Design Aspects of Pipe Conveyors
G. Lodewijks and M.E. Zamiralova
The 12th International Conference on Bulk Materials Storage,
2
Challenge the future
Contents
1. Introduction2. Indentation Rolling Resistance
3. Pipe Forming Capacity
4. Belt Rotation
1.
6
2.
Rolling resistance force
Rotational inertia of the idlers
Flexural deformation
Indentation
Load forces fro the belt - for open trough belt conveyor 61% [1]
[1] Hager, M., Hintz, A., The Energy-Saving Design of Belts for Long Conveyor Systems, Bulk Solids Handling, 13 (1993) 749.
8
Concentrated forces from the material load for pipe belt conveyors [2],
modified from the approach for deep trough belt conveyors [3]:
( )
( )
2 m ( , ) p act d pas d 2 n l F R g C C α α α α α α α α α ρ α α α α +Δ +Δ ⎛ ⎞ ʹ Δ = ⋅ Δ ⋅ ⋅ ⋅ ⎜ + ⎟ ⎝∫
∫
⎠( )
2 2act (cos2 cos ) (cos sin ),
C α = ϕ+ α ⋅ α+ ⋅m α
( )
2 2 pas sin (cos 2 cos ) (cos ).C
m α
α = ϕ + α ⋅ α +
Load forces determination
[2] Dmitriev, V. G., Sergeeva, N. V.: Tension calculation of pipe conveyors, GIAB M, Moscow State Mining University, 16 (2009) 144-170.
[3] Gushin, V. M.: Determination parameters of the load-carrying surface for the steep inclined conveyors with the deep troughed belt, Mine and quarry transport, Nedra, 1 (1975) 164-166.
Concentrated forces from the belt. Total normal contact force.
Total normal contact force for each n-th roll:
m b zn n n F = F + F 3 b2 b stif 2 1 2 p ' 1 24 E h F l R α µ µ = ⋅ ⋅
− Weight of the belt [2]
Stiffness of the belt [4]:
p b b1 stif 2 6 R m g F F l В π ʹ ʹ = + ⋅ ⋅ p b b2 b6 stif 2 cos 6 3 R m g F F F l B π π ʹ ʹ = = + ⋅ ⋅ p b b3 b5 stif 2 cos 6 3 R m g F F F l B π π ʹ ʹ = = − ⋅ ⋅ p b b4 stif 2 6 R m g F F l В π ʹ ʹ = − ⋅ ⋅
10 Indentation contact model
The stress distribution [5]:
2 2 0 1 1 1 ( , ) ( ) ( ) 1 exp 2 m i i i i i E E k x a x y a x x a a k R h hR k σ = ⎛ ⎛ ⎛ − ⎞⎞⎞ = − + ⎜⎜ − + + ⎜⎜ − ⎜ ⎟⎟⎟⎟⎟ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠
∑
Parameters ki equal [5] : i i b i b i V k V E η τ = =[5] Nuttall, A. J. G., Lodewijks, G., Klein Breteler, A. J.: Modeling rolling contact phenomena in a pouch belt conveyor system, Wear, 260 (2006) 1081-1089.
Generalized Maxwell model with multiple parameters
Deformation of the contact [5] : 2 2 0 1 2 ( , ) 2 2 x y w x y z R R = − − Winkler foundation
[5] Nuttall, A. J. G., Lodewijks, G., Klein Breteler, A. J.: Modeling rolling contact phenomena in a pouch belt conveyor system, Wear, 260 (2006) 1081-1089.
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1) Half length of the contact:
2) Division into strips, y – coordinates.
3) Determination x - coordinates:
The normal contact force on each idler roll:
. 2 0 ) , 0 ( c = ⇒c= R2z0 σ y1, y2, y3…yp ( ( ), ) 0 ( ) w a y y = ⇒a y ( ( ), ) 0b y y b y( ) σ − = ⇒ 1 1 [5] ( ) calc 2 0 ( ) 2 ( , )d d 2 ( , )d ( , )d 2 j j a a a y c p z j b y b b y F σ x y x y σ x y x y σ x y x = − − − ⎡Δ ⎤ ⎢ ⎥ = = + Δ ⎢ ⎥ ⎣
∑
⎦∫ ∫
∫
∫
[5] Nuttall, A. J. G., Lodewijks, G., Klein Breteler, A. J.: Modeling rolling contact phenomena in a pouch belt conveyor system, Wear, 260 (2006) 1081-1089.
Indentation force.
Where q – number of strips,
- for odd number of strips.
( ) 0 ( ) 2 ( , )d d a y c y b y M x σ x y x y − =
∫ ∫
⋅Moment My form the asymmetric pressure
distribution [5] : , d ) , ( 2 d ) , ( 2 1 1 2 1 1 ind ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎣ ⎡ + = =
∫
∑
− = a b p j y n x x y x x x y x qR c R M F σ σIndentation rolling resistance force Find for
each roll of the idler set:
2 1 + = q
p
[5] Nuttall, A. J. G., Lodewijks, G., Klein Breteler, A. J.: Modeling rolling contact phenomena in a pouch belt conveyor system, Wear, 260 (2006) 1081-1089.
14 0 2 4 6 8 10 0 0.005 0.01 0.015 0.02 0.025 0.03 Vb [m/s] f ind [-] Q = 25% Q = 50% Q = 75%
Indentation rolling resistance friction factor:
0 2 4 6 8 10 0 0.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04 0.045 0.05 Vb [m/s] f ind [-] Q = 25% Q = 50% Q = 75%
For each n-th roll:
n z n n F F find = ind l g m m F f n n ʹ ʹ + ʹ =
∑
= ) ( m b 6 1 ind ind DIN:0 2 4 6 8 10 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1x 10 -3 Vb [m/s] z 0 [m ] F1 F2, F6 F3, F5 F4 0 2 4 6 8 10 0 0.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04 0.045 0.05 Vb [m/s] f ind [-] Pipe Trough Indentation depth.
Comparison with the open trough belt conveyors.
16
3.
Pipe conveyor test rigs: design, application and test results
I. Static 6-point testing devices
II. Static test rigs with various frames and supports
III. Dynamic measurements at the dynamic test rigs or
IV. Existing pipe conveyor installations
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Main goal is measuring the roll/pipe contact forces that
primarily determine the pipe forming capacity, with a
focus on the effect of the belt’s stiffness.
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Theoretical predication of load distribution
10 20 30 40 50 60 70 80 0 100 200 300 400 500 600 700 m`b [kg/m3] Re a c ti o n f o rc e R [N] R 1 R2, R6 R3, R5 R4 20 30 40 50 60 70 80 90 100 0 50 100 150 200 250 300 350 400 E2 [MPa] Re a c ti o n f o rc e R [N] R1 R2, R6 R3, R5 R4
0 50 100 150 200 250 300 1 2 3 4 5 6 0.00% 5.00% 10.00% 15.00% 20.00% 25.00% 30.00% 1 2 3 4 5 6
Absolute values
Percentile values: F
n/Σ|F
n|
22
i) Static 6-point testing devices
CDI together with Veyance, USA Taiyuan University of Science and Technology, China
24 TU Delft tests performed on Phoenix test rig, Germany. Focus on effect overlap on load distribution using parameter B/D. Adjustable plate lengths and pipe diameter.
26 Test rig from ITA Leibzig
University of Hanover - Hötte
With a static 6 point test device the effects of curves and belt tension can not be studied.
ii) Static test rigs with various frames
Taiyuan University of Science and Technology, China
Variation in tension, pitch and curve radii. No information available on the tested belts.
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12 m long static test rig – CKIT/FLS/ConvEx/TU Delft
30 Overlap at the top Overlap at the bottom
Test rig of the Technical University of Košice, Slovak Republic
32
Test rig of Phoenix Conveyor Belt Systems GmbH and the
34 Typical test results with the Hanover test rig
iii) Dynamic measurements
Dynamic test rig of the University of Leoben, Department of Conveying Technology and Design Methods, Austria
36
Test rig of the Institute of Transport and Automation Technology (ITA) at Leibniz
Experiment details
38 Test results for a belt speed of 2 m/s
Test results for the “Rollgurt” conveyor in the lime and cement plant in Alsen Breitenburg, Germany
40
Test section in pipe conveyor in cement plant Hugo Miebach Söhne, Portland-Zementwerk Wittekind, used by Hötte for the field measurements, Institute of Transport and Automation Technology (ITA) a t L e i b n i z U n i ve r s i ty o f Hannover.
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4.
• Curve routes in horizontal and
vertical planes
• Low or unbalanced load from the
material • Irregular wear of the idler rolls
44 Twisting effect
Mass centroid effect
Moment of inertia effect
Shear center effect
Twisting effect.
Shear center concept.
Open thin-wall structures.
• The thickness of the walls is small, compared to the
height and width of the cross section
46 Location of the shear center for doubly and singly symmetric cross sections.
S 2 z wy yz wz y z yz I I I I y I I I + = − S 2 y wz yz wy y z yz I I I I z I I I − + = − p d wy A I =
∫
w z A p d wz A I =∫
w y AShear center location for unsymmetrical cross sections.
Shear center coordinates in centroidal coordinate system:
Sectorial liner moments about y and z axes: Sectorial area: p p p 0 d d s s A w =
∫
r s =∫
r s48 Shear center concept.
Pipe belt conveyors
• Lateral load forces • Geometry
Lateral load forces inducing the shear center effect
.
Lateral forces from the curves
Load forces from the material
50 Geometry of the cross section.
Assumption about the singly symmetric cross section
.
[1] Lodewijks, G., Drenth, K. F., Van der Mel, P. S., 2010, "Belt Conveyor Technology - Rotation of Pipe Conveyors," Bulk solids handling : the international journal of storing and handling bulk materials., 30(3), pp. 144-148.
Unsymmetrical cross section. Archimedean spiral 0 ( ) 2 r ϕ r δ ϕ π = + d ( d ) ( ) d 2 r r ϕ ϕ r ϕ δ ϕ π = + − = 0 d ( ) d d 2 h r ϕ ϕ r δ ϕ ϕ π ⎛ ⎞ = ⋅ = ⎜ + ⎟ ⎝ ⎠ 0 d d 2 A δ r δ ϕ ϕ π ⎛ ⎞ ≈ ⎜ + ⎟ ⎝ ⎠
52 0 0.1 0.2 0.3 0.4 0.5 0 20 40 60 80 100 120 140 160 k [-] γ [° ] 0 20 40 60 80 100 120 140 160 0.08 0.09 0.1 0.11 0.12 0.13 0.14 0.15 0.16 γ [°] r 0 [m ] Length of overlap: Δ = kB Angle of overlap : γ 2 ( ) ( ) 4 2 B πδ B πδ πδ γ δ − + − Δ + + − Δ + ⋅ Δ = Initial radius r0 : 2 o B r πδ π − − Δ =
Location of the shear center. 3 3 'sin 'cos ; 2 2 3 3 'cos 'sin . 2 2 x y x y y x π π γ γ π π γ γ ⎧ ⎛ ⎞ ⎛ ⎞ = ⎜ + ⎟+ ⎜ + ⎟ ⎪ ⎪ ⎝ ⎠ ⎝ ⎠ ⎨ ⎛ ⎞ ⎛ ⎞ ⎪ = ⎜ + ⎟− ⎜ + ⎟ ⎪ ⎝ ⎠ ⎝ ⎠ ⎩ ( ) ( ) cos ; ( ) ( )sin . x r y r ϕ ϕ ϕ ϕ ϕ ϕ ʹ = ⎧ ⎨ ʹ = ⎩ 0 ( ) 2 r ϕ r δ ϕ π = +
Position of any point of the cross section medial line.
Polar coordinate system xy:
Cartesian coordinate system x’y’ :
54 2 2 2 0 0 d sin d 2 x A S y A r π γ δ δ ϕ ϕ ϕ π + ʹ ⎛ ⎞ ʹ = = ⎜ + ⎟ ⋅ ⎝ ⎠
∫
∫
2 2 2 0 0 d cos d 2 y A S x A r π γ δ δ ϕ ϕ ϕ π + ʹ ⎛ ⎞ ʹ = = ⎜ + ⎟ ⋅ ⎝ ⎠∫
∫
'C y S X A ʹ = ' C ' Sx Y A =Position of the centroid.
0 0.1 0.2 0.3 0.4 0.5 -4 -3 -2 -1 0 1 2 3 4 k [-] X C [m m ] 0 0.1 0.2 0.3 0.4 0.5 0 5 10 15 20 25 k [-] Y C [m m ] C C C C C C ' sin ' cos ; ' cos ' sin . X X Y Y X Y γ γ γ γ = − ⎧ ⎨ = + ⎩
Location of the shear center. Centroidal coordinate system.
C C 0 C C C 0 C 3 cos ; 2 2 3 sin . 2 2 x x X r X y y Y r Y δ π ϕ ϕ γ π δ π ϕ ϕ γ π ⎧ ⎛ ⎞ ⎛ ⎞ = − =⎜ + ⎟ ⎜ − − ⎟− ⎪ ⎪ ⎝ ⎠ ⎝ ⎠ ⎨ ⎛ ⎞ ⎛ ⎞ ⎪ = − = + − − − ⎜ ⎟ ⎜ ⎟ ⎪ ⎝ ⎠ ⎝ ⎠ ⎩
Position of any point of the cross section medial line in centroidal coordinate system : x yC C
Geometrical moments of inertia:
∫
= A x y A I ( C)2d C∫
= A C y x A I ( )2d C Product of inertia:∫
= A y x x y A I C Cd C C56 Centroidal coordinate system.
Sectorial liner moments in centroidal coordinate system
Sectorial area in centroidal coordinate system: S 2 p p 0 0 d d 2 A w r l r θ δ ϕ ϕ π ⎛ ⎞ = = ⎜ + ⎟ ⎝ ⎠
∫
∫
∫
= A C wx w y A I C p d∫
= A C wy w x A I C p dPosition of the shear center.
-error less than 0,1%
C C C C C C C C C S 2 y wx x y wy x y x y I I I I x I I I − = − C C C C C C C C C S 2 x wy x y wx x y x y I I I I y I I I − + = − 0 0.1 0.2 0.3 0.4 0.5 -5 0 5 10 15 20 25 30 35 k [-] XS [m m ] Analytical ANSYS 0 0.1 0.2 0.3 0.4 0.5 -400 -300 -200 -100 0 100 200 k [-] Y S [m m ] Analytical ANSYS
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Location of the shear center.
ANSYS model.
Location of the shear center.
Cross sections for various length of overlap.
k = 0,0 k = 0,1 k = 0,2
k = 0,3 k = 0,4 k = 0,5
- Shear center - Centroid
60
• Calculation method has been
constructed for the determination position of the shear center.
• Changing of the geometrical parameters
of the belt can not solve the shear center effect of the twisting of pipe conveyor belt.
Solutions?
• Increasing lateral friction between the
belt and rolls.
• Increasing torsional stiffness of the belt
structure.
5.
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From this paper it can be concluded that important design aspects that affect the performance of a pipe conveyor include:
I. the belt’s stiffness. This does not only determine the pipe forming capability but also the indentation rolling resistance. If the pipe contact forces are known then the indentation rolling resistance can be calculated. The test rig to measure these forces however, determines their magnitude and distribution.
II. The ratio between the overlap and the belt width. This ratio has an impact on the location of the shear center which affects the torque generated when a force exerted on the belt does not go through the shear center.