CHALMERS UNIVERSITY OF TECHNOLOGY
DEPARTMENT OF NAVAL ARCHITECTURE
AND MARINE ENGINEERING
GOTHENBURG
-SWEDEN
TEHORETICAL STUDY OF THE WAVE
RESISTANCE OF SIDEWALL HOVERCRAFTS
by
NIKOLAI PLISSOV
DIVISION OF SHIP HYDROMECHANICS REPORT NO 51
1 . S ULIT.L: 11 Y
. INTRO DITCT TON 2
3.
FO Ri.11. LA S FOR T.,--TAVE RE S I S T ANC E - 44-, RESULTS 2,..i.:11) Ti-'IR. DISCUSSIO 13
5,
CONC LUDING RELIARK 15,
Q. A C ICTOVIL ED GE1.. .1T ' 15
70 REFERENCES .16
8 . liUlER.ICA L C 01UTAT ION OF
INTEGRALS Ii AND
12 17
C 01TUT ER PROGRAM 20
-FIGURES
This report is concerned, withthe wave
resistance of simplified
sidewall hovercrafts
traveling over water of infinite depth withsteady speed. An approximate approach is used
to derive
suit-able exPressions.for the wave. .drag. Unlike prOriOs theoretical
woks in this field his report- contains -vast calculations in
which the separation of wavemaking
coMponents'cfrom walls,
air :cushion and interaction between them) of.sidewail hovercraft
is shown. Comparisons. are also dene with available theoretical
results. Some details with 'respect to practical computingand
2. INTRODUCTION
The wave resistance of a eijeawall hovercraft
depends on
thetype and design of the creft because of
the
sidewalls.itmore important or this typ
of .air-cushion vehicle
than forthe.amphibieus oneec.. The .alide'6oards can probably change the
two humps of the. resistance and corresponding Froude
num-bers.
There are many unanswered questions in this field. Afew papers concerning the
,problem
are availableand
are short,ly considered below.
In the work
by
Chaplin [1] it is recomended either'to neglectthe wavetaking
of
the sidewalls or to regard it as theaddi-tional wave resistance of two separate thin hulls. HowevIr
this approach seems to be too primitive. There are two szecial.
theoretical. investigations on the subject by.Hurthy and Yin [2,5J.
Murthy [2] assumes that the sidevalls can be replaced by two e
uniform pressure distributions of rectangular form travelilime over the water.surface.together with the main pressure
distri,-bution from the air cushion. The value of the pressure in these
. side distributions is
determinated .by the draught of_the
side-walls.
The wavemaking'of
the forward and, aft sealsis
neglec-ted. These assumptions made it possible to
derive.at,a formula
for wave resistance. Hurthy computed several examples bud didn't
separate the interference part of the wave resistance.
Yim
[3]
used Eretensky formula for wave resistance ofa
:Pressuredistribution in a channel of finite width. The sidewalls were
regarded as two linear source distributions along their
center--planes. This assumption corresponds to the
well
known slendership theory. Since the same source distribUtions was taken as
for isolated thin hull without air Cushion effect
and this
dis-tributions were supposed not to
affect
the wavemaking of the aircushion. it means that only Wave sUperposition without reflection
was considered. A formula was derived and some calculationS
for
infinite rater were done. As a result theaUthor could,show the influence of the Froude number and of
some
geometri-cal factors on the wave resistance. He also made the first
ef-feet by increas'ini,; the rushion_pressure in the local areas near
the seals. In thi;?; aph the Sizes of the areas. are not de,..
fined. however. The infi of sidewalls on the total wave
resistance hasnot been shown.
Experimental invecidge-Lion,s, cif the wave drag of sidewall
hover-crafts are no known.
The aim of present investigation is:
to split otal wave resistance in components
to carry out more complete calculations than before
3° to show how the sidewalls wavemaking and the
inter-ference between them and air cushion depends on
-FORMULAS FOR WAVE IIES=ANCE
An appreximate apbrea-J11. oimA.ar to reference
DI
is used toderive to a.forml).1a fo± the ave resistance. The drag of the
seals is nelecT,ed and .aal vfivemaking is regarded to
be.g.ene-rated,by the aj.1- cushion and .the sidewalls. The former is
presented as a ctang area of uniform pressure distri- .
bution.
The sideboards are assumed to be
thin andsymmetri-cal with respect to their centerplanes. Figure 1 shows the
main geometrical characteristics of craft and of the moving
coordinate system oxyz. The x-axis lies on the water
sur-face and coincides with the speed vector The
2;.;.akis is
directed' upwards
Fig 1 Vain geometrical characteristics
/
c.
where 12
, density of
the.water
and
= a1 + al
tr b b b 1 1 ' /69:ces
3 0Q'9
Acco.,.ding to [4] (see also 11Costyukav [5 ] ) the wave profile
at a great distance behind a moving body can be' fOund in the
Mtn: r
Z(zpp=
a(69-cosEcLW069
(-2* cose?
&e:/2.-/
fa2
Le)--,-,,Lvo(-cvs62
:Ye ./2. 6))jj
c/62
( 2 )
where
and the wave amplitude is
az(62) gro)
(4)
The probleft is
find a()) and. b(e)
we write a(8) and b(8) as
a
a
1 2
b =
bl
Havelock's formuda
41
tu:ed for the wave resistance
speed of the craft
In [5]
a1 1 .aerminate.the contribution from the sideWalls
15
derived at by. afftion..of w%ves from two Walls (a1 bl
and
al , bi). b, determinae the contribution from the air
cushion pressure
distbu4-io1.
We thus accept the sameassumP-tion as in reference [3],
ize
we consider only superpositionof waves_ fro :2 differe:-It sources. Wavemaking at great distance
from an origine
is
regarded to be the same as if the origine'is
'isolated.
Thisapproach is fairly
approximate and thefol-lowing numerical results can be interpreted- mainly qualitati,'
vely0 However they must be closer to reality the greater the
distance between the hulls and the smaller their thickness and draught may be
As a starting point two known expressions for waveprofile
ordi-nates at great distance behind a thin ship
[5]
and behind apressure distribution according to [6] are taken. They
are respectively: 2
(16)
#5/. Jir
Z4
(x?:iyi)=1 ---7.---.7
rdS
e
(COL52/
CM36)
(7) whereto,
cog
624-(041r--are coordinates of a point of the hull surface S
q is the
density of sources distributed, over surface Sand
-yz
,hitib
s6;7- (1,-);;j6
)
where()Co1.6)
L °p is the pressure distributed over the arrea
a
7 a)
(8)
Then
Formula (7) the coordinate system
01 xl yl
zifixed to a 11;A1., In t1L:: sl(:nder ship case
[51
thesourcedi-stribution over
the
center-olane of the ship.Considering cylindrical hulls with
cons-tant form of the watea-iiy. we can obtain. according to [5]:
K) r7J77
,.,e
d
(9)
where
7-1/(1)
is the equation of the waterline. In thefol-lowing calculations we put
Qpa
)"Ja
/
I 2r
r
-
Z2
To derive final exp-.L.essns
for
al; bit al; 131 andhence for
If
and
we must next take some successive steps.a1 u1
1. SUbstitude (11) into
(7)
and integrate the .latterregarding dS = d
d1 and -0;5
L1ZCi Z
- Hi
7C/Z0
where Hi is the "effective" draught,of the sidewall (see later)
(12)
1
where
0,
x,
t1
are the coordinates fixedto
the leftboard and
o1 °1:1 2,1
to the right one..
2. Transform the results to the coordinate system oxyz
using the relations:
= x
xi
X1
=x
y = y -. y + 0.5B
8
-3.
0oi.o.a.2e the e:KSsions found in step 2 with formulaand separateHt.hus a(8). and b(8).
Ommiting int,F:rnediate e..(7mutt.iftions we give the.final.expre6sions
.0
The .integration with respect to C. in formula (7) is D rformed
from 0 to
HI.
where H. is the
mean
value between outside andin-' I
-sidedip.ghts at zero speedj
I-4
a
6-p
"
(14)
In (14) -H - outside drawjht of sidewall
p - air cushion pressure
(11,- a.)- inside draught.
specific
weight
of the waterThis approximate approach has been ..used. to take into account the
difference between the, waterievels outside and inside the
ide-walls.
Similarly one can reduce foildula (8) to (2) and obtain
a22 b2.
o
#4szr
#.0,543CO59t9
f
fl
-6:64
-0.6-8And after. integration
a2
= 08/5
)18.S01
S6'2(
)/Zi
)(7 l'S6'n
20
2 Cola
7-~
" t Ce75co5 6
4.714;1,0 dg.ebi.
(13)
(15)
Now.froa (i3) and (i5) the expression for the wave
resi-stance is easily obtaindo
F/2 . q where /.2
=
Tri9-2fi
42(6)0053,62,o/6i
--Lt 0=
- 61-/*P2r. cop& sz)zz/ 1-48
Se.44.0) .16,f22()I.L
ild& (17)
y. y_
i'-' 1 307,220
(2! ciasz
(2.005(i
0
5,
t)" viA..-R
V
R14,1S
,z
...)0.2f2/itz(0.067.-5362ci
-/o2qp-vrvz
4,ei
)/. 8,..911?0Ocog
st.:1,71vz,
Ze
;
z
* CO"32(r
2
co5z 6 e -2.e6456
zy
cog 640
26-6-(p /cof3
r
7)1' 0 zs
(:;?2c0$621
"Z(19)
-vH4
e
Y---1-3-1-L--f.161. ).--CCth
,Y 16i)
LAI cou32
y
L) c,/2.2Cai Y
-2))
Rwc is
the wave resistance of the air cushion, ioe of. a
rectanu-lar'pressure distribution.
Rws is the wave resistance of the sidewalle
ARw is the wave resistance due to interection between the
cushion and the sidewalls.
(16)
(le)
We shall not coliipute :awe since the extended calculations of this
part made by Newnan. and Poole are 'available [7]. The wave resi
4°. eff4.4.
cos.'
GW4
stance of
gations of catamarans.- r.nere, are however
two
reasons that have .made us to c67-sin-te this i)art in the present
work.,
.First thedraught of the sidewalls than available data from
catamarans. Second it ii7.batter to compare the tart of
eachcom-ponent of total wave resistance taking the. same sidewallform
both (18) and
(19).
Nov attentionwill
be paid to calculationsof avi and cIRW. Since dimensional values - are unctinvinient for practical employment the following non-dimensional characteris-ticsare introduced.
IU
cwu: in principle be taken from investi-,
The coefficient
a,
gives the relation between the buoyncy of thesidewalls and-the air cushion lift. .
Instead
of RWs-and
ARW non-dimensional wave resistancecoeffi-cients
Cw1 and Cw2 related to air
cushion lift
are introdUced.CW- -I
P-
L B _ApiTm F L 1' S (20) ( 21 ) (22)Taking (20) - (22) into account the e.:cpreSsions
for
CW/,Cw2 can
easily be obtained from (18) and (19)
"24/
2ir(e-'7'/Fez;coczo.iz
Ke2.8.-)3
c6:S2(V-V
- cos.E
ars 6 Ecrirl-(
2k
z ccitsi)
v
2ki
l`ft.
r2_
17 .a----n
'CO:3( ,---j- 2 7 ejiciy3-iodo3 (23).
92'4.1
C't(x2 #,)2
2
twoof[ie
''PL
2
N
For computation we reduce the integrals
(23) and
(24) by the
substitution
1 cose
_ 1Then
= G 1 1 w2 G2where
2048t2
Kc: n,-
2 B ° P 112
26-6
e'
'C2c
6.3'61)cos362
)6-.
Re
ad t.1-
/
Y&Ago?
lee
zn(2-R
CO30) ./-
11-M
.Sti>27
)
--
R/
) d
2
C°-) (
'C'e2C46 0 !J
in formula (23) is
11.17
Rea
3 /3. (L
A
2
G256
Ks 2 -n5
Ke(z4-1)_7- C3. coil
Re
2k0
.66:
6,
24:.1.), 1r
0,2(
(24)
(30)
G2z9:3+1).
VC(23)
(26)
es°
C,i/Xa.7%
2;
=7
e
Nia LIZ 1-11Pe
, )17214
2 14.1)2' (Z2-1-2)
Ike
y)7
jj
2k0
QThe
final
exprssions 32) are used for computation.Numerical computation of (30) and (31) faces some special
fea-tures, Both integrals- have
infinite upper limits
though theyare convergent. The integrand in (31) is undertermined at x=0.
The intergrands osscilate and this is the reason for the large
number of steps necessary for numerical integration. The cal7
culations have been done on 'Hewlett - Packard digital computer
In the
end
of the report details on practical computations ofintegrals (30)7.(31) and also the computer program, are given. Relative error in numerical integration is about 1%.
In formulas (30) and (31) following designations have been in-troduced
=7. 0
40 RESULTS AND THEIR
,72SION-The results of computation are given in figures 2 - 14. The
total wave resi.2tnce'coffcient C is a sum of wave-resistance
coefficients cbmItedc-ding to formulas (28)
'(31)and wave
resistance coefficient Ow, of the moving pressure field from
[7]
thusCt C11 Cw2 Ow,
:awe
where
C=
T MC .t4 +.3
Fig. 2 and 3 show the variation of each component as 7211 as
to-tal wave resistance with Froude number. In the figures s61.1e
theoretical results from [2] and [3]. are also given for
cOM:-parison. One observes two humps at Froude numbers Fr
0935
andFr 096. The latter is biggest. The wave resitance of the
sidewalls (Cwi) i8 negligibly small but the drag due to interac-tion of the air cushiori :iLnd the sidewalls is about 20-30 percents
of air Cushion wave drag at Fr 095 - 0.96. At a low TroUde
number (Fr F4
0,35)
the interaction resistance is negative andat Jr 095 - 096 it is largest. Comparizon.With calculations
carried out by Tim
E3]
shows good qualitative and quantitativeagreement. Murthyis results [2] givea bit higher wave
resi-stance coefficients at Fr 0,4 and move the first hump to
lo-.
wer Froude number. The qualitative agreement is satisfactory
however.
Figures 5
5
illustrate variation. of "additional" waveresi-stance coefficient K with Fr Ke,
Coefficient K is Cw K c.,we
(35)
(34)
Thus K show.: hOw the ai..(:%.m.;hion-Wave dra increases due to the sidewalls.
It appears f-for: fiz 6 doesnit'practically depend on
but
essential; 'i.. E..-on-theair
cushion pressure undergi-ven sizes of P., Than the greater a (i.e less
pressure) the greater is relative sidewalls effect. When the
buoyncy of the sidewa:Ils is about 50% of the air cushion lift the additional wave resistance due to the sidewalla is about.'
50 - 60% of air
cushion Wave d,-a. It is interesting to noticethat the relative width of cushion
2
and draught R of theboards affect this coefficien fairly little. Values of the to-,
- 15
ON'aLUDI-1\111 REMARK
The calculaion:
bere-Iik-previoustwo papers
on this subjectare based on a.7, approach. Further theoretical Work
in this field oan be cono-rnc,d with formulas which take into
account the-reotion
and
distortionof
waveSfrom differentparts of a hovercraft, However, this theoretical troo-.
blem
is
fairly complex.At
any rate experitents withmeasureent of wave resistance of sidevall hovercraft sees. now to be more desirable to check the simplified.thecries and to give the answer about practical expedience of the developing of more exact theories.
6. ACKNMILEDGF2,IENT
This Work was carried out under Sponsorship of Division of Ship Hydromechanies of Chalmer's UniVersity of Technology asa ipart
REFERENCES
Chaplin, E.7i.
"Some J.-J Priniles of Ground Effect Machines",
Section D Drag D;:i.v.J.d Taylor HodelBasin
Report 1.966
MUrthy,
"The Wave Resistance of a Sidewall Hovercraft
Cata-marans and Trimarane, .
University of Southamvton-,,A,A.SO.
Report NQ
296 1969
Yim, B.B.
"On The Wave Resistance of Surface .Effect Ships",
J.S.R. .15
(1971)
14.
Havelock,"The calculation of wave resistance",
Ibid vol
144, lig 85, 1934
Kostyukov, A.A.
"Theory of Ship Waves and Wave Resistance",
Leningrad
1968
6. Lunde, J.K.
"A Pressure Distribution 1.Aoving at Constant Speed
of Advance on the Surface of
Deep
or Shallow Water'",Skipsmodelltanken, Norges Tekniske
Hogskole,Trondheim, 1951
t.
Newman, j0J,, Poole, F.A.P."'Wave Resistance of a .Moving Pressure Distribution. In a Canal"
8. NME4ICAL 00YPUTATION OF INTEGRA1Z 11 AND 712 Then (z).(i% 0 grals A If
and
So far. as (31) are convergent one can replace.
infinite.
up-_91er.itLit 7:y,c=e number N. It is possible :toesti-mate the accuracy' d'ue to thi3 replacement. Let the integrand in
(30)
be F1(,:). ancI. in (51) - :F2(x)cA =
10-
1f(ZYZ +if 617*/z
2To find the error of A
1
and make its estimate
2
K 4 K 2
.
C, C_m + -r
2 5 8
truncation in (30) we consider
inte-zjz
L
ikjo2C3 z
i`c
3
3
/2
4/4
r
/11(A le
19 A67/W9
AV
/
01/Ke-at given r:Lc.f:.,
L;
1061
N1 ;
ey:
M
/
/ 1CIThe same app:cac iitI reL,;pect to
z
ko
,a/.2
._P-2
(7)
-C/2 Z.
(
)
2-/
+ C
3 (a-2-#.-/)ai(rZ a 1`2)
1 2.7 A72 /V23/
)dz
- /ife
Z.C3
)0/2 Alo2 (.3.2'
a7
/12
(
7.9
7 /
1//442
IL 7476 /
0/ z
Rp
z opy26
Thus where 2 C,T°
2 T = 2 8 + and A2 =1052
One-Usefull property of the integrands was found at some
preli-minary computations. They are with great Accuracy constant at
x 00.01 at any value of XC1' C C. . This property.has been.
o' 2' 5
used to eliminate the difficulty of numeridal integration of
22(x)' at x = 0 and to simplify
comraltation program.
12
was thus
computed as
6r
--2
(ezi
e2
.F2(x)dx gives(36)
(37)
(38).
Where c
2
sHane
0,01 and greater than P6
301!
uni-formity of 1)talli th
sayar.: method has been used for
al-though F.1 io:detemine at 0. An other-uSeft111 point came
from PreliMinry oalcIdaons
Because of integrandsoscil-lations and eMe..".!,1 meanings it
is better to de.Vide the
integra,-.tion interVal. in 2evera1 parts.
The 'number of
steps andcot-puter.time cai. e red7loed in
this ways All these observations
have been regarded in the following computer program.. The
pro-gram
is
written in the computerianguage "Basic" which is used9. COMIJUTER PROGRAM
1. Di7,F.F::: (X) ;....FNA(X)-(o7 DIP FNP (x) FNB(X)
Statent 1:is vc7Lripus, If
Cr1 is computeithen
FNF(X) . i(x), if Cw, - FHF(X) FNB(X)
5. PRINT"-ET:GINTTM"
70 PRINT "INPUT FR, EL, Hp 39 ES, A IS REQUIRED"
100 INPUT Al, A24 A3, A4, A5, A6
Because of Basic features we :inust use another desigpa7
tions in practical program* Statement 10 demands of
the input of main initial data:
Al = Fr, A2 = Ke, A3 = A4 = S, A5 = b, AG =
200 LET i'd0 = 1,333 A*- A3 * .A21- 2/A6/ A4 %i A5
In
the:2..ca,,Lri
MO p30. LET HO = A- 110/2
HO
n
in the present program400 LET KO = Al 4 2
50. LET Cl HO/K0
60. tET C2 . A4/K0
70* LET C3 = A20K0/2
100. LET
TI = (1o4/12)
4-031.2/8 +KOt2gC3/5
mn
1100 LET T2 + C3/6
115.
PINT "INPUm Zl Z2
IS REWIRED"120. INPUT Z11 Z2
°Statement 120 requiresZ1 = 81 and Z2 =52 to be input*
81 and&2
determinate the accuracy of calculations (Seeformulas (56) and (37))
'..
140. LET
N2.
((LO_;- ;T2 *10 t Z2) )/6)145. PRINT t2 WILL PRINTED"
150. PRINT 111 N2
Ni, N2 ar.the up.-ber limits for the integrals computed
160. DEF
= xi
+ 1170. DEF _(X:= 1 -
P.Ci
PNZ(X) 2)180. DEF FNP(X) = A2/2/1C0*FNZ(X)
190. DEF FNC(X) = t 2/FNZ(X)* SIN(FNP(X)) - 03*COS(FNP
200. DEF F11(X) = SQ,R(X t 2 4. 2)
210. DEF FND (X) = C2* FAX) * FR(x) X
220,, DEF FITE(X) = SIN(FND(X))
230, DEF FNG(X) = COS(FND(X)/2)
240. DEP F.NK(X) = SIN (FNZ(X)/2/K0)
250. DEF FNA(X) = (FN2,:(X) t 2 * FNG(X) t. 2* FNC(X) 2)/(FNZ(X)1%
14*-PNQ,(X)
260.
DEF 1M(X)
F3(X)/(FITZ(7)*X3i-PNg(X))270, DEF FNB(X) F11(X)*FNL(X)*FNIC(X)* FTIC(X)/FNZ(X)/FNQ,(X)
Statements 160-270 after all define two integrands
(x) = (X) and_ 7E02(x) . FNB(X)
2800 DIM T ( 6 )
All integration interval 0-N (or 0-N2) is devided on six
parts. 6 numbers in matrix T. are the bounds of these
sub-intervals
2900 PRINT "INPUT LIAT T"
300. laT INPUT T
Statement 300 requires o above-mentioned numbers to be
in--out. The first tuber must be less or equal 0.01, the last
equal
Ni rhen C. or rhon Cw20
3100 PRINT "INRIT El"
320, INPUT El
Statement
320 requires El.- to be input. El determinatessubinteri,
taken equal 10751 (or 10-62) thenthe absoluto srror over interval
0-N1 (or
0-N2
is ,6 0
10 (or 6 '0 10 `-`-)330..
LEI' VUTN
340.
LET FO 217(7/0)350.
LET- YO VU 1.1;!0 360 PRINT "YO"370.
PRINT YOStatement 370 prints the first part of integrals computed
according to (38) 375. LET Y4 YO
380.
FOR K = 1 TO 5390.
LET X1 = T(X.)4000
LET X2 = T(K + 1) 410. PRINT "INPUT N" 4206 INPUT ITStatement 420 requires N to be ihput, The .number 2N
equal to to number of steps -in numerical integration for
everSi subinterval.
4300
GOSUB 800Statement 430 is the address to the subroutine for
numeri-cal
'integration440.
PRINT "Y, E9"
450.
PRINT Y, E9Statement .450 .prints.
5 pairs
Y2 E9corresponding to5 in.-.
tegration subintervals begining- from the second.. 1. is the
meaning
of
integraliand E9 Shows ho r the integral has beencomputed. E9 can be equal. 0; 1; 2,,
.IF E9 0 it means that required accuracy has been reached
IF E9. 2 it means the opposite situation because of. small N and IT must be increased.. The case E9 = 1 means that the-required accuracy cann't be obtained because of rounding
460. LET 14 14 + I
470.
NEXT K545,
PRINT "THE VHOLE ijEGHALYI"
550.
PRINT V,Statement 550 Prints the value of the whole integral from
0 to N.. )
555.
PRINT "INTPLIT W = 1 FOR R1 OR VT = 2 FORR2"560. INPUT W
Statement 560 requires W to be input
W
1 whenCti
computing and W = 2 when Cw2570. IF W > = 115 TEEN 605
575.
LET 01 (65202 ftKO*A5 )/(42 t 2 itA4 LIO)580
LET R1 = G1 4-Y4585.
PRINT "R.1"590.
PRINT R1Statement 590 irints siciewalls wave resistance coefficient
Cw1 = R1 600. .G0 TO 1250
605.
LET G2 = (81.6*K0*,15)/(A2*A4) 610. LET R2 . G2 *14 615. PRINT "R2" 620. PRINT R2Statement 620 prints "interaction" wave resistance coeffi-cient
Cw2 =
6303 GO TO 1250:
The following statements are the Subroutine for...numerical
integration of a given fuction, it uses trapezoidal rule
together with Rotberg's extrapolatien method. This
inte-gration method gives the smallest truncation error in com-paring with other numerical methods at the same number of
steps.
The .trogram_has been
developed from the similar:Subroutine
for
-Fortran. -(see IBM.Apulication Program.Q
24.
800,
DIM A(3o)
810.
LET A(1) ,=70e:5
820.
LET H = X2
X1830.
LET TIEN -1170840.
IF H
0 THEN 1200850,
LETH1 = H
860.
LET F El /ABS (H)870,
LETD2 = 0
880,
LETP =1
890.
LIT2Ji = 1
900.
FORI
= 2
TO N910.
LET Y= A(1)
920,
LETD1 = D2
930.
LETH2 =
940.
LETH1 = 0.5* H1
950.
LETP
= 0.5P
960,
LET X X1 +111970,
LET S 0980.
FOR J
1, TO J 1
990,
LET SS + FNF(X)
1000,
LET X= X + 112
1010.
NFAT J1020.
LETA(I) = 0.5 if A(I
F S1030.
LET Q=
11040,
LET33 =. I
11050,
FORJ
= 1
TO 33
1060.
LET15 =
J
1090.
LET A(I5)-.. '
WI5+1
A(I5))/(5..1)
11000 NEXT
1110.
LETD2:. ABS(Y
A(i))
1120.
IF (I
5) LO
HE1150
11300
IF (2)
= 0
HEN 120011400
IF (D2- D1) s,>= 0
THEN 122011506
LET31 = 31 +-31
1160.
NEXT 11170,
LETE9 = 2
1180.
LET H si-A(1)1190.
GO TO 1240
1200.
LETE9 =
1210.
GO TO1i0
1220.
LET E9 . 11230.
LET Y= H*Y
1240.
RETURN1250.
ENDInput data for this numerical integration subroutine are:
X1 - the lower integration
unit
X2 the upper integration limit
2N is the number of integration steps (N- DIM A in
statement 800 so if it is required N 30 one must changc the statement 800)
B1 - the upper bound of the reauired absolute error
FNF(X) the definition of the external function subprogram
used
Output data
Y - the resulting approximation for the integral value
so-called error taratetr
E9 0 or E9 =-1 or E9 = 2. .See the notes to
state-' ment 450.
r
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