ARKUSZ PRÓBNEJ MATURY Z OPERONEM
FIZYKA I ASTRONOMIA
POZIOM ROZSZERZONY
Czas pracy: 150 minut ,QVWUXNFMDGOD]GDMÈFHJR
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Fizyka i astronomia Poziom rozszerzony
1
Listopad 2013
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Numer
zadania 3RSUDZQDRGSRZLHGě Liczba
punktów 1. 1.1
SNWļ]DSLVDQLH,,]DVDG\G\QDPLNL1HZWRQDEH]XZ]JOÚGQLHQLDNUÈĝND
a Q Q
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m m
m m g
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1 2
1 2
1 2
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50 10 m 8 s m
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punktów 1.3
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Numer
zadania 3RSUDZQDRGSRZLHGě Liczba
punktów 6SRVöE,,
SNWļ]DSLVDQLHUöZQDñUXFKXZNLHUXQNXSR]LRP\PLZNLHUXQNXSLRQRZ\P x=v0x⋅t
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1000000 10
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Numer
zadania 3RSUDZQDRGSRZLHGě Liczba
punktów 3. 3.1
SRSNWļQDU\VRZDQLHNDĝGHJRZHNWRUDLQGXNFML
PDJQHW\F]QHM3U]\NïDGRZRZSXQNFLH3
16
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r
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1 a
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7
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Numer
zadania 3RSUDZQDRGSRZLHGě Liczba
punktów
SNWļ]D]QDF]HQLHQDU\VXQNXNLHUXQNXW\ONRMHGQHJRSUÈGXI:JDïÚ]L]DZLHUDMÈFHM
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R
2R
1E
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12
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2 18 A 10A
SNWļREOLF]HQLHVSDGNXQDSLÚFLDQDRSRU]HR1
U10
3RQLHZDĝZWHMJDïÚ]LSUÈGQLHSï\QLHQLHPDVSDGNXQDSLÚFLDQDRSRUQLNXR1.
SNWļREOLF]HQLHVSDGNXQDSLÚFLDQDRSRU]HR2
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U2=10A⋅188=180V
SNWļREOLF]HQLHUöĝQLF\SRWHQFMDïöZQDNRQGHQVDWRU]H UCU2180 V
5öĝQLFDSRWHQFMDïöZSRPLÚG]\ZÚ]ïDPL A i B MHVWWDNDVDPD
SNWļREOLF]HQLHïDGXQNXQDNRQGHQVDWRU]H Q=C U⋅ C
Q =0 5 10, ⋅ −6F⋅180V=9 10⋅ −5C
SNWļREOLF]HQLHOLF]E\HOHNWURQöZRGSRZLDGDMÈFHM]JURPDG]RQHPXïDGXQNRZLHOHN- WU\F]QHPX
N Q
e N = ⋅
⋅
= ⋅
−
−
9 10
1 6 10 5 625 10
5 19
C 14
C
, ,
SNWļREOLF]HQLHHQHUJLL]JURPDG]RQHMZNRQGHQVDWRU]H WCUC2
2
W = ⋅ ⋅
( )
= = ⋅
−
0 5 10 180 −
2 0 0081 8 1 10
6 2
, 3
, ,
F V
J J
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Numer
zadania 3RSUDZQDRGSRZLHGě Liczba
punktów
SNWļZ\]QDF]HQLHLORĂFLHQHUJLLSRWU]HEQHMGR]DJRWRZDQLDZRG\
Q=mw⋅cw⋅ %T
SNWļZ\]QDF]HQLHZ]RUXQDF]DVSRWU]HEQ\GR]DJRWRZDQLDZRG\
P Q
t t Q
P
m c T
U I
w w
= = ⋅ ⋅
⋅
%
2
1 pkt – obliczenie czasu
t =
⋅
⋅
⋅
⋅
= =
1 4190 80
180 10 186 2 3 1
kg J
kg K K
V A s min
, ,
SNWļREOLF]HQLHVWDïHMVLDWNL
d = = ⋅ − =
1
200mm 5 10 6 5 m µmα
10
SNWļVNRU]\VWDQLH]UHODFMLWU\JRQRPHWU\F]QHM
tg
( )
B =x Lx= ⋅L
( )
= ⋅L = ⋅L−
( )
tgB B
B
B B sin
cos
sin sin
1 2
SNWļVNRU]\VWDQLH]UöZQDQLDQDVLDWNÚG\IUDNF\MQÈ n⋅λ=d⋅sinα
SNWļZ\]QDF]HQLHSRïRĝHQLDSUÈĝNDQDHNUDQLH
x L n
d n
d
n L
d n
= ⋅
⋅
− ⋅
= ⋅ ⋅
−
(
⋅)
M M
M 1 M
2 2 2
SNWļZ\]QDF]HQLHZ]RUXQDUöĝQLFÚRGOHJïRĂFLSRPLÚG]\SUÈĝNDPL
%x=x2−x1
%x L n
d n
n
d n
= ⋅
−
(
⋅)
− −(
⋅)
M M M
2 2
2 2
1 2
1 2
SNWļREOLF]HQLHUöĝQLF\RGOHJïRĂFL
%x =3 5 10⋅ −7 ⋅0 5 2 − 1
, m , m
=
L
a
x
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w w w. o p e r o n . p l 7
Numer
zadania 3RSUDZQDRGSRZLHGě Liczba
punktów
SNWļZ\]QDF]HQLHZ]RUXQDUöĝQLFÚRGOHJïRĂFLPLÚG]\SUÈĝNDPLGODUöĝQ\FKGïXJR- ĂFLIDOL
%x=x2−x1
%x n L
d n d n
= ⋅
−
(
⋅)
−
−
(
⋅)
M M
M M
2
2 2
2
1
2 1
2
SNWļREOLF]HQLHUöĝQLF\RGOHJïRĂFL
%x = ⋅ ⋅
(
⋅)
−(
⋅ ⋅)
−⋅
⋅
−
− −
−
3 0 5 6 5 10
5 10 3 6 5 10
3 5 10 5 1
7
6 2 7 2
7
, ,
,
m m ,
m m
m 0
0−6 2 3 3 5 10−7 2
( )
−(
⋅ ⋅)
=
,
m m
0 104, m10 4, cm
SNWļREOLF]HQLHVWDïHMVLDWNL d n
= ⋅ λ sinα d = ⋅ ⋅
= ⋅ =
−
5 4 10 −
0 5 4 5 10 4
7
6
, m ,
m µmα
SNWļREOLF]HQLHOLF]E\U\V
N = ≈
1
4mm 250 µm
α