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Rachunek Prawdopodobieństwa 2

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Rachunek Prawdopodobieństwa 2

Zestaw zadań nr 4

Termin realizacji: 14 XI 2008

1. For a simple random walk S with S0= 0 and p < 1/2, show that the maximum M = max{Sn: n ≥ 0} satisfies P (M ≥ r) = (p/q)r for r ≥ 0.

2. For a simple random walk S with S0 = 0, let Tb be the number of steps until the walk first reaches b where b > 0. Show that E(Tb|Tb< ∞) = b/|p − q|.

3. Pokazać, że dla każdego m ≥ 1, 2 m

µ2m − 2 m − 1

2−2m= (−1)n+1 µ1

2

m

.

4. Pokazać, że 2 t2

³p1 − s2t2p 1 − t2

´

= 1

n + 1 X n=0

t2nP (S2n= 0)(1 − s2n+2).

5. Let (Zn), n ≥ 0, be a branching process with Z0= 1. Find an expression for the generating function Gn of Zn if G1= 1 − α(1 − s)β, 0 < α, β < 1.

6. Each generation of a branching process is augmented by a random number of immigrants who are indistinguishable from the other members of the population. Suppose that the numbers of immigrants in different generations are independent of each other and of the past history of the branching process, each such number having probability generating function (pgf) H(s).

Show that the pgf Gn of the size of the nth generation satisfies Gn+1(s) = gn(G(s))H(s), where G is the pgf of a typical family of offsprings.

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