “(∃x ∈ A

)[x > γ

ξ

& (∀ε < i)(∀y ∈ B

ε

)(d(x, y) = g

(j

ε

))]”

because x = α

satisfies it. As all the parameters, i.e. A

, γ

ξ

, d, g

and hB

ε

: ε < ii, belong to N

βξ

(remember clauses (e) and (c); note that B

ε

M

α

i,ji(0)

, α

i

< β

ξ

), there is an ordinal β

ξ

∈ (γ

ξ

, β

ξ

) ⊆ (γ

ξ

, γ

ξ+1

) satisfying the demands on x. Now, necessarily for some j

i

(1, ξ) ∈ (j

i

(0), κ) we have β

ξ

∈ M

γξ+1,ji(1,ξ)

. Hence for some j

i

< κ the set

A

i

:= {β

ξ

: ξ < µ

+i

& j

i

(1, ξ) = j

i

}

has cardinality µ

+i

. Clearly A

i

⊆ A

(as each β

ξ

∈ A

). Now, the sequence hM

γξ,ji

: ξ < µ

+i

i

_

hM

δi,ji

i is ≺-increasing, and hence A

i

⊆ M

δi,ji

. Since µ

+ji

> µ

+i

= |A

i

| we have A

i

∈ M

δi,ji

. Note that at the moment we know that the set A

i

satisfies the demands (δ)–(ζ). By the choice of j

i

(0), as j

i

> j

i

(0), clearly M

δi,ji

≺ M

α,ji

, and hence A

i

∈ M

α,ji

. Similarly, hA

ε

: ε ≤ ii ∈ M

α,ji

, α

∈ M

α,ji

and

sup(M

α,ji

∩ λ

ji

) = f

α

(j

i

) < f

(j

i

).

Consequently, S

ε≤i

A

ε

∪ {α

} ⊆ M

α,ji

(by the induction hypothesis or the above) and it belongs to M

α,ji

. Since S

ε≤i

A

ε

∪ {α

} ⊆ A

, clearly (H(χ), ∈, <

χ

) |= “



∀x ∈ [

ε≤i

A

ε

∪ {α

}



(d(x, f

(j

i

)) = g

(j

i

))”.

Note that [

ε≤i

A

ε

∪ {α

}, g

(j

i

), d, λ

ji

∈ M

α,ji

and f

(j

i

) ∈ λ

ji

\sup(M

α,ji

∩ λ

ji

).

(7)

Hence the set B

i

:=

n

y < λ

ji

:



∀x ∈ [

ε≤i

A

ε

∪ {α

}



(d(x, y) = g

(j

i

)) o

has to be unbounded in λ

ji

. It is easy to check that j

i

, A

i

, B

i

satisfy clauses (α)–(κ).

Thus we have carried out the induction step, finishing the proof of the theorem.

2.1

Theorem 2.2. Suppose µ is a singular limit of measurable cardinals.

Then (1)

 µ

+

µ



 µ µ



θ

if θ = 2 or at least θ < cf(µ).

(2) Moreover , if α

< µ

+

and θ < cf(µ) then

 µ

+

µ



 α

µ



θ

.

(3) If θ < µ, α

< µ

+

and d is a function from µ

+

× µ to θ then for some A ⊆ µ

+

, otp(A) = α

, and B = S

i<cf(µ)

B

i

⊆ µ, d¹A × B

i

is constant for each i < cf(µ).

P r o o f. Clearly (3)⇒(2)⇒(1), so we shall prove part (3).

Let d : µ

+

× µ → θ. Let κ := cf(µ). Choose sequences hλ

i

: i < κi and

i

: i < κi such that hµ

i

: i < κi is increasing continuous, µ = P

i<κ

µ

i

, µ

0

> κ + θ, each λ

i

is measurable and µ

i

< λ

i

< µ

i+1

(for i < κ). Let D

i

be a λ

i

-complete uniform ultrafilter on λ

i

. For α < µ

+

define g

α

κ

θ by g

α

(i) = γ iff {β < λ

i

: d(α, β) = γ} ∈ D (as θ < λ

i

it exists). The number of such functions is θ

κ

< µ (as µ is necessarily strong limit), so for some g

κ

θ the set A := {α < µ

+

: g

α

= g

} is unbounded in µ

+

. For each i < κ we define an equivalence relation e

i

on µ

+

:

αe

i

β iff (∀γ < λ

i

)[d(α, γ) = d(β, γ)].

So the number of e

i

-equivalence classes is ≤

λi

θ < µ. Hence we can find an increasing continuous sequence hα

ζ

: ζ < µ

+

i of ordinals < µ

+

such that:

(∗) for each i < κ and e

i

-equivalence class X, either X ∩ A ⊆ α

0

, or for every ζ < µ

+

, (α

ζ

, α

ζ+1

) ∩ X ∩ A has cardinality µ.

Let α

= S

i<κ

a

i

, |a

i

| = µ

i

, ha

i

: i < κi pairwise disjoint. Now, by induction on i < κ, we choose A

i

, B

i

such that:

(a) A

i

S

{(α

ζ

, α

ζ+1

) : ζ ∈ a

i

} ∩ A and each A

i

∩ (α

ζ

, α

ζ+1

) is a singleton,

(b) B

i

∈ D

i

,

(c) if α ∈ A

i

, β ∈ B

j

, j ≤ i then d(α, β) = g

(j).

Now, at stage i, h(A

ε

, B

ε

) : ε < ii are already chosen. Let us choose A

ε

. For

each ζ ∈ a

i

choose β

ζ

∈ (α

ζ

, α

ζ+1

) ∩ A such that if i > 0 then for some

(8)

β

0

∈ A

0

, β

ζ

e

i

β

0

, and let A

i

= {β

ζ

: ζ ∈ a

i

}. Now clause (a) is immediate, and the relevant part of clause (c), i.e. j < i, is O.K. Next, as S

j≤i

A

j

⊆ A, the set

B

i

:= \

j≤i

\

β∈Aj

{γ < λ

i

: d(β, γ) = g

(i)}

is the intersection of ≤ µ

i

< λ

i

sets from D

i

and hence B

i

∈ D

i

. Clearly clause (b) and the remaining part of clause (c) (i.e. j = i) holds. So we can carry out the induction and hence finish the proof.

2.2

References

[EHR] P. E r d ˝o s, A. H a j n a l and R. R a d o, Partition relations for cardinal numbers, Acta Math. Acad. Sci. Hungar. 16 (1965), 93–196.

[BH] J. B a u m g a r t n e r and A. H a j n a l, Polarized partition relations, preprint, 1995.

[J] T. J e c h, Set Theory, Academic Press, New York, 1978.

[Sh:g] S. S h e l a h, Cardinal Arithmetic, Oxford Logic Guides 29, Oxford Univ. Press, 1994.

[Sh 430] —, Further cardinal arithmetic, Israel J. Math. 95 (1996), 61–114.

[Sh 420] —, Advances in cardinal arithmetic, in: Finite and Infinite Combinatorics in Sets and Logic, N. W. Sauer et al. (eds.), Kluwer Acad. Publ., 1993, 355–383.

[Sh 108] —, On successors of singular cardinals, in: Logic Colloquium ’78 (Mons, 1978), Stud. Logic Found. Math. 97, North-Holland, Amsterdam, 1979, 357–380.

Institute of Mathematics Department of Mathematics

The Hebrew University Rutgers University

91 904 Jerusalem, Israel New Brunswick, New Jersey 08903

E-mail: shelah@math.huji.ac.il U.S.A.

Received 4 November 1995;

in revised form 18 October 1996

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